Answer:
f ’= 97.0 Hz
Explanation:
This is an exercise of the doppler effect use the frequency change due to the relative movement of the fort and the observer
in this case the source is the police cases that go to vs = 160 km / h
and the observer is vo = 120 km / h
the relationship of the doppler effect is
f ’= f₀ (v + v₀ / v- \(v_{s}\))
let's reduce the magnitude to the SI system
v_{s} = 160 km / h (1000 m / 1km) (1h / 3600s) = 44.44 m / s
v₀ = 120 km / h (1000m / 1km) (1h / 3600s) = 33.33 m / s
we substitute in the equation of the Doppler effect
f ‘= 100 (330+ 33.33 / 330-44.44)
f ’= 97.0 Hz
Sarah is studying the various processes involved with mass wasting. One of her classmates
brought in this photo. He said the arrows indicate a mass wasting process taking place.
Sarah said he was incorrect. Who do you agree with? Explain.
Sarah's classmate is incorrect. The photo indicates a small hill.
O Sarah's classmate is correct. This is an model of a slide and the hillside is quickly sliding out over the sidewalk.
O Sarah's classmate is correct. This is creep and the photo shows a hillside that is slowly moving over the
sidewalk.
O Sarah's classmate is incorrect. The photo shows the slight effect of gravity on the hillside but it is not a process
associated with mass wasting.
Answer:
Sarah's classmate is incorrect. The photo shows the slight effect of gravity on the hillside but it is not a process
associated with mass wasting.
Explanation:
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A __________ pollutant interacts with a part of the atmosphere and becomes a __________ pollutant.primary; secondarysecondary ; primary
A primary pollutant interacts with a part of the atmosphere and becomes a secondary pollutant.
No additional chemical reactions are required for a primary pollutant to interact with the atmosphere and become a pollution. Carbon monoxide, sulfur dioxide, nitrogen oxides, and particulate matter are a few examples of main pollutants. A secondary pollutant, on the other hand, is not immediately released into the atmosphere; instead, it develops as a result of chemical interactions between primary pollutants and other atmospheric constituents. Ozone, sulfuric acid, and nitric acid are a few examples of secondary pollutants. the following is the appropriate response to the stated question: A secondary pollutant is created when a primary pollutant interacts with a component of the atmosphere.
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Why can't we hold a glass with oily hands?!
Is it related to friction?!
Pls help me ill give brainliest
Answer:
c
Explanation:
a, b, and d are examples of moving forward
while c is moving backwards.
An 856 kg drag race car accelerates from rest to 105 km/h in .934s. What change in momentum does the force produce? Answer in units of kg • m/s
Part 2: what average force is exerted on the car? Answer in N
Hello!
Topic: Dinamic
Value to calculate: Force
First, we have to calculate the aceleration, for that, lets aplicate the formula:
\(\boxed{a=\frac{V-Vi}{t} }\)
How the final velocity is in km/h, we have to convert it on m/s, so:
m/s = km/h / 3,6
m/s = 105 / 3,6
m/s = 29,16
Then, lets replace formula according problem information:
\(a = \dfrac{29,16m/s-0m/s}{0,934s}\)
\(a =31,22\ m/s^{2}\)
Now, how we have the aceleration, lets applicate second law of newton for calculate the force produced:
\(\boxed{F=ma}\)
Replace and resolve it:
F = 856 kg * 31,22 m/s^2
F = 26724,32 kg * m/s^2
Then the force is of 26724,32 kg * m/s^2
But how we know an 1 kg * m/s^2 = 1 N
Then the average of the force is of 26724,32 N
(1) The change in momentum of race car is 89880 kg-km/h.
(2) The average force exerted on the car is of 96231.26 N.
Given data:
The mass of race car is, m = 856 kg.
The initial speed of car is, u = 0 km/h.
The final speed of car is, v = 105 km/h.
The time interval is, t = 0.934 s.
1)
The change in the impact due to average force is known as momentum change. The expression for the change in momentum is given as follows,
\(\Delta P = m(v-u)\)
Solving as,
\(\Delta P = 856 \times (105-0)\\\\\Delta P = 89880 \;\rm kg.km/h\)
Thus, we can conclude that the change in momentum of race car is 89880 kg-km/h.
