A person walking through snow sinks into it. The person makes a change so that they do not sink as far next time they go out. What do they do?
A Crouch as they walk to lower their centre of mass.
B Run as fast as they can to increase the power they dissipate.
C Wear shoes with a much larger area on the bottom to increase the area of their feet in contact with the snow.
D Wear a heavy backpack to increase their weight and so make them more stable.
Answers
In order to not to sink in snow they Wear shoes with a much larger area on the bottom to increase the surface area of their feet in contact with the snow
The size of the snow shoes prevents them from sinking into the snow. They have a big surface. since the relationship between surface area and pressure is inverse. Therefore, when the surface area is big, less pressure will be placed on the ground by the shoes.
In comparison to the bottoms of shoes alone, the snowshoes have a larger contact surface with the snow. Because they cover a larger surface area than would be the case if he were wearing only shoes, they lessen the pressure that the person's weight puts on the snow. will not become as firmly embedded in the snow as a result
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If we try to walk on snow, our feet will sink in the snow because our feet has less surface area.
We know that lesser the surface area the more is the pressure on the surface. If we put on skies, we can move over the snow easily because skies have larger surface area and hence decrease the pressure on the snow.
Hence decrease the pressure on the snow while we walk on snow.
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Related Questions
If it took you 5 seconds to move a rock 15 meters using a force of 150 Newtons, how much power did you need to use?
500 joules/sec
45 joules/sec
4,500 joules
450 joules/sec
Answers
Answer:
Given that:
Time taken = 5 seconds
Distance = 15 meters
Force = 150 Newtons
Power = ?
Recall that power is the rate of work done per unit time
i.e Power = work / time
(since work is a product of force and distance, then
power = (force x distance)/ time
Power = (150 Newtons x 15 m) / 5 s
Power = 2250 / 5
Power = 450 joules per second
Answer:
450 joules/sec
Explanation:
150 x 15 = 2,250
2,250 / 5 = 450
= 450 joules/sec
What is the motion of the object?
F = 90 N
F3 = 60 N
F = 20 N
F2 = 90 N
Constant speed to the left
Accelerating to the left
Accelerating to the right
Constant speed to the right
Answers
Answer:
Thus, the object is accelerating to the left
Explanation:
The Net Force
The net force is the result of adding all the forces as vectors acting on a body.
\(\vec F=\vec F_1+\vec F_2+...+\vec F_n\)
Each vector can be expressed in its rectangular components Fx and Fy, and the sum is the sum of the rectangular components separately.
Second Newton's law gives the relation between the net force and the acceleration of the body:
\(\vec F = m.\vec a\)
We can see the acceleration is a vector with the same direction as the net force.
The diagram shows two vertical forces and two horizontal forces.
The vertical forces are acting in opposite directions and with the same magnitude, thus they cancel out, leaving zero net force in the y-axis.
The horizontal forces are opposite and with different magnitudes. Since the force acting to the left (F3) has a greater magnitude than the force acting to the right (F4), there is a net force directed to the left with a magnitude of 60 N - 20 N = 40 N
Thus, the object is accelerating to the left
Mathias is going to do some informational interviewing. What is one of the main benefits of doing these interviews?
O A.
OB.
O C.
O D.
A.He will gain insight about a new career opportunity.
B.He will likely be offered a position with a company.
C.He will be able to ask questions about job openings.
D.He will find out how much money everyone earns.
Answers
Answer:
A
Explanation:
One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.
Pls help me
What is the acceleration of a 10 kg mass pushed by a 5 N force?
Answers
Answer:
The answer is 0.5m/s²
Explanation:
Acceleration=Force ÷mass
= 5÷10=0.5m/s²
Mr Smith is working in a muddy garden. When he picks up a paving stone his feet sink deeper into the mud. Explain why his feet sink into the mud more when he picks up the paving stone. Write about pressure in your answer
Answers
because he is carrying more mass and as the ground is muddy his feet goes in due to the pull of gravity
Which factors affect the gravitational force between two objects?
distance and velocity
O mass and distance
mass and weight
O acceleration and weight
Answers
Answer:
mass and distance
Explanation:
I could explain it but I don't know how to word it xd
Answer:
My best guess is:
B) mass and distance
This is because gravity is affected by the size of objects and the distance between objects.
