A package is dropped from the plane which is flying with a constant horizontal velocity of va = 150 ft/s. Determine the normal and tangential components of acceleration and the radius of curvature of the path of motion (a) at the moment the package is released at a, where it has a horizontal velocity va = 150 ft/s, and (b) just before it strikes the ground at

b

The correct option is Plasma tails point directly toward the Sun, while dust tails are curved and extend mostly towards the Sun and the direction of the comet's orbit.

The tails of a comet can be divided into two types: plasma tails and dust tails. The direction in which the tails point depends on the type of tail.

Plasma tails are made up of ionized gas and are influenced by the solar wind, a stream of charged particles that emanate from the Sun. The plasma tails point directly away from the Sun, in the opposite direction to the solar wind.

Dust tails, on the other hand, are made up of small solid particles that are pushed away from the nucleus of the comet by the pressure of sunlight. Dust tails are curved and extend mostly away from the Sun and towards the direction of the comet's orbit, due to the motion of the comet around the Sun.

So, plasma tails point directly toward the sun while dust tails are curved and extend mostly toward the sun and towards the direction of the comet's orbit.

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correct question

In what direction do the tails point?

-Plasma tails point directly toward the Sun. Dust tails are curved and extend mostly toward the Sun and towards the direction of the comet's orbit.

-Plasma tails point in the direction opposite to which the comet travels. Dust tails point mostly toward the Sun and are bent in a direction of the comet's motion.

-Plasma tails point directly in the direction in which the comet travels. Dust tails point mostly out from the Sun and are bent in a direction opposite to the comet's motion.

-Plasma tails point directly away from the Sun. Dust tails are curved and extend mostly out from the Sun and backwards in the direction of the comet's orbit.

Answer:

it's D

Explanation:

its on edge

The angle at which a 2.20 µm wide slit produces its first minimum for 410 nm violet light can be calculated using the equation for the first minimum in a single slit diffraction pattern. The equation is given by:

sinθ = (m * λ) / w

Where:
θ is the angle of the first minimum
m is the order of the minimum (in this case, m = 1 for the first minimum)
λ is the wavelength of the light (410 nm, which is equal to 410 * 10^(-9) m)
w is the width of the slit (2.20 µm, which is equal to 2.20 * 10^(-6) m)

we have:

sinθ = (1 * 410 * 10^(-9)) / (2.20 * 10^(-6))

Calculating this expression, we find:

sinθ ≈ 0.1864

To find the angle θ, we can take the inverse sine (sin^(-1)) of 0.1864:

θ ≈ sin^(-1)(0.1864)

Using a calculator, we find:

θ ≈ 10.7°

Therefore, the angle at which the 2.20 µm wide slit produces its first minimum for 410 nm violet light is approximately 10.7°.

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Rounding this value to the nearest 0.1°, the angle at which the first minimum occurs for the 2.20 µm wide slit with 410 nm violet light is approximately 93.2°.

Explanation :

The angle at which the first minimum occurs for a slit can be calculated using the formula:

θ = λ / (2 * a)

Where θ is the angle, λ is the wavelength of the light, and a is the width of the slit.

Given that the width of the slit is 2.20 µm and the wavelength of the violet light is 410 nm (or 410 x 10^-9 m), we can substitute these values into the formula:

θ = (410 x 10^-9) / (2 * 2.20 x 10^-6)

Simplifying this expression:

θ = 0.00041 / 0.0000044

θ = 93.18 degrees

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The force on an electron due to a magnetic field can be calculated using the formula F = qvB, where F is the force, q is the charge of the electron, v is the velocity of the electron, and B is the magnitude of the magnetic field.

Given:

Charge of the electron (q) = 1.60218 x 10^-19 C

Mass of the electron (m) = 9.10939 x 10^-31 kg

Magnitude of the magnetic field (B) = 0.259 T

To find the force on the electron, we need to determine the velocity of the electron after it has been accelerated across the potential difference.

