A planet with a mass of 2.7 x 1022 kg is in a circular orbit around a star with a mass of 5.3 x 1032 kg. If the planet has an orbital radius of 4.8 x 10 m, what is its orbital period? (Universal gravitation constant, G = 6.67. 10-11 m kg 15-2) 23. A 0.05 kg softball was bounced on the sidewalk. The velocity change of the ball is from 30 m/s downward to 20 m/s upward. If the contact time with the sidewalk is 1.25 ms. a) What is momentum change of the ball? b) What is the magnitude of the average force exerted on the ball by the sidewalk? 24. A rocket explodes into four pieces of equal mass. Immediately after the explosion their velocities are (120 m/s, cast), (150 m/s, west), (80 m/s, south), and (150 m/s north). What was the velocity of the rocket's center of mass before the explosion? 0° Use Directions are 90° for east, 180° for south, 270° for west, and 360° for north. 270° 90° 180°
Answers
The orbital period of the planet is approximately 1.2411 x 10^6 seconds.
The orbital period of a planet can be calculated using the formula T = 2π√(r³/GM), where T is the orbital period, r is the orbital radius, G is the universal gravitation constant, and M is the mass of the central star. In this case, with a planet mass of 2.7 x 10^22 kg, a star mass of 5.3 x 10^32 kg, and an orbital radius of 4.8 x 10^10 m, the orbital period of the planet can be determined.
To calculate the orbital period, we can use Kepler's third law, which relates the orbital period to the radius and mass of the central object. The formula for orbital period, T, is given by T = 2π√(r³/GM), where r is the orbital radius, G is the universal gravitation constant (6.67 x 10^-11 m^3 kg^-1 s^-2), and M is the mass of the central star.
Plugging in the given values, we have T = 2π√((4.8 x 10^10)^3 / (6.67 x 10^-11) (5.3 x 10^32 + 2.7 x 10^22)).
Simplifying the expression inside the square root, we get T ≈ 2π√(1.3824 x 10^33 / 3.53671 x 10^22).
Further simplifying, T ≈ 2π√(3.9117 x 10^10), which gives T ≈ 2π(1.9778 x 10^5) ≈ 1.2411 x 10^6 seconds.
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Related Questions
What will happen to a satellite's orbit if its engines are turned on, causing it to
gain velocity tangential to its orbit?
O A. The height of its orbit will decrease.
OB. It will lose kinetic energy.
C. It will lose gravitational potential energy.
OD. The height of its orbit will increase.
Answers
If 100 joules of heat are added to 50. 0 grams of water at 25 degree Celsius, What would be the new temperature of this mass of water?
Answers
At a certain time a particle had a speed of 82 m/s in the positive x direction, and 9.3 s later its speed was 30 m/s in the opposite direction. What was the average acceleration of the particle during this 9.3 s interval?
Answers
The average acceleration of the particle with a speed of 82 m/s in the positive x direction and with a speed of 30 m/s during 9.3 s interval is -12 m/s².
Average acceleration is given as,
a = (v2 - v1) / t
where,
a = average acceleration
v1 = initial velocity
v2 = final velocity
t = time elapsed
Therefore, the formula to calculate the average acceleration of the particle is,
a = (v2 - v1) / t
Here,
v1 = 82 m/s
v2 = -30 m/s
t = 9.3 s
a = ?
Substitute the values in the formula to find the answer,
a = (-30 - 82) / 9.3
a = -112 / 9.3
a = -12 m/s²
The average acceleration of the particle during this 9.3 s interval is -12 m/s².
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You are planning measurements of vibrations of a flagpole in a strong wind flow. As the wake is also vibrating, you can measure those oscillations also in the flow with a hot wire anemometer (you can reference the coursework exercise on the hot wire anemometer). Make a sketch of the system with the major components needed to achieve a value of this dominant frequency from the flow. Describe the physical principle how a hot-wire is used to convert the flow signal into an electrical signal. The Strouhal-number of the pillar is Sr=0.2 and the diameter of the pillar is 20cm. What information and value can be gained from it, if you have measured the frequency to be f=20Hz?
Answers
By using a hot wire anemometer and measuring the dominant frequency of the flow, we can determine the velocity of the flow around the flagpole.
