A plane flying at a steady speed of 100 m/s accelerates to 150 m/s in 10 seconds. What is the plane’s acceleration?

Answers

Answer 1

A plane flying initially at 100 m/s uses an acceleration of 5 m/s² to reach a velocity of 150 m/s in 10 seconds.

What is acceleration?

Acceleration is the change in velocity over time.

A plane is flying initially at 100 m/s (u) and it accelerates to 150 m/s (v) in 10 s (t). We can calculate its acceleration using the following expression.

a = v - u / t = (150 m/s - 100 m/s) / 10 s = 5 m/s²

A plane flying initially at 100 m/s uses an acceleration of 5 m/s² to reach a velocity of 150 m/s in 10 seconds.

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Related Questions

answer the question in the picture

answer the question in the picture

Answers

The option that represents what the magnetic field look like above the North pole is an arrow that decreases as we go up and points up (E)

How to explain the information

The magnetic field lines of a magnet point away from the north pole and towards the south pole. The field lines are strongest at the poles and weaken as you move away from the poles.

So, the arrow that represents the magnetic field above the north pole will be pointing up, but it will become smaller and smaller as you go up.

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A single-phase 60-Hz overhead power line is symmetrically supported on a horizontal cross arm. Spacing between the centers of the conductors acing between the centers of the conductors (say, a and b) is 2.5 m. A telephone line is also symmetrically supported on a horizontal cross arm 1.8 m directly below the power line. Spacing between the centers of these conductors (say, c and d) is 1.0 m.

4 x 10^7 ln âDad. Dln/Dnk. Dtet

where, for example, Dud denotes the distance in meters between conductors a and.

a. Hence, compute the mutual inductance per kilometer between the power line and the telephone line.
b. Find the GO-Hz voltage per kilometer induced in the telephone line when the power line carries 150 A.

Answers

Complete question is;

A single-phase 60-Hz overhead power line is symmetrically supported on a horizontal cross arm. Spacing between the centers of the conductors acing between the centers of the conductors (say, a and b) is 2.5 m. A telephone line is also symmetrically supported on a horizontal cross arm 1.8 m directly below the power line. Spacing between the centers of these conductors (say, c and d) is 1.0 m.

The mutual inductance per unit length between circuit a-b and circuit c-d is given as 4 x 10^(-7) ln √((D_ad × D_bc)/(D_ac × D_bd)) H/m

where, for example, D_ad denotes the distance in meters between conductors a and d.

a. Hence, compute the mutual inductance per kilometer between the power line and the telephone line.

b. Find the 60-Hz voltage per kilometer induced in the telephone line when the power line carries 150 A

Answer:

A) M = 1.01 × 10^(-4) H/km

B) v_cd = 5.712 V/km

Explanation:

A) From the distances given in the question, we can deduce that;

D_ac = √(((2.5/2) - (1/2))² + 1.8²)

D_ac = 1.95 m

Also;

D_ad = √(((2.5/2) + (1/2))² + 1.8²)

D_ad = 2.51 m

I_a and I_b are put of phase by 180°. Thus, due to a and b, the flux linkages to c and d is given as;

φ_cd = 4 x 10^(-7)I_a( ln (2.51/1.95))

Mutual inductance per km is given as;

M = φ_cd/I_a

Thus;

M = 4 x 10^(-7)( ln (2.51/1.95))

M = 1.01 × 10^(-7) H/m

Per km;

M = 1.01 × 10^(-7) × 1000

M = 1.01 × 10^(-4) H/km

B) voltage per km is gotten by;

v_cd = ωMI

Now, ω = 2πf = 2π × 60 = 377 rad/s

Thus;

v_cd = 377 × 1.01 × 10^(-4) × 150

v_cd = 5.712 V/km

The radius of the earth is 6.4 x 10^6 m . Calculate the angular and linear velocity of a participle at the earth's surface.

