A new non-electrolyte molecular is discovered. When 241 mg of the molecular is dissolved in 250.0 mL of water, it has an osmotic pressure of 0.072 atm at 25 oC.What is the molar mass of the molecular

Answer: 6.75 moles

Explanation:

This is a simple stoichiometry proboe. that I would set up like this:

(13.5 moles CuCI2) (1 mol I2 / 2 moles CuCi2)

That means you all you have to do for this problem is divide by 2 and cancel out the unit moles CuCI2, which leaves you with 6.75 moles I2.

Hope this helps :)

Answer:

5 m/s²

Explanation:

From the question given above, it took 8 s for the train to get to a speed of 45 m/s. This simply means the train was maintaining 5 m/s as it travels in order to get to an open track.

Thus, we obtained the following data from the question.

Initial velocity (u) = 5 m/s

Final velocity (v) = 45 m/s

Time (t) = 8 s

Acceleration (a) =.?

Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) /t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the velocity of the train as follow:

Initial velocity (u) = 5 m/s

Final velocity (v) = 45 m/s

Time (t) = 8 s

Acceleration (a) =.?

a = (v – u) /t

a = (45 – 5) / 8

a = 40/8

a = 5 m/s²

Therefore, the acceleration of the train is 5 m/s².

Answer:

Its B =)

Explanation:

B. The movement of basketball players on a court of the following is an example of quantization

The process of translating continuously infinite values to a more manageable collection of discontinuous finite values is known as quantization. It involves estimating real-world values with a digital representation that places restrictions on a value's precision and range in the context of simulation and embedded computing.

As a general guideline, quantize to the note you've played that is the shortest; for example, if the phrase contains both eighth and quarter notes, use eighth note resolution. Keep in mind that many rhythms may really employ triplets; if things aren't working out, you may try utilising a triplet resolution.

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Answer:Pretty Big Lol

Explanation:

Answer:

When there is an increase in an activity, like sales or manufacturing, the overall amount of an expense, known as a fixed expense, does not change.

Thus, Normal definitions typically include the phrase within a relevant or appropriate range of activity since a change is likely to take place at fixed expense either an exceptionally high or low volume or expense.

Of course, the rent will probably need to adjust if sales quadruple or fall to 20% of the average level. However, as the extreme circumstances are outside of the relevant range for short-term analysis, the current rent of $2,000 is regarded as a fixed expense.)

The following are some instances of costs that are probably set within a fair range of retail sales, The yearly pay for the shop manager.

Thus, When there is an increase in an activity, like sales or manufacturing, the overall amount of an expense, known as a fixed expense, does not change.

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Answer:

A

Explanation:

I took the test 100%, good luck

Erosion and deposition work together to form sand dunes as waves cause erosion along coastlines and deposit sand away from the shore. So the correct option is A.

Erosion is the removal of the material's surface from the crust of the Earth. It is mainly the debris of soil and rock. The eroded materials are transported by natural agents such as water or wind from the point of their removal.

The term erosion gives an explanation for the wearing down and molding of the landforms on the surface of Earth. This includes the rock weathering from its original position, the transport of this weathered material, and the erosion which is the result of the action of wind or glacial processes, etc.

The more appropriate term for this would be denudation or degradation. This includes processes of mass movement. This is a definition of erosion that is very narrow and excludes the process of the transport of eroded material by natural agencies.

Therefore, the correct option is A.

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Answer:

[H₃O⁺] = 0.0507 M

pH = 1.29

Explanation:

23.1 g of HCI (a strong acid) is added to water to make 1250 mL of solution. Calculate [H₃O⁺] and pH of the solution.

Step 1: Given data

Step 2: Calculate the concentration of HCl

We will use the following expression.

[HCl] = mass HCl / molar mass HCl × liters of solution

[HCl] = 2.31 g / 36.46 g/mol × 1.250 L

[HCl] = 0.0507 M

Step 3: Calculate the concentration of H₃O⁺

HCl is a strong acid according to the following equation.

HCl(aq) + H₂O(l) ⇒ H₃O⁺(aq) + Cl⁻(aq)

The molar ratio of HCl to H₃O⁺ is 1:1. Then, [H₃O⁺] = 0.0507 M.

Step 4: Calculate the pH of the solution

We will use the following expression.

pH = -log [H₃O⁺]

pH = -log 0.0507

pH = 1.29

Answer:

Water molecules will move across the semipermeable membrane from the 0.12% protein solution to the 0.15% protein solution in a process known as osmosis.

Explanation:

Due to the difference in the concentrations of the two solutions as well as the presence of a semipermeable membrane, a concentration gradient is setup. The 0.15% protein solutions contains more protein molecules than the 0.12% protein solution. Water molecules will move across the semipermeable membrane from the 0.12% protein solution to the 0.15% protein solution in a process known as osmosis.

Osmosis is the movement of water molecules across a semipermeable membrane from a region of lower solute concentration or higher concentration of water molecules to a region of higher solute concentration or lower concentration of water molecules until an equilibrium concentration is attained.

This is a passive process and is facilitated by the concentration gradient as well as a presence of a semipermeable membrane which allows only water molecules to move across it but not solute molecules.

Answer:

1.70 L

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = constant = 1.2 atm

Initial volume (V1) = 1.25 L

Initial temperature (T1) = 293 K

Final temperature (T2) = 398 K

Final volume (V2) =?

Since the pressure is constant, the gas is obeying Charles' law. Thus, we can obtain the new volume (V2) of the gas by applying the Charles' equation as shown below:

V1/T1 = V2/T2

1.25 / 293 = V2 /398

Cross multiply

293 × V2 = 1.25 × 398

293 × V2 = 497.5

Divide both side by 293

V2 = 497.5 / 293

V2 = 1.70 L

Therefore, the new volume of the gas is 1.70 L.

Answer:

2ethylhexane

Explanation:

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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Answer:

Overall, energy is released in exothermic and absorbed in endothermic reactions. Therefore, "a" is the correct statement. The other statements are all incorrect.

Explanation:

u suck

Answer:

number of moles = 0.21120811

Explanation:

To find the number of moles, given the mass of the solute, we use the formula:

\(\mathrm{n = \dfrac{ m }{ M } }\)

\(\mathrm{n = number\:of\:moles\:(mol)}\)

\(\mathrm{m = mass\:of\:solute\:(g)}\)

\(\mathrm{M = molar\:mass\:of\:solute\:( \dfrac{ g }{ mol } )}\)

Label the variables with the numbers in the problem:

\(\mathrm{n =\:?}\)

\(\mathrm{m =30\:g }\)

\(\mathrm{M =\:?\:Calculate\:the\:molar\:mass }\)

The first thing we have to do is find the molar mass of sodium sulfate, in order for us to use the formula for finding the number of moles:

Formula for finding the molar mass of sodium sulfate:

\(M({ \left Na \right }_{ 2 } { \left So \right }_{ 4 }) = m \left( Na \right) +m \left( S \right) +m \left( O \right)\)

For the variables and what they mean are below for finding the molar mass of sodium sulfate:

\(\mathrm{M =molar\:mass }\)

\(\mathrm{m =moles=2\:moles\:for\:Na\:,1\:mole\:for\:S,\:and\:4\:moles\:for\:O}\)

\(\mathrm{Na =sodium=22.99\:g }\)

\(\mathrm{S =sulfur=32.06\:g }\)

\(\mathrm{O =oxygen=16.00\:g }\)

Plug the numbers into the formula, to find the molar mass of sodium sulfate:

\(M({ \left Na \right }_{ 2 } { \left So \right }_{ 4 }) = m \left( Na \right) +m \left( S \right) +m \left( O \right)\)

\(\mathrm{Substitute\:the\:values\:into\:the\:formula}\)

\(M = 2 \left( 22.99 \right) +1 \left( 32.06 \right) +4 \left( 16.00 \right)\)

\(\mathrm{Multiply\:2\:by\:22.99\:to\:get\:45.98\:and\:1\:by\:32.06\:to\:get\:32.06}\)

\(\mathrm{M = 45.98+32.06+4\:(16)}\)

\(\mathrm{Multiply\:4\:by\:16\:to\:get\:64}\)

\(\mathrm{M = 45.98+32.06+64}\)

\(\mathrm{Add\:45.98\:and\:32.06\:to\:get\:78.04}\)

\(\mathrm{M = 78.04+64}\)

\(\mathrm{Add\:78.04\:and\:64\:to\:get\:142.04}\)

\(\mathrm{M = 142.04}\)

Now that we have found the molar mass, we can calculate the number of moles in the solution of sodium sulfate with the formula:

\(\mathrm{n = \dfrac{ m }{ M } }\)

\(\mathrm{n =\:?}\)

\(\mathrm{m =30\:g }\)

\(\mathrm{M = 142.04\:g/mol}\)

\(\mathrm{Substitute\:the\:values\:into\:the\:formula}\)

\(\mathrm{n = \dfrac{ 30 }{ 142.04 }}\)

\(\mathrm{Divide\:142.04\:by\:30\:to\:get\:0.21120811}\)

\(\mathrm{n = 0.21120811}\)

0.21120811 rounded gives you 0.2112

or if you did the problem without decimals

30 grams of sodium sulfate divided by its molecular weight – which we found to be 142 – gives us a value of 0.2113 moles.

