a real heat engine working between heat reservoirs at 980 k and 630 k produces 700 j of work per cycle for a heat input of 2800 j .

Answers

Answer 1

Its thermal efficiency is 25%.

What is thermal efficiency?

Thermal efficiency is the ratio of an engine's or machine's useful output energy to its total energy input. It is a measure of how well energy is converted from one form to another, and is expressed as a percentage. Thermal efficiency is an important factor in determining the cost-effectiveness of many energy systems such as engines, power stations and industrial processes. Increasing the thermal efficiency of a system can lead to significant cost savings and environmental benefits.

Thermal Efficiency = (Work Output / Heat Input) x 100

= (700 J / 2800 J) x 100

= 25%

Therefore, the thermal efficiency of the heat engine working between heat reservoirs at 980 k and 630 k is 25%.

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Complete questions as follows-

200 word and should plag free

a real heat engine working between heat reservoirs at 980 k and 630 k produces 700 j of work per cycle for a heat input of 2800 j . Its thermal efficiency is


Related Questions

One car is traveling with a speed of 40 miles per hour. A second car is traveling with a speed of 50 miles per hour. They crash into each other. It is a very different accident if they crash into each other head on, or if the faster one hits the slower one from behind. What does this have to do with the word velocity?

Answers

Answer:

Velocity is a vector whose magnitude is called speed. Collision study needs to analyse the transfer of momentum, which is another vector quantity associated with the velocity vector of each object

Explanation:

The important concept to recall is that velocity is a vector quantity, which has direction apart from just magnitude (as speed is). So in the transfer of momentum (another vector quantity) that takes place in a collision, it is extremely important to know the direction of the velocity vector, since there is much larger transfer of momentum if the cars collide heads on, than if the cars collide from behind while going in the same direction.

A 3.0 kg block is pushed 1.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 26.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
2
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.20, find
a) the work done by the force on the block.
Answer in units of J.
b) the work done by gravity on the block.
Answer in units of J.
c) the magnitude of the normal force between
the block and the wall.
Answer in units of N.

A 3.0 kg block is pushed 1.0 m at a constantvelocity up a vertical wall by a constant forceapplied at

Answers

(a) The work done by the applied force is 32.6 J.

(b) The work done by gravity on the block is 29.4 J.

(c) The magnitude of the normal force is 29.4 N.

What is the force applied to the block?

The force applied to the block is determined by applying the formula for the net force on the block.

F(net) = 0

Fcosθ - mg - Fsinθμ = 0

Fcosθ - Fsinθμ = mg

F(cosθ - sinθμ) = mg

F = (mg) / (cosθ - sinθμ)

F = (3 x 9.8) / (cos26  -  0.2 x sin26)

F = 36.25 N

The work done by the applied force is calculated as;

W = Fd cosθ

W = (36.25 x 1) x cos(26)

W = 32.6 J

The work done by gravity on the block is calculated as follows;

W = mgd

W = 3 x 9.8 x 1

W = 29.4 J

The magnitude of the normal force is calculated as follows;

N = mg

N = 3 x 9.8

N = 29.4 N

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Find the average velocity (in m/s) of a cyclist that starts 150 meters north of town and is 1200 meters north of town after 30 minutes

Answers

Answer:

v = 0.58 m/s

Explanation:

The velocity of an object is given as the ratio of the total distance traveled by the object to the time interval taken for traveling. Hence, we use the following formula to find the average velocity of the cyclist:

v = s/t

where,

v = average velocity = ?

s = distance traveled = final position - initial position =1200 m - 150 m =1050 m

t = time interval = (30 min)(60 s/1 min) = 1800 s

Therefore,

v = 1050 m/1800 s

v = 0.58 m/s


How are wavelength and frequency related?
As wavelength increases frequency increases.
b. As wavelength decreases frequency decreases.
As wavelength increases frequency decreases.
d. None of the above

Answers

Answer:

Hey dear

Explanation:

Its option C

As Wavelength increases frequency decreases

In other case,

When Wavelength decreases frequency increases

its opposite

Tq

A rock requires 100 N of force to be lifted 0.5 m from the ground to a bucket in 2 s. How much power is required?

Answers

The power required to lift the rock is 250 Watts.