Answers

Answer: the angular velocity of a particle at the Earth's surface is approximately 7.27 x 10^-5 rad/s, and the linear velocity of the particle is approximately 464.1 m/s.

Explanation:

F = kx
k = ?
Select one:
a. F/x
b .x/F
c. F + x
d. F − x

Answers

Answer:

\(F = kx \\ k = \frac{F }{x} \)

so the answer is a

A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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A cylindrical water tank has a height of 20cm and a radius of 14cm. If it is filled to 2/5 of its capacity, calculate.

I. Quantity of water in the tank

II. Quantity of water left to fill the tank to its capacity.

Answers

Answer:

4.926 L Y 7.389 L

Explanation:

first you calculate the tank volume

V = π\((14 cm)^{2}\)(10 cm = \(12315 cm^{3}\)

then you convert to liters

\(12315 cm^{3}\) = 12.315 l

then you calculate the liters of water

2/5(12.35 l) = 4.926 l

finally we calculate the amount without water

12.315 l - 4.926 l = 7.389 l

HERE IS MORE INFORMATION ON THE SUBJECT. THEY REMOVED THE

ENGLISH SITE BUT YOU CAN USE TRANSLATOR

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7. What is the velocity of an object with a distance of 90m south and a time of
5s?

Answers

Answer:

Explanation:

v= s/t

V =90m/5s

V = 8m/s

Physics like really need help please

Physics like really need help please

Answers

Answer:

Explanation:

Consider first case with incline:

It is frictionless so the only force on mass is gravity, g.

The force has two components: one that is along the incline direction and another perpendicular to the incline.

The perpendicular component does no work as it is perpendicular to the direction of motion.

The incline component of gravity = g*sinθ

=10*sin30deg; using 10m/s^2 for g

Length of incline = 5/sinθ = 5/sin30deg

Work done = force * distance

= mass * acceleration * distance

= 5 * 10*sin30deg * 5/sin30deg

= 250J

Mass starts from rest so its initial speed=0

Using the kinematic equation: final speed^2 = initial speed^2 + 2*acceleration*distance

Final speed^2 = 0 + 2*(10*sin30deg)*(5/sin30deg)

= 2*10*5

=100

Final speed = 10m/s

Now for the second case of vertical drop:

Work done by gravity = mass * gravity * height

= 5 * 10 * 5

= 250J

Using conservation of energy, Final kinetic energy = Work done by gravity

1/2 * Mass * Final speed^2 = 250

Final speed^2 = 2 * 250 / 5 = 100

Final speed = 10m/s

In both scenarios, the work done by gravity and the mass' final speed are the same.

On the image at right, the two magnets are the same. Which paper clip would be harder to remove?

Answers

Answer:B

Explanation: The book is thinner making magnets attraction stronger, making the paper clip harder to move

In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

A spring is compressed 1.3 cm. How far must you compress a spring with twice the spring constant to store the same amount of energy?

Answers

Answer:

Explanation:

The energy stored is E = 1/2 kx^2.

E1 = E2

1/2 k(1.3)^2 = 1/2 (2k)x^2

x^2 = 1/2 (1.3)^2

x = 1.3/sqrt(2) cm

x =0.919 cm

rate me thanks

Compression in a spring with twice the spring constant to store the same amount of energy is 0.919 cm

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Given spring is compressed 1.3 cm. Compression in a spring with twice the spring constant to store the same amount of energy is,

The energy stored is E = 1/2 kx².

E1 = E2

1/2 k(1.3)² = 1/2 (2k)x²

x^2 = 1/2 (1.3)²

x = 1.3/√2 cm

x = 0.919 cm

Compression in a spring with twice the spring constant to store the same amount of energy is 0.919 cm.

