A non-polar molecule that has a dipole moment induced by the motion of its electrons:
A. inter-molecular force
B. hydrogen bond
C. london dispersion force
D. dipole-dipole bond
E. instantaneous dipole moment

Answer : The correct option is, (B) has fewer subatomic particles than an atom of iron (Fe) .

Explanation :

The given element is chromium (Cr). The atomic number of chromium is 24.

As we know that the atomic number is either equal to the number of protons or number of electrons.

So, Atomic number = Number of protons = Number of electrons = 24

And we know that mass number is the sum of number of protons and number of neutrons.

Mass number of chromium = 52

Mass number = Number of protons + Number of neutrons

52 = 28 + Number of neutrons

Number of neutrons = 28

And we know that the atomic number of iron (Fe) is 26.

Number of protons = Number of electrons = 26

Mass number of Fe = 56

Number of neutrons = 30

From the given options we conclude that the a neutral atom of chromium has fewer subatomic particles than an atom of iron (Fe).

Hence, the correct option is, (B) has fewer subatomic particles than an atom of iron (Fe) .

Answer:

404.8g of (NH4)HSO4 is produced.

Explanation:

Step 1:

Data obtained from the question. This include the following:

Temperature (T) = 10°C = 10°C + 273 = 283K

Pressure (P) = 110KPa = 110/101.325 = 1.09atm

Volume (V) = 75L

Step 2:

Determination of the number of mole of ammonia, NH3.

The number of mole (n) of ammonia, NH3 can be obtained by using the ideal gas equation. This is illustrated below:

Note:

Gas constant (R) = 0.0821atm.L/Kmol

Number of mole (n) =?

PV = nRT

1.09 x 75 = n x 0.0821 x 283

Divide both side by 0.0821 x 283

n = (1.09 x 75) /(0.0821 x 283)

n = 3.52 moles

Step 3:

Determination of the number of mole ammonium hydrogen sulfate produced from the reaction.

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH3 + H2SO4 —> (NH4)HSO4

From the balanced equation above,

1 mole of NH3 produced 1 mole of (NH4)HSO4

Therefore, 3.52 moles of NH3 will also produce 3.52 moles of (NH4)HSO4.

Therefore, 3.52 moles of ammonium hydrogen sulfate, (NH4)HSO4 is produced.

Step 4:

Conversion of 3.52 moles of ammonium hydrogen sulfate, (NH4)HSO4 to grams. This is illustrated below:

Molar Mass of (NH4)HSO4 = 14 + (4x1) + 1 + 32 + (16x4) = 115g/mol

Number of mole of (NH4)HSO4 = 3.52 moles

Mass of (NH4)HSO4 =..?

Mass = mole x molar Mass

Mass of (NH4)HSO4 = 3.52 x 115 = 404.8g

Therefore, 404.8g of (NH4)HSO4 is produced.

Answer:

the answer for 5 is liquid

Answer:

Matter in compound having chemical bonds while in mixture matter have physical interaction.

Explanation:

We know that element is a substance that is made up of atoms. The atoms of different elements combine to form compound. These are the form of matter that have characteristic properties and having fixed chemical composition. The atoms of different elements are combine to gather through the chemical bond.

For example:

Consider the compound water. It has hydrogen and oxygen. Atoms are bonded together through chemical bond and having fixed proportion. So we can say that their interaction is chemical interaction.

While in mixture different matter combined through the physical interaction.

Atoms of different elements are not chemically bonded together.

For example:

Mixture of sand and water.

Mixture of oil and water.

The daughter nucleus that is formed in the process is  152/64Gd .

Gadolinium-152 and a beta particle are produced during the beta decay of europium-152. An electron that is released from the nucleus during the decay process is the beta particle.

A beta ray is released from an atomic nucleus during a radioactive decay process known as beta decay. The proton in the nucleus changes from a proton to a neutron during beta decay, and vice versa.

