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Something that has many particles in a small space would have a ————- density
Fill in blank
Answers
Answer:
a high density i believe
Explanation:
Answer:
it may have a higher density
25. You lift a book from the floor to a bookshelf 1.0 m above the ground. How much power is used if the
upward force is 15.0 N and you do the work in 2.0 ?
Answers
Explanation:
P=E/T
E=15N
T=2s
P=15/2
P=7.5
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Energy Essay Question 1
You do work on something when you lift it against gravity. How does this work relate to gravitational potential
energy? If the lifted object is released, what becomes of this energy? Be sure to define all terms that you use.
Posted Mon Jan 30, 2023 at 1:16 pm
Criteria
Grading Scale
DS Immersive Reader Grade: N/A O
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As the object is raised, the gravitational potential energy of the system grows. When you drop something, the potential energy of the object is transformed into kinetic energy, which is the energy of the moving object, when it strikes the ground.
What is kinetic and potential energy?
Potential energy is the energy stored in an object or system due to its position or arrangement of elements. It is unaffected by the environment outside the installation or system, such as air or altitude. Conversely, kinetic energy refers to the energy of moving particles in a system or object.
An object's kinetic energy, unlike potential energy, relates to other stationary and moving objects in its immediate vicinity. Thus, the lifted object is in kinetic motion when released.
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Unscramble the terms in italics to complete the sentences below. Write the terms on the lines provided. 5. In dry regions where sheep and cattle eat the grasses, reggianvorz increases soil erosion.
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The term which describes the increased soil erosion in the regions where sheep and cattle eat the grasses and reggianvorz is called overgrazing.
What is overgrazing ?Overgrazing happens when livestock and other grazers (such as wildlife) consume more plant biomass than the vegetation can replenish in a reasonable amount of time, exposing the soil and lowering the vegetation's potential for production.
The exposure of the soil might hasten the potential for processes of water and wind erosion, which can result in soil losses. Less water infiltration into the soil might result in slower plant growth due to accelerated erosion processes and soil compaction caused by grazing animals.
Because less plant biomass is accessible as litter due to ongoing overgrazing, less soil organic matter, nutrients, and biotic activity are added to the soil. This causes the soil structure to deteriorate, which lowers the soil's capacity to store water and raises the risk of erosion.
Therefore, the term describing the given action is overgrazing.
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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What physical quantity does the slope of the v2/2 v/s h graph represent: #Hint: The algebraic statement of the conservation of Mechanical Energy is FEequals 1 half m v squared plus m g h where E,m, and g are constants. Solve for v2/2and determine what the slope would be if 'h' was on the horizontal axis. slope--g slope=-Elm slope-E slope-h
Answers
The physical quantity that does the slope of the v2/2 v/s h graph represent is the slope-g. The slope is representing the change in v over the change in time.
By definition, that is the acceleration. Also extra than only a gimmick, it is geometry's manner of displaying us how variables now no longer most effective relate to 1 another, however how they are able to constitute the fee of alteration among the variables.
The slope of the displacement time graph offers us the bodily amount called pace. The slope of a pace graph represents an object's acceleration. As a result, the cost of the slope at a given time represents the object's acceleration at that time. The fee of changing of an object's pace with admire to time is described as acceleration.
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For 2 non-perpendicular vectors, R is calculated by component method.
5. A baseball player leaves the bench and runs A= 25 m [E] and then B=40 m [SW].
Draw these two vectors, determine their x- and y-components, then draw their
resultant vector R by triangle method .Use scale 5 m= 1 cm. Calculate R by
component method and compare with the graphical value.
Answers
Answer:
30.3 meters, 172 degrees.
