A rectangular coil moving at a constant speed v enters a region of uniform magnetic field from the left. while the coil is entering the field, the direction of the magnetic force is upward left.
A magnetic force is a force of attraction or repulsion that acts between two accelerated charged particles that are exerted on one charge by the magnetic field produced by the other charged particle.
For currents in circular or closed loop wires, the right-hand can be used to determine how magnetic fields emerge.The right-hand rule allows us to determine the direction of the magnetic field that the current in the straight wire is radiating.In a rectangular coil the induced emf will remain constant because in this case the rate of change of area in the magnetic field region remains constant whereas in a circular coil the rate of change of area in the magnetic field region is not constant.
In this case, you point with your right thumb in the direction of the current passing through the electrical conductor, and since the a rectangular coil moving at a constant speed v enters a region of uniform magnetic field from the left, the direction of the magnetic force will be upward left.
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Consider a situation where over the course of a 24-mile long run, a runner becomes increasingly tired. In the first hour he runs 12 miles, in the second hour 6 miles, in the third hour 3 miles, and so on, so that each hour he runs half the distance to go. How long will it take to finish the race?
The runner will take a full day to complete the race, assuming he maintains the same pattern of slowing down by half the previous hour's distance each hour.
How did we get this assertion?We can approach this problem by using a formula for the sum of an infinite geometric series, since the distances covered by the runner in each hour form a geometric sequence with a common ratio of 1/2. The formula is:
S = a / (1 - r),
where S is the sum of the series, a is the first term, and r is the common ratio.
In this case, the first term a is 12 miles, and the common ratio r is 1/2. We want to find the total distance S covered by the runner over the entire 24-mile race, so we can set:
S = 12 / (1 - 1/2) = 24
This means that the runner will cover the remaining 12 miles in the final hour, and so the total time taken to finish the race will be:
1 + 1 + 1 + ... (24 times) = 24 hours
So, the runner will take a full day to complete the race, assuming he maintains the same pattern of slowing down by half the previous hour's distance each hour.
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A 682-kg elevator starts from rest and moves upward for 3.10 s with constant acceleration until it reaches its cruising speed, 1.80 m/s.
(a) What is the average power of the elevator motor during this period? (Answer in horsepower)
(b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with
constant speed.) (answer in horsepower)
a) the average power of the elevator motor during this period is 0.1696 hp
b) The power during an upward trip with constant speed is 16.13 horsepower.
To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.
Given:
Mass of the elevator (m) = 682 kg
Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²
Time taken for acceleration (t) = 3.10 s
(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:
d = 0.5 * a * t^2
= 0.5 * 0.5806 m/s² * (3.10 s)^2
= 1.0153 m
Next, we can calculate the work done (W) by the elevator motor:
W = m * a * d
= 682 kg * 0.5806 m/s² * 1.0153 m
= 391.55 J
Now, to find the average power (P), we divide the work done by the time taken:
P = W / t
= 391.55 J / 3.10 s
= 126.36 W
To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.
Therefore, the average power of the elevator motor during this period is:
P = 126.36 W / 745.7
= 0.1696 hp
(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.
The force of gravity (Fg) can be calculated using:
Fg = m * g
= 682 kg * 9.8 m/s²
= 6683.6 N
The power (P) required is given by the formula:
P = Fg * v
= 6683.6 N * 1.80 m/s
= 12030.5 W
To convert the power to horsepower:
P = 12030.5 W / 745.7
= 16.13 hp
Therefore, the power during an upward trip with constant speed is 16.13 horsepower.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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The figure below shows a box with a mass of m = 7.40 kg that starts from rest at point A and slides on a track with negligible friction. Point A is at a height of ha = 5.10 m. An illustration shows a wavy track, starting from a crest, moving to a trough, then again to a crest and trough, and finally to a crest that then moves downward. Three points in the track are highlighted, A, B, and C. Point A is at the top of the track where a box of mass m is placed ready to get released. It is at the height labeled ha from the ground. Point B is shown at the next crest and is at a height of 3.20 meters from the ground. Point C is shown at the following trough and is at a height of 2.00 meters from the ground. (a) What is the box's speed at point B (in m/s)? m/s What is the box's speed at point C (in m/s)? m/s (b) What is the net work (in J) done by the gravitational force on the box as it moves from point A to point C?
