Answer:
180 m/s
Explanation:
To find the answer you simply divide 900 by 5.
Which is not an Ultimate Frisbee rule?
238 U + 92 write the complete nuclear equation
Answer:The equation is balanced for both charge and nucleon number, as required.
Explanation:2713Al + 42He → 3015P + n
PLS HELP MEH!!!!
Sound travels fastest in
a) air
b) water
c) glass
d) diamond
WILL MARK BRAINLIEST IF ANSWER
Answer:
hope this helps
Explanation:
Of the three phases of matter (gas, liquid, and solid), sound waves travel the slowest through gases, faster through liquids, and fastest through solids
so your answer would be B.
lol i'm going to fail please help
Scientists have found that the long slow sound produced by blue whales is almost consistently a B pitch at 16.0 Hz. The wavelength of this note is 97.5 m. How long would it take for this sound from a blue whale of scientists that is tracking them from 11 km away?
The answer is 7.1 s I just don't know how to get it :/
NO LINKS ISTGGGG
Answer:
Explanation:
The frequency is 16.0 Hz. That means that 16 of these waves can pass a single point in 1 second. We are given frequency and wavelength. The equation that relates them is
\(f=\frac{v}{\lambda}\) where f is frequency, v is velocity, and λ is wavelength. Putting all this together:
\(16.0=\frac{v}{97.5}\) and solving for velocity,
v = 16.0(97.5) so
v = 1560 m/s. This wave can travel 1560 meters in a single second!!! Now that we know this velocity, we can use it in a proportion to find our unknown, which is how long, t, it will take to hear this sound 11000m away. (11 km is 11000m):
\(\frac{1560m}{1s}=\frac{11000}{t}\) and cross multiply to get
1560t = 11000 so
t = 7.1 seconds
what is the weight of a 60 kg table.
Weight = Fg = mg = (60 kg)*(9.8 m/s2) = 588 N
Part A A supernova that occurs 10,000 years from now in a galaxy 50,000 light years away: A supernova that occurs 10,000 years from now in a galaxy 50,000 light years away: was observed on Earth 40,000 years ago. was observed on Earth 50,000 years ago. will be observed on Earth 50,0000 years from now. will be observed on Earth 60,000 years from now. will be observed on Earth 10,000 years from now.
The Supernova will be observed on Earth 60,000 years from now.
What is Supernova?A supernova is a star's tremendous and brilliant explosion. It is referred to as a supernova or a supernovae and is abbreviated as SN or SNe.This fleeting astronomical occurrence takes place either when a white dwarf is set off into uncontrolled nuclear fusion or during the latter phases of the development of a big star. The original object, known as the progenitor, either disintegrates completely or falls into a neutron star or black hole.Before fading over the course of several weeks or months, the peak optical luminosity of a supernova can be similar to that of an entire galaxy.Compared to novae, supernovae are more energetic. Nova, which in Latin means "new," refers to what appears to be a transitory new bright star in astronomy. Supernovae can be distinguished from regular novae by the prefix "super-."To learn more about Supernova with the given link
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If Earth's mass doubled, your weight would..
a. increase
b. decrease
c. stay the same
Answer:
a. increase
Explanation:
Doubling the mass of the Earth would double your weight, since gravitational force is directly proportional to mass, but doubling the radius (which doubles if the diameter doubles) would decrease your weight by a factor of 1/4, since gravitational force is inversely proportional to the square of the radius.
Suppose you want to calculate how much work it takes to lift a 22.5 Kg barbell. Besides the mass of the
barbell, what other information do you need to know? (Circle all that apply)
a. the shape of the weights
b. how high the barbell is being lifted
c. the strength of the person doing the lifting
d. the strength of gravity
e. None of the above
Answer:
Explanation: I know that people'strength vary on what they can lift.
8. what type of curves or surfaces might be used in a graphical representation of physical phenomena that have similar shapes at multiple scales?
Fractal curves or surfaces might be used in a graphical representation of physical phenomena that have similar shapes at multiple scales.
Fractals are self-similar patterns that repeat at different levels of magnification, making them useful in representing complex phenomena such as turbulence, erosion, and the branching patterns of trees and rivers. They are also commonly used in computer graphics and simulations.
