Answers
The efficiency of an engine is defined as ratio of the useful work done to the heat provided or,
in terms of temperature of the source and the sink the efficiency of heat engine is given by \(1-\frac{T_{2} }{T_{1} }\)
Thus, we have two formulae to calculate the efficiency of a heat engine.
η= \(\frac{useful work done}{heat absorbed}\) ....1
η= \(1-\frac{T_2}{T_1}\) ....2 (where \(T_{2}\) and \(T_{1}\) are temperatures of sink and source respectively)
Given quantities are,
\(T_{1}\) = 830K\(T_1\) =288KWork done = 230000JNow, by equating (1) and (2) equation,
⇒ \(1-\frac{T_2}{T_1}\) = \(\frac{Useful work done}{Heat absorbed}\)
Substituting the given values;
⇒ \(1-\frac{288}{830}\) = \(\frac{230000}{heat absorbed}\)
⇒therefore, heat absorbed = 353846.15 J
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Related Questions
You have been contracted to map the Ryerson Campus at a scale of 1:1,000 using 1:3,000 photographs. It is required that you use photogrammetric techniques to perform the mapping using scanned (i.e., digitized) aerial photographs. The aerial photographs are taken with a focal length of 152.000 mm and have a 230mm by 230mm format. The aerial camera has both side and corner fiducials. The camera calibration information is available on a camera calibration report. Answer the following questions keeping in mind that you must choose a scanning resolution (in microns or dpi).
1. You must perform a fiducial transformation (i.e., interior orientation) using a 2-D transformation. What fiducial transformation model would you use and why? What magnitude of residuals would you expect?
2. If you adopted a local Cartesian coordinate system, which of the following image coordinate corrections would you apply and what would be their expected order of magnitude?
principal point offsets,
radial lens distortion,
atmospheric refraction,
earth curvature.
Answers
An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.
What are the purposes of fiducial marks?Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.
Fiducial markers: how do they function?Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.
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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.
Given the Ryerson Campus is at a scale of 1:1000
Then the photographic scale (s) = 1:3000
The focal length of camera (f) = 152mm = 0152m
The format is (k) = 230 x 230mm = 0.23m
the photographic scale (s) = F/H where H is the image height
1/3000 = 0.152 /H Then H = 456m
Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s
(1-0.6) x 0.23/1/3000 = 276mm
Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m
Hence the central points are plotted within the area range in 276m x 483m magnitude.
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Which is the right one?
(Show work)
Answers
Air resistance will cause less movement both in the vertical and the horizontal direction.
What does the principle of superposition help scientists determine?
A) The super powers of a rock layer
B) The exact and absolute age of a rock layer
C) The relative age of a rock layer
D) The position of a fossil
Answers
Answer:
B
Explanation:
the exact and absolute age of a rock layer
Answer:
The relative age of a rock layer.
Explanation:
The answer is C.
An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
Answers
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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A bullet is fired vertically upward a velocity of 80m/s to what height will the bullet rise above the point of projection
Answers
Answer:
The bullet will rise 320 meters above the point of projection.
Explanation:
Assuming that air friction is negligent we can use the kinematic equation:
\(v_{2} ^2=v_{1} ^2+2(-a)d\\0\frac{m^2}{s^2} =6400\frac{m^2}{s^2} +2(-10\frac{m}{s^2} )d\\-6400\frac{m^2}{s^2} =(-20\frac{m}{s^2}) d\\320m=d\)
*acceleration is negative (-a) as it is acting in the opposite direction of the motion of the bullet.*
The bullet rises to a height of 3600 m if a bullet is fired upward with a velocity of 80 m/s.
Assume the air friction is negligible, the kinematic equation:
\(v_f^2 = v_i^2 +2(-a) d\)
Where,
\(v_i^2\) - iinitial velocity = 80 m/s
\(v_f^2\)- final velocity = 0
\(d\)- distance= ?
