A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (32.7%), Married (52.7%), Widowed (2.7%), Divorced (11.9%). The table below shows the results of a random sample of 1704 adult men from California. Test the claim that the distribution from California is as expected at the a-0.01 significance level. a. Complete the table by filling in the expected frequencies. Round to the nearest whole number: Frequencies of Marital Status Outcome Frequency Expected Frequency Never Married 545 Married 892 Widowed 27 Divorced 240 b. What is the correct statistical test to use? Select an answer c. What are the null and alternative hypotheses? c. What are the null and alternative hypotheses? H: Marital status and residency are dependent. The distribution of marital status in California is the same as it is nationally. The distribution of marital status in California is not the same as it is nationally. Marital status and residency are independent. H: The distribution of marital status in California is the same as it is nationally, The distribution of marital status in California is not the same as it is nationally. O Marital status and residency are independent. O Marital status and residency are dependent. d. The degrees of freedom e. The test-statistic for this data - (Please show your answer to three decimal places.) f. The p-value for this sample - (Please show your answer to four decimal places.) g. The p-value is Select an answer a h. Based on this, we should Select an answer 1. Thus, the final conclusion is... h. Based on this, we should Select an answer 1. Thus, the final conclusion is... There is insufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally. There is sufficient evidence to conclude that the distribution of marital status in California is the same as it is nationally. There is sufficient evidence to conclude that marital status and residency are dependent. There is sufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally. There is insufficient evidence to conclude that marital status and residency are dependent.

The upper specification limit is 2.520 mm, and the lower specification limit is 2.480 mm.  The process is not capable according to the purchaser's requirement of a capability index of 1.50.

(a) The upper specification limit (USL) is calculated by adding the process mean (2.500 mm) to the upper tolerance (0.020 mm), resulting in 2.520 mm. The lower specification limit (LSL) is calculated by subtracting the lower tolerance (0.020 mm) from the process mean, resulting in 2.480 mm.

(b) The process capability index (Cp) is calculated by dividing the tolerance width (USL - LSL) by six times the standard deviation. In this case, the tolerance width is 0.040 mm (2.520 mm - 2.480 mm) and the standard deviation is 0.004 mm. Therefore, Cp = 0.040 mm / (6 * 0.004 mm) = 1.25.

(c) The purchaser requires a capability index (Cpk) of 1.50, which measures how well the process meets the specification limits. Since Cp (1.25) is less than the desired Cpk (1.50), the process is not capable according to the purchaser's requirement. It is not good enough for the supplier either, as the Cp is less than the desired level.

(d) If the process mean were to drift to 2.497 mm, the Cp value would remain the same at 1.25. Since the Cp value is still less than the desired Cpk of 1.50, the process would still not be good enough for the supplier's needs, even with the changed process mean.

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Answer:

\(x=\pm 4\sqrt2\)

Step-by-step explanation:

Left hand side is a positive number. Right hand side is positive. The equation should have real roots. (worst case, the root would be complex, but let's not open that can of worm)

Let's start noticing that \(32 = 2^5 =4^2\cdot 2\) and then take the square root of both sides, remembering that we need to take a plus or minus sign ( both a and -a squared give the same result!)

\(x= \pm \sqrt{4^2\cdot2}=\pm 4\sqrt2\)

Since the length and width of the rectangle is doubled, then the perimeter of the rectangle is doubled and the area of the rectangle is fourfold.

Perimeter and area of rectangle:

The general form to calculate  Perimeter of a Rectangle

P = 2(a + b);

And Area of Rectangle

A= a × b

where

a refers the length

b refers the width

Given,

Suppose the length and width of the rectangle are doubled.

Here we need to find the effect on the perimeter and the area of the rectangle.

While we looking into the given rectangle,

We have identified that the value of

length = 17 feet,

width = 4 feet

So, the perimeter of rectangle is,

=> P = 2 (17 + 4) = 42

Similarly, the area of the rectangle is

=> A = 17 x 4 = 68

Here we have given that the length and width is doubled, then the value of length is 34 and the width is 8.

Now, the perimeter of the rectangle is,

=> P = 2 (34 + 8) = 84

And the area of the rectangle is,

=> A = 34 x 8 = 272

While we comparing the resulting values we have identified that the perimeter is doubled and the area is fourfold.

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Answer:

i believe the answer is 0,2

Hi! I'm happy to help!