Explanation:
Hope it helps! =D
how much energy must be absorbed by 20 point grams of water to increase its temperature from 283 degrees Celsius to 303°C 
Answers
The amount of energy required to increase the temperature of 20 g of water from 283°C to 303°C is approximately 6.1 kJ.
How much energy must be absorbed by 20 point grams of water to increase its temperature from 283 degrees Celsius to 303°C?To calculate the amount of energy absorbed by 20g of water when its temperature increases from 283°C to 303°C, you must use the formula for specific heat capacity.Specific heat capacity is the amount of energy required to raise the temperature of 1g of a substance by 1°C. The formula for specific heat capacity is Q=mcΔT, where Q is the energy absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. In this case, the mass of the water is 20g, the change in temperature is 20°C, and the specific heat capacity of water is 4.2 J/g°C. Therefore, the energy required to increase the temperature of 20g of water from 283°C to 303°C can be calculated as follows: Q= 20g x 4.2 J/g°C x 20°C = 1680J. Therefore, the amount of energy absorbed by 20g of water to increase its temperature from 283°C to 303°C is 1680J.
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Calculate the velocity of the man if he moves 6 m to the right and 4 m [i.e. the man ends up at 2 m to the right in the positive direction] to the left within 4.4 seconds as shown in the figure below?
Answers
The velocity of the man given the data from the question is 0.45 m/s
What is velocity?Velocity is simply defined as the rate of change of displacement with time. Mathematically, it can be expressed as:
Velocity = Change of displacement / time
Data obtained from the questionFrom the question given above, the following data were obtained:
Displacment 1 = 6 m right Displacement 2 = 4 m leftChange of displacement = 6 - 4 = 2 m rightTime = 4.4 secondsVelocity = ?How to determine the velocity of the manThe velocity of the man can be obtained as follow:
Velocity = Change of displacement / time
Velocity = 2 / 4.4
Velocity = 0.45 m/s
Thus, the velocity of the man is 0.45 m/s
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1. The distance between New York City and Dallas is about 1500 miles. Assume you drive to New York City at an average velocity of 80 miles per hour - how many hours will it take to reach New York City?
Answers
Answer: 22 hours 15 minutes
Explanation: The calculated flying distance from New York City to Dallas is equal to 1371 miles which is equal to 2206 km. If you want to go by car, the driving distance between New York City and Dallas is 2492.32 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 22 hours 15 minutes.
A 0.360-m-long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal rails connected through a 45.0 ohm resistor, as shown in the diagram, so the apparatus makes a complete circuit. The circuit is in a uniform 0.650-T magnetic field that is directed out of the plane of the figure. At the instant when the bar is moving to the left at 5.90 m s, (a) is the induced current in the circuit clockwise or counterclockwise and (b) what is the rate at which the applied force is doing work on the bar?
Answers
(a) The induced current in the circuit is clockwise.
b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.
How to solve(a) The induced current in the circuit is clockwise.
This can be determined using the right-hand rule.
As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.
(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:
induced EMF (ε) using Faraday's law:
ε = BLv
= (0.65 T) * (0.36 m) * (5.9 m/s)
= 1.389 Tm²/s
= 1.389 V (since 1 Tm²/s = 1 V)
induced current (I) using Ohm's law:
I = ε/R
= 1.389 V / 45 Ω
= 0.03086 A
force (F) from the Lorentz force law, where F = ILB:
F = ILB
= (0.03086 A) * (0.36 m) * (0.65 T)
= 0.00723 N
Finally, we find the power (P) using P = Fv:
P = Fv
= (0.00723 N) * (5.9 m/s)
= 0.04266 W
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It is now 9:11 a.m. but when the bell rings at 9:12 a.m. Susie will be late for Mrs. Garner's U.S. History class for the 3rd time this week. She must get from one side of the school to the other by hurrying down three different hallways. She runs down the first hallway (D-Hall), a distance of 47.0 meters. The second hallway (C-Hall) is filled with students, and she covers its 63.0 m length quickly. The final hallway (B- Hall) is empty, and Susie sprints its 76.0 m length. How fast does Susie need to go to make it to class on time (Hint: Calculate the total distance. Then calculate her total average speed rounded to the nearest tenths in meters/seconds.)?
