A resistor with resistance R is connected to a battery that has emf 16.0V and internal resistance r = 0.380 ohm.
For what two values of R will the power dissipated in the resistor be 79.0W ?

Answer:

A

Explanation:

since it did not absorb the heat then it is an insulator

The magnitude of the force (in n) that the third block applies on the second block is 140N

To determine the magnitude of the force that the third block applies on the second block, we first need to find the acceleration of the blocks.

Using Newton's Second Law (F = ma), we can calculate the acceleration of the smallest block:

35 N = 5 kg * a

a = 7 \(m/s^{2}\)

Since the second and third blocks are connected by a rope, they will have the same acceleration as the smallest block.

Next, we can calculate the force that the third block applies on the second block using the equation F = ma:

F = 20 kg * 7 \(m/s^{2}\)

F = 140 N

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Answer:

2 to 4 hours

Explanation:

Given that,

Microbial food infections

We know that,

Food infection :

When we eat old food, uncooked, fermented food, more junk food and contaminated food then 2 to 4 hours after eating we started vomiting, headache then we affected by food infections.

So, we can say that microbial food infections are usually not seen until 2 to 4 hours after eating contaminated food.

Answer:

0.0227528381

Explanation:

2.389/105

(a) In a parallel-flow arrangement, the outlet temperature of the water and the air can be determined using the energy balance equation. The heat transfer rate between the water and the air is equal to the product of the water mass flow rate, specific heat capacity of water, and the change in temperature of the water:

Similarly, the heat transfer rate between the air and the water is equal to the product of the air mass flow rate, specific heat capacity of air, and the change in temperature of the air:

Since the heat exchanger is operating under fully-developed flow conditions, the outlet temperature of the water and the air can be found by equating the heat transfer rates:

By substituting the given values, including the specific heat capacities of water and air, and solving the equations, the outlet temperatures of the air and water can be calculated.

(b) In a counter-flow arrangement, the outlet temperatures of the air and water can be determined using a similar energy balance equation. However, in this case, the change in temperature of the air is taken as the difference between the outlet and inlet temperatures of the air:

Again, by equating the heat transfer rates, substituting the given values, and solving the equations, the outlet temperatures of the air and water in a counter-flow arrangement can be calculated.

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Answer:

   q = 224 mm,   h ’= - 98 mm, real imagen

Explanation:

For this exercise let's use the constructor equation

        \(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)

where f is the focal length, p and q are the distance to the object and the image respectively.

In a mirror the focal length is

        f = R / 2

indicate us radius of curvature is equal to the diameter of the eye

       R = 3,50  10² mm

       f = 3.50 10² /2 = 1.75 10² mm

they also say that the distance to the object is p = 0.800 10³ mm

        1 / q = 1 / f - 1 / p

        1 / q = 1 / 175 - 1 /800

        1 / q = 0.004464

         q = 224 mm

to calculate the size let's use the magnification ratio

          m = \(\frac{h'}{h} = - \frac{q}{p}\)

          h '= \(- \frac{q}{p} \ h\)

          h ’= - 224 350 / 800

          h ’= - 98 mm

in concave mirrors the image is real.

Answer:

Explanation:

It means that while we live, we are obligated to get the most out of living. If we do not, then we are dying a spiritual death -- one that robs us of seeing hearing tasting everything that we can and experience everything we can.

If we fail to do that, we are spiritually dead, which means that we live a life without meaning. We are worse than being physically dead. We are like Zombies that take in nothing.

Answer:

What's the question?

Explanation:

If the star radiates uniformly in all directions, the total power output of the star is 2.37 x 10²⁷ W.

The formula for the intensity of the light at a distance R from the source of light (which is star in this case) is given by,

I = P/A

I is the intensity,

P is the power,

A is the area.

We can write,

P = IA

Intensity is given to be 15.4 W/m².

A = πR²

Here, we will take the value of R is 7 x 10¹² m.

So,

A = π( 7 x 10¹²)²

Putting the values,

P = IA

P = 15.4 x π x ( 7 x 10¹²)²

P = 2.37 x 10²⁷ W.

The power output of the star is 2.37 x 10²⁷ W.

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Answer: If Maxwell's wheel were to rotate twice as fast, its kinetic energy would increase by a factor of four. This is because the kinetic energy is proportional to the square of the angular velocity.

Explanation:

I'm assuming that you are referring to a specific laboratory experiment or problem. However, you haven't provided any details about the experiment or the given information. Please provide me with the necessary information to answer your questions.

