A racetrack curve has radius 90.0 m
and is banked at an angle of 18.0 ∘
. The coefficient of static friction between the tires and the roadway is 0.400. A race car with mass 1200 kg
rounds the curve with the maximum speed to avoid skidding.

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

Answer:

Tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s

Explanation:

From the question above,

(1) tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s

Mometum = mass×velocity

Momentum = 270×0.5

Momentum = 135 kgm/s

(2) hare with a mass of 2.7 kg moving at a velocity of 7 m/s

Mementum = mass × velocity

Momentum = 2.7×7

Momentum = 18.9 kgm/s

(3) turtle with a mass of 91 kg moving at a velocity of 1.4 m/s

Momentum = mass × velocity

Momentum = 91×1.4

Momentum = 127.4 kgm/s

(4) roadrunner with a mass of 1.8 kg moving at a velocity of 6.7 m/s

Momentum = mass × velocity

Momentum = 1.8×6.7

Momentum = 12.06 kgm/s

From the above, the one with the greatest momentum is tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s

Answer:

the curring flowing into the capracitor will  get "stuck" on the plates because they can't get past the insulating dielectric.

Explanation:

60

because mass of an object never change

but weight can change for example if it's

mass is 60kg 5he wieght will be 60kg * 9.8m/s²

=588N

Answer:

false

Explanation:

Answer:

false

Explanation:

edge

Answer:

USA

NAMELY UNITED STATES OF AMERICA

america

Explanation:

because why not

Answer:

228.23m

Explanation:

Vy=59sin70=55.44m/s

x=V0t+1/2at^2

0=55.44t-4.9t^2

t=11.31s

Vx=59cos70=20.18m/s

Range=20.18*11.31=228.23m

Answer:

the last time i had my tempature taken was at disney prings about a week ago -_- they used one of those gun things that dont touch u and the SHOVED me forward so i guess i was fine

Explanation:

Answer:

thermometer

Explanation:

The shutter speed that should be used if the lens is changed to f/4.0 is; Choice D: 1/500 s.

The relationship between the shutter speed and the focal ratio is an inverse relationship.

Ratio of Areas = 5.6²/4²

Since; T1A1 = T2A2

In essence; when the focal ratio is reduced as in this case; from f/5.6 to f/4.0; the shutter speed is increased.

Ultimately, the shutter speed of the camera in discuss increases to; 1/500 s.

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Answer:

3,295.348Joules

Explanation:

Potential Energy = mass * acceleration due to gravity * height

Given the following

Mass = 73.1kg

Acceleration due to gravity = 9.8m/s²

Distance (Height) = 4.6m

Substitute into the formula;

Potential Energy = 73.1 * 9.8 * 4.6

Potential Energy = 3,295.348Joules

Hence Tim gain 3,295.348Joules of energy

Answer:

85

Explanation:

soln

given that;

frequency=17Hz

wavelength=5m

speed?

formula for wavelength is;

wavelength= speed/frequency

then ; making v the subject formula

we have that v=wavelength*frequency

v=17*5=>85ms

Answer:

About 4.4 seconds

Explanation:

\(h=1/2(gt^{2} )\)

\(t^{2} =\frac{2h}{g}\)

\(t=\sqrt{\frac{2h}{g} }\)

\(t=\sqrt{\frac{2(93)}{9.8} } =\sqrt{18.98} =4.36\)

Hope this helps

Explanation:

Energy utilization focuses on technologies that can lead to new and potentially more efficient ways of using electricity in residential, commercial and industrial settings—as well as in the transportation sector

The velocity of the large cart after the collision is approximately 0.0486 m/s in the opposite direction of its initial motion.

We can use the principle of conservation of momentum to find the speed of the large cart after the collision. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum (p) of an object is calculated by multiplying its mass (m) by its velocity (v). Therefore, the momentum of the small cart before the collision is:

p_small_before = (mass_small) * (velocity_small) = (0.300 kg) * (1.80 m/s) = 0.540 kg·m/s.

Since the large cart is at rest before the collision, its initial momentum is zero:

p_large_before = 0 kg·m/s.

After the collision, the small cart bounces back at a speed of 0.810 m/s. According to the law of conservation of momentum, the total momentum after the collision should equal the total momentum before the collision. Therefore, the momentum of the small cart after the collision is:

p_small_after = (mass_small) * (velocity_small_after) = (0.300 kg) * (-0.810 m/s) = -0.243 kg·m/s.

The momentum of the large cart after the collision is labeled p_large_after. Since the initial momentum of the large cart is zero and the momentum after the collision is determined by the momentum of the small cart, we can write:

p_large_after = -0.243 kg·m/s.

To find the speed of the large cart after the collision, we divide the momentum by its mass:

velocity_large_after = p_large_after / (mass_large) = (-0.243 kg·m/s) / (5.00 kg) = -0.0486 m/s.