To measure the dominant frequency of vibrations in the flow around a flagpole using a hot wire anemometer, the following components are needed:
Flagpole: This is the main structure being investigated, with a known diameter of 20 cm and a Strouhal number (Sr) of 0.2.
Hot wire anemometer: The anemometer consists of a thin wire made of a temperature-sensitive material, such as platinum or tungsten. The wire is mounted in the flow and heated to a constant temperature using electrical current.
Signal conditioning circuitry: This circuitry is responsible for controlling the current passing through the wire and measuring the voltage across it.
Data acquisition system: This system records the electrical signal from the hot wire anemometer for further analysis.
The physical principle behind the hot wire anemometer is that as the flow velocity increases, it cools the heated wire, causing a change in its resistance. This change in resistance leads to a variation in the voltage across the wire, which is proportional to the flow velocity.
By measuring the dominant frequency of the flow using the hot wire anemometer, valuable information can be obtained.
In this case, if the measured frequency is f = 20 Hz, and the Strouhal number (Sr) is known to be 0.2, we can calculate the flow velocity (V) as follows:
V = Sr * f * d
where d is the diameter of the flagpole. Plugging in the values, we have:
V = 0.2 * 20 Hz * 0.2 m
V = 0.8 m/s
Therefore, the obtained information is that the flow velocity around the flagpole is 0.8 m/s.
In conclusion, by using a hot wire anemometer and measuring the dominant frequency of the flow, we can determine the velocity of the flow around the flagpole.
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the alpha particles emitted by radon–222 have an energy of 8.8 × 10–13 j. if a 200. g pb brick absorbs 1.0 × 1010 alpha particles from radon decay, what dose in rads will the brick absorb?
Answers
The brick will absorb 0.044 rads of radiation dose.
Radon decay alpha particles absorbed, dose?To calculate the dose in rads absorbed by the brick, we can use the following formula:
dose (in rads) = energy absorbed (in joules) / mass of absorbing material (in kg)
First, we need to calculate the energy absorbed by the brick. The energy of one alpha particle is given as 8.8 × \(10^-^1^3\)J. Therefore, the total energy absorbed by 1.0 × 1010 alpha particles is:
energy absorbed = (8.8 × \(10^-^1^3\)J/alpha particle) x (1.0 × \(10^1^0\) alpha particles) = 8.8 × \(10^-^3\) J
Now, we can calculate the dose in rads absorbed by the brick:
dose = (8.8 × \(10^-^3\) J) / (0.200 kg) = 0.044 rads
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Percent Yield Lab Report
Instructions: For this investigative phenomenon, you will need to determine the percent yield of magnesium oxide from the given reaction to determine if it is a useful commercial process. Record your data and calculations in the lab report below. You will submit your completed report.
Title:
Objective(s):
Hypothesis:
No hypothesis needed for this lab. Your theoretical yield calculation serves as your prediction for what you expect the lab to produce, and that will be determined later in the lab.
Procedure:
Access the virtual lab. Because this lab is virtual, summarize the steps used to collect your data. In addition, list and explain your controlled variables, independent variable, and dependent variable for this lab.
Materials:
Percent Yield Virtual Lab
Variables:
Remember, controlled variables are factors that remain the same throughout the experiment. An independent (test) variable changes so that the experimenter can see the effect on other variables. The dependent (outcome) variable will change in response to the test variable.
Controlled variables:
Independent Variable:
Dependent Variable:
Summary of Steps:
Data:
Type the data in the data table below. Don’t forget to record measurements with the correct number of significant figures. Hint: Using the same instrument, you should have the same number of digits to the right of the decimal.
Data
Trial 1
Trial 2
Mass of empty crucible with lid
26.698(g) 26.691(g)
Mass of Mg metal, crucible, and lid
27.040(g) 27.099(g)
Mass of MgO, crucible, and lid
27.198(g) 27.361(g)
Calculations:
Show your calculations for each of the following. Remember, calculations should follow rules for significant figures.
Write the balanced chemical equation for the reaction you are performing.
Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of Mg, crucible, and lid (row 2 in the chart) to find the mass of magnesium for each trial.
Trial 1:
Trial 2:
Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of MgO, crucible, and lid (row 3 in the chart) to find the mass of magnesium oxide for each trial. This is the actual yield of magnesium oxide for each trial.
