A projectile is launched at an angle into the air at velocity v and angle 0. Determine its vertical acceleration.
The answer choices are in the picture.

1 mole of nitrogen atoms moving at 35.0 m/s possesses approximately 27.8 joules of energy.

To calculate the energy possessed by 1 mole of nitrogen atoms moving at 35.0 m/s, we need to consider both the kinetic energy and the molecular mass of nitrogen.

The kinetic energy (KE) of an object is given by the equation KE = 1/2 * m * v^2, where m is the mass and v is the velocity.

The molar mass of nitrogen (N₂) is approximately 28.0134 g/mol, which can be converted to kilograms by dividing by Avogadro's number (6.022 × 10^23). This gives us a mass of approximately 4.65 × 10^(-26) kg for one nitrogen atom.

Plugging in the values, we have KE = 1/2 * (4.65 × 10^(-26) kg) * (35.0 m/s)^2.

Evaluating the equation, we find that the kinetic energy possessed by one nitrogen atom is approximately 4.62 × 10^(-23) joules.

Since we are considering 1 mole of nitrogen atoms, we need to multiply this value by Avogadro's number to get the energy possessed by 1 mole. Avogadro's number is 6.022 × 10^23, so the total energy is approximately 2.78 × 10^1 joules, or 27.8 J.

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Answer:

1) 50 facing towards the right

2) 150 facing right

3) 200 facing right

4) 0- no direction

5) 50- facing left

6) 50 facing right

Explanation:

forces in opposite directions and equal magnitudes counteract each other. in number 2 they face the same direction so they would just be added. in number 4 they oppose each other so would be subtracted

Answer:

We know the momentum after the collision MUST be equal to the momentum BEFORE the collision.  

Momentum is a VECTOR quantity having both magnitude and direction.  The first ball has momentum P =m*v = 2*4 = 8 at 90degrees.  The second ball has momentum P = 1*8 = 8 at -90 or 270 degrees.  They sum to zero when you perform vector addition.

Explanation:

Answer:

Explanation:

We can use the kinematic equation v^2 = u^2 + 2as to solve for the length of the driveway. Here, u = 0 (since the car starts from rest), v = 3.8 m/s, a = F/m = 4.0 x 10^3 N / 2.1 x 10^3 kg = 1.9 m/s^2. Solving for s, we get:

s = (v^2 - u^2) / 2a = (3.8^2) / (2 x 1.9) = 3.8 m

So the length of the driveway is 3.8 meters.

A. The ball's (vertical) velocity \(v\) at time \(t\) is

\(v(t) = 30\dfrac{\rm m}{\rm s} - gt\)

so that after 4 seconds, the ball's speed is

\(|v(4\,\mathrm s)| = \left|30\dfrac{\rm m}{\rm s} - \left(10\dfrac{\rm m}{\mathrm s^2}\right) (4\,\mathrm s)\right| = \boxed{10\frac{\rm m}{\rm s}}\)

(The velocity is -10 m/s, so the ball is falling back down at this point.)

B. At maximum height, the ball has zero velocity, so it takes

\(30\dfrac{\rm m}{\rm s} - gt = 0 \implies t = \dfrac{30\frac{\rm m}{\rm s}}g = \boxed{3\,\mathrm s}\)

for the ball to reach this height.

C. The height of the ball \(y\) at time \(t\) is

\(y(t) = \left(30\dfrac{\rm m}{\rm s}\right) t - \dfrac g2 t^2\)

The maximum height is attained by the ball at 3 seconds after it's thrown, so

\(y_{\rm max} = \left(30\dfrac{\rm m}{\rm s}\right) (3\,\mathrm s) - \dfrac{10\frac{\rm m}{\mathrm s^2}}2 (3\,\mathrm s)^2 = \boxed{45\,\mathrm m}\)

D. The time it takes for the ball to reach its maximum height is half the time it spends in the air. So the total airtime is \(\boxed{6\,\mathrm s}\).

Put another way: When the ball returns to the height from which it was thrown, its final velocity has the same magnitude as its initial velocity but points in the opposite direction. This is to say, after the total time the ball is in the air, it's final velocity will be -30 m/s. Then the total airtime is

\(30\dfrac{\rm m}{\rm s} - gt = -30\dfrac{\rm m}{\rm s} \implies t = \dfrac{60\frac{\rm m}{\rm s}}g = \boxed{6\,\mathrm s}\)

Put yet another way: Solve \(y(t) = 0\) for \(t\). I don't see a need to elaborate...

Answer:

Thermal and kinetic.

Explanation:

Thermal energy is the energy generated by heat. Kinetic energy is the movement of particles in a substance which is responsible for the heat increase.

Answer:Thermal and kinetic.

Explanation:

Answer:

Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.

