A project was expected to be completed in 11 weeks by a crew of six (6) workers. The work was to be completed without overtime, namely, with 40-hour workweeks. Workers were to be paid $20 per hour, which included all fringes. Before construction began, the owner decided that the project schedule was to be accelerated by having the workers work 8 hours on Saturdays. Assume wages are paid at time-and-a-half on Saturdays - What is the revised expected duration of the project? - What is the added cost due to the acceleration?
Answers
Answer:
≈$13,315.20
Explanation:
Before the acceleration, the crew of 6 workers worked 40 hours per week, for a total of:
6 workers × 40 hours/worker/week = 240 hours/week
The project was expected to take 11 weeks, for a total of:
11 weeks × 240 hours/week = 2,640 hours
The cost of labor for the original schedule would be:
240 hours/week × $20/hour/worker × 6 workers = $28,800/week
Over 11 weeks, this would be a total labor cost of:
$28,800/week × 11 weeks = $316,800
Now, with the accelerated schedule, the workers will work an extra 8 hours on Saturdays, for a total of:
6 workers × 8 hours/worker = 48 hours
On Saturdays, the workers will be paid time-and-a-half, which means they will be paid $30 per hour (1.5 times the normal rate of $20 per hour).
So the labor cost for each worker on Saturdays will be:
$30/hour/worker × 8 hours/worker = $240/worker
For the whole crew, the labor cost for Saturdays will be:
$240/worker × 6 workers = $1,440/week
So the new total labor cost per week will be:
240 hours/week × $20/hour/worker × 6 workers + $1,440/week = $30,240/week
To calculate the revised expected duration of the project, we need to divide the total number of hours required for the project by the total number of hours worked per week, including the Saturday overtime:
2,640 hours ÷ (240 hours/week + 48 hours/week) = 9.23 weeks
So the revised expected duration of the project is approximately 9.23 weeks.
The added cost due to the acceleration is the difference between the total labor cost for the original schedule and the total labor cost for the accelerated schedule:
$30,240/week - $28,800/week = $1,440/week
Over the 9.23 weeks of the accelerated schedule, this added cost will be:
$1,440/week × 9.23 weeks = $13,315.20
So the added cost due to the acceleration is approximately $13,315.20.
Related Questions
tank(V):=if(V>_1000gal,"full","empty") and tank(2000gal) what is answer?
Answers
The tank with a volume of 2000 Gallons would be considered "full" according to the given conditional statement. This expression is useful in situations where we need to determine the status of a tank based on its volume. We can substitute different values of V into the expression to determine the tank's status for different volumes.
The expression Tank(V):=if(V>_1000gal,"full","empty") is a conditional statement that checks if the value of V is greater than 1000 gallons. If it is, then the tank is considered "full", otherwise, it is considered "empty".
When we evaluate the expression Tank(2000gal), we are essentially asking the question, "Is a tank with a volume of 2000 gallons considered full or empty according to this statement?" Since 2000 is greater than 1000, the answer would be "full". The tank with a volume of 2000 gallons would be considered "full" according to the given conditional statement. This expression is useful in situations where we need to determine the status of a tank based on its volume. We can substitute different values of V into the expression to determine the tank's status for different volumes.
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In a linked-based implementation of the ADT list with only a head reference, what is the performance of removing an entry at the end of the list? a. O(n) b. O(n) C. O(log n) d. 0(1) 27. In a linked-based implementation of the ADT list with a tail reference, what is the performance of removing an entry at the beginning of the list? a. 0(1) b. O(log n) C. O(n) d. O(nº). 28. In a linked-based implementation of the ADT list with a tail reference, what is the performance of removing an entry that is not at the beginning of the list? a. O(n) b. O(n) C. O(log n) d. 0(1)
Answers
An entry at the end of a linked-based list can be removed with O(n) performance using just the head reference.
What is the performance of removing an entry at the end of a linked-based list with only a head reference?In a linked-based implementation of the ADT list with only a head reference, removing an entry at the end of the list has a performance of O(n). This is because to remove the last element, we need to traverse the entire list from the head to the second-to-last node in order to update the reference and remove the last node.
