A poll was taken in a town with a population of 15,000. The poll asked for an opinion of the city council's performance for the past year. The number of
people who thought that the council had done well was 9,500. What percent of the population voted favorably? (Round to the nearest tenth if necessary)

Answer:

in 2002 89.7 percent of people owned dogs

Answer:

Step-by-step explanation:

Sure it is

Answer:

You are right it is not a triangle

It take 21.2 minutes longer to fill both the pipe together if both were opened at the same time.

In mathematics, fractions are used to represent proportions/parts of a whole. represent the same part of the whole. The top number is called the numerator and the bottom number is called the denominator. The numerator express the number of equal parts and the denominator defines the total number of equal parts of the whole.

Based on the given condition- formulation is-

1/1/45+1/40

We have to find the common denominator and then we can write the numerators above the common denominator

1/(8/45×8 + 9/40×9)

Now we have to calculate the product

1/(8/360+9/40×9)

1/(8+/360+9/360)

We have to write the numerators over common denominator

1/ 8+9/360

= 1/17/360

Divide a fraction by multiplying it's reciprocal

=360/17

= 21.2 m

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A state with a sales tax is a better option for both individuals and state governments.

WHAT IS SLES TAX?

A state without a sales tax may seem preferable since they do not have to pay additional taxes on purchases. However, in such states, the government often imposes higher income taxes or property taxes to compensate for the lack of sales tax revenue. Therefore, it ultimately depends on the individual's financial situation and spending habits.

From the state government's perspective, having a sales tax is generally more beneficial as it provides a consistent and reliable revenue stream. Sales tax revenue is collected on a regular basis and is not subject to fluctuations in the economy or changes in demographics. Additionally, sales tax revenue is not as heavily reliant on the state's residents and can be partially collected from tourists and visitors who make purchases within the state.

In my opinion, a state with a sales tax is a better option for both individuals and state governments. While paying additional taxes may not seem appealing, it allows the state to fund essential services such as education, healthcare, and infrastructure. Additionally, sales tax revenue is spread across a wider population, making it more equitable and less burdensome on individual taxpayers. Overall, having a sales tax system in place helps to ensure that the state government can continue to provide essential services and maintain a stable economy.

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For the data  12, 14, 21, 19, 25, 29, 26, 21, 15, and 18.

the mean is 20

the standard deviation is 3.7

the interquartile is 10

For the data  12, 14, 21, 19, 25, 29, 26, 21, 15, and 18. the mean is calculated as follows

= sum of data / number of data

sum = 200

number of data = 10

mean (x bar)  = 200 / 10

= 20

standard deviation

standard deviation is the square root of  the ratio of sum of squares to number of samples

sum of squares = (x - x bar)²

= (12 - 20)² + (14 - 20)² + (21 - 20)² + ......+(21 - 20)² + (15 - 20)² + (18 - 20)²

= 274

standard deviation = √(274 / 20) = 3.7

Interquartile range = upper quartile - lower quartile

raw data = 12, 14, 21, 19, 25, 29, 26, 21, 15, and 18

arranged data =  12, 14, 15, 18, 19, 21, 21, 25, 26, 29,

upper quartile = 25

lower quartile = 15

Interquartile range = 25 - 15 = 10

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Answer:

.5 < 2 - sqrt(2) < .6

Step-by-step explanation:

sqrt() is larger than 1.4 and less than 1.5

2 - sqrt(2)    2 -1.4 = .6

2 - sqrt (2) 2 - 1.5 = .5

.5 < 2 - sqrt(2) < .6

\(1.4 < \sqrt{2} <1.5 \\ - 1.5 < - \sqrt{2} < - 1.4 \\ 2 - 1.5 < 2 - \sqrt{2} < 2 - 1.4 \\ 0.5 < 2 - \sqrt{2 } < 0.6\)

The potential areas for Franklin's garden are 144ft², 36ft² and 196ft² hence options (b), (e), and (f) are correct.

