Answer:
A person's weight will be slightly less at the top of a mountain than at the base. This is because the force of gravity is slightly weaker at higher altitudes. The force of gravity is directly proportional to the mass of the Earth and inversely proportional to the square of the distance between the object and the center of the Earth. Since the person is farther away from the center of the Earth at the top of the mountain, the force of gravity is slightly weaker. This means that the person will weigh slightly less.
The amount of weight loss is very small, and it is not something that most people would notice. However, it is a real effect, and it can be measured. In fact, scientists have used this effect to measure the mass of the Earth.
As a student studying in South Korea, what changes you think must be made in the education system to make it better?
Explanation:
studying hard is the only thing that could make the educational system better
I think the student when he studying first time then first he want to speak Korean and study hard for that but if he try then only he can be better
Explanation:
and he or she should have interest to study if he or she have interest then only their education will be better
and if he / she didn't have interest on study then we can't do anything........
Input voltage= transformer 115v show that output voltage is 20v approximately
The transformer is a step down transformer as we have been shown in the data.
What is the step down transformer?The question is incomplete as the complete data is not shown. However, we can see that this is a step down transformer as the output voltage is less than the input voltage.
In a step-down transformer, the number of turns in the secondary coil is less than the number of turns in the primary coil. This results in a decrease in the voltage of the AC supply at the output of the transformer.
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How does the energy stored in a capacitor change, as the capacitor remains connected to a battery, if the separation of the plates is doubled? How does the energy stored in an isolated capacitor change if (a) the potential difference is doubled, or (b) the separa- tion of the plates is doubled? A huge 4.0-F capacitor has enough stored energy to heat 2.8 kg of water from 21°C to 95°C. What is the potential difference across the plates?
Connected capacitor: doubling plate separation has no energy effect. Isolated capacitor: separation decreases by 4x, doubling potential difference increases energy by 4x. Specific heat capacity needed for 4.0-F capacitor's potential difference heating water.
(a) In an isolated capacitor, if the separation of the plates is doubled, the capacitance (C) is halved (C' = C/2). The energy stored in a capacitor is given by the formula U = (1/2)CV², where U is the energy, C is the capacitance, and V is the potential difference. Thus, if the separation is doubled, the new energy stored becomes U' = (1/2)(C/2)V² = (1/4)CV², resulting in a decrease by a factor of 4.
(b) When the potential difference (V) across the plates of an isolated capacitor is doubled, the energy stored becomes U' = (1/2)CV'², where V' is the new potential difference. Doubling the potential difference yields U' = (1/2)C(2V)² = 4CV², which represents an increase by a factor of 4.
Determining the potential difference across the plates of a 4.0-F capacitor that can heat 2.8 kg of water requires additional information such as the specific heat capacity of water and the amount of energy needed to heat the water from 21°C to 95°C.
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electromotive force in a circuit;
A) causes free electrons to flow
B) increases the circuit resistance
C) maintains circuit resistance
D) it needed to make the circuit complete
Answer:
A causes free electrons to flow
Explanation:
The amount of force that causes electrons to flow in a conductor is called electromotive force.
The particles of a substance in which state of matter have the least energy?
A. Liquid
B. Solid
C. Gas
D. Vapor
Answer:
B. Solid
Explanation:
Solid particles have the least amount of energy, and gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles. A change in phase may occur when the energy of the particles is changed. There are spaces between particles of matter.
hope i helped have a great day
Answer:
B. Soild
Explanation:
I dont feel like explaning (:
Which of the following types of vehicles would have the lowest tailpipe emissions?
A) gasoline-electric hybrid
B) plug-in hybrid
C) fully electric
D) gas-powered conventional
E) high-efficiency diesel -----C
Among the vehicle types listed, fully electric vehicles would have the lowest tailpipe emissions. The correct option is (C).
Gasoline-electric hybrids (A) use a combination of a gasoline engine and an electric motor, which helps reduce emissions compared to conventional gas-powered vehicles (D). However, they still produce some tailpipe emissions as they partly rely on gasoline combustion.
Plug-in hybrids (B) offer further emissions reduction as they can be charged and driven solely on electricity for a limited range before switching to the hybrid gasoline-electric mode. While their overall emissions are lower than gasoline-electric hybrids, they still emit tailpipe emissions when operating in hybrid mode.
High-efficiency diesel vehicles (E) can have improved fuel economy compared to conventional gas-powered vehicles, but they still emit tailpipe emissions, including particulate matter and nitrogen oxides, which can be harmful to the environment and human health.
In contrast, fully electric vehicles (C) have no tailpipe emissions, as they do not have an internal combustion engine and run entirely on electricity stored in their batteries. They are considered zero-emission vehicles, contributing to cleaner air and reduced greenhouse gas emissions.
However, it's essential to consider the source of electricity generation for charging, as it can impact the overall emissions associated with electric vehicle use. Using renewable energy sources for charging can further minimize environmental impacts. Thus, the correct option is C.
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A 0.045-kg golf ball is dropped from rest. Is dropped from a height of 1.3m and comes back up at a height of .7m
The time to drop from 1.3m and velocity after height at 0.7 mis mathematically given as
t1 = 0.515 sec
v0 = 3.7m/s
What is the time to drop from 1.3m and velocity after height at 0.7?Question Parameters:
A 0.045-kg golf ball is dropped from rest.
Is dropped from a height of 1.3m and comes back up at a height of .7m
Generally, the equation for the time to drop from 1.3m is mathematically given as
yf - yi = vi t + a t^2/ 2
Therefore
0 - 1.3 = 0 - 9.8 t^2 /2
t1 = 0.515 sec
Hence, after its max height is 0.7 m,
vf^2 - vi^2 = 2 a (yf - yi)
0^2 - (v0)^2 = 2(-9.8)(0.7 - 0)
v0 = 3.7m/s
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Can you help me on this please
Answer: the water level would rise since the pebble displaces minimal water compared to the boat.
Explanation:..........
A solid cylindrical disk has a radius of 0.15 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 50-N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 110 rad/s2. What is the mass of the disk?
Answer:
Torque = I α = 1/2 M R^2 α where α is the angular acceleration
Torque = F R where F is applied to a distance R from center
F R = 1/2 M R^2 α
M = 2 F / (R α) = 2 * 50 / (.15 * 110) = 6.06 kg
Do you believe that there should be no age limit in ballroom dancing?
Answer:
There should be a certain age limit Idon't know
Explanation:
1. Two charged spheres are held a distance r apart, as shown in the figure below. Compare
the force of sphere A on sphere B with the force of sphere B on sphere A.
A.
B.
C.
D.
Sphere A
+3aC
FA on B-FB on A
3FA on B-9FB on A
9FA on B = -3FB on A
FA on B=-6FB on A
he
+9 MC
Sphere B
the two changes
horos
Answer:
F = K Qa Qb / R^2
The forces are equal - the same on each sphere
Suppose the force was repulsive, for simplicity, obviously a string holding them together would have the same tension in both directions
A 3 kg block is sliding across a horizontal surface. The initial speed of the block is 4 m/s, but because of friction the block's speed will decrease at a constant rate (i.e., constant acceleration) until the block finally comes to a stop after sliding 8 m. What is the average power (in W) supplied by friction as the block slows to a stop?
The average power supplied by friction as the block slows to a stop is **6 W**. To find the average power supplied by friction, we can use the formula Power = (Work done) / (Time taken).
First, we need to find the work done by friction. The work done is equal to the change in kinetic energy. Since the block starts with an initial speed and comes to a stop, its change in kinetic energy is:
ΔKE = KE_final - KE_initial = 0 - (1/2) * m * v_initial^2
Substituting the given values:
ΔKE = - (1/2) * (3 kg) * (4 m/s)^2 = -24 J
Next, we need to determine the time taken to cover the given distance. The average speed of the block can be calculated using the formula:
Average Speed = (Initial Speed + Final Speed) / 2
Since the final speed is 0 m/s, the average speed is:
Average Speed = (4 m/s + 0 m/s) / 2 = 2 m/s
Time taken to cover 8 m at an average speed of 2 m/s:
Time = Distance / Speed = 8 m / 2 m/s = 4 s
Now, we can calculate the average power:
Power = (-24 J) / (4 s) = -6 W
Since power cannot be negative in this context, we take the absolute value, resulting in an average power of 6 W.
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Help me pleaseee, it’s due today: Two people push on a large gate as shown on the view from above in the diagram. If the moment of inertia of the gate is 90 kgm2, what is the resulting angular acceleration of the gate?
Answer:
the angular acceleration of the gate is approximately 1.61 \(\frac{rad}{s^2}\)
Explanation:
Recall the formula that connects the net torque with the moment of inertia of a rotating object about its axis of rotation, and the angular acceleration (similar to Newton's second law with net force, mass, and linear acceleration):
\(\sum \tau_1=I\,\alpha\)
In our case, both forces contribute to the same direction of torque, so we can add their torques up and get the net torque on the gate:
\(\tau_{net}=(20*2+30*3.5) \,N\,m=145\,\,N\,m\)
Now we use this value to obtain the angular acceleration by using the given moment of inertia of the rotating gate:
\(\sum \tau_1=I\,\alpha\\145\,\,N\.m=(90\,\,kg\,m^2)\,\alpha\\\alpha= \frac{145}{90} \frac{rad}{s^2} = 1.61\, \frac{rad}{s^2}\)
Which of the following describes the correct order of energy conversions necessary to form electricity from solar panels?
Solar Heat Kinetic → Electric
Solar- Kinetic Heat → Electric
Solar 1 Heat → Electric
O Solar ->Electric
Answer:
hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9
A 2.5 –g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree’s trunk. What force was exerted on the bullet in bringing it to rest?
Answer:
A 2.5 g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree's trunk. What is the initial kinetic energy of the bullet? 153.125 J Correct: Your answer is correct.Jan 8, 2020
Explanation:
A 0.0225 T magnetic field points
directly east. A loop of area 0.0471 m2
faces directly north. What is the
magnetic flux through the loop?
Answer:
0
Explanation:
acellus
what its average distance (semimajor axis) from the sun?
The dwarf planet Eris orbits the Sun every 557 years. The average distance (semimajor axis) from the Sun is 67.7 a.u.
A line segment that passes through the center and periphery foci and terminates at the broadest points of the perimeter is known as an ellipse's main axis in geometry. The semi-major axis goes from the center via a focus and out to the periphery since it is one of the main axes. In essence, it is the radius of an orbit at its two farthest points. The radius serves as the semi-major axis for the unique instance of a circle. The semi-major axis can be compared to the long radius of an ellipse.
A line segment associated with most conic sections, such as ellipses and hyperbolas, and which forms right angles to the semi-major axis is known as the semi-minor axis (a semi-minor axis).
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o
10 points
What is the period of a pendulum consisting of a 6-kg object oscillating
on a 4-m string? *
0.25 s
2 s
O O O
35
45
A mass-spring system makes 20 complete oscillations in 5 seconds. What 10 points
is the period and frequency of the oscillations? *
Hi there!
1.
The period of a pendulum can be calculated using the following equation:
\(\large\boxed{T = 2\pi \sqrt{\frac{L}{g}}}\)
T = period (s)
L = length of string (m)
g = acceleration due to gravity (m/s²)
Plug in the values:
\(T = 2\pi \sqrt{\frac{4}{9.8}} = \boxed{4.014 s}\)
2.
Calculate the period:
\(T = \frac{\text{Time}}{\# of oscillations} = \frac{5}{20} = \boxed{0.4 s }\)
Frequency is the reciprocal of the period, so:
\(f = \frac{1}{T} = \frac{1}{0.4} = \boxed{2.5 Hz}\)
An 85 kg construction worker has 37,485J of gravitational potential energy. To the nearest whole number,
worker is _________
mabove the ground
Answer:
45m above the ground
Explanation:
got it right on Edg 2020
a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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Which one of these are considered as mechanical energy?
Chemical energy
Nuclear energy
Thermal energy
Radiant energy
Electrical energy
gravitational potential energy
rotational kinetic energy
translational kinetic energy
elastic potential energy
Answer:
gravitational potential energy
Explanation: Hope it helps you:)))
have a good day
Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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in a particular wire in a circuit, conventional current flows in the z direction. what is the direction of electron current in the wire? electron current i flows in the ---select--- direction.
In a particular wire in a circuit, if conventional current flows in the z direction, the direction of electron current in the wire would be in the opposite direction, which is the -z direction.
To understand this concept, let's start with the understanding that in a wire, electrons are the charge carriers. When a voltage is applied to the circuit, the electrons will flow from the negative terminal of the voltage source to the positive terminal.
However, the conventional current flow assumes the opposite direction. It is defined as the flow of positive charges from the positive terminal to the negative terminal of the voltage source. This convention was established before the discovery of the electron, when it was believed that positive charges were the mobile charge carriers.
So, in the wire where conventional current flows in the z direction, the electrons actually flow in the opposite direction, which is the -z direction.
In conclusion, in a wire where conventional current flows in the z direction, the electron current flows in the opposite direction, which is the -z direction.
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An electric field of constant magnitude ???? is tangent everywhere to a curved surface of area ????. What is the electric flux through the curved surface?a) Zerob) EAc) –EAd) 2EAe) Not enough information
The electric flux through the curved surface is given by Φ = EA, which is option (b).
The electric flux through a closed surface is defined as the total electric field passing through that surface. In this case, we have a curved surface with a constant electric field tangent to it.
The formula for electric flux is given by Φ = ∫E⋅dA, where Φ is the electric flux, E is the electric field, and dA is the differential area vector.
Since the electric field is tangent to the surface, we can write E⋅dA = E dA cosθ, where θ is the angle between the electric field and the differential area vector. Since the electric field and the differential area vector are parallel, θ = 0, and cosθ = 1. Thus, E⋅dA = EdA.
The integral then simplifies to Φ = E ∫dA = EA, where A is the total area of the curved surface.
Therefore, the electric flux through the curved surface is given by Φ = EA.
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The voltage waveform in the given figure is applied across a 55-μf capacitor
Answer:
Explanation:
A capacitor is an electronic component that stores and releases electrical energy. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied across the plates, charge accumulates on them, creating an electric field between the plates.
The capacitance of a capacitor is a measure of its ability to store charge. It is typically represented by the symbol 'C' and is measured in farads (F). In your case, you mentioned a 55-μF (microfarad) capacitor, indicating its capacitance value.
When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The rate at which the capacitor charges and discharges depends on the capacitance and the resistance in the circuit
Since there is no figure provided in the text, I am unable to reference it for the specific details of the voltage waveform. However, I can explain the general behavior of a capacitor when a voltage waveform is applied.
When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The behavior of the capacitor is determined by its capacitance, which is given as 55 μF in this case.
As the voltage waveform varies, the capacitor stores and releases electrical charge. During the rising portion of the waveform, the capacitor charges and accumulates energy. During the falling portion, the capacitor discharges and releases the stored energy.
The exact behavior and characteristics of the voltage waveform and the charging/discharging process depend on the specific shape and frequency of the waveform. Without the specific details of the voltage waveform provided in the figure, it is challenging to provide a more detailed analysis.
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What do you think it would be like to live in a binary star system? If Earth was to orbit around two stars, what might be different on Earth?
Binary stars certainly have habitable zones where liquid water may exist on the planet's surface but it may be difficult for life to gain a foothold. Colder than 16 degrees Fahrenheit minus 100 degrees on Earth.
Orbital binaries are planets orbiting two stars instead of one star. Two stars orbit each other in a binary star system, but planets usually orbit farther from the center of the system than either star but can be in stable orbits around one of the stars in the binary system. A planet is known.
No planet in a binary system is likely to have the stable orbits necessary for the evolution of life. Earth is probably very rare in that it has a stable orbit at just the right distance from a benign star and maintains that orbit for the required 4.5 billion years. We say that planets orbit stars, but that's not entirely true. Planets and stars actually orbit around a common center of gravity. This common center of gravity is called the centroid.
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Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1. 2 m high. Student 2 pushes an identical box up a 5 m ramp from the floor to the top of the same table. Which student did the MOST work?.
The student 2 did the MOST work because he pushed the box to a greater height.
The given parameters:
Force applied by Student 1 = 500 NHeight of table for student 1 = 1.2 mHeight of ramp for student 2 = 5 mThe work done by student 1 is calculated as follows;
Work = P.E = mgh
P.E = 1.2mg
The work done by the student 2 is calculated as;
P.E = 5mg
where;
m is the mass of the boxThus, we can conclude that the student 2 did the MOST work.
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A particle in uniform circular motion requires a net force acting in what direction? A. Towards the center of the circle. B. In the direction of velocity. C. Opposite the direction of the velocity. D. Away from the center of the circle. E. Upward. F. Downward
A particle in uniform circular motion requires a net force acting towards the center of the circle. So option A is correct.
The net force acting on a particle moving in a circular path is always directed towards the center of the circle. The motion of a particle in a circular path is characterized by the direction of its velocity and acceleration at each instant in time. These two vectors are always perpendicular to each other.The magnitude of the net force required to keep a particle in uniform circular motion depends on the mass of the particle and its velocity, as well as the radius of the circular path it is following. This force is referred to as the centripetal force and is always directed towards the center of the circle.The centripetal force is provided by some other object, such as a string or a gravitational field, which acts to pull the particle towards the center of the circle. Without this force, the particle would continue to move in a straight line tangent to the circle, rather than in a circular path.Therefore option A is correct.
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state two reasons why the rod is not in equilibrium
Answer:
For equilibrium the net torque on the rod must be zero. So the 100N forces should on either side of the pivot point i.e. one on the left and one the right, and in same direction.
first make a substitution and then use integration by parts to evaluate the integral. (use c for the constant of integration.) x ln(5 x) dx
∫xln(5+x)dx
u = ln(5+x) , dv = xd
du = (1/5+x)dx , v = x2/2
∫xln(5+x)dx = ln(5+x).x2/2 -∫ x2/2 .1/5 dx
=x2ln(5+x)/2 - 1/2 ∫[(x-5) + 25/5+x] dx
=x2ln(5+x)/2 - 1/2 (x2/2 - 5x + 25ln[5+x]) + c
=1/2 (x2 - 25) ln(5+x) - 1/4.x2 +5/2.x+c
In calculus, and more generally in mathematical analysis, integration by parts or partial integration is a process that finds the integral of a product of functions in terms of the integral of the product of their derivative and antiderivative
Integration by parts is a special method of integration that is often useful when two functions are multiplied together, but is also helpful in other ways
∫ udvdx dx = uv − ∫ vdu dx dx. This is the formula known as integration by parts.
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