One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.

Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.

Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.

The core (nucleus) of an atom is made up of protons and neutrons. Protons have a charge, whereas neutrons have no charge. A cloud of charged particles known as electrons surrounds the nucleus. Electrons have a charge that is diametrically opposed to the charge on the

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The paragraph primarily discusses the concept of overwinding old clocks and its consequences, indicating that overwinding clocks used to be a common mistake. Here option D is the correct answer.

The paragraph explains that overwinding occurs when the mainspring is almost fully wound, but the operator continues to turn the winding key, resulting in the spring coiling too tightly or even breaking.

This suggests that overwinding was a mistake commonly made in the past when operating old-fashioned clocks. The other options, such as clocks changing over the years or clocks becoming fragile with age, are not directly addressed in the paragraph and are therefore less supported.

The option e. "time flies when you're having fun" is unrelated to the paragraph and can be disregarded as an irrelevant answer choice. Hence option D is the correct answer.

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Answer:

C 2000v its obviously ans because if o is 1000 2 vo is 2000v

Answer:

F=w=ma                                                                                                                                                       OR by using equations of motions                                                                               vf=vi-at                    : a=vf-vi/t                                                              eq 1                         s=vit+1/2at squre                                                                                 eq 2                     2as=vf squre - vi squre                                                                        eq 3                                                                                                                                                                                  

Explanation:

where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.

Answer:

an acronym because it is shorted to remember like mvemjsun it's the planet

Answer:

Which feature is created when a block of rock dropped down in relation to the block of rock beside it?

Explanation:

Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.

Answer:

oof ok

Explanation:

Thank you :)

Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

Answer:

approx 6 × 10^24 kg is earth's mass

Increasing the magnitude of the charges on two particles and decreasing the distance between them will result in a significant increase in the strength of the electric force between the particles.

According to Coulomb's law, the electric force (F) between two charged particles is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance between them (r):

F ∝ (q1 * q2) / \(r^{2}\)

When the magnitude of the charges on the particles is increased, let's say doubling both charges, the force between them will also double. This is because the product of the charges in the numerator increases, leading to a proportional increase in the overall force.

Simultaneously, decreasing the distance between the particles, let's say halving the distance, will have an even more pronounced effect. Since the distance is squared in the denominator, halving it will result in the force being multiplied by a factor of four. Thus, the force between the particles will become four times stronger.

Therefore, by both increasing the magnitude of the charges on the particles and decreasing the distance between them, the strength of the electric force between the particles will be significantly amplified. The combined effect of these changes will lead to a much more powerful attraction or repulsion between the charged particles, resulting in a greater overall force of interaction.

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An autobiography, like a memoir, is the writer's recounting of his or her life and is written in the first person, making the writer the protagonist of the narrative.

Contemporary/Realistic: In order to accurately portray our environment and society, realistic fiction develops fictional people and circumstances. Growing up and dealing with social and personal issues are the main themes. Characters in this genre are depicted as they learn about both themselves and others.

Historical and contemporary fiction make up realistic fiction's two subgenres. Unlike current fiction, which takes place in the present or recently past, historical fiction takes place at a period that is far enough back in history to be deemed history.

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Answer: the answer is b

Explanation:

edge

The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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Answer:

A

Explanation:

Explanation:

I see an object that is has a Positve acceleration for 4 seconds then a constant acceleration for the final 6 seconds.

ii. Acceleration is the slope of a velocity versus time graph.

Since the first phase is a line, it has a uniform slope.

So we need to chose two points to find the acceleration

Let's use (2,60) and (4,90).

\(a = \frac{90 - 60}{4 - 2} = \frac{30}{2} = 15\)

So the acceleration is 15.

This means, for any velocity versus time graph, the velocity is

\( \frac{v _{f} - v _{i}}{t} = a\)

This is velocity final- velocity initial divided by time equals Acceleration

iii. The average velocity is the the sum of the final velocity and initial velocity divided by 2.

So the average velocity is

\( \frac{30 + 90}{2} = 60\)

Then to find distance

\(v _{avg}t = d\)

So during the first interval, the motorbike travels

\(60 \times (4) = 240\)

In the next part, the average velocity stays at 90 and this occurs for 6 seconds

\(90 \times 6 = 540\)

Next, we add the velocities

\(240 + 540 = 780\)

So the distance travleed is 780 meters which is close to 800

In a case whereby the lowest pitch that the average human can hear has a frequency of 28.0 Hz sound with this frequency travels through air with a speed of 331M/S  the wave length is

Frequency refers to the number of vibrations measured each second. A wave is a collection of vibrations known as energy. The top node is referred to as the trough, and the bottom node as the crest.