To find the potential areas for Franklin's square garden, we need to find the perfect squares that can be expressed as the product of two identical whole numbers. These perfect squares will represent the areas of the square gardens with whole number side lengths,

a) 20 ft² = 2 x 2 x 5 = (2 x 2) x 5 = 4 x 5, not a perfect square

b) 144 ft² = 12 x 12 = (12 x 12), a perfect square

c) 1,000 ft² = 10 x 10 x 10 = (10 x 10) x 10 = 100 x 10, not a perfect square

d) 300 ft² = 10 x 10 x 3 = (10 x 10) x 3 = 100 x 3, not a perfect square

e) 36 ft² = 6 x 6 = (6 x 6), a perfect square

f) 196 ft² = 14 x 14 = (14 x 14), a perfect square

Therefore, the potential areas for Franklin's garden are 144 ft², 36 ft², and 196 ft². So, options (b), (e), and (f) are the potential areas for Franklin's square garden with whole number side lengths.

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Answer:

Im not sure

Step-by-step explanation:

GOOD LOOK ON YOUR TEST HE DISCONN-ECTED

The balance increase for card i is $89.24 greater than the balance increase for card h. Card i has a balance of $1,522.16 and an interest rate of 12.05%, compounded monthly. Now, we can calculate the balance for both cards after three years using the compound interest formula: A = P(1 + r/n)^(nt)

Given, Card h has a balance of $1,186.44 and an interest rate of 14.74%, compounded annually.

Card i has a balance of $1,522.16 and an interest rate of 12.05%, compounded monthly. Now, we can calculate the balance for both cards after three years using the compound interest formula: A = P(1 + r/n)^(nt),

where A = final amount, P = principal (initial balance), r = annual interest rate (as a decimal), n = number of times compounded per year, t = time (in years)

For card h,

A = 1186.44(1 + 0.1474/1)^(1*3)

A = 1883.99

For card i, A = 1522.16(1 + 0.1205/12)^(12*3)

A = 1973.23

Therefore, the balance for card i will have increased more than that of card h, and the difference in the increase is: 1973.23 - 1883.99 = 89.24

The balance increase for card i is $89.24 greater than the balance increase for card h. Hence, the required answer is card i.

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(a) A nonzero vector orthogonal to the plane through the points P, Q, and R is (9, -17, 35). (b) The area of triangle PQR is \(\sqrt\)(811) / 2.

(a) To determine a nonzero vector orthogonal to the plane through the points P, Q, and R, we can first find two vectors in the plane and then take their cross product. Taking vectors PQ and PR, we have:

PQ = Q - P = (5, 1, -2) - (-4, 0, 0) = (9, 1, -2)

PR = R - P = (6, 4, 1) - (-4, 0, 0) = (10, 4, 1)

Taking the cross product of PQ and PR, we have:

n = PQ x PR = (9, 1, -2) x (10, 4, 1)

Evaluating the cross product gives n = (9, -17, 35). Therefore, (9, -17, 35) is a nonzero vector orthogonal to the plane through points P, Q, and R.

(b) To determine the area of triangle PQR, we can use the magnitude of the cross product of vectors PQ and PR divided by 2. The magnitude of the cross product is given by:

|n| = \(\sqrt\)((9)^2 + (-17)^2 + (35)^2)

Evaluating the magnitude gives |n| = \(\sqrt\)(811).

The area of triangle PQR is then:

Area = |n| / 2 = \(\sqrt\)(811) / 2.

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In a diagram,

Where l is the length of the ladder.

Therefore, using the Pythagorean theorem,

Solving for l,

Solve using the quadratic formula,

However, notice that if l=2, l-4 would be negative which is impossible as it is a length.

Therefore, the only valid answer is l=10.

the lower class limit represents the smallest data value that can be included in the classThe statement is true.

The lower class limit is the smallest value that can be included in a class interval.

Therefore, the statement is correct.