Trial 1:
Trial 2:
Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
Trial 1:
Trial 2:
Determine the percent yield of MgO for your experiment for each trial.
Trial 1:
Trial 2:
Determine the average percent yield of MgO for the two trials.
Conclusion:
Write a conclusion statement that addresses the following questions:
Explain why the product had a higher mass than the reactant, and how this relates to conservation of matter.
What sources of error may have contributed to the percent yield not being 100 percent? (Think about things that may have led to inaccurate measurements or where mass of the product could have been lost if this experiment was conducted in a physical laboratory.)
How do you think the investigation can be explored further?
Post-Lab Reflection Questions
Answer the reflection questions using what you have learned from the lesson and your experimental data. It will be helpful to refer to your chemistry journal notes. Answer questions in complete sentences.
When conducting this experiment, some procedures call for heating the substance several times and recording the mass after each heating, continuing until the mass values are constant. Explain the purpose of this process and how it might reduce errors.
Your company currently uses a process with a similar cost of materials that has an average percent yield of 91 percent. If the average percent yield of this process is higher than that, this could save the company money. What is your recommendation to the company? Please support your recommendation using your data, calculations, and understanding of stoichiometry gathered from this lab.
Answers
Based on the data obtained from the reaction, the following conclusions can be made;
according to the law of conservation of mass, the mass of the product was higher than the reactant because of the mass of oxygen added during the combustion.the percent yield is less than 100% because of loss in mass of either reactants or products.the errors could have occurred during the weighing and transfer of reactants and productsrepeated measurements are required in order to improve accuracyWhat is the percent yield of the reaction?Equation of the reaction is given below:
2 Mg + O₂ ----> 2 MgOTrial 1
Mass of empty crucible with lid = 26.698 (g)
Mass of Mg metal, crucible, and lid = 27.040 (g)
Mass of MgO, crucible, and lid = 27.198 (g)
Mass of metal = 27.040 - 26.698 = 0.342
Mass of MgO = 27.198 - 26.698 = 0.500
Moles of Mg usedmoles of Mg = mass/molar mass
molar mass of Mg = 24 gmoles of Mg = 0.342/24 = 0.01425
Moles of MgO expectedBased on the equation of reaction;
moles of MgO expected = 0.01425
moles of MgO produced = mass/molar mass
molar mass of MgO = 40 g/molmoles of MgO produced = 0.500/40 = 0.0125
Percent yieldPercent yield = (moles of MgO produced/moles of MgO expected) * 100%Percentage yield = 0.0125/0.01425 * 100%
Percent yield of MgO = 87.7%
Trial 2
Mass of empty crucible with lid = 26.691 (g)
Mass of Mg metal, crucible, and lid = 27.099 (g)
Mass of MgO, crucible, and lid = 27.361 (g)
Mass of metal = 27.099 - 26.691 = 0.408
Mass of MgO = 27.361 - 26.691 = 0.670
Moles of Mg usedmoles of Mg = mass/molar mass
molar mass of Mg = 24 gmoles of Mg = 0.408/24 = 0.0170
Moles of MgO expectedBased on the equation of reaction;
moles of MgO expected = 0.0170
moles of MgO produced = mass/molar massmolar mass of MgO = 40 g/mol
moles of MgO produced = 0.670/40 = 0.01675
Percent yieldPercent yield = (moles of MgO produced/moles of MgO expected) * 100%Percent yield = 0.01675/0.0170 * 100%
Percent yield of MgO = 98.5%
Average percent yield = (87.7 + 98.5)% / 2
Average percent yield = 89.0%
Based on the data obtained from the reaction, the following conclusion can be made;
according to the law of conservation of mass, the mass of the product was higher than the reactant because of the mass of oxygen added during the combustion.the percent yield is less than 100% because of loss in mass of either reactants or products.the errors could have occurred during the weighing and transfer of reactants and productsrepeated measurements are required in order to improve accuracyLearn more about law of conservation of mass at: https://brainly.com/question/1824546
Answer:
90.3
Explanation:
Edge 2022
Can a constant magnetic field set a proton at rest into motion?
Answers
Answer:
No.