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A hiker with a skin surface area of 1.3 m² is protected from hypothermia (the cold) by a close-fitting sleeping bag 30 mm thick. If her skin temperature is 34°C and she can safely lose 85 W of heat by conduction through the sleeping bag, what is the lowest outside temperature for which the sleeping bag provides adequate protection? Ignore heat losses due to convection or radiation. Coefficient of thermal conductivity of the sleeping bag = 0.019 Wm¹¹°C-¹ ​

Answers

Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.

Explanation:

To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.

The rate of heat loss through conduction can be calculated using the formula:

Q = (k * A * ΔT) / d

Where:

Q is the rate of heat transfer (in Watts)

k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)

A is the surface area (1.3 m² in this case)

ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)

d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)

Let's plug in the values:

Q = (0.019 * 1.3 * ΔT) / (30 / 1000)

The hiker can safely lose 85 W of heat, so we can set up the equation:

85 = (0.019 * 1.3 * ΔT) / (30 / 1000)

To solve for ΔT, we can rearrange the equation:

ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)

ΔT ≈ 89.61°C

A point object moves from point A to point B along a circular path with a radius. What is the size of the angle ?

Answers

The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

How to solve size of an angle?

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

A8 kg ball is held at postam A before being rolled down the ramp below. Asume no energy is lost due to
Position
A
A-5m)
Position
B
(x-2m)
Position
C
As
h-5m
Kinetic Energy
B
h-2.5 m
Gravitational Potential Energy
C
h-0m
Total Energy

A8 kg ball is held at postam A before being rolled down the ramp below. Asume no energy is lost due toPositionAA-5m)PositionB(x-2m)PositionCAsh-5mKinetic

Answers

At position A, the ball has only potential energy due to its position above the ground.

The potential energy of the ball at position A is:

PE = mgh

where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the ball above the ground.

PE(A) = 8 kg * 9.8 m/s^2 * 5 m

PE(A) = 392 J

At position B, the ball has both kinetic and potential energy.

The potential energy of the ball at position B is:

PE = mgh

where m is the mass of the ball, g is the acceleration due to gravity, and h is the height of the ball above the ground.

PE(B) = 8 kg * 9.8 m/s^2 * 2.5 m

PE(B) = 196 J

The kinetic energy of the ball at position B is:

KE = (1/2)mv^2

where m is the mass of the ball and v is the velocity of the ball.

Since the ball is rolling down the ramp, we can use the conservation of energy principle to find the velocity of the ball at position B.

The total energy of the ball at position A is:

E(A) = PE(A)

E(A) = 392 J

The total energy of the ball at position B is:

E(B) = PE(B) + KE(B)

E(B) = 196 J + (1/2)(8 kg)v^2

E(B) = 196 J + 4v^2

Since energy is conserved, we have:

E(A) = E(B)

392 J = 196 J + 4v^2

196 J = 4v^2

v^2 = 49 m^2/s^2

v = 7 m/s

The kinetic energy of the ball at position B is:

KE(B) = (1/2)mv^2

KE(B) = (1/2)(8 kg)(7 m/s)^2

KE(B) = 196 J

At position C, the ball has only kinetic energy.

The potential energy of the ball at position C is zero since the ball is at ground level.

The kinetic energy of the ball at position C is:

KE(C) = (1/2)mv^2

KE(C

A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?

Answers

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

Mr. Dunn drives 64.8km from work at a speed of 48km/h. Mrs. Dunn drives 81.2km from work
at a speed of 58km/h. They both leave work at the same time. Show complete working to secure
full credits. [4]
i. Who arrives home first?
ii. How many minutes later is it before the second person gets home?
iii. A Coyote is chasing its meal (the Road Runner). Unfortunately, the Coyote has difficulty
adjusting to the Road Runner’s speed but we have a good idea of what it is.
plz help me i will mark you as brainliest

Answers

Answer:

i) Mr. Dunn arrives to home first.

ii) 3 min

Explanation:

i. To find who arrives first to home you calculate the time, by using the following formula:

\(t=\frac{x}{v}\)

x: distance

v: velocity

Mr. Dunn:

\(t=\frac{64.8km}{48km/h}=1.35h\)

Mrs. Dunn:

\(t=\frac{81.2km}{58km/h}=1.4h\)

Hence, Mr. Dunn arrives to home first.

ii. To calculate the difference in minutes, you convert hours to minutes:

\(1.35h*\frac{60min}{1h}=81min\\\\1.40h*\frac{60min}{1h}=84min\\\\\Delta\ t=(84-81)min=3min\)

the difference between the times is 3min

(i) Mr. Dunn takes less time so he arrives at home first.