Explanation:
Which side of a cuboid should be placed on the ground to exert maximum pressure?
a) The smallest side
b) The largest side
c) The longest side
d) Each side will exert the same pressure on the ground
Answers
the position of an object on a velocity time graph is given as (20,5) and (10,3). calculate the acceleration of the object
Answers
Now I don’t know if you mistyped the points in like that instead of (5,20) and (3,10) or not because that would make more sense than what you sent, but I’ll solve both cases
Case 1:
Using (20,5) (10,3)
As we said, first numbers are time values, second numbers are velocity values
t1 = 10s and t2 = 20s
v1 = 3m/s and v2 = 5 m/s
Using the formula a = (v2 - v1)/(t2 - t1)
a = (5-3)/(20-10) = 2/10 = 0.2 m/s^2
Case 2:
If we use (5,20) and (3,10)
t1=3s and t2=5s
v1=10m/s and v2=20m/s
Using the same formula
a= (20-10)/(5-3) = 10/2 = 5m/s^2
Hope this helps
What are used to transfer electrical energy from a power plant all the way to a home? generators turbines power transformers power lines
Answers
Answer:
Power lines
Explanation:
Generators induce that current that runs the turbines
Turbines also induce currents from water waves that is transmitted.
Transformers change A.C to D.C or vice versa.
Plz help
Fill in the blank with the correct observation from the simulation.
As the days go on, the distance that the moon is from the sun in the night sky
A. Stays the same
B. Decreases
C. Increases
Answers
Starting at New Moon, The visual distance increases for about 2 weeks, then decreases for about the next 2weeks, until the next New Moon.
On the average, it changes by about 12° per day.
If you were a member of Congress, what legislation would you introduce if acid rain from a coal
Answers
There are many reasons. The easiest solution is because the rain that we remember acidic has a low pH; it has a better amount of hydrogen ions.
Acid rain manipulation implies three adjustments a notably extra complicated and cumbersome regulatory program beneath the Clean Air Act, new emission manipulation prices for initial rollback requirements and next offsets, and on account of these, new impediments to utility and commercial plant creation, expansion, and modernization.
The Acid Rain application (ARP) has brought widespread discounts in sulfur dioxide (SO2) and nitrogen oxide (NOX) emissions from fossil fuel-fired strength flora, full-size environmental and human fitness blessings, and a ways lower-than-anticipated prices.
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If you were unfortunate enough to be 5.5 mm away from such a lightning bolt, how large a magnetic field would you experience
Answers
The question is incomplete. Here is the complete question.
Lightning bolts can carry currents up to approximately 20kA. We can model such a current as the equivalent of a very long, straight wire.
(a) If you were unfortunate enough to be 5.5m away from such a lightning bolt, how large a magnetic field would you experience?
(b) How does this field compare to one you would experience by being 5.5cm from a long, straight household current of 5A?
Answer: (a) B = 7.27 x 10⁻⁴ T
(b) Approximately 40 times higher than a household one.
Explanation: Using Biot-Savart Law, the magnetic field in a straight, long wire is given by
\(B=\frac{\mu_{0}I}{2.\pi.r}\)
where:
\(\mu_{0}\) (permeability of free space) = \(4.\pi.10^{-7}\)T.m/A
(a) If lightning bolt is compared to a long and straight wire, then magnetic field is
\(B=\frac{4.\pi.10^{-7}.10.10^{3}}{2.\pi.5.5}\)
B = 7.27 x 10⁻⁴ T
The magnitude of magnetic field in a lightning bolt is 7.27 x 10⁻⁴ T
(b) Magnetic field in a household wire will be
\(B=\frac{4.\pi.10^{-7}.5}{2.\pi.5.5.10^{-2}}\)
B = 1.82 x 10⁻⁵ T
Comparing fields:
\(\frac{7.27.10^{-4}}{1.82.10^{-5}}\) ≈ 40
The filed for a lightning bolt is approximately 40 times higher than for a household wire.
the order of magnitude of the electrical potential generated when 5000 electron volts of work are done on 10 electrons is
A) 1 B) 2 C) 3 D) 4
Answers
The order of magnitude of the electrical potential generated is 1 (option A).
What is electric potential?
Electric potential, also known as voltage, is a measure of the electric potential energy per unit charge of an electric field at a given point in space. It is a scalar quantity that is expressed in units of volts (V).
The electric potential at a point in space is defined as the amount of work required to move a unit positive charge from infinity to that point, against the electric field. It is also given by the ratio of the potential energy of a charged particle in an electric field to its charge.
