The width of the valley is approximately 343 m.
The time difference between the two echoes is the time it takes for the sound to travel across the valley and back, which is twice the time it takes for the sound to travel from the rifle to one mountain. Let's call this time t.
So, t = 2.00 s / 2 = 1.00 s
The speed of sound in air is approximately 343 meters per second. Let's call the width of the valley d.
Using the formula for distance, speed, and time:
d = speed × time
d = 343 m/s × 1.00 s
d = 343 meters
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Which diagram shows the effect of cutting the
acceleration in Part A in half and not changing
the value of the initial velocity?
Acceleration is the rate of change of velocity over time. The diagram that shows the effect of cutting acceleration by half without changing initial velocity is graph (c)
The equation is given as:
\(v = 2t + 4\)
The first equation of motion is:
\(v = u + at\)
By comparing both equations, we have:
\(u = 4\) --- initial velocity
\(a = 2\) --- acceleration
When the acceleration is cut in half, the new acceleration is:
\(a_{new} = \frac a2\)
\(a_{new} = \frac 22\)
\(a_{new} = 1\)
So, the equation of velocity is:
\(v = u + at\)
\(v = 4 + 1 \times t\)
\(v = 4 + t\)
When \(t = 0\)
\(v = 4 + 0 = 4\)
When \(t = 1\)
\(v = 4 + 1 = 5\)
The graph of velocity that satisfies \(v = 4 + t\) and the values of time (t) and velocity (v) tested above is (c).
See attachment for the diagram (graph)
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An iron core cannot support a star because:
Iron supplies too much pressure.
Iron cannot fuse with other nuclei to produce energy.
Iron has poor nuclear binding energy.
Iron is in the form of a gas, not a solid, in the center of a star.
An iron core cannot support a star because iron cannot fuse with other nuclei to produce energy. Fusion reactions in stars occur primarily through the conversion of hydrogen into helium in a process known as nuclear fusion.
During the life cycle of a massive star, nuclear fusion reactions create progressively heavier elements in its core. As the fusion process progresses, the core transforms lighter elements into heavier ones, ultimately forming iron. Iron has poor nuclear binding energy compared to lighter elements, which means it requires energy rather than releasing it when nuclei combine to form iron. This is due to iron having the highest binding energy per nucleon, making it the most stable nucleus. Fusion reactions involving iron actually consume energy rather than producing it, leading to the inability of an iron core to support a star. The accumulation of iron in the core triggers the collapse of the star, resulting in a supernova or, in some cases, the formation of a neutron star or black hole.
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An iron core cannot support a star because iron cannot fuse with other nuclei to produce energy, and it has poor nuclear binding energy. Additionally, iron is a solid and cannot withstand the extreme conditions at the core of a star.
An iron core cannot support a star because iron cannot fuse with other nuclei to produce energy. In stars, the fusion of lighter elements into heavier ones releases energy, which is essential for the star to maintain its stability and shine. Iron at the core of a star cannot contribute to this fusion process, leading to the star's collapse or explosion.
Furthermore, iron has poor nuclear binding energy compared to other elements. Nuclear binding energy is the energy required to hold a nucleus together. Iron has a lower binding energy per nucleon, making it energetically unfavorable for a star to have an iron core, as it would result in lower stability and energy production.
Lastly, iron is not in the form of a gas, but a solid, at the center of a star. The core of a star is under immense pressures and temperatures that allow elements to exist in extreme states, such as plasma. Iron cannot withstand these extreme conditions and cannot provide the necessary energy for a star to sustain itself.
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Rebecca forgets to title her notes in her physics
class. These are the notes she takes:
Which title would be the best choice for Rebecca's
notes?
-Special signals that help them be seen in the body
-Used in
-CAT scans
-radioactive tracers
-Help create better images inside the body
Uses of Nanotechnology: Carbon Wires
O Uses of Nanotechnology: Quantum Dots
O Quantum Mechanics: Carbon Wires
O Quantum Mechanics: Quantum Dots
Answer:
use of nanotechnology ; quantum dots
Explanation:
edg 2021
Answer:
Explanation:
The notes are about using Quantum Dots for bio-medical imagining. The notes are more on its uses than its theory. So the title should be O Uses of Nanotechnology: Quantum Dots.
What is a example of analyze and interpret data?
Answer:
Data from a cross-sectional study or survey might need to incorporate weights or design effects in the analysis.The analysis plan should specify which variables are most
Explanation:
Explanation:
For example, scientists on a ship may examine SONAR data collected in real-time to determine the shape of the seafloor (Fig 2.7 A). ... Biologists might graph the number of box jellyfish over time and compare these data to the phases of the moon to look for patterns (Fig 2.7 B).