The lower class limit represents the smallest data value that can be included in a particular class. In a frequency distribution table, data values are grouped into classes, and each class has a lower and upper class limit. The lower class limit denotes the lowest value within that class, and any data value equal to or greater than the lower limit but less than the upper limit falls into that class.

The statement is true, as the lower-class limit indeed represents the smallest data value that can be included in the class.

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Answer:

Decrease by 2 and 3

Then on x increase by 2 and 3

Step-by-step explanation:

Answer:

The expression that represent each person's share is: \(y(p) = \frac{8}{p}\)

Step-by-step explanation:

To divide a pizza, or anything else, equally among a certain number of people, we need to divide the total of pizza available by the number of people who will eat the pizza. In this case there are 8 slices and 'p' people, therefore:

\(y(p) = \frac{8}{p}\)

In order to validate the expression, we can see that if 8 people eat the pizza, each gets one slice, because 8 divided by 8 is 1, while if 4 people eat the pizza each get 2 and so on.

The expression that represent each person's share is: \(y(p) = \frac{8}{p}\)

Answer:

Step-by-step explanation:

i can not see the attachment

Answer:

i would say C if not A i maybe wrong on both but dont hate me, i tried

Step-by-step explanation:

On a number line, the distance between any number and itself is always 0. Therefore, the distance between 6 and 6 is 0.

The distance between 24 and 17 can be calculated by subtracting the smaller number from the larger number, considering only the magnitude: |24 - 17| = 7.

Similarly, the distance between 17 and 24 can be calculated as |17 - 24| = 7. The absolute value ensures that the distance is always positive, regardless of the order of subtraction.

For the distance between a variable "t" and 4, the answer depends on the relationship between t and 4. If t is smaller than 4, the distance is expressed as |t - 4|. If t is greater than 4, the distance is expressed as |4 - t|. In either case, the absolute value ensures a positive value.

The distance between any numbers a and b on the number line can be calculated as |a - b|.

The relationship between |p - q| and |q - p| is that they are equal. The absolute value function disregards the sign of the argument, so whether you subtract p from q or q from p, the result will have the same magnitude. Therefore, |p - q| = |q - p|.

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The polygon above has 10 sides . It is an irregular decagon.

A polygon is defined as a shape that has equal side and interior angles while an irregular polygon is the polygon that has unequal sides and angles.

Typical examples of polygon include the following: Triangles, hexagons, pentagons, decagon, heptagon, nonagons. and quadrilaterals

From the shape given above, the polygon has ten sides and angles that are unequal in size. Therefore the shape given above is a typical example of an irregular decagon.

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Answer:

21,080

Step-by-step explanation:

Answer:

5 + 2s

Step-by-step explanation:

To simplify this expression, we will simply factor out the variable s from the terms with s, and use addition and the distributive property to reapply the variable to the simplified term.

5 + 10s - 8s

= 5 + s ( 10 - 8 )

= 5 + s ( 2 )

= 5 + 2s

Hence, the simplified expression of 5 + 10s - 8s is 5 + 2s.

Cheers.

it takes 5 years  for the shoreline to erode 15 feet to a grass line

Two or more expressions with an Equal sign is called as Equation.

The erosion rate of a coastline is approximately 3 feet per year

if erosion continues at the current rate, how many years will it take for the shoreline to erode 15 feet to a grass line

Let us formulate the equation

Let x be the number of years for 15 feet.

3/1=15/x

Apply cross multiplication

3x=15

Divide both sides by 3

x=5

which is 5 years,

adding 24 ft means, it would take 13 yrs.

3 x 8 = 24

Hence it takes 5 years  for the shoreline to erode 15 feet to a grass line

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Answer:

From the graph

\(x=1\)

\(y=0\)

--------------

hope it helps...

have a great day

Answer: need brainliest

Step-by-step explanation:

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{-\frac{5}{2}})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{\left( -\frac{5}{2} \right)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}} \implies \cfrac{-8+\frac{5}{2}}{3+3}\implies \cfrac{~ \frac{ -16+5}{2 } ~}{6}\implies \cfrac{~ \frac{ -11}{ 2} ~}{6} \\\\\\ \cfrac{~ \frac{ -11}{ 2} ~}{\frac{6}{1}}\implies \cfrac{ -11}{ 2}\cdot \cfrac{1}{6}\implies -\cfrac{11}{12}\)

Dividing two polynomials may produce another polynomial only when the divisor has a lower degree than the dividend. Otherwise, it will generally result in a rational function.