The electrical potential generated when work is done on an electron is given by the formula:
ΔV = ΔW/q
where ΔW is the work done on the electron, and q is the charge of the electron.
Substituting the given values, we get:
ΔV = (5000 eV) / (10 × 1.6 × 10^-19 C)
ΔV = 3.125 × 10^16 V
To determine the order of magnitude of this potential, we can round it to the nearest power of 10. In this case, the number is between 10^16 and 10^17, so we can round it to 10^16.
Therefore, the order of magnitude of the electrical potential generated is 1 (option A).
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Given average life span of us people is 77 yrs. and a person has an average heart rate of 72 beats per minute.
Answers
Explanation:
One of the vital signs a nurse checks when you visit the doctor is your heart rate, along with temperature, blood pressure and respiratory rate. Your heart rate, which is measured by your pulse, is an important indicator of your overall health and fitness level. It can signal certain medical conditions or a need to adjust lifestyle habits that elevate your heart rate above the normal range determined by your age.
A net force of 200 N is applied to a 20 kg cart that is already moving at 3
m/s. The final speed of the cart was 8 m/s. For how long was the force
applied? *
Answers
Answer:
t=0.5 seconds
Explanation:
Given that,
Force, F = 200 N
Mass of a cart, m = 20 kg
Initial speed of a cart, u = 3 m/s
Final speed, v = 8 m/s
Let t is the time for which the force is applied. Force applied to an object is given by :
F = ma
or
\(F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{20\times (8-3)}{200}\\\\t=0.5\ s\)
So, for 0.5 seconds the force is applied.
The length of a simple pendulum is 0.80 m and the mass of the "bob" at the end is 0.31 kg. The pendulum is pulled away from equilibrium at an angle of 6.8 degrees and released from rest.
a. What is the angular frequency of the motion?
b. Using the position of the bob at its lowest point as the reference level, determine the total mechanical energy of the pendulum as it swings back and forth.
c. What is the bob's speed as it passes through the lowest point of the swing?
Answers
a) angular frequency of the motion is ω = 3.5s⁻¹
b) total mechanical energy of the bob is T.M.E = 0.029J
c) bob's speed at the lowest point is V= 0.43m/s.
A mechanical device that oscillates or sways is known as a simple pendulum. The gravitational force is primarily responsible for this motion, which takes place in a vertical plane.
Given,
Length of a simple pendulum, L = 0.80m
Mass of the bob, m = 0.31 kg
h= L- LcosΘ = L (1 - cosΘ)
a) Angular frequency, ω = 2π / T
where, T = 2π √(L/g)
ω = 2π / 2π √(g/L)
ω =√(9.8 / 0.80) s⁻¹
ω = 3.5s⁻¹
b) Total mechanical energy, T.M.E = (K.E.)ₐ + (P.E.)ₐ
As (K.E.)ₐ = 0
(P.E.)ₐ =mgh
T.M.E = 0 + mgh, where h = L (1-cosΘ)
T.M.E = ngL (1-cosΘ)
= 0.31*9.8*0.80(1-0.988)
= 0.029J
Thus, T.M.E = 0.029J
c) bob's speed at the lowest position, V
TMEb = 0.029J
(KE)b + (PE)b = 0.029J
1/2mV² + 0 = 0.029J
V =√(2*0.029/m)
V = 0.43m/s
So, the speed at the lowest point is V= 0.43m/s.
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Louis Armstrong ride his bike 55km east time trial in 51 minutes what was his average velocity in KM/min?
Answers
Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.
How to determine average velocity?To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.
Average Velocity = Displacement / Time
Displacement = 55 km (since he rode 55 km to the east)
Time = 51 minutes
Average Velocity = 55 km / 51 min
To express the average velocity in km/min, convert the time from minutes to minutes.
1 hour = 60 minutes
Average Velocity = 55 km / 51 min × (1 hour / 60 min)
Average Velocity = 55 km / 51 min × (1/60) hour
Simplifying the expression:
Average Velocity = 1.078 km/min
Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.
