A potential difference of 71 mV is developed across the ends of a 12.0-cm-long wire as it moves through a 0.27 T uniform magnetic field at a speed of 6.0 m/s. The magnetic field is perpendicular to the axis of the wire.

Required:
What is the angle between the magnetic field and the wire's velocity?

Answers

Answer 1

Answer:

Explanation: please see attached file I attached the answer to your question.

A Potential Difference Of 71 MV Is Developed Across The Ends Of A 12.0-cm-long Wire As It Moves Through
Answer 2

The angle between the magnetic field and the wire's velocity is 33.2 degrees.

Calculation of the angle:

Since the potential difference = 71mv = 71 *10 ^-3 V

The length is 12 cm = 0.12m

The magnetic field i.e. B = 0.27T

The speed or v = 4 m/s

here we assume \(\theta\) be the angle

So,

e = Bvl sin\(\theta\)

So,

\(Sin\theta\) = e/bvl

= 71*10^-3 / 0.27 *4*0.12

= 0.5478

= 33.2 degrees

Therefore, the angle should be 33.2 degrees

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Related Questions

a copper water tank of mass 20 kg contains 150 kg of water at 15°C calculate the energy needed to heat the water and the tank to 55°C

copper shc - 385j/kg
water shc - 4200j/kg

Answers

Answer: 25230800 Joules

Explanation: We can treat the copper tank and the water inside as two different objects since they have different specific heats. We will utilize Q=Mcdelta(t) in this problem where M is mass, c is specific heat, and delta t is the change in temperature.

Since we are treating the copper and water separately we can make a Mcdelta(t) for each one of them. This gives us Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t)). The delta t will be the same because both the copper and water are at 15 celsius. Now we just do some calculations.

Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t))

Q=(20)(385)(55-15)+(150)(4200)(55-15)

Q=30800+25200000

Q=25230800 J

This number may seem absurdly high but there is 150 kg of water being heated up which is 150 liters(A LOT!).

Hope this helps!

Which statement BEST explains why a bouncing basketball will not remain in motion forever?

Group of answer choices

The energy is transferred to sound and heat energy.

The energy is used up and destroyed.

The energy is transferred to light and potential energy.

The energy is transferred to chemical and heat energy.

Answers

Answer:

The energy is transferred to chemical and heat energy.

Explanation:

If you define "bouncing" as leaving the ground for any amount of time, the ball stops bouncing when the elastic energy stored in the compression phase of the bounce is not enough to overcome the weight of the ball. This is the proof of the answer i Hope this helps :)

Sasha is measuring the rate of heat energy given off by an incandescent light bulb. The theoretical value is 55.4 watts. Her measurement has a 2.17 error. Which of the following values may have been Sasha's measurement? (Choose all that apply)



A. 1.20 watts
B. 54.2watts
C.56.6watts
D.53.23watts
E. 57.57watts

Answers

The measurement of Sasha, given the data from the question is 57.57 watts (Option E)

How to determine Sasha's measurement

The following data were obtained from the question:

Theoretical value = 55.4 wattsAbsolute error = 2.17 wattsSasha' measurement =?

To obtain Sasha's measurement, we shall determine the experimental measurement. This is illustrated below:

Absolute error = Experimental measure - theoretical measurement

2.17 = Experimental measure - 55.4

Collect like terms

Experimental measure = 2.17 + 55.4

Experimental measure = 57.57

Thus, we can conclude that Sasha' measurement is 57.57 watts (Option E)

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state ohmic conductor​

Answers

Answer:

An ohmic conductor is defined as one which obeys ohm's law that is V ∝ I where is the voltage and is the current. There must be a linear graph. Silver is an example of an ohmic conductor as the graph for silver is a linear graph. Silver and copper are some examples of ohmic conductor

how can you relazie a perfect balck body in pratice​

Answers

a perfect black body can’t be realized

What is energy anything that takes up space and has mass a change in the position of an object a push or pull the ability to cause change in matter

Answers

Energy is that which has the ability to cause change in matter.

What is energy?

Energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light. Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.

So in simple definition we can say that energy is that which has the ability to cause change in matter.

Based on the given statements we can classify them as;

anything that takes up space and has mass - matter.cause a change in the position of an object through push or pull - forcethe ability to cause change in matter - energy.

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An organism has 20 chromosomes after fertilization.after meiosis, how many chromosomes would each sex cell have?

