A rifle bullet is going 2760 ft/s and hits a tree. It slows to 0 ft/s in 0.13sec. What was its


acceleration?

Answer:

The answer is D because when the faults move that is the tectonic plates moving. So earth quakes will be forming when the fault moves.

Explanation:

Answer:

I would have to say that i feel that after 2 seconds it would be 8 m/s and the overall distance would be 200 m but don't quote me on it

Explanation:

Answer:Thermometer

Explanation:

Answer:

The sense of weightlessness in orbiting satellite is because of the lack of any contact-forces. The only force that acts upon humans in space is the force of gravity, which acts at a distance; but as there is no counter-force, we do not experience the sensation of weight over there.

Answer:

3, 4, 1, 2

Explanation:

Answer:

It would go out the bottom hole faster.

Explanation:

It goes down the bottom hole faster because the water would get poured out the bottom before they even flipped the water bottle.

Answer:

Terminology: Energy - Is the ability to do work. Work - Is the measure of energy transferred when a force acting over a distance. Power - Is the rate at which energy is transferred, used, or transformed

Explanation:

Thank you

At the time of the summer solstice, the noontime altitude of the sun is at its highest point, around 90°.

Altitude is the height above sea level. It is typically measured in either metres or feet. In aviation, altitude can also refer to the vertical distance between an aircraft and a certain reference point on the ground. Altitude can be used to determine the air pressure, temperature, and density of the air. Altitude can also be used to calculate the distance a plane can travel without refueling. Altitude can play an important role in the weather of an area, as air pressure and temperature tend to decrease with altitude. Altitude can also affect the type of vegetation found in an area. In mountain regions, the altitude can have a dramatic effect on the climate, creating distinct areas of vegetation and wildlife. Altitude can also affect the types of crops that can be grown in an area, depending on the air pressure, temperature, and precipitation.

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The acceleration of free fall on the planet is 3.6 m/s^2. The correct answer is option C.

Let's assume that acceleration of free fall on the planet is a.

Potential energy of stone at height 2.0m is given be,

mah = 2ma

Kinetic energy of stone just before reaching the surface of the planet is,

Kinetic energy = mv^2/2

v= 3.8 m/s

Kinetic energy = 7.22m

By law of conservation of energy, Kinetic energy will be equal to Potential energy, and we get;

2ma = 7.22m

a = 3.6 m/s^2

Hence, the acceleration of free fall on the planet is is 3.6 m/s^2. Option C is the correct answer.

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Answer:

A

Explanation:

Because D is definitely true and there is only one false sentence what means if that non of B or C is false because if one is false so other one needs to be too.

Magellan could not use Polaris for navigation in the Southern Hemisphere because it is not visible from that region.

Polaris, also known as the North Star, has been used for navigation by explorers in the Northern Hemisphere. However, when Magellan sailed to the Southern Hemisphere, he could not use Polaris for navigation.

Polaris is located very close to the North Celestial Pole, which means it appears to be almost directly above the Earth's North Pole. As a result, when navigating in the Northern Hemisphere, Polaris remains relatively fixed in the night sky, providing a reliable point of reference for determining north.

In the Southern Hemisphere, however, Polaris is not visible. This is because it is located close to the Earth's North Pole, and the South Celestial Pole does not have a bright star comparable to Polaris. Navigators in the Southern Hemisphere must rely on other celestial objects, such as the Southern Cross or specific constellations, to determine their direction.

Therefore, Magellan could not use Polaris for navigation in the Southern Hemisphere because it is not visible from that region.

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a. Dislocations are defects in a crystalline structure where atoms are out of position. They can move under the application of shear stress.

Dislocations allow metal crystals to be plastically deformed at a much lower stress than their theoretical shear strength because they are responsible for the plastic deformation of metals. The dislocations present in the metal crystal structure make it easier to slide one layer over the other. The shear stress applied to the crystal is spread over a large area, which reduces the stress required to cause the crystal to deform plastically. Thus, a small shear stress is sufficient to create a much larger plastic deformation.

b. A dislocation line is defined as a line along which there is a lattice distortion relative to the ideal crystal lattice. There are two main types of dislocations: edge dislocations and screw dislocations. Burgers vector (b) is the magnitude and direction of lattice distortion caused by a dislocation. An edge dislocation results when a half plane of atoms is inserted in a crystal structure, whereas a screw dislocation results when one part of a crystal structure is moved relative to the other part in a spiral motion along a single slip plane. The Burgers vector is a vector that connects the distorted lattice points before and after the dislocation has passed through the lattice.