(ii) The second person arrives 3 min late.

Time taken to arrive home:

(i) We have to calculate the time taken to reach home by Mr. Dunn and Mrs. Dunn.

t = x/v

where x is the distance

and v is the velocity

Time taken by Mr. Dunn:

distance x = 64.8 km

speed v  = 48 km/h

t = 64.8 / 48

t = 1.35 h

Time taken by Mrs. Dunn:

distance x = 81.2 km

speed v  = 58 km/h

t' = 81.2 / 58

t' = 1.4 h

Hence, Mr. Dunn arrives at home first.

(ii) To calculate the difference in minutes, you convert hours to minutes:

The time taken by Mr. Dunn in minutes is:

t = 1.35×60 = 81 minutes

The time taken by Mrs. Dunn in minutes is:

t' = 1.4×60 = 84 minutes

the difference between the times is 3min

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Express 6revolutions to radians

Answers

Answer:

About 37.70 radians.

Explanation:

1 revolution = 2\(\pi\) radians

∴ 6 revolutions = (6)(2\(\pi\) radians)

6 revolutions = 37.6991 or ≈ 37.70 radians

Calculate the young modulus in a cantilever depression method. The length is 1m which is suspended by a load of 150g. The depression is found to be 4cm. The thickness of the beam is 5mm and the breath is 3cm.(g=9.8)

Answers

The young's modulus in a cantilever will be 3.92 x 10¹⁰ N/m².

What is young's modulus?

Young's modulus (E) is a material property that indicates how easily it can stretch and deform and is defined as the ratio of tensile stress () to tensile strain (). Where stress denotes the amount of force applied per unit area ( = F/A) and strain denotes the extension per unit length

Given that the length is 1m which is suspended by a load of 150g. The depression is found to be 4cm. The thickness of the beam is 5mm and the breath is 3cm.

The young's modulus will be calculated by the formula below,

Y = (4gl³) / (bd³) x ( M / y )

Y = ( 4 x 9.81 x 1³ x 0.150 ) / ( 0.03 x 0.005³ x 0.04 )

Y = 3.92 x 10¹⁰ N/m².

Therefore, young's modulus will be 3.92 x 10¹⁰ N/m².

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Which of the following shows evidence of the carbon cycle?
a. A fox getting its energy from a mouse and a mouse getting its energy
from the grass.
b. Plants growing in a greenhouse.
c. Water falling as rain then evaporating back into the atmosphere.
d. A river flowing to the ocean.

Answers

A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

What is the carbon cycle?

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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It is the final seconds of an ice hockey game between the Flyers and the Bruins. The Bruins are down by 1 point. With 20 s left in the game, the Bruins pull the goalie and have him play as a forward in an attempt to tie the game. The Flyers successfully defend their goal for 9 s. With only 1.25 s remaining on the game clock, a Flyer shoots the puck on the ice past the skates and sticks of the other players and toward the Bruins' goal. The puck is 37 m from the goal when it leaves the stick with an initial horizontal velocity of 30 m/s. The shot is perfectly directed toward the empty goal, but the ice slows the puck down at a constant rate of 0.50 m/s2 as it slides toward the goal. None of the Bruins can stop the puck before it reaches the goal.
A. Where is the puck when the game clock reaches zero and the horn sounds to end the game?
B) Do the flyers win the game by 1 or 2 points?

