A projectile is fired at a velocity of 50 m/s straight into the air. What is the velocity of the projectile when the objects displacement is 16 meters and headed downward?

Answer:

Approximately \(2.69\; {\rm A}\).

Explanation:

Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:

\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).

Electric current \(I\) is the rate of flow of electric charge.

In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:

\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).

Explanation:

lower number of atoms and gram

brainliest expected and your welcome

Answer:

low atomic mass

high thermal energy

low kinetic energy

low number of atoms per gram

Finally, the vapor pressure of substance b can be determined using Raoult's law: vapor pressure of b = mole fraction of b * vapor pressure of pure b.

However, we need additional information such as the vapor pressure of pure b to calculate the vapor pressure of b accurately.

To determine the vapor pressure of substance b when 400 g of substance a (with a molar mass of 80 g/mol) and 1700 g of substance b (with a molar mass of 85 g/mol) are mixed, we need to consider the mole fractions of the two substances.

First, let's calculate the number of moles for each substance.

For substance a:
moles of a = mass of a / molar mass of a
moles of a = 400 g / 80 g/mol
moles of a = 5 mol

For substance b:
moles of b = mass of b / molar mass of b
moles of b = 1700 g / 85 g/mol
moles of b = 20 mol

Next, we need to calculate the total number of moles in the mixture:
total moles = moles of a + moles of b
total moles = 5 mol + 20 mol
total moles = 25 mol

Now, let's calculate the mole fraction of substance b:
mole fraction of b = moles of b / total moles
mole fraction of b = 20 mol / 25 mol
mole fraction of b = 0.8

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The reading on the scale is equal to the weight of the student which is 646.8 N.

The given parameters;

The reading on the scale is determined by applying Newton's second law of motion as follows;

\(R = ma+ mg\\\\R = m(a + g)\\\\R = m(0 + g)\\\\R = mg\)

The student is at rest and not accelerating, a =0

\(R = 66 \times 9.8\\\\R = 646.8 \ N\)

Thus, the reading on the scale is equal to the weight of the student which is 646.8 N.

The complete question is below:

A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1). what is the reading on the scale?

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In the game of volleyball, low intensity is often used during warm-up exercises or cool-down sessions.

These exercises are designed to help players get their bodies warmed up and ready to play, or to help them cool down after a game or practice. There are several low-intensity exercises that are commonly used in volleyball, including stretching, jogging, and light calisthenics.Stretching is a key part of any volleyball warm-up routine. This helps to get the blood flowing to the muscles and prepares them for the more intense exercises that are to follow. Some of the most common stretching exercises include hamstring stretches, quad stretches, and shoulder stretches. These exercises help to improve flexibility and range of motion, which can reduce the risk of injury during the game.Jogging is another common low-intensity exercise that is used in volleyball.

This helps to get the heart rate up and prepare the body for more intense activities. Jogging can also help players to develop endurance and stamina, which can be critical in the later stages of a game or tournament.Light calisthenics, such as jumping jacks, sit-ups, and push-ups, can also be used to warm up or cool down. These exercises are designed to help improve strength and endurance while also promoting flexibility and range of motion. Players can choose from a variety of different exercises to create a customized workout routine that meets their specific needs and goals.Overall, low-intensity exercises are an important part of any volleyball training program. They help to prepare the body for more intense activities while also promoting flexibility, endurance, and strength. By incorporating these exercises into their training routine, volleyball players can improve their overall fitness and performance on the court.

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Answer:

Oxygen-Symbol-O Potassium Symbol-K

A) Valency is the combining capacity of any element. Valence electrons refers to the electrons found in the outermost shell of the atom of the element.

B) Symbol and valency:

C) The reaction would be:

\( \large{ \boxed{ \rm{2Mg + O_2 \longrightarrow \: 2MgO}}}\)

\( \large{ \boxed{ \rm{Magnesium + Oxygen \longrightarrow Magnesium oxide.

}}}\)

━━━━━━━━━━━━━━━━━━━━

Answer:

A force of 355 N is applied to an object that accelerates at a rate of 7.8 m/sec2 . What is the mass of the object ?