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If a Current Current of strength 3A flows through aresistance of 20 om for 10 minutes,then calculate the amount of heat produced in the resistance.
Answers
Answer:
1.08 x 10^5 J
Explanation:
First, apply the formula V = IR , where V is the voltage, I is the current and R is the resistance.
R -> 20 ohm (Given)
I -> 3A (Given)
Hence, V = 3 x 20 = 60V (60 volts)
Next, apply the formula E = Pt , where E is the energy produced, P is the power and t is the time in seconds
Furthermore, since P = IV (power = current x voltage)
The formula can be re-expressed as E = VIt
t -> 10 minutes = 600 seconds (don't forget to convert time to seconds!)
Therefore, energy = (60 x 3 x 600) J
= 108000 J
= 1.08 x 10^5 J (in scientific notation)
Hea produced in the resistance = energy produced in the resistor
= 1.08 x 10^5 J
A 1200 kg wrecking ball hangs from a 14-m-long cable. The ball is pulled back until the cable makes an angle of 19.0 ∘ with the vertical. By how much has the gravitational potential energy of the ball changed?
Answers
Explanation:
Seems like there might be an easier way than all of this trig work.....let me know if it is incorrect: ( due to rounding the answer may be 8979 J )
Odina walked down the hall at school from the cafeteria to the band room, a distance of 100.0m. A class of physics students
recorded and graphed her position every 2.0s, noting that she moved 2.6m every 2.0s. Odina was 25m from the band room
at 58s.
Please select the best answer from the choices provided
Т
F
Answers
Find distance she traveled:
100m -25m = 75m
58 seconds / 2 second intervals = 29
29 x 2.6m = 75.4 meters total.
if the distance wasn’t rounded the statement was False.
Answer: False
A plane moves 599 m northeast along a runway.
If the northern component of this displacement
is 89 m, how large is the eastern component?
Answers
The eastern component of the plane's displacement is 592.35 m.
The given parameters;
the resultant of the plane displacement = 599 mthe northern component of this displacement, Y = 89 mLet the eastern component of this displacement = XThe eastern component of the plane's displacement is calculated by applying Pythagoras theorem as follows;
X² + Y² = 599²
X² + 89² = 599²
X² = 599² - 89²
X² = 350880
X = √350880
X = 592.35 m
Thus, the eastern component of the plane's displacement is 592.35 m
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When is the ball in a state of free fall?
Answers
Answer: a. The moment the ball leaves the athlete's hand traveling upwards, reaches maximum height, then traveling downward till the moment just before the athlete catches it.
I think this is the answer. In Newtonian physics, free fall is any motion of a body where gravity is the only force acting upon it. The body is moving only under the influence of the earth's gravity.
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How much potential energy is stored in a spring that is stretched 15 cm by a force of 72 N?
Answers
Answer:
10,800
Explanation:
The formula is MGH I hop this helps
In testing an automobile tire for proper alignment, a technician marks a spot on the tire 0.220 m from the center. He then mounts the tire in a vertical plane and notes that the radius vector to the spot is at an angle of 30.0° with the horizontal. Starting from rest, the tire is spun rapidly with a constant angular acceleration of 1.90 rad/s2. (Assume the spot's position is initially positive, and assume the angular acceleration is in the positive direction).A) What is the angular speed of the wheel after 1.30 s?
B) What is the tangential speed of the spot after 1.30 s?
C) What is the magnitude of the total acceleration of the spot after 1.30 s?
D) What is the angular position of the spot after 1.30 s?
Answers
Answer:
a) The angular speed of the wheel after 1.30 seconds is \(2.47\,\frac{rad}{s}\), b) The tangential speed of the spot after 1.30 seconds is \(0.543\,\frac{m}{s}\), c) The magnitude of the total acceleration of the spot after 1.30 seconds is \(1.406\,\frac{m}{s^{2}}\), d) The angular position of the spot is 2.130 radians (122.011°).