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Answer:

Explanation:

Your question is quite confusing, particularly the information about microsecond = 0.5.

I'm going to ASSUME that you mean coefficient of static friction μs = 0.5

unfortunately typing a subscript "s" is very difficult and probably leads to such confusion.

I will also ASSUME that the block, and spring, and force vector are all horizontal.

If the force is slowly increased until the block slips, the spring will compress until the force on each end equals the maximum static friction force. As we are not concerned with the compression distance, only the force, we can ignore the spring constant information and simply find the maximum available static friction force.

F = μN

F = μmg

F = 0.5(4.0)(9.8)

F = 19.6 N

Not that it matters, but the spring will have extended or compressed 19.6/0.8 = 24.5 m, which is a very long and very light spring

The new planet has the radius of only 1/4th of earth and mass of half that of earth. Then , the gravity on the surface of the new planet will be8 times higher than that of earth.

The gravitational force is the force by which an object attracts other object into its center of mass. Earth attracts every objects on ots surface to the ground by gravitation.

The force of gravitation is directly proportional to the mass and inversely proportional to the distance or radius of the planet.

g =  G m/r²

Where G is the universal gravitational constant.

The new planet has the mass half of that of earth (me) and radius 1/4th of earth.

gn = G me/2 (re/4)²

  = G 16 me/2

  = 8 ge

Where ge is the gravity by earth and gn that of new planet. The gravitational force of the new planet will be 8 times greater than that of earth.

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Answer:

A) 10.0 m/s

Explanation:

the formula for average speed is  v=d/t

the distance is 100 meters

The time is 10.0 seconds

so  v=100m/10.0s

       = 10.0m/s

so the runners average speed was 10.0m/s

The average speed of the runner is equal to 10.0 m/s. Therefore, option (A) is correct.

The speed of a body can be described as the distance covered in a definite time interval. The average speed can be defined as a scalar parameter as it possesses magnitude with no direction.

The speed can be determined from the ratio of the distance traveled by the object to the time taken to travel that distance.

The speed of any object can be calculated from the formula equation mentioned below:

Speed =  total distance /time taken

Given, the distance covered by the runner = 100 m

The time taken by the runner, t = 10.0 s

The average speed of the runner can be calculated from the formula as shown below:

Speed = 100/10 = 10 m/s

Therefore, the average speed of the runner is 10.0 m/s.

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Answer:

10,800

Explanation:

The formula is MGH I hop this helps

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

The 15 km/s velocity is equivalent to 15000 m/s and 54000 km/h.

Velocity is a vector quantity. It consist both a direction and a magnitude. The magnitude of velocity is called speed. Its S.I. unit is a meter/second. It also has other units like Km/h and Km/s. Its dimensional formula is [\(LT^{-1}\)].

Given in the question

Velocity is 15 Km over a second

We can infer from the given value that the body moves 15 km per second.

1 Km = 1000 m

1 Km × 15  = 15 × 1000 m

So 15 Km = 15000 m

Hence we can say that the body travels 15000 meters in a second.

As a result, its velocity in m/s is 15000 m/s.

Now

15 kilometers can be covered in 1 second.

Distance traveled in 3600 seconds = 3600 × 15 Km

So the total distance traveled in 3600 seconds is 54000 kilometers.

Also 3600 seconds = 1 hour

In other words, The body travels 54000km in 1 hour, hence its velocity is 54000 km/h.

Therefore, the 15 km/h velocity is equal to 15000 m/s and 54000 km/h.

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For the first one, W = 7.3 kJ, Q = 25.83kJ

For the second one, W = Q = 124KJ

First One:

Parameters given are:

Mass m = 0.05kg

\(V_{2}\) = 0.0658 \(m^{3}\)

Since the pressure is constant, \(P_{1} = P_{2} = 2bar\)

While \(T_{1} = 130\)°C

Convert degree Celsius to degree kelvin

Temperature = 273 + 130 = 403 K

Before we can get the work done, we need to calculate the initial volume \(V_{1}\) by using Ideal gas general formula.

\(P_{1}V_{1} = mRT_{1}\)

Make \(V_{1}\) the subject of formula

\(V_{1}\) =  \(mRT_{1}\) / \(P_{1}\)

\(V_{1}\) = (0.05 x 287 x 403) / (2 x \(10^{5}\))

\(V_{1}\) = 0.0289\(m^{3}\)

From the table, specific volumes are:

\(u_{1}\) = 0.578\(m^{3}\)kg

\(u_{2}\) = 1.316\(m^{3}\)kg

Work done can be calculated by using the below formula

W = P( \(u_{2}\) - \(u_{1}\) )

W = 2 x \(10^{5}\)( 1.316 - 0.578)