Work done by gravity when it moves from A to C will be 288.6 joule
How to calculate the valueApplying conservation of energy between point A and B,
7.4xgx5.9 = 1/2x7.4xv2 + 7.4xgx3.2
873.2 = 7.4v2 + 473.6
v = 7.34 m/s
It should be noted that to find velocity at C, which has come down to a height of 2 meter, it means it has travelled by 5.9-2 =3.9 m
so, v2 = 2gh = 20x3.9 =
v = 8.83 m/s
Work done by gravity when it moves from A to C = mxgx(5.9-2) = 288.6 joule
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phys 181 magnitiude of a vector
The y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.
Y-component of the vectorThe y component of the vector will be determined from the resultant vector and the x component of the vector.
R² = Y² + X²
Y² = R² - X²
Where;
Y is the y-component of the vectorX is the x component of the vectorR is the resultant vectorY² = 85.2² - 76.4²
Y² = 1,422.08
Y = √1,422.08
Y = 37.7 N
Angle between the vectorsθ = arc tan (Y/X)
θ = arc tan (37.7/76.4)
θ = 26.2⁰
Thus, the y component of the vector is 37.7 N and the angle between the vectors is 26.2⁰.
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9. A balloon is filled with 1000 cm3 of a gas weighing 1000 g. Will it rise or fall when it is released?
We can calculate the density of the balloon as follows:
\(\rho=\frac{mass}{volume}=\frac{1000g}{1000cm^3}=\frac{1g}{cm^3}\)Therefore, the balloon will fall
Since the density of air is about 0.00123 g/cm^3 , the balloon is much more dense than the surrounding air. As a result, the balloon weighs more than the air that it displaces so the balloon will fall.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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Which of the following best represents R=A+B ?
A)
B)
C)
Answer:
C
Explanation:
Options A and B are not even pointing in the direction as the vectors in the question so they shouldn't even be considered.
Option C looks like the closes since vectors A and B are pointing in a similar direction (negative x-axis)
The best representation for the resultant vector representing the resultant R=A+B would be option C because the result is represented by the closing side of the triangle, therefore the correct answer would be C.
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out the resultant vector from the sum of vector A and vector B,
The resultant of the vector can be calculated with the help of the triangle law of the vector addition in which the sum is given by the closing side of the triangle.
Thus, the correct answer is option C.
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4. What is the coefficient of x in the expression x + 3y + 2?
A. 0
B. 1
C. 2
D. 3
Answer:
B) 1
Explanation:
There is not a coefficient before x, so automatically the answer is 1
Answer :-
Hi there!
\(\:\mathsf\red{Your\:answer\:is\:B.\:(1)}\)
Explantion :-We know
Coefficient is the number or value which should be putten in front of the variable given.
Here,
'x' is the variable. Before x, there is no number mentioned. So the number would be 1.
\(\:\sf\purple{Hope\:this\:helps\:you!\::)}\)
A wave has an amplitude of 0.0800 m
and is moving 7.33 m/s. One oscillator
in the wave takes 0.230 s to go from
one crest to the next crest. Find the
wavelength of the wave.
(Unit = m)
If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The
wavelength of the wave is 1.69m.
What is the wavelength?The wavelength of a wave can be determined using the equation:
Wavelength = velocity / frequency
To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.
frequency = 1 / time
frequency = 1 / 0.230
frequency ≈ 4.35 Hz
Substitute the values into the wavelength equation:
wavelength = velocity / frequency
wavelength = 7.33 / 4.35
wavelength ≈ 1.69m
Therefore the wavelength of the wave is approximately 1.69 meters.
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with an armature resistance of 0.03 2 and a field resistance of
41.67 2. The motor has compensating windings, so armature
reaction can be ignored. Mechanical and core losses may be
assumed to be negligible for the purposes of this problem. The
motor is assumed to be driving a load with a line current of 126 A
and an initial speed of 1103 r/min. To simplify the problem,
assume that the amount of armature current drawn by the motor
remains constant.
A. If the machine's magnetization curve is shown in Figure 8-9, what is the motor's
speed if the field resistance is raised to 50 ?
B. Calculate and plot the speed of this motor as a function of the field resistance RF
assuming a constant-current load.
R₁ = 0.03 2
EA
IA
IF
IL
RF + Radj
LF
+
250 V
A. The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min
A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:
EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.
