To find the velocity at t=4.0s, we can integrate the given acceleration function with respect to time. The integral of 5.0t with respect to t is (5/2)t².
At t=2.0s, the velocity is +17 m/s.
So, we can substitute t=2.0s and
v=17 m/s into the equation (5/2)t² to find the constant of integration.
Using the equation (5/2)t² + C = v, we can solve for C:
(5/2)(2.0²) + C = 17
C = 17 - 10
C = 7
Now, we can find the velocity at t=4.0s by
substituting t=4.0s into the equation (5/2)t² + C:
(5/2)(4.0²) + 7 = 40 + 7 = 47 m/s
Therefore, the velocity at t=4.0s is 47 m/s.
To obtain the velocity as a function of time, we already have the equation (5/2)t² + C.
We can write this as v(t) = (5/2)t² + 7, where v(t) represents the velocity at any given time t.
The particle changes direction when its velocity changes sign. In this case, the particle changes direction when the velocity changes from positive to negative or from negative to positive. Since the velocity function v(t) = (5/2)t² + 7 is a quadratic function, the vertex of the parabola represents the point where the velocity changes sign.
To find the time when the velocity changes sign, we can set v(t) = 0 and solve for t:
(5/2)t² + 7 = 0
(5/2)t² = -7
t² = -14/5
Since we cannot take the square root of a negative number in real numbers, the particle never changes direction.
The slowest speed occurs when the velocity is zero. To find when the velocity is zero, we can set v(t) = 0 and solve for t:
(5/2)t² + 7 = 0
(5/2)t^2 = -7
t^2 = -14/5
Since t² is negative, there are no real solutions for t. This means the velocity never reaches zero, so there is no slowest speed.
To find where the particle is at t=5s, we need to find its position.
We can integrate the velocity function v(t) = (5/2)t² + 7 with respect to t to find the position function.
The integral of (5/2)t² + 7 with respect to t is (5/6)t³ + 7t + D.
At t=2.0s,
The position is x=-6m.
So, we can substitute t=2.0s and x=-6m into the equation (5/6)t³ + 7t + D to find the constant of integration.
Using the equation (5/6)t³ + 7t + D = x, we can solve for D:
(5/6)(2.0³) + 7(2.0) + D = -6
(5/6)(8) + 14 + D = -6
20/3 + 42/3 + D = -6
62/3 + D = -6
D = -6 - 62/3
D = -20/3
Now, we can find the position at t=5.0s by substituting t=5.0s into the equation (5/6)t³ + 7t + D:
(5/6)(5.0³) + 7(5.0) - 20/3 = 208.33 - 20/3
Therefore, at t=5.0s, the particle would be at a position of approximately 187.67 meters.
In conclusion,
1) The velocity at t=4.0s is 47 m/s.
2) The velocity as a function of time is v(t) = (5/2)t² + 7.
3) The particle does not change direction.
4) The particle does not have a slowest speed.
5) At t=5.0s, the particle would be at a position of approximately 187.67 meters.
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An E-M wave is a transverse wave in which amplitude changes in the electric and magnetic fields are perpendicular to the direction of wave propagation. True or false ?
a) True
b) False
Answer:
True
Explanation:
An E-M wave is a transverse wave in which amplitude changes in the electric and magnetic fields are perpendicular to the direction of wave propagation.
What is an E-M wave?An electromagnetic (E-M) wave is a type of wave that consists of oscillating electric and magnetic fields.
These waves are transverse, which means that the direction of the wave is perpendicular to the direction of the wave's propagation.
The amplitude of the electric and magnetic fields of an E-M wave changes as it moves through space.
This change is perpendicular to the direction of the wave's propagation, making E-M waves transverse waves.
These waves have a wide range of frequencies, and they are used in everything from radio and television broadcasts to cellular communication and GPS systems.
Therefore, we can conclude that the given statement is True. An E-M wave is a transverse wave in which amplitude changes in the electric and magnetic fields are perpendicular to the direction of wave propagation.
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Describe something Joule believed that contradicted the beliefs of his peers.
Answer:
Joule, a 19th-century physicist, believed in the conservation of energy, which contradicted the beliefs of his peers at the time. His contemporaries believed that energy was a substance that could be created or destroyed. In contrast, Joule believed that energy could only be transformed from one form to another but could never be created or destroyed. He demonstrated this through a series of experiments where he showed that heat and mechanical work were equivalent forms of energy and that the total amount of energy in a closed system remained constant.