Think about the physical activities that you have done as a part of this course. Describe a time during one activity in which a competitor displayed good sportsmanship toward you.
The activity in which a competitor displayed good sportsmanship towards me was during a football match.
What is Sportsmanship?This is an ethics or attitudes that show respect for the rules of a game and for the other players.
Sportsmanship was shown when i lost the deciding penalty and was consoled by the opponent.
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What is mast often givena value of zero to describe an object's position on a straight line? Odisplacement Oreference point O distance Oending location Mak Save and Exit
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Plz don't answer late..
a 150 N force is used to pull a wooden box across a wooden surface at a constant velocity. what is the mass of the box?
Answer:
The mass of the box:
m = 60 kg
Explanation:
Given:
F = 150 N
g = 10 m/s²
_________
m - ?
Coefficient of friction wood on wood:
μ = 0.25
Friction force:
F₁ = μ*m*g
Newton's Third Law:
F = F₁
F = μ*m*g
The mass of the box:
m = F / ( μ*g) = 150 / (0.25*10) = 60 kg
how do newtons first and third laws describe the motion of an object?
Answer:
Newton's laws of motion relate an object's motion to the forces acting on it.
Explanation:
In the first law, an object will not change its motion unless a force acts on it. ... In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
A device sends out waves with frequency of 68. 0 Hz and a wavelength of 28. 0 m. What are the speed of those sound waves?
Those sound waves travel at a speed of 1904 meters per second.
The equation for velocity is v = (68 Hz)(28m) = 1904 m/s.
As with all waves, the relationship between the speed of sound, its frequency, and its wavelength is vw=f, where vw denotes the speed of sound, f denotes its frequency, and f denotes its wavelength.
The frequency of a wave is expressed in Hertz (Hz), which is the number of waves that pass by each second. A sound wave, for instance, might have a frequency of 450 Hz.
"The distance between the two successive crests or troughs of the light wave" is how wavelength of light is described. Using the Greek letter lambda (λ), it is identified.
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A car is going 60.0 mi/h and has to stop in 6.0 seconds. What is the car’s acceleration?
Explanation:
Convert mi/h to ft/s.
60.0 mi/h × (5280 ft/mi) × (1 h / 3600 s) = 88.0 ft/s
Find the acceleration.
a = Δv / Δt
a = (0 ft/s − 88.0 ft/s) / 6.0 s
a = -14.7 ft/s²
The driver must accelerate the car at the average rate of
- 10 mile / hour-second
for 6 seconds .
Which of the following is a renewable resource?
Multiple choice question.
A)
natural gas
B)
minerals
C)
geothermal
D)
oil
PLEASE HELP FAST ASAP
Answer:
B) minerals .Because they mainly consist of metals
in a scale model of the solar system erected in dallas at the perot museum to give a true sense of the size of the solar system, the earth is represented by a tiny poppy seed with a properly scaled orbit that is located 77 feet from the scale model sun (which is represented by a softball to keep the difference in sizes properly balanced). to keep the scale properly spaced, how far away would neptune - at 30.1 au - have to be placed (using only 3 significant figures)?
To keep the scale properly spaced, Neptune would have to be placed 2,350 feet away from the scale model sun.
In the scale model at the Perot Museum, the Earth is represented by a poppy seed and is located 77 feet from the scale model Sun. To determine the distance for Neptune, we will use the given information about Earth's distance and the astronomical unit (AU) conversion.
1 AU is the average distance from Earth to the Sun, which is 93 million miles. Neptune is 30.1 AU from the Sun.
First, find the scale of the model by dividing the scaled Earth-Sun distance (77 feet) by 1 AU in feet (93 million miles * 5280 feet/mile):
Scale = 77 ft / (93,000,000 miles * 5280 ft/mile) ≈ 1.592 × 10^-10
Next, calculate the scaled Neptune-Sun distance by multiplying Neptune's actual distance in AU (30.1 AU) by the conversion factor (1 AU in feet) and the scale factor:
Scaled distance = 30.1 AU * (93,000,000 miles * 5280 ft/mile) * 1.592 × 10^-10 ≈ 2350 feet
So, in this scale model, Neptune would have to be placed approximately 2350 feet away from the Sun.
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What does Newton's second law describe?
A. How inertia affects the motion of an object
B. The relationship between force, mass, and acceleration
C. Action-reaction pairs
D. How friction and the normal force are related
A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 375-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 1.80 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.75 Hz. Ignoring any reflections of sound in the room and using 343 m/s for the speed of sound, determine the amplitude (in m) of the simple harmonic motion.
Answer:
\(0.361\ \text{m}\)
Explanation:
\(f_s\) = Frequency of source = 375 Hz
\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz
v = Speed of sound in air = 343 m/s
T = Time period = 1.8 s
\(v_m\) = Maximum speed of the microphone
We have the relation
\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)
Amplitude is given by
\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)
The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).