No, dividing two polynomials may not result in another polynomial. It can produce a rational function.

A polynomial is an algebraic expression consisting of terms with non-negative integer exponents. When two polynomials are divided, the result is not always a polynomial.

If the degree of the polynomial being divided (dividend) is higher than the degree of the polynomial dividing (divisor), then the result can be a polynomial with a lower degree. However, if the degree of the divisor is equal to or greater than the degree of the dividend, the result will generally be a rational function, which is a ratio of two polynomials.

A rational function has the form P(x)/Q(x), where P(x) and Q(x) are polynomials and Q(x) is not equal to zero. The division can introduce terms with negative or fractional exponents, making the result a rational function rather than a polynomial.

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The likelihood of finding that the sample mean is between 59,050 and 60,950 miles can be determined by calculating the probability using the normal distribution with a sample size of 90, a population mean of 60,000 miles, and a population standard deviation of 4,000 miles.

To find out the probability of getting a sample mean between 59,050 and 60,950, a simulator is used to determine the tread life of tires mounted on light-duty trucks that follows a normal probability distribution.

Here, the population mean is 60,000 miles and the standard deviation is 4,000 miles. The given sample size is 90.

We can use the formula for standardizing the score. The standardized score for the lower limit of 59,050 is -2.78, and that of the upper limit of 60,950 is 2.78. Now, we need to find the probability of getting the mean value between -2.78 and 2.78.

We can use the standard normal distribution table to find the value, which is 0.9950 for z = 2.78 and 0.0050 for z = -2.78. Hence, the required probability is 0.9900.

Therefore, the likelihood of finding that the sample mean is between 59,050 and 60,950, for a sample size of 90 tires, is 0.9900.

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Answer:

plz explain ?

Step-by-step explanation:

The length of the equilateral triangle = 4.8m

Given that,

The area of the equilateral triangle = 10.2 m²

The formula for the area of an equilateral triangle = \(\sqrt{3} /4 a^{2}\)

Therefore,  

\(\sqrt{3} /4 a^{2}\) = 10.2

\(a^{2}\) = 10.2 × \(4/\sqrt{3}\)

\(a^{2}\) = 10.2 × 4/ 1.732

\(a\) = 4.85

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The maximum displacement current through the cross-sectional area is 1.77 A.

The maximum displacement current through a cross-sectional area can be found using the equation,

\(I =\ \in_0(d \phi_{E/dt} )\)

where I is the displacement current, ε₀ is the electric constant \(8.85 \times 10^{-12} F/m\), and \((d \phi_{E/dt} )\) is the rate of change of the electric flux through the cross-sectional area.

The electric flux \(\phi_E\) through a surface is given by:

\(\phi_E = \int E\times dA\)

where E is the electric field and dA is the differential area vector.

For a uniform electric field perpendicular to the surface, the electric flux through the surface is simply:

\(\phi_E = E\times A\)

where E is the magnitude of the electric field and A is the area of the surface.