- Edge dislocation: The Burgers vector for an edge dislocation is perpendicular to the dislocation line. It is depicted in the following diagram:
- Screw dislocation: The Burgers vector for a screw dislocation is parallel to the dislocation line. It is depicted in the following diagram:

c. The yield strength of a metal alloy depends on a number of factors. The following are some of the most important:

- Oo: The initial resistance of the material to deformation
- Oss: The effect of impurities and solute atoms
- Oph: The effect of grain size and shape on deformation
- Osh: The effect of texture on deformation
- Ogs: The effect of dislocations and other defects on deformation

The sum of all these effects is equal to the yield strength of the metal alloy. This relationship can be written as: Uyield = 0o + Oss + Oph + Osh + Ogs

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answer 4

Explanation:

The Geiger-Marsden experiment was a series of experiments conducted by Ernest Marsden and Hans Geiger in 1909 that helped to explain the structure of atoms.

The experiment involved firing alpha particles at a thin sheet of gold foil and measuring the angles at which the particles were deflected.

The results of the experiment were unexpected: some of the alpha particles were deflected at large angles, and a few even bounced back in the direction from which they had come. This result could not be explained by the existing Thomson model of the atom, which proposed that atoms were made up of a positively charged "pudding" with negatively charged electrons scattered throughout.

The Bohr-Rutherford model of the atom, proposed by Niels Bohr and Ernest Rutherford, was able to explain the results of the Geiger-Marsden experiment. According to this model, atoms have a small, dense, positively charged nucleus at the center, with negatively charged electrons orbiting around it in specific energy levels.

The deflection of the alpha particles in the Geiger-Marsden experiment could be explained by the presence of the positively charged nucleus, which caused the alpha particles to deflect or bounce back when they came close to it. This led to the development of the modern atomic model, which includes the concept of energy levels and the specific arrangement of electrons within an atom.

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The charge on the fixed particle is approximately 3.334 μC. To solve this problem, we can use the principles of conservation of energy and Coulomb's law.

Charge of the released particle, q = +3.5 μC

Distance between the particles initially, r1 = 2.0 m

Distance the released particle moves, r2 = 1.0 m

Kinetic energy of the released particle, KE = 35 mJ = 35 × 10^-3 J

We can determine the work done by the electrostatic force as the released particle moves from distance r1 to r2. The work done is equal to the change in potential energy.

The change in potential energy is given by:

ΔPE = PE2 - PE1

where PE2 is the potential energy of the system at distance r2 and PE1 is the potential energy of the system at distance r1.

The potential energy due to the electrostatic force between two charged particles is given by:

PE = k * (|q1 * q2|) / r

where k is the Coulomb's constant (8.99 × 10^9 N m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

At distance r1:

PE1 = k * (|q1 * q2|) / r1

At distance r2:

PE2 = k * (|q1 * q2|) / r2

The work done is then:

ΔPE = PE2 - PE1 = k * (|q1 * q2|) * (1/r2 - 1/r1)

Since the released particle is initially at rest, its initial total mechanical energy is zero. Therefore, the work done by the electrostatic force is equal to the change in kinetic energy:

ΔPE = KE

Substituting the given values:

k * (|q1 * q2|) * (1/r2 - 1/r1) = 35 × 10^-3

Solving for |q1 * q2|:

|q1 * q2| = (35 × 10^-3) * (r2 - r1) / k

Now, we can substitute the values and solve for the charge on the fixed particle:

|q1 * q2| = (35 × 10^-3) * (1.0 - 2.0) / (8.99 × 10^9)

|q1 * q2| = -1.167 × 10^-11 C^2

Since the charge of the released particle is q1 = +3.5 μC, we can find the charge of the fixed particle, q2:

|q1 * q2| = |q1| * |q2|

|q2| = |q1 * q2| / |q1|

|q2| = (-1.167 × 10^-11) / (3.5 × 10^-6)

|q2| ≈ -3.334 × 10^-6 C

Since charge cannot be negative, we take the magnitude of |q2|:

|q2| ≈ 3.334 μC

Therefore, the charge on the fixed particle is approximately 3.334 μC.

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The 5-volt reading we can expect between the two test points if the reference lead is on the lowest voltage.

The given data is as follows:

The first test marked voltage = 5 volts

The second test marked voltage = -3.3 volts

Let us assume that the two test points are there is a conductive track between them, the voltage between the two points can be calculated using the voltage difference between the two test points.

The voltage difference between the  two test points is calculated as:

5 volts - (-3.3 volts) = 8.3 volts

If the reference lead is on the lowest voltage, It means that the negative side of the voltmeter is attached to the test point with the lower voltage which is -3.3 volts.