The type of curves or surfaces that might be used in a graphical representation of physical phenomena that have similar shapes at multiple scales are called fractals. Fractals are self-similar patterns, meaning they have the same or similar shapes when viewed at different scales. These curves and surfaces can be used to model various natural phenomena, such as coastlines, mountains, and cloud formations, as well as in various scientific and mathematical applications.
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Balok diam diatas bidang miring pada sudut kemiringan 40° balok mulai bergerak,tentukan koefisien gesek statis antara balok dan bidang miring
Answer:
0.84
Explanation:
m = Massa balok
g = Percepatan gravitasi
\(\theta\) = Sudut kemiringan
\(\mu\) = Koefisien gesekan statik antara balok dan bidang miring
Gaya balok karena beratnya diberikan oleh
\(F=mg\sin\theta\)
Gaya gesekan diberikan oleh
\(f=\mu mg\cos\theta\)
Kondisi dimana balok mulai bergerak adalah ketika gaya balok akibat beratnya sama dengan gaya gesek pada balok.
\(mg\sin\theta=\mu mg\cos\theta\\\Rightarrow \mu=\dfrac{mg\sin\theta}{mg\cos\theta}\\\Rightarrow \mu=\tan\theta\\\Rightarrow \mu=\tan40^{\circ}\\\Rightarrow \mu=0.84\)
Koefisien gesekan statik antara balok dan bidang miring adalah 0.84.
a car of mass 1200kg travelling at 30m/s runs into the back of a stationary
lorry. The car and lorry move at 4m/s after impact. Determine the mass of the
lorry.
Answer:
The mass of the lorry 7800 kg
Explanation:
Momentum conservation law for inelastic collision:
\(m1*V1 + m2*V2 =( m1 + m2)*V^{'} \\ \\1200*10^{3} g * 30 m/s + m2*0 m/s =(1200*10^{3} g + m2)*4 m/s\\ \\\frac{1200*10^{3} g * 30 m/s}{4 m/s} -1200*10^{3} g=m2\\ \\m2=9000*10^{3} g-1200*10^{3} g=7800*10^{3} g=7800 kg\)
A metal spoon is put in a cup of hot tea and then put it into the mouth. The spoon is not very hot, but the tea is much hotter. Why?
A rocket leaves a launch pad at liftoff with a great deal of upward momentum. what was initially given downward momentum?
The downward momentum initially given is carried by the exhaust gases expelled from the rocket engines.
According to the law of conservation of momentum, the total momentum of a system remains constant if no external forces act on it. In the case of a rocket launching from a launch pad, the upward momentum of the rocket is balanced by an equal and opposite downward momentum given to something else in the system.
Typically, in rocket launches, the downward momentum is given to the exhaust gases expelled from the rocket engines. As the rocket engines expel gases at high speeds in the downward direction, the gases carry a significant amount of momentum in that direction. This downward momentum of the exhaust gases is equal in magnitude but opposite in direction to the upward momentum of the rocket.
So, in the scenario described, the downward momentum initially given is carried by the exhaust gases expelled from the rocket engines.
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Jibari walks 40. 0 meters east in 120. 0 seconds. He then walks 30. 0 meters west in 60. 0 seconds. What is his average velocity for the trip??
Answer:
0.389 meters per second
Explanation:
1. Get your knowns
a. 40 meters per 120 seconds
b. 30 meters per 60 seconds
2. Add
Total distance = 40 meters + 30 meters = 70 meters
Total time = 120 seconds + 60 seconds = 180 seconds
3. Divide
Average velocity = 70 meters / 180 seconds
= 7 meters / 18 seconds
= 0.388... meters per second
Which term best describes how the solar system formed?.
Answer:
Approximately 4.6 billion years ago, the solar system was a cloud of dust and gas known as a solar nebula.
Explanation:
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A student uses a 320 Hz tuning fork during a lab investigation into the speed of sound. If the air temperature in the classroom is 20 degrees Celsius, what is the wavelength of the sound waves produced by the tuning fork?
A. 1.07 m
B. 3.43 m
C. 0.933 m
D. 343 m
E. 343 m
Answer:343m
Explanation:
What are some things to be wary of with hemoconcentrators?
By being wary of these factors and following the recommended guidelines, you can ensure the safe and effective use of hemoconcentrators in medical procedures.
When using hemoconcentrators, it's essential to be cautious and consider a few factors to ensure their safe and effective use. Some things to be wary of with hemoconcentrators include:
1. Compatibility: Make sure the hemoconcentrator is compatible with your specific application and equipment to avoid any malfunctions or complications during the procedure.