Power is defined as the amount of work done per unit time. In this case, the work done is the force applied multiplied by the distance moved, which is:

work = force x distancework = 100 N x 0.5 mwork = 50 Joules

The time taken to lift the rock is 2 seconds. Therefore, the power required is:

power = work/timepower = 50 J/2 spower = 25 W

However, this is the power required to lift the rock at a constant speed. To accelerate the rock from rest to the final velocity in 2 seconds, additional power is needed. Assuming the rock is lifted at a constant acceleration, the average power is:

average power = work/timeaverage power = (force x distance)/timeaverage power = (100 N x 0.5 m)/2 saverage power = 25 W

Therefore, the power required to lift the rock is 25 W to maintain a constant speed, or 250 W to accelerate the rock from rest to the final velocity in 2 seconds.

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I get angry and throw a pen straight down to the floor. I throw it with an initial speed of 25 m/s. It took 0.25 second to fall. What is the velocity of the pen just before it hit the floor?​

Answers

v2=u2+2as

v2=0×2×25×0.25

v2=25×0.25

v2=6.25m/s2

what is kinematics ;-;
explain.​

Answers

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

Explanation:

1. Multiple light bulbs are connected in series across a 120.0 V
source of emf. The current in the circuit is 1.25 A. If each light
bulb has a resistance of 3.00 £2, how many light bulbs are in
the circuit?


2. If the resistance of bulb A is 6 2, the resistance of bulb B is
18 02, and the equivalence resistance of the circuit is 1202,
what is the resistance of bulb C?

Answers

1) Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs: n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs. There are 32 light bulbs in the circuit.

2) The total resistance is equal to the sum of individual resistances: R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω. The resistance of bulb C is 96 Ω.

In a series circuit, the total resistance is equal to the sum of individual resistances. Using Ohm's Law, we can find the total resistance:

R = V/I = 120.0 V/1.25 A = 96 Ω

Since each bulb has a resistance of 3.00 Ω, we can calculate the number of bulbs:

n = R/R_bulb = 96 Ω/3.00 Ω = 32 bulbs

Therefore, there are 32 light bulbs in the circuit.

In a series circuit, the total resistance is equal to the sum of individual resistances:

R_eq = R_A + R_B + R_C

Substituting the given values:

120 Ω = 6 Ω + 18 Ω + R_C

Solving for R_C:

R_C = 120 Ω - 6 Ω - 18 Ω = 96 Ω

Therefore, the resistance of bulb C is 96 Ω.

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Calculate the amount, in grams, of an original 300 gram sample of potassium 40 remaining after 3.9 billion years.
a. 300
b. 150
c. 75
d. 37.5​

Answers

71718 88.
1919910
So just if

The graph below shows the conservation of energy for a skydiver jumping out
of a plane and landing safely on the ground. Which energy is represented by
line C?

The graph below shows the conservation of energy for a skydiver jumping outof a plane and landing safely

Answers

Answer:

Kinetic energy

Explanation:

A 4.0 kg slides with an initial speed of 3.0m/s towards a spring on a frictionless horizontal surface. When the box hits the spring, the spring compresses by
0.30 m. What is the spring constant?

A 4.0 kg slides with an initial speed of 3.0m/s towards a spring on a frictionless horizontal surface.

Answers

The  spring constant is 400 N/m. For the given question.

What is spring constant ?

The spring constant (k) is a physical property of a spring, which represents the stiffness of the spring. It is defined as the force required to stretch or compress a spring by a certain amount (x) divided by that amount of deformation:

k = F/x

where F is the applied force and x is the displacement or deformation of the spring from its equilibrium position. The spring constant has units of force per unit of length, such as newtons per meter (N/m) in the SI system of units. A higher spring constant means that more force is required to deform the spring by the same amount, and the spring is considered to be stiffer. Conversely, a lower spring constant means that less force is required to deform the spring by the same amount, and the spring is considered to be more flexible.

We can use the conservation of energy to find the spring constant.

Initially, the box has kinetic energy given by:

K₁= (1/2)mv₁²

= (1/2)(4.0 kg)(3.0 m/s)²

= 18 J

At maximum compression, all of the kinetic energy is stored as potential energy in the spring. The potential energy stored in a spring is given by:

U = (1/2)kx²

where k is the spring constant and x is the displacement from the equilibrium position. In this case, x is the compression of the spring, which is 0.30 m.

So, the potential energy stored in the spring is:

U = (1/2)kx²

= (1/2)k(0.30 m)²

= 0.045k J

Since energy is conserved, we can equate the initial kinetic energy to the potential energy stored in the spring:

K₁= U

18 J = 0.045k J

k = 400 N/m

Therefore, the spring constant is 400 N/m.