Does sound tend to bend upward or downward when its speed is less near the ground?
Explanation:
When the speed of sound near the ground is reduced, (such as on a cold day when the layer of air nearest ground is colder than the air above) the higher speed of the wavefronts above cause a bending of sound toward the ground.
James is planning a science fair project on sound waves. He places an alarm inside a jar which he can remove the
air from. Before he removes the air, he can hear the alarm ringing. After he removes the alr, he cannot hear the
alarm ringing. What condusion can you draw from this experiment?
A. Sound waves can travel in a vacuum
B. Sound waves are transverse waves and are loud
C. Sound waves cannot travel through a medium
D. Sound waves require a medium to travel through
Answer:
D
Explanation:
this is simple, because when air is removed, means that there is no particles in the jar so vacuum is achieved, and when you can't hear a sound means that the sound couldn't travel through the vacuum. which means that sound cannot travel through vacuum,
as a result, sound requires a medium ( air) travel from one point to another.
hope it helps, if not please report it so that someone else gets to try it
Question 6
Marks: 1
A ______ is a dimensionless unit to express physical intensity or sound pressure levels.
Choose one answer.
a. noise level
b. decibel
c. hertz
d. sound pressure level (SPL)
A decibel is a dimensionless unit to express physical intensity or sound pressure levels.
A decibel is a dimensionless unit to express physical intensity or sound pressure levels. The decibel, in turn, measures the power of the sound, its energy, and the stronger or weaker it is emitted. Measures the volume of the sound. It is a logarithmic scale that quantifies the relative loudness or softness of a sound compared to a reference level. The decibel scale is based on powers of 10, where an increase of 10 dB represents a tenfold increase in sound intensity. The reference level for the decibel scale varies depending on the context. In the field of acoustics, the commonly used reference level is 0 dB, which corresponds to the threshold of human hearing. Positive decibel values indicate increasing sound levels, while negative values indicate decreasing sound levels or the absence of sound.
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A 17-tooth spur pinion has a diametral pitch of 8 teeth/in, runs at 1016 rev/min, and drives a gear at a speed of 508 rev/min. Find the number of teeth on the gear and the theoretical center-to-center distance.
A/C Transformer The input voltage to a transformer is 120 V RMS AC to the primary coil of 1000 turns. What are the number of turns in the secondary needed to produce an output voltage of 10 V RMS AC?
The number of turns in the secondary coil needed to produce an output voltage of 10 V RMS AC, given an input voltage of 120 V RMS AC to the primary coil with 1000 turns, is 83.33 turns (rounded to the nearest whole number).
To determine the number of turns in the secondary coil, we can use the turns ratio formula of a transformer:
\(Turns ratio = (Secondary turns)/(Primary turns) = (Secondary voltage)/(Primary voltage)\)
Rearranging the formula, we can solve for the secondary turns:
\(Secondary turns = (Turns ratio) × (Primary turns)\)
In this case, the primary voltage is 120 V RMS AC, and the secondary voltage is 10 V RMS AC. The turns ratio is the ratio of secondary voltage to primary voltage:
\(Turns ratio = (10 V)/(120 V) = 1/12\)
Substituting the values into the formula, we can calculate the number of turns in the secondary coil:
\(Secondary turns = (1/12) * (1000 turns) = 83.33 turns\)
Therefore, approximately 83.33 turns (rounded to the nearest whole number) are needed in the secondary coil to produce an output voltage of 10 V RMS AC.
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High-frequency rtms and low-frequency rtms are believed to _________ and ___________, respectively, activity within those brain regions to which it is applied.
High-frequency rTMS and low-frequency rTMS are believed to stimulate and inhibit, respectively, activity within those brain regions to which it is applied.
rTMS stands for Repetitive transcranial magnetic stimulation.
It is a safe, harmless and non-invasive method that is used to treat brain activities by controlling the brain stimuli.
Depressed and anxious patients suffer from brain diseases and exhibit different levels of brain activities leading to the release of stimuli in high and low amounts.
However, it is a widely used technique that is differentiated into high and low-frequency rTMS.
Low-frequency rTMS has a value of less than 1 Hz and exhibits inhibitory effects while high-frequency value exceeds 5 Hz and exhibits excitatory effects.
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strike two tuning forks, one with frequency of 340 hz, the other 342 hz. what will we hear
You will hear a phenomenon called beating, with a beat frequency of 2 Hz, resulting in alternating constructive and destructive interference between the two tuning forks.
When you strike two tuning forks with slightly different frequencies (340 Hz and 342 Hz), the sound waves they produce will interfere with each other. This interference creates a pattern of alternating constructive and destructive interference.