Answers

Answer:

A

 \(k = 0.11 \ m \)  beyond the goal  post

B

Given that the goal  was score against the Bruins it then means that the Flyer won the game with 2 points

Explanation:

From the question we are told that

  The amount of time left in the game is  \(t =  20 \ s\)

   The  amount of time the goal was defended  is  \(t_1  =  9 \  s\)

   The  time remaining when the shot was made is  \(t_2 =  1.25 \  s\)

     The  distance of the pluck from the goal is  \(d =  37 \  m\)

     The  initial  velocity of the pluck is \(u =  30 \  m/s\)

    The acceleration of the pluck is  \(a =  -0.50 \  m/s^2\)

Generally the distance travel at the remaining time is mathematically represented as

      \(D =  u *  t _2  +  \frac{1}{2}* a*  t_2\)

      \(D =  30 * 1.25  - \frac{1}{2}* 0.50* 1.25^2\)

       \(D =  37.11 \ m \)

So the position of the pluck when the game clock reaches zero is

        \(k = D - d\)

=>    \(k = 37.11 - 37\)

=>        \(k = 0.11 \ m \)  beyond the goal  post

Given that the goal  was score against the Bruins it then means that the Flyer won the game with 2 points

What height would a 4 kg book need to be to have a potential energy of
235.2 J on earth?*
need help!!

Answers

Answer:

5.99 m  = 6 m

Explanation:

PE = m*g*h

235.2 J = (4 kg)(9.81 m/s^2)(h)

h = (235.2 J)/(9.81*4)

h = 5.99 m

h = 6 m

Power can also be written as force times velocity.
Question 3 options:
True
False

Answers

Answer:

  True

Explanation:

The units of force are newtons (N). The units of velocity are meters per second (m/s). The units of power are joules per second.

The units of the product of force and velocity are ...

  (N)(m/s) = (N·m)/s

The unit joule can be defined as 1 newton-meter:

  N·m = J

So, the product of force and velocity is ...

  Fv = (N)(m/s) = N·m/s = J/s . . . . units of power

Power can be written as force times velocity.


What is Energy in physics?

Answers

Answer:

Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.

Explanation:

Hope this helps!

a hohmann transfer is a fuel efficient transfer orbit to an outer planet. the process requires placing a spacecraft into an elliptical orbit about the sun, such that the perihelion, the point closest to the sun, is at the departure planet and the the aphelion, the point farthest from the sun, is at the arrival planet. the entire trajectory is depicted below.(a) Use Kepler's third law to calculate how long it would take to go from the Earth to Mars on such an orbit. (b) Can such a transfer be undertaken at any time? Explain.

Answers

A chemical rocket may launch a satellite into a Hohmann transfer orbit and maintain it there until it reaches the farthest point in the orbit by performing two very powerful burns.

These chemical rockets aren't very effective, though. They would have perished because it would have taken four weeks to return to Earth orbit.One (very powerful) engine burn is all that the Hohmann transfer orbit requires. But the interval between the two engine burns is nearly half an orbit, or 2 weeks in the event of an Earth to Moon transfer, as opposed to 3 days for the Apollo approach.That translates into four times as much food, oxygen, and cramping in the muscles, which results in increased mass and fuel. Apollo 13 remained on its orbit around the Moon after their oxygen tank exploded, depriving them of electrical power and heating, and returned to Earth after nearly 5 days.

They would have perished if they had been in a Hohmann transfer orbit, which would have taken around 4 weeks to return to.

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What will be the volume and density of stone if mass of stone is 10 gram .please tell the answer fast it's very urgent I will mark as a brain me answer if you will answer it correct.

Answers

Answer:

\(\large \boxed{\text{3.3 cm}^{3}}\)

Explanation:

Assume the stone consists of basalt, which has a density of 3.0 g/cm³.