Answers

Answer:

EACH SEX CELL WILL HAVE 10 CHROMOSOMES BECAUSE n+n=2n

means haploid parent cells join or fuse to form diploid zygote

Answer:

10

Explanation:

Do you think Kepler will be able to detect Earth-sized planets in transit?

Answers

Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.

Explanation:

A model rocket has a mass of 0.2 kg, with a motor that can provide a force of 200 N. A second model rocket is being built with the same motor, but it is being designed to accelerate one-fourth as much as the first rocket.What kind of change can be made in the design to achieve this objective?
brainliest! for a full explanation

Answers

We can achieve this design by adding weight to the second rocket, such as by adding a heavier nose cone, fins, or other components.

What kind of change can be made in the design?

The first model rocket has a mass of 0.2 kg and is powered by a motor that can provide a force of 200 N.

Using Newton's second law of motion, we can calculate the acceleration of the rocket:

F = ma

where;

F is the force applied to the rocket, m is the mass of the rocket, and a is the acceleration of the rocket.

Rearranging the equation, we can solve for the acceleration:

a = F/m

Plugging in the values, we get:

a = 200 N / 0.2 kg

a = 1000 m/s^2

So the first model rocket accelerates at 1000 m/s².

The second model rocket is being designed to accelerate one-fourth as much as the first rocket. This means that its acceleration will be:

a' = 1/4 * a

a' = 1/4 * 1000 m/s²

a' = 250 m/s²

So we need to design the second rocket so that it accelerates at 250 m/s².

We can use the same motor, so the force applied to the rocket will still be 200 N. Therefore, we need to change the mass of the rocket to achieve the desired acceleration.

Using the equation for acceleration, we can solve for the mass needed to achieve an acceleration of 250 m/s²:

a' = F/m'

250 m/s² = 200 N / m'

m' = 200 N / 250 m/s^2

m' = 0.8 kg

So the mass of the second rocket needs to be 0.8 kg in order to achieve an acceleration of 250 m/s² with the same motor.

Thus, we can achieve this by adding weight to the second rocket, such as by adding a heavier nose cone, fins, or other components. Alternatively, we could also increase the size of the second rocket while keeping the same mass, which would decrease its acceleration but also increase its overall speed and altitude.

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Because of surface tension, it is possible, with care, to support an object heavier than water on the water surface. The maximum thickness, h, of a square material that can be supported is assumed to be a function of the length of the side of the square, the density of the material, the acceleration of gravity, and the surface tension of the liquid. Develop a suitable set of dimensionless parameters for this problem.

Answers

Answer:

\(\pi 1 = \frac{h}{l}\)

\(\pi 2 =\) б / \(l^2gp\)

\(\frac{h}{l} =\) Ф ( б / \(l^2gp\) )

Explanation:

Develop a suitable set of dimensionless parameters for this problem

The set of dimensionless parameters for this problem is :

\(\pi 1 = \frac{h}{l}\)

\(\pi 2 =\) б / \(l^2gp\)

\(\frac{h}{l} =\) Ф ( б / \(l^2gp\) )

and they are using the pi theorem, MLT systems

attached below is a detailed solution

Because of surface tension, it is possible, with care, to support an object heavier than water on the

How has Physics improved
or affected our society?

Answers

By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life

From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.

The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.

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which is not an insulator?
A wood
B plastic foam
C aluminum foil
D fiberglass

Answers

Answer:the answer is C aluminum foil

Explanation:

Part A : A cylindrical water tank 10cm high and 520cm in diameter is filled with solution with a density of 0.75 g/cm^3

a) What is the water pressure on the bottom of the tank? (pressure in psi)
Show calculations

b) What is the average force on the bottom? ​​

Answers

Answer: \(0.1066\ psi, 15.611\ kN\)

Explanation:

Given

the height of the tank is \(h=10\ cm\)

The diameter of the tank is \(d=520\ cm\)

Density of solution \(\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3\)

\((a)\) Water pressure at the bottom of the tank is

\(P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa\)

\(1\ Pa=0.000145038\ psi\)

\(\Rightarrow P=735\ Pa\ or\ 0.1066\ psi\)

\((b) \text{Average force on the bottom is the product of pressure and area of the base}\)

\(F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN\)

Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93

Particles q +8.0 C, q2 +3.5 C, and93-2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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A ball is rolling away from you at a constant speed, hits a wall, and then suddenly stops moving. Imagine a position-versus-time graph showing the ball’s motion. Describe the line on the graph.