Constructive interference occurs when the waves are in phase, making the sound louder, while destructive interference occurs when they are out of phase, making it quieter. The difference in frequencies (342 Hz - 340 Hz = 2 Hz) determines the beat frequency, which is the rate at which the loudness fluctuates. In this case, you will hear beats occurring 2 times per second, resulting in a rhythmic pulsing sound.
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derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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which of the following is suitable to make a cable out of metal?
a. hard
b. insulative
c. ductile
d. elastic
Velocity and Time
Using the graph above, what is the approximate velocity of the object at 5 seconds? *
During what time interval is the object slowing down? Explain how you can tell.
At what time or times was the velocity of the object about 4 m/s?
Describe the motion of the object being described in above graph.
Answer:
h=112.35
Explanation:
becuase it had to
If the current through a resistor is tripled, how does the power dissipated by
the resistor change?
If the current that is circuit is tripled, the power is increased by a factor of 9. Option D
What is power?The term power refers to the rate of doing work. Now if we have to obtain the work done by the use of the formula; P = I^2R
Now if the current that is circuit is tripled, the power is now obtained by;
P = (3I)^2R = 9I^2R hence the power is increased by a factor of 9.
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PLEASSEEE HELPP I GIVE BRAINLYEST Label a data table so that the experimenter can record observations for the sand and water temperatures at various points.
The labelled table data hat the experimenter can record observations for the sand and water temperatures at various points is given below.
Where is the labelled table data?Here is a labeled data table for recording sand and water temperatures at various points:
Point Sand Temperature (°C) Water Temperature (°C)
1
2
3
4
5
The table is 5 columns wide and 3 rows long, with the first column labeled "Point" to indicate the location being observed, and the second and third columns labeled "Sand Temperature (°C)" and "Water Temperature (°C)" respectively to indicate the type of temperature being measured.
The cells under the "Sand Temperature (°C)" and "Water Temperature (°C)" columns are left blank to allow the experimenter to record the corresponding temperature readings for each point.
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Label a data table so that the experimenter can record observations for the sand and water temperatures at various points.
the column table 5 length x 3 width
10
Select the correct answer.
Which quantity is a vector quantity?
O A. displacement
OB. distance
O C.
O D. temperature
OE. volume
mass
Answer:
A. Displacement is a vector quantity.
What is the kinetic energy of a car with a mass of 1781 kg if it's traveling at 19.33 m/s? Submit your answer in exponential form.
332734.34 Joules
Explanation
Kinetic energy is a form of energy that an object or a particle has by reason of its motion and mass, it is represented by the expression
\(\begin{gathered} E_k=\frac{1}{2}mv^2 \\ where\text{ m is the mass} \\ v\text{ is the velocity} \\ the\text{ unit for kinetik energy is Joules} \\ 1\text{ Joule} \\ 1\text{ Joule=kg}\frac{m^2}{s^2} \end{gathered}\)then
Step 1
a) Let
\(\begin{gathered} mass=\text{ 1781 Kg} \\ v=19.33\frac{m}{s} \end{gathered}\)b) now,replace in the formula:
\(\begin{gathered} E_{k}=\frac{1}{2}mv^{2} \\ E_k=\frac{1}{2}(1781kg)(19.33\frac{m}{s})^2 \\ E_k=332734.34\text{ Joules} \end{gathered}\)therefore, the answer is 332734.34 Joules
I hope this helps you
reddit two parakeets sit on a swing with their combined center of mass 24.0 cm below the pivot. at what frequency (in hz) do they swing?
We are expected to determine how often the pendulum swings. About 1.58 Hz/1.58 H z was the swing frequency of the two parakeets.
What does a pendulum's motion indicate?This is so because the pendulum's swinging motion results from the pull of gravity produced by the magnitude of the earth. The velocity of a pendulum can also be influenced by other elements, such as its length. Advertisement. Background. An object suspended from a fixed location and swinging back and forth due to gravity is known as a pendulum.
What are the benefits of pendulum exercises?The pendulum stretch, among other shoulder stretches, can increase the range of motion, alleviate discomfort, and improve flexibility. This activity has been recommended by your doctor or physical therapist to assist speed
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A tuning fork is struck and produces a sound. The wavelength of this
sound is 2.5 m and the period of this sound is 0.25 s. Find the
frequency of the sound wave and the speed of the wave.
Answer:
Speed= 10meters per second, Frequency = 4hz
Explanation:
First we need to find the frequency of the wave. The formula for frequency is: f (frequency) = 1 / T (period). This means we need to convert the period into seconds and then use it as a denominator with one on the numerator.
Since the period is 0.25,
1/0.25= 4hz
Now, we just need to multiply the frequency with the wavelength
4hzx2.5= 10
= 10 meters per second