\(\rho = \text{10 g}\times\dfrac{\text{1 cm}^{3}}{\text{3.0 g}} = \text{3.3 cm}^{3}\\\\\text{The volume of the stone is $\large \boxed{\textbf{3.3 cm}^{3}}$}\)

Given an average cell is ten times the mass of a bacterium. The mass of a bacterium is 10-15 kg. And a person's mass is 65 kg.

Answers

Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is  6.5 * 10¹⁵  cells.

What is the number of cells in a person weighing 65 kg?

The number of cells in a human is calculated as follows:

The mass of an average cell is ten times the mass of a bacterium.

The mass of a bacterium = 1 * 10⁻¹⁵ kg

mass of an average cell = 10 *  1 * 10⁻¹⁵ kg =  1 * 10⁻¹⁴ kg

Number of cells = mass of person/mass of cell

Number of cells = 65 kg/1 * 10⁻¹⁴ kg

Number of cells = 6.5 * 10¹⁵  cells.

In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.

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Note that the complete question is given below:

Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.

Which result occurs during an exothermic reaction?

A. Light is released into the environment, while heat is absorbed.

B. Heat is released into the environment, while light is absorbed.

C. Light and heat are absorbed from the environment.

D. Light and heat are released into the environment.

Answers

In exothermic reactions, heat and light are released to the surrounding environment. On the other hand, in an endothermic reaction, heat is required and therefore it can be considered as a reactant.

In exothermic reactions, light and heat are released into the environment (Option D).

Exothermic reactions release energy in the form of heat or light.

Combustion reactions are generally exothermic reactions.

After an exothermic reaction takes place it is possible to observe that the energy of the products of the reaction is lesser than the energy of the reactants.

The energy released in exothermic reactions is evidenced by the increase in temperature of the reaction.

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Answer:

(Question) Which result occurs during an exothermic reaction?

(Answer) Light or heat are released into the environment.

(Question) Which event is an example of an endothermic reaction?

(Answer) photosynthesis

(Question) How is total reaction energy calculated?

(Answer) reactant bond energy – product bond energy

(Question) When producing hydrogen iodide, the energy of the reactants is 581 kJ/mol, and the energy of the products is 590 kJ/mol. The equation is shown.

H2 + I2 → 2HI

What is the total energy of the reaction? Is this an endothermic or exothermic reaction?

(Answer) –9 kJ/mol, exothermic

(Question) Hydrogen bromide breaks down into diatomic hydrogen and bromine in the reaction shown.

2HBr → H2 + Br2

The energy of the reactant is 732 kJ/mol, and the energy of the products is 630 kJ/mol.

What is the total energy of the reaction? Is this reaction endothermic or exothermic?

(Answer) 102 kJ/mol, endothermic

Explanation:

just finished the quick check UwU

A balloon with a charge of 4.0 µC is held a distance of 0.70 m from a second balloon having the same charge. Calculate the magnitude of the repulsive force. (Hint: µ is a metric prefix that means micro or 10 -6 so 4.0 µC means 4.0 microcoulombs

Answers

Answer:

Im sorry I do not know how to do this, I hope you will be able to figure it out

Explanation:

4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V

4. Calculate the total resistance of the circuit if R1=4 , R2=30 , R3=10, R4=5 Determine the current

Answers

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Which of the following are true about a "simple compressible system"? It cannot be a mixture of different substances (e.g. oxygen and nitrogent) It's only relevant reversible work mode is associated with expansion or compression It may not have any heat transfer to or from the system Magnetization is a relevant reversible work mode It can be composed of any phases of a substance: solid, liquid, and/or gas It's state is specified if given two independent, intensive thermodynamic properties

Answers

Explanation:

The volume of a simple compressible system is not fixed. At a state of equilibrium, there should be uniformity in the entire system.

From the question we have here, these are the correct options:

1. It cannot be a mixture of different substances (e.g. oxygen and nitrogent)

2. It can be composed of any phases of a substance: solid, liquid, and/or gas

3. It's state is specified if given two independent, intensive thermodynamic properties.

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