a particle of mass 1.3kg is sliding down a frictionless slope inclined at 30 to the horizontal. the acceleration of the particle down the slope is

Special relativity and general relativity are both theories proposed by Albert Einstein. Special relativity deals with the laws of physics in the absence of gravity, while general relativity extends special relativity to include gravity and explains the curvature of spacetime caused by mass and energy.

Special relativity, proposed in 1905, deals with the laws of physics in the absence of gravitational fields. It introduces the concepts of time dilation and length contraction, stating that the laws of physics are the same for all observers moving at constant speeds relative to each other.

One piece of evidence supporting special relativity is the famous Michelson-Morley experiment, which failed to detect the existence of the hypothetical luminiferous aether.

On the other hand, general relativity, formulated in 1915, is an extension of special relativity that incorporates gravity. It postulates that gravity arises from the curvature of spacetime caused by mass and energy. General relativity explains the motion of celestial bodies, the bending of light in the presence of massive objects, and phenomena like black holes.

One piece of evidence supporting general relativity is the observed gravitational redshift, where light emitted from a source in a strong gravitational field is shifted to longer wavelengths.

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We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.

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The final velocity and the loss of kinetic energy is mathematically given as

Question Parameters:

Generally, the equation for the conservation of momentum   is mathematically given as

m1v1 = m2v2

(7500 + 4000) * vf = 4000 * 0.250

vf = 0.087 m/s

b)

Generally, the equation for the loss of kinetic energy  is mathematically given as

loss in kinetic energy = initial kinetic energy - final kinetic energy

Therefore

L-K.E= 0.50 * 4000 * 0.25^2 - 0.50 * (4000 + 7500) * 0.087^2

L-K.E= 81.5 J

In conclusion, the final velocity and the loss of kinetic energy

vf = 0.087 m/s

L-K.E= 81.5 J

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Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

The plates of the Earth's crust are described as  Large pieces of lithosphere that fit together like a jigsaw puzzle.

Therefore option A is correct.

What is the lithosphere?

The  lithosphere is described as the rigid, outermost rocky shell of a terrestrial planet or natural satellite.

The Earth's crust is made up of  of several large tectonic plates that move relative to one another.

These plates are made up of the rigid outer layer of the Earth called the lithosphere.

In conclusion, lithosphere is broken up into a number of pieces or plates that fit together just as  a jigsaw puzzle.

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Answer:

\(q = -461532.5 \ C\)

Explanation:

From the question we are told that

     The  electric filed is  \(E = 102 \ N/C\)  

Generally according to Gauss law

=>   \(E A = \frac{q}{\epsilon_o }\)

Given that  the electric field is pointing downward  , the equation become

    \(- E A = \frac{q}{\epsilon_o }\)

Here   \(q\) is the excess charge on the surface of the earth

          \(A\) is the surface  area of the of the earth which is mathematically represented as

     \(A = 4\pi r^2\)

Where r is the radius of the earth which has a value \(r = 6.3781*10^6 m\)

 substituting values

    \(A = 4 * 3.142 * (6.3781*10^6 \ m)^2\)

    \(A =5.1128 *10^{14} \ m^2\)

So

   \(q = -E * A * \epsilon _o\)

Here \(\epsilon_o\) s the permitivity of free space with value

          \(\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2\)

substituting values

     \(q = -102 * 5.1128 *10^{14} * 8.85 *10^{-12}\)

     \(q = -461532.5 \ C\)

Answer:

speed = distance/time

this is the equation substitute your values and get the answer....btw check you question again..

The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

⁻ΔP₁ = ΔP₂

ΔP₂ = m₂v₂ - m₂u₂

ΔP₂ = m₂(v₂ - u₂)

ΔP₂ = 3m₁(v₂ - u₂)

ΔP₂ = 3 x 3.8 x (1.7 - 0)

ΔP₂ = 19.38 kgm/s

Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The complete question is beblow

A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.

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With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.

By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.

According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.

The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

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mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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Answer:

Polishing the rough surface.

Oiling or lubricating with graphite or grease the moving parts of a machine.

Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.

Explanation:

The potential energy changes indicated by C and B involve energy lost by the surroundings. Therefore, option B is correct.

Potential energy is the energy possessed by an object due to its position or condition. It is often associated with the potential for the object to do work or undergo a change. The concept of potential energy arises from the interactions between objects or within a system.

Potential energy is converted into other forms of energy, such as kinetic energy (energy of motion) when the object or system undergoes a change or is acted upon by external forces.

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Your question is incomplete, most probably the correct answer is this:

Based on the diagram, which statement explains how energy is conserved during this chemical reaction? (A) is also gained by the surroundings. B. The potential energy changes indicated by C and B involve energy lost by the surroundings. C. The potential energy lost by the reaction system (C) is also lost by the surroundings. D. The potential energy lost by the reaction system (B) is gained by the surrounding​

Answer:206.3

Explanation:

The time that takes for a small bag of sand to reach the ground after it is released from an ascending hot-air balloon whose upward velocity is 2.25 m/s is 2.94 s.  

We can find the time that takes for the bag to reach the ground with the following equation:

\( y_{f} = y_{i} + v_{i_{y}}t + \frac{1}{2}gt^{2} \)   (1)

Where:            

\( y_{f} \): is the final height = 35.8 m

\( y_{i} \): is the initial height = 0

\( v_{i_{y}} \): is the initial velocity = 2.25 m/s

t: is the time =?

g: is the acceleration due to gravity = 9.81 m/s²

When the bag is released, it will move upward until it reaches a maximum height and then begins to fall. We can find the time that takes for the bag to reach the maximum height as follows:      

\( v_{f} = v_{i} - gt \)  (2)

Where:

\( v_{f} \): is the final velocity = 0 (at the maximum height)

\( v_{i} \): is the initial velocity = 2.25 m/s

The time is:        

\( t = -\frac{v_{f} - v_{i}}{g} = \frac{2.25 m/s}{9.81 m/s^{2}} = 0.23 s \)

This is the rise time it takes for the bag to reach the maximum height, which is equal to the fall time it takes for the bag to reach the same starting point (35.8 m above the ground), so:

\( t = 0.23 s*2 = 0.46 s \)

Now, from equation (1) we have:

\( 35.8 m = 0 + 2.25 m/s*t + \frac{1}{2}9.81 m/s^{2}*t^{2} \)    

By solving the above quadratic equation for t we have:

\( t = 2.48 s \)    

Hence, the total time is:

\( t = 2.48 s + 0.46 s = 2.94 s \)

Therefore, the time that it takes for the bag to reach the ground is 2.94 s.

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In order to find the energy stored by the car, let's use the formula below:

Where E is the electrical energy, Q is the charge and V is the potential difference (voltage).

So, for Q = 15.4 C and V = 9.16 * 10^8 V, we have:

Now, converting this energy into kinetic energy, we have:

Therefore, putting the answer with 3 significant digits, the velocity of the car would be 3980 m/s.

The displacement of a 1.5 kg mass is then determined using the formula x = F/k.  stretching a spring 2 cm from its equilibrium position need twice as much effort as stretching it a distance of x

W = 1/2kx2 = 1.96 Joules.

Actually, it requires more than twice as much labour since, as the spring extends, more power is needed to do so.

The shear strength and shear modulus of a compression spring formed of music wire with a 2mm diameter are 800 MPa and 80 GPa, respectively.

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4.24 meters is the Johns displacement.

The modification of an object's position is referred to as displacement. It is a vector quantity with a direction and magnitude. It is depicted as an arrow that moves from the starting point to the ending. For instance, if an object moves from position A to position B, its position changes.

(8m west) + (3m south) + (8m east) + (10m north) =

[ (2m west)+(8m east) ] + [ (3m south)+(10m north) ] =

[ (-2m east)+(4m east) ] + [ (-3m south)+(10m south) ] =

(2m east) + (7m south)

The North/South component and the East/West component are the orthogonal (perpendicular) components of the displacement that we currently have.

To combine these, it's time for Pythagoras:

Displacement = √[ (2m)² + (7m)² ]

Displacement = √ (4m² + 14m²)

Displacement = √18m²

Displacement = 4.24 meters Southeast.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

Day 0 to day 2: 5km/day

Day 2 to day 3: 2km/day

Explanation:

Day 0 to day 2: 10/2 = 5

Day 2 to day 3: 12 - 10 = 2

To Calculate:

The x-axis, or the days from 0 to 6, line up with the y-axis, or the distance from 0 to 24.  The point in the graph means that on that day, the turtle traveled that much distance.  For example, on the third point (2, 10), the day is 2 and the distance is 10.  To find the distance over multiple days, catalog the days in your mind and look for the points.  Then, find the difference.  For example, from day 2 (2, 10) to day 5 (5, 18), this would look like: 5 - 2 = 3, and 18 - 10 = 8, so this means that over 3 days, the turtle traveled 8 km.

Sound level in dB of the ultrasound used in medical diagnostics is approximately 99.7 dB.

Ultrasound is an imaging method that uses sound waves to produce images of structures within body.

SIL = 10 log10(I/I0)

where I is sound intensity in watts per square meter, and I0 is reference sound intensity of 1 picowatt per square meter (1 p W/m²).

SIL = 10 log10(6.87 × 10⁻² W/m² / 1 p W/m²)

= 10 log10(6.87 × 10²) + 10 log10(10¹²)

= 10 log10(6.87 × 10⁻²) + 120

1 p W/m² = 10⁻¹² W/m^2.

SIL = 10 log10(6.87 × 10⁻²) + 120

= 99.7 dB

Therefore, the sound level in dB of the ultrasound used in medical diagnostics is approximately 99.7 dB.

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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The ranking of the voltages, V₁, V₂, V₃, and V₄ in the order of decreasing voltage value is; V₂ > V₃ > V₁ > V₄

A voltage is the difference in potential or pressure that pushes or causes the flow of electric current in a circuit or conducting loop.

The current flowing through the circuit can be found using the following formula;

\(I=\dfrac{V}{R}\)

The formula for conductivity is presented as follows;

\(\sigma =\dfrac{l}{R\times A}\)

Where;

σ = The conductivity of the material

l = The length

R = The resistance to electricity

A = The cross-sectional area of the conductor

Therefore;

\(R=\dfrac{V}{I}\)

\(R=\dfrac{l}{A\times \sigma}\)

\(\dfrac{V}{I} =\dfrac{l}{A\times \sigma}\)

\(V=\dfrac{l \times I}{A\times \sigma}\)

Based on the dimensions of the cylinders, obtained from a similar question, we get;

\(V_1=\dfrac{3\cdot L \times I}{\pi \cdot D^2\times \sigma} = 3\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}\)

\(V_2= \dfrac{2\cdot L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} = \dfrac{8\cdot L \times I}{\pi \cdot D^2\times \sigma} = 8\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}\)

\(V_3=\dfrac{L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} =\dfrac{4\cdot L \times I}{\pi \cdot D^2\times \sigma}= 4\times \dfrac{L \times I}{\pi \cdot D^2\times \sigma}\)

\(V_4=\dfrac{L \times I}{\pi \cdot D^2\times \sigma} = 1\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}\)

Therefore;

V₁ = 3·V₄

V₂ = 8·V₄

V₃ = 4·V₄

The rank of the voltages in the order of decreasing value is therefore;

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The liquid's surface tension in N/m is determined as 0.25 N/m.

Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Mathematically, the formula for surface tension of a liquid is given as;

γ = F/L

γ = F/2x

where;

From Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.

F = kx

where;

The final equation for the surface tension of the liquid film becomes;

γ = F/2x

γ = kx/2x

γ = k/2

γ = (0.5 N/m) / 2

γ = 0.25 N/m

Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.

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The direction in which the 25 kg mass will move is to the Left. The correct option is A.

This is because the force pulling to the left is greater than that to the right.

The velocity of the mass after 1 second will be 0.4 m/s

The velocity of the mass after 2 seconds will be 0.8 m/s

The net force o the mass of 25 kg is given below:

Net force = 20 N - 10 N

Net force = 10 N

The velocity of the mass is given by the formula below:

Velocity = net force * time / mass

velocity after 1 second = 10 * 1 / 25

velocity after 1 second = 0.4 m/s

velocity after 2 seconds = 10 * 2 / 25

velocity after 2 seconds = 0.8 m/s

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Answer:

10m

Explanation:

let's take the acceleration as a constant throughout the complete motion...

therefore first let's find the acceleration

\(s = ut + \frac{1}{2} a {t}^{2} \\ 2 = \frac{1}{2} a {1}^{2} \\ a = 4m {s}^{ - 2} \)

then we have to find v1

apply V = u + at

v = 4×1

= 4ms^-1

lets find the distance travel by the object DURING THE TIME INTERVAL 1-2

\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 4 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s= 6m \)

then let's find the V2

\( {v}^{2} = {u}^{2} + 2as \\ {v}^{2} = {4 }^{2} + 2 \times 4 \times 6 \\ {v}^{2} = 64 \\ v = \sqrt{64} = 8m {s}^{ - 1} \)

\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 8 \times 1 + \frac{1}{2} \times 4 \times {1}^{2} \\ s = 10m \)

The distance traveled by the object during the time interval from t = 2 seconds to t = 3 seconds would be 10 meters, therefore the correct answer is option B.

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem, an object released from rest at time t = 0 slides down a frictionless incline a distance of 2 m during the time interval from t=0 seconds to t = 1 seconds.

2 = ut + 1/2*a*t²

2 = 0 + 0.5×a×1²

a = 2 / 0.5

a = 4 meters / second²

Now to find the velocity after the 2 seconds,

v = u + at

v = 0 + 4×2

v = 8 m/s

Now by using the second equation of motion,

S = ut + 1/2×a×t²

S = 8×1 + 0.5×4×1²

S = 8 + 2

S = 10 meters

Thus, The distance traveled by the object during the time interval from t = 2 seconds to t = 3 seconds would be 10 meters, therefore the correct answer is option B.

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Answer:

fair palybtgshsisuehdh

The vectors addition permits locating the perfect result for the sum of the two vectors in option B).  See attached and the vector is directed to the right and up.

Vector addition is the operation of adding or extra vectors together into a vector sum. The so-known as parallelogram regulation gives the rule for vector addition of or greater vectors. for two vectors and, the vector sum is received via placing them head to tail and drawing the vector from the loose tail to the unfastened head.

A vector is an amount or phenomenon that has impartial residences: importance and direction. The time period also denotes the mathematical or geometrical representation of the sort of quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

Vectors are used in technological know-how to describe something that has a direction and a magnitude. they're commonly drawn as pointed arrows, the length of which represents the vector's importance

Disclaimer: your question is incomplete, please see below for the complete question.

The image shows the complete question.

Which vector is the sum of vectors à and b?

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Answer:

A.

Position-time graph:

The position-time graph for the ball punted vertically will be a parabolic curve, with the vertex at the highest point of the ball's trajectory. Since the initial position is zero, the curve will go through the origin.

Velocity-time graph:

The velocity-time graph will be a straight line that starts at the initial velocity and decreases linearly until it reaches zero at the highest point of the ball's trajectory. After that, the velocity increases linearly in the negative direction until the ball hits the ground.

Acceleration-time graph:

The acceleration-time graph will be a constant negative value, representing the acceleration due to gravity.

Motion map:

A motion map is a diagram that shows the position of an object at several specific times during its motion. For the ball punted vertically, the motion map would look like this:

|O|------|-------|------|-------|------|H|

O represents the initial position, and H represents the highest point of the ball's trajectory. The "|" symbols represent the position of the ball at regular intervals of time.

B.

To find the initial velocity of the ball, we can use the hang time and the acceleration due to gravity.

Hang time = 3.8 seconds

Acceleration due to gravity = -9.8 m/s^2

At the highest point of the ball's trajectory, the velocity is zero. Therefore, we can use the following kinematic equation to find the initial velocity:

hang time = (final velocity - initial velocity) / acceleration

Solving for initial velocity:

initial velocity = final velocity - (hang time x acceleration)

final velocity = 0 m/s

hang time = 3.8 s

acceleration = -9.8 m/s^2

initial velocity = 0 - (3.8 x -9.8)

initial velocity = 37.64 m/s

Therefore, the initial velocity of the ball was 37.64 m/s.