2. Clotting risks: Hemoconcentrators can sometimes lead to increased blood clotting risks. Ensure appropriate anticoagulation measures are in place during the procedure to minimize this risk.
3. Flow rate: Be mindful of the blood flow rate through the hemoconcentrator. Exceeding the recommended flow rate could lead to hemolysis or other complications.
4. Sterility: Maintain a sterile environment and follow proper handling procedures to prevent contamination, which could potentially lead to infection.
5. Monitoring: Closely monitor the patient's vital signs, blood pressure, and fluid balance during the procedure to promptly identify and address any adverse reactions or complications.
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A child and sled with combined mass m1 begin to slide from rest at the top of an icy frictionless hill of height H. At the bottom of the hill the sled collides with a snowman of mass m2 that falls onto the sled. What will be the final speed of the combined child, sled, and snowman system?
Final speed of the combined child, sled, and snowman system is given by: v_final = (m1 * sqrt(2 * g * H)) / (m1 + m2)
Explanation:
To find the final speed of the combined child, sled, and snowman system, follow these steps:
step1: Calculate the gravitational potential energy (PE) of the child and sled at the top of the hill: PE = m1 * g * H, where g is the acceleration due to gravity.
step2: Since there is no friction, the potential energy will convert into kinetic energy (KE) at the bottom of the hill: KE = 0.5 * m1 * v1^2, where v1 is the speed of the child and sled at the bottom of the hill.
step3: Equate the potential and kinetic energies: m1 * g * H = 0.5 * m1 * v1^2. Solve for v1: v1 = sqrt(2 * g * H).
step4: Use the conservation of momentum principle for the collision between the sled and the snowman: m1 * v1 = (m1 + m2) * v_final, where v_final is the final speed of the combined system.
step5: Substitute the expression for v1 from step 3 into the momentum equation and solve for v_final: v_final = (m1 * sqrt(2 * g * H)) / (m1 + m2).
Thus, the final speed of the combined child, sled, and snowman system is given by: v_final = (m1 * sqrt(2 * g * H)) / (m1 + m2).
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2. Think about an activity you may have learned that involves muscle memory. Consider when you first learned the activity, how easy or difficult it was the first time, and if you can do it now without thinking. What happened in your brain during practices that resulted in muscle memory for you?
Answer:
Muscle memory is found in many everyday activities that become automatic and improve with practice, such as riding bicycles, driving motor vehicles, playing ball sports, typing on keyboards, entering PINs, playing musical instruments, poker, martial arts, and dancing.
Explanation:
an athlete leaves one end of a pool of length at and arrives at the other end at time . she swims back and arrives at the starting position at time . if she is swimming initially in the positive direction, determine her average velocities symbolically in
Given that an athlete leaves one end of a pool of length at and arrives at the other end at time . She swims back and arrives at the starting position at time . If she is swimming initially in the positive direction, we need to find her average velocities symbolically in positive and negative direction.
The formula for average velocity is: Average velocity = displacement/time taken We know that the displacement is zero because the athlete returns to the starting point. Hence, the average velocity is zero in both the positive and negative directions. Mathematically, we can write it as: v _avg = 0 (in both directions)Therefore, the average velocities symbolically in both the positive and negative directions are zero.
an athlete leaves one end of a pool of length at and arrives at the other end at time . she swims back and arrives at the starting position at time . if she is swimming initially in the positive direction, determine her average velocities symbolically in the average velocities symbolically in both the positive and negative directions are zero. If she is swimming initially in the positive direction, we need to find her average velocities symbolically in positive and negative direction.
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Two cats jump off a roof that is 23m off the ground. Cat A jumps directly up with a velocity of 7m/s, and cat B jumps directly down with a velocity of 7m/s. How far up does cat A go? How fast does cat A go just before it hits the ground? How fast does cat B go just before it hits the ground? How much longer is cat A in the air than cat B?
The height reached by cat A is 2.5 m.
The speed of cat A before it hits the ground is 36.4 m/s.
The speed of cat B before it hits the ground is 22.39 m/s.
The time spent in air by cat A than cat B is 1.43 seconds.