Joule's ideas challenged the established scientific beliefs of his time. They paved the way for the development of the first law of thermodynamics, which states that the total energy in a closed system is constant and cannot be created or destroyed. By proposing and demonstrating these ideas, Joule made significant contributions to the development of classical physics and helped lay the foundations of modern energy science.
Answer:
James Prescott Joule was a 19th-century British physicist who made significant contributions to the study of thermodynamics. One of his beliefs that contradicted the beliefs of his peers was the idea that heat was a form of energy.
At the time, the prevalent belief was that heat was a fluid-like substance called "caloric" that flowed from hot objects to cold objects. Joule challenged this idea and proposed that heat was actually a form of energy that could be transformed into other forms of energy, such as mechanical energy.
Joule's work showed that heat was a conserved quantity, much like energy, and that it could be quantified in terms of work done. This was a significant departure from the prevailing ideas of the time and helped lay the foundation for the study of thermodynamics.
A train is traveling at a speed of 80km/h when the conductor applies the brakes. The train slows with a constant acceleration of magnitude of 0.5 m/s^2. We want to find the distance the train travels from the time the conductor applies the brakes until the train comes to a complete stop. Which kinematic formula would be most useful to solve for the target unknown?
Answer:
d = 493.72 m
Explanation:
Given that,
Initial velocity of the train, u = 80 km/h = 22.22 m/s
Acceleration of the train, a = -0.5 m/s² (negative as it slows down)
Finally brakes are applied, v = 0
We need to find the distance the train travels. Let the distance be d. Using third equation of kinematics to find it.
\(v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(22.22)^2}{2\times (-0.5)}\\\\d=493.72\ m\)
So, the required distance is equal to 493.72 m.
write the merits and demerits of ultraviolet rays
Review the following situations and determine whether each is an elastic collision or an inelastic collision. Choose the situations that are elastic collisions. Select all that apply.
A. Momentum is conserved; kinetic energy is not.
B. A moving hockey puck strikes one at rest; the objects exchange velocity.
C. Momentum and kinetic energy are conserved.
D. A collision between a volleyball and a basketball occurs; there is no deformation.
E. After a collision, objects are stuck together, moving together.
Answer:
Your answer would be D.
when a coil is carrying a current of 25.0 a that is increasing at 145 a/s the induced emf in the coil has magnitude 3.70 mv . find the self-inductance of the coil.
Self-inductance of the coil is calculated as 25.5 µH.
What is self inductance?The tendency of a coil to resist changes in current is called self-inductance. Whenever current changes in a coil, they induce an EMF, that is directly proportional to the rate of change of current through the coil.
Induced emf in a inductor is given by equation,
E = L * di/dt
where,
E is the voltage of the circuit which is given 3.70mv= 0.0037v
Also given, current = 25A, di/dt = 145
L -- inductance of the circuit.
0.0037 = L * 145
L = 0.0037 / 145
L = 0.0000255
L = 25.5 µH
Self-inductance of the coil = 25.5 µH
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As we have learned the Bernoulli Principle plays an important role in the process of phonation. Simply put, the Bernoulli Principle states that an increase in the speed of a fluid (in this case, exhaled air) through a constriction occurs simultaneously with a decrease in air pressure surrounding the constriction. This theory plays an important part in one theory of phonation, the myoelastic aerodynamic theory.
For this discussion, please describe, in paragraph form and in stepwise fashion, how the Bernoulli Principle acts on the vocal folds during phonation. Begin your discussion with air exhaled from the lungs to initiate phonation and end with cessation of vocal fold vibration. Support your description of this process using the myoelastic aerodynamic theory of phonation.
During phonation, the Bernoulli Principle, as described by the myoelastic aerodynamic theory, influences the vibration of the vocal folds in the following step wise fashion:
Bernoulli Principle plays an important role in the process of phonation:
Air exhalation: The process begins with the exhalation of air from the lungs, which passes through the trachea and reaches the larynx.
Constriction at the glottis: As the exhaled air enters the larynx, it encounters the glottis, the narrow opening between the vocal folds. The vocal folds consist of elastic tissues supported by muscles.
Vocal fold adduction: Under the influence of muscle contractions, the vocal folds come together, causing adduction or closure of the glottis. This closure creates a narrow passage for the exhaled air to pass through.