2)
Now, use the concept of impulse-momentum which says that the impulse is equal to change in momentum. Which means,
\(I = \Delta P\)
And impulse is,
\(F \times t = \Delta P\\\\F = \dfrac{\Delta P}{t}\)
Solving as,
\(F = \dfrac{89880}{0.934}\\\\F = 96231.26 \;\rm N\)
Thus, we can conclude that the average force exerted on the car is of 96231.26 N.
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a commonly used piece of test equipment in a coaxial cable system that detects rf energy and displays the measurement in dbmv and/ dbuv is a ?
a signal level meter. A signal level meter is a commonly used piece of test equipment in a coaxial cable system that detects RF energy and displays the measurement in dBmV and/or dBuV.
a signal level meter. A signal level meter is a commonly used piece of test equipment in a coaxial cable system that detects RF energy and displays the measurement in dBmV and/or dBuV. a signal level meter is that it is used to measure the strength of a signal within a coaxial cable system. The signal level meter detects RF energy and converts it into a signal strength measurement in dBmV or dBuV, which are both units of power relative to a reference level. The measurement can be used to ensure that the signal is within an acceptable range and to troubleshoot any issues with the coaxial cable system.
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what do fast-twitch and slow-twitch muscle fibers share in common
Answer:
Explanation:Slow-twitch muscle fibers support long distance endurance activities like marathon running, while fast-twitch muscle fibers support quick, powerful movements such as sprinting or weightlifting.
what two things does the strength of gravity depend on?
Answer:
i found this i hope it helps
Explanation:
The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.
a sphere of diameter 6.0
cm is moulded into a thin wire of diameter 0.2 mm calculate the length of the wire in metres
Answer:
V1 = 4/3 pi R^3 = pi D^3 / 6 D = 2 R volume of sphere
V2 = pi r^2 L = pi d^2 L / 4 volume of wire
V2 / V1 = 1 = 3/2 d^2 L / D^3 since volumes are equal
L = 2/3 D^3 / d^2 = 2/3 * 6^3 / .02^2 = 360,00 cm = 3600 m
What does it mean to say that energy is conserved?
The total energy of a system remains constant in an isolated system, according to the law of conservation of energy.
Energy can be changed from one form to another, for as converting potential energy to kinetic energy, but the overall amount of energy in the domain never changes.
The kinetic energy that is lost as a body slows down when ascending against the pull of gravity was thought to be turned into potential energy, or stored energy, which was then converted back into kinetic energy when the body accelerated upon returning to Earth.
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A truck with a mass of 5000 kg and transfers 800,000 newtons(N) of force when it hits a wall. What was the acceleration of the truck?
a. 160 m/s
b. 160 km/hr
c. 160 m/s2
d. 160 miles/hr
An increase in speed or velocity can be described as:
Answer:
acceleration
rhymes with accelerator
Explanation:
the increase/decrease or the sudden change in speed and direction of object
5. A hiker accidentally drops an apple from a cliff. She observes that it hits the ground below after 2.4 s. If the apple accelerated at 10 m/s (gravity) while falling, how high was the
cliff?
cliff height -
וח
"Round your answer to the nearest thousandth if necessary,
Answer:
28.8m
Explanation:
Given parameters:
Time of fall = 2.4s
Acceleration due to gravity = 10m/s²
Unknown:
Height of cliff = ?
Solution:
To solve this problem, we use the expression:
H = ut + \(\frac{1}{2}\)gt²
u is the initial velocity
t is the time taken
g is the acceleration
t is the time
H = 0x2.4 + \(\frac{1}{2}\) x 10x2.4² = 28.8m
Why is it necessary to use oil in conjunction with the 100x lens but not the other objectives?
Because the refractive indexes of the immersion oil and the glass microscope slide are the same; the oil prevents the refraction of the incoming light rays.
An invisible space is present between the slide and the lens that contains air.
When the light rays fall on the slide and lens they might get refracted due to air present between them.