In a linked-based implementation of the ADT list with a tail reference, removing an entry at the beginning of the list has a performance of O(1). Since we have a reference to the tail, we can directly update the head reference to the next node without traversing the entire list.
In a linked-based implementation of the ADT list with a tail reference, removing an entry that is not at the beginning of the list also has a performance of O(1). We can update the references of the neighboring nodes to bypass the node being removed without needing to traverse the entire list.
Overall, the key difference lies in the ability to directly access the head or tail reference, which influences the performance of removing elements in different positions in the list.
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the most likely creep mechanism at high temperatures and low applied stresses is: the most likely creep mechanism at high temperatures and low applied stresses is:crack propagationgrain boundary diffusiondislocation glide.dislocation motion (climb)bulk diffusion
Answers
The most likely creep mechanism at high temperatures and low applied stresses is "dislocation motion (climb)". Option e is answer.
This mechanism involves the movement of dislocations through the lattice structure of a material, which leads to deformation or strain. When high temperatures and low applied stresses are present, the movement of dislocations through the lattice structure becomes the dominant mechanism for creep.
Other creep mechanisms such as crack propagation, grain boundary diffusion, and bulk diffusion are more likely to occur under different conditions such as low temperatures, high applied stresses, or in materials with specific microstructures. Understanding the dominant creep mechanism is important in designing and selecting materials for high-temperature applications where creep resistance is critical.
Option e is answer.
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The rafter is fastened to the outside wall so that the plumb cut in the birdsmouth is tight to the exterior wall sheathing
Select one:
O True
O False
Answers
In the last lesson, you work with several different kinds of bounding boxes. Write a function named sameSize which uses the structure BBox. The function returns true if two boxes have the same size. 4 bbox.cpp 1 #include "bbox.h" 2 char BBox(const BBox& bi, const BBox& b2) 3 { if (bl == b2) 5 return true; 6 } 7 8 bbox.h 1 #ifndef BBOX H 2 #define BBOX H 3 4 struct BBox 5 { 6 1/ upper-left corner 7 8 int width; 9 int height; 10 }; 11 12 bool sameSize(const BBox& bl, const BBox& b2); 13 14 #endif int x; int y; Now, write a function named sameArea which uses the structure BBox. The function returns true if two boxes have the same area. bbox.cpp 1 #include "bbox.h" 2. 3 4 bbox.h i #ifndef BBOX H 2 #define BBOX H 3 4 struct BBox 5 { 6 int x; 1/ upper-left corner 7 8 int width; 9 int height; 10 }; 11 12 bool sameArea(const BBox& bi, const BBox& b2); 13 14 #endif int y; Write a function equals that returns true if both boxes have the same coordinates and size. bbox.cpp 1 #include "bbox.h" 2 3 4 bbox.h 1 #ifndef BBOX H 2 #define BBOX H 3 4 struct BBox 5 { 6 int x; // upper-left corner 7 8 int width; 9 int height; 10 }; 11 12 bool equals(const BBox& bl, const BBox& b2); 13 14 #endif int y;
Answers
Now you have the functions same Area and equals that return true if the boxes have the same area and same coordinates and size, respectively.
To write a function named sameArea which uses the structure BBox, the function returns true if two boxes have the same area. Here is the required code:
bbox.cpp
#include "bbox.h"bool sameArea(const BBox& bl, const BBox& b2) { if (bl.width * bl.height == b2.width * b2.height) return true;
else return false; }bbox.h
#ifndef BBOX_H
#define BBOX_Hstruct BBox{int x; // upper-left cornerint width;int height;};bool sameArea(const BBox& bl, const BBox& b2);#endifWe use the given structure to write a function named sameArea. The function receives two arguments in the form of structure BBox. In order to compare two boxes, we need to calculate the area of each box. The formula to calculate the area of a box is as follows: Area of the box = width * heightNow, we will use this formula to compare the area of two boxes. If the area of two boxes is the same, the function will return true, otherwise, the function will return false.