Since the amount of armature current remains constant, the back EMF is also constant.
Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:
IF = (250 V - EA)/(RF + R₁)
At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.
If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.
Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:
kϕN/IF1 = kϕN/IF2
N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min
Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:
N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min
where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.
Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.
A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.
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a gardener uses 3500 J of work to push a wheelbarrow for 110 seconds
A. 26.4 W
B. 36.6 W
C. 15.2 W
D. 31.8 W
Answer:
(D)
\(powe r= \frac{work \: done}{time \: passed} \)
power. = 3500J/110S
=31.81818181818JS^-1
=31.8W
Is a neutron positive ornegative
Answer:
neither
Explanation:
Neutrons have no charge and have their name because of their "neutral" charge. Protons are positively charged and electrons are negatively charged.
What type of forces is acting on an object that prevents the object from moving?
use the Group of answer choices
a Balanced forces
b Friction forces
c Gravity forces
d Unbalanced forces
Answer: Friction Forces
Explanation: (I took the same test and got the answer)
_________________________________________
I hope this helps!
What fraction of the total kinetic energy is rotational for the following objects rolling without slipping on a horizontal sur- face? (a) a uniform solid cylinder; (b) a uniform sphere; (c) a thin- walled, hollow sphere; (d) a hollow cylinder with outer radius R and inner radius R>2.
The ratio of their rotational kinetic energies is 4/5 or 0.8.
Let's denote the mass and radius of the cylinder and sphere as "m" and "r", respectively. At the top of the incline, both objects have only potential energy, which is then converted to kinetic energy. At the bottom of the incline, both objects have both translational and rotational kinetic energy.
For a uniform solid cylinder, the rotational inertia is\(1/2 * m * r^2\). For a uniform sphere, the rotational inertia is\(2/5 * m * r^2\). Therefore, the ratio of their rotational kinetic energies is:
(rotational kinetic energy of sphere) / (rotational kinetic energy of cylinder)
\(= (2/5 * m * r^2 * (v/r)^2) / (1/2 * m * r^2 * (v/r)^2)\)
= (4/5)
Therefore, rotational kinetic energy of sphere is 80% of rotational kinetic energy of the cylinder at bottom of the incline.
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--The complete Question is, A uniform solid cylinder and a uniform sphere with the same mass and radius are released from rest at the top of an incline. They both roll without slipping down the incline and reach the bottom with the same translational speed. What is the ratio of their rotational kinetic energies at the bottom of the incline?--
A 15,000 kg railroad car. A, traveling a speed of 32.0 m/s strikes an identical car, B, at rest. If the cars lock together as result of the collision, what is their common speed just afterwards?
The speed of the cars as they stuck together is 16 m/s.
What is the speed after Collison?We know that the momentum after the Collison must be equal to the total momentum before the Collison and thus is what we call the principle of the conservation of linear momentum and that is what we are going to apply here so that it can help us to solve this problem at hand here.
Given that;
Momentum before Collison= Momentum after Collison
Then we have;
( 15,000 kg * 32.0 m/s) + (15,000 kg * 0 m/s) = (15,000 kg + 15,000 kg)v
v = ( 15,000 kg * 32.0 m/s) / (15,000 kg + 15,000 kg)
v = 16 m/s
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Can anyone help with the attached question
The wave front, also known as the wavefront, is an imaginary surface that represents equivalent points of a wave that vibrate in sync. The correct option is D ; 2.0 .
What is a wavefront in physics?A wave front is described as a surface where the wave's phase remains constant. At any one time, all particles of the medium are moving in the same direction along a certain wave front. Two kinds of wave fronts are very essential. They are plane and spherical wave fronts, respectively. A wavefront is a surface on which the wave disturbance is in the same phase at all places. For example, the ripples of water created when a stone is tossed into a pond.
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what is the voltage supplied to a wire that has a resistance of 1200 Q and a current of 0.10 amps
The voltage supplied to the wire is 120 volts.
To calculate the voltage supplied to a wire, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R). Mathematically, this relationship is expressed as V = I * R.
In this case, the wire has a resistance of 1200 Ω (ohms) and a current of 0.10 amps. We can substitute these values into the formula to find the voltage:
V = I * R
V = 0.10 A * 1200 Ω
V = 120 A * Ω
Therefore, the voltage supplied to the wire is 120 volts.