Explanation:

Answer:

C. Spring Tides is the answer.

First thing's first, we need to find the Net Force of the system in order to solve for acceleration. Gravity and Normal Force cancel out, so we don't really have to worry about anything on the y-axis. However, looking at the x-axis, we see two forces: the Force of the push and Frictional Force.

This means that:

\(F_{net}\) = 500 - 100

\(F_{net}\) = 400 (N)

Recall that Force = Mass * Acceleration. Since we have the Force and Mass, we can easily solve for Accel:

F = ma

a = \(\frac{F}{m}\)

Plug the net force and mass into the equation:  

a = \(\frac{F}{m}\)

a = \(\frac{400}{50}\)

a = 8 (m/\(s^{2}\))

The box's acceleration is 8 m/\(s^{2}\)

If you have any questions about how I got to the answer, just ask :)

True, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

Electric field is the region of space at which electric force is felt.

E = kq/r²

where;

at infinite plane, r → ∞, and E = 0

Thus, the electric field produced by a uniform, infinite plane of charge does not depend on the distance from the plane.

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When they are anti-parallel to one another, the dipole has the highest electric potential energy.

Think about a dipole with charges q1 = +q and q2 = -q that is set up in the same uniform electric field as in the previous figure. There is a gap between the charges, and the electric field's strength is E.

As shown in the figure, the charges' respective forces are given as -qE and +qE.

Knowing that a dipole experiences a torque equal to, which can be expressed as  = p*E, when it is placed in a uniform electric field rather than a force,

Taking into account that the potential energy is located at the initial angle

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In order to model the thermal energy of diamond, 4 springs are required, while the model the thermal energy of solid argon 3 springs are required.

Thermal energy is the internal energy in a substance, that is, the energy of the particles that make up a substance. When two objects at different temperatures come into contact, the heat is transferred from the hotter object to the colder object until both objects reach the same temperature. A system of springs may be used to represent a solid. The particles of a solid are represented by the springs, which are elastic. The more energy the system has, the more the springs will vibrate.

The particle model of thermal energy is based on the idea that all matter is made up of tiny particles that are constantly in motion, and that the faster these particles move, the hotter the object becomes. To model the thermal energy of diamond, four springs are required because diamond is a covalent network solid in which each carbon atom is bonded to four other carbon atoms in a tetrahedral arrangement. Diamond's structure is made up of carbon atoms bonded together by strong covalent bonds. When a carbon atom is bonded to four other carbon atoms, it forms a very strong and stable tetrahedral structure. Diamond's thermal energy is modeled using four springs.

To model the thermal energy of solid argon, three springs are required because argon is a noble gas with a face-centered cubic structure. Solid argon, like other noble gases, has a simple structure. The argon atoms in solid argon are arranged in a cubic array, with an atom at each corner and one in the center of each face of the cube. To model the thermal energy of solid argon, three springs are used. The thermal energy is modeled using these three springs.

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To balance the forces. The tension and gravity are both in a downward motion when the thing is at the bottom. And . It is obvious that T at the bottom is heavier than T at the top by a factor of two.

When the particle is at the highest point of the circle, the tendency of the string to sag is greatest. The circular path's lowermost point experiences the most strain. The rope is most likely to break here.

Therefore, At the string's peak, there might be no tension. It is based on how quickly the rotating mass is moving. It will be slower at any given speed than at other locations in the “orbit.”

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Answer:

Because the pupil of the eye is very small in bright sunlight, very little light enters the eye when we enter a gloomy cinema hall from bright sunlight.

Explanation:

Answer:

well i mean its dark

darkened cinema hall

our eyes cant clearly see dark

Answer:

the first on the left goes with the 3rd on the right

second left last right

3rd goes with 1st

4th goes with 5th

5th goes with 4th

and last but not least 6th goes with the second

Explanation:

Answer :

556.59 m/s.

Explanation:

Given that,

An airplane is traveling at an altitude of 15,490 meters.

A  box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.

The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :

\(v^2-u^2=2as\)

Put u = 0 and a = g

\(v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s\)

So, when it hits the ground its velocity is 556.59 m/s.

Option c is correct. Approximately 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.

For solving this problem, need to calculate the z-scores for the given range of bulb lives and then use these z-scores to find the corresponding probabilities from the standard normal distribution table.