To write the function sameArea, which returns true if two boxes have the same area, follow these steps:
1. In "bbox.h", declare the sameArea function prototype within the existing file:
```cpp
bool sameArea(const BBox& b1, const BBox& b2);
```
2. In "bbox.cpp", define the sameArea function:
```cpp
#include "bbox.h"
bool sameArea(const BBox& b1, const BBox& b2) {
int area1 = b1.width * b1.height;
int area2 = b2.width * b2.height;
return area1 == area2;
}
```
To write the function equals, which returns true if both boxes have the same coordinates and size, follow these steps:
1. In "bbox.h", declare the equals function prototype within the existing file:
```cpp
bool equals(const BBox& b1, const BBox& b2);
```
2. In "bbox.cpp", define the equals function:
```cpp
#include "bbox.h"
bool equals(const BBox& b1, const BBox& b2) {
return b1.x == b2.x && b1.y == b2.y && b1.width == b2.width && b1.height == b2.height;
}
```
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A well-hydrated human body is made up of about _______ percent water.
Answers
Answer:
70%
Explanation:
70%
Explanation:
A well-hydrated human body is made up of about 70% water :)
Hope that helps
The device shown below contains 2 kg of water. The cylinder is allowed to fall 800 m during which the temperature of the water increases by 2.4°C. Some amount of water is added to the container and the experiment is repeated. All other values remain constant. This time the temperature of the water increases by 1.2°C. How much water was added to the container?
Answers
Answer:
m_added = 2 kg
Explanation:
From the question, we are told that the cylinder is allowed to fall 800 m in height. Thus, the potential energy will be converted into heat energy which will increase the temperature of water .
Now, let the mass of the falling cylinder be denoted by "m1" and let h be the height of fall.
Thus;
Formula for potential energy = mgh
Thus, as said earlier it's converted to heat generated. So heat generated = m1gh
Now let's calculate the heat absorbed;
heat absorbed = (m2)cΔt
Where;
ΔT is change in temperature
c is specific heat of water .
m2 is mass of water
Heat absorbed = heat generated
Thus;
(m2)cΔt = m1gh
Δt = m1gh/(m2•c)
Now, in both cases of the water and cylinder, m1, g , h and c are constant
Thus, we have;
Δt = (m1gh/m2) × 1/c
Where;
(m1gh/m2) is denoted as a constant k.
Thus;
Δt = K/m
For the first experiment, we have;
m = 2 kg
Δt = 2.4
Thus;
2.4 = K/2
Multiply both sides by 2 to get;
K = 4.8
For the second experiment, we have;
Δt = 1.2
Also,we have seen that K = 4.8
Thus;
Δt = K/m
Thus;
1.2 = 4.8/m
m = 1.2
m = 4 kg
Thus,mass added is;
m_added = 4 - 2
m_added = 2 kg
The lattice parameter of copper is 0.362 nanometer. The atomic weight of copper is 63.54 g/mole. Copper forms a fcc structure. Answer the following questions.
a. Volume the unit cell in cubic centimeters in cubic centimeters is:______
b. Density of copper in g/cm^3 is:________
Answers
Answer:
a) 4.74 * 10^-23 cm^3
b) 8.9 g/cm^3
Explanation:
Given data :
Lattice parameter of copper = 0.362 nM
Atomic weight of copper = 63.54 g/mole
Given that copper forms a fcc structure
a) Calculate the volume of the unit cell
V = a^3
= ( 0.362 * 10^-7 cm )^3 = 4.74 * 10^-23 cm^3
b) Calculate density of copper in g/cm^3
Density = ( n*A ) / ( Vc * NA) ----------- ( 1 )
where: NA = Avogadro's number = 6.022 * 10^23 atoms/mol
n = number of atoms per unit cell = 4
A = atomic weight = 63.54 g/mol
Vc = volume of unit cell = 4.74 * 10^-23 cm^3
Input values into equation 1
Density = 8.9 g/cm^3
what does the mechanical hound look like in fahrenheit 451
Answers
In Fahrenheit 451, Ray Bradbury introduces a dystopian novel featuring a mechanical hound, a fearsome and relentless machine designed to eliminate books-related crimes.