Time of motion of cat A
The time of motion of cat A is calculated as follows;
h = vt - ¹/₂gt
-23 = 7t - 4.9t²
4.9t² - 7t - 23 = 0
solve the quadratic equation using formula method;
a = 4.9, b = -7, c = - 23
t = 3.0 seconds
Time of motion of cat BThe time of motion of cat B is calculated as follows;
h = vt - ¹/₂gt
23 = 7t + 4.9t²
4.9t² + 7t - 23 = 0
solve the quadratic equation using formula method;
a = 4.9, b = 7, c = -23
t = 1.57 seconds
Height reached by cat Ah = u²/2g
h = (7²)/(2 x 9.8)
h = 2.5 m
Speed of cat A before it hits the groundv = u + gt
v = 7 + 3(9.8)
v = 36.4 m/s
Speed of cat B before it hits the groundv = u + gt
v = 7 + 1.57(9.8)
v = 22.39 m/s
Time spent in air by cat A than cat B
Time difference = 3 s - 1.57 s = 1.43 seconds
Thus, the height reached by cat A is 2.5 m.
The speed of cat A before it hits the ground is 36.4 m/s.
The speed of cat B before it hits the ground is 22.39 m/s.
The time spent in air by cat A than cat B is 1.43 seconds.
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30 ml= 30 ml- 26 mL 26 mL- 22 ml -22 ml- -B 18 ml 18 ml- 14 mL 14 mL- 10 ml- 10 ml- X The mass of sample X is 20.0g. It was placed in a graduated cylinder and the water level rose from A to B. What is the density of sample X? Pay close attention to significant figures.
Answer:4.0
Explanation:
please help :(
3.) What is the physical quantity which
represents the basis of the functioning of a
loudspeaker?
4.) Why doesn't a direct current operate a
loudspeaker?
If an object was traveling horizontally off a cliff at 9 m/s for 7 seconds, how far did it go?
The object travelled 63 meters at 9m/s for 7 seconds.
What is distance travelled?The length of the trajectory taken between the initial and final positions of the moving body is the distance traveled.
To calculate the distance traveled by an object traveling horizontally off a cliff, you can use the formula:
d = v * t
where d is the distance traveled, v is the velocity (9 m/s), and t is the time (7 seconds).
By substituting the given values into the formula, we get:
d = 9 * 7 = 63 meters
So, the object traveled 63 meters horizontally before it hit the ground after being launched off the cliff at 9 m/s for 7 seconds.
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Fossil fuels are burned, transferring their chemical potential energy to heat energy. How are nuclear power stations different?
Answer:
fossil fuels are natural and limited, nuclear is man made and more toxic
Explanation:
A child attaches a rubber ball to a string and whirls it around in a circle overhead. If the string is 0.2m long and the ball's speed is 16 m/s, what is the ball's centripetal acceleration?
Answer:
The centripetal acceleration, \(a_c = 1280 m/s^2\)
Explanation:
Centripetal acceleration is given by the formula:
\(a_c = \frac{v^2}{r}\)
Where the speed of the ball, v = 16 m/s
Length of the string, r = 0.2 m
Substituting these parameters into the centripetal equation above:
\(a_c = \frac{16^2}{0.2}\\a_c = \frac{256}{0.2}\\a_c = 1280 m/s^2\)
What is the net force on a 4,000-kg car
that doubles its velocity from 15 m/s west
to 30 m/s west over 10 seconds?
Answer:
6000 N toward west
Explanation:
F = ma
a = 30-15/10 = 1.5 m/s^2 towards west
m = 4000 kg
F = 4000 x 1.5 = 6000 N towards west
Gold-198 has a half-life of 2.7 days. Complete the table for an initial sample size of 200 grams
25.1 grams are still present after 8.1 days. When the Gold-198 has a half-life of 2.7 days.
What is radioactivity?The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that wants to give up some energy in order to move to a more stable form.
The half-life of the gold =2.7 days
Sample size = 200 grams
N is the left amount after the given time =?
Constant of rate = 0.26
The rate constant is found as;
\(\rm \lambda = \frac{0.693}{t^{\frac{1}{2}}} \\\\ \lambda = 0.256 \ days^{-1}\)
The amount after the given time;
\(\rm N=N_0 \times e^{-\lambda t} \\\\\ N = 200 \times e^{-0.256 \times 8.1 \ days} \\\\N=25.1 \ gm\)
Hence,25.1 grams are still present after 8.1 days.
