When a dielectric slab is placed between a parallel-plate capacitor energy stored in it will decrease.
The parallel plate capacitor is a device that uses two parallel plates connected across a battery to create an electric field between them. Before the dielectric breaks down, a parallel plate capacitor can only hold a certain amount of energy. Draw a parallel plate capacitor and a slab with dielectric constant K between this capacitor. In capacitors, the energy stored is given by the formula U = 1/2 CV² where C is the capacitance and V is the potential difference. From this formula, we can tell that U is directly proportional to V. When V decreases, U also decreases. This is because dielectric reduces the electric field between the plates and decreases the energy stored in the field. Therefore, the option is 2) decreases.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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which of the following phenomena suggest that light may be transverse wave
#polarization
#reflection
#photoelectric effect
#diffraction
Answer:
Polarization.
Reason being that phenomena verifies the transverse nature of light
a car is moving 5.82 m/s when it accelerates at 2.35 m/s2 for 3.25, what is its final velocity
The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.
Pleaseeee help!
A speedboat moves due north for 12 km before oat from its original position? Find its average velocity, in m s - 1 , if the total time taken is 30 minutes.
The average velocity of the speedboat is approximately 6.67 m/s.
To find the average velocity of the speedboat, we need to calculate the displacement and divide it by the total time taken.
Given:
Distance traveled north = 12 km
Time taken = 30 minutes
First, let's convert the distance traveled from kilometers to meters:
Distance traveled = 12 km = 12,000 m
Next, let's convert the time taken from minutes to seconds:
Time taken = 30 minutes = 30 * 60 seconds = 1800 seconds
To calculate the average velocity, we use the formula:
Average Velocity = Displacement / Time
Since the speedboat moves due north, its displacement is equal to the distance traveled north, which is 12,000 m.
Average Velocity = 12,000 m / 1800 s
Calculating this expression gives us:
Average Velocity = 6.67 m/s
Therefore, the average velocity of the speedboat is approximately 6.67 m/s.
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who is the Prime Minister of India
Answer:
Narendra Modi
Explanation:
The answer depends on what year you are talking about on, Narendra Modi was a prime minister of india since 2014. If you are missing information on your question tell me so I can try and tell you the answer,
Hope this helped,
have a good day :]
In the picture shown below A represents a characteristic of only geocentric model, B represents a characteristic common to both geocentric and heliocentric models, C represents a characteristic of only heliocentric model, and D represents a characteristic which the geocentric and heliocentric models do not have.
Under which label will the characteristic, "The sun and planets revolve around a central moon in the solar system" fall?
A
B
C
D
i don't understand this, can someone help please??
Explanation:
N2 + H2 --> NH3
balance them:
N2 + 3 H2 --> 2 NH3
so if 6 moles of N2 react, 12 moles of NH3 will form.
(you have to look at the big number in front, in this case its N2 and 2 NH3, therefore the amount of N2 will produce double the amount of NH3 )
Which of the following objects is accelerating?
Answer: A flower pot falling
Explanation:
The car on the curve (its direction is changing) and the falling flower pot (its speed is changing) are both undergoing acceleration.
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Sarah and her bicycle have a total mass of 40 kg. Her speed at the top of a 10 m high and 100m long hill is 5 m/s. If the force of friction on her way down is 20 N, at what speed will she be going when she reaches the bottom
Answer:
She will be going at 11.01 m/s when she reaches the bottom.
Explanation:
We can find the speed at the bottom by equating the total work with the change in energy:
\( W = E_{f} - E_{i} \) (1)
There is no energy conservation because there is a force of friction on her way down.
By entering \(W = -F_{\mu}*d\), where \(F_{\mu}\) is the force of friction (is negative because it is in the opposite direction of motion) and d is the displacement, into equation (1) we have:
\(-F_{\mu}*d = E_{f} - E_{i}\)
In the initial state, we have kinetic and potential energy and in the final state, we have only kinetic energy.
\(-F_{\mu}*d = \frac{1}{2}mv_{f}^{2} - (\frac{1}{2}mv_{i}^{2} + mgh)\)
Where:
m: is the total mass = 40 kg
\(v_{f}\): is the final speed =?