Answers
Answer:
3.1 m/s
Explanation:
The total distance she has to run is the addition of the three lengths:
47 + 63 + 76 = 186 meters.
She needs to cover it one minute (60 seconds). Therefore her speed must be:
186 m / 60 s = 3.1 m/s
- A certain mass is suspended at one end of a spring of spring-constant of 32,000gm/s2. The
time taken to execute 10 oscillations is 15 second.
(a) What is the time period?
(b) What is the value of mass suspended at the end of the spring.
Answers
Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.
Explanation:
Why is DNA a useful evolutionary clock?
Answers
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
Answers
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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Frequency= Wavelength = 502 km Speed= 100 m/s
Answers
Answer:
Explanation:
Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.
fill in the blank. a 10-kg rock and a 20-kg rock are thrown upward with the same initial speed v0 and experience no significant air resistance. the 20 kg rock will reach a height which is___the maximum height of the 10-kg rock.
Answers
The 20 kg rock will reach a height which is less than the maximum height of the 10-kg rock.
The 20-kg rock will reach a height which is less than the maximum height of the 10-kg rock.
The maximum height reached by an object is proportional to the square of its initial velocity. The force of gravity acting on an object is proportional to its mass. Hence, the acceleration due to gravity is equal to the force of gravity divided by the mass of the object. This means that a heavier object will have a smaller acceleration and will reach a lower maximum height compared to a lighter object, despite being thrown with the same initial velocity.
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If and object undergoes a change in momentum of 12 kg*m/s over a 10
second interval, what was the force exerted?
Answers
The magnitude of the force exerted on this object is 1.2 Newton.
Given the following data:
Change in momentum = 12 Kgm/s.Time = 10 seconds.What is impulse?In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.
Mathematically, impulse is given by this formula:
\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)
Substituting the given parameters into the formula, we have:
\(Force \times 10=12\\\\Force =\frac{12}{10}\)
Force = 1.2 Newton.
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6. In an integrated circuit, each wafer is cut into sections, which
ООО
A. have multiple circuits and are placed in individual cases.
B. carry a single circuit and are placed in individual cases.
C. carry a single circuit and are placed all together in one case.
D. have multiple circuits and are placed all together in one case.
o
Answers
Answer:
B. carry a single circuit and are placed in individual cases.
Explanation:
An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.
Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.
Similarly, an integrated circuit (IC) also referred to as microchip can be defined as a semiconductor-based electronic component that comprises of many other tiny electronic components such as capacitors, resistors, transistors, and inductors.
Integrated circuits (ICs) are often used in virtually all modern electronic devices to carry out specific tasks or functions such as amplification, timer, oscillation, computer memory, microprocessor, etc.
A wafer can be defined as a thin slice of crystalline semiconductor such as silicon and germanium used typically for the construction of an integrated circuit.
In an integrated circuit, each wafer is cut into sections, which generally comprises of a single circuit that are placed in individual cases.
Additionally, a semiconductor can be defined as a crystalline solid substance that has its conductivity lying between that of a metal and an insulator, due to the effects of temperature or an addition of an impurity.
Answer: B got it right on the test just now
Explanation:
Conclude what happens to the speed of light when it passes from a medium of low index of refraction into a medium of high index of refraction? Justify your statement using the data you have collected
Answers
The thing that happens to the speed of light when it passes from a medium of low index of refraction into a medium of high index of refraction is that it tend to speed up.
Why does it speed up?Light moves more quickly when it enters a medium with a lower refractive index, as air from water. The light deviates from the straight line. Light will move more slowly and obliquely as it penetrates a substance with a higher refractive index.
The speed of light increases with decreasing refractive index. The lesser refractive index belongs to medium A. When moving at a speed equal to the speed of light divided by the refractive index, light will move more quickly through medium A.
Hence, Light bends in the direction of the normal as it passes through an interface into a medium with a greater index of refraction. On the other hand, light bending away from an interface from higher n to lower n.
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additional data were collected and are displayed in the figure. (figure 2)based on the trend of these data, predict the expected resistance r of the sample at temperatures very close to absolute zero.
Answers
The 4 x 10^-3 ohms is at temperatures very close to absolute zero.
What is ohms?
A SI-derived unit for measuring electrical resistance in materials or electrical devices. When a one-volt potential difference is applied, a one-amp current flows through the conductor, which has a resistance of one ohm.
