The displacement at t is 525m .
Calculation :
u = initial velocity = 30 m/s
a = 30 m/s²
t = 5s
d = distance traveled in 5 seconds
v = velocity after 5 seconds
d = u.t + (1/2) at² = 30 * 5 + 30 * 52 / 2 = 525m
a displacement is a vector whose length is the shortest distance from the starting position of a moving point P to the ending position. [1] Quantify both the distance and direction of net or gross movement along a straight line from the start position to the end position of a point trajectory. A shift can be identified by a move that maps a start position to an end position.
Displacement can also be expressed as the relative position (result of movement), ie the final position xf of the point relative to the initial position xi. The corresponding displacement vector can be defined as the difference between the final position and the initial position:
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how is it possible for objects of the same volume to have different masses
Objects of the same volume can have different masses due to variations in their **density**.
Density is defined as mass per unit volume and represents how much mass is packed into a given volume. If two objects have the same volume but different densities, their masses will differ.
For example, consider two cubes of the same size, but one is made of iron and the other is made of aluminum. Iron is denser than aluminum, which means that for the same volume, the iron cube will have more mass compared to the aluminum cube.
The density of an object depends on its composition, arrangement of particles, and the forces acting between them. Different materials can have different densities due to variations in their atomic or molecular structure.
Therefore, even though objects may occupy the same volume, their masses can differ if their densities vary. It is the density of the material that determines how much mass is contained within a given volume.
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Q- A body is acted upon by two forces 30N due east and 40N due North. Calculate
resultant and its direction.
Answer:
the following image will make you understand
Explanation:
gyromagnetic ratios for 1h and 13c are 2.6752 x 108 t -1 s -1 and 6.7283 x 107 t -1 s -1 . find the resonant frequencies of these two nuclei at 3.0 t magnetic field.
To find the resonant frequencies of 1H and 13C nuclei at a 3.0 T magnetic field, we can use the formula resonant frequency = gyromagnetic ratio * magnetic field strength
For 1H, the gyromagnetic ratio is 2.6752 x 10^8 T^-1 s^-1 and the magnetic field strength is 3.0 T. Plugging these values into the formula, we get:
resonant frequency of 1H = 2.6752 x 10^8 T^-1 s^-1 * 3.0 T = 8.0256 x 10^8 Hz
For 13C, the gyromagnetic ratio is 6.7283 x 10^7 T^-1 s^-1 and the magnetic field strength is 3.0 T. Plugging these values into the formula, we get:
resonant frequency of 13C = 6.7283 x 10^7 T^-1 s^-1 * 3.0 T = 2.0185 x 10^8 Hz
The resonant frequency of 1H is 8.0256 x 10^8 Hz and the resonant frequency of 13C is 2.0185 x 10^8 Hz at a 3.0 T magnetic field.
The gyromagnetic ratio is a fundamental constant that relates the magnetic moment of a nucleus to its angular momentum. It is specific to each type of nucleus and is measured in units of T^-1 s^-1.
Resonant frequency is the frequency at which a nucleus absorbs electromagnetic radiation in a magnetic field. It is directly proportional to the gyromagnetic ratio and the magnetic field strength. In NMR spectroscopy, the resonant frequency is used to identify the type of nuclei present in a sample and to study their chemical environment.
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An object has a mass of 20kg, what is its weight on Earth?
Answer:
The formula is W=mg.
W=20×10=200.
Answer:
\(\Huge \boxed{\mathrm{200 \ N}}\)
Explanation:
\(\sf Weight \ (N)= mass \ (kg) \times acceleration \ of \ gravity \ (m/s^2)\)
\(W=mg\)
The mass of the object is 20 kg.
The acceleration of gravity is 10 m/s².
\(W=20 \times 10\)
\(W=200\)
The weight of the object is 200 N.
Identify one similarity between fission and fusion
Answer:
Both fission and fusion release large amounts of energy.