However, I can provide you with some general information that may help you solve your problem.

To find the angular velocity of the wheel when it is fully unwound, you can use the conservation of energy principle. The initial energy of the system is equal to the final energy of the system. The initial energy is the potential energy stored in the spring, which is given by ½kx², where k is the spring constant and x is the displacement of the spring. The final energy is the rotational kinetic energy of the wheel, which is given by ½ Iω², where I am the moment of inertia of the wheel and ω is the angular velocity. Setting these two energies equal, you can solve for ω.

To compute the downward acceleration of a falling wheel of the same shape and size but made of a different material which is three times as heavy, you need to use the equation for the gravitational force, which is given by F = mg, where m is the mass of the object and g is the acceleration due to gravity. Since the mass of the wheel is three times as heavy, the gravitational force acting on it will also be three times as heavy. Therefore, the downward acceleration will be the same as that of a wheel of normal weight.

If the radius of the axle of Maxwell's wheel is reduced to ½ the measured value, whereas the disk remains the same, the moment of inertia of the wheel will decrease. This is because the moment of inertia is proportional to the square of the radius. Therefore, the downward acceleration will be bigger. The exact value of the acceleration will depend on the new moment of inertia of the wheel.

To find a value a that is accurate to within a few percent, you need to provide me with the necessary information about the experiment or the problem.

The ratio of the moments of inertia of a disk and a hoop of the same radius and mass is ½. This can be derived using the formula for the moment of inertia of a disk (½mr²) and a hoop (mr²) and dividing the moment of inertia of the hoop by the moment of inertia of the disk.

If Maxwell's wheel were to rotate twice as fast, its kinetic energy would increase by a factor of four. This is because the kinetic energy is proportional to the square of the angular velocity.

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Given :

A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground.

The kinetic frictional force between the plow and the field is 250 N.

To Find :

The Normal Force from the ground onto the plow.

The acceleration of the plow.

Solution :

Normal force = mg + F sin Ф

= 75×10 + 700 × sin 35°

= 1151.50 N

Now,

ma = 700 cos Ф - 250

75×a = 323.4

a = 4.31 m/s²

Hence, this is the required solution.

Answer:

In geometry, parallel lines are lines in a plane which do not meet; that is, two straight lines in a plane that do not intersect at any point are said to be parallel. Colloquially, curves that do not touch each other or intersect and keep a fixed minimum distance are said to be parallel.

In a series circuit, the current that flows through each of the components is the same, and the voltage across the circuit is the sum of the individual voltage drops across each component. ... In a series circuit, every device must function for the circuit to be complete.

In a series circuit, all components are connected end-to-end, forming a single path for current flow. In a parallel circuit, all components are connected across each other, forming exactly two sets of electrically common points.

Explanation:

I hope these helps^,^      ^_^

The initial separation d between the mass and the spring is 0.14m.

A m = 2.88kg mass starts from rest and slides a distance d down a frictionless θ = 34.7° incline. While sliding, it comes into contact with an unstressed spring of negligible mass. The mass slides an additional 0.185m as it is brought momentarily to rest by compression of the spring (k = 409N/m).

The initial separation d between the mass and the spring can be calculated using the equation:

d = (2*m*g*sin(θ)) / k

Substituting in the given values, we get:

d = (2*2.88kg*9.8m/s2*sin(34.7°)) / 409N/m

d = 0.14m

Therefore, the initial separation d between the mass and the spring is 0.14m.

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Answer:

Explanation:

There are three states of matter; solid, liquid and gaseous states.

The solid state of matter has it's particles tightly packed with very restricted  or no movement within the molecule hence the reason for it's definite shape.

The liquid state of matter has it's particles with a free movement (better than solid but not as free as gases) within the molecule hence it's particles are loosely packed within the molecule. Hence, they (liquids) assume the shape of the container in which they are stored and they move freely when released from the container.

The gaseous state of matter has it's particles totally loosely packed as a result of it's particles moving freely and colliding against one another.

Thus, we can use the above descriptions to answer the statements from the question.

1) The atoms in a  ----- are closely packed, but able to slide past each other. Answer: From the description above, it can be deduced that the atoms here are in a solid because the particles within a solid are closely packed.

2) The atoms in a  -------- spread as far apart as possible.

Answer: The atoms here are in gaseous form because, as described earlier, they are loosely packed and  can thus be as far apart as possible.

3) A  ----- has a definite shape and volume.

Answer: As described earlier, a solid substance would have a definite shape and volume because it's particles are tightly packed.