To solve this, we have to use the order of operations, or PEMDAS. (parenthesis, exponents, multiplication or division, and addition or subtraction)

We will start out with parenthesis. Since there are no expressions inside of the parenthesis, we can remove them.

But, before we do that, we have a positive negative, the negative form of positive is negative, so we remove the plus sign as well as the parenthesis.

1.7+(-5)+(3.27)=

1.7-5+3.27=

Now since we have no exponents, multiplication, or division, we move on to addition or subtraction. We have some of both, so we move from left to right.

Our first equation is 1.7-5, so we do that first.

1.7-5+3.27=

-3.3+3.27=

Now, we only have one addition problem left, -3.3+3.27, so we'll do that.

-3.3+3.27=

-0.03

After this equation is fully simplified, we are at -0.03!

I hope this was helpful, keep learning! :D

Answer:

\(0.00007024\) cm

Step-by-step explanation:

Standard notation just mean to expand the number.

Because the exponent is -5, move the decimal 5 places to the left.

\(7.024*10^{-5}\)

\(0.00007024\)

Hope this helped!

The distance it will reach to  x, = 46.6 feet

acc to our question-

hence,The distance it will reach to  x, = 46.6 feet

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The area covered by the algae in square meters d days after the treatment is applied can be calculated using the formula A = A0 * e^(-k*d), where A is the final area covered by the algae, A0 is the initial area covered by the algae, e is the base of the natural logarithm, k is the decay constant, and d is the number of days after the treatment is applied.

To fill out the table, you will need to plug in different values for d into the formula and calculate the corresponding values for A. Start with the initial area covered by the algae, A0, and then use the formula to calculate the area covered by the algae for each subsequent day, d. Round the values to the nearest tenth.

For example, if A0 is 100 square meters and k is 0.05, you can calculate the area covered by the algae after 1 day by plugging in d = 1 into the formula:

A = 100 * e^(-0.05*1) = 100 * e^(-0.05) ≈ 100 * 0.951 ≈ 95.1 square meters

Repeat this calculation for different values of d to fill out the table. Remember to round the values to the nearest tenth.

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Answer:

At the store every lollipop coasts $2 you have a coupon that will give you $2 off any purchase.  

Step-by-step explanation:

2= the coast for each single lollipop

x= the number of lollipops you buy

-2= the $2 taken off your purchase due to your coupon

Answer:

The correct option is;

A. Car B was 10 miles east of car A

Step-by-step explanation:

The given parameters are;

The speed of car A = 45 miles per hour

The direction of car A = East

The distance of car B from Johnstown after 2 hours = 100 miles east

The direction of Car B = East

The distance of car B from Johnstown is given on the graph

Therefore, the initial distance of car A from Johnstown when car A began driving is given as follows;

The initial distance, east, of car A from Johnstown = 100 - 2 × 45 = 10

∴ The initial distance, east, of car A from Johnstown = 10 miles

From the graph, the initial distance, east, of car B from Johnstown = 20 miles

Therefore, car B was 10 miles east of car A

Answer:

Car B was 10 miles east of car A

Step-by-step explanation:

9514 1404 393

Answer:

  6

Step-by-step explanation:

Dilation about the origin multiplies each coordinate by the scale factor. We can find the scale factor by considering the x-coordinates of A and A'.

  scale factor = Ax'/Ax = 18/3 = 6

The scale factor is 6.

Answer:

10 quarters

40 dimes

Step-by-step explanation:

q + d = 40

25q + 10d = 625

25 > 10

q < d

25(10) = 250

10(40) = 400

$2.50 + $4.00 = $6.00

Answer:

15 quarters and 25 dimes

Step-by-step explanation:

Answer:

$20.75

Step-by-step explanation:

The answer is $21.50

Explain:

$8.60 / 4 = $2.15

$2.15 x 10 = $21.50

Could I have brainliest?

Yes, the variable is statistically significant if the t-statistic is 2.54. In hypothesis testing, the t-statistic measures the difference between the observed value and the expected value, relative to the variability in the data.

It is used to determine if there is a significant difference between the sample mean and the population mean.

To assess statistical significance, we compare the t-statistic to the critical value, which is determined based on the desired significance level and the degrees of freedom. If the absolute value of the t-statistic exceeds the critical value, it indicates that the variable is statistically significant.

In this case, since the t-statistic is 2.54, it means that the observed value deviates from the expected value by a significant amount, and it is unlikely to have occurred by chance alone. Therefore, the variable is statistically significant.