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The surface of the exit road is horizontal, not banked. (See figure.) If the static
friction between the tires and the surface of the road is us = 0.688 and the
maximum speed with which the car can exit the highway safely without sliding is
25.2 m/s, what is the radius of curvature of a highway exit, r?

Answers

The radius of curvature of the highway exit is approximately 220 km.

To find the radius of curvature of the highway exit, we can use the centripetal force equation:

F = mv^2 / r

where F is the maximum static friction force, m is the mass of the car, v is the maximum safe speed, and r is the radius of curvature.

We can solve for r by rearranging the equation:

r = mv^2 / F

Substituting the given values, we have:

r = (1000 kg)(25.2 m/s)^2 / (0.688)

r = 2.20 x 10^5 m

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Find the tension in each of the two ropes supporting a hammock if one is at an angle of θ1= 16 degrees above the horizontal and the other is at an angle of θ2= 38 degrees above the horizontal. The person sleeping in the hammock (unconcerned about tensions and ropes) has a mass of 70 kg
T1=
T2=

Answers

The rope is under about 411.8 N of stress at point 1, and around 532.6 N of tension at point 2.

Calculation-

         /|

       / |

T1  /  |   θ1

   /     |

  /   θ1|

 /        |

/_____|

\           |

 \          | θ2

  \        |

T2  \    |

         \ |

           \|

The forces in the x and y axes must balance since the hammock is at rest. Consequently, we may write:

ΣF_x = T1 cosθ1 - T2 cosθ2 = 0

ΣF_y = T1 sinθ1 + T2 sinθ2 - mg = 0

Let's change the equations such that we can solve for T1 and T2:

T1 = T2 cosθ2 / cosθ1

T2 = (m g) / (sinθ2 - sinθ1)

T1 = T2 cos(38°) / cos(16°) = 0.773 T2

T2 = (70 kg)(9.81 m/s^2) / (sin 38° - sin 16°) = 532.6 N

Therefore, we can find T1:

T1 = 0.773 T2 = 0.773(532.6 N) = 411.8 N

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Can someone who knows how to do physics please answer this

Can someone who knows how to do physics please answer this

Answers

Answer:

  about 3.17647 hours

Explanation:

The appropriate relation is ...

  time = distance/speed

  time = (270 km)/(85 km/h) = 3 3/17 h ≈ 3.17647 h

It will take Derek about 3.17647 hours to drive the distance.

A businessman reached is home by riding motorcycle with in 5 minutes by travelling 9 km distance. Then what is has average velocity?​

Answers

We can use the formula:

average velocity = displacement / time

Here, the displacement is the distance travelled, which is 9 km, and the time taken is 5 minutes, or 5/60 = 1/12 hours (since there are 60 minutes in an hour). Therefore:

average velocity = 9 km / (1/12 hours)

= 108 km/h

So the average velocity of the businessman is 108 km/h.

What must you know about a nuclear reaction to calculate the amount of
energy it will produce?
OA. The sum of the total nuclear mass before and after the reaction
OB. The difference between the total nuclear mass before and after
the reaction
OC. The ratio of total nuclear mass before the reaction to the total
nuclear mass after the reaction
D. The product of the total nuclear mass before and after the
reaction

Answers

B. The difference between total nuclear mass before and after the reaction.

This is because you can see how much nuclear matter had actually been used in the reaction by finding the difference between the initial mass and final mass.

In 2012, NASA sent the 900kg Curiosity robot to Mars to study the planet. a) Recall the relationship between the weight P and the mass m. Specify the units. b) What is the weight of Curiosty on Mars? c) Compare the weight of Curiosity on Earth and on Mars. Why is it more important on Earth

Answers

(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

(b)The weight of Curiosity on Earth is approximately 8820 Newtons.

a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.

c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.

The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.

It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.

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1. One of two identical metal spheres has a
charge of +q and the other sphere has a
charge of -q. The spheres are brought
together momentarily and then separated.
Compared to the total charge on the two
spheres before contact, the total charge on
the two spheres after contact is

Answers

Two identical metal spheres carry charges of + q and - 2q respectively.

What is identical metal spheres?

It is given that initially sphere has different charges and momentarily brought in contact with each other.

When the spheres are touched then charge is equally redistributed among spheres such that now they possess the equal amount of charges.