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Differentiate between the resolving power and magnifiying power of a lens. What is meant by the term "parfocal"?
Resolving power refers to the ability of a lens to distinguish between two closely spaced objects. It is determined by the wavelength of light and the numerical aperture of the lens.
Magnifying power, on the other hand, refers to the ability of a lens to enlarge the size of an object. It is determined by the focal length of the lens.
The term "parfocal" refers to a type of lens system where multiple lenses have the same focal point when the focus is adjusted. This means that when switching between different lenses, the focus remains the same, making it easier for the user to switch between lenses without losing focus.
Differentiating between the resolving power and magnifying power of a lens involves understanding their respective functions. Resolving power refers to the ability of a lens to distinguish between two closely spaced objects, or in other words, the clarity with which the lens can produce an image. Magnifying power, on the other hand, refers to the degree to which a lens can enlarge the image of an object.
The term "parfocal" is used to describe a set of lenses that, when interchanged on a microscope or other optical instrument, maintain their focus on the same object. This means that when you switch from one parfocal lens to another, only minimal adjustments to the focus are needed, allowing for a seamless transition between lenses with different magnifying powers.
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Resolving Power: It is the ability of a lens to separate or distinguish between closely spaced objects, reflecting the detail that can be seen with the lens.
The magnifying powerMagnifying Power: It denotes how much larger an object appears through a lens compared to its actual size. High magnification doesn't necessarily mean better image quality.
Parfocal: This term refers to lenses that remain in focus even when the magnification or focal length changes. It enables swift adjustments in magnification without needing constant refocusing.
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1. What kind of spectrum (continuous, bright line or dark line) would you expect to see (in visivble light) from each of the following objects? Explain how you reached each conclusion. a. a steel girder, still glowing as it is removed from its mold b. sunlight shining through our atmosphere (as seen from Earth's surface) c. the Orion Nebula (a hot, glowing cloud of thin gases)
2. The planets in our solar system show regularities and trends that suggest they formed in a rotating disk of gases and dust grains called solar nebula. Describe three of these regularities/trends and their significance in the solar nebula concept.
1. a. A steel girder, still glowing as it is removed from its mold, would produce a **bright line spectrum**. This is because the intense heat causes the atoms in the steel to emit light at specific wavelengths. The high temperature excites the electrons in the atoms, and as they return to lower energy levels, they emit photons of specific energies, resulting in distinct bright lines in the spectrum.
b. Sunlight shining through our atmosphere (as seen from Earth's surface) would produce a **continuous spectrum**. The sunlight consists of a broad range of wavelengths, covering the entire visible spectrum. As it passes through Earth's atmosphere, which contains various gases, particles, and molecules, these components do not selectively absorb or emit specific wavelengths, resulting in a continuous distribution of colors in the spectrum.
c. The Orion Nebula, a hot, glowing cloud of thin gases, would exhibit an **emission line spectrum**. The gases in the nebula are energized by nearby stars, causing them to emit light at specific wavelengths characteristic of the elements present. The excited electrons in the gas atoms emit photons at discrete energies, creating bright lines in the spectrum corresponding to specific elements or molecular transitions.
2. Three regularities/trends observed in the planets of our solar system that support the solar nebula concept are:
a. **Orbital Plane Alignment**: Most planets orbit the Sun in a nearly flat plane known as the ecliptic. This alignment suggests that the planets formed from a rotating disk of gas and dust, as the rotation of the solar nebula would have caused material to flatten into a disk-shaped structure.
b. **Terrestrial and Jovian Planet Differences**: There is a clear distinction between the inner terrestrial planets (Mercury, Venus, Earth, and Mars) and the outer gas giant planets (Jupiter, Saturn, Uranus, and Neptune). The terrestrial planets are smaller, denser, and composed mainly of rocky material, while the gas giants are larger, less dense, and composed mostly of hydrogen and helium. This supports the idea that the solar nebula had different zones with varying compositions and temperatures, leading to the formation of different types of planets.
c. **Rocky Debris in Inner Solar System**: In the inner solar system, there are numerous rocky asteroids and comets, which are remnants from the early stages of planet formation. These bodies are predominantly found in the asteroid belt between Mars and Jupiter and the Kuiper Belt beyond Neptune. Their presence suggests that rocky material was abundant closer to the Sun, while the outer regions contained more gas and icy material.
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