4) The shape of a  ----- can change, but the volume is definite.

Answer: The substance here is a liquid because the particles are free (but not as free as gases) and would have a definite volume but will assume the shape of the any container they are placed in (hence they have an irregular shape).

Answer:

The atoms in a

✔ liquid

are closely packed, but able to slide past each other.

The atoms in a

✔ gas

spread as far apart as possible.

A

✔ solid

has a definite shape and volume.

The shape of a

✔ liquid

can change, but the volume is definite.

Explanation:

The decibel level of the sound noise that we will hear is the sum of the decibel level of the two speakers. Thus the sound power will be 190 dB.

The formula for sound power is:

Sound Power (P) = I * A

Where,

I = intensity

A = the surface area of the sphere (A = 4πr²)

The formula for decibels is:

D = 10 * log(P₁/P₂)

Where,

P₁ is the initial power

P₂ is the final power

Therefore,

Sound Power of the first speaker (P₁) = 0.625 Watts

Sound Power of the second speaker (P₂) = 0.258 Watts

Distance from the first speaker = 7.8 meters

Distance from the second speaker = 4.3 meters

Radius of the first sphere (r₁) = 7.8 meters

Radius of the second sphere (r₂) = 4.3 meters

Surface Area of the first sphere (A₁) = 4π(7.8)²

= 1928.61 m²

Surface Area of the second sphere (A₂) = 4π(4.3)²

= 232.83 m²

Using the formula of intensity above,

The intensity of the sound for the first speaker (I₁) = P₁ / A₁= 0.625 / 1928.61

= 0.000324 watts/m²

The intensity of the sound for the second speaker (I₂) = P₂ / A₂

= 0.258 / 232.83

= 0.001107 watts/m²

Using the formula for decibels,

The decibel level of the first speaker (D₁) is,

D₁ = 10 * log(I₁ / (1E-12))

= 10 * log(0.000324 / (1E-12))

= 89.39 dB

The decibel level of the second speaker (D₂) is,

D₂ = 10 * log(I₂ / (1E-12))

= 10 * log(0.001107 / (1E-12))

= 100.37 dB

Therefore, the decibel level of the sound noise that we will hear is the sum of the decibel level of the two speakers, i.e.,D = D₁ + D₂= 89.39 + 100.37= 189.76 ≈ 190 dB

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Option A is correct. The resultant quantity is 50m/s to the right.

Vector quantities are quantities that have both magnitude and direction.

From the diagram shown,  we can see that 100m/s vector moves in the positive x-direction, this means that the  of magnitude the vector is +100m/s.

For the vector 50m/s, we can see that it is moving in the negative x-direction, this shows that the magnitude of the 50m/s vector is -50m/s.

Resultant speed = +100 - 50

Resultant speed = +50m/s

Since the resultant speed is a positive value, this mean that the resultant quantity will be moving towards the right.

Hence the correct option will be 50m/s to the right.

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a)  Marcy's momentum just as she jumps is 75 Ns, and her velocity is 12.5 m/s.

b) Marcy jumps with a speed of 12.5 m/s.

c) Since the Earth is so massive compared to Marcy, its velocity is negligible and can be assumed to be zero.

d) Marcy experiences a force of approximately 29.41 N when she lands.

a) To calculate the value of the momentum of Marcy, we can use the formula: p = mv

where p is momentum, m is the mass of the body, and v is the velocity of the cat.

The impulse will be: J = Ft

where J is the impulse, F is the force, and t is the time for which the force is applied.

Substituting the given values, we get:

J = 50 N * 1.5 s = 75 Ns

Therefore, her final momentum just as she jumps is:

p = J = 75 Ns

Substituting the given mass of Marcy, we get:

p = m*v

75 Ns = 6 kg * v

v = 12.5 m/s

b) To calculate Marcy's speed as she jumps, we use the same velocity we calculated above. Therefore, Marcy jumps with a speed of 12.5 m/s.

c) To calculate the Earth's speed just as Marcy jumps, we need to consider conservation of momentum.

Since the Earth is much more massive than Marcy, its velocity does not change significantly when Marcy jumps.

Therefore, the initial momentum of the Earth and Marcy is zero, and the total momentum just as Marcy jumps is:

p_total = m_Marcy * v_Marcy

where m_Marcy is the mass of Marcy and v_Marcy is her velocity.

The momentum of the Earth is zero, so the total momentum just as Marcy jumps is entirely due to Marcy's momentum.