When they are suspended from the thread their separation increases compared to previous situation because now the value of force increases because of the change in the product of charges.

For example, Suppose initially they possess 15 C and 17 C charge and after redistribution they both possess 16 C  of charge.

Product of charges=15*17=255

Final Product of charges=16*16=256

As force depends upon the Product of the charges so there will be more repulsive force.    

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Our power plant generates electricity using a steam turbine. At the exit from our power generation process, we end up with 562.0 kg/s of liquid water at 330.0 K. We cannot release this water directly into a nearby river if the temperature is over 310.00 K, without causing significant thermal pollution that would damage fish populations. Our plan is to mix this warm water with another cooler water stream at 290.00 K. What is the mass flow rate of this cool water stream needed to meet the regulation

Answers

Answer:

The mass flowrate of the cooling water needed to meet the regulation is 560 kg/s

Explanation:

The given information are;

The mass flow rate of the water = 562.0 kg/s

The temperature of the exit water = 330.0 K

The allowable temperature of the of released water into nearby river = 310.00 K

The temperature of the cool water with which the temperature of the exit water is cooled = 290.00 K

Therefore, we have;

Heat gained by the mixture = The heat of the final mixture exited to the river

Q = m×c×ΔT

\(m_w\) = 562.0 kg/s

The mass of the cooling water = x

The final temperature = 310 K

4.2×562×(330 - 310) = x×4.2×(310 - 290)

47208 = 84×x

x = 47208/84 = 560 kg

Therefore, the mass flowrate of the cooling water needed to meet the regulation = 560 kg/s.

Question 2 of 32
A water-skier with a mass of 68 kg is pulled with a constant force of 980 N by
a speedboat. A wave launches him in such a way that he is temporarily
airbome while still being pulled by the boat, as shown in the image below.
Assuming that air resistance can be ignored, what is the vertical acceleration
that the water-skier experiences on his return to the water surface? (Recall
that g = 9.8 m/s2)
Rope Force
ODON
Weight
O A. - 18.1 m/s2
OB. - 15.6 m/s2
O C. -11.2 m/s2
OD. -9.8 m/s2

Answers

Answer:

OD. -9.8 m/s2

Explanation:

The only force vertical force that is acting on the skier is gravity and since its pulling him back it's a negative force down the y axis.

A student moves a horseshoe magnet by hand across a tabletop to varying distances from an electromagnet, as shown in the diagram above.

The student records observations of how much force it takes to hold the horseshoe magnet in place at each distance. Observations

• 20 cm: no force required
• 10 cm: small force required; easy to hold in place
• 5 cm: large force required; very difficult to hold in place

What do the student's observations demonstrate?

A. The electromagnet's magnetic field becomes stronger as more magnetic material is added to it.

B. The electromagnet's magnetic field is stronger as more turns are added to the wire on the nail.

C. The electromagnet's magnetic field becomes stronger as a small amount of strength is added to the system by the battery.

D. The electromagnet's magnetic field is stronger close to it than far from it.​

A student moves a horseshoe magnet by hand across a tabletop to varying distances from an electromagnet,

Answers

The closer together they are the harder it is to hold on to because the magnetic field is stronger as it gets closer.


Answer:

D. The electromagnet's magnetic field is stronger close to it than far from it.​

A roller-coaster goes over an 11 m tall hill then approaches a 24 m hill. What is theminimum velocity the roller-coaster would need when going over the 11 m hill tomake it to the top of the 24 m hill?

Answers

Make a diagram to visualize the problem.

As you can observe, at point A the roller-coater has both mechanical energies, while at point B, it has just potential energy because it stops once reaches the 24-meters hill.

Using the law of conservation of energy, we have'

\(\begin{gathered} E_A=E_B \\ \text{mgh}_A+\frac{1}{2}m(v_A)^2=\text{mgh}_B \end{gathered}\)

We can cancel out because they are the same, and solve for v_A.

\(\begin{gathered} gh_A+\frac{1}{2}v^2_A=gh_B \\ \frac{1}{2}v^2_A=gh_B-gh_A \\ v^2_A=2(gh_B-gh_A) \\ v_A=\sqrt[]{2(gh_B-gh_A)} \end{gathered}\)

Where g = 9.8 m/s^2, h_B = 24 m, and h_A = 11 m.