\(v_{i}\): is the intial speed = 5 m/s
g: is the gravity = 9.81 m/s²
h: is the height = 10 m
\( -20 N*100 m = \frac{1}{2}40 kg*v_{f}^{2} - \frac{1}{2}*40 kg*(5 m/s)^{2} - 40 kg*9.81 m/s^{2}*10 m \)
By solving the above equation for \(v_{f}\) we have:
\( v_{f} = 11.01 m/s \)
Therefore, she will be going at 11.01 m/s when she reaches the bottom.
I hope it helps you!
A ball of mass M and speed of V collides head on with a ball of mass 2M and a speed of v/2, as
shown above. If the two balls stick together, their speed after the collision is
Answer:
2/3V
Explanation:
Given that a ball of mass M and speed V collides with another ball of mass 2M and velocity v/2 . After collision they stick together and we need to find their speed after collision . According to Law of Conservation of Momentum , The total momentum of the system before and after collision is constant .That is ;
\(\sf\qquad\longrightarrow m_1u_1+m_2u_2=m_1v_1+m_2v_2\\ \)
\(\sf\qquad\longrightarrow MV + 2M\bigg(\dfrac{V}{2}\bigg) = (2M + M)(v)\\ \)
\(\sf\qquad\longrightarrow MV +MV= 3Mv\\\)
\(\sf\qquad\longrightarrow 2MV = 3Mv\\ \)
\(\sf\qquad\longrightarrow v =\dfrac{2M}{3M}V\\ \)
\(\sf\qquad\longrightarrow \pink{ v_{after\ collision}=\dfrac{2}{3}V }\)
Hence the velocity after the collision ia 2/3V .
what is the state of y when y = k/x, x is halved.
Answer:
y becomes doubled.
Explanation:
If;
y = \(\frac{k}{x}\)
what is the state of y when x is halved;
the given expression is an inverse relationship. When y increases, x is supposed to decrease and vice versa.
if x is halved; x = \(\frac{x}{2}\)
\(\frac{k}{\frac{x}{2} }\) = \(\frac{2k}{x}\)
Now compare :
\(\frac{k}{x}\) : \(\frac{2k}{x}\)
we see that y becomes doubled
Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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A gene can be best described as a unit of –
a particle of mass slides without friction on the inside of a cone in a circular orbit of radius at height above the base of the cone. the cone is rotating about the vertical axis with angular velocity . the velocity of the particle as observed in the rotating reference frame is given by . here both and are magnitudes (positive quantities). the axis of the cone is vertical and gravity points downward. the apex half-angle of the cone is
the apex half-angle of the cone is \(\frac{V^{2} }{g}\)
Calculation :
Ncosθ = mg ---1
Nsinθ =\(\frac{mv^{2} }{r}\)
divide eqn 1 and 2
tanθ = V²/rg ---3
now tan θ = h/r ---4
fro eqn 3 and 4
h= \(\frac{V^{2} }{g}\)
A cone is a three-dimensional geometric shape that tapers from a flat base (often not necessarily circular) to a point called the vertex or apex.
A cone is formed by a series of line segments, half-lines, or lines that connect a point (vertex) common to all points on the base in a plane that does not contain vertices. Depending on the author, the basis may be restricted to a circle, a one-dimensional square in the plane, a closed his one-dimensional figure, or any of the above plus all enclosed points. A cone is a solid object if the base contains the enclosed points. Otherwise, it is a 2D object in 3D space. For solids, the boundaries formed by these lines or partial lines are called faces. If the sides are unlimited, it is a conical surface.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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A car is travelling in a straight line and has its velocity uniformly reduced from 20 m * s ^ - 1 to 12m * s ^ - 1 in a distance of 80 m. The car the travels at the lower velocity for 1 minute, and then decelerates uniformly to rest in a further 12 sec. show the whole journey on a velocity-time graph and calculate
(i) the initial deceleration and the time taken to travel 80 m.
(ii) the final deceleration
(iii) the total displacement for the whole journey
i) The initial deceleration of the car is -1.6 m/s² and the time taken is 5 seconds
ii) The final deceleration is -1 m/s²
iii) The total dispalcement = 1016 m
What is the initial deceleration of the car?The initial deceleration of the car is given by the formula below:
v² = u² + 2as
where;
v is the initial velocityu is the final velocitya is acceleration/decelerations is the displacementSolving for a;
12² = 20² + 2 * a * 80
a = -1.6 m/s²
Time taken, t = v - u / a
t = 12 - 20 / (-1.6)
t = 5 seconds
Final deceleration:
a = v - u / t
a = 0 - 12 / 12
a = -1 m/s²
iii) Displacement at constant velocity = 12 * 1 * 60
Displacement at constant velocity = 720 m
Final displacement, s = ut + 0.5at²
s = 12 * 12 + 0.5 * 1 * 12²
s = 216 m
Total dispalcement = 80 + 720 + 216
Total dispalcement = 1016 m
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*
Which of the following cannot be an example of projectile motion
A. A football flying through the air
B. An apple falling from a tree
C. A pencil rolling on the ground
D.A rocket dropping from its maximum height
What sort of energy do machines use to do work?; What is a machine that increases force?; What's a machine that increases speed?; What is a change caused by kinetic energy as well as a change that involves potential energy?
Mechanical energy is the energy that machines use to do work and levers are a machine that increases force sleever that increases speed.
There are two types of hydroelectric power projects is conventional and pumped storage. In a conventional hydroelectric facility, water passes from the intake and out the outflow one time.
In a pumped storage facility, water may pass through the turbine multiple times. The operation of a hydropower project, like any power plant, may generate solid and industrial wastes.
Hydroelectric power generation decommissioning includes waste management of any reservoir sediments, especially where power plant placement is downstream from significant industrial or natural environmental hazard sources.
In Hydroelectric power generation, kinetic energy of the water is converted into the mechanical energy of the turbine which further converted into the electrical energy.
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how does mass relates to latent heat?
The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.
What is latent heat?Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.
Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.
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why no tempature can be lower than 0 kelvin
Answer:
At zero kelvin (minus 273 degrees Celsius) the particles stop moving and all disorder disappears. Thus, nothing can be colder than absolute zero on the Kelvin scale. Physicists have now created an atomic gas in the laboratory that nonetheless has negative Kelvin values.
Explanation:
A pupil carries out an experiment to measure the speed of a dropped ball.
The ball falls at a distance of 2m in a time of 0.67s
Emily says that if the ball continues to fall for three times as long, the average speed of the ball will be about 9m/s
Jack says the ball will not be falling this fast.
State who you think is correct and explain your reasoning
Jack is right. If the ball continues to fall for three times as long, the average speed of the ball will be smaller than 9 m/s, because if the time of motion of an object increases, the speed at which it falls decreases.
What is the time of motion of the ball?
The time of motion of the ball is calculated as follows;
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity of the ballt is the time of motion of the ballg is acceleration due to gravityThe initial vertical velocity of the ball = 0
h = 0 + ¹/₂gt²
h = ¹/₂gt²
t = √(2h / g)
t = √(2 x 2 / 9.8)
t = 0.64 m/s
The given time of motion of the ball = 0.67 second
If the ball continues to fall for 3 times as long, new time of motion of the ball = 3 x 0.67 s = 2.01 s
The average speed of the ball at this speed is calculated as;
s = [(u + v)/2 ]t
s = [(0 + v) / 2]t
s = (vt) / 2
vt = 2s
v = 2s / t
v = (2 x 2 m) / (2.01 s)
v = 1.99 m/s
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When you turn down the volume on the television, you reduce the _______ carried by the sound waves, so you also reduce their ________
Answer:
when you turn down the volume on the television, you reduce the intensity carried by the sound waves, so you also reduce their amplitude.
Explanation:
When you turn down the volume of the television, you are actually reducing the intensity of the sound wave, which is directly proportional to the amplitude of the sound. Amplitude is height of the sound wave.
Therefore, when you turn down the volume on the television, you reduce the intensity carried by the sound waves, so you also reduce their amplitude.
Which statement is true? speed is a scalar quantity and velocity is a vector quantity, speed and velocity are both scalar quantities,
speed is a scalar quantity and velocity is a vector quantity
Activities 1. Find the force needed to accelerate a mass of 40kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10s
The force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is 12.4 N.
Start by calculating the change in velocity (Δv) experienced by the object. This can be done by subtracting the initial velocity v₁ from the final velocity v.
Δv = v - v₁ = ((8î + 3) - 5k) - ((4î - 5) + 3k)
= 8î + 3 - 5k - 4î + 5 - 3k
= 4î - 8k + 8
Next, calculate the acceleration (a) using the formula:
a = Δv / t
where t is the time interval, given as 10 seconds.
a = (4î - 8k + 8) / 10
= (0.4î - 0.8k + 0.8) m/s²
The force (F) required to accelerate the object can be found using Newton's second law:
F = m * a
where m is the mass, given as 40 kg.
F = (40 kg) * (0.4î - 0.8k + 0.8) m/s²
= (16î - 32k + 32) N
Simplify the expression to obtain the final answer:
F = 16î - 32k + 32 N
≈ 12.4 N
Therefore, the force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is approximately 12.4 N.
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Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the snowmobile, including Sully, is 280 kilograms. If Sully accelerates to a velocity of 16 meters/second over 10 seconds, what’s the force exerted by the snowmobile to accelerate? Use F = ma, where . A. 160 N B. 168 N C. 248 N D. 280 N E. 324 N
Answer:
280.6N
Explanation:
According to Newton's second law;
Force = mass * acceleration
Given
Mass = 280kg
velocity = 10m/s
Time = 10 secs
Acceleration = velocity?/Time
Force = mass * velocity/time
Force = 280 + (16-10/10)
Force = 280 + 0.6
Force = 280.6N
Hence the force exerted by the snowmobile to accelerate is 280.6N
Answer:168 N
Explanation:
what is the acceleration of a ball traveling horizontally wit an initial velocity of 20 meters/seconds and, 2.0 seconds later, a velocity of 30 meters/seconds
Answer:
\(a=5\ m/s^2\)
Explanation:
Given that,
Initial velocity of the ball, u = 20 m/s
Final velocity, v = 30 m/s
Time, t = 2 seconds
Let us assume to find the acceleration of the ball. The rate at which the velocity of the ball is changing is called the acceleration of the ball. So,
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{30-20}{2}\\\\a=5\ m/s^2\)
So, the acceleration of the ball is \(5\ m/s^2\)
I need help with this answer
help
1. Calculate the Energy of skater at all the positions shown. Position C is the highest point the skater reaches
The energy of the skater at each position is:
A: 1920 JB: 1764 JC: 3528 JHow to calculate conservation of energy?At position A, the skater is at the lowest point, so the PE is zero. The KE can be calculated using the formula KE = (1/2)mv², where m is the mass of the skater and v is the velocity:
KE = (1/2)(60 kg)(8 m/s)²
KE = 1920 J
Therefore, at position A, the skater has 1920 J of kinetic energy and 0 J of potential energy.
At position B, the skater has gained some height, so there is some potential energy. The KE can be calculated as before, and the PE can be calculated using the formula PE = mgh, where m is the mass of the skater, g is the acceleration due to gravity (9.81 m/s²), and h is the height:
KE = (1/2)(60 kg)(8 m/s)²
KE = 1920 J
PE = (60 kg)(9.81 m/s²)(3 m)
PE = 1764 J
Therefore, at position B, the skater has 1920 J of kinetic energy and 1764 J of potential energy.
At position C, the skater has reached the highest point, so the KE is zero. The PE can be calculated as before:
PE = (60 kg)(9.81 m/s²)(6 m)
PE = 3528 J
Therefore, at position C, the skater has 0 J of kinetic energy and 3528 J of potential energy.
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the following items describe observational characteristics that could indicate that an object is either a white dwarf or a neutron star. match each characteristic to the correct object.
When a white dwarf acquires enough mass for its carbon interior to start fusing, a white dwarf supernova results.
The white dwarf entirely explodes as the star's fusion starts nearly immediately throughout the entire star. When iron is produced during fusion in a star's core, a "massive stellar supernova" results. If a white dwarf in a near binary system acquires enough mass to surpass the "white dwarf limit (1.4 solar masses)," it will erupt as a supernova. The absence of hydrogen characteristics in type I supernovae's spectra at maximum luminosity is a crucial identifying trait. The remnant core of a low-mass star known as a white dwarf is protected from the force of gravity by electron degeneracy pressure. The mass of the Sun is often condensed into a body no bigger than Earth in a white dwarf.
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