If the rays get refracted then the diameter of the objective lens will expand further.
So in order to prevent the refraction of light, it is very important to lubricate the surface of the lens because glass and oil have same refractive index and without oil the light rays refract from their original path.
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What do you think will happen when the balloon is moved closer to the wall?
A. Some positive charges in the wall will move towards the balloon B. Some negative charges in the wall will move towards the balloon C. Some positive charges in the wall will go onto the balloon D. Some negative charges on the balloon will go to the wall Neutral wall Negatively charged balloon
When the balloon is moved closer to the wall, there will be an electrostatic interaction between them. The balloon, being negatively charged, will repel the negative charges in the wall. This will cause some of the negative charges in the wall to move toward the balloon, resulting in option B.
As for option A, it is not likely that positive charges in the wall will move toward the balloon. This is because like charges repel each other and positive charges in the wall would be repelled by the positively charged balloon, which is not the case in this scenario.
Option C is also unlikely because positive charges in the wall would be attracted to the negatively charged balloon. However, the balloon cannot accept these charges as it is already negatively charged.
Option D is also incorrect as negative charges on the balloon would be repelled by the negative charges in the wall and would not be attracted to it.
Therefore, when the negatively charged balloon is moved closer to the neutral wall, some of the negative charges in the wall will move toward the balloon resulting in option B.
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When you stand on the merry-go-round in question 12, you hold a string from which
is suspended a rubber stopper of mass 45 g. You are 2.9 m from the centre of the
merry-go-round. You take 4.1 s to complete one revolution. What angle does the string make with the vertical?
The angle the string makes with the vertical is : 34.6°
Given data :
mass of rubber stopper ( m ) = 45 g
Radius ( r ) = 2.9 m
Time to complete one revolution ( T ) = 4.1 secs
Calculate the angle the string makes with the verticalapplying the formula below
Tan ∅ = \(\frac{mw^2r}{mg}\) --- ( 1 )
cancel out m from equation ( 1 )
Tan ∅ = \(\frac{w^2r}{g}\) ----- ( 2 )
where ; w = \(\frac{2\pi }{T}\)
Therefore equation ( 2 ) becomes
Tan ∅ = \(\frac{4\pi ^2r}{T^2g}\) --- ( 3 )
where ; r = 2.9 m, T = 4.1 secs , g = 9.8
Insert values into equation ( 3 )
Tan ∅ = 0.69
∅ = Tan ( 0.69 )
= 34.6°
Hence we can conclude that The angle the string makes with the vertical is : 34.6°.
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How much will an object weigh on the moon if it weighs 60 lbs on the earth?
Answer:
10lbs on the moon
Explanation:
Conservation of Energy:
A 60 kg glider is gliding through the air at a height of 300 meters with a speed of 40 m/s. The glider dives to a height of 200 meters. Determine the glider's new speed.
The new speed of the glider is 42.2 m/s.
The new speed of the glider can be calculated using the principle of the law of conservation of energy.
Note: Total energy of the glider before the dive = Total energy of the glider after the dive.
Formula:mv²/2+mgh = mV²/2 +mgH................ Equation 1Simplifying the equation above,
v²/2+gh = V²+gHmake V the subject of the equation.
V = √[(v²/2)+gh]-gH]............... Equation 2Where:V = New speed of the gliderv = initial speed of the gliderh = initial height of the gliderH = New height of the gliderg = acceleration due to gravity.From the question,
Given:v = 40 m/sh = 300 metersH = 200 metersg = 9.8 m/s²Substitute these values into equation 2.
V = √[(40²/2)+(9.8×300)-(9.8×200)]V = √(800+2940-1960)V = √1780V = 42.2 m/s.Hence, The new speed of the glider is 42.2 m/s.
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What new characteristic did John Dalton add to the model of the atom?
An atom is a round, solid mass.
An atom has a massive, positive center.
An atom is made up of smaller particles.
An atom can join with other kinds of atoms.
Answer: It is matter
Explanation:
Answer:
D
Explanation:
Trust me, I just did the test. :) :) :)
If a cannonball were launched horizontally (launch angle of 0) with a speed of 35m/s from a height of 15m, how long would the cannonball remain in the air?