The potential difference (V) is given as 82300 V, which can be used to calculate the final kinetic energy of the electron using the equation:

qV = (1/2)mv^2

Solving for v, we have:

v = sqrt((2qV)/m)

Substituting the given values, we find:

v = sqrt((2 * 1.60218 x 10^-19 C * 82300 V) / (9.10939 x 10^-31 kg))

v ≈ 5.47 x 10^6 m/s

Now, we can calculate the force on the electron due to the magnetic field:

F = qvB

Substituting the values, we get:

F = (1.60218 x 10^-19 C) * (5.47 x 10^6 m/s) * (0.259 T)

F ≈ 2.244 x 10^-15 N

Therefore, the force on the electron due to the magnetic field is approximately 2.244 x 10^-15 N.

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Answer:

Its the first option

Melting point

Well we know that if we freeze something, it will turn into a solid right? If it was boiling point, it would be steam, so your answer would be Melting Point

Hope this helps you out!

The approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

This calculation is based on the formula n = L/λ, where n is the number of wavelengths, L is the length of the object, and λ is the wavelength of light. To calculate the wavelength of light, we use the formula c = λf, where c is the speed of light and f is the frequency of light.

In this problem, we are given the diameter of the retroreflecting bead, which is assumed to be spherical. Therefore, its length is equal to its diameter, which is 5 × \(10^-^5\)m. We are also given the speed of light, which is 3 × \(10^8\) m/s, and an approximation of the frequency of light, which is \(10^1^5\) Hz.

Using the formula c = λf, we can solve for the wavelength of light:

λ = c/f = (3 ×\(10^8\) m/s)/\((10^1^5\)Hz) = 3 ×\(10^-^7\)m

Finally, we can use the formula n = L/λ to calculate the approximate number of wavelengths of light that can travel in one direction within the retroreflecting bead:

n = L/λ = (5 ×\(10^-^5\) m)/(3 ×\(10^-^7\) m) = 166.67 ≈ 167

Therefore, the approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

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The ideal body position while driving is with the knee slightly bent from the seat while pressing the pedals. The best choice is therefore B.

What significance does proper body posture have?

The right blood flow, which supports and maintains the health of the muscles, tendons, and ligaments, depends on the body's posture.

The picture that is attached contains the entire question.The right body alignment to choose while driving aids in the development of the right control over the vehicle. When pressing the pedals, the knee should be slightly bent and the seat should be adjusted such that the bottom touches the back of the seat. So, choice B is the right one.

The ideal body position for your legs after you adjusted Seat is with your knee

A. is fully tucked in when pressing the pedals

B. is slightly crooked when pressing the pedals

C. is fully extended when pressing the pedals

D. is pressing directly on the pedals

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Mapping methods such as digital mapping using satellite imagery or aerial photography can provide much higher resolution and accuracy. These methods utilize advanced technology and can capture detailed features and measurements with greater precision.

The mapping method with the lowest resolution is usually the one that has a smaller scale or less detailed data. For example, a world map would have a lower resolution than a city map since it covers a much larger area and shows less detail. Therefore, the mapping method with the lowest resolution depends on the scale and level of detail in the data being used.

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Answer:

it is the impact of a meteorite, volcanic activity, or an explosion.

The work done by the dog is 0.81J.

Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.

It is said that no work is done if the object does not move.

The work done on an object is the amount of energy transferred to an object through work.

According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:

Force = mass × acceleration

Force = 0.75kg × 9.8m/s²

Force = 7.35N

Work done = 7.35N × 0.11m = 0.81J

Therefore, 0.81J is the work done by the dog.

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Answer:

q+13

Explanation:

Answer:

Below

Explanation:

Alkaline earth metals have 2 valence electrons, which means that when they react with other elements, they will lose rather than gain their 2 electrons making them positive ions or cations.

So the correct answer to your question would be....