Therefore, we have:

p_total = m_Marcy * v_Marcy = 6 kg * 12.5 m/s = 75 kg m/s

Since the total momentum is conserved, the final momentum is also 75 kg m/s. Therefore, after Marcy jumps, the Earth has a velocity such that its momentum is also 75 kg m/s.

Since the Earth is so massive compared to Marcy, its velocity is negligible and can be assumed to be zero.

d) When Marcy lands, she experiences an impulse that changes her momentum. Since she lands with the same speed she jumped with, her change in momentum is:

Δp = mv - m0 = m*v

where m is the mass of Marcy and v is her velocity. The time for which Marcy experiences this impulse is the time she spends in the air, which is 2.55 seconds.

Therefore, the force that Marcy experiences is given by:

F = Δp/t = m*v/t = 6 kg * 12.5 m/s / 2.55 s = 29.41 N

Therefore, Marcy experiences a force of approximately 29.41 N when she lands.

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Because the radiant of the Lyrid meteor shower is located in the constellation Lyra, one can conclude that the meteors in this shower are named after the constellation where they appear to originate.

Radiant is the point in the sky where the meteors appear to be coming from, and it is used to identify the specific meteor shower. When the Earth passes through the debris left by a comet or asteroid, the tiny particles collide with our atmosphere, causing the meteor shower. The Lyrid meteor shower is caused by the Earth passing through the debris left by Comet Thatcher.

Constellations are groupings of stars that are used to help navigate the night sky. The constellation Lyra is a small constellation that is easily recognizable by its bright star Vega. The Lyrid meteor shower occurs annually in late April when the Earth passes through the debris left by Comet Thatcher.

Observers can see around 10-20 meters per hour during this time. So, in conclusion, the radiant of the Lyrid meteor shower being in the constellation Lyra allows for the identification and naming of the meteor shower.

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The four methods of acquiring knowledge are observation, experience, reasoning, and education.

Observation involves gathering information through the senses and paying attention to what is happening in the environment. Experience involves learning through personal encounters, such as practical work or life events. Reasoning involves using logic and critical thinking to draw conclusions and make decisions.

Education involves acquiring knowledge through formal instruction and learning, such as in a school setting or through reading and studying. All four methods are important and can be used in combination to acquire a deep and well-rounded understanding of a subject.

Observation and experience provide hands-on and practical knowledge, while reasoning and education provide theoretical and abstract knowledge. By using a combination of these methods, individuals can broaden their understanding and knowledge of the world around them.

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a) Sketch the plate shape: we get a shape that resembles a trapezoid.

The plate shape is determined by the lines y = 2 - x² and y = 2x - 1. To sketch the plate shape, we can plot these two lines and shade the region in between them. The intersection points of the lines are found by solving the equations simultaneously:

2 - x² = 2x - 1

Simplifying, we get:

x² + 2x - 3 = 0

Factoring, we have:

(x - 1)(x + 3) = 0

So, x = 1 and x = -3. Plugging these values into the equations of the lines, we find the corresponding y-values:

For x = 1:

y = 2 - (1)² = 1

For x = -3:

y = 2(-3) - 1 = -7

Plotting these points and connecting them with the lines, we get a shape that resembles a trapezoid.

b) Total charge through the double integral:

To find the total charge Q, we need to integrate the charge density p(x, y) over the entire plate. We can express this as a double integral:

Q = ∬ p(x, y) dA

c) Reducing the double integral to repeated integrals: The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.

Since the plate shape is described by the lines y = 2 - x² and y = 2x - 1, we can rewrite the double integral as a repeated integral by integrating with respect to x and y separately:

Q = ∫∫ p(x, y) dy dx

The limits of integration for y are from the lower curve y = 2 - x² to the upper curve y = 2x - 1. The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.

d) Calculating the integral: The total charge Q of the thin plate is approximately 12.4 mC.

Now, we can evaluate the double integral to find the total charge Q:

Q = ∫(-3 to 1) ∫(2 - x² to 2x - 1) x²y dy dx

Performing the inner integral with respect to y first, we get:

Q = ∫(-3 to 1) [x²(y²/2 - y)] from 2 - x² to 2x - 1 dx

Simplifying the inner integral, we have:

Q = ∫(-3 to 1) [(x²/2)(2 - x²) - x²(2x - 1)] dx

Expanding and simplifying further, we get:

Q = ∫(-3 to 1) (x² - x⁴/2 - 4x³ + 2x²) dx

Integrating term by term, we have:

Q = [x³/3 - x⁵/10 - x⁴ + 2x³/3] from -3 to 1

Evaluating the integral at the limits, we get:

Q ≈ 12.4 mC (rounded to five significant figures)

Therefore, the total charge Q of the thin plate is approximately 12.4 mC.