It's important to note that Ohm's Law holds true for resistors and other components in a circuit that obey Ohm's Law. In real-world scenarios, there may be other factors to consider, such as the presence of non-ohmic devices or components with varying resistance.
Additionally, in an AC (alternating current) circuit, the relationship between voltage, current, and resistance may involve complex quantities and phase differences. However, for a simple DC (direct current) circuit with a linear resistor, Ohm's Law provides an accurate relationship between voltage, current, and resistance.
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You want to calculate how long it takes a ball to fall to the ground from a
height of 20 m. Which equation can you use to calculate the time? (Assume
no air resistance.)
O A. vz? = v? +2aAd
B. a =
V₂-vi
At
O c. At=V1
4
a
O D. At=
2Ad
a
If a person wants to calculate the length of time it takes for a ball to fall from a height of 20m, the correct equation that they should use is:
D. Δt= √2Δd/a
What is the equation for finding the length of time for a free fall?The free fall formula should be used to obtain the length of time that it takes for a ball to fall from a given height. This formula also factors the height or distance from which the fall occurred and this is denoted by the letter d. The small letter 'a' is denotative of acceleration due to gravity and this is a constant pegged at -9.98 m/s².
So, the change in height is obtained and multiplied by two. This is further divided by the acceleration and the square root of the derived answer translates to the time taken for the ball to fall from the height of 20m. Of all the options listed, option D represents the correct equation.
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19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.
The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula
W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.
Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.
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Which moving object, in all likelihood,
will have the greatest momentum?
A volleyball hit by a fourth-grader
B volleyball hit by an Olympic volleyball
player
C volleyball hit by a senior adult
D volleyball hit by a basketball coach
please answer fast!!
Answer:
either b or d
Explanation:
Matter can undergo chemical reactions which feature of the components only stays the same in chemical reactions
In chemical reactions, the total mass of the components remains the same.
Chemical reactions involve the transformation of substances into new substances with different chemical properties. During these reactions, various changes occur, such as the rearrangement of atoms, the breaking and forming of chemical bonds, and the conversion of reactants into products. However, one fundamental principle that remains constant is the law of conservation of mass.
The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. This means that the total mass of the reactants must be equal to the total mass of the products. No matter can be lost or gained during the reaction; it simply undergoes a rearrangement at the atomic or molecular level.
This principle holds true regardless of the complexity of the chemical reaction. Whether it involves simple reactions between two elements or complex reactions with multiple reactants and products, the total mass before and after the reaction remains constant.
This concept is vital in understanding stoichiometry, which is the quantitative relationship between reactants and products in a chemical reaction. By balancing chemical equations and applying the law of conservation of mass, scientists can determine the relative amounts of substances involved in a reaction.
Overall, while the physical and chemical properties of substances may change during a chemical reaction, the total mass of the components involved in the reaction remains constant.
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1. At t=0s, a particle moving in the x-y plane with constant acceleration has a velocity ofv; = (3î-2)) m/s, and is at the origin. At t=3s, the particle's velocity is f = (91+7j) m/s. Find (a)the acceleration of the particle (b) Its coordinates at t=3s
Answer:
the particle is at coordinates (18,15/2)
Explanation:
To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:
a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j
So the acceleration of the particle is a = 2i + 3j m/s².
To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:
r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j
We can use the kinematic equations of motion to solve this problem.
Let the acceleration of the particle be a = axî + ayj.
(a) Using the equation of motion v = u + at, where u is the initial velocity:
f = v = u + at
Substituting the given values, we get:
(91+7j) = (3î-2j) + a(3î + 3j)
Equating the real and imaginary parts, we get:
91 = 3a + 3a (coefficients of î are equated)
7 = -2a + 3a (coefficients of j are equated)
Solving these equations simultaneously, we get:
a = î(23/6) + j(1/2)
So the acceleration of the particle is a = (23/6)î + (1/2)j.
(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:
At t = 3s, the displacement of the particle is:
s = ut + (1/2)at^2
Substituting the given values, we get:
s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2
Simplifying, we get:
s = 9î + (17/2)j
So the coordinates of the particle at t=3s are (9, 17/2).