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Answer:

A= 18, B= 12

Step-by-step explanation:

A +B= 30 -----(1)

A :B= 3 :2

From the ratio,

A ----- 3 units

B ----- 2 units

Units shall be represented by the letter u from this point forth.

Substitute into equation (1):

3u +2u ---- 30

5u ----- 30

u ----- 30 ÷5= 6

This means that 1 unit represents 6.

A

= 3(6)

= 18

B

= 2(6)

= 12

The equation that relates E to H is E = $30H.

The earnings of the tutor for working for 13 hours is $390.

The total earnings of the tutor can be determined by multiplying the earnings per hour by the total hours worked.

The equation that would be used to determine the total earnings would be a liner equation. A linear equation is a function that increases by a constant value.

Total earnings = earning per hour x number of hours worked

Total earnings = $30 x H

E = $30H

Earnings after working for 13 hours : 13 x $30 = $390

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Question 3: True

Question 4: False

Question 5: True

If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c.

This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.

Question 3: If f'(c) < 0 then f(x) is decreasing and the graph of f(x) is concave down when x = c.

True

When the derivative of a function, f'(x), is negative at a point c, it indicates that the function is decreasing at that point. Additionally, if the second derivative, f''(x), exists and is negative at x = c, it implies that the graph of f(x) is concave down at that point.

Question 4: A local extreme point of a polynomial function f(x) can only occur when f'(x) = 0.

False

A local extreme point of a polynomial function can occur when f'(x) = 0, but it is not the only condition. A local extreme point can also occur when f'(x) does not exist (such as at a sharp corner or cusp) or when f'(x) is undefined. Therefore, f'(x) being equal to zero is not the sole requirement for a local extreme point to exist.

Question 5: If f'(x) > 0 when x < c and f'(x) < 0 when x > c, then f(x) has a maximum value when x = c.

True

If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c. This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.

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No, we cannot draw a triangle with sides 3 cm, 3.5 cm, and 6.5 cm.

Let's understand the concept behind this:

Apply the triangle's length-of-sides property, which stipulates that the total of any two sides should be more than the value of the third side. Such a triangle cannot exist if there is any pair of sides whose sum is equal to or less than the third side.

We must determine whether the supplied side lengths constitute a triangle. We now understand that the triangle's third side should be greater than the sum of any two of its sides. Such a triangle cannot exist if there is any pair of sides whose sum is equal to or less than the third side. So, we'll try every combination and see if it meets the criteria.

Let’s assume AB = 3 cm, BC = 3.5 cm and AC = 6.5 cm.

AB + AC = 3 + 6.5 cm = 9.5 cm > 3.5 cm = BC.

AC + BC = 6.5 + 3.5 = 10 cm > 3 cm = AB.

AB + BC = 3 + 3.5 cm  = 6.5 cm = AC.

However, in this case, the length of the third side is equal to the total lengths of the other two sides, which renders the triangle's condition incorrect.

Therefore, there does not exist any triangle with sides of 3 cm, 3.5 cm, and 6.5 cm.

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Given that profits decrease by 13.8% when the degree of operating leverage (DOL) is 3.8.

The decrease in sales is: We have to determine the percentage decrease in sales Let the percentage decrease in sales be x.

Degree of Operating Leverage (DOL) = % change in Profit / % change in Sales3.8

= -13.8% / x Thus, we have: x

= -13.8% / 3.8

= -3.63%Therefore, the decrease in sales is 3.63%.Hence, the correct option is C) 3.63%. Percentage decrease in sales = % change in profit / degree of operating leverage

= 13.8 / 3.8

= 3.63% The percentage decrease in sales is 3.63%.

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The three division expressions that are each equivale to 35.78 ÷ 6 is 0.5933\(\times10^1\), 59.33\(\times10^{-1}\) and 59.33\(\times10^{-2}\).

In the given question we have to use the powers of 10 to write three division expressions that are each equivale to 35.78 ÷ 6.

The given expression is 35.78 ÷ 6

To express in power of 10 we have to firstly simplify the given expression.

To simplify the given expression we have to divide the 35.78 by 6.

So 35.78 ÷ 6 =5.9633

To express in the power of 10 we move the decimal point left and right.

When we move left the power is positive and when move right power is negative.