The z-score can be calculated using the formula:

z = (x - μ) / σ,

where x is the value, interested in, μ is the mean, and σ is the standard deviation. In this case, the mean (μ) is 750 hours and the standard deviation (σ) is 50 hours.

For a life of 710 hours:

z = (710 - 750) / 50 = -0.8

For a life of 830 hours:

z = (830 - 750) / 50 = 1.6

Next, look up the probabilities associated with these z-scores in the standard normal distribution table. The probability associated with a z-score of -0.8 is 0.2119, and the probability associated with a z-score of 1.6 is 0.9452.

For finding the number of bulbs expected to have a life between 710 and 830 hours, calculate the difference between these probabilities:

0.9452 - 0.2119 = 0.7333

Therefore, approximately 0.7333 * 700 = 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.

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Answer:

By applying relative small force to the smaller piston

Explanation:

If a car sits on top of the large piston, it can be lifted by applying a relatively small force to the smaller piston, the ratio of the forces being equal to the ratio of the areas of the pistons

Answer:

a. 25.80 m

b. 4.59s

Explanation:

(refer to attached for reference)

Part a :

We are asked to find the distance the ball rises "s"

The relevant equation of motion is:

v² = u² + 2as,

Given:

Initial speed, u = 22.5 m/s

As the ball rises, we can also deduce the following:

1) the ball rises to a maximum height before it starts falling again. At the point of maximum height, for a split second, speed of the ball is zero.

Hence we can deduce that final speed, v = 0 m/s

2) the only acceleration acting on the ball as it travels is gravity acting downward. Hence the acceleration that the ball experiences is equal to negative gravitational acceleration, i.e a = - 9.81 m/s²

Simply substitute the above values into the equation above and solve for distance "s"

v² = u² + 2as

0² = 22.5² + 2(-9.81)s

19.62s = 22.5²

s = 22.5² / 19.62 = 25.80 m (answer)

Part b:

We are asked to find how long the ball takes to rise and fall again before it is caught. We are also told that the time for the ball to rise is the same as the time for the ball to fall. Hence all we need to do is find the time taken for the ball to rise and then multiply that by 2 to get our answer.

In this case, the relevant equation of motion is:

v = u + at, where t is the time taken for the ball to rise.

simple substitute the above known values into this equation and solve for t

v = u + at

0 = 22.5 + (-9.81)t

9.81t = 22.5

t = 22.5/9.81

t = 2.29 s

hence the time taken to rise AND fall = 2t = 2(2.29) = 4.59s (answer)

The ball will rise to the height of 25.8 meters and the ball will remain in air for 4.5 seconds for both rise and fall of the ball.

In the field of physics, the idea and practice of motion are crucial. Numerous words and elements are important to the motion. Such as length, breadth, depth, velocity, and so forth. Static or variable velocity is a property of moving things. Thus, if the motion is accelerating, the initial velocity and the ultimate velocity may differ. The pace at which an object's position changes in relation to time is known as its velocity.

According to the question, the given values are :

Initial Speed, u = 22.5 m/s

Final Speed, v = 0 m/s

Acceleration, a = -9.8 m/s²

Use equation of motion :

v = u + at

0 = 22.5 + (-9.8)(t)

t = 22.5 / 9.8

t = 2.2 seconds.

(a) The height rise of the ball will be :

s = ut + 1/2 at²

s = 22.5(2.2) + 1/2(-9.8)(2.2)²

s = 49.5 - 23.71

s = 25.8 meters.

(b) The time that the ball remain in the air :

2(t) = 2 (2.2)

= 4.4 seconds.

Hence, the ball will cover a distance of 25.8 meters and the time it will be in the air is 4.4 seconds.

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Answer:

An object at rest is described by Newton's First Law of Motion. An object in static equilibrium has zero net force acting upon it. The First Condition of Equilibrium is that the vector sum of all the forces acting on a body vanishes.

Explanation:

Answer:

see below

Explanation:

the first condition means that the light ray inside the optically denser medium hits the surface of the optically less dense medium.

this in simple words means, light must be travelling from am optically denser medium to an optically less dense medium

hope this helps :)

Answer:

c 82.45 m

Explanation:

To solve this problem, we have to apply the right motion equation.