Two horizontal forces act on an object. One force has a magnitude of 75.0 N and is directed due 30.0° south of east. The other force has a magnitude of 55.0 N and is directed due 70.0° north of west. What is the magnitude and direction of the sum of the two force vectors. Select one: 122.4 N, 43.2° north of east 130.0 N, 40.0° south of east 46.6 N, 17.1° south of east 48.3 N, 17.1° north of east 20.0 N, 40.0° north of east
Explanation:
70 degrees North of west = 110 degrees
30 degrees southof east = - 30 degrees:
Vertical components added together =
75 (sin -30) + 55 sin 110 = 14.18 N
Horizontal components added together =
75 cos (-30) + 55 cos 110 = 46.14 N
Magnitude = sqrt ( 14.18^2 + 46.14^2 ) = 48.3 N
direction = arctan ( 14.18 / 46.14) = ~ 17.1 North of East
I You are driving down the road at 15.6 m/s (35 mph) when an ambu-
lance passes you with its siren blaring. The ambulance siren produces
a frequency of 700 Hz. As the ambulance approaches you from be-
hind, you hear a frequency of 740 Hz. (a) What is the speed of the am-
bulance? (b) What frequency do you hear after the ambulance passes?
The speed of the ambulance is 33.35 m/s and the frequency heard after the ambulance passes is 667.07 Hz.
Calculation:-
V = f(344 - 15.6/344 - vs)
740 = 700(344 - 15.6/344 - vs)
344 - V s = 70/74 (344 - 15.6)
344 - V s = 310.64
V s = 33.35 m/s
After pass
F = 700 ( 344 + 15.6/344 + 33.35)
= 700 × 359.6/377.35
F = 667.07 Hz
Frequency is the wide variety of occurrences of a repeating event in line with a unit of time. The time period frequency refers to the variety of waves that pass a set factor in unit time. It additionally describes the number of cycles or vibrations undergone for the duration of one unit of time with the aid of a body in periodic motion.
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Please help and find the voltage drop. Thank you giving Brianlest
The voltage drop can be seen from the full circuit diagram.
What is a voltage drop in a circuit?A voltage drop in a circuit refers to the decrease in voltage (electrical potential difference) along a conductor as electric current flows through it. It is caused by the resistance of the conductor, which resists the flow of electric current, thus converting some of the electrical energy into heat.
Voltage drop is an important consideration in electrical circuit design, particularly in long or complex circuits, because it affects the amount of voltage available to power electrical devices. If the voltage drop is too large, the devices may not operate correctly, or they may be damaged.
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PLS HELP In which situation is work being done? (Check all that apply.) Your answer:
A boy coasting down the sidewalk on a skateboard.
Lifting your binder out of your backpack into your top row locker.
Pushing a shopping cart down the aisle at Publix.
Pushing on a broken down car but it doesn’t move.
The legs on your science table holding up the table top.
Carrying a heavy backpack down the hall.
Answer:
Lifting your binder out of your backpack into your top row locker.
Pushing a shopping cart down the aisle at Publix
Explanation:
These are the only two in which an object is moving because of an applied force
A china dish falls from a height of 1.5 m above the floor. Calculate its velocity just before it
reaches the ground. (ag = - g= -9.8 m/s^2) *
Answer:
12m/s
Explanation:
v^2=u^2+2as
v=?
u=0 (the dish was stationary before it fell)
a=9.81 m/s^2 (acceleration due to gravity/freefall)
s=1.5m (the drop height)
So: v^2=0+2.9.81.1.5 = 144.35415
and therefore v=sqrt 144.35415
12x12=144 so I'd say v=12m/s
a stone dropps 7,11m how long will it take it to fall
The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Heightu = Initial velocityt = Timeg = Acceleration due to gravityFrom the question,
Given:
u = 0 m/sH = 7.11 mg = 9.8 m/s²Substitute these values into equation 1 and solve for t.
7.11 = (0×t)+9.8×t²/27.11 = 4.9t²t² = 7.11/4.9t² = 1.451t = √1.451t = 1.2 secondsHence, the time it takes the stone to fall is 1.2 seconds.
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Change of state due to cooling is due to
Change of state due to cooling is due to the removal of thermal energy from a substance. A substance changes states, such as from a gas to a liquid or from a liquid to a solid, when its particles lose kinetic energy as it loses heat and moves more slowly. Eventually, the particles reorganize into a more ordered form with less energy. The term "solidification" or "freezing" refers to this process.