The first expression is 0.5933\(\times10^1\)

The second expression is 59.33\(\times10^{-1}\)

The third expression is 593.3\(\times10^{-2}\)

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Answer:

slope= 3/2

Step-by-step explanation:

The standard error of the sampling distribution of sample proportions for samples size

1) n = 35 ⇒ SE = 0.07

2) n = 100 ⇒ SE = 0.04

3) n = 250 ⇒ SE = 0.03

We know that the formula for thr standard error(SE) of the sample Proportion is:

SE = \(\sqrt{\frac{p(1-p)}{n} }\)

as the sample size increases, the standard error decreases.

Here, the percentage of people who prefer dogs to cats is 78%

so, p = 0.78

For samples of size n = 35,

SE = \(\sqrt{\frac{0.78\times (1-0.78)}{35} }\)

SE = \(\sqrt{\frac{0.1716}{35} }\)

SE = 0.07

For sample size n = 100,

SE = \(\sqrt{\frac{0.78\times (1-0.78)}{100} }\)

SE = \(\sqrt{\frac{0.1716}{100} }\)

SE = 0.041

For samples of size n = 250,

SE = \(\sqrt{\frac{0.78\times (1-0.78)}{250} }\)

SE = \(\sqrt{\frac{0.1716}{250} }\)

SE = 0.03

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The complete question is:

The percentage of people who prefer dogs to cats is 78% for a given population. What is the standard error of the sampling distribution of sample proportions for samples of size n=35, n=100, and n=250?

Answer:

87

Step-by-step explanation:

the slope is very easy you can solve it in easy way all you have to do is give me your phone

We have the following expression given:

We can take common factor and we got:

And after simplify we got:

Answer:

The 15th term is 103

Step-by-step explanation:

Arithmetic Sequence

An arithmetic sequence is a list of numbers with a definite pattern by which each term is found by adding or subtracting a fixed quantity to the previous term. If n is the number of the term, then:

\(a_n=a_{n-1}+d\)

Where d is called the common difference. If we know the first term, the nth term is calculated by:

\(a_n=a_1+(n-1)*d\)

The question asks us to find the term n=15 of an arithmetic sequence with a common difference d=7 and first term a1=5.

Applying the formula above:

\(a_{15}=5+(15-1)*7\)

\(a_{15}=5+14*7\)

\(a_{15}=5+98=103\)

The 15th term is 103

Considering the definition of zeros of a function, the zeros of the function f(t)= (t-5)² - 9 are 2 and 8.

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

That is, the zeros of a function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

Considering the function f(t)= (t-5)² - 9, if the zeros of a function are those values ​​of x for which the expression is equal to 0, you get:

(t-5)² - 9= 0

Solving:

(t-5)² = 9

t-5 = √9

t-5= ±3

Then:

t-5= 3

t= 3 +5

t= 8

and

t-5= -3

t= -3 +5

t= 2

Finally, the zeros of the function are 2 and 8.

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Answer:

A≈78.54in²

Step-by-step explanation:

Can I have brainliest pls?

Given:

The compound inequality \(2x-3 < 7\) and \(5-x \leq 8\).

To find:

The solution for the given compound inequality

Solution:

We have, compound inequality \(2x-3 < 7\) and \(5-x \leq 8\).

For \(2x-3 < 7\),

Add 3 on both sides.

\(2x < 7+3\)

\(2x < 10\)

Divide 2 on both sides.

\(x< 5\)            ...(i)

For \(5-x \leq 8\),

Subtract 5 from both sides.

\(-x \leq 8-5\)

\(-x \leq 3\)

Divide both sides by -1. So, the sign of inequality is changed.

\(x \geq -3\)            ...(ii)

Using (i) and (ii), we get the solution of given compound inequality as

\(x \geq -3\)  and \(x< 5\)

Therefore, the correct option is D.

The doubling time for this population of butterflies is approximately 12 months.

To determine the doubling time for this population of butterflies, we can use the rule of 70. The rule of 70 states that to find the approximate doubling time of a population, you divide 70 by the growth rate as a percentage.

In this case, the initial population is 14 and the predicted population in 6 months is 24, so the growth rate can be calculated as follows:

Growth rate = (Predicted population - Initial population) / Initial population x 100%
Growth rate = (24 - 14) / 14 x 100%
Growth rate = 71.43%

Using the rule of 70:
Doubling time = 70 / Growth rate
Doubling time = 70 / 71.43
Doubling time ≈ 0.98 years or approximately 12 months

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