Explanation:
No, a constant magnetic field cannot set a proton at rest into motion. A constant magnetic field can only exert a force on a moving charged particle, causing it to experience a force perpendicular to both the magnetic field and the particle's velocity vector. If the proton is initially at rest, it will not experience any force from the magnetic field, and therefore will not be set into motion.
How many electrons are necessary to produce a charge of −1.2C ? Express your answer using two significant figures. Part B What is the mass of this many electrons? Express your answer using two significant figures
Answers
(a) The charge of -1.2C corresponds to approximately -7.5 × 10^19 electrons. (b) The mass of this many electrons is approximately 4.8 × 10^-17 kilograms.
(a) To determine the number of electrons necessary to produce a charge of -1.2C, we need to consider the elementary charge. The elementary charge represents the charge carried by a single electron, which is approximately -1.6 × 10^-19 coulombs. Dividing the given charge by the elementary charge, we find the number of electrons.
Number of electrons = -1.2C / (-1.6 × 10^-19C/electron) ≈ 7.5 × 10^19 electrons
(b) To calculate the mass of this many electrons, we utilize the mass of a single electron. The mass of an electron is approximately 9.1 × 10^-31 kilograms. Multiplying the number of electrons by the mass of a single electron, we obtain the mass.
Mass of electrons = (7.5 × 10^19 electrons) × (9.1 × 10^-31 kg/electron) ≈ 4.8 × 10^-17 kilograms
Therefore, the charge of -1.2C corresponds to approximately -7.5 × 10^19 electrons, and the mass of this many electrons is approximately 4.8 × 10^-17 kilograms.
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someone please help ASAP !!
Answers
Answer:0.147 seconds or secs
Explanation: This is because 1/6.80 is equal to 0.147 secs
Write a set of turtle instructions to draw an AND gate.
Answers
The turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
To draw an AND gate using turtle graphics, you can use the following set of instructions:
Set up the turtle:
a. Set the turtle's initial position.
b. Set the turtle's pen color and size.
Draw the first input line:
a. Move the turtle forward to the starting point of the line.
b. Draw a straight line segment to represent the first input.
Draw the second input line:
a. Move the turtle to the starting point of the second line.
b. Draw a straight line segment to represent the second input.
Draw the output line:
a. Move the turtle to the starting point of the output line.
b. Draw a straight line segment to represent the output.
Draw the logic gate shape:
a. Move the turtle to the starting point of the gate.
b. Draw a rectangle to represent the gate.
c. Add any necessary labels or symbols to indicate it as an AND gate.
Add connections between lines and gate:
a. Move the turtle to the intersection point of the first input line and the gate.
b. Draw a small line segment to connect the input line to the gate.
c. Repeat the above step for the second input line and the gate.
d. Draw a small line segment to connect the output line to the gate.
Repeat the above steps as necessary to draw multiple AND gates or any additional components.
Remember to adjust the turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.
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A bullet penetrates through a wooden block and it’s velocity is doubled. What is the ratio between the bullet’s initial kinetic energy and final kinetic energy?
Answers
Can I get a Brainly
25. The emission spectrum from a particular element shows three lines of wavelength 445 nm, 586 nm
and 667 nm respectively.
a) Calculate the energies of the emitted photons which has produced the three lines in the
spectrum in J and eV.
b) Draw the energy level diagram for an atom of the element which has produced these
photons and show the electron transitions which have given rise to the three spectral lines.
Answers
Answer:
a.
445 nm : 4.45 x 10^-19 J
445 nm : 2.78 eV
586 nm : 3.38 x 10^-19 J
586 nm : 2.11 eV
667 nm : 2.99 x 10^-19 J
667 nm : 1.87 eV
b.
E3 to E1 : ΔE = 1.87 eV
E3 to E2 : ΔE = 0.24 eV
E2 to E1 : ΔE = 0.24 eV
Explanation:
a) To calculate the energies of the emitted photons, we can use the formula:
E = hc/λ
where E is the energy of the photon in Joules, h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon in meters.