The voltage difference between the  two test points is

8.3 volts - 3.3 volts = 5 volts

Therefore we can conclude that the 5-volt reading we can expect between the two test points.

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The average acceleration of the car as it accelerates from 15 m/s to 25 m/s will be 2.5 m/s².

Average acceleration is the average rate of change of velocity with respect to time. Mathematically -

a = Δv/Δt

Given that a car is traveling at 15 m/s in north direction and in 4 seconds it accelerates to 25 m/s in the north direction only. Therefore, we can write -

initial velocity [u] = 15 m/s

final velocity [v] = 25 m/s

time taken [Δt] = 4 s

The magnitude of the average acceleration can be calculated as follows-

a = Δv/Δt

Δv = v - u = 25 - 15

Δv = 10 m/s

Therefore -

a = 10/4

a = 2.5 m/s².

Therefore, the average acceleration of the car will be 2.5 m/s².

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The moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².

The given parameters;

The moment of inertial of the wheel is calculated as follows;

\(I = I_{hoop} + 3I_{spoke}\\\\I = MR^2\ + \ 3(\frac{1}{3} mL^2)\\\\I = (4.3 \times 0.67^2) \ + \ (0.15 \times 0.67^2)\\\\I = 2.0 \ kgm^2\)

Thus, the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².

"Your question is not complete, it seems to be missing the following information";

find the moment of inertial of the wheel about an axis through its center and perpendicular to the plane of the wheel.

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the initial kinetic energy is equal to the final kinetic energy

The force required to tip the cube is equal to the coefficient of static friction times the weight of the cube.

fx=μs * 87 kg * 9.8 m/s^2

Generally, The cube will start to tip when the net torque about the point of contact between the cube and the floor is equal to zero. The torque is given by:

torque = force x distance from axis of rotation

The distance from the axis of rotation is half the edge length of the cube (0.475m), and the force is the force applied by the person (). Therefore, the torque is:

torque = fx x 0.475

For the cube to tip, the torque due to the person's force must be greater than the maximum torque the friction can provide, which is the friction force times the distance from the axis of rotation.

The maximum torque provided by friction is:

friction torque = friction force x 0.475

Since the friction force is equal to the normal force (mg) multiplied by the coefficient of static friction (μs), the maximum torque provided by friction is:

friction torque = μs * mg * 0.475

where m is the mass of the cube, g is the acceleration due to gravity and μs is the coefficient of static friction between the cube and the floor.

So, we can find the force needed to tip the cube by equating the torque due to the force with that of the friction torque.

Fx*0.475 = μs * m * g * 0.475

Fx= μs * m * g

Fx= μs * 87 kg * 9.8 m/s^2

Note: The coefficient of static friction (μs) is a dimensionless quantity between 0 and 1, it varies depending on the surfaces in contact.

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Answer:

4.3 x 10^16 kg

Explanation:

M = rv^2/G =[90,000 x 5.66^2] / [6.67 x 10^-11]

M = 43,226,446,776,611,694 = 4.3 x 10^16 kg - Ida's mass.

Answer:

Explanation:

the person on top of me was correct 4.3 10^16 i have it in my notes from when i was in school :) so they are right

Answer:

x

Explanation:

The question relates to the energy required to pump water out of the

spout at the top of the triangular prism tank.

The width of the layer of water Δx thick is x m.

Reasons:

The location of the layer Δx m thick = x meters above the bottom

The length of the triangular (cross-section) prism tank = 8 meters

The length of the layer Δx thick layer = 8 meters

From the attached drawing of the cross-section of the tank, we have;

The height of the triangular tank cross-section = 3 meters

The length of the base of the triangular cross-section = 3 meters

By similar triangles, we have;

\(\dfrac{Height \ of \ Tank}{Base \ length \ of \ tank}= \dfrac{Height \ of \ layer \ with \ thickness \ \Delta x }{Width \ of \ layer \ with \ thickness \ \Delta x}\)

Which gives;

\(\dfrac{3}{3} =\dfrac{x}{Required \ width}\)

\(\dfrac{3}{3} =1 = \dfrac{x}{Required \ width}\)

Required width × 1 = x

The required width = x m

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An object moves from point A to point B to point C, then back to point B and then to point C along the line. The distance covered by the moving object is 17 km.The magnitude and direction of the 9 km direction A to C.

Given:

Distance from A to B = 5km

Distance from B to C = 4km

Movement of object = A to B to C + C to B + B to C

Movement is in straight line

What is distance?

Distance is referred to the total path or way covered by any object in its entire motion.

Distance comes in the list of scalar quantities.

It only has magnitude.

What is displacement?

(a)Displacement is referred as the straight line joining the start and end points of any body's motion.

It is independent of the total path.