Explanation:
One or more atoms of a different weight to the reactant atom is formed in both fission and fusion reactions. There is a change in weight between the reactant (s) and product (s) in both fission and fusion reactions.
Please help me!! I will give lots of pints, rate your answer, give thanks and award you as the brainliest for the correct answer!!! :))
Answer:
a. 25 N. The box will move toward the greater force, however, I'm not too sure if that is enough to move a 100kg box.
Explanation:
First, let's define resultant force.
Resultant force is the total force of action enacted on a object or thing.
To get the resultant force of this problem, add 10 N to 15 N and you will get an answer of 25 N total.
The object will move toward the greater force because there is a larger difference between the force on the left.
A plane can fly 390 miles in the same time as it takes a car to go 120 miles. If the car travels 90 mph slower than the plane, find the speed of the plane.
thats a hella slow plane
a box is given a kick, and subsequently slides along a horizontal, frictionless surface with velocity ~v0. it then travels up a ramp inclined at an angle θ to the horizontal. there is friction between the ramp and the box.
The motion of the box further will depend on the specific details and values given for θ, v0, and μ, as well as any additional constraints or objectives in the problem.
In this scenario, the box is initially given a kick and slides along a horizontal, frictionless surface with a velocity represented by v0. Then, it travels up a ramp inclined at an angle θ to the horizontal, and there is friction between the ramp and the box.
To analyze the motion of the box, we need to consider the forces acting on it.
1. The force of gravity (mg): This force acts vertically downward and can be resolved into two components: one perpendicular to the ramp (mg * cos(θ)) and one parallel to the ramp (mg * sin(θ)).
2. Normal force (N): This force acts perpendicular to the ramp and counteracts the component of gravity that is perpendicular to the ramp (mg * cos(θ)).
3. Frictional force (f): This force opposes the motion of the box and acts parallel to the ramp. The magnitude of the frictional force can be determined using the equation f = μ * N, where μ is the coefficient of friction between the box and the ramp.
The key factors that determine the subsequent motion of the box up the ramp are the angle of the ramp (θ), the initial velocity of the box (v0), and the coefficient of friction (μ).
If the initial velocity of the box is sufficient to overcome the frictional force and propel the box up the ramp, it will continue moving upwards until the force of gravity acting along the ramp becomes greater than the force component parallel to the ramp due to the initial velocity. At this point, the box will start to slow down, eventually come to a stop, and start moving back down the ramp.
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An object has an x-momentum of 8.5 kilogram-meters/second and a -momentum of 9.8 kilogram meters/second. What Is resultänt
momentum of the object?
OA 15.5 kilogram-meters/second
OB. 14.8 kilogram-meters/second
0c 12.97 kilogram-meters/second
OD. 16.8 kilogram-meters/second
Answer:
The resultant momentum is 12.97 kg.m/s. Choice: c
Explanation:
Momentum
The momentum is a vector that measures the quantity of motion that an object has. It's also known by the term "mass in motion".
As a vector, it can be expressed by its rectangular components:
\(\vec p = p_x\mathbf{i}+p_y\mathbf{j}\)
The magnitude of the momentum is:
\(\mid \mid \vec p \mid \mid =\sqrt{p_x^2+p_y^2}\)
The object described has an x-component of:
px=8.5 Kg.m/s
And a y-component of:
py=9.8 Kg.m/s
Thus, the magnitude of the momentum is:
\(\mid \mid \vec p \mid \mid =\sqrt{8.5^2+9.8^2}\)
\(\mid \mid \vec p \mid \mid =\sqrt{72.25+96.04}\)
\(\mid \mid \vec p \mid \mid =\sqrt{168.29}\)
\(\mid \mid \vec p \mid \mid =12.97\)
The resultant momentum is 12.97 kg.m/s. Choice: c
hello please help i’ll give brainliest
Answer:
D, the lithosphere. (CRUST AND UPPER MANTLE)
Explanation:
A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere. Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest. Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).
Information found on:
https://pubs.usgs.gov/gip/dynamic/tectonic.html#:~:text=A%20tectonic%20plate%20(also%20called,both%20continental%20and%20oceanic%20lithosphere.&text=Continental%20crust%20is%20composed%20of,such%20as%20quartz%20and%20feldspar.
A series RC circuit has a resistance of 200 ohm and a capacitance of 25 mF and is driven by a 120 V, 60 Hz source. (a) Find the capacitive reactance of the circuit.
Given:
The resistance is,
\(R=200\text{ ohm}\)The capacitance is,
\(\begin{gathered} C=25\text{ mF} \\ =25\times10^{-3}\text{ F} \end{gathered}\)The applied voltage is,
\(V=120\text{ V}\)The frequency of the AC is,
\(f=60\text{ Hz}\)To find:
The capacitive reactance
Explanation:
The capacitive reactance is,
\(\begin{gathered} X_C=\frac{1}{2\pi fC} \\ =\frac{1}{2\pi\times60\times25\times10^{-3}} \\ =0.106\text{ ohm} \end{gathered}\)Hence, the capacitive reactance is 0.106 ohm.
Why do you ask me that’s all me the moon seem like they’re walking on Spring tomorrow on earth we are from your tractor to the ground???
Waves Problem set *use units*
1.A tall, thin tree sways back and forth in the breeze with a frequency of 58.0 Hz. What is the period of the tree?
2.A periodic transverse wave that has a frequency of 24.9 Hz, travels along a string. The distance between the crest and the adjacent trough is 3.4 m. What is its wavelength?
3.What is the speed of a sound wave that has a frequency of 285 Hz and a wavelength of 1.5 m?
4.A person yells across a canyon and hears the echo 5.5 seconds later. If the speed of sound is 336.0 m/s, how far away is the other side of the canyon?
5.Radio station WKLB in Boston broadcasts at a frequency of 97.1 kHz. What is the wavelength of the radio waves emitted by WKLB? ( Radio waves travel at the speed of light 3x108 m/s) ps. no decimals
6. Water waves at a lake cross a distance of 7 m in 3.9 s. The period of oscillation is 3 s. What is the speed of the water waves?
7.Water waves at a lake cross a distance of 9 m in 2.9 s. The period of oscillation is 3.1 s. What is the wavelength of the water waves?
8.One pulse is generated every 0.84 s in a tank of water. What is the frequency of the pulses?
9. One pulse is generated every 0.95 s in a tank of water. What is the speed of propagation of the wave if the wavelength of the surface wave is 1.9 cm?
10.Dog whistles are inaudible to humans because dogs can hear at much higher frequencies than humans are capable of detecting. If a dog whistle has a wavelength of 2.3 x 10-3 m, what is the frequency of sound emitted? *Sound travels at 340 m/s.
11. What is the speed of sound in air that has a temperature of 29.2 o C?
12. What is the wavelength of sound in air that has a temperature of 7.9 o C has a frequency of 40.7 Hz?
To solve problems involving waves, it's important to know the relationships between frequency, wavelength, and speed, which are given by the formulas v = f λ and T = 1/f, where v is the speed of the wave, f is the frequency, λ is the wavelength, and T is the period of oscillation.
The period of the tree is T=1/f= 1/58.0 Hz = 0.0172 s.
The wavelength of the wave is λ = 2 (crest to trough distance) = 2 (3.4 m) = 6.8 m.
The speed of the sound wave is v = f λ = (285 Hz) (1.5 m) = 427.5 m/s.
The distance to the other side of the canyon is d = (speed of sound) × (time for echo to return) / 2 = (336.0 m/s) × (5.5 s) / 2 = 924 m.
The wavelength of the radio waves emitted by WKLB is λ = c / f = 3 x 10^8 m/s / 97.1 x 10^3 Hz = 3.09 m.
The speed of the water waves is v = λ / T = (7 m) / (3 s) = 2.33 m/s.
The wavelength of the water waves is λ = v T = (2.9 s) (2.33 m/s) = 6.74 m.
The frequency of the pulses is f = 1/T = 1/0.84 s = 1.19 Hz.
The speed of the wave is v = λ / T = (1.9 cm) / (0.95 s) = 2 cm/s.
The frequency of the sound wave is f = v / λ = 340 m/s / 2.3 x 10^-3 m = 1.48 x 10^5 Hz.
The speed of sound in air at 29.2°C is v = 331 m/s + (0.6 m/s/°C) × (29.2°C) = 349.5 m/s.
The wavelength of the sound wave is λ = v / f = (331 m/s + (0.6 m/s/°C) × (7.9°C)) / (40.7 Hz) = 8.06 m.
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How does a pizza,car, and a candle cause change? Correct Answer gets Brainliest:)
What is the distance that an airplane traveling at 600 mph, moves during the time it takes to scan the instruments?, (Time is about 0.5 seconds, 5,280 ft/mi)
Answer:
d = 134.11 m
Explanation:
Speed of an airplane, = 600 mph
We need to find the distance moved in 0.5 s (to scan the instruments).
1 mph = 0.44704 m/s
It means,
600 mph = 268.22 m/s
Speed = distance/time
Distance, d = v t
d = 268.22 m/s × 0.5 s
d = 134.11 m
So, the distance moved by airplane is 134.11 m.
on average, how often do impacts large enough to produce mass extinction on the earth occur?
I don't know I can't read that sorry I mean don't understand
an asteroid is 180,000km away from the moon on a collision course. how much time will it take before the asteroid is 10km away if it is moving at a constant velocity of 36,000m/s?
Answer:
See below
Explanation:
(180 000 - 10) km / 36 km/s = 4999.7 =~ 5000 seconds = 83 .3 min
equity theory discusses individuals' perceptions about the relationship between ____ and ____.
Equity theory discusses individuals' perceptions about the relationship between inputs and outcomes. Inputs refer to the contributions an individual makes to a relationship or job, such as time, effort, skills, or resources, while outcomes are the rewards or benefits they receive in return, such as pay, recognition, status, or satisfaction.
Equity theory argues that people strive for fairness or balance in their relationships, so they compare their inputs and outcomes with those of others and assess whether they are getting what they deserve. If they perceive that they are under-rewarded or over-rewarded relative to their peers or standards, they may experience feelings of inequity, such as guilt, resentment, or envy, which can affect their motivation, performance, and well-being.
Therefore, maintaining equity in relationships is crucial for promoting satisfaction, trust, and commitment. Equity theory also suggests that individuals may restore equity by changing their inputs, outcomes, or perceptions, or by leaving the relationship altogether.
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an object that is accelerating may be
It must be either speeding up, or slowing down, or turning. There are no other possibilities.
Need help this is a grade
Answer: C
Explanation: When you have a tomato for example, it absorbs every color but red and therefore, appears red.
Which of the following statement/s is/are true? Check all that apply. Jupiter's Great Red Spot is in the southern hemisphere of the planet The fastest wind speed recorded in our solar system is on the dwarf planet Pluto Neptune's Great dark spot is in the northern hemisphere of the planet Water geyser is located on the South Pole of Saturn's Moon Enceladus The Hexagon hurricane is on the North Pole of the planet Uranus
The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.
Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.
The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.
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What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s? 10 m/s2 –15 m/s2 15 m/s2 5 m/s2
Answer:
5 m/s²
Explanation:
Acceleration = change in speed/time taken
20-5=15
15/3= 5 m/s²
You must park at least _____ away from a fire hydrant.
Answer: at least 10 feet away
Explanation:
( TRUE false )
1.)manuals are the organic matter.
2.)combine is used for sowing the seeds.
3.) the first agricultural task is sowing of seeds.
4.) many plants are first grown in Kinder Gardens and then sown in fields.
5.) earthworm are farmer friendly.
6.)substance that kills
pests are called weedicides.
7.) animals which provide us both egg and flesh are called milch animals.
8.) Grains should be dried in Sun before storage.
9.)wheat,gram,barley,potato, are kharif crops.
10.) the crops on in June /July and harvested in September/ October are called rabi crops.
plz answerzz fast
Answer:
number 6 is wrong
the answer is pesticides
2.combines are used for harvesting or threshing.so number 2 is wrong
at least you tried
Explanation:
there is no such thing as weedicides
Answer:
1. True
2.True
3.False
4. True
5. True
6.False
7.False
8.True
9.False
10.False
What does a slope of zero on a distance versus time graph show?
1. Object is not moving
2. Object does not have mass
3. Distance increasing over time
4. Distance decreasing over time
Answer: 1
Explanation: if there is no slope nothing is happening
What is the total distance, side to side, that the top of the building moves during such an oscillation
The total side to side distance at the top of the building, covered during such an oscillation is 8.4 cm.
Solution:
The height of building is, h = 152 m.
The frequency on windy days is, f = 0.17 Hz.
The acceleration on the top of building is, a = 2/100g (Here g is gravitational acceleration).
\(a = A \times \omega ^{2}\)
\(a = A \times (2\pi f) ^{2}\)
\(\frac{2}{100} \times g = A \times (2\pi \times 0.17) ^ 2\)
A = 0.042m
hence the total distance is twice the distance
that is 0.084m
What is oscillation?The recurrent or periodic change of a quantity around a central value (often an equilibrium point) or between two or more different states is known as oscillation.Alternating current and a swinging pendulum are two common examples of oscillation. Physics can employ oscillations to approximate complicated interactions, like those between atoms.To learn more about Oscillation with the given link
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Question:
The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acceleration of the top of the building can reach 2.0% of the free-fall acceleration, enough to cause discomfort for occupants. What is the total distance, side to side, that the top of the building moves during such an oscillation?
HELP!
Explain how the conservation of energy and the conservation of matter might still be considered true when put together in spite of the ability of each to convert into the other.
Answer:
the conservation of both matters because without each other the balance of nature will be destroyed it helps in such a way that the food chain will be maintained.
it is as such considered because without matter there would be no energy and the reverse is such.
it is still considered because without one another famous atomic theories wouldn't have been made such as gas, liquid and solid.
in conclusion all these work together to balance the galaxy as a whole
Both the conservation of energy and the conservation of matter is important because, without each other, the natural equilibrium will be disrupted.
What is the law of conservation of energy?According to the Law of conservation of energy. Energy can not be created nor be destroyed it can transfer from one to another form.
The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.
The conservation of both is important because without each other, the natural equilibrium will be disrupted, and it aids in the maintenance of the food chain.
It is seen as such because there would be no energy without matter and vice versa.
Hence both the conservation of energy and the conservation of matter is important
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A parallel-plate capacitor has square plates that are 7.40 cm on each side and 3.20 mm apart. The space between the plates is completely filled with two square slabs of dielectric, each 7.40 cm on a side and 1.60 mm thick. One slab is Pyrex glass and the other slab is polystyrene. If the potential difference between the plates is 84.0 V, find how much electrical energy (in nJ) can be stored in this capacitor.
Answer:
The energy that can be stored in the capacitor is 239 nJ
Explanation:
We first calculate the capacitance of each material. Let C₁ be the capacitance of pyrex glass and C₂ be the capacitance of polystyrene.
C₁ = κ₁ε₀A/d where κ₁ = dielectric constant of pyrex glass = 5, A = area of plates = L² where L = length of square plate = 7.40 cm = 7.40 × 10⁻² m and d = thickness of pyrex slab = 1.60 mm = 1.60 × 10⁻³ m and ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m
C₁ = κ₁ε₀A/d = κ₁ε₀L²/d = 5 × 8.854 × 10⁻¹² F/m × (7.40 × 10⁻² m)²/1.60 × 10⁻³ m = 2424.2252/1.60 × 10⁻¹¹ F = 1515.14 × 10⁻¹¹ F = 15.2 × 10⁻⁹ F = 15.2 nF
C₂ = κ₂ε₀A/d where κ₂ = dielectric constant of polystyrene = 3, A = area of plates = L² where L = length of square plate = 7.40 cm = 7.40 × 10⁻² m and d = thickness of polystyrene slab = 1.60 mm = 1.60 × 10⁻³ m and ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m
C₁ = κ₁ε₀A/d = κ₁ε₀L²/d = 3 × 8.854 × 10⁻¹² F/m × (7.40 × 10⁻² m)²/1.60 × 10⁻³ m = 1454.5351/1.60 × 10⁻¹¹ F = 909.08 × 10⁻¹¹ F = 9.09 × 10⁻⁹ F = 9.09 nF
Since the capacitors are in series, we find their effective capacitance C from
1/C = 1/C₁ + 1/C₂
C = C₁C₂/(C₁ + C₂)
= 15.2 × 10⁻⁹ F × 9.09 × 10⁻⁹ F/(15.2 × 10⁻⁹ F + 9.09 × 10⁻⁹ F)
= 138.168 × 10⁻¹⁸/24.29 × 10⁻⁹ F
= 5.69 × 10⁻⁹ F
The amount of electrical energy stored in a capacitor is given by W = 1/2CV² where C = capacitance and v = voltage applied. Now C = 5.69 × 10⁻⁹ F and V = 84.0 V for this capacitor
So W = 1/2 × 5.69 × 10⁻⁹ F × 84.0 V
= 238.98 × 10⁻⁹ J
≅ 239 × 10⁻⁹ J
= 239 nJ
So the energy that can be stored in the capacitor is 239 nJ
The Hubble Space Telescope is in orbit around
the Earth at a height of 560km above the Earth’s
surface. Take the radius and mass of the Earth to
be 6.4 × 106m and 6.0 × 1024kg, respectively.
a Calculate Hubble’s speed.
Answer:
Approximately \(7.6 \times 10^{3}\; {\rm m\cdot s^{-1}}\) assuming that the orbit is circular.
Explanation:
Let \(m\) denote the mass of the telescope.
The gravitational attraction from the Earth on the telescope would be:
\(\begin{aligned}F &= \frac{G\, M\, m}{r^{2}}\end{aligned}\),
Where:
\(G \approx 6.67 \times 10^{-11}\; {\rm m^{3}\, kg^{-1}\, s^{-2}}\) is the gravitational constant,\(M \approx 6.0 \times 10^{24}\; {\rm kg}\) is the mass of the Earth, and\(r\) is the radius of the orbit.In this question, the telescope is at a height of \(r = 560\; {\rm km} = 5.60 \times 10^{5}\; {\rm m}\) above the surface of the Earth. Add this height to the radius of the Earth to find the radius of the orbit:
\(\begin{aligned} r &= 5.60 \times 10^{5}\; {\rm m} + 6.4 \times 10^{6}\; {\rm m} \\ &= 6.960\times 10^{6}\; {\rm m}\end{aligned}\).
Assuming that gravitational attraction from the Earth is the only force on the telescope. The net force on the telescope would then be equal to this attraction, \((G\, M\, m) / r^{2}\).
By Newton's Laws of Motion, divide the resultant force on the telescope by its mass to find the acceleration of the telescope:
\(\begin{aligned}a &= \frac{G\, M\, m / r^{2}}{m} \\ &= \frac{G\, M}{r^{2}}\end{aligned}\).