λ = wave velocity/frequency

λ = 331 m/s / 28 Hz

λ = 11.82 m

As a result, the lowest pitch that a typical person can hear is at a frequency of 29 Hz. The wavelength of sound at this frequency is 11.82 m as it moves through air at a speed of 331 m/s.

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Answer:

4.The atoms are vibrating in place

Explanation:

The answer is;  The atoms are vibrating in place

We know that, molecules in the crystal have a definite position in the crystal and are bonded to each other by electrostatic forces. However, since the molecules have some energy, they vibrate in their positions. Their energy, however, is not high enough to cause them to overcome the strong bonding (unless the crystal is heated or the atoms are irradiated).

The car that has the greater acceleration magnitude is car B

Torricelli's theorem can be used to calculate the magnitude of an object's acceleration when the value of time is not known:

                                            \(v^{2} = v_{0}^{2} + 2a\Delta S\)

Note that \(v\\\) is the final velocity value, \(v_{0}\) is the initial velocity value, \(a\) is the acceleration value, and \(\Delta S\) is the displacement.

Substituting the values ​​given by the question in the formula, we have:

                                           \(10^{2}= 0^{2}+2\times a \times 50\)

                                                    \(100 = 100a\)

                                                     \(a = 1m/s^{2}\)

    2. CAR B

                                               \(20^{2} = 10^{2} + 2\times a \times 50\)

                                                   \(400 = 100 + 100a\)

                                                        \(100a=300\)

                                                         \(a = 3m/s^{2}\)

So, comparing the two acceleration calculated above,  it is assumed that the car has the greater acceleration magnitude is car B with \(3m/s^{2}\)  comparing to \(1m/s^{2}\)  of the car A.

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the average velocity of the ball between t=0s and t=6s is +6ft/s.

To calculate the average velocity of the baseball between t=0s and t=6s, we need to find the displacement of the ball during this time period and divide it by the time taken.

Looking at the graph, we can see that at t=0s, the ball is at position x=0ft and at t=6s, the ball is at position x=+36ft. Therefore, the displacement of the ball during this time period is:

Δx = xf - xi = +36ft - 0ft = +36ft

The time taken for this displacement is:

Δt = t f - ti = 6s - 0s = 6s

Therefore, the average velocity of the ball is:

v = Δx/Δt = +36ft/6s = +6ft/s

The positive sign indicates that the ball is moving in the positive x-direction, towards the catcher.

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For a charge to experience no net force,

F1 = F2

kQ1Q = kQ2Q

(d + x)² x²

where, Q1 = 5.75e-6C

Q2 = 4.55e-6C

Q = third charge

d = 16.5e-2 m

x = unknown distance

kQ1Qx² = kQ2Q(d+x)²

Q1x² = Q2(d²+2dx+x²)

Q1x² = Q2d² + 2Q2dx + Q2x²

Q1x² - 2Q2dx - Q2x² = Q2d²

x²(Q1 - Q2) = Q2d² + 2Q2dx

x² = Q2d² + 2Q2dx

Q1 - Q2

2Q2dx is a very small value thus it's approximated to zero.

x²=4.55e-6*(16.5e-2)²

5.75e-6 - 4.55e-6

square rooting both sides

x = 16.5e-2√4.55e-6

√(5.75e-6 - 4.55e-6)

x = 0.32m = 32cm

The 3rd charge must be placed at 32cm so it experiences no net charge.

The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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The speed of the ball rebounding from the plate is approximately 13.2 m/s.

According to the graph, the greatest force exerted by the football on the force plate during impact is around 1900 N. The ball comes to a halt on the force plate before rebounding.

The kinetic energy of the ball before impact equals the kinetic energy of the ball after the rebound, according to the law of conservation of energy.

The speed of the ball rebounding can be calculated using the formula:

(1/2)mv²= (1/2)mv_0²

where m is the mass of the ball (0.43 kg), v is the speed of the ball rebounding, and v_0 is the initial speed of the ball (15 m/s).

Solving for v, we get:

v = sqrt(v_0² - (2F/m))

where F is the maximum force exerted on the force plate (1900 N).

Plugging in the values, we get:

v = sqrt(15² - (2*1900/0.43)) ≈ 13.2 m/s

Therefore, the speed of the ball rebounding from the plate is approximately 13.2 m/s.

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Answer:

Reflection and diffraction

Explanation:

Reflection involves a change in direction of waves when they bounce off a barrier; refraction of waves involves a change in the direction of waves as they pass from one medium to another; and diffraction involves a change in direction of waves as they pass through an opening or around a barrier in their path.Diffraction refers to various phenomena that occur when a wave encounters an obstacle or opening. It is defined as the bending of waves around the corners of an obstacle or through an aperture into the region of geometrical shadow of the obstacle/aperture.