A projectile is launched from ground level with an initial speed of 47 m/s at an angle of 0.6 radians above the horizontal. It strikes a target 1.7 seconds later. What is the vertical distance from where the projectile was launched to where it hit the target.

(a) The magnitude of the charge on sphere is 1.52 x 10⁻⁸ C.

(b) The total electric flux leaving surface of sphere is 1,717.86 Nm²/C.

(c) The electric field at surface of sphere is 91.82 N/C.

The charge on the sphere is calculated as follows;

Q = Aσ

where;

A = 4πr²

A = 4π(1.22)² = 18.7 m²

Q = (18.7) x (8.13 x 10⁻⁶ x 10⁻⁴)

note: 1 cm² = 10⁻⁴ m²

Q = 1.52 x 10⁻⁸ C

Ф = Q/ε₀

Φ = (1.52 x 10⁻⁸) / (8.85 x 10⁻¹²)

Φ  = 1,717.86 Nm²/C

E = Ф/A

\(E = \frac{Q}{4\pi \varepsilon _0 r^2} \\\\E = \frac{1.52 \times 10^{-8} }{4\pi \times 8.85 \times 10^{-12} \times (1.22)^2} \\\\E = 91.82 \ N/C\)

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Explanation:

In this case, if the current points down, then the middle finger points down. If the field is to the left, then the forefinger points to the left. To satisfy the left hand rule, the thumb must point towards you, which indicates that the motion is towards you. Therefore, the motion is towards you.

Answer:

       d = 6 i^   m

Explanation:

This is an exercise in kinematics, where the position vector is the displacement of the body from one point to another.

In this case we are told that for t = 0 the worm is at x₀ = 3m and with velocity starts from zero, after t = 1 s it is at x₁ = 9m and with a velocity of

v₁ = 5 m / s

They ask what is the displacement for the time of 1 s

               d = x₁ - x₀

               d = 9 -3 m

               d = 6 m

Bold indicates vector, displacement vector is

             d = 6 i ^ m

If the system is moving to the left with a constant acceleration and the surface is perfectly smooth, the reading on the spring balance would be zero.

The spring balance measures the force exerted on it, which in this case would be the force due to gravity acting on the object.

However, since the surface is smooth and there is no friction, there would be no additional force acting on the object, resulting in zero net force and therefore zero reading on the spring balance.

We observe that only in these particular circumstances would the reading on the spring balance be zero.

The reading on the spring balance would be different if there were additional forces operating on the object, such as friction or an outside force.

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The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

350 m/s

31 degrees C.

Explanation:

speed of sound is given as the product of frequency and wavelength

1m to be 100 cm than 35 cm will be 35/100=0.35m

Answer: This was due on the 20th

Explanation:

Answer:

simple carbohydrate

Explanation:

Simple carbs are like cakes, donuts, and candy, etc.

Hope this helps :D

Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Answer:

The strength of the electric field is determined by the amount of charge on the source charge (Q) and the separation distance (d) from the source charge.

Explanation:

The interaction of charged objects is a non-contact force that operates over a certain separation distance. Distance, distance, distance. Every electrical contact is accompanied by a force, emphasizing the significance of these three factors. Whether it's a plastic golf tube attracting paper bits, two like-charged balloons repelling, or a charged Styrofoam plate interacting with electrons in a piece of metal, the three crucial factors that impact the strength of the interaction are always two charges and a distance between them.  The electrical force, like all other forces, is usually measured in Newtons. The electrical interaction's intensity is a vector quantity with both magnitude and direction since it is a force. The electrical force's direction is determined by whether the charged objects are charged with similar or opposing charges, as well as their spatial orientation. With a little logic and knowledge of the two objects' charge types, the direction of the force on either of them may be determined. Objects A and B in the figure below have similar charges, hence they repel each other.

Answer:

coal

Explanation:

Answer:

The formula for potential energy depends on the force acting on the two objects.