Since the cannonball was launched horizontally (launch angle of 0) with a speed of 35m/s from a height of 15m, the time the cannonball remains in the air is for 1.75 s
What is a projectile?A projectile is an object that moves through air in a parabolic path
How long would the cannonball remain in the air?Since the cannonball is a projectile and was launched horizontally (launch angle of 0) with a speed of 35m/s from a height of 15m, using the equation of motion y' - y = ut - 1/2gt² we find the time it takes the cannonball to reach the ground. or remain in the air
Since y' - y = ut - 1/2gt² where
y' = ground level = 0 my = height cannonball is launched from = 15 m, u = initial vertical speed of cannonball = 0 m/s (since it is launched horizontally), t = time cannonball is in the air, g = acceleration due to gravity = 9.8 m/s²Substituting the values of the variables into the equation and solving for t, we have
y' - y = ut - 1/2gt²
0 m - 15 m = 0 m/s × t - 1/2 (9.8 m/s²)t²
- 15 m = 0 m/s - (4.9 m/s²)t²
- 15 m = - (4.9 m/s²)t²
t² = -15 m/- (4.9 m/s²)
t² = 3.061 s²
t = √3.061 s²
t = 1.75 s
So, the time the cannonball remains in the air is for 1.75 s
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Find the mass of the second object if the force of gravity between the two objects is 0.128N. The mass of the first object is 1300 kg and the 2 objects are 0.23 m apart.
Considering the Law of Universal Gravitation, the mass of the second object is 78090.19 kg.
The Law of Universal Gravitation is a law that states that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.
This law establishes that every particle attracts any other particle with a force directly proportional to the product of the masses of both and inversely proportional to the square of the distance that separates them:
\(F=G\frac{m1m2}{r^{2} }\)
where m1 and m2 are their masses; r the distance between them and G a universal constant that is called the constant of gravitation.
In this case, you know:
F= 0.128 NG=6.67× 10⁻¹¹ Nm²/kg²m1= 1300 kgm2= ?r= 0.23 mReplacing:
\(0.128 N=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{1300 kg m2}{(0.23 m)^{2} }\)
Solving:
\(0.128 N=1.639x10^{-6}\frac{N}{kg }x m2\)
m2=0.128 N ÷ 1.639×10⁻⁶ \(\frac{N}{kg}\)
m2=78090.19 kg
In summary, the mass of the second object is 78090.19 kg.
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https://brainly.com/question/858421?referrer=searchResultshttps://brainly.com/question/2347945?referrer=searchResultsWhat is one characteristic of the organization of the Periodic Table?
Atoms of elements with the same electron configuration are organized in columns.
Elements are organized in alphabetical order.
Atoms of elements with the same atomic number are organized in diagonals.
Atoms of elements with the same volume are organized in columns.
Answer:
Atoms of elements with the same electons in the outer most shell they are put in the same group on the periodic table
fffffrrrrreeeeee points you can have them!
Answer:
Thank you so much!
Explanation:
Answer:
joe
Explanation:
mama
for quarte wage-late, what is the phase shift between slow-light and fast-light
In terms of phase shift, slow-light and fast-light have a 180-degree phase difference.
This means that the crest of the slow-light wave is exactly opposite to the trough of the fast-light wave, and vice versa. The phase shift between these two types of light arises due to their different speeds of propagation through a medium. Slow-light is produced by a phase shift of the light wave in a medium that slows down its speed, while fast-light is created by a phase shift that speeds up the light wave. In the case of quarter wavelength, the phase shift between slow-light and fast-light is a half cycle, which means that they are exactly out of phase. This phenomenon has many important applications in areas such as fiber-optic communication, quantum computing, and sensing technologies.
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flood and landslides occur more in rainy season, why
Explanation:
When the water level in Neapl's over 6,000 rivers and creeks, flowing north to South, swells up during the monsoon season, they wreak havoc in the downstream communities of the plains .
Name three types of energy that exist in a large piece of charcoal on a grill in the sunlight. Explain why the charcoal has each type of energy.