What is the description of the mechanical hound in the book?The hound, resembling a large dog, has a six-legged body and emits a green light. Its synthetic body is heat-resistant and fireproof, and it moves swiftly, chasing targets with great speed.
The hound emits a constant mechanical hum, adding to its eerie presence. The mechanical hound serves as a menacing enforcer of the oppressive regime in Fahrenheit 451.
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the breastplate that is worn by augustus of primaporta reflects greek political ideology.
Answers
The breastplate worn by Augustus of Primaporta reflects Greek political ideology. Greek political ideology had a significant impact on Roman art, literature, and culture. The breastplate depicts several scenes from Greek mythology, including the goddess Athena leading a battle against the giants. This imagery serves to associate Augustus with the heroes of ancient Greece and portray him as a powerful and virtuous leader, in the same way that Greek leaders used mythology to legitimize their rule.
The breastplate of Augustus of Primaporta reflects Greek political ideology, which is evident in the artwork's symbolism. The breastplate depicts Augustus as a conqueror who has defeated his enemies and brought peace and prosperity to Rome. The goddess Roma is shown on his shoulder, and she is depicted as a powerful and virtuous woman who embodies the values of the Roman Republic. The Cupid on Augustus' side is a symbol of divine endorsement of the rule of Augustus. The imagery in the breastplate is reminiscent of the artwork created during the Hellenistic period, when the Greeks were expanding their empire and exerting their influence over the Mediterranean region. Additionally, the breastplate features a depiction of Augustus himself, portrayed as a youthful and athletic figure, further emphasizing his strength and leadership qualities. This type of imagery was common in Greek art and reflects the idealized portrayal of rulers in classical Greek political ideology. Overall, the use of Greek mythology and imagery on Augustus' breastplate served to align him with the traditions and values of ancient Greece and reinforce his legitimacy as a leader.
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Water discharging into a 10-m-wide rectangular horizontal channel from a sluice gate is observed to have undergone a hydraulic jump. The flow depth and velocity before the jump are 0.8m and 7m/s, respectively. Determine (a) the flow depth and the Froude number after the jump (b) the head loss (c) the dissipation ratio.
Answers
Answer:
A) flow depth after jump = 2.46 m, Froude number after jump = 0.464
B) head loss = 0.572 m
C) dissipation ratio = 0.173
Explanation:
Given data :
width of channel = 10-m
velocity of before jump (V1) = 7 m/ s
flow depth before jump (y1) = 0.8 m
A) determining the flow depth and the Froude's number after the jump
attached below is the solution
B) head loss
HL = Y1 -Y2 + \(\frac{V_{1} ^2 - V_{2} ^2}{2g}\) = 0.8 - 2.46 + \(\frac{49 - 5.1984}{19.62}\) = 0.572
C) dissipation ratio
HL / Es1 = 0.572 / 3.3 = 0.173
Es1 = 0.8 + \(\frac{7^2}{2*9.81}\) = 0.173
This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answers
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
B/ Evaluate e^(πi/2)
Answers
You get a result immediately from Euler's formula:
e ^(i π/2) = cos(π/2) + i sin(π/2) = 0 + i * 1 = i
which one of these reduce fraction?
Answers
On a negatively grounded system, the
Jump Pack negative clamp should be
attached to the when engine starting.
Answers
Answer:
Explanation:
The positive (red) cable should be attached to the positive terminals on each battery. The negative (black) cable should have one end attached to the negative terminal of the dead battery, and one end grounded.
Start by connecting the positive (often red) clamps of the jumper cables to the positive terminals of your battery. These are often marked, but they can be hard to see. Be sure to look closely to ensure that you are connecting to the right portion of the battery.
The following 4 consecutive 15-minute vehicle counts were taken on a highway:
300, 400, 250, 350.
Required:
Compute the hourly flow rates for each period, the total hourly volume, and the peak hour factor.