Answers

Answer:

It would show a "straight line".

Explanation:

Newton's First Law of Motion states that an object at rest will remain at rest and an object in motion will remain in motion (at a constant velocity) unless acted upon by an unbalanced force. Newton's first law of motion is also called the law of inertia.

In a laboratory experiment, a student was exploring the stretch of a spring based on the pull of the force. The student used weights of 1 N, 2 N, 3 N, 4 N, and 5 N. The points were plotted, and the relationship was analyzed. The graph is shown.

A graph titled stretch versus force is shown with stretch on the vertical axis and force on the horizontal axis. The graph is a straight diagonal line from bottom left to top right going through points 0 comma 0, 1 comma 1.0, 2 comma 3.6, 3 comma 5.5, 4 comma 7.2, and 5 comma 9.1.
Which of the following values would be considered an interpolation?

Force = 0 N, stretch = 0 cm
Force = 3 N, stretch = 5.5 cm
Force = 4.4 N, stretch = 7.9 cm
Force = 5.2 N, stretch = 9.3 cm

Answers

Final answer:

Interpolation refers to determining a value within an established dataset. In the context of the spring stretch experiment, the value 'Force = 4.4 N, stretch = 7.9 cm' is considered an interpolated value as it falls within the used force range (0N to 5N). The other values are either used in the experiment or extrapolations.

Explanation:

In this context, interpolation refers to the process of determining a value within an existing data set or between two known values. In your given data for the spring stretch experiment, the force values used in the experiment range from 0N to 5N. As such, an interpolated value would need to fall within this range.

Given that, the value Force = 4.4 N, stretch = 7.9 cm would be considered an interpolation because it falls within the known values used in the experiment. The rest of the options are either values used in the experiment (0 N, 3 N) or extrapolation (5.2 N) as they are outside of the range of force investigated.

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Final answer:

Considering the values from the experiment, the interpolated value between the known points on the graph is 'Force = 4.4 N, stretch = 7.9 cm', since it falls within the range of given values.

Explanation:

In the context of this laboratory experiment, interpolation refers to predicting a value within a range of known values. From the given points plotted on the graph, the values of force range from 0 N to 5 N, and the corresponding stretch ranges from 0 cm to 9.1 cm. Looking at the listed options, the value Force = 4.4 N, stretch = 7.9 cm falls within these known ranges of both force and stretch, thereby qualifying as an interpolation.

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A baseball (m = 140 g) traveling at 30. m/s moves a fielder's glove backward 35 cm when the ball is caught.  
What was the average force exerted by the ball on the glove?​

Answers

Answer:

180

Explanation:

1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);

2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).

3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which

\(F=\frac{mV^2}{2L};\)

4) according to the last formula

\(F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).\)

The force exerted by the ball on the glove is 180 Newtons.

What is force?

In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687).

Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it.

Given:

A baseball (m = 140 g) traveling at 30 m/s moves a fielder's glove backward 35 cm when the ball is caught,

Calculate the value of force as shown below,

Force = m × V² / 2L

Force = 0.140 × 30² / 2 × 0.35

Force = 0.140 × 900 / 0.70

Force = 126 / 0.7

Force = 180 N

Thus, the force exerted by the ball is 180 Newtons.

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Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!


Here is a function machine.



Input : multiply by 6. Subtract 80: output



The input is the same as the output. Find the input.


Also can you please show me an easy to work out these type of questions

Answers

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?

Answers

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?​

Answers

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.

Answers

The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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You are a visitor aboard the New International Space Station, which is in a circular orbit around the Earth with an orbital speed of o=2.45 km/s
. The station is equipped with a high velocity projectile launcher, which can be used to launch small projectiles in various directions at high speeds. Most of the time, the projectiles either enter new orbits around the Earth or eventually fall down and hit the Earth. However, as you know from your physics courses at the Academy, projectiles launched with a sufficiently great initial speed can travel away from the Earth indefinitely, always slowing down but never falling back to Earth.

With what minimum total speed, relative to the Earth, would projectiles need to be launched from the station in order to "escape" in this way? For reference, recall that the radius of the Earth is E=6370000 m
, the mass of the Earth is E=5.98×1024 kg
, the acceleration due to gravity on the surface of the Earth is =9.81 m/s2
and the universal gravitational constant is =6.67×10−11 N·m2/kg2
.