\(a\)- gravitational acceleration = 9.8 m/s² = 10 m/s²
Put the values in the formula,
\(\begin {aligne} 0 = (80)^2 + 2 (10)^2 d\\\\d = \dfrac {6400}{ 200}\\\\d &= 3600 \rm \ m\end {aligne}\\\)
Therefore, the bullet rises to a height of 3600 m if a bullet is fired upward with a velocity of 80 m/s.
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What are some of the forces affecting rock climbers?
Answers
Answer:
Gravitational force
Explanation:
Gravitational force is obviously one of the biggest obstacles in climbing. You are essentially going against this very strong force to pull your body mass up the beautiful terrain. Gravity is defined as the force of attraction between all masses in the universe, gravity is what allows the sport of climbing.
Answer:
Gravity, low oxygen, and rock slides.
Explanation:
Some rock climbers train for years but are hardly prepared for some situations.
How is the çhocolate shell on the outside of the bar different from the ice cream on the inside?
Answers
Answer:
Cake Crunch (Enriched Wheat Flour [Bleached Flour, Niacin, Reduced Iron, Thiamine Mononitrate, Riboflavin, Folic Acid]), Sugar, Vegetable Shortening [Partially Hydrogenated Soybean and Cottonseed Oil], Salt, Sodium Bicarbonate, Artificial Flavor, Soy Lecithin, Soybean Oil, Coconut Oil, Sugar, Chocolate Liquor, ...
Jerry's boat capsized last Saturday, he had been fishing with a friend. His friend made it to shore and went
for help, but it was too late. The boat was pulled out of the river and taken to the police station, Jerry's body
was found floating in the missouri river the next day. The police assumed after speaking with the friend, that
Jerry drowned, but a quick look at the body by the ME and the manner of death had to be listed as pending
investigation. The ME found petechial hemorrhaging and there was no water in his lungs.
What do you think actually happened? Provide evidence and reasoning for your claim
HELPPP
Answers
Answer:
the friend strangled Jerry to death then went to get help.
Explanation:
Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!
Answers
Answer:
Explanation:
Photosynthesis is needed to store energy for the growth of the plant. It is like a factory that uses sunlight energy to convert 6CO₂ and 6H₂O into C₆H₁₂O₆ and 6O₂
Cell respiration is the process of breaking down the glucose and converting it into the other needed components of life. It's the engine that's fueled by the sugar of photosynthesis.
1. Ignoring air resistance, a 1.4 kg metal can was dropped from an unknown height. Just before it hits the ground, the metal can had a velocity of 3.8 m/s. Find the height the can was dropped from.
Answers
t = (v2 - v1)/a = (3.8 m/s - 0 m/s) / (-9.8 m/s^2) = 0.388 s
Next, we can use the equation of motion to find the height:
h = v1t + (1/2)at^2 = 0 m/s * 0.388 s + (1/2)(-9.8 m/s^2)(0.388 s)^2 = 7.11 m
So the height that the can was dropped from is 7.11 meters
Answer:
The can was dropped from a height of 0.74 meters.
Explanation:
We can use the Conservation of Energy to evaluate the height.
The formula for the Conservation of Energy is
\(\frac{1}{2} mv^2=mgh\)
Lets solve for \(h\).
Cancel the common factor of \(m\).
\(\frac{1}{2} v^2=gh\)
Rewrite \(\frac{1}{2} v^2\) as \(\frac{v^2}{2}\) .
\(\frac{v^2}{2}=gh\)
Multiply both sides by 2.
\(v^2=2gh\)
Divide both sides by \(2g\).
\(\frac{v^2}{2g}=h\)
Numerical Evaluation
We are given
\(v=3.8\\g=9.81\)
Substituting our values into our equation for height gives us
\(h=\frac{3.8^2}{2*9.81}\)
Evaluate \(3.8^2\).
\(h=\frac{14.44}{2*9.81}\)
Multiply \(2\) and \(9.81\).