Answers
Answer:
Hourly flow rates are provided below
The total hourly volume is 1,300
Peak hour factor 0.8125
Explanation:
The data can be calculate as below
Time _______ Vehicle count ______ Hourly flow rate
0 - 15 _______ 300 _____________ 4 x 300 = 1,200
15 - 30 ______ 400 _____________ 4 x 400 = 1,600 Maximum
30 - 45 ______ 250 _____________ 4 x 250 = 1,000
45 - 60 ______ 350 _____________ 4 x 350 = 1,400
Hence, Maximum hourly flow rate is 1,600
Calculate hourly volume
Hourly volume = 300 + 400 + 250 + 350 = 1,300
Now calculate Peak hour factor
Peak hour factor = Hourly volume / maximum hourly flow = 1,300 / 1,600 = 0.8125
For a manufacturing process that produces copper tubing, a(n) would track the variability of the tubing's diameter. A. R-chart B. x-bar chart C. p-chart D.m-chart E. v-chart
Answers
A. R-chart An R-chart, also known as a range chart, is used to track the variability or dispersion of a manufacturing process.
It is commonly used in statistical process control (SPC) to monitor the consistency of a process over time.
In the case of copper tubing production, an R-chart would be suitable for tracking the variability of the tubing's diameter. The chart displays the range (the difference between the largest and smallest values) of a set of samples taken from the manufacturing process. By analyzing the range values, one can assess whether the process is producing tubing with consistent diameter or if there is excessive variability.
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Describe short report on how different between Dead load and Live load
Answers
Where does Burj Khalifa located? and how many meters?
Answers
Answer:
Burj Khalifa is located in dubai UAE at over 828m
Explanation:
828 metres
Answer:
The Burji Khalifa, known as the Burj Dubai prior to its inauguration in 2010, is a skyscraper in Dubai, United Arab Emirates. With a total hight of 829.8 m and a roof hight of 828 m, the Burji Khalifa has been the tallest structure and building in the world since its topping out in 2009.
What were the trade-offs and opportunity costs of one of Teasha’s economic decisions?
Answers
Answer:
Opportunity cost she loses the chance to get the degree. The trade- off is she gets to start a business.
Explanation:
A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is applied to the top side of the plate. A normal tensile force of 20kN is applied to the right side of the plate. The elastic modulus, E, is 115 GPa for titanium.If the left and bottom edges of the plate are fixed, calculate the normal strain and elongation of both the TOP and RIGHT side of the plate.
Answers
Answer:
\(X_t=2.17391304*10^{-4}\)
\(X_r=2.89855072*10^{-4}\)
\(e_t=0.0026\)
\(e_r=0.0035\)
Explanation:
From the question we are told that:
Dimension \(12*12\)
Thickness \(l_t=5mm=5*10^-3\)
Normal tensile force on top side \(F_t= 15kN\)
Normal tensile force on right side \(F_r= 20kN\)
Elastic modulus, \(E=115Gpap=>115*10^9\)
Generally the equation for Normal Strain X is mathematically given by
\(X=\frac{Force}{Area*E}\)
Therefore
For Top
\(X_t=\frac{Force_t}{Area*E}\)
Where
\(Area=L*B*T\)
\(Area=12*10^{-2}*5*10^{-3}\)
\(Area=6*10^{-4}\)
\(X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}\)
\(X_t=2.17391304*10^{-4}\)
For Right side\(X_r=\frac{Force_r}{Area*E}\)
Where
Area=L*B*T
\(Area=12*10^{-2}*5*10^{-3}\)
\(Area=6*10^{-4}\)
\(X_r=2.89855072*10^{-4}\)
\(X_r=2.89855072*10^{-4}\)
Generally the equation for elongation is mathematically given by
\(e=strain *12\)
For top
\(e_t=2.17391304*10^{-4}*12\)
\(e_t=0.0026\)
For Right
\(e_r=2.89855072*10^{-4} *12\)
\(e_r=0.0035\)
Distinguish between systems analysis and systems design?
Answers
Answer:
System analysis can be defined as a deep analysis of a part of the structure of a module that has been designed before. System design means to make any module or a part of the structure from scratch and build it completely without estimation.
Explanation:
Here are the city gas mileages for 13 different midsized cars in 2008. 16, 15, 22, 21, 24, 19, 20, 20, 21, 27 , 18 , 21 , 48 What is the minimum ?
Answers
Answer:
Minimum city gas mileage is 15
Explanation:
Minimum city gas mileage among 13 different car sizes in 2008 is 15.
Which of the following is responsible for maximizing building efficiency by managing all of a building’s electrical and mechanical operations?
automated building management (ABM)
computer-aided design (CAD)
operations management system (OMS)
building automation system (BAS)
Answers
The following responsible for maximizing building efficiency by managing all of a building’s electrical and mechanical operations is building automation system (BAS).
The fourth option is correct.
What is building automation system ?A building automation system (BAS) is a network designed to connect and automate certain functions inside a building.
All of the building control systems, from lighting and HVAC (Heating, Ventilation & Air Conditioning) to fire and security systems, all are wired through one set of controls.
Maximum building efficiency is obtained by building automation system . It can be done by managing all of a building’s electrical and mechanical operations.
Thus, the fourth option is correct.
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Vacancy diffusion statement refer to that a mechanism that
atom at lattice traveled to a vacant latblèe
• True
• False
Answers
Answer:
true
Explanation:
Every motor vehicle except for
grade.
must be equipped with a parking brake that can hold a vehicle stationary on any
a) Motorcycles
b) Ambulances
c) Garbage trucks
Answers
Answer:
Motor Cycles
Explanation:
Motor cycles have no parking brake
2
A spring balance pulls with 5 N on a beam of 0.5 m.
What is the torque at the end of the beam?
Answers
Answer:
The torque at the end of the beam is 2.5 Nm
Explanation:
Given;
length of beam, r = 0.5 m
applied force, F = 5 N
The torque at the end of the beam is given by;
τ = F x r
where;
τ is the torque
F is applied force
r is length of the beam
τ = 5 x 0.5
τ = 2.5 Nm
Therefore, the torque at the end of the beam is 2.5 Nm
What is the ls option that prints the author of a file?
Answers
Answer:
You need to use option '–author' along with option '-l' to print the author name of each file.
Explanation:
hopefully this helps you sorry if it doesn’t help you
Write a program, to divide the list into almost two equally-length parts and output two lists:
Example1: if the length is even
Input: ["1","2","5","8","9","0"]
Output: ["1", "2", "5"] ["8","9","0"]
Example2: if the length is odd
Input: ["1","2","5","8","9"]
Output: ["1", "2"] ["5","8","9"]
Answers
To divide the list into almost two equally-length parts and output two lists, the following Python program can be used:
my_list =
["1","2","5","8","9","0"]
list_length = len(my_list)if list_length % 2 == 0:
# length is even mid = list_length // 2 list1 = my_list[:mid]
list2 = my_list[mid:]else:
# length is odd mid = list_length // 2 list1 = my_list[:mid+1] list2 = my_list[mid+1:]print(list1) print(list2)
The above program divides the list into two almost equal parts by checking whether the length of the list is odd or even.
If the length of the list is even, it divides the list into two equal parts.
If the length of the list is odd, it divides the list into two parts where the first part has one more element than the second part.
In the first example where the input list is ["1","2","5","8","9","0"], the length of the list is even,
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which action is an example of how engineering affects science.
A) Identifying ways to improve the design of an infrared camera.
B) Designing an infrared camera that can record animal behavior in darkness.
C) Using observations of predators to from a hypothesis about their behavior.
D) Testing the effect if infrared light on the behaviors of nighttime predators.
Answers
Answer:It was B
Explanation:i took it on apec
and got A wrong so it told it was B
The action that is an example of how engineering affects science is designing an infrared camera that can record animal behavior in darkness. The correct option is B.
What is engineering?Engineering is the process of using mathematical and scientific principles to solve issues in the real world and create novel products and processes for use in a variety of fields and applications.
Engineering is the use of science and math to address issues. Engineers analyze how things operate and use scientific discoveries in real-world settings.
Strong problem-solving skills are among the most important traits an engineer can have. A substantial portion of an engineer's duties involve analyzing a situation, spotting issues, and then coming up with solutions.
Designing an infrared camera that can capture animal behavior in the dark is an example of how engineering influences research.
Thus, the correct option is B.
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