You are a visitor aboard the New International Space Station, which is in a circular orbit around the

Answers

Answer:

To calculate the minimum total speed required for the projectile to escape the Earth's gravitational pull, we can use the equation for escape velocity:

v_escape = sqrt(2GM/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth.

Plugging in the given values, we get:

v_escape = sqrt(26.67e-115.98e24/6370000)

v_escape = 11186.4 m/s

This is the minimum total speed required for the projectile to escape the Earth's gravitational pull. In order to achieve this speed, the projectile would need to be launched with a velocity of 11186.4 m/s relative to the Earth.

Explanation:

An owl has a mass of 4 kg. It dives to catch a mouse, losing 800 J of its GPE. What was the starting height of the owl, in meters?

Answers

The owl started out at a height of about 3.2 metres.

What is gravity?

Gravity is the force that draws objects toward the center of a planet or other object.

How do you determine this?

Gravitational potential energy (GPE) is calculated as follows:

GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).

On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.

By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.

By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.

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Question 20 (4 points)
Listen
When a net horizontal force of 250 N acts on a 50-kg cart that is free to roll on a
level surface,
A) the cart accelerates at 9.8 m/s².
B)
the cart accelerates at 0.20 m/s².
C)
the cart accelerates at 5 m/s².
D)
the cart accelerates at 12500 m/s².
E)
the cart does not accelerate because it pushes back on the person with a
force of 250 N.

Answers

Explanation:

C is correct.

Newton second law states that force is directly proportional to acceleration with m being the constant of variation.

\(f _{net} = m(a)\)

So

\(250 = 50(a)\)

\(a = 5\)

A is wrong, the constant g only happens in free fall or in vertical direction

B and D are wrong due to the mathematical error or equation error

2.27 A gas is compressed from V1= 0.3 m3, p1=1 bar to V2= 0.1 m3, p2 =3 bar. The pressure and
the volume are related linearly during the process. For the gas, find the
work, in kJ.
2.29 A gas expands from an initial state where p1=500kPa and V1=0.1m3 to a state
end where p2= 100 kPa. The relationship between pressure and volume during the process is
pV=constant. Schematize the process in a p-V diagram and determine the work, in
kJ.

Answers

Answer:

-40 kJ

80 kJ

Explanation:

Work is equal to the area under the pressure vs volume graph.

W = ∫ᵥ₁ᵛ² P dV

2.27) Pressure and volume are linearly related.  When we graph P vs V, the area under the line is a trapezoid.  So the work is:

W = ½ (P₁ + P₂) (V₂ − V₁)

W = ½ (100 kPa + 300 kPa) (0.1 m³ − 0.3 m³)

W = -40 kJ

2.29) Pressure and volume are inversely proportional:

pV = k

The initial pressure and volume are 500 kPa and 0.1 m³.  So the constant is:

(500) (0.1) = k

k = 50

The final pressure is 100 kPa.  So the final volume is:

(100) V = 50

V = 0.5

The work is therefore:

W = ∫ᵥ₁ᵛ² P dV

W = ∫₀₁⁰⁵ (50/V) dV

W = 50 ln(V) |₀₁⁰⁵

W = 50 (ln 0.5 − ln 0.1)

W ≈ 80 kJ

2.27 A gas is compressed from V1= 0.3 m3, p1=1 bar to V2= 0.1 m3, p2 =3 bar. The pressure andthe volume
2.27 A gas is compressed from V1= 0.3 m3, p1=1 bar to V2= 0.1 m3, p2 =3 bar. The pressure andthe volume

In six sentences discuss the 4 universal forces

Answers

There are four fundamental forces at work in the universe: the strong force, the weak force, the electromagnetic force, and the gravitational force.

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Title: The Four Universal Forces

There are four fundamental forces in the universe that govern the behavior of matter and energy. These forces are:

1. Gravity: Gravity is the force that attracts two objects with mass towards each other. It is the weakest of the four fundamental forces but has an infinite range. Gravity is responsible for the motion of planets, stars, and galaxies.

2. Electromagnetic force: The electromagnetic force is the force that exists between electrically charged particles. It is responsible for the behavior of atoms and molecules, and the interaction between light and matter.

3. Strong nuclear force: The strong nuclear force is the force that holds the nucleus of an atom together. It is a very strong force that only acts over short distances.