The beta particle is represented by the symbol "β" with a superscript indicating its charge (-1 for an electron)

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Answer:

brainliest plss

Explanation:

Most hydrogen atoms have a nucleus with only a single proton. About 1 in 10,000 hydrogen nuclei, however, also has a neutron; this particular isotope is called deuterium. An extremely rare hydrogen isotope, tritium, has 1 proton and 2 neutrons in its nucleus. ... Most hydrogen atoms have only a proton in the nucleus

Option A: It is the amount of energy stored in the intermolecular attractions that hold particles together in an ionic solid, and option C: it is the amount of enthalpy change that occurs when 1mol of ionic solid is converted into gaseous ions, describes lattice energy.

The enthalpy change required to convert one mole of an ionic solid into gaseous ionic components is known as lattice energy. The strength of the ionic bonds in an ionic compound is gauged by lattice energy. It holds the particles together in a molecule. Thus, option A and C describes lattice energy. It sheds light on a number of ionic solids' characteristics, such as their solubility, hardness, and volatility.

The lattice energy of an ionic solid cannot be measured directly, but only be detected with Born-Haber cycle. It is expressed in terms of kilo-joule per mole, KJ/mol.

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The technique used to separate calcium carbonate from a mixture of calcium carbonate and water is called filtration.

This method involves pouring the mixture through a porous substance, such as filter paper, to keep the solid calcium carbonate in place while allowing water to pass through. After being collected and dried, the resultant residue on the filter paper can be used to make pure calcium carbonate.

Decantation and sedimentation are other potential methods. In this method, the mixture is left to remain for a while, during which the calcium carbonate particles gravitationally sink to the bottom. The calcium carbonate sediment can then be removed by carefully pouring out or decanting the clear water at the top.

Keep in mind that the technique used will rely on the unique characteristics of the combination and the desired level of calcium carbonate purity. Depending on the circumstances, other methods may also be utilized, such as evaporation or centrifugation.

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Answer:

This is not a question

Explanation:

no

Answer:

Explanation:

I would say a mass spectrometer. Not entirely sure on that tho

The compounds formed in the Strecker synthesis from ketones or aldehydes are amino acids, and a Ramachandran plot can visualize the dihedral angles (phi and psi angles) that are formed between the peptide bonds in a protein structure.

In the Strecker synthesis, the compounds that can be formed from ketones or aldehydes are amino acids. Amino acids are organic compounds that contain an amino group (-NH2) and a carboxyl group (-COOH). They are the building blocks of proteins.

A Ramachandran plot, on the other hand, is a graphical representation used to visualize the dihedral angles that are formed between the peptide bonds in a protein structure. These angles are known as phi (Φ) and psi (Ψ) angles. Phi angle refers to the rotation around the alpha carbon (Cα) and the nitrogen (N) atoms, while psi angle refers to the rotation around the alpha carbon (Cα) and the carbon (C) atoms.

In a Ramachandran plot, the x-axis represents the phi angle, and the y-axis represents the psi angle. By plotting the phi and psi angles for each residue in a protein, a Ramachandran plot can provide insights into the overall conformation and stability of the protein structure.

To summarize, the compounds formed in the Strecker synthesis from ketones or aldehydes are amino acids, and a Ramachandran plot can visualize the dihedral angles (phi and psi angles) that are formed between the peptide bonds in a protein structure.

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Answer:

C9H13O3N

Explanation:

Take the atomic mass of C=12.0, H=1.0, O=16.0 and N=14.0.

We can draw a chart (please view this on desktop so to avoid spacing errors):

Let the mass of Epinephrine be 100g.

                             C                       H                          O                              N

mass(g) :              59                      7.15                    26.2                         7.65

no. of moles : 59/12 =4.9167     7.15/1 = 7.15     26.2/16=1.6375 7.65/14=0.5464

(n.o.m. = mass/molar mass)

Ratio:   4.9167/0.5464 =9    7.15/0.5464=13      1.6375= 3      0.5464/0.5464 =1

(divide the n.o.m. by the smallest n.o.m., which is 0.5464 in this case, take the whole numbers)

So, the empirical formula will be: C9H13O3N

But this is still not yet the molecular formula. We have to ensure the molar mass is 183g/mol. Multiply the empirical formula by n.

So, let the molecular formula of Epinephrine be (C9H13O3N)n.

12x9n + 1x13n + 16x3n + 14n = 183

108n + 13n + 48n + 14n = 183

183 n = 183.

n = 1

Hence, the molecular formula is C9H13O3N.

Answer:

Electrovalent / Ionic bond

Explanation:

Hope it helps!!

Answer:

Ahhh! I had the same question

Explanation:

Answer:

The correct answer is O=49.94 approx

Explanation:

To calculate the correct percent composition of (NH4)2CO3, first calculate the molar mass of the compound,

   Molar mass of N: 14.01 g/mol

   Molar mass of H: 1.01 g/mol

   Molar mass of C: 12.01 g/mol

   Molar mass of O: 16.00 g/mol

   Molar mass of (NH4)2CO3: (2 x 14.01 g/mol) + (8 x 1.01 g/mol) + 12.01 g/mol     + (3 x 16.00 g/mol) = 96.09 g/mol

Then we can calculate the percent composition of each element in (NH4)2CO3:

   Percent composition of N: (2 x 14.01 g/mol) / 96.09 g/mol x 100% = 29.14%

   Percent composition of H: (8 x 1.01 g/mol) / 96.09 g/mol x 100% = 8.41%

   Percent composition of C: 12.01 g/mol / 96.09 g/mol x 100% = 12.50%

   Percent composition of O: (3 x 16.00 g/mol) / 96.09 g/mol x 100% = 50.95%

Therefore, the correct percent composition for (NH4)2CO3 is:

   N = 29.14%

   H = 8.41%

   C = 12.50%

   O = 50.95%

Answer: 3.2

Explanation:

The base name for an ester with a propyl group attached to the carbonyl carbon atom is "propyl ester." In the context of a simulation, you would need to extend the left chain according to the given parameters within the simulation for the specific compound you are working with.

If we extend the left chain of an ester with a propyl group attached to the carbonyl carbon atom as far as the simulation allows, we would have the following structure:

CH3-(CH2)2-C(=O)-OR

Where R represents the rest of the ester molecule.The base name for an ester with a propyl group attached to the carbonyl carbon atom is propyl propanoate. This name is derived from the parent carboxylic acid, which is propanoic acid (also known as propionic acid), and the alcohol used to form the ester, which is propanol (also known as 1-propanol or n-propanol).The esterification reaction between propanoic acid and propanol yields propyl propanoate as the ester product, with the elimination of a molecule of water. The ester is commonly used as a flavor and fragrance ingredient in various food and cosmetic products.

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Answer:

It starts at zero, and travels to the other side. Once it reaches the other fixed point, the wave travels back to the starting poing, this is represented as the lighter line. Notice the point right in the middle at p. This point is called a node.

Explanation:

Answer:

The energy for a quantum of light is 2.84 x 10-19

try that

Answer:

86.96

Explanation:

Answer:

0.921 J/g degrees C

Explanation:

Recall that the First Law of Thermodynamics demands that the total internal energy of an isolated system must remain constant. Any amount of energy lost by the brakes must be gained by the tires (in the form of heat in this situation).  Therefore, heat given off by the brakes = −heat taken in by tires, or:

−qbrakes=qtires

The equation used to calculate the quantity of heat energy exchanged in this process is:

−qbrakes=−cbrakes mbrakes ΔTbrakes=ctires mtires ΔTtires=qtires

First we must convert the mass of the tires and the brakes from  kg to  g.

massbrakes=90.7 kg×1,000. g1 kg=9.07×104 g

masstires=123 kg×1,000. g1 kg=1.23×105 g

Next, substitute in known values and rearrange to solve for ctires. Note that the final temperature for both the tires and the brakes is 172∘C, the initial temperature of the brakes is 312∘C and the initial temperature of the tires is 15∘C.

−(1.400Jg∘C)(9.07×104 g)(172∘C−312∘C)=(ctires)(1.23×105 g)(172∘C−15∘C)

ctires=−(1.400 Jg∘C)(9.07×104 g)(−140∘C)(1.23×105 g)(157∘C)=17,777,200 J19311000 g∘C=0.9206Jg∘C

The answer should have three significant figures, so round to 0.921Jg∘C.

Answer:

The answer to your question is given below.

Explanation:

Potassium (K) has 19 electrons with electronic configuration of 2, 8, 8, 1.

Fluorine (F) has 9 electrons with electronic configuration of 2, 7.

Fluorine needs 1 electron to complete it's octet configuration.

Hence, potassium (K), will lose 1 electron to fluorine (F) to form potassium ion (K+) with electronic configuration of 2, 8, 8. The fluorine atom (F) will receive the 1 electron from potassium to form the fluoride ion (F-) with electronic configuration of 2, 8.

**** Please see attached photo for further details.

Answer:

1.)REACTANT

Answer:

I. Concrete sidewalks

Explanation:

One of the factor that affects the infiltration of water into the surface of the soil is the use of concrete sidewalks.

Concrete is impermeable and non - porous media

When concrete pavements are used, water will not be able to move into the ground. They run on the surface and collects into nearby streams and water bodies.

The conditions of temperature and pressure in which a sample of CO₂ (g) would behave least like an ideal gas are high temperature and high pressure; 150°C and 300 kPa, option C

An ideal gas is any gas whose molecules obey the gas law and whose behavior follows the ideal gas behavior.

The behavior of ideal gases is as follows:

For a given gas to behave as an ideal gas, it must be under conditions of extremely high temperatures and low pressure.

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Cu: +2, C: +4, O: -2 in \(CuCO_3\). N: -3, H: +1, Cl: -1 in \(NH_4Cl.\) N: +5, H: +1, Cr: +6 in (\(NH_4)2CrO_4\).
The oxidation number is a measure of the degree of oxidation of an element in a compound.

In \(CuCO_3\), copper (Cu) has an oxidation state of +2, carbon (C) has an oxidation state of +4, and oxygen (O) has an oxidation state of -2.

In \(NH_4Cl\), nitrogen (N) has an oxidation state of -3, hydrogen (H) has an oxidation state of +1, and chlorine (Cl) has an oxidation state of -1.

In (\(NH_4)2CrO_4\), nitrogen (N) has an oxidation state of +5, hydrogen (H) has an oxidation state of +1, and chromium (Cr) has an oxidation state of +6.

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The oxidation number, In the compound CuCO3, Cu has +2,O atom has a -2 , C has a +4 . In NH4Cl, N has a -3 , H has a +1, Cl has a -1. In (NH4)2CrO4, N has a -3,  H has a +1, Cr has a +6, O has a -2.

The oxidation number is a number assigned to each element in a compound that reflects its ability to gain or lose electrons. In the compound CuCO3, Cu has an oxidation number of +2 because it belongs to the group of transition metals and typically has a variable oxidation number. C has an oxidation number of +4 because it forms four covalent bonds with O atoms, and each O atom has a -2 oxidation number. Therefore, the sum of the oxidation numbers of C and O must equal zero. O has an oxidation number of -2 because it is a highly electronegative element that attracts electrons towards itself. In NH4Cl, N has an oxidation number of -3 because it forms three covalent bonds with H atoms, which each have an oxidation number of +1. Cl has an oxidation number of -1 because it is a highly electronegative element that attracts electrons towards itself. In (NH4)2CrO4, N has an oxidation number of -3 again because it forms three covalent bonds with H atoms. H has an oxidation number of +1. Cr has an oxidation number of +6 because it is in Group VI of the periodic table and has six valence electrons. Finally, O has an oxidation number of -2 because it is highly electronegative.

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Answer: 1.3

Explanation: 80 divided by 60 is 1.33333333333

fire in a circle

Explanation:

bc

Answer:

a) Chlorine Trifluoride

b) Dichlorine Heptoxide

GOOD LUCK FOR FUTURE! :)