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The answer is  0.48 kg m^2

Given,

m1 = 0.2 kg

m2 = 0.3 kg

L = 2 m

Let the centre of mass is at a distance d from 0.2 kg.

So, m1 x d = m2 x (L - d)

0.2 x d = 0.3 x (2 - d)

2 d = 6 - 3d

5 d = 6

d = 1.2 m

Moment of inertia about the centre of mass,

I = m1 x d^2 + m2 x (L - d)^2

I = 0.2 x 1.2 x 1.2 + 0.3 x 0.8 x 0.8

I = 0.288 + 0.192

I = 0.48 kg m^2

All bodies have a tendency to resist changes to their current states, according to Newton's second law. A body in motion resists change by not coming to a complete halt right away, just as a body at rest resists change when it is put into motion. Similar to this, a rigid body's rotational inertia refers to the amount of torque necessary to modify the angular velocity of the body.

The concept of a rigid body's rotational inertia is crucial since it clarifies how much torque is needed to accomplish a certain goal. The mass of a rigid body and its distribution with regard to the axis around which it rotates have an impact on its rotational inertia.

The distance of the centre of mass from the axis of rotation increases or decreases the rotational inertia of a rigid body.

m1 x d = m2 x (L - d)

I=13mL2 I = 1 3 m L 2 is the moment of inertia for a rod that spins about an axis perpendicular to the rod and passing through one end. The moment of inertia is I=112mL2 if the axis of rotation passes through the middle of the rod.

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Assuming you are supposed to write each conversion in scientific notation:

(2) 1 m = 100 cm, so

(67 cm) × (1/100 m/cm) = 67/100 m = 0.67 m = 6.7 × 10 ⁻¹ m

(3) 1 km = 1,000 m, so

(1.2 km) × (1000 m/km) = 1200 m = 1.2 × 10³ m

(4) 1 m = 1,000 mm = 10³ mm, so

(6.2 × 10 ⁻³ m) × (10³ mm/m) = 6.2 mm

(5) 1 m = 1,000,000,000 nm = 10⁹ nm, so

(4.05 × 10³ nm) × (1/10⁹ m/nm) = 4.05 × 10 ⁻⁶ m

(6) 1 g = 1,000,000 µg = 10⁶ µg, so

(3200 µg) × (1/10⁶ g/µg) = 3200 × 10 ⁻⁶ g = 3.2 × 10 ⁻³ g

Answer:

\(F=3.53\times 10^{22}\ N\)

Explanation:

Given that,

Mass of the Sun, \(m_1=1.99\times 10^{30}\ kg\)

The distance of Sun from the Earth, \(r=150\times 10^9\ m\)

We know that,

The mass of the Earth, \(m_2=6\times 10^{24}\ kg\)

We need to find the gravitational force between the Sun and the Earth.

The formula between two masses is given by :

\(F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1.99\times 10^{30}\times 6\times 10^{24}}{(150\times 10^9)^2}\\\\F=3.53\times 10^{22}\ N\)

So, the gravitational force between the Sun and the Earth is \(3.53\times 10^{22}\ N\)

Answer:

O Black

Explanation:

Black because black is the absence of all light.

Answer:

-8Y =6-18

-8Y=-12

Y=-12+8

y=-4

In a stable ecosystem, the number of predators increases if the number of prey increases.

Predators are the species that are dependent upon prey for their foods. predators actually hunt the prey for their food.

predators are the species that depend upon other living species like deer fish goats etc for example lions depend upon deer, zebras, etc.

while the preys are the species who depend upon the plants for their food so if the number of preys will be higher then the number of the predators will also be higher.

Thus In a stable ecosystem, the number of predators increases if the number of prey increases.

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Answer:

1. 2380m

2. 13.6m

3. 132 Hz

Physical rules are observed during star formation, such as conservation of momentum, where accumulations of gas and dust collapse under the influence of gravity and begin to create stars.

The events listed must be in the following order for star formation: Clouds contract when subjected to gravity. The main star produces a breeze. Due to static electricity, lumps are formed. As the angular momentum is conserved, a disk is formed.

Collisions are the origin of planetesimals. As nuclear reactions proceed, stars are born.

The process of star formation takes about a million years from the time the first gas cloud begins to compress to the point where stars form and begin to shine like the sun.

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