4. Weak nuclear force: The weak nuclear force is the force responsible for certain types of radioactive decay. It is a very weak force that only acts over very short distances.

These four fundamental forces are responsible for all the interactions that occur in the universe. While gravity dominates on the largest scales, the other three forces are more important on the atomic and subatomic scales. Understanding and describing the behavior of matter and energy at these scales requires a deep understanding of the four fundamental forces and their interactions.

A large boulder falls from an underwater ledge and crashes on the floor of the ocean. A pod of dolphins is 800 meters away. Determine how long it takes for the sound of the crash to reach the dolphins.

0.5 sec
0.3 sec
2.3 sec
1.9 sec

Answers

Answer:

0.5

Explanation:

Answer:

0.539

Explanation:

find the rate of energy radiated by a man by assuming the surface area of his body 1.7m²and emissivity of his body 0.4​

Answers

The rate of energy radiated by the man is 3.86 x \(10^{-8}\)  J/s. \(m^{2}\).

The amount of energy radiated by an object majorly depends on the area of its surface and its temperature. The is well explained in the Stefan-Boltzmann's law which states that:

Q(t) = Aeσ\(T^{4}\)

where: Q is the quantity of heat radiated, A is the surface area of the object, e is the emmisivity of the object, σ is the Stefan-Boltzmann constant and T is the temperature of the object.

To determine the rate of energy radiated by the man in the given question;

\(\frac{Q(t)}{T^{4} }\) = Aeσ

But A = 1.7 m², e = 0.4 and σ = 5.67 x \(10^{-8}\) J/s.

So that;

\(\frac{Q(t)}{T^{4} }\) = 1.7 * 0.4 * 5.67 x \(10^{-8}\)

     = 3.8556 x \(10^{-8}\)

     = 3.86 x \(10^{-8}\)  J/s. \(m^{2}\)

Thus, the rate of energy radiated by the man is 3.86 x \(10^{-8}\)  J/s. \(m^{2}\).

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A soil clod weighing 885 grams was coated with paraffin. The weight of the clod and the paraffin was 993 grams. The total volume of the clod when immersed in water was 492 cm³. If the mass water content of the clod was 18%, its particle density is 2.65 g/cm³ and paraffin's density is 0.89 g/cm³, determine (i) the bulk density, (ii) void ratio, and (iii) the degree of saturation. 2​

Answers

(i) To determine the bulk density of the soil, we need to know the volume of the soil without any voids. The volume of the soil including voids is 492 cm³, so we need to determine the volume of the soil particles in the clod.

First, we can determine the mass of the dry soil particles by subtracting the mass of the water from the total mass of the clod and paraffin:

Mass of dry soil particles = Total mass - Mass of water
Mass of dry soil particles = 993 g - (0.18 x 885 g)
Mass of dry soil particles = 850.3 g

Next, we can determine the volume of the dry soil particles by dividing their mass by their particle density:

Volume of dry soil particles = Mass of dry soil particles / Particle density
Volume of dry soil particles = 850.3 g / 2.65 g/cm³
Volume of dry soil particles = 321.4 cm³

Now we can calculate the bulk density of the soil:

Bulk density = Mass of dry soil particles / Total volume
Bulk density = 850.3 g / 492 cm³
Bulk density = 1.728 g/cm³

(ii) The void ratio is the ratio of the volume of voids to the volume of soil particles. We can determine the volume of voids by subtracting the volume of dry soil particles from the total volume of the clod:

Volume of voids = Total volume - Volume of dry soil particles
Volume of voids = 492 cm³ - 321.4 cm³
Volume of voids = 170.6 cm³

Now we can calculate the void ratio:

Void ratio = Volume of voids / Volume of dry soil particles
Void ratio = 170.6 cm³ / 321.4 cm³
Void ratio = 0.531 or 53.1%

(iii) The degree of saturation is the ratio of the volume of water to the volume of voids. We can determine the volume of water by multiplying the mass of water by the inverse of its density:

Volume of water = Mass of water / Density of water
Volume of water = 0.18 x 885 g / 1 g/cm³
Volume of water = 158.7 cm³

Now we can calculate the degree of saturation:

Degree of saturation = Volume of water / Volume of voids
Degree of saturation = 158.7 cm³ / 170.6 cm³
Degree of saturation = 0.93 or 93%

The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.

Answers

The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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