 Given parameter;

 Initial velocity  = 90mph

 So;

 Using;

      V²  = U² - 2gh ; we can solve this problem

 V is the final velocity = 0mph

U is the initial velocity

g is the acceleration due to gravity

h is the height

 Now insert the parameters and solve;

        We need to convert from mph to m/s

          1 mph  = 0.45m/s

          90mph  = 40.5m/s

    0² = 40.5² - (2 x 9.8 x h)

      0 = 1640.25  - 19.6h

    -1640.25 = -19.6h

           h  = 83.7m

The amperage represents the rate at which electric charge flows through a conductor.

What is amperage?

Amperage is a measure of electrical current, or the rate at which electrical charge flows through a circuit. It is measured in units of amps (A). Amperage is related to voltage and resistance in an electrical circuit, and can be calculated using Ohm's law. Amperage is important to consider when sizing electrical components and wiring for a circuit, as too much amperage can cause damage to the components.

The amperage, also known as current, represents the rate at which electric charge flows through a conductor. It is measured in amperes (A) and is a measure of the quantity of electric charge that passes through a given point in a circuit per unit of time. In other words, amperage is a measure of how many electrons are flowing through a wire at a given moment. A low amperage means that there is a small amount of electric charge flowing through the conductor. This could be because the resistance of the conductor is high, or because the voltage of the power source is low. A low voltage, on the other hand, means that there is a small potential difference between two points in a circuit, which means that the electric charge is not being pushed as hard and may not be flowing as quickly.

Therefore, it represents the rate at which electric charge flows through a conductor.

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The electric fields is always directed from higher potential to the lower potential.

The electric fields always aiming from the region of higher potential to the region of lower potential. So the force of electrostatic and the direction of the travel of electrons will be always from lower potential to the region of higher potential.

An electric field is defined as the physical field which covers the electrically charged particles and also they can apply force on all other charged particles.

So we can conclude that the electric fields is always directed from higher potential to the lower potential.

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Answer:

The biggest difference between the two is in how they produce light. Incandescent bulbs produce light by a heating a metallic filament until it starts to radiate light. On the other hand, fluorescent lamps produce light by exciting a gas and causing it to glow.

Explanation:

When the velocity of a particle moving along an axis is known, the instantaneous acceleration equal to zero is given as 0.6t.

We estimate the average speed between two places in time separated by t while allowing t to decrease. The outcome is the velocity function's derivative, v. (t).

The slope of the tangent line to the graph at any given location on the graph corresponds to the instantaneous acceleration there. The instantaneous acceleration of the particle is equal to 0 when this line is horizontal and has a slope of 0. According to the plot, these times correlate to the velocity function's extrema, which can be found at t = 1.75, 2.75, 3.25, and for all t = 4.

t = 0.6 is the most likely choice.

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Correct option is B, satellite that has the greatest speed has Mass Radius m ½R.

Because the satellite orbits the earth, the gravitational pull of the planet on the satellite supplies the necessary centrifugal force. In a circular orbit, the gravitational force is constant, hence the satellite's velocity is also constant.

Kepler's third law informs us that

V² = GM/R

Therefore, v = (GM/R)

Where;

V is the speed

G stands for gravity constant.

Mass is M.

R is radius

Let's begin by examining the first choice, which is Option B.

Here, mass equals m and radius equals (1/2)R.

Consequently, v = (Gm/(R/2)) = (2Gm/R)

After carefully examining each choice, it is evident that option B will have the highest velocity because its numerator is the largest, which will result in a higher velocity.

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The answer that matches both trials is (A) Does not change - Does not change.

The speed of the two-cart system's center of mass during the collision in each trial can be analyzed using the principle of conservation of momentum. In both trials, the total momentum before and after the collision remains the same.
In Trial 1, the collision is elastic, meaning that both kinetic energy and momentum are conserved. The center of mass does not change during the collision since the total momentum remains constant. Therefore, for Trial 1, the correct answer is "Does not change."
In Trial 2, the carts stick together during the collision, and although kinetic energy is not conserved, the total momentum is still conserved. As a result, the center of mass of the two-cart system does not change during the collision.

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Answer:

B

Explanation: you are staying longr to jump 3 meters than one meter