Answer:

v = 0.54 m/s

Explanation:

The Principle Of Conservation Of Mechanical Energy

In the absence of friction, the total mechanical energy is conserved. That means that

Em=U+K is constant, being U the potential energy and K the kinetic energy

U=mgh

\(\displaystyle K=\frac{mv^2}{2}\)

When the mass (m=1 kg) of the pendulum is at the top of the path at a height of h=1.5 cm=0.015 m, its kinetic energy is 0 and its potential energy is:

U=1 * 9.8 * 0.015 = 0.147 J

That potential energy is completely transformed into kinetic energy at the bottom of the swing. The speed can be calculated by solving for v:

\(\displaystyle \frac{mv^2}{2}=0.147\)

Multiplying by 2 and dividing by m:

\(\displaystyle v^2=\frac{2K}{m}\)

\(\displaystyle v^2=\frac{2*0.147}{1}=0.294\)

\(v=\sqrt{0.294}\)

v = 0.54 m/s

Answer:

63 miles per hour

Explanation:

you just divide miles and hours to get your average speed

To solve this we must be knowing each and every concept related to velocity. Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

V is the velocity measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.

For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.

v = √(k / m) ×A

v = velocity of the mass

k= spring constant

m =mass of the object

A= amplitude of the oscillation.

substituting all the given values in the above equation, we get

2.3 m/s = √(200 N/m / 3.00 kg)×A

A = 2.3 m/s / √(200 N/m / 3.00 kg)

    = 0.23 m

v =√(200 N/m / 3.00 kg) ×0.23 m

 = 2.75 m/s

Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

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Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.

The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.

The force applied is the weight of the bag, which is given by:

F = m * g

where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:

F = 50 kg * 9.81 m/s²

F = 490.5 N

The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:

v = (10 * 30 cm) / 10 s

v = 30 cm/s

The power of the porter is the rate at which work is done, which can be calculated as:

P = W / t

where W is the work done and t is the time taken. Substituting the values, we get:

P = F * d * v / t

P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s

P = 441,450 J/s

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The time required for half of the oil droplets to coalesce is 34.65 minutes.b) Calculation to find how long it takes for practically all of the oil droplets to coalesce:To find the time it would take for practically all of the oil droplets to coalesce, we need to use the following formula and solve for time when n is equal to 0.0 = e^(-0.02t)-infinity = -0.02tNo oil droplets remain after an infinite amount of time. Therefore, it takes an infinite amount of time for all the oil droplets to coalesce.Answer: It takes an infinite amount of time for all the oil droplets to coalesce.

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To find iy, va, vb, and vc in the circuit below, you can use the techniques of Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL). By using these two laws, you can find the unknowns in the circuit by setting up a system of equations.

KVL states that the algebraic sum of all the voltages around any loop of a circuit must equal zero. KCL states that the algebraic sum of all the currents into and out of any node must equal zero.

For example, if the circuit is labeled in a clockwise direction, the equation for KVL can be written as V1 + V2 + V3 = 0, and the equation for KCL can be written as I1 + I2 = I3.

Once the equations are set up, you can solve for iy, va, vb, and vc by using substitution or elimination.

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Answer:

slender-bodied non-stinging insect having iridescent wings that are outspread at rest; adults and nymphs feed on mosquitoes etc.

Explanation:

I hope this works. I have a snake and it helps to know this stuff

Answer:

 g = 1.19 m / s²

Explanation:

Let's solve this problem in parts.

Let's start by looking for the speed of the pulse in the wire, the wave speed is constant

          v = l / t

let's calculate

          v = 1.52 / 0.0833

           v = 18.25 m / s

now we can use the relationship between velocity and material properties

           v = \(\sqrt{\frac{T}{\mu } }\)

           T = v² μ

let's calculate

           T = 18.25² 4.41 10-4

           T = 1.4688 10-1 N

finally let's use the equilibrium condition

            T - W = 0

            W = T

             m g = T

             g = T / m

we calculate

              g = 1.4688 10⁻¹ / 0.123

              g = 1.19 m / s²

Answer:

5.98 m

Explanation:

\(T=2\pi \sqrt\frac{L}{g}\)

\(T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2)\) = 11.15*4.6²/(4π²) = 5.98 m

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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According to the question the initial velocity of the airplane was 607.5 m/s.

Initial velocity is the speed of an object at the start of a motion. It is a vector quantity, which means that it has both a direction and a magnitude. The direction of an object's initial velocity is the same as the direction of its motion and the magnitude of its initial velocity is equal to the speed at which it is moving. Initial velocity is often denoted by the letter “u” and its units are usually meters per second (m/s). Initial velocity can be used to calculate the position of an object at any given time using equations of motion.

The initial velocity of the airplane can be calculated using the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Plugging in the given values:
v = 0 + (11.5 m/s2 × 53 s)
v
= 607.5 m/s
Therefore, the initial velocity of the airplane was 607.5 m/s.

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A 20.0 N block slides over a horizontal table. If it takes 5.0 N to move the block at a constant velocity, the coefficient of friction is D. 0.25.

Given,

Frictional force (F) is 5.0 N

Normal force (N) is 20.0 N

The coefficient of friction (µ), a numerical value, is obtained by dividing the resistive force of friction (F) by the normal or perpendicular force (N) pushing the objects together.

i.e., µ = F/N

Calculating the coefficient of friction :

The frictional force is equal to and opposing the applied force since the box is traveling at a constant speed.

µ = F / N

µ = 5.0 N / 20.0 N

µ = 1/4 N

µ = 0.25 N

Thus, the coefficient of friction is D. 0.25.

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The separation distance in B is a number times greater than in A, then the force of attraction in B is less than A.

The force of attraction between two charged object is determined by applying Coulomb's law.

Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

Mathematically, this law is written as;

F = Kq₁q₂/r²

where;

From the formula given above, as the distance of separation increases, the magnitude of the force of attraction between the charges decreases. Also, as the distance of separation between the charges decreases, the magnitude of the force of attraction between the charges increases.

Thus, the magnitude of the force of attraction between charged objects is a function of the magnitude of the charges and distance of separation between the charges.

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After considering the given data and information we come to the conclusion that overall magnitude of the carts' common final velocity is 3.6 m/s, under the condition that a cart with mass m subscript 1 equals 0.25 space k g is at rest on a track.

Then, we can apply the law of conservation of momentum to evaluate the common final velocity of the carts.

The law of conservation of momentum projects that the total momentum of an isolated system stays constant if no external forces act on it. For this required case, the system is the two carts.

Before the collision, the first cart is in the rest and the second cart has a velocity of 6.17 m/s. Hence, the total momentum of the system before the collision is

p = m₁v₁ + m₂v₂

Here,

m1 and m2 are the masses of the carts and `v1` and `v2` are their velocities.

Staging the given values,

p = (0.25 kg)(0 m/s) + (0.35 kg)(6.17 m/s)

Applying simplification this expression

p = 2.16 kgm/s

Post the event of collision, the two carts stick along each other and move with a common final velocity `v`. The total momentum of the system after the collision is

p = (m₁ + m₂)v

Staging the given values, and evaluate for v

v = p / (m₁ + m₂)

Staging the given values

v = (2.16 kgm/s) / (0.25 kg + 0.35 kg)

v = 2.16/0.6

Applying simplification this expression

v ≈ 3.6 m/s

Then, the overall magnitude of the carts' common final velocity is approximately 3.6 m/s.

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Answer:

240Nm

Explanation:

Given parameters:

Force on the bank vault = 300N

Distance to the plane of the vault  = 0.8m

Unknown:

Torque = ?

Solution:

Torque is the component of force that causes an object to rotate about an axis;

  Torque  = Fr x sinФ

Here Ф  = 90°

         r  = distance

   Torque  = 300 x 0.8 x Sin 90°

    Torque  = 240Nm

mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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