Explanation:
a) Given that tire accelerates at constant rate, final angular speed can be predicted by using the following formula:
\(\omega = \omega_{o} + \alpha \cdot \Delta t\)
Where:
\(\omega\) - Final angular speed, measured in radians per second.
\(\omega_{o}\) - Initial angular speed, measured in radians per second.
\(\alpha\) - Angular acceleration, measured in radians per square second.
\(\Delta t\) - Time, measured in seconds.
Given that \(\omega_{o} = 0\,\frac{rad}{s}\) (starts at rest), \(\alpha = 1.90\,\frac{rad}{s^{2}}\) and \(\Delta t = 1.30\,s\), the final angular speed is:
\(\omega = 0\,\frac{rad}{s} + \left(1.90\,\frac{rad}{s^{2}} \right) \cdot (1.30\,s)\)
\(\omega = 2.47\,\frac{rad}{s}\)
The angular speed of the wheel after 1.30 seconds is \(2.47\,\frac{rad}{s}\).
b) The tangential speed of the spot is the product of the distance between the center of the wheel and spot. That is:
\(v = r \cdot \omega\)
Where r is the distance between the center of the wheel and spot. The tangential speed of the spot after 1.30 seconds is:
\(v = (0.220\,m)\cdot \left(2.47\,\frac{rad}{s} \right)\)
\(v = 0.543\,\frac{m}{s}\)
The tangential speed of the spot after 1.30 seconds is \(0.543\,\frac{m}{s}\).
c) The magnitude of the total acceleration of the spot is the magnitude of the vectorial sum of radial and tangential accelerations (both components are perpendicular to each other), which is determined by the Pythagorean theorem, that is:
\(a = \sqrt{a_{r}^{2} + a_{t}^{2}}\)
Where \(a_{r}\) and \(a_{t}\) are the radial and tangential accelerations.
\(a = r\cdot \sqrt{\omega^{4} + \alpha^{2}}\)
If \(r = 0.220\,m\), \(\omega = 2.47\,\frac{rad}{s}\) and \(\alpha = 1.90\,\frac{rad}{s^{2}}\), then, the resultant acceleration is:
\(a = (0.220\,m)\cdot \sqrt{\left(2.47\,\frac{rad}{s} \right)^{4}+\left(1.90\,\frac{rad}{s^{2}} \right)^{2}}\)
\(a \approx 1.406\,\frac{m}{s^{2}}\)
The magnitude of the total acceleration of the spot after 1.30 seconds is \(1.406\,\frac{m}{s^{2}}\).
d) Let be 30° (0.524 radians) the initial angular position of the spot with respect to center. The final angular position is determined by the following equation of motion:
\(\omega^{2} = \omega_{o}^{2} + 2\cdot \alpha \cdot (\theta - \theta_{o})\)
Final angular position is therefore cleared:
\(\theta - \theta_{o} = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)
\(\theta = \theta_{o} + \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)
Given that \(\theta_{o} = 0.524\,rad\), \(\omega_{o} = 0\,\frac{rad}{s}\), \(\omega = 2.47\,\frac{rad}{s}\) and \(\alpha = 1.90\,\frac{rad}{s^{2}}\), the angular position of the spot after 1.30 seconds is:
\(\theta = 0.524\,rad +\frac{\left(2.47\,\frac{rad}{s} \right)^{2} - \left(0\,\frac{rad}{s}\right)^{2}}{2\cdot \left(1.90\,\frac{rad}{s^{2}} \right)}\)
\(\theta = 2.130\,rad\)
\(\theta = 122.011^{\circ}\)
The angular position of the spot is 2.130 radians (122.011°).
In the rotational motion of an object, the angular acceleration is always towards the center, and the further discussion is as follows:
Rotational motion:The tangential acceleration of the object keeps changing its direction as the object rotates, always directed toward the tangent of the circle passing through the position of the object.
Radius of the spot, r = 0.220
minitial angle from the horizontal, θ = 30°
angular acceleration, α = 1.9 rad/s²
(a) from the first equation of motion we get:
ω = ω₀ + αt where
ω is the final angular speed
ω₀ is the initial angular speedand
t is the time = 1.3sω = 1.9×1.3 rad/sω = 2.47 rad/s
(b) tangential speed (v) is given by:
v = r×ωv = 0.220×2.47 m/sv = 0.5434 m/s
(c) The instantaneous tangential acceleration is given by:
\(a_t\) = rω²so the resultant acceleration will be:
\(a=\sqrt{a_t^2+\alpha^2}\\\\a =\sqrt{r^2\omega^4+\alpha^2}\\\\a= \sqrt{(0.220)^2(2.47)^4+(1.9)^2}\\\\a = 1.4 \ \frac{m}{s^2}\)
(d)
The angular displacement is given by:
θ = θ₀t + ¹/₂αt²θ₀ = 30° = 0.524
rad θ = 0.524×1.3 + ¹/₂×1.9×1.3²θ = 2.286 radθ = 131°
Following are the solution for points:
For a)
The angular speed is 2.47 rad/s
For b)
The tangential speed is 0.5434 m/s
For c)
Total acceleration is 1.4 m/s²
For d)
The final angular position is 131°
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The way in which one atom interacts with another atom is mostly influenced by the configuration of the
A. electrons farthest from the nucleus.
B. protons in the center of the nucleus.
C. electrons closest to the nucleus.
D. protons on the outer edge of the nucleus.
Answers
The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.
Option A.
What is atom?An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).
The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.
Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.
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At t = 0, one toy car is set rolling on a straight track with initial position 13.0 cm, initial velocity -3.6 cm/s, and constant acceleration 2.20 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 11.5 cm, initial velocity 5.40 cm/s, and constant zero acceleration. (a) At what time, if any, do the two cars have equal speeds? (Enter NA if the cars never have equal speeds.) s (b) What are their speeds at that time? (Enter NA if the cars never have equal speeds.) cm/s (c) At what time(s), if any, do the cars pass each other? (If there is only one time, enter NA in the second blank. If there are two times, enter the smaller time first. If they never pass, enter NA in both blanks.) s s (d) What are their locations at that time? (If there is only one position, enter NA in the second blank. If there are two positions, enter the smaller position first. If they never pass, enter NA in both blanks.) cm cm (e) Explain the difference between question (a) and question (c) as clearly as possible.
Answers
Answer:
that's too much to read
Cheetah mothers perform a number of different behaviors. They and their cubs stay in one place for only four days, moving on before they leave too strong a smell behind in one area. They also expend time and energy teaching their cubs to hunt successfully. In one or two sentences, explain how these behaviors affect cheetah reproductive success.(2 points)
Answers
Answer:
Cheetah cubs are in danger from predators like lions and hyenas which can track their prey by scent and so the mother and her cubs leave an area when their scent is too strong so that they are not hunted and the cubs survive.
Mother Cheetahs also train their cubs to hunt so that they may get food for themselves which will ensure their survival as well thus showing that both of these practices can impact on reproductive success.
determine energy of absorbed photon.
Answers
The energy of an absorbed photon is \(2.998 * 10^8\) and the resulting unit for energy is Joules (J).
To determine the energy of an absorbed photon in electronvolts (eV), we can use the equation E = hv, where E represents energy, h is Planck's constant, and v is the frequency of the photon. By substituting the values and units correctly, we can calculate the energy in electronvolts.
To determine the energy of an absorbed photon, one can use the following formula:
energy of absorbed photon = Planck's constant x frequency of radiation
Where Planck's constant is equal to \(6.626 * 10^{-34\) Joule seconds and frequency of radiation is measured in Hertz (Hz).
The energy of an absorbed photon can also be expressed using the wavelength of the radiation instead of its frequency.
The formula for this is:energy of absorbed photon = Planck's constant x speed of light / wavelength of radiation
Where the speed of light is equal to \(2.998 * 10^8\) m/s.In both cases,
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Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.
Answers
1,401.88 N is the required weight of the man using the given conversion factor.
Determining the weight of an objectTo calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:
314 pounds ÷ 2.2 pounds/kg = 142.73 kg
Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):
Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N
The required weight in Newton of the man is 1,401.88 N
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