\(h=\frac{14.44}{19.62}\)
\(h=0.736235\)
Note: We also could have solved this using the kinematics equations. Both methods give you the same answer.
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CHANGING STATES OF MATTER
As substances gain or lose energy their state, or phase, of matter changes,
STATE OF MATTER
Sublimation
Deposition
Condensation
Answers
Answer:
condensation and deposition
Explanation:
when something gets cooler it's molecules lose kinetic energy and that applies only in condensation and depostion
forces applied to the collision
Answers
Answer: I think this is the answer, In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.
Explanation: I had a question similar to this, Hope this helps!
When ultraviolet light with a wavelength of 400.0 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 eV.
What is the maximum kinetic energy K0 of the photoelectrons when light of wavelength 310 nm falls on the same surface?
Use h = 6.63×10−34 J⋅s for Planck's constant and c = 3.00×108 m/s for the speed of light and express your answer in electron volts.
Answers
Answer:
Explanation:
energy of photon having wavelength of 400 nm = 1237.5/400 eV
= 3.1 eV.
Maximum kinetic energy of photoelectrons = 1.1 eV .
Threshold energy Ф = 3.1 - 1.1 = 2 eV .
energy of photons having wavelength of 310 nm = 1237.5 / 310 eV = 4 eV .
Maximum kinetic energy of photoelectrons = energy of photons - Threshold energy
= 4 - 2 = 2 eV .
Required kinetic energy K₀= 2 eV.
A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).
Answers
The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².
How to calculate acceleration?Acceleration is change of velocity with respect to time (can include deceleration or changing direction).
The acceleration of a body can be calculated by using the following expression;
a = F/m
Where;
a = acceleration (m/s²)F = force (N)m = mass (kg)According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:
a = 4N ÷ 2.55kg
a = 1.57m/s²
Therefore, 1.57m/s² is the acceleration of the object.
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A submarine is designed to submerge to a depth of 340 m how much greater is the pressure on the side of the deck compared to the surface
Answers
The Pressure difference is given as 3482 kPa. Note that is is assumed that the ocean water density is 1024Kg/m³
What is the calculation justifying the above result?Let pressure on the surface is Po. Then pressure at h depth is, P = (Po + hdg ) where d is the density of the liquid.
Let's also assume that the ocean water has a density of 1024Kg/m³
Then, the pressure difference is ∆P = hdg
= 340×1024×10
= 3481600Pa
\(\approx\) 3482 kPa
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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
Answers
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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An airbys A380 airliner lands at 30 m/s. Partially loaded, its mass is 480000 kg. The engines apply reverse thrust for 12s to slow the plane to 25 m/s.How much thrust did the engines apply?
Answers
To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.
First, we calculate the change in velocity (∆v):
\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)
Next, we calculate the acceleration (∆a) using the formula:
\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)
where ∆t is the change in time, which is 12 seconds in this case.
\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)
Now, we can determine the force (thrust) applied by the engines using Newton's second law:
\(\displaystyle\sf F=m\cdot a\)
where m is the mass of the airplane, which is 480000 kg.
\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)
Calculating the result:
\(\displaystyle\sf F=-200000\,N\)
Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.
How are energy and motion related?
Answers
Motion energy is indeed the total of kinetic and potential energies in a workable item. The energy contained in moving things is known as motion energy.
What is energy?In physics, energy is the capacity to accomplish work. It can be potential, kinetic, thermal, electric, chemical, radioactive, or in other forms. There is also heat and work, which is energy inside the process of being transferred through one body to the other. Energy is always classified according to its type once it has been transmitted.
The energy contained in moving things is known as motion energy, sometimes known as mechanical energy. More energy is saved when the thing goes quicker. Motion energy is indeed the total of kinetic and potential energies in a workable item.
Therefore, motion energy is indeed the total of kinetic and potential energies in a workable item.
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I NEED A 100% ACCURATE ANSWER FOR THIS QUESTION ASAP NO LINKS !!!
What is defined by force per unit area?
1: gravity
2: force
3: temperature
4: pressure
Answers
Answer:
4. pressure is defined as force per unit area
Pressure is defined by force per unit area.
WHAT IS PRESSURE:Pressure refers to the force applied to a substance per unit area. Force is measured in Newtons (N) while area is measured in m², hence, the unit of pressure is N/m² also called pascal.Therefore, according to this question, it can be said that pressure is defined by force per unit area
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How do we know how much
gravitational force objects have?
Answers
Answer:
With a force of 1 Newton, an object weighing 100 grams is dragged towards the planet's center. On Earth, an item with a mass of 100 grams has a gravitational pull of only 1%, or about kg.
Explanation:
i hope this helps
what is the value of pi(8.104)^2 written with correct significant numbers
Answers
Answer:206.3
Explanation:
statics and strength of materials
Answers
The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.
What is the force P?The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;
Take moment about the joint to determine the magnitude of the force along part BC.
120 kN x 750 mm = F x 1000 mm
F = ( 120 kN x 750 mm ) / ( 1000 mm )
F = 90 kN
Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.
Stress in AB = 2 times stress in BC
P/A₁ = 2F/A₂
where;
A₁ is the area of segment ABA₂ is the area of segment BCA₁ = πd²/4 = π(50 x 10⁻³)²/4
A₁ = 1.96 x 10⁻⁵ m²
A₂ = πd²/4 = π(75 x 10⁻³)²/4
A₂ = 4.42 x 10⁻³ m²
P/A₁ = 2F/A₂
P = (2F x A₁) / (A₂)
P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )
P = 798.2 N
P = 0.798 kN
P ≈ 0.8 kN
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A boat heads East across a South flowing river. The river is 246 m wide and flows at a rate of 6.4 m/s. The boat sails across at 5.3 m/s..
How long will it take the boak to cross the river?
Answers
If a boat heads East across a South flowing river. The river is 246 m wide and flows at a rate of 6.4 m/s. The boat sails across at 5.3 m/s, then the time taken by the boat to cross the river would be 46.41 seconds.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.
As given in the problem a boat heads East across a South flowing river. The river is 246 m wide and flows at a rate of 6.4 m/s. The boat sails across at 5.3 m/s.
Time taken by the boat to cross the river = 246/5.3
=46.41 seconds
Thus, the time taken by the boat to cross the river would be 46.41 seconds.
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A 2kg block on a horizontal table is pulled to the right by a constant force of 16N the acceleration of the block is 3m/s^ 2 Determined the coefficient of kinetic friction between the block and the table top
Answers
The coefficient of kinetic friction between the block and the table top is 0.204.
Kinetic friction calculation.
To determine the coefficient of kinetic friction, we can use the equation for the net force acting on the block:
F_net = ma
where F_net is the net force, m is the mass of the block, and a is the acceleration of the block. The net force is the difference between the applied force and the force of friction:
F_net = F_applied - F_friction
where F_applied is the applied force, and F_friction is the force of friction.
Since the block is moving with constant velocity, the force of friction is equal in magnitude but opposite in direction to the applied force:
F_friction = μ_k * N
where μ_k is the coefficient of kinetic friction, and N is the normal force (equal to the weight of the block, N = mg).
Substituting the expressions for F_net and F_friction into the first equation and solving for the coefficient of kinetic friction, we get:
F_applied - μ_k * N = ma
μ_k = (F_applied - ma) / N
Substituting the given values, we get:
μ_k = (16 N - 2 kg * 3 m/s^2) / (2 kg * 9.8 m/s^2)
μ_k = 0.204
Therefore, the coefficient of kinetic friction between the block and the table top is 0.204.
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The position of a particle moving along the x axis is given by x = 6.0t 2 - 1.0t 3, where x is in meters and t in seconds. What is the position of the particle when it achieves its maximum speed in the positive x direction?
Answers
The position of the particle when it achieves its maximum speed in the positive x direction is 20 meters
Explanation:The position of the particle is given by the equation
\(x=6t^2-t^3\)The speed (v) of the particle is calculated as:
\(\begin{gathered} v=\frac{dx}{dt} \\ v=12t-3t^2 \end{gathered}\)The acceleration of the particle is:
\(\begin{gathered} a=\frac{dv}{dt} \\ a=12-6t \end{gathered}\)At maximum speed, the acceleration of the particle is zero
That is, a = 0
a = 12 - 6t
0 = 12 - 6t
6t = 12
t = 12/6
t = 2
This means that the speed of the particle is maximum at the time, t = 2
Substitute t = 2 into x = 6t² - t³
x = 6(2²) - (2²)
x = 6(4) - 4
x = 24 - 4
x = 20 meters
The position of the particle when it achieves its maximum speed in the positive x direction is 20 meters
what are the factors affecting center of mass in an object
Answers
- The axis of the system.
- The distribution of mass.
- The mass of the rigid body.
How much work is done on a 85 Newton box of books that you carry horizontally 4 meters across a room?
a 60 J
b 360 J
c 0 J
d 10 J
e 6 J
Answers
The work done on 85 N boxes of books while carried horizontally 4m across a room is equal to zero. Therefore, option (C) is correct.
What is the work?Work can be demonstrated as the energy used when a force is exerted to move an object through a definite displacement. The work done defines both the exerted force on the object and the distance moved by the object.
The applied force moves an object in a straight line in the direction of the exerted force over a displacement 'd'.
W= F × d
Where 'F' is the exerted force and 'd' is the displacement and W is work done.
Given, the weight of the box = 80 N
The displacement , d = 4 m
In order for to work to be done the box should move in the direction of exerted force as the books are moving forward direction and the applied force in an upward direction to carry the box.
Therefore, the distance moved in the direction of force is zero so the work done is also equal to zero.
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write down the value of
920 kg in g
Answers
Answer:
920000
Explanation:
Each kg contains 1,000 grams
why in five glass is not give a vinegar
Answers
While certain types of glass containers may be suitable for short-term storage of vinegar, it is generally recommended to use non-reactive materials, such as plastic or stainless steel, for long-term storage to avoid any potential chemical reactions or corrosion.
Vinegar is an acidic liquid that contains acetic acid. When vinegar comes into contact with certain types of glass, particularly those made of lead or other reactive materials, a chemical reaction can occur. This reaction can lead to the leaching of potentially harmful substances into the vinegar.
Glass containers made from specific types of glass, such as soda-lime glass, are generally safe for storing vinegar.
However, it is important to note that prolonged storage or exposure to vinegar can still cause the glass to corrode over time. This can result in the deterioration of the glass container, potentially leading to breakage or the release of glass fragments.
To avoid any potential issues, it is recommended to use containers made of non-reactive materials, such as food-grade plastic or stainless steel, for long-term storage of vinegar. These materials do not react with the acidic nature of vinegar and do not pose a risk of leaching harmful substances.
Additionally, it is important to store vinegar in a cool, dark place to maintain its quality and prevent spoilage. Exposure to light and heat can degrade the quality of vinegar over time.
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A sample of The halflife of the substance is 21 minutes the number of atoms remaining underway. radioactive Substances has 812X1020 atom Determine the number of atoms remaining
Answers
After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.
To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:
N(t) = N0 * \((1/2)^{(t / T)\),
where:
N(t) = number of atoms remaining at time t,
N0 = initial number of atoms (812 x \(10^{20\) atoms),
T = half-life of the substance (21 minutes), and
t = time that has passed.
Let's calculate the number of atoms remaining after a given time.
Suppose the time passed is t = 42 minutes (twice the half-life).
N(t) = 812 x \(10^{20\) * \((1/2)^{(42 / 21)\)
N(t) = 812 x \(10^{20\) * \((1/2)^2\)
N(t) = 812 x \(10^{20\) * 1/4
N(t) = 203 x \(10^{20\) atoms.
So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.
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