W = 147600 J/kg

The Total work done = 147600 x 0.05 = 7380J = 7.3 kJ

To calculate the heat supplied by using the heat formula

Q = m\(C_{p}\)( \(T_{2} - T_{1}\)), we need to calculate for final temperature \(T_{2}\) and also check the table for

where \(C_{p}\) = 1.005

we can calculate for \(T_{2}\) by using Ideal gas formula

\(P_{2}V_{2} = mRT_{2}\)

make \(T_{2}\) the subject of formula

\(T_{2}\) = PV/mR

\(T_{2}\) = (2 x \(10^{5}\) x 0.0658) / (0.05 x 287)

\(T_{2}\) = 917 K

Substituting \(T_{2}\) and other parameters into the formula

Q = m\(C_{p}\)(\(T_{2} - T_{1}\))

Q = 0.05 x 1.005 ( 917 - 403)

Q = 25.83 KJ

Second one

From the question, the following parameters are given

mass m = 1kg

Molar M = 28kg/mol

Since the system is compressed reversibly and isothermally,

\(T_{2}\) = T = 20°C

\(P_{1}\) = 1.01 bar

\(P_{2}\) = 4.2 bar

To calculate both heat and work done, we will use the formula below

W = RTln\(P_{1}\)/\(P_{2}\)

But R = Ro/M

R = 8314/28

R = 297 J/kg.k

W = 297 x 293 x ln(1.01/4.2)

W = - 124kJ / kg

We can therefore conclude that the work input during the process is

124 KJ While the heat produced is also 124 KJ because W = Q

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9.8 N is the magnitude of the force that maintains circular motion acting on the puck.

32.53 m/sec is the linear speed of the puck.

The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. An item does not have a force inside of it or within it. Another item applies a force to another. The concept of a force is not restricted to living or non-living entities. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

As we know, from free body diagram, when the system is in equillibrium, the force acting on the puck on the table is as follows:

When the air puck of mass is revolving round the circle, then the tension (T) in the top string and the bottom of the string is same.

F = T

F = 9.8 N

Now, calculate the velocity of the puck:

From the given data, the air puck moves in a circular path. Hence, the tension in the top string is equal to the centripetal force acting on the puck.

Thus, the expression for the tension in the top string is as follows:

T = mv² / R

The velocity of the puck is as follows:

Mg = mv² / R

v² = MgR / m

v² = (2.7 × 9.8 × 1.2 ) / 0.030

v² = 1058.4

v = \(\sqrt{1058.4}\)

v = 32.53 m/sec

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maybe a spectrograph ?

Answer:sin40∘=0.643) Hint: The relationship of angle of incidence and angle of refraction at interface of two media is given by Snell's law.

Explanation:

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

The greatest distance of the block from the center of rotation so that it does not slip is approximately 0.089 meters or 8.9 centimeters.

In order for the block to remain on the turntable without slipping, the frictional force between the block and the turntable must be equal to or less than the maximum friction that can be developed, which is 2 N in this case. The maximum frictional force is given by the product of the coefficient of friction and the normal force.The normal force is equal to the weight of the block, which is 5 N. Therefore, the maximum frictional force is 2 N.

To find the greatest distance of the block from the center of rotation without slipping, we need to consider the centrifugal force acting on the block due to the rotation of the turntable. The centrifugal force is given by the product of the mass of the block, the acceleration due to the rotation (which is equal to the square of the angular velocity times the radius), and the coefficient of friction.

Since the weight of the block is 5 N, the mass can be calculated as 5 N divided by the acceleration due to gravity (approximately 9.8 m/s^2), which gives us a mass of approximately 0.51 kg.

Given that the turntable is rotating at 0.6 revolution per second, the angular velocity can be calculated as 2π times the frequency, which gives us approximately 3.77 rad/s.

Let's assume the greatest distance of the block from the center of rotation is "r" meters.

The centrifugal force is then given by m * (ω^2) * r, and this force must be equal to or less than the maximum frictional force, which is 2 N.

Therefore, we can write the equation:

m * (ω^2) * r ≤ 2 N

Substituting the values we calculated:

0.51 kg * (3.77 rad/s)^2 * r ≤ 2 N

Simplifying the equation, we find:

r ≤ 0.089 m

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Answer:

i think its D

Explanation:

Answer:

The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.

Answer:

a. 4N and 7N

Explanation:

Draw a free body diagram.

Sum of the forces in the x direction:

∑F = ma

T₂ cos 30° − T₁ cos 60° = 0

T₂ cos 30° = T₁ cos 60°

T₂ (½√3) = T₁ (½)

T₁ = T₂ √3

Sum of the forces in the y direction:

∑F = ma

T₂ sin 30° + T₁ sin 60° − mg = 0

T₂ sin 30° + (T₂ √3) sin 60° − mg = 0

½ T₂ + 1.5 T₂ − mg = 0

2 T₂ = mg

T₂ = 4 N

T₁ = 4√3 N

T₁ ≈ 7 N

The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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