It is a vector quantity and has magnitude as well as direction.

In the given figure:

A to B to C = (5+4) = 9 km

C to B = 4 km

B to C = 4 km

Distance covered = total path covered in its motion =  A to B to C + C to B + B to C = 9 + 4 + 4 = 17 km

(b) Initial point of body = A = 0 km

Final point of body = C = 9 km

Displacement of the body = A to C = (9 - 0) km= 9 km

displacement 9 km

direction A to C

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The distance from the central bright fringe to the 3rd dark fringe is approximately 0.48 cm.

Solution

The distance between the central bright fringe and the 3rd dark fringe in a double-slit experiment is given by:

y = (m * λ * L) / d

If y denotes the distance between the edges,

m is the fringe order (an integer value representing the number of bright or dark fringes away from the central fringe),

λ is the wavelength of the light,

L is the length between the two slits.

The distance between the two slits is given by d.

Substituting the given values, we get:

y = (3 * 600 nm * 150 cm) / 3.55 μm

y = 4800 nm

Converting nanometers to centimeters, we get:

y = 4800 nm * (1 cm / 10^7 nm)

y = 0.48 cm

Therefore, the distance from the central bright fringe to the 3rd dark fringe is approximately 0.48 cm.

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Polaris, which is the tip of the handle of the Little Dipper or the tail of the little bear in the constellation Ursa Minor, is indicated by the two stars at the end of the Dipper's "cup."

Polaris, the North or Pole Star, is by far the most important and well-known star in Ursa Minor. The star at the very end of the bear's lengthy tail is this. Polaris is significant because it is practically immediately over the North Pole. This means you can use it as a compass to locate your way north.

The Indian name for the constellation Ursa Minor is Laghu Saptharishi where 'Laghu' means 'Small'. The name is sequential with the name Saptharishi for the constellation Ursa Major.The Ursa Minor Dwarf is a dwarf spheroidal galaxy discovered during the Palomar Sky Survey in 1955 by A.G. Wilson of the Lowell Observatory in the United States. It is a Milky Way satellite galaxy that may be found in the constellation Ursa Minor.

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Answer:

The force is doubled as well.

Explanation:

If you double the spring then the force doubles as well.

If the deflection of the spring is doubled, the force exerted by the spring will also be doubled.

The relationship between the deflection of a spring and the force it exerts is described by Hooke's Law, which states that the force exerted by a spring is directly proportional to its deflection. Mathematically, this can be expressed as:

F = kx

where F is the force exerted by the spring, x is the deflection of the spring, and k is the spring constant, which represents the stiffness of the spring.

If we double the deflection of the spring, then x becomes 2x, and the force exerted by the spring becomes:

F = k(2x) = 2kx

Thus, if the deflection of the spring is doubled, the force exerted by the spring will also be doubled (assuming the spring constant remains constant).

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Answer:

180.7km/hr²

Explanation:

Given parameters:

Initial velocity  = 10miles/hr

Final velocity  = 25miles/hr

Time taken = 5minutes

     To hr

               60min  = 1hr

               5min gives 0.083hr

Unknown:

Acceleration  = ?

Solution:

To solve this problem,

   Acceleration  = \(\frac{v - u}{t}\)  

v is the final velocity

u is the initial velocity

  Acceleration  = \(\frac{25 - 10}{0.083}\)   = 180.7km/hr²

According to conservation of energy, the energy of interacting bodies in a closed system remains constant. The total energy of an isolated system remains constant; it is said to be conserved over a period of time.

Elastic energy is the mechanical implicit energy stored in the configuration of a material or physical system as it's subjected to elastic distortion by work performed upon it. Elastic energy occurs when objects are impermanently compressed, stretched or generally misshaped in any manner.

The mechanical energy is never lost forever , rather it gets converted to thermal energy because of the friction .

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The three forces that you exert while riding a bicycle would be the gravitational force, frictional force, and the resistance force of the air.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem we have to list the three forces that you exert when riding a bicycle.​

Thus, three forces that you exert while riding a bicycle would be the gravitational force, frictional force, and the resistance force of the air.

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The Bicyclist's Acceleration is 2.7 m/s2. Thus, Option C is the answer

The bicyclist's acceleration can be found using the equation:

acceleration = (final velocity - initial velocity) / time

In this case, the final velocity is 12.15 m/s, the initial velocity is 0 m/s (since the bicyclist starts from rest), and the time is 4.5 seconds. Plugging these values into the equation, we get:

acceleration = (12.15 m/s - 0 m/s) / 4.5 seconds

acceleration = 2.69 m/s2

Therefore, The correct answer is c. 2.7 m/s2

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