    C) 2 valence electrons, cations

Hope this helps! Best of luck <3

Answer:

true:)

Explanation:

Answer: inertia

Explanation:

he glass of water has inertia — it will not move unless a big enough force acts on it. The force in this activity pulling on the glass of water is the friction between the tablecloth and the glass.

She would most likely receive a clearer digital radio signal rather than an analog signal because digital radio signals are better equipped to handle electrical interference than analog radio signals.

Digital radio signals are composed of digital data which is broken down into discrete packets that are sent out and received separately makes them more resilient to interference because the signal can be reassembled from the packets even if some of them are distorted. On the other hand, analog radio signals are composed of continuous waves which are more vulnerable to interference and if any part of an analog signal is distorted, the entire signal can be lost. Therefore, digital radio signals are better suited to environments with electrical interference, and Jackie would be more likely to receive a clearer signal if she used a digital radio. If there are no digital radio stations available in Jackie's area, then she would most likely receive a clearer signal if she was using an analog radio.

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To find the time it took for the car to accelerate, you can use the formula:

t = (v - u) / a

where t is the time, v is the final velocity, u is the initial velocity, and a is the acceleration.

Plugging in the given values, you get:

t = (26 m/s - 19 m/s) / (205 m / t^2)

You can then rearrange the equation to solve for t:

t = sqrt(205 m / (26 m/s - 19 m/s))

Solving for t, you get:

t = sqrt(205 m / 7 m/s) = sqrt(29.3 s^2) = 5.4 s

So it took the car approximately 5.4 seconds to accelerate from 19 m/s to 26 m/s.

A 0.25 kilogram object just on end of the a spring moves in simple harmonic motion with an amplitude of 18.75 cm. 200 n/m is the spring constant.

Amplitude modulation, or AM, is now utilized for two-way radio communication for aircraft at VHF frequencies and for audio transmission on the long, medium, and short wave bands. Due to the use of superior modulation techniques, it is only used in a very small number of other applications.

Angular velocity ω = 2π / T where T is time period of rotation .

                               = 2 x 3.14 / .34

                               = 18.47 rad /s

energy = 1/2 m ω²Α²

6 = .5 x 18.47² x A²

A² = 0.035176

A = .18753

  = 18.75cm

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Abraham Lincoln

Explanation:

hope it helps you a little

To find the range of values required for the capacitor (C) in the tuning circuit of an AM radio, we can use the formula for the resonance frequency of an LC circuit:f = 1 / (2π√(LC))

Given:
Inductance (L) = 0.250 mH
Minimum frequency (f_min) = 550 kHz
Maximum frequency (f_max) = 1650 kHz
We need to find the range of capacitance (C) values that allow the circuit to resonate within this frequency range.
For the minimum frequency:
550 kHz = 1 / (2π√(0.250 mH * C_min))
√(0.250 mH * C_min) = 1 / (2π * 550 kHz)
0.250 mH * C_min = (2π * 550 kHz)^(-2)
C_min = (2π * 550 kHz)^(-2) / 0.250 mH
Similarly, for the maximum frequency:
1650 kHz = 1 / (2π√(0.250 mH * C_max))
√(0.250 mH * C_max) = 1 / (2π * 1650 kHz)
0.250 mH * C_max = (2π * 1650 kHz)^(-2)
C_max = (2π * 1650 kHz)^(-2) / 0.250 mH
Calculating these values will give us the range of capacitance required for the tuning circuit.
Please note that I'm providing the general approach to calculate the range of capacitance based on the given parameters. You can substitute the values into the formulas and perform the calculations to obtain the specific range.

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The movement of a pendulum is a good example of potential energy being transformed into kinetic energy and back again.

Kinetic Energy: The energy of a body due to its motion is called kinetic energy.

Potential Energy: Potential energy is the energy that is stored in an object due to its position relative to some zero position. Electrostatic energy, Gravitational energy, etc. are some examples of potential energy.

When the pendulum is at its extremes, all the energy of the pendulum is converted into potential energy. And when it is at the center it has only kinetic energy. At other positions, the total energy is the sum of potential and kinetic. But the total energy of the pendulum is always conserved.

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The correct question is-

Give an example of a system where potential energy is transformed into kinetic energy and back again. Explain.

Answer:

Explanation: I know that people'strength vary on what they can lift.

Answer:

HW3 Motion (Ldimension _ obiecL acceleralions) Question rocket on the ground is launched with an acceleration of 40 m/s $ upward. seconds inlo the flight the engine shuts off: Assume there no air resistance. Preliminary questions The acceleraton of the rocket i5 40 mls/5. Do you have t0 then adjust this acceleration wth the acceleration due t0 gravity? When Ihe engine shuts ofl, which molion variable(s) changes and how does change? Calculation What is the maximum height that the rocket reaches? At what time atter launch will tne rocket retum to the ground? Queslion You drive into 120 meter long block Irom the Ielt end at = constant speed of 21 mls_ Alter some Ume. you brake with constant acceleralion 0l 3 msls: You want come (0 slop at Ine right end of the block: How much time (Irom when you enter Ihe block) should you wail belore braking? How far down the block (from the left end) d2 you travel before braking? Question You are rest at stop sign; There another stop sign that is 100 meters away: Your maximum acceleration is mists and You maximum braking acceleration misis How much time do you spend acceleraling? How much time do you spend braking? What is the tolal travel lime? Over how much distance do you accelerate? Over how much distance do you brake? What is the tolal travel distanco?

Explanation:

Answer:

Weight is what you get when a certain amount of gravity is acting on that mass, and something, like the surface of a planet, is resisting that action. In space, when falling freely, there's nothing resisting the pull of gravity so weight disappears. Mass however stays.

hope this helps u

Explanation:

The approximate length of the shadow cast by the tower when the angle of elevation to the Sun is 65º is 66.2 feet.

To determine this, we can use the concept of similar triangles. The angle of elevation to the Sun and the angle of elevation to the top of the tower are the same for both scenarios. Therefore, the ratios of the corresponding sides of the triangles will be equal. Given that the length of the shadow is 64.3 feet when the angle of elevation is 69º, we can set up the following proportion: (Length of the shadow)/(Height of the tower) = (Length of the shadow when angle of elevation is 65º)/(Unknown height of the tower).

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New kinetic energy:

If the initial kinetic energy of a car is 0.3 MJ and the speed of the car decreased two times then the new kinetic energy will be 0.075 MJ.

The calculation for kinetic energy:

Step-1:

It is given that the car has a kinetic energy of 0.3 MJ. It is required to find the new kinetic energy when the car's speed decreases two times from its initial speed.

Let the mass of the car is m and the initial speed of the car is v.

It is known that the kinetic energy is calculated as,

\(\text{K.E}=\frac{1}{2}\times \text{mass}\times\text{speed}^2\)

Therefore the initial kinetic energy is the car is,

\(\text{K.E}_1=\frac{1}{2}\times \text{m}\times\text{v}^2\)

Step-2:

The speed of the car is decreased two times. Thus the speed becomes v/2. Therefore the final kinetic energy is the car is,

\(\text{K.E}_2&=\frac{1}{2}\times \text{m}\times(\frac{v}{2})^2\\&=\frac{1}{4}\times\frac{1}{2}\times \text{m}\times\text{v}^2\\&=\frac{1}{4}\times\text{K.E}_1\\&=\frac{1}{4}\times {0.3}\text{ MJ}\\&=0.075 \text{MJ}\)

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Answer:

3.5

Explanation:

The answer should be 3.5

Answer:

3.5

Explanation:

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

Answer:Since the plane velocity and the wind velocity form a right triangle when added together in head-to-tail fashion, the angle between the resultant vector and the southward vector can be determined using the sine, cosine, or tangent functions. The tangent function can be used; this is shown below:

Explanation:

Answer:

D Elastic collision because momentum is conserved

Explanation:

this is the answer may i be marked brainliest?