For the first line of wavelength 445 nm:
E = hc/λ = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(445 x 10^-9 m) = 4.45 x 10^-19 J
To convert this to electron volts (eV), we can use the conversion factor 1 eV = 1.602 x 10^-19 J:
E = 4.45 x 10^-19 J/(1.602 x 10^-19 J/eV) = 2.78 eV
For the second line of wavelength 586 nm:
E = hc/λ = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(586 x 10^-9 m) = 3.38 x 10^-19 J
E = 3.38 x 10^-19 J/(1.602 x 10^-19 J/eV) = 2.11 eV
For the third line of wavelength 667 nm:
E = hc/λ = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s)/(667 x 10^-9 m) = 2.99 x 10^-19 J
E = 2.99 x 10^-19 J/(1.602 x 10^-19 J/eV) = 1.87 eV
b) The energy level diagram for an atom of the element which has produced these photons can be drawn as follows:
markdown
E3
|
| ΔE = 1.87 eV
|
|
|
E2
|
| ΔE = 0.24 eV
|
|
|
E1
The electron transitions which have given rise to the three spectral lines are:
The transition from energy level E3 to E1, which produces the photon of wavelength 445 nm and energy 2.78 eV (ΔE = 1.87 eV).
The transition from energy level E3 to E2, which produces the photon of wavelength 586 nm and energy 2.11 eV (ΔE = 0.24 eV).
The transition from energy level E2 to E1, which produces the photon of wavelength 667 nm and energy 1.87 eV (ΔE = 0.24 eV).
Note that this energy level diagram is just one possible arrangement of energy levels that could produce the observed spectral lines. There may be other possible arrangements of energy levels that could also explain the observed lines.
ChatGPT
Newton's first law of motion is the law of inertia
Answers
Answer:
this statement is true because I looked it up
the mass of piece of granite is 15.6g when it is suspended can a mass of 5.5g of water is displaced find the dencity of granite
Answers
Answer:
2836.36 kg/m³
Explanation:
Applying,
Densty of granite(D')/Density of water(D) = weight of granite(W')/weight of water displaced(W)
D'/D = W'/W................... Equation 1
Make D' the subject of the equation
D' = W'D/W............... Equation 2.
From the question,
Given: W' = mg = 9.8(15.6/1000) = 0.15288 N, W = 9.8(5.5/1000) = 0.0539 N, Constant: D = 1000 kg/m³
Substitute these values into equation 2
D' = 1000(0.15288)/0.0539
D' = 2836.36 kg/m³
pls somebody help me quick
Answers
Answer:
greater than
Explanation:
A bowling ball is bigger than a golf ball and greater than means bigger.
6. For a cell to produce a current, the
electrodes of the cell must.
a. have a potential difference.
b. be in a liquid.
c. be at two different temperatures.
d. be flattened,
Answers
Answer:
for a cell to produce a current the cell electrodes of the cell must have a potential difference option A is the correct answer
Current flows in a circuit having a cell only when the electrodes of the cell have finite potential difference.
Bert is playing on his school's basketball team and one of the players on the other team continues to push him off balance when the referee isn't looking. Bert is getting frustrated as the other player is beating him to the ball almost every time by using this illegal tactic. How should Bert handle this situation in a responsible manner?
Refuse to shake hands with the other team at the end of the game and call them all dirty players
Take a flop and fall down purposely the next time the player does it to get the ref's attention
Talk to his team captain and ask him to alert the referee to keep a better eye on the player
When the ref isn't looking push the other player off balance when he has the opportunity
Answers
Answer:
Talk to his team captain and ask him to alert the referee to keep a better eye on the player.
Answer:
C - talk to coach and ask to alert the ref
Explanation:
I took the test
An archer performs 100 joules of work in pulling back the string of a bow. What will be the initial speed of a 0. 5-kilogram arrow when it is fired from the bow?.
Answers
The initial speed of a 0.5 kg arrow when it is fired from the bow is equal to 20 m/s.
What is kinetic energy?Kinetic energy can be described as the energy carried by a moving body due to its motion. Work should be done on the object in order to bring the change in the kinetic energy of a moving object.
The kinetic energy of an object can be determined from the mathematical formula:
K.E. = ½ mv²
Where ‘v’ is the object's velocity and ‘m’ is the object's mass.
Given, the mass of the arrow, m = 0.5 Kg
The work done = kinetic energy = 100 J
The kinetic energy = (1/2)× m ×(v)²
100 = (1/2)× 0.5 ×(v)²
v² = 400
v = 20 m/s
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You go to a dog park that is shaped like a rectangle. you walk into the park at the entrance in the northwest corner. the park is called the land of 133 puppies! that's a very specific name. you only see 16 puppies at the entrance. you walk 33.8 meters to the east to go to the puppy water fountain to see if you can find the other puppies. it is 3 o'clock in the afternoon and there are 21 puppies here. the fountain has a circumference of 6.71 meters. interesting. the one with with the black and white spots plays with a golf ball rolling down a ramp. you leave and walk 41.1 meters south to the puppy playground. there are 21 puppies running around and playing. there is a statue of a doggo that is 10.47 meters tall. wow. you hear excited yips to the west, so you walk 33.8 meters back to the western side of the park to find a puppy food truck! here, there are 98 puppies! the park is aptly named.
how much shorter would it have been to have gone straight to the puppy food truck from the entrance instead of the route you chose? (distance minus displacement)
Answers
The difference between the distance traveled and the displacement from the entrance to the puppy food truck is 108.7 meters.
How much shorter was the direct route to the puppy food truck from the entrance?To calculate the difference between the distance traveled and the displacement, we need to compare the total distance covered along the chosen route with the straight-line distance from the entrance to the puppy food truck. The distance traveled is the sum of the distances traveled in each direction, while the displacement is the straight-line distance between the starting and ending points.
By using the given information about the distances walked in each direction, we can determine the total distance covered. Subtracting the displacement from the distance traveled gives us the difference, which represents how much shorter the direct route would have been.
This calculation helps quantify the efficiency of the chosen route and provides an understanding of the potential time and effort saved by taking a more direct path.
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the speed of light in a material 1.81 x 10^8 m/s what is the absolute index of fraction of the material
Answers
The speed of light in a material 1.81 x 10^8 m/s; thus the absolute index of refraction of the material is 1.11.
The absolute index of refraction, also known as the refractive index, is the ratio of the speed of light in a vacuum to the speed of light in a material. In this case, the speed of light in the material is given as 1.81 x 10^8 m/s. The speed of light in a vacuum is always constant and is equal to 3 x 10^8 m/s. Therefore, the absolute index of refraction can be calculated as follows:
Absolute index of refraction = speed of light in a vacuum / speed of light in the material
Absolute index of refraction = 3 x 10^8 m/s / 1.81 x 10^8 m/s
Absolute index of refraction = 1.11
Therefore, the absolute index of refraction of the material is 1.11.
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calculate the frequency of a wave using an equation
Answers
Answer:
1. f=1T. where: f is the frequency of the wave in hertz. T is the period of the wave in seconds.
2. f=vλ where: f is the frequency of the wave in hertz. v is the velocity of the wave in meters per second. λ is the wavelength of the wave in meters
3. f=cλ
Explanation:
A DSB-SC modulated signal is transmitted over a noisy channel, with power spectral density of white noise being 0.5x10 watts/Hz. The message bandwidth is 4 kHz and the carrier frequency is 200 kHz. Assuming that average power of modulated wave is 10 Watts, determine output signal-to-noise ratio of the receiver.
Answers
The average power of the modulated wave is 10 Watts and the noise power is 0.5 x 10 Watts/Hz x 4 kHz = 2 Watts. Therefore, the SNR is 10/2 = 5, in decibels, 10 log (10/2) = 7.9 dB.
The signal-to-noise ratio (SNR) of the receiver output is the ratio of the average power of the modulated wave to the noise power.
The SNR is a measure of the power of the signal relative to the noise. A higher SNR means that the signal is more powerful relative to the noise, which means that there is a higher chance of the signal being accurately decoded by the receiver.
In this case, the output SNR of the receiver is 7.9 dB, which is a relatively low value, but still indicates that the signal has a higher power than the noise and is more likely to be decoded correctly.
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Complete question :-
A DSB-SC modulated signal is transmitted over a noisy channel, with spectral density has an power value of white noise being 0.5x10 watts/Hz. The message bandwidth is 4 kHz and the carrier frequency is 200 kHz. Assuming that average power of modulated wave is 10 Watts, determine output signal-to-noise ratio of the receiver.
at what energy do approaching protons interact with the individual nucleons instead of the mean field of the nucleus
Answers
The energy at which approaching protons interact with the individual nucleons instead of the mean field of the nucleus is called the delta resonance excitation energy.
The pion production threshold attraction speed is nearly 140-200 MeV for light nuclei like Helium, and Hydrogen and increases up to 500 MeV. The energy at which the proton center is the collective effect of nucleons in the nucleus.
The energy is in a higher energy state which further causes the formation of delta resonance relevant in many parts of electrons. This resonance further emits a pion, leading to the interaction between protons and nucleons than the nucleus.
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Use DeMorgan's Theorem, as well as any other applicable rules of Boolean algebra, to simplify the following expression so there are no more complementation bars extending over multiple variables: \[ \
Answers
The expression to be simplified is, A + BC + ABCD. Using De Morgan's theorem, we can convert complementation bars extending over multiple variables into complementation bars over single variables. The De Morgan's theorem states that the complement of a product is equal to the sum of complements. De Morgan's Theorem:
1. (AB) = A + B2. (A + B) = A B The steps to simplify the given expression using De Morgan's theorem are as follows: A + BC + ABCD = A + (BC + ABCD) = A + (BC). (ABCD) = A + (B + C) (A + B + C + D) = A + AB + AC + BC + BD = A + AC + BC + BD.
Hence, the simplified expression is A + AC + BC + BD. Thus, using DeMorgan's Theorem and other applicable rules of Boolean algebra, the given expression is simplified to A + AC + BC + BD.
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A planet of constant mass orbits the sun in an elliptical orbit. Neglecting any friction effects, what happens to the planet's rotational kinetic energy about the sun's center?
A) It decreases continually.
B) It increases continually.
C) It remains constant.
D) It increases when the planet approaches the sun, and decreases when it moves farther away.
E) It decreases when the planet approaches the sun, and increases when it moves farther away.
Answers
The correct answer to the question is option D (It increases when the planet approaches the sun, and decreases when it moves farther away).
Rotational kinetic energy (K) of an object is given by:
K = 1/2 Iω²
where, I = Moment of inertiaω = Angular velocity of the object.
A planet orbits the Sun in an elliptical orbit. The gravitational force acting between the Sun and the planet is known as centripetal force. This force is responsible for keeping the planet in a circular orbit around the Sun. Neglecting frictional effects, the total mechanical energy of the planet in an elliptical orbit remains constant.
However, the kinetic energy (K) and potential energy (U) vary with distance.
Let's say that when the planet is closest to the sun, its distance is rmin. Similarly, when the planet is farthest away from the Sun, its distance is rmax. At the closest distance to the Sun (r = rmin), the kinetic energy of the planet is minimum. This is because the planet moves the slowest at this point. When the planet moves away from the Sun, it moves faster and its kinetic energy increases.
The kinetic energy is maximum when the planet is farthest away from the Sun (r = rmax). As the planet continues to move away from the Sun, its speed decreases and so does its kinetic energy.
Therefore, the kinetic energy of the planet increases when the planet approaches the Sun and decreases when it moves farther away from the Sun.
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PLEASE ASAP! I SENT A PHOTO CHECK AND TELL!
Answers
Answer:
Answer B is the correct answer: "Motion of one projectile as seen from the other is a straight line."
Explanation:
Let's write the equations of motion for each projectile, using that projectile \(a\) is launched with velocity \(a\) which has components associated with the angle of launching, given in x and y coordinates as: \(a_x\,\,and\,\,a_y\).
Similarly, assume that projectile b is launched with velocity \(b\) with components due to the launching angle = \(b_x\,\,and \,\,b_y\)
then the equations of motion for the two projectiles launched at the same time (t) from the same spot (position that we assume to be at the origin of coordinates to simplify formulas) are:
\(x_a=a_x\,t\\y_a= a_y\,t-\frac{1}{2} g\,t^2\\and\\x_b=b_x\,t\\y_b= b_y\,t-\frac{1}{2} g\,t^2\)
therefore, from the frame of reference of projectile "b", the x and y position of projectile "\(a\)" would be:
\(x_{a\,b}= x_a-x_b= a_x\,t-b_x\,t=(a_x-b_x)\,t\) which is linear in "t"
\(y_{a\,\,b}=y_a-y_b= a_y\,t-\frac{1}{2} g\,t^2-\left[ b_y\,t-\frac{1}{2} g\,t^2\right]=(a_y-b_y)\,t\) which is also linear in t.
Therefore the motion of one projectile with reference to the other is a straight line (answer B)
Notice as well that this two projectiles cannot collide because they have been launched together, and supposedly at different speeds and angles. The only way that they can share the same x-coordinate and the same y-coordinate at the same time "t" is if their velocity components are equal, which is not what we are told.
\(x_a=x_b\\a_x\,t= b_x\,t\\and\\y_a= y_b\\a_y\,t-\frac{1}{2} g\,t^2= b_y\,t-\frac{1}{2} g\,t^2\\a_y\,t=b_y\,t\\a_y=b_y\)
Which of the following phrases best describes a physical model?
A. An exact copy of an object, system, or process
B. A chemical formula
C. A graph or equation
D. A representation of an object, system, or process
Answers
Answer:D a representation of an object system or process
Explanation:
The phrase that best describes a physical model is an exact copy of an object, system or process.
What is meant by a physical model ?A physical model is defined as a model of any object which can be moved or can be held.
Here,
The physical model can be defined as a larger or smaller copy of the object which is to be represented.
The physical models are made for the perfect examination and study of the the physical characteristics of the particular object.
From the above given data,
There is only one example that can be considered as a physical model of a system.
Chemical formula, graph or equation are just a graphical or written representation of a system.
We know that the physical model must be a similar copy of the system,
An exact copy of an object, system or process is an example of physical model.
Hence,
The phrase that best describes a physical model is an exact copy of an object, system or process.
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Please help u guys acellus sucks
Answers
Answer:
6.0cm
Explanation:
Given
focal length = 15.0cm
object distance = 10.0cm
Required
Image distance v
Using the formula
1/f = 1/u + 1/v
1/15 = 1/10+1/v
1/v = 1/15 + 1/10
1/v = 2+3/30
1/v = 5/30
v = 30/5
v = 6.0cm
Hence the image distance is 6.0cm
Answer:
6.0 (2 sig figs)
Explanation:
Is it General Physics? I had it and passed the Final Exam with an A in the beginning of July!
Which gloves are safe for working with electricity?
Answers
Nitrile Gloves gloves are safe for working with electricity.
What are Nitrile Gloves?A synthetic rubber made from acrylonitrile and butadiene, nitrile rubber is also referred to as nitrile butadiene rubber, NBR, Buna-N, and acrylonitrile butadiene rubber. Trade names like Perbunan, Nipol, Krynac, and Europrene are also used. Being resistant to chemicals, fuel, and oil makes this rubber special.
What is a nitrile glove used for?These gloves are therefore the best option for anyone who must handle potentially dangerous and caustic chemicals. Being incredibly puncture-resistant and removing the possibility of latex allergic reactions, they are also ideal for the majority of medical settings.
Is nitrile safe on skin?The robust barrier of protection provided by nitrile gloves can help keep the wearer safe from chemicals, acids, and oils. Latex-free: Nitrile gloves are excellent for anyone with sensitive skin or a latex allergy because they are latex-free, unlike natural rubber gloves.
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How does radiation transfer thermal energy from the Sun to Earth?
Answers
Answer:
Sample Response: Radiation transfers thermal energy from the Sun to Earth by electromagnetic waves. Electromagnetic waves can transfer energy with or without matter.Explanation:
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Thermal energy transfers from the Sun to Earth by the process named radiation.
What is radiation heat transfer?The energy that matter emits as photons or electromagnetic waves is known as radiation heat transfer. Even when a medium is present in between, radiation can still be significant. The transfer of heat between a living thing and its environment serves as one example.
All objects emit photons, which are forms of energy. The smallest distinct amount of electromagnetic radiation is termed a photon (i.e., one quantum of electromagnetic energy is called a photon). Photons have no mass and move randomly in terms of direction, phase, and frequency.
The heat generated by the chemical reactions occurring in the sun radiates outward and into space rather than remaining close to the sun. Even though the earth is millions of kilometers from the sun, the reactions release so much energy that some of it can still reach the planet. The majority of the sun's rays are in the ultraviolet spectrum, and these rays are what typically go from the sun to the earth as heat energy. Thermal radiation is the term used to describe this type of heat transfer.
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