Air pressure drop: As the exhaled air passes through the narrowed space between the adducted vocal folds, its speed increases due to the constriction. According to the Bernoulli Principle, an increase in the speed of a fluid (in this case, the exhaled air) through a constriction is accompanied by a decrease in air pressure surrounding the constriction.
Vocal fold vibration: The drop in air pressure above the vocal folds creates a suction force, pulling the vocal folds inward and causing them to vibrate. The myoelastic component of the theory states that the vocal folds are elastic and have a natural tendency to return to their resting position after being stretched. As the air passes through the glottis, the vocal folds are pushed apart momentarily, allowing the airflow to resume.
Repeated vibration: This cycle of vocal fold adduction, air pressure drop, vibration, and temporary separation repeats rapidly, resulting in the production of sound waves. The frequency and pattern of vocal fold vibration determine the pitch and phonetic quality of the voice.
Phonation control: The pitch and loudness of the voice can be controlled by altering the tension and positioning of the vocal folds. Muscular adjustments in the larynx regulate the degree of adduction and tension, allowing for variations in voice production.
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Sky divers jump out of a plane at an altitude of 6000 m. How much time will pass until they deploy their parachutes at an
altitude of 1260 m? Assume that air resistance is negligible.
t = _____ s
Displacement of diver , d = 6000-1260 = 4740 m.
Let, time taken be t .
By equation of motion :
\(v^2-u^2=2gs\\\\v=\sqrt{2gs}\\\\v=\sqrt{2\times 9.8\times 4740}\ m/s\\\\v=304.8\ m/s\)
Now , by equation :
v = u +gt
304.8 = 0 + 9.8t
t = 31.1 seconds
Hence, this is the required solution.
estimate the overall resistance of a heating element which is 220 cm long and consists of nichrome wire with a diameter of 0.56 mm. the resistivity of nichrome is 110x10-8 ω•m.
The estimated overall resistance of the heating element is approximately 0.99 Ω. We can use the formula for the resistance of a wire.
To estimate the overall resistance of the heating element, we can use the formula for the resistance of a wire:
R = (ρ * L) / A
where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.
Given:
Length of the wire (L) = 220 cm = 2.20 m
Diameter of the wire (d) = 0.56 mm = 0.056 cm = 0.00056 m
Resistivity of nichrome (ρ) = 110 × 10^(-8) Ω·m
First, we need to calculate the cross-sectional area (A) of the wire using the diameter:
A = π * (d/2)^2
Substituting the values:
A = π * (0.00056/2)^2
= π * (0.00028)^2
= π * 7.84 × 10^(-8) m^2
≈ 2.461 × 10^(-7) m^2
Now, we can calculate the resistance (R):
R = (ρ * L) / A
= (110 × 10^(-8) Ω·m * 2.20 m) / 2.461 × 10^(-7) m^2
= 0.99 Ω
Therefore, the estimated overall resistance of the heating element is approximately 0.99 Ω.
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If you stand near a campfire and you feel the heat without touching it, what type of thermal energy transfer is occurring?.
If you stand near a campfire and you feel the heat without touching it, Radiation transfer is occurring
What is Radiation ?One of the three methods for transferring thermal energy is thermal radiation. The other two methods require matter to transfer energy, these are conduction and convection, respectively. The only thermal energy transfer method that is independent of matter is radiation.
Electromagnetic waves make up thermal radiation, the majority of which are visible and infrared. This is given off by an object as a result of its temperature. When this radiation strikes and absorbs energy from another object, it transforms that energy into heat.
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A block of weight W is pushed to the right across a level surface at a constant velocity by a force P acting at an angle above the horizontal, as shown. The magnitude of the normal force exertedon the block by the surface is
ANSWER:
(a)
\(w+P\cdot\sin \theta\)STEP-BY-STEP EXPLANATION:
The first thing is to make the force diagram to be able to determine the answer, just like this:
Therefore, in the y-direction, we can determine the value of the normal force as follows:
\(N=w+P\cdot\sin \theta\)
A Sodium ion has a positive charge because it has
Answer:
This is because the 11 positive protons and 10 negative electrons end up with an overall charge of +1.
Explanation:
Answer:
One electron in it's outer shell
difference between uniform velocity and variable velocity
Explanation:
when a body covers equal distance in equal interval of timein a specific direction it is said to have uniform velocity . when a body covers unequal distance in equal interval of time in a specified direction , it is said to have variable velocity .what are some factors that affect the frequency of sound
Answer:
1. direction of propagation of sound
2.medium through which sound trsnsmitted
can a negatively-charged electroscope be used to determine whether an object is positive or negative? explain.
Indeed, through a method known as induction, a negatively-charged electroscope can be used to identify whether an object is positive or negative.
When a negatively-charged object is brought near the electroscope, the negative charges in the electroscope will be repelled by the negative charges on the object, and move to the far end of the electroscope. This will leave the near end of the electroscope with a net positive charge.
If the object is then brought into contact with the electroscope, some of the negative charges on the object will flow onto the electroscope, neutralizing the positive charge on the near end of the electroscope. However, some of the negative charges on the object will remain on the far end of the electroscope, leaving a net negative charge on the electroscope.
At this point, the electroscope has a negative charge that is due in part to the negative charges on the object. If the object is then moved away from the electroscope, the negative charges on the far end of the electroscope will be less strongly repelled, and will move back towards the near end of the electroscope. This will leave the near end of the electroscope with a net positive charge again, but the charge will be less than the original positive charge. The net charge on the electroscope after this process will depend on the initial charge on the object. If the object is positively charged, it will attract negative charges to the near end of the electroscope, leaving a net negative charge on the electroscope. If the object is negatively charged, it will repel negative charges to the far end of the electroscope, leaving a net negative charge on the electroscope.
Therefore, by observing the final charge on the electroscope after this process, one can determine whether the object is positive or negative.
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If the definition of gravity is an attractive force between two masses, why do we not feel a gravitational force between two people?
Answer: Because your mass is so much less than the mass of the Earth,
Explanation:
You can't feel your gravitational force. Because the Earth's gravity has the same pull on every object, all objects fall at the same speed (in a vacuum). On Earth, we have air. Air resistance will cause some objects to fall more slowly than others will.
Hope it helps I had this question too!
Have a good day
you see the moon almost directly in the south at 10pm. what phase is it?
Waning Gibbous is the phase of the moon when you see directly in the south at 10 pm.
What does Waning Gibbous phase mean?You might catch the moon in its waning gibbous phase between full and last quarter moon, late at night or early in the morning. It will appear less than fully lit but more than half-lit. At sunset, a full moon rises. A waning gibbous moon, on the other hand, rises later at night than a full moon. You'll see it rising over your eastern horizon between dusk and midnight local time.
A waning gibbous moon can catch you off guard if you happen to be out late at night and notice it rising strangely a few hours after sunset. When it gets close to the horizon, it'll shine red like a distorted full moon.
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Which sports are similar to the sport that you’ve chosen? How are the sports similar? How are they different?
Answer:
sports are not that simular they are just diferrent ok bud
Explanation:
Answer:
if you chose boxing..
Explanation:
Boxing is similar to any one-on-one sport where opponents go head to head. I think it’s like wrestling, karate, and mixed martial arts. The sports are similar in that they require one opponent to overtake another. They are different in how that is accomplished. For example, karate and mixed martial arts are about striking. But wrestling is about putting someone in a hold without hitting them. Boxing and wrestling have been around for a long time. I think karate has too.
When resting, a person has a metabolic rate of about 4.70x10^5 joules per hour. The person is submerged neck deep into a tub containing no 812kg of water at 23.07 degrees Celsius. If the heat from the person goes only into the water, by how much will the water temperature temperature increase after 43 minutes of immersion?
Given
Rate of metabolic rate,
\(Q=4.70\times\frac{10^5J}{hr}\)Mass of water,
\(m=812kg\)The initial temperature,
\(T=23.07^oC\)Explanation
The heat transferred in 43 minutes is given by
\(\begin{gathered} Q\times\frac{43}{60}=mc(T_f-T_i) \\ \Rightarrow4.70\times10^5\times\frac{43}{60}=812\times4180(T_f-28) \\ \Rightarrow T_f=28.099^oC \end{gathered}\)Conclusion
The temperature increase to 28.099 degC
what is the wavelength of a beam of light having a frequency of 6 × 1017 hz?
The wavelength of the light beam having a frequency of 6 × 1017 hz is 0.05 nm.
To calculate the wavelength of a light beam, we can use the formula:
λ = c/f
Where λ is the wavelength, c is the speed of light and f is the frequency of the light.
The speed of light is approximately 3 x 10^8 m/s, we can use this value to find the wavelength.
λ = c/f
λ = (3 x 10^8 m/s) / (6 x 10^17 Hz)
λ = 0.05 nm
So the wavelength of the light beam is 0.05 nm.
It's important to mention that the wavelength is inversely proportional to the frequency, meaning if the frequency is high the wavelength is short and if the frequency is low the wavelength is long.
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17.
_______ energy is energy that is stored or waiting to be used.
Mechanical
Kinetic
Electrical
Potential
Write down any four points that should be considered during household wiring
Answer:
USE RUBBER CLOVES
USE A PLIER
USE CONDUCTIVE WIRES
SWITHC OFF THE MAIN SWITCH WHILE WIRRING
Explanation:
Question 6 of 10
The bonds of the products store 27 kJ more energy than the bonds of the
reactants. How is energy conserved during this reaction?
A. The reaction uses up 27 kJ of energy when bonds break.
B. The surroundings absorb 27 kJ of energy from the reaction
system.
C. The reaction system absorbs 27 kJ of energy from the
surroundings.
D. The reaction creates 27 kJ of energy when bonds form.
Energy conserved during this reaction in this way; The reaction system absorbs 27 kJ of energy from the surroundings. Option C
what should you know about conserving or storing energy in this scenario?In the situation that has been described, it showss that the reaction is endothermic, which means it requires energy to proceed.
The bonds in the products store more energy than those in the reactants, and that extra energy has to come from somewhere, and the only explanation is that it came from the surroundings.
The energy is conserved because it is not lost or created; it is simply transferred from the surroundings to the system.
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We have is when a sound wave passes from air into
The frequency of sound waves remains the same or is unaffected when sound moves from air into water. The correct option is D
What properties of sound waves are affected when sound moves from air into water?Some properties of sound waves will change when it passes from air to water.
The wave's wavelength will lengthen when it passes through the boundary and enters the water.
Because some sound is reflected by the water's surface, the intensity of sound in the water will be lower than it was in the air.
However, because a crest moves away from the border every time a crest approaches it, the frequency will remain the same.
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Complete question:
What happens to a sound wave as it travels from air into water? (a) Its intensity increases. (b) Its wavelength decreases. (c) Its frequency increases. (d) Its frequency remains the same. (e) Its velocity decreases.
a piece of 14-gauge copper wire (meaning that it has a diameter of 1.63mm) has a resistance of 0.128 . the resistivity of copper is . what must be the length of the wire?
The length of the copper wire must be approximately 44.2 meters for it to have a resistance of 0.128 ohms, assuming a 14-gauge wire with a diameter of 1.63 mm and using the resistivity of copper.
To find the length of the wire, we can use Ohm's Law, which states that the resistance (R) is equal to the product of the resistivity (ρ), the length (L), and the cross-sectional area (A) of the wire, divided by the diameter (d) of the wire squared.
The formula can be written as:
R = ρ * (L / A)
Resistance (R) = 0.128 ohms
Resistivity of copper (ρ) = (1.68 × 10^-8) ohm-meter (at 20°C)
Diameter (d) = 1.63 mm = 0.00163 meters (converted from millimeters to meters)
We need to find the length (L) of the wire.
To calculate the cross-sectional area (A) of the wire, we can use the formula for the area of a circle:
A = π * (d/2)^2
Plugging in the values, we have:
A = 3.14159 * (0.00163 / 2)^2
A ≈ 2.08 x 10^-6 square meters
Rearranging Ohm's Law to solve for the length (L), we get:
L = (R * A) / ρ
Substituting the given values:
L = (0.128 * 2.08 x 10^-6) / (1.68 x 10^-8)
L ≈ 44.2 meters
The length of the copper wire must be approximately 44.2 meters for it to have a resistance of 0.128 ohms, assuming a 14-gauge wire with a diameter of 1.63 mm and using the resistivity of copper.
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A brick is resting on a rough incline. The friction force acting on the brick, along the incline, isA. equal to the weight of the brickB. less than the weight of the brickC. greater than the weight of the brickD. zero
When a brick (brickA) is resting on a rough incline, the friction force acting on the brick along the incline depends on a few factors. First, let's discuss the forces acting on the brick (brickA). The weight of the brick acts vertically downward due to gravity, and this force can be represented as the weight vector. We can decompose the weight vector into two components: one parallel to the incline (weight_parallel) and one perpendicular to the incline (weight_perpendicular).
The friction force acting on the brick (brickA) along the incline is opposing the component of the weight vector parallel to the incline (weight_parallel). The force of friction is determined by the product of the normal force (which in this case is equal to weight_perpendicular) and the coefficient of friction between the brick and the incline (brickC).
Now, let's analyze the given options:
A. Equal to the weight of the brick - This is incorrect, as the friction force is only equal to the weight_parallel component, not the entire weight of the brick.
B. Less than the weight of the brick - This is correct. The friction force acting on the brick along the incline is opposing the weight parallel component, which is always less than the total weight of the brick.
C. Greater than the weight of the brick - This is incorrect, as the friction force is only acting against the weight parallel component and cannot be greater than the total weight of the brick.
D. Zero - This is incorrect. Since the brick is on a rough incline, there will be a friction force acting against the weight parallel component.
So, the correct answer is B. The friction force acting on the brick along the incline is less than the weight of the brick.
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the dimension of time is t. and the dimension of length is l. in dimensional analysis, what is the dimension of an acceleration?
The dimension of acceleration is L T⁻².
In the dimensional analysis, the dimension of acceleration is L T⁻² where L stands for length and T stands for time.
Acceleration can be defined as the rate of change of velocity over time. It can also be expressed as a vector quantity that indicates the change in the speed or direction of an object.
a=v/t
where v= change in velocity (m/s) and t= time (s)
In physics, dimensional analysis is a useful tool for checking the validity of a proposed equation or law. It is a way of expressing the units of physical quantities in terms of their fundamental dimensions. This process helps to identify the correct combination of dimensions for a particular physical quantity.
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We can set up the equation:
l * √2 = 24√2
dividing both sides by √2:
l = 24
so, the length of the frame is 24 units.
Let's denote the dimensions of the frame as length (l) and width (w). since the diagonal of the frame makes a 45-degree angle with one side, we can use the properties of a 45-45-90 right triangle to find the relationship between the diagonal and the sides.
in a 45-45-90 triangle, the sides are in the ratio 1:1:√2. since the diagonal of the frame is 24√2, it is the hypotenuse of a 45-45-90 triangle.
according to the ratio, the hypotenuse (diagonal) is √2 times the length (l) of the side. since the frame is rectangular, the width (w) would be the same as the length (l).
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If the thumb and finger each squeeze with a force Ft = Ff = 10.0 N, what force do the forceps jaws exert on the plastic rod?
Express your answer to three significant figures and include the appropriate units.
Answer:
FJ = 31.48N
Explanation:
In this case you have that the torque exerted by each, thumb and finger, over the point P, is equal and opposite by the torque exerted by each Jaw.
You equal one of the torque produced by your hand, as for example, the torque of the finger, with the torque produced by one jaw:
\(\tau_F=\tau_J\\\\F_Fd_1=F_Jd_2\) (1)
FF: finger force = 10.0N
FJ: jaw force = ?
d1: distance from finger to point P = 8.50cm = 0.085m
d2: distance form the border of the Jaws to the point P = 2.70cm = 0.027m
You solve the equation (1) for FJ and replace the values of the other parameters:
\(F_J=\frac{F_Fd_1}{d_2}=\frac{(10.0N)(0.0850m)}{0.027m}=31.48N\)
The force exerted by each jaw is 31.48N
The force that the forceps jaws exert on the plastic rod will be 31.48N.
From the information given, the following can be depicted:
d1 = 8.50cm = 0.085md2 = 2.70cm = 0.027mFf = 10NFj = UnknownTherefore, the jaw force will be calculated thus:
Fj = (Ff × d1) / d2
Fj = (10 × 0.085) / 0.027
Fj = 31.48N
Therefore, the jaw force is 31.48N.
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If a paper airplane has a forward velocity of 2 m/s, but air resistance has a velocity of 1 m/s acting against the paper airplane, then what is the resultant forward velocity of the paper airplane?
Answer:
F_{resultant} = 1 [m/s]
Explanation:
These types of problems can be solved by means of relative velocities, where vectors (forces or velocities) are necessarily handled, these velocities depending on the velocity are added or subtracted.
Forces to the right are taken as positive and negative to the left.
\(F_{velocity}-F_{air}=F_{resultant}\\2-1 = F_{resultant}\\\\F_{resultant} = 1 [m/s]\)
hello! Someone please help me with this.
Explanation:
VT= 10 v
IT = V/R = 10/5= 2 A
RT= 5 ohm
PT = 20w
\( {i}^{2} \times r = {2}^{2} \times 5 = 20watts\)