In this case, the magnitude of the electric field is given by:

\(E = E_0\ Cos(\omega t)\)

The maximum value of E is \(E_0 =20 V/m\), which occurs when \(Cos(\omega t) =1\)

The maximum electric flux through the cross-sectional area \(A = 0.60 m^2\) is therefore:

\(\phi_E = E \times A = (20 V/m) \times (0.60 m^2) = 12 V\)

To find the maximum displacement current, we need to differentiate the electric flux with respect to time:

\(d\phi_{E/dt} = -E_0\ \omega Sin(\omega t)\)

The maximum value of sin(ωt) is 1, so the maximum value of \(d\phi_{E/dt}\) is:

\(d\phi_{E/dt} = -E_0\ \omega Sin(\omega t) = -20V/m \times (1.0 \times 10^7 s^{-1}) \times 1 \\d\phi_{E/dt} = -2.0 \times 10^8 V/s\)

Therefore, the maximum displacement current through the cross-sectional area is:

\(I =\ \in_0(d \phi_{E/dt} ) = (8.85 \times 10^{-12} F/m)\ \times (-2.0 \times 10^8 V/s) =-1.77A\\\)

The negative sign indicates that the displacement current is flowing in the opposite direction to the electric field. However, the magnitude of the displacement current is always positive.

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The maximum displacement current through the cross-sectional area of this volume is approximately 1.06 milliamperes (mA), or 1.06 × 10⁻³A.

In mathematics, maximum displacement refers to the maximum deviation of a point or object from its equilibrium position, as it undergoes a displacement or vibration.

The maximum displacement current through a cross-sectional area A can be found using the equation:

I = ε₀ A (dE/dt)

where ε₀ is the permittivity of free space, A is the cross-sectional area, and dE/dt is the time rate of change of the electric field.

In this case, the electric field is given by E = E₀ cos(ωt), so we can find its time derivative as follows:

dE/dt = -E₀ω sin(ωt)

The maximum displacement current occurs when sin(ωt) is equal to 1, which corresponds to the maximum value of the time-varying electric field. At this point, the displacement current is:

I = ε₀ A (dE/dt) = ε₀ A (-E₀ω)

Substituting the given values, we get:

I = (8.85 × 10⁻¹²C²/Nm²)(0.60 m²)(-20 V/m)(1.0 × 10⁷ s⁻¹)

I ≈ -1.06 × 10⁻³ A

Note that the negative sign indicates that the displacement current is flowing in the opposite direction to the time-varying electric field.

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Answer:

\(2 {x}^{2} + 5x - 3 = 0 \\ 2( {x}^{2} + \frac{5}{2} x - \frac{3}{2} ) = 0 \\ 2( {x}^{2} + \frac{5}{2} x + {( \frac{5}{4} )}^{2} ) - \frac{3}{2} - {( \frac{5}{4} )}^{2} ) = 0 \\ ( {(x + \frac{5}{4} )}^{2} = \frac{49}{16} \\ x + \frac{5}{4} = ± \frac{7}{4} \\ x = 0.5 \: \: and \: \: 3\)

Answer:

x= \(\frac{1}{2}\)     or     x= -3

Step-by-step explanation:

\(\boxed{x^{2} +kx=(x+\frac{k}{2})^{2} -(\frac{k}{2})^{2} }\)

First ensure that the coefficient of x² is 1.

x² +\(\frac{5}{2}\)x -\(\frac{3}{2}\)= 0

[x +(\(\frac{5}{2}\) ÷2)]² -(\(\frac{5}{2}\) ÷2)² -\(\frac{3}{2}\)= 0

(x +\(\frac{5}{4}\))² -(\(\frac{5}{4}\))² -\(\frac{3}{2}\)= 0

(x +\(\frac{5}{4}\))²- \(\frac{25}{16}\) -\(\frac{3}{2}\)= 0

(x +\(\frac{5}{4}\))² -\(\frac{49}{16}\)= 0

(x +\(\frac{5}{4}\))²= \(\frac{49}{16}\)

x +\(\frac{5}{4}\)= \(\sqrt{\frac{49}{16} }\)                (square root both sides)

x +\(\frac{5}{4}\)= ±\(\frac{7}{4}\)

x= -\(\frac{5}{4}\) +\(\frac{7}{4}\)       or       x= -\(\frac{5}{4}\) -\(\frac{7}{4}\)

x= \(\frac{1}{2}\)             or       x= -3

It be 12 cause from the smaller one 2*4 would = to 8 and 5*4 also = to 20 so 3*4 = to 12.