What is resistance ?
Resistance is the obstacle that a substance offers to the flow of electrical current. The ohm, frequently written as a word and occasionally represented by the uppercase Greek letter omega, is the commonly used unit of resistance.
Use the same slope that you hopefully calculated in part A (1/40), solve for a line equation to represent the graph, and plug in 0 for the x variable (temperature here).
y=mx+b.....R=(1/40)T+4....
R(0 Kelvin) = (1/40)*0 + 4 = 4 but because R is in milliohms, 4 x 10^-3 ohms.
Therefore, 4 x 10^-3 ohms is at temperatures very close to absolute zero.
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Two car (A) and (B) start from the rest at the same instant of time t=0 . From the points M and N respectively in uniformly accelerated rectilinear motion and in opposite directions as shownin the adjacent figure give acceleration of (A) is 4m/s² and that (B) is 2m/s² .MN 30km At the instant t the car (A) covered a distance d¹ and B covers a distance d² 1 determine as a function of t d¹and d² . 2 deduce the time meeting 2 cars . 3 answer the preceding questions but consider that car (B) in uniform rectilinear motion with a speed of 10 m/s
Answers
To solve the problem, let's break it down into three parts:
1. Determining the distance covered by cars A and B as a function of time:
For uniformly accelerated rectilinear motion, we can use the following equation to calculate the distance covered:
distance = initial velocity * time + (1/2) * acceleration * time^2
For car A:
The initial velocity is 0 m/s, and the acceleration is 4 m/s².
So, the distance covered by car A at time t is:
d¹(t) = 0.5 * 4 * t^2 = 2t^2
For car B:
The initial velocity is 0 m/s, and the acceleration is -2 m/s² (opposite direction to car A).
So, the distance covered by car B at time t is:
d²(t) = 0.5 * -2 * t^2 = -t^2
2. Deducing the time of meeting for the two cars:
To find the time of meeting, we need to set the distances covered by both cars equal to each other:
2t^2 = -t^2
Simplifying the equation:
2t^2 + t^2 = 0
3t^2 = 0
Since the equation equals zero, the only solution is t = 0. This means that the two cars meet at the starting point at t = 0.
3. Considering car B in uniform rectilinear motion with a speed of 10 m/s:
If car B is moving at a constant speed of 10 m/s, it means its acceleration is 0 m/s². Therefore, the equation for car B's distance covered becomes:
d²(t) = initial velocity * time = 10 * t = 10t
Now, we can answer the preceding questions using this new equation for car B.
1. The distance covered by car A at time t is still d¹(t) = 2t^2.
The distance covered by car B at time t is now d²(t) = 10t.
2. The time of meeting for the two cars can be found by setting the distances equal to each other:
2t^2 = 10t
Simplifying the equation:
2t^2 - 10t = 0
2t(t - 5) = 0
From this equation, we have two solutions:
t = 0 (the initial meeting point)
t = 5 seconds (when the two cars meet again after 5 seconds)
Therefore, the cars meet again after 5 seconds.
Please note that the distances calculated above are in terms of t, the time elapsed since t = 0.
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Two uniform solid spheres, each with mass 0.852 kg
and radius 8.00×10−2 m are connected by a short, light rod that is along a diameter of each sphere and are at rest on a horizontal tabletop. A spring with force constant 153 N/m has one end attached to the wall and the other end attached to a frictionless ring that passes over the rod at the center of mass of the spheres, which is midway between the centers of the two spheres. The spheres are each pulled the same distance from the wall, stretching the spring, and released. There is sufficient friction between the tabletop and the spheres for the spheres to roll without slipping as they move back and forth on the end of the spring.
Assume that the motion of the center of mass of the spheres is simple harmonic. Calculate its period.
Answers
The period of the simple harmonic motion of the center of mass of the two spheres is approximately 0.770 seconds.
To find the period of the simple harmonic motion of the center of mass of the two spheres, we need to use the equation for the period of a mass-spring system:
T = 2π√(m/k)
where T is the period, m is the total mass of the system (two spheres), and k is the spring constant.
First, we need to find the total mass of the system:
m = 2m1 = 2(0.852 kg) = 1.704 kg
where m1 is the mass of one sphere.
