A restaurantis planning to make changes to its menu. In order to decide which potential menu items are most popular with the city's population, the owners will conduct a survey. Which survey methods would produce a representative sample of the city's population

Answer:

Thats going to be 12x

Step-by-step explanation:

Answer:

tan B = 5/12

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side/ adj side

tan B = 5/12

Answer:the third one I suppose

Step-by-step explanation:

Answer:

24496

Step-by-step explanation:

40912 * (1-5%) ^10 = 24495.5

becuase they are humans, so round up to 24496

Answer:

I think it's (B)

Step-by-step explanation:

Answer:

x-int: -0.5; y-int: 1

Step-by-step explanation:

We see the intercepts in the graph.

The y-intercept is at 1.

The x-intercept is at -0.5.

Answer: x-int: -0.5; y-int: 1

Answer:

-11

Step-by-step explanation:

See the picture for your understanding.

Since a and b are oppoiste angles of 80° and 60° respectively

a = 80°

b = 60°

Since sum of three angles in a triangle is 180°

x + 51 + 60° + 80° = 180°

x = -11

The exact volume of the region in the first octant cut from the solid sphere ρ < 5 by the half planes θ = π/6 and θ = π/3 is (125π - 125√3)/12.

To find the volume of the region in the first octant cut from the solid sphere ρ < 5 by the half planes θ = π/6 and θ = π/3, we need to integrate over the appropriate region in spherical coordinates.

The region in the first octant that is cut by the half planes θ = π/6 and θ = π/3 forms a wedge-shaped region. In spherical coordinates, the limits of ρ, θ, and φ for this wedge-shaped region are as follows:

ρ: 0 to 5 (since ρ < 5) θ: π/6 to π/3 (the region between θ = π/6 and θ = π/3) φ: 0 to π/2 (since we are in the first octant) To find the volume, we integrate ρ2 sin(φ) dρ dθ dφ over this region:

V = ∫∫∫ ρ2 sin(φ) dρ dθ dφ Integrating with the appropriate limits: V = ∫[θ=π/6 to π/3] ∫[φ=0 to π/2] ∫[ρ=0 to 5] ρ2 sin(φ) dρ dθ dφ

Simplifying the integration: V = ∫[θ=π/6 to π/3] [sin(φ)/3 ρ3] |[ρ=0 to 5] dθ dφ V = ∫[θ=π/6 to π/3] (125/3) sin(φ) dθ dφ

Now integrating with the appropriate limits:

V = (125/3) [-1/2 + √3/2] [φ] |[φ=0 to π/2]

V = (125/3) [-1/2 + √3/2] (π/2)

V = (125/3) [π/2] [-1/2 + √3/2]

V = (125/3) [π/4 - (√3)/4]

V = (125π - 125√3)/12

Therefore, the exact volume of the region is (125π - 125√3)/12.

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Sample 1: Mean=10.01, Standard deviation=13.90 Sample 2: Mean

=11.43, Standard deviation

=14.10

Sample size of 1st year = n1

= 1012Mean of 1st year sample

= X1 = 10.01Standard deviation of 1st year sample

= s1

= 13.90Sample size of 2nd year

= n2

= 1012Mean of 2nd year sample

= X2

= 11.43

Standard deviation of 2nd year sample = s2

= 14.10 Let us assume a significance level of α = 0.05, which implies that the critical region consists of 2.5% in both tails (since it is a two-tailed test).

Therefore, we do not have sufficient evidence to conclude that the mean number of hours per week spent on the Internet differs between 2010 and another year.

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Answer:

x=30°

Step-by-step explanation:

x +2x+3x=6x

since triangles are 180° in total. 6/180=30

so 30° is your answer.

Answer:

Okay

but where is the question ????

Answer:

what question lol

Step-by-step explanation:

6 hours long is a job for which both companies will charge the same amount and the cost will be $410.

a) Let 'x' stand for the number of hours required to complete the task.

350 + 10x = 300 + 15x

350-300=15x-10x

50=5x

x=6

Thus both the companies will charge the same for a task that takes 6hours.

b) The price will be 350+10(6) =  

=350+60

= $410

How to simplify  algebraic expression?

Finding a simplified version of an expression is the act of simplifying it. In order to factor or simplify the phrase, we also need to know how to combine like terms and factor a number in addition to the order of operations.

You gather the variables with the same degree that are like terms, or together. The constant terms should be separated to provide simplification.

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Answer:

The answer is 4/1 or simplified it would be 4.

Step-by-step explanation:

The rise is 4 and the run is 1. 4/1!

Answer:

I think the correct answer is Mode for the first blank and Median for the second blank.

I hope this helps!

Answer

(x + 2)² + 6 = 0

Explanation

We are asked to express the quadratic equation in its completed square form.

The way to do this is to add and subtract the square of the half of the coefficient of x from the left hand side.

Coefficient of x = 4

Half of the coefficient of x = (4/2) = 2

Square of the half of the coefficient of x = 2² = 4

x² + 4x + 10 = 0

x² + 4x + 4 - 4 + 10 = 0

x² + 4x + 4 + 6 = 0

x² + 2x + 2x + 4 + 6 = 0

x(x + 2) + 2 (x + 2) + 6 = 0

(x + 2) (x + 2) + 6 = 0

(x + 2)² + 6 = 0

Hope this Helps!!!

The number of months before the due date was the discount date is 6.67.

Given:A $2000.00 note bearing interest at 10% compounded annually Discount rate of 12% compounded semi-annuallyProceeds = $1900.00To find:

Solution: Let’s calculate the present value of the note.

We know that,

P = A/(1 + R/N)^(Nt)

Here,

P = Present value

A = Future value

R = Rate of interest

N = Compounding period

t = Time in years

A = $2000R = 10%

N = 1 (Compounded annually)

t = 5 years

Now,P = 2000/(1+ 10%/1)^(1×5) = $1296.21

Now let’s calculate the number of months before the due date was the discount date.Using the formula for semi-annual compounding,

P = A/(1 + R/N)^(Nt)Here,

P = $1900.00A

= $1296.21R

= 12%N = 2 (Compounded semi-annually)t

= (n/12) months Let’s assume the discount date is n months before the due date.

Now,P = A/(1 + R/N)^(Nt)1900

= 1296.21/(1 + 12%/2)^(2n/12)19/12

= 1/(1 + 6%/2)^(n/6)

We know that, (1 + 6%/2)

= 1.03^2

= 1.0609.(1.0609)^(n/6)

= 12/19n/6

= log(12/19) / log(1.0609)

= 6.67 months (approximately)

Therefore, the discount date was 6.67 months before the due date.

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The lower bound of the confidence interval is 0.55.

A confidence interval for a proportion is a range of values that is likely to contain a population proportion with a certain level of confidence.

Construct a confidence interval of the population proportion at the given level of confidence x equals = 540, n equals = 900, 96% confidence.

The value of p is;

\(\rm p=\dfrac{x}{n}\\\\p =\dfrac{540}{900}\\\\p=0.6\)

The standard error of the proportion is:

\(\rm \sigma_p=\sqrt{\dfrac{p(1-p)}{n}} \\\\ \sigma_p=\sqrt{\dfrac{0.6(1-0.6)}{540}} \\\\ \sigma_p=\sqrt{\dfrac{0.6\times 0.4}{540}} \\\\ \sigma_p=\sqrt{\dfrac{0.24}{540}} \\\\ \sigma_p=\sqrt{0.00044}\\\\ \sigma_p=0.02\)

The critical z-value for a 94% confidence interval is z = 2.04

The margin of error (MOE) can be calculated as:

\(\rm Margin \ of \ error=\sigma_p \times z =2.04 \times0.02 =0.04\)

Then, the lower bound of the confidence interval is;

\(Lower \ bound =p-x\times \sigma_p=0.6-0.04=0.55\)

Hence, the lower bound of the confidence interval is 0.55.

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To find the total number of students Mrs. Martinez teaches, we need to add the number of students in both of her classes. We are given that there are 12 women and 14 men in her first class, and 11 women and 17 men in her second class.

Therefore, we can add the number of women and the number of men in each class separately and then add the totals to get the final answer.Number of women in the first class = 12 Number of men in the first class = 14 Number of women in the second class = 11 Number of men in the second class = 17 To find the total number of students in the first class, we add the number of women and men:

Total number of students in the first class = 12 + 14 = 26 Similarly, to find the total number of students in the second class, we add the number of women and men:Total number of students in the second class = 11 + 17 = 28 To find the total number of students that Mrs. Martinez teaches, we add the number of students in both of her classes: Total number of students = 26 + 28 = 54

Therefore, Mrs. Martinez teaches 54 students altogether.

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Data were collected for 1 quantitative variable(s). yes, It is appropriate to say that a stem and leaf plot for this type of data. The stem and leaf plot has right skewed shape curve.

From the above data that were collected for one quantitative variable. Yes, it is appropriate to say that to make a stem and leaf for this type of data and number of variables.

Stems               |         Leaves

    5                   |     2, 6, 1, 2, 4, 8, 0, 9, 7

     6                  |       7, 7, 5, 2, 0, 5, 8 , 8

     7                  |          8,    4,   7,   1 and   8

     8                  |             9   , 4,    8

      9                 |                8,    9

Also, the shape of the stem and leaf plot is right skewed curve.

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Step-by-step explanation:

Refer to attachment.

Hope it helps.

Answer: so there for the answer is 498

Step-by-step explanation:

The statement "If two events are independent, P(AIB)-P(B)" is false. The correct statement is: "If events A and B are independent, then P(A and B) = P(A) × P(B)."

The statement "If two events are independent, P(AIB)-P(B)" is incorrect. In fact, the correct formula for the probability of the intersection of two independent events is P(A and B) = P(A) × P(B).

When events A and B are independent, it means that the occurrence of one event does not affect the probability of the other event. In this case, the probability of both events A and B happening is equal to the product of their individual probabilities.

So, the correct statement should be: "If events A and B are independent, then P(A and B) = P(A) × P(B)." This formula reflects the fundamental concept of independent events, where the probability of their intersection is simply the product of their individual probabilities.

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LHS :-

Answer:

6%

Step-by-step explanation:

Given,

Interest (I) = 2160

Principal (P) = 12000

Time (T) = 3 yrs

Rate (R) = ?

We know that,

R = ( I *100)/ (P*T)

= (2160*100)/(12000*3)

= 6%

therefore, the rate of interest is 6%

Answer:

64 cm

Step-by-step explanation:

To find the volume, you should multiply length by width, and then by height or 4 x 4 = 16, then 16 x 4 = 64

The latest time for pickup, found by converting the 150 minutes maximum time provided by the school, from minutes to hours is about 5:45 pm

Minutes can be converted into hours by dividing the number of minutes by 60, which is the number of minutes in an hour.

The time that school ends = 3:15 pm

The latest time for pick up after school care = 150 minutes after school ends

Therefore, the latest time for pick up after school care = 3:15 pm + 150 minutes

60 minutes = 1 hour

150 minutes = (1/60) × 150 = 2.5

The latest for pick up = 3:15 pm + 2.5 hours = 5:45 pm

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Answer:

3:20

Step-by-step explanation:

Hipe this helps x

Ugh its not letting me senddd

Answer:

V = hpi(r)^2

 =  20(3.14)(17)^2 = 18,149.20 cubic mm

More accurately,

V = 20(3.14159)(17)^2 = 18158.39 mm^3

Step-by-step explanation: