a particle moving in a straight line with constant acceleration has a velocity of 3 ms-1 at one instant, and 5 seconds later, it has a velocity of 23 ms-1. The value of t is

Answer:

both

the cleen soap is falling on a nasty floof cleans the floor and gets dirty

Explanation:

Answer:

UH UH

Explanation:

Answer:

all are harmful to the body

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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To calculate the volume of a parallelepiped given the sides, we can use the scalar triple product. The formula for the volume of a parallelepiped with sides a, b, and c is:

Volume = |a · (b × c)|

where · represents the dot product and × represents the cross product.

Using the given sides:

a = (7, 2, 4)

b = (4, 7, 6)

c = (3, 4, 7)

First, calculate the cross product of b and c:

b × c = (7*7 - 4*4, 6*3 - 7*7, 4*4 - 2*3)

      = (49 - 16, 18 - 49, 16 - 6)

      = (33, -31, 10)

Next, calculate the dot product of a and the cross product (b × c):

a · (b × c) = 7*33 + 2*(-31) + 4*10

           = 231 - 62 + 40

           = 209

Finally, take the absolute value of the result to obtain the volume:

Volume = |209| = 209 cubic units

Therefore, the correct answer is:

209 cubic units

The expression "velocity as a function of time" refers to the change in an object's velocity over time, which can be observed by graphing the velocity against time on a graph.

Speed and time are related in the first equation of motion. V = u + at represents the first motion equation. Here, u denotes the starting velocity, a the acceleration, and t the duration, whereas v denotes the end velocity. The derivative of x with respect to time, or v(t)=ddtx, represents the instantaneous velocity of an object. It is the limit of average velocity as the time approaches zero (t). V (t) equals d d t x (t). Instantaneous velocity has a dimension of length per time, just like average velocity does.

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Answer:

F=w=ma                                                                                                                                                       OR by using equations of motions                                                                               vf=vi-at                    : a=vf-vi/t                                                              eq 1                         s=vit+1/2at squre                                                                                 eq 2                     2as=vf squre - vi squre                                                                        eq 3                                                                                                                                                                                  

Explanation:

where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.

Answer:

The deceleration is  \(a = - 76.27 m/s^2\)

Explanation:

From the question we are told that

   The height above  firefighter safety net is \(H = 14 \ m\)

   The length by which the net is stretched is \(s = 1.8 \ m\)

From the law of energy conservation

    \(KE_T + PE_T = KE_B + PE_B\)

 Where \(KE_T\) is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

   and  \(PE_T\) is the potential energy of the before jumping  which is mathematically represented at

          \(PE_T = mg H\)

and  \(KE_B\) is the kinetic energy of the person just before landing on the safety net  which is mathematically represented at

        \(KE_B = \frac{1}{2} m v^2\)

and  \(PE_B\) is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

   So the above equation becomes

          \(mgH = \frac{1}{2} m v^2\)

=>           \(v = \sqrt{2 gH }\)

    substituting values

                \(v = 16.57 m/s\)

Applying the equation o motion

             \(v_f = v + 2 a s\)

Now the final velocity is zero because the person comes to rest

      So

         \(0 = 16.57 + 2 * a * 1.8\)

            \(a = - \frac{16.57^2 }{2 * 1.8}\)

            \(a = - 76.27 m/s^2\)

Answer:

The answer is within the picture.

Explanation:

Answer:

A , D , E

Explanation:

Solution:-

- Consider the two identical objects with mass ( m ).

- The stiffness of the springs are ( k1 and k2 ).

- Both the spring store 55.0 J of potential energy.

- We will apply the principle of energy conservation on both the systems. In both cases the spring stores 55.0 Joules of energy. Once released, the objects gain kinetic energy with a consequent loss of potential energy in either spring.

- The maximum speed ( v ) is attained when all the potential energy is converted to kinetic energy.

- Apply Energy conservation for spring with stiffness ( k1 ).

                         ΔU = ΔEk

                         55.0 = 0.5*m*v^2

                         v = √ ( 110 / m )

- Apply Energy conservation for spring with stiffness ( k2 ).

                         ΔU = ΔEk

                         55.0 = 0.5*m*v^2

                         v = √ ( 110 / m )

Answer: Both objects will have the same maximum speed ( A )

- We are told that one spring is more stiff as compared to the other one. The measure of stiffness is proportionally quantified by the spring constant. To mathematically express we can write it as:

                         k1 > k2

Where,

                 k1: The stiff spring

                 k2: The flexible spring

Answer: The stiff spring has a larger spring constant than the flexible spring. ( D )

- We will assume that the spring with constant ( k1 ) undergoes a displacement ( x1 ) and the spring with constant ( k2 ) undergoes a displacement ( x2 ). The potential energy stored in both spring is the same. Hence,

                      U1 = U2

                      0.5*( k1 ) * ( x1 )^2 = 0.5*( k2 ) * ( x2 )^2

                      [ k1 / k2 ] = [ x2 / x1 ]^2

Since,

                     k1 > k2 , then [ k1 / k2 ] > 1    

Then,

                     [ x2 / x1 ]^2 > 1

                     [ x2 / x1 ] > 1

                     x2 > x1                  

Answer: The flexible spring ( x2 ) was compressed more than the stiff spring ( x1 ). ( E )

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:

1.332 N

Explanation:

Net Force = Mass x Acceleration
1.2 x 1.11 = 1.332 N

I'm so sorry if I'm wrong.

Answer: Answer is below <3 (The underlined part is the answer)

Explanation: The reason why an object with a smaller mass has a larger acceleration than an object with a larger mass if the same force acts on each is because the acceleration of an object depends on its mass as well as the force exerted on it, and if the mass is smaller than the other object than it is faster.

The reason why a football accelerates faster than a soccer ball when the same amount of force is applied is because of the difference in their masses. The acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. This means that the smaller the mass of an object, the greater the acceleration it experiences when the same amount of force is applied to it.

A football is typically smaller and lighter than a soccer ball, so when the same amount of force is applied to both balls, the football experiences a greater acceleration due to its lower mass. This is consistent with Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

Additionally, the surface area and shape of the balls can also affect their acceleration. A football is typically more aerodynamic with a pointed shape that reduces air resistance, allowing it to move through the air more easily and accelerate faster. In contrast, a soccer ball has a more spherical shape that can create more air resistance, slowing down its acceleration.

Therefore, the mass, shape, and surface area of the ball are all factors that can affect its acceleration when a force is applied.

Answer:

it depends on the wind and any other conditions but if you have a controlled environment it should take 1 second to get 40 meters but it could go higher in which it could take about 5 seconds to go 200 meters

Explanation:

hope it helped

:)

Explanation:

Q1. Given:

v = 0 m/s

a = -5.5 m/s²

t = 3.5 s

Find: Δx

Δx = vt − ½ at²

Δx = (0 m/s) (3.5 s) − ½ (-5.5 m/s²) (3.5 s)²

Δx ≈ 33.7 m

Q2. Given:

Δx = 400 m

v₀ = 7.0 m/s

v = 35 m/s

Find: a

v² = v₀² + 2aΔx

(35 m/s)² = (7.0 m/s)² + 2a (400 m)

a = 1.47 m/s²

Answer:

The color of an object is the wavelength of light that it reflects.

Answer:

v = 0.064 m/s

Explanation:

Given that,

The mass of two skaters = 75 kg

The mass of a ball = 0.4 kg

The speed of the ball = 6 m/s

The speed of skater = 6 m/s

We need to find the velocity of each of the two skaters.

Under the values given the moment with respect to the ball and which is subsequently transmitted to people it would be given by:

\(P=0.4(6)+0.4(6)\\\\=4.8\ kg-m/s\)

We know that,

P = mv

Where

v is the velocity of each skater.

\(v=\dfrac{p}{m}\\\\v=\dfrac{4.8}{75}\\\\=0.064\ m/s\)

So, the velocity of each of the skaters is 0.064 m/s.

The balloon hits the ground right before the professor gets there.

The balloon picks up speed due to gravity and we can calculate the time taken for it to fall to the ground as follows:

Gravity (g) = 9.81 m/s²

Height or distance (s) = 11 meters

Initial Speed (u) = 0 m/s

using equation of motion

\(s = ut + \frac{1}{2}at^{2}\)

where s = height

u = initial speed

a = acceleration due to gravity

t = time taken

then using above values we get

11 = 0 x 2 + 0.5 x (9.8 x t²)

t = 1.4975

So we can see that the balloon takes 1.4975 seconds to fall to the ground, and since the professor takes 2 seconds to get to that place.

The balloon hits the ground right before the professor gets there.

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The length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

Given data: r = 0.2 mm = 0.2 x 10^-3m Resistivity = 3 x 10^-6 ohm R = 15.552 ohm

Formula Used: Resistivity (ρ) = (RA)/L

Where, R is resistance, A is the area of cross-section, L is the length of the wire.

Resistance (R) = ρ (L/A)

Multiplying A on both sides, we get

Resistance (R) x A = ρ L ... equation (1)

Area of the cross-section of a wire of radius (r) is given by, A = πr^2

where, π is a constant whose value is 3.14

Substituting the given values, we get

A = πr^2= π (0.2 x 10^-3m)^2= 1.2566 x 10^-7 m^2

Substituting the values of R, A and ρ in equation (1), we get

Length of wire (L) = (Resistance x Area) / Resistivity= (15.552 ohm x 1.2566 x 10^-7 m^2) / (3 x 10^-6 ohm)= 6.5268 m

Therefore, the length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

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The models that predict galaxies should be getting farther apart now are; accelerating model, critical model,- and coasting model.

Observations show that the expansion of the universe is accelerating, such that the velocity at which a distant galaxy recedes from the observer is continuously increasing with time.

The accelerating model of the galaxies predicts that galaxies should be getting farther apart now.

From the model presented in the graph critical model of the galaxies also predict that galaxies should be getting farther apart now.

Another model that predicts that galaxies should be getting farther apart now is coasting model.

These models can be seen in the graph as they increase proportional with time. That is the distance between galaxies increase with increase in time measured in years.

Thus, we can conclude that there  models ( accelerating, critical and coasting model) predicts the relative position of the galaxies from us.

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The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Answer:

\(a=2.5\ m/s^2\)

Explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly over time.

The equation that describes the change of velocities is:

\(v_f=v_o+at\)

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

Solving the equation for a:

\(\displaystyle a=\frac{v_f-v_o}{t}\)

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.

The acceleration is:

\(\displaystyle a=\frac{7.5-0}{3}\)

\(\boxed{a=2.5\ m/s^2}\)

Answer:

zero

Explanation:

The work done is zero because the object has no displacement

Answer:

I don’t understand Espanol

Explanation:

sorry

Good energy, Bad energy, Energy used to run, Energy drinks,