\(\begin{gathered} v_A=\sqrt[]{2(9.8\cdot24-9.8\cdot11)}(\frac{m}{s}) \\ v_A=\sqrt[]{2(235.2-107.8)}(\frac{m}{s}) \\ v_A\approx16(\frac{m}{s}) \end{gathered}\)

Therefore, the minimum velocity the roller-coaster would need when going over the 11-meters hill is 16 m/s.

A roller-coaster goes over an 11 m tall hill then approaches a 24 m hill. What is theminimum velocity

If an object is placed between a convex lens and its focal point, which type of image will be produced?

Answers

Blury image or some type of incorrect postural image

You are in charge of designing a study that determines how far the average fire ant travels from its colony to collect resources.


Plan an investigation to provide evidence of the distance traveled by fire ants.

Also describe the process you will use to accurately measure the distance traveled including the tools you will use and the data you will collect.

Answers

To accurately measure the distance traveled by the fire ants, we could use a measuring tape or a GPS device. For short distances, a measuring tape would suffice, while for longer distances, a GPS device would provide more accurate measurements.

How to investigate the distance traveled by fire ants to collect resources?

To investigate the distance traveled by fire ants to collect resources, we could follow the following plan:

Select a suitable study site: We need to select a study site where fire ants are present and are actively collecting resources. It should also be a site where we can easily track and observe the movement of the ants.Mark the location of the colony: Once we have identified a study site, we should locate the fire ant colony and mark its location.Place resources at varying distances: We should then place resources, such as food or sugar water, at varying distances from the colony, starting from the immediate vicinity of the colony and extending outwards in increasing increments.Observe and track ants: We should observe and track the ants as they leave the colony to collect resources. We can mark the ants with a non-toxic paint to identify and track their movement.Measure the distance traveled: We can use a measuring tape or a GPS device to accurately measure the distance traveled by the marked ants from the colony to the resource site.Record the data: We should record the distance traveled by each marked ant in a spreadsheet or database.Analyze the data: Once we have collected the data, we can use statistical analysis to determine the average distance traveled by fire ants to collect resources.

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A runner runs the 100 meter dash in 16.6 seconds. What is their average speed? (in meters per second) SOMEBODY PLEASE HELP ME!!!

Answers

Formula: s = d/t

s = speed

d = distance

t = time

We are given the distance and time, so we can use that to solve for the speed.

s = 100/16.6

s ≈ 6.02m/s

Best of Luck!

earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________

Answers

earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.

What is energy?

Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.

The term earth's energy budget is also described as the  balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.

The earth's energy budget was mainly three types as shown:

shortwave radiation, longwave radiation, and internal heat sources.

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Can an object ever be accelerating and experiencing an instantaneous velocity of 0 m/s? Explain.

Answers

It is possible to have a zero instantaneous velocity with non-zero acceleration.

Considering an example of free fall or a stone released from some height. When the stone is at intial condition, then it has zero velocity, but it has gravitational acceleration; due to this gravitational acceleration, the stone starts moving just after releasing it.

Hence, it is possible to have zero velocity, but non zero accceleration.

The magnitude of the electric field due to a point charge object at a distance 4.0 m is 9 N/C. From the same
charged object the electric field of magnitude, 16 N/C will be at a distance of

Answers

The electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

The magnitude of the electric field due to a point charge object follows the inverse square law, which states that the magnitude of the electric field is inversely proportional to the square of the distance from the charged object. Mathematically, this is expressed as:

\(E = k*q/r^2\)

where E is the electric field, k is Coulomb's constant (\(k = 9 x 10^9 N*m^2/C^2\)), q is the charge of the object, and r is the distance from the object.

We can use this formula to find the distance at which the electric field has a magnitude of 16 N/C. Let's call this distance x:

16 = \(k*q/x^2\)

We can rearrange this equation to solve for x:

x = \(\sqrt(k*q/16)\)

To find q, we need another piece of information. We know that the electric field has a magnitude of 9 N/C at a distance of 4.0 m. Using the same formula as before, we can solve for q:

9 = \(k*q/4^2\)

q = \(9*4^2/k\)

Now we can substitute this value for q into the equation for x:

x =\(\sqrt(k*(9*4^2/k)/16)\)

x =\(\sqrt(9*4^2/16)\)

x = \(\sqrt(36)\)

x = 6.0 meters

Therefore, the electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.

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How do heat and thermal energy
differnt ?



HELP PLEASE FAST ASAP!?!???!??!?

Answers

Thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.

A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?

Answers

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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