Next, we need to find the spring constant:
k = 153 N/m
Now, we can calculate the period:
2π√(1.704 kg/153 N/m) ≈ 0.770 s
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5 points
15. *
15. Which one of the following
quantities is NOT a vector?
A velocity
B acceleration
C distance
D displacement
A
B
С
Answers
Answer:
distance is not a vector. it is scalar
Please show work if possible! Thank you!!
A 2.0 x 103 kg roller coaster travels around a vertical 24-m radius loop. If the coaster has a tangential speed of 18 m/s at the lowest point of the loop, what is the normal force that is exerted on the coaster by the track at this point?
a. 5.3 x 10^4 N
b. 4.7 x 10^4 N
c. 3.0 x 10^4 N
d. 2.7 x 10^4 N
Answers
B. The normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.
Normal force exerted on the coaster at the lowest point
Fₙ = mg + mv²/r
where;
m is mass of the coasterv is speed of the coasterr is radius of the pathFₙ = (2,000 x 9.8) + (2,000 x 18²)/24
Fₙ = 46,600 N
Fₙ = 4.7 x 10⁴ N
Thus, the normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.
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The same collision as in Question 5 takes place, only this time the car and the truck bounce off each other completely elastically What are the final velocities of the car and truck just after the collision?
Answers
The final velocities of the car and truck just after the collision will be as per the conservation of momentum.
Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].
According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.
if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.
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You are pulling a wagon with a mass10kg and it’s moving forward at a constant rate. Your friend gets into the wagon and it’s slows down. What can you do to get the wagon moving faster?
Answers
Explanation:
Without changing the constant speed, your friend can empty the contents of the wagon, or decrease the overall rate, or the terrain the wagon is traveling on, all of these would increase the wagon's speed. Also, you could try applying a heavier pulling force, like using a horse instead of yourself, or you and a horse to get going faster.
Hope this helps!
Which element is a good material for use as a semiconductor?copperoxygensiliconsodium
Answers
To find:
Which of the given elements is a good material for semiconductor?
Explanation:
The silicon is widely used for the manufacturing of semiconductors. The stable structure of the silicon makes it a suitable candidate for the manufacture of semiconductors. The silicon is widely abundant in nature. This makes it economical.
How come the arrow points the other direction when we look at it through a glass of water?
Answers
Problem Try to answer the following questions:(a) What is the maximum height above ground reached by the ball?(b) What are the magnitude and the direction of the velocity of the ball just before it hits the ground? Show Your Problem Solving Steps: Show these below:1) Draw a Sketch2) Choose origin, coordinate direction3) Inventory List – What is known?4) Write the kinematics equation(s) and solution of Part (a):5) Write the kinematics equation(s) and solution of Part (b):Problem 3 A small ball is launched at an angle of 30.0 degrees above the horizontal. It reaches a maximum height of 2.5 m with respect to the launch position. Find (a) the initial velocity of the ball when it’s launched and (b) its range, defined as the horizontal distance traveled until it returns to his original height. As always you can ignore air resistance.(a) Initial velocity [Hints: How is v0 related to vx0 and vy0. How can you use the information given to calculate either or both of the components of the initial velocity?](b) Range [Hints: This problem is very similar to today’s Lab Challenge except that for the challenge the ball will land at a different height.]
Answers
3.
\(\begin{gathered} \theta=30^{\circ} \\ y_{\max }=2.5m \end{gathered}\)a)
\(\begin{gathered} y_{\max }=\frac{v^2\sin ^2(\theta)}{g} \\ \end{gathered}\)Solve for v:
\(\begin{gathered} v=\sqrt[]{\frac{y_{\max }\cdot g}{\sin ^2(\theta)}} \\ v=98\cdot\frac{m}{s} \end{gathered}\)b)
\(\begin{gathered} r=\frac{v^2}{9}\sin (2\theta) \\ r=\frac{98^2}{9.8}\cdot\sin (2\cdot30) \\ r=\frac{98^2}{9.8}\sin (60) \\ r=848.7m \end{gathered}\)The half-life of Silver-105 is 3.57 x 106 seconds. A sample contains 5.78 x 1017 nuclei. What is the decay constant for this decay?
Answers
Answer:
The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:
16:42
λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.
Explanation: