A particale's velocity function is given by V=3t³+5t²-6 with X in meter/second and t in second Find the velocity at t=2s
A particale's velocity function is given by V=3t³+5t²-6 with X in meter/se

Answer: The car is travelling at a constant speed. Because it travells 30 miles in 30 minutes. While it travells 40 miles in 40 minutes.

Explanation:

The bus' kinetic energy (in joules) at the moment before sven stops pulling is 1195.2 Joules.

The energy associated with an object’s state of motion is Kinetic energy is a scalar quantity that is never negative in value and formula is K.E = 1/2mv^2.

The kinetic energy for the x, y, and z components are additive, Kinetic energy is relative to the motion of observer’s reference frame, since speed and velocity are as well.

An object’s kinetic energy depends more on its speed than its mass. Any change in an object’s speed will affect a change in its kinetic energy.

Given,

Frictional force (f) = 1920 N

Distance Cover (x) = 2·19 m

Then energy loss due to frictional force = fx

                                                              = 1920 × 2.19

                                                              = 4204.8 J

Energy apply by Sven is 5400 J

Rest of the energy. Kinetic is used to increase the kinetic energy of bus. So kinetic energy of the bus = 5400-4204.8

                                             = 1195.2 J

When sven stops pullin, bus's kinetic energy is = 1195.2 J

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The acceleration necessary to keep the object in uniform circular motion is 43.48 m/s²

From the question given above, the following data were obtained:

The acceleration required to keep the object in circula motion can be obtained as follow:

a = v² / r

a = 10² / 2.3

a = 100 / 2.3

a = 43.48 m/s²

Thus, the acceleration required to keep the object in circula motion is 43.48 m/s².

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The gas is compressed to 1/7 of its original volume, but since the process is horizontal, there is no change in volume. Hence, no work is done during the process A to B.

Therefore, the work done (WAB) during the process A to B is zero.

The work done by or on the gas during the process A - B can be calculated using the following formula: WAB = -∫PdV where P = pressure, and V = volume. To calculate WAB, we need to calculate the integral of PdV. Since B is represented by a horizontal line, the pressure P is constant. Therefore, WAB = -P∫dVWhere, ∫dV is the integral of dV from the initial volume Vi to the final volume Vf.

The gas is compressed from state A to state B. Therefore, the initial volume Vi = 7.0 dm³ and the final volume Vf = 1/7 * 7.0 dm³ = 1.0 dm³.WAB = -P ∫dV = -P(Vf - Vi)WAB = -200 kPa (1.0 dm³ - 7.0 dm³) = 1200 JThe work done by the gas during the process A - B is -1200 J.

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The car could maintain its speed for approximately 250 hours, assuming the batteries are fully charged.

To determine how long a car can maintain a certain speed while driving at an angle, we would need additional information regarding the car's specifications, such as its power, battery capacity, energy consumption rate, and efficiency. Without these details, it's not possible to provide a specific answer.

However, I can give you a general concept. The time the car can maintain a certain speed will depend on the available energy stored in the batteries and the rate at which the car consumes energy while driving at that speed and angle.

If we know the car's energy consumption rate (measured in units such as watt-hours per kilometer or kilowatt-hours per mile), and the battery capacity (measured in units such as kilowatt-hours), we can estimate the time the car can maintain the speed.

For example, if we know the car's energy consumption rate is 200 watt-hours per kilometer and the battery capacity is 50 kilowatt-hours, we can calculate the time as follows:

Time (in hours) = Battery Capacity (in kilowatt-hours) / Energy Consumption Rate (in kilowatt-hours per hour)

In this example:

Time = 50 kilowatt-hours / 0.2 kilowatt-hours per hour

Time = 250 hours

So, the car could maintain its speed for approximately 250 hours.

Please note that this is a simplified example, and in reality, there are various factors that can affect the range and duration of an electric vehicle, such as terrain, driving conditions, temperature, and driving style. Additionally, electric cars often have sophisticated energy management systems that optimize efficiency and range.

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Here are the answers to the questions:1. Three main orbital changes that the earth undergoes and their time periods are:A. Precession- every 26,000 years B. Obliquity- every 41,000 years C. Eccentricity- every 100,000 yearsThese changes in the earth's orbit, together, have an impact on the amount of solar radiation that reaches the Earth's surface, which then affects climate change. Three cyclical orbital changes and their times associated with Milankovitch are:A. Eccentricity - every 100,000 yearsB. Obliquity - every 41,000 yearsC. Precession - every 26,000 years2. All EMR in order of wavelength are:- Gamma rays- X-rays- Ultraviolet radiation- Visible light- Infrared radiation- Microwave- Radio wavesForms of EMR from the sun that are reaching right now are UV radiation, visible light, and infrared radiation.

The number of forms of EMR reaching the moon right now is two, UV radiation, and visible light.The ozone layer is present in the stratosphere and is formed through a series of complex chemical reactions. The primary function of the ozone layer is to protect the earth from the harmful effects of UV radiation by absorbing it. The balance of EMR plays a critical role in the greenhouse effect. As the amount of greenhouse gases increases, the amount of energy that is absorbed by the Earth's surface also increases. Carbon dioxide and other greenhouse gases can absorb and emit infrared radiation, which plays a crucial role in climate change.3. The four forms of heat transfer to and on planet earth are:- Conduction- Convection- Radiation- AdvectionThese four forms of heat transfer are responsible for weather on planet Earth.

For example, when the sun heats the ground, it results in conduction, which then results in convection as the air heats up and rises. This can lead to cloud formation and precipitation.4. The time it takes for EMR from the University of Delaware to reach:A. Moon - About 1.28 secondsB. Jupiter - About 33.75 minutesC. Closest star (not the sun) - About 4.37 yearsD. Your mother - This question is not clear, please provide more context.

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Generally speaking, the object distance indicates that the light rays emanating from the object are parallel to one another, resulting in f=-4.221.

A ray is defined as a small, usually straight-traveling beam of light. The laser or laser pointer's light beam is an illustration of a ray. According to the ray model of light, a ray moves in a straight line until it encounters an object, such as a mirror or the boundary between two materials.

image distance is v = 4.7 + (2.1 * 10-2) = -4.721 m the negative

means image is formed behind the lens

Generally the object distance is u = ∞ this mean the light ray coming from the object are parallel to each other.

So from lens equation

=-고=수

=> f = -4.721 m

As an electromagnetic wave, light travels in straight lines along narrow beams of light, which are referred to as rays. Despite the fact that reflection or refraction can alter its direction, light always moves in a straight line.

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The magnitude of the resulting acceleration of the block is (8), 14.5455 m/s²

Use Newton's second law to solve this problem:

ΣF = ma

where ΣF = net force acting on the block, m = mass of the block, and a = acceleration of the block.

Resolve the force of 87 N into its horizontal and vertical components.

F_horizontal = F cosθ = 87 cos 30° = 75.366 N

F_vertical = F sinθ = 87 sin 30° = 43.5 N

The net force in the horizontal direction is:

ΣF_horizontal = 29 N

Using ΣF = ma, find the acceleration:

a = ΣF / m = 29 N / 2 kg = 14.5 m/s²

Therefore, the magnitude of the resulting acceleration of the block is:

a = 14.5 m/s²

The answer is (8) 14.5455, which rounds to 14.5 m/s².

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After fertilization in the fallopian tube, It will take 6-12 days for the zygote to travel before arriving at the uterus.

A zygote is, generally speaking, a cell created by the fusion of two gametes; the growing person is created from such a cell.

It takes the zygote around 6–12 days following fertilization in the fallopian tube for the fertilized egg to travel to the uterus and attach to the uterus, a process known as implantation.

Hence It will take 6-12 days for the zygote to travel before arriving at the uterus.

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(10 tiles/sec) · (30 cm/tile)  =  300 cm/sec

That's  3000 mm/sec

That's  3 x 10³  mm/sec

Answer:

the motion of an object at a constant speed along a circular path is known as Uniform circular motion

The work required to stretch the spring having a spring constant (force constant) of 2500 n/m by 2.0 cm is 0.2 Joules.

The work required to stretch an ideal spring can be calculated using the formula:

Work = \((1/2) * k * x^2\)

Where k is the spring constant and x is the displacement from the equilibrium position.

Given that the spring constant is 2500 N/m and the displacement is 2.0 cm (or 0.02 m), we can substitute these values into the formula:

Work =\((1/2) * 2500 N/m * (0.02 m)^2\)

Calculating this expression, we get:

\(Work = (1/2) * 2500 N/m * 0.0004 m^2 \\Work = 0.5 N * 0.0004 m^2\)

Work = 0.0002 Nm = 0.2 J

Therefore, the work required to stretch the spring by 2.0 cm is 0.2 Joules.

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the drawdown at each distance from the well after 1 day of pumping.

calculate the drawdown at different distances from the well, we can use the Theis for equation confined aquifers:

s = (Q / (4πT)) × W(u)

where:

s is the drawdown at a certain distance from the well,

Q is the pumping rate (28 m³/day),

T is the transmissivity of the confined aquifer (3.8 m²/day),

W(u) is the well function that depends on the dimensionless distance u.

The well function W(u) can be calculated

W(u) =\((1 / u) × e^(u^2) × erfc(u)\)

where:

u = (r²S) / (4Tt)

r is the distance from the well,

S is the\(storativity\) of the confined aquifer (0.0035),

t is the time of pumping in days,

(u) is the complementary error function.

Now let's calculate the drawdown at the given distances of 1.5 m, 5.5 m, 10 m, 25 m, 75 m, and 150 m after 1 day of pumping.

Assuming the well is located at the origin (0,0) in a radial system:

For r = 1.5 m:

u = (1.5² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 5.5 m:

u = (5.5² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 10 m:

u = (10² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 25 m:

u = (25² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 75 m:

u = (75² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 150 m:

u = (150² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

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.

Answer:

the Virgo consentellation

Explanation:

Answer:

The answer is -0.5m/s2

Explanation:

I did the test and got it right.

The magnitude of the acceleration of the dog is ​0.5 m/s².

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions. Acceleration is a vector quantity since it has both a magnitude and a direction.

Initial speed of the dog = 7.5 m/s

Final speed of the dog = 0 m/s

Time taken = 15 second

Hence acceleration of the dog = change in speed/ time interval

= (final speed - initial speed)/time interval

= ( 0 m/s - 7.5 m/s)/15 second

= - 0.5 m/s²

Hence, the magnitude of the acceleration of the dog is ​0.5 m/s².

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Answer:

answer my question

Explanation:

Answer: 36 Kg

Explanation:

Ke= 1/2MV^2

Plug in the kinectic energy (3042 J) and solve for M.

3042= 1/2 (M) (13^2)

M= 36 Kg

Answer: the answer is carbon monoxide

Explanation:

hope this helps :)

A circular coil of wire has 300 turns and an average radius of 2:00 cm. The coil is placed at a 60° angle to the uniform magnetic field between the two poles of a large electromagnet. The strength of the field changes at a rate of -0.300 T/s. The magnitude of the resulting induced emf in the circular coil is zero.

To calculate the magnitude of the resulting induced electromotive force (emf) in the circular coil, we can use Faraday's law of electromagnetic induction, which states that the emf induced in a circuit is equal to the rate of change of magnetic flux through the circuit.

The magnetic flux (Φ) through a coil of wire is given by the product of the magnetic field strength (B), the area of the coil (A), and the cosine of the angle (θ) between the magnetic field and the normal to the coil:

Φ = B * A * cos(θ)

In this case, the magnetic field strength (B) is changing at a rate of -0.300 T/s, the area of the coil (A) can be calculated using the formula for the area of a circle (A = π *\(r^2\)), and the angle (θ) is 60 degrees.

First, let's calculate the area of the coil:

A = π * \(r^2\)

A = π *\((0.02 m)^2\)

A =\(0.0012566 m^2\)

Next, let's calculate the rate of change of magnetic flux:

dΦ/dt = B * dA/dt * cos(θ)

dΦ/dt = (-0.300 T/s) * (0) * cos(60°)   (since the area does not change with time)

Finally, the induced emf (ε) is equal to the negative of the rate of change of magnetic flux:

ε = -dΦ/dt

ε = -0

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The resistor that should be placed in series with the meter to limit the current flow to 1mA when 10V is applied across the combination is 10,000 ohms.

To limit the current flow to 1mA when 10V is applied across the combination, we need to use Ohm's law. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

I = V/R

Where I is the current, V is the voltage, and R is the resistance.

We know that the current is 1mA and the voltage is 10V. So, we can rearrange the equation to solve for the resistance:

R = V/I

R = 10V/1mA

R = 10,000 ohms

Therefore, the resistor that should be placed in series with the meter to limit the current flow to 1mA when 10V is applied across the combination is 10,000 ohms.

It's important to note that the potential difference between the terminals of the meter (100mV) is irrelevant in this calculation, as we are only concerned with the voltage and current across the combination of the meter and resistor.

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Electric current is defined as the total flow of electric charge through a surface over a period of time. Despite not being a vector, electric current has a sense of direction connected with it.

Electric current flows in a direction that is parallel to the motion of the positive charge and transverse to the motion of the negative charge. Ampere is the S.I. unit of electric current (A).

Every revolution, the charged particle that is rotating around the circle passes by a single point on the circle. That is, a charge of Q passes by a point on the circle over the course of evolution, and since que is provided in the question, we can simply use que in the numerator.

We do not, however, know the precise time period because omega, a related quantity, is provided in the question; therefore, we will just relate to these two quantities. T is equal to two pi radiance over Omega Radiance per second since we know that the angular velocity is equal to the circumference of the circle divided by the time it takes for a revolution to occur.

Our expression for the present is therefore cute over T, which is to buy over Omega, which only comes out to good Q over two pi. There is also our typical electric current.

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Answer:

1) Periodically check the no stop or NDL time on their computers

2) The dive computer planning mode can be used if available

3) Make use of a dive planning app

4) Check data from the RDP table or an eRDPML

Explanation:

The no stop times information from the computer gives the no-decompression limit (NDL) time allowable which is the time duration a diver theoretically is able to stay at a given depth without a need for a decompression stop

The dive computer plan mode or a downloadable dive planning app are presently the easiest methods of dive planning

The PADI RDP are dive planners based on several years of experience which provide reliable safety limits of depth and time.

Explanation:

It is due to cohesion (option C)

No, the object's displacement and distance traveled will be equal; however, because the object's initial position is unknown, the object's position may differ from its displacement and distance traveled.

Because the initial position is not provided, we cannot assert that the displacement or distance equals the position. We might have arrived at a different conclusion if the starting point had been zero, because the distance from zero equals the position.

What precisely do you mean by position, displacement, and distance?

The location of an object (whether a person, a ball, or a particle) at a given point in time is referred to as its position. The displacement of an object is the difference in its position from one time to the next. Distance is the total amount the object has traveled in a certain period of time.

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• The only force acting on the ball, and thus the net force, is due to its own weight, with magnitude

w = m g = (0.4 kg) (9.8 m/s²) ≈ 3.9 N

pointing downward.

• The ball is in free fall, so its acceleration is g = 9.8 m/s² (also pointing downward).

• The ball is dropped from a height of 49 m, so its height y at time t is

y = 49 m - 1/2 g t ²

Set y = 0 and solve for t :

0 = 49 m - 1/2 g t ²

t ² = (98 m) / g

t = √((98 m) / g) = √(10) s ≈ 3.2 s

• The ball's velocity v at time t is

v = - g t

so that at the time found previously, the ball will have attained a velocity of

v = - g (3.2 s) ≈ -31 m/s

and thus a speed of about 31 m/s.

The receiver of a signal must understand the code or language being used to avoid confusion and losses.

This is usually in the form of a sound or body movement and is involved in conveying messages to people.

The receiver must understand the code or language in order to prevent confusion or loss of lives and properties.

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Answer:

The formula is MgVg=MbVb.

which is 5×Vg=0.01×250.

5Vg=2.5.

Vg=2.5/5.

Vg=0.5m/s.

Answer:

Explanation:

The magnetism of a permanent magnet results from the magnetic moments of electrons in the material making up the magnet interactions with Earth's magnetic field the magnetic moments of nuclei in the material making up the magnet electric currents inside the magnet.

The tension in the string pulling the box is most nearly 17 N.

The given parameters;

The tension on the string is calculated by applying Newton's second law of motion as follows.

\(\Sigma F = ma\)

at constant speed, acceleration, a, = 0

\(\Sigma F = 0\\\\T_x - \mu F_n = 0\\\\Tcos(\theta) - \mu F_n = 0\\\\Tcos(\theta)= \mu F_n\\\\T = \frac{\mu F_n}{cos(\theta)} \\\\T = \frac{0.3 \times 5 \times 9.8}{cos(30)} \\\\T = 16.97 \ N\\\\T \approx 17 \ N\)

Thus, the tension in the string pulling the box is most nearly 17 N.

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