Answer:
* thermal energy
potential energy,
potential energy
Explanation:
The ship has various types of energy,
* thermal energy. This energy is associated with the temperature of the coal, the hotter the greater its internal energy,
* potential energy this energy is stored in the constituent atoms within carbon
* potential energy. It is due to the configuration of the system, in this case the sun heats the coal
7. Why do you think the Redfield ratio continues to be used in oceanographic models, given it is known to be an over-simplification?
The Redfield ratio is the ratio of various chemical elements present in the average phytoplankton biomass. This defines the stoichiometry of photosynthesis and remineralization reactions.
The Redfield ratio is 106:16:1 across the ocean. Many models predict that a warmer ocean will hold less carbon because phytoplankton will become smaller as the ocean warms and bring less carbon to the seafloor as they die. Carbon nitrogen and phosphorus are the most important of these nutrients and CNP.
A ratio between 100:5:1 and 100:10:1 should be maintained to ensure maximum microbial activity in aerobic wastewater treatment. Many trace elements or micronutrients are also required. This is because a specific form of nitrogen found in the air nitrogen gas cannot be assimilated by most living organisms or require nitrogen in solid form.
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Basketball was originally created to keep what athletes in shape during the off season?
Your answer:
Soccer players
Baseball players
Track runners
Basketball players
Answer:
Basketball players
Explanation:
Basketball players
what are the salient features of a hydrodynamic entry region? a thermal entry region? are hydrodynamic and thermal entry lengths equivalent? if not, on what do the relative lengths depend?
Inviscid flow region and boundary regions are the salient features of a hydrodynamic entry region, a thermal entry region are hydrodynamic and thermal entry lengths equivalent.
A material's capacity to conduct heat is determined by its thermal conductivity. In contrast to materials with high thermal conductivity, low thermal conductivity materials transmit heat more slowly. For instance, insulating materials like Rockwool or Styrofoam are effective at retaining heat while metals often have high thermal conductivity and are very effective at transferring heat. In line with this, materials with high thermal conductivity are frequently used as heat sinks, whereas those with low thermal conductivity are employed as thermal insulation. Thermal resistance is the inverse of thermal conductivity. Working with numbers that are derivatives of thermal conductivity and that implicitly account for design-specific details like component dimensions is a typical practice in engineering. For instance, the amount of heat that travels through a plate of a certain area and thickness in a unit of time when the temperatures on its opposing faces differ by one kelvin is known as thermal conductance. Similar to how electrical conductivity and electrical conductance relate to one another, thermal conductivity and conductance do the same. The opposite of thermal conductivity is thermal resistance.
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n the basis of your results in parts a–c, which would appear larger: the image seen by the observer (with both lenses present) or the object itself (with the lenses removed)? Explain. e.The arrangement of lenses illustrated at the beginning of this problem can be used as a compound microscope. Lens 1, called the objective, is placed near the object of interest. Lens 2, known as the eyepiece, is placed so that one of its focal points coincides with the image produced by the objective. In order to improve the angular magnification of the microscope shown above, would you replace the eyepiece (lens 2) with another lens that has a smaller focal length or a larger focal length? Explain your reasoning.
In the given situation, where lenses are used in a compound microscope, the image seen by the observer with both lenses present would appear larger than the object itself without the lenses. This is due to the magnifying effect of the lenses.
In a compound microscope, the objective lens forms a magnified real image of the object. The eyepiece lens then further magnifies this real image, allowing the observer to view an enlarged virtual image. The combined effect of both lenses results in an overall magnification of the image.
Regarding the improvement of angular magnification, replacing the eyepiece (lens 2) with another lens that has a larger focal length would be beneficial. The angular magnification of a compound microscope is directly related to the focal length of the eyepiece. A larger focal length eyepiece would provide a higher magnification. This is because a larger focal length lens would bend light rays at a greater angle, resulting in a more magnified view for the observer.
Therefore, replacing the eyepiece with a lens having a larger focal length would enhance the angular magnification and improve the overall magnifying capabilities of the compound microscope.
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