Assuming that the telescope in a circular orbit. The telescope would be in a centripetal motion, and the acceleration of the telescope would be:
\(\displaystyle a = \frac{v^{2}}{r}\),
Where:
\(v\) is the orbital speed of the telescope, and\(r\) is the orbital radius of the telescope.Equate the two expressions for the acceleration of this telescope and solve for the orbital speed of the telescope:
\(\begin{aligned}\frac{G\, M}{r^{2}} &= \frac{v^{2}}{r}\end{aligned}\).
\(\begin{aligned} v &= \sqrt{\frac{G\, M}{r}} \\ &\approx \sqrt{\frac{(6.67 \times 10^{-11})\, (6.0 \times 10^{24})}{(6.960 \times 10^{6})}}\; {\rm m\cdot s^{-1}} \\ &\approx 7.6 \times 10^{3}\; {\rm m\cdot s^{-1}}\end{aligned}\).
To calculate Hubble's speed, we use the velocity formula for an object in circular orbit: v = sqrt(GM/r). Inserting the given and known values into the equation and calculating yields an orbital speed of approximately 7,555 m/s.
Explanation:To calculate Hubble's speed, one needs to use the formula for the speed of an object in a circular orbit. The formula is v = √(GM/r), where v is the velocity (which we want to find), G is the gravitational constant, M is the mass of Earth, and r is the total distance from the center of the Earth to the Hubble.
Here's the step-by-step solution:
First, we add the Earth’s radius and the height of the Hubble orbit above the surface. So r = 6.4 × 10^6 m (radius of earth) + 560 × 10^3 m (orbit height) = 6.96 x 10^6 m.Then, plug the values into the formula. Remember, G is 6.67 × 10^(-11) m^3 kg^-1 s^-2, and M is 6.0 × 10^24 kg:v = √([6.67 × 10^(-11) m^3 kg^-1 s^-2] * [6.0 × 10^24 kg] / [6.96 x 10^6 m])Calculate the expression inside the square root first then take the square root of the result. Doing so gives an approximate orbital speed of 7,555 m/s.Learn more about Hubble's Speed here:https://brainly.com/question/31803167
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rotational kinematics with constant angular acceleration: a 1.15-kg grinding wheel 22.0 cm in diameter is spinning counterclockwise at a rate of 20.0 revolutions per second. when the power to the grinder is turned off, the grinding wheel slows with constant angular acceleration and takes 50.0 s to come to a rest. (a) what was the angular acceleration (in rad/s2) of the grinding wheel as it came to rest if we take a counterclockwise rotation as positive? (b) how many revolutions did the wheel make during the time it was coming to rest?
(a) The angular acceleration of the grinding wheel as it came to rest is approximately -0.008 rad/s² (clockwise).
(b) The wheel made approximately 1000 revolutions during the time it was coming to rest.
(a) We can use the formula of rotational kinematics:
ω = ω₀ + αt
where ω is the final angular velocity, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time.
Given:
ω = 0 rad/s (final angular velocity)
ω₀ = 20.0 revolutions per second = 20.0 * 2π rad/s (initial angular velocity)
t = 50.0 s
Substituting the values into the formula, we have:
0 = 20.0 * 2π + α * 50.0
Solving for α, we get:
α ≈ -0.008 rad/s² (clockwise)
(b) To find the number of revolutions the wheel made during the time it was coming to rest, we can use the formula:
θ = ω₀t + 0.5αt²
where θ is the angular displacement.
Given:
ω₀ = 20.0 revolutions per second = 20.0 * 2π rad/s (initial angular velocity)
t = 50.0 s
α ≈ -0.008 rad/s² (clockwise)
Substituting the values into the formula, we have:
θ = (20.0 * 2π) * 50.0 + 0.5 * (-0.008) * (50.0)²
Simplifying the equation, we find:
θ ≈ 1000 revolutions
Therefore, the wheel made approximately 1000 revolutions during the time it was coming to rest.
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