There are two types of waves that i know of

First one is a longitudinal wave- This is where the movement of the particles are parallel to the energy.

An example of this motion is clapping or speaking into a microphone

The second wave is a transverse wave. This is where they move at a 90 degree angle to the direction of the waves advanced.

An example of this is ripples on the surface of water.

Hope that helps

The viscosity of such a flow is its resistance. Because of the bonding that exists in organic liquids, as the chain lengthens, so does the viscosity. Consequently, the order should be as follows:

CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3

CH3CH2CH2CH2CH2CH2CH2CH3

CH3CH2CH2CH2CH2CH3

A liquid can flow because its molecules can move around one another. The resistance to flow of motor oil is measured by its viscosity. Oil with a low viscosity, such 0W-20, flows more quickly than oil with a high viscosity (e.g. 20W-50). Imagine water and honey to serve as an example. Water flows significantly more quickly than honey when poured from a container. The thicker the oil, the higher the number. Oil thins out as the number decreases. An engine's typical working temperature is 212°F, or 100°C, so an oil with a grade of 5W-30 will have a viscosity rating of 30 at that temperature. When engine parts are cold, thin, low viscosity oils flow more easily to protect them. The film strength needed to protect engines at high temperatures is often best maintained by thick, high viscosity lubricants.

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Answer:

51.16% H₂O

Explanation:

To find the percent water in the hydrate, you need to

(1) calculate the masses of 7H₂O and MgSO₄ · 7H₂O

(2) calculate the percent composition

(Step 1)

Atomic Mass (Mg): 24.305 g/mol

Atomic Mass (S): 32.065 g/mol

Atomic Mass (O): 15.999 g/mol

Atomic Mass (H): 1.008 g/mol

Mass (MgSO₄): 24.305 g + 32.065 g + 4(15.999 g/mol) = 120.366 g

Mass (7H₂O): 14(1.008 g/mol) + 7(15.999 g/mol) = 126.105 g

Mass (MgSO₄·7H₂O): 120.366 g + 126.105 g = 246.471 g

(Step 2)

                                                Mass Water
Percent Composition  =  ----------------------------  x  100%
                                                Total Mass

                                                    126.105 g H₂O
Percent Composition  =  --------------------------------------  x  100%
                                          246.471 g MgSO₄·7H₂O

Percent Composition = 51.16% H₂O

There are 3.44 x 10^{22} particles in 0.057 moles of lithium bromide.

The lithium bromide formula also known as the lithium monobromide formula or Bromo lithium formula is explored. It is a counterion bromide-based salt of lithium.

we have to use Avogadro's constant,

Avogadro's constant, is approximately equal to 6.022 x 10^{22} particles per mole.

we can use the following formula:

number of particles = moles x Avogadro's constant

Substitute the values,

number of particles = 0.057 moles x 6.022 x 10^{23} particles/mol

Simplifying the equation

number of particles = 3.44 x 10^{22} particles

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Answer:

1.)

Explanation:

Answer:

Q1) d Q2) c Q3) d Q4) c  Q5) 350

Explanation:

Q1) (d) One mole of any substance contains 6.02 x 10^23 atoms, molecules or ions.

thus, using ratio we can calculate the number of moles for 6.022 z 10^22

                                           moles   :    atoms

                                               1        :     6.022 x 10 ^23

                                               X       :      6.022 x 10^23

therefore X =  6.022 x 10^22 / 6.022 x 10^23

X = 0.1 moles

Q2) (c) again we use the ratio method:

moles   :  atoms

   1        :   6.022 x 10^23

   3       :     X

and X = 3 x (6.022 x 10^23)

       X = 1.0886 x 10^24

Q3) (d)  again using the ratio method:

moles   :   molecules

  1         :   6.022 x 10^23

   15       :     X

therefore, X = 15 x (6.022 x 10^23)

                 X = 9.033 x 10^24

Q4)  (c) in order to figure out the moles we first calculate the molar mass

Mr = ( 39 + 35.5) = 74.5 g

now to calculate the moles we use the formula: given mass/molar mass

moles = 23/74.5 = 0.3087 moles

Q5) Mr of C10H22O13 =  (12 x 10) + (1 x 22) + (16 x 13)

= 120 + 22 + 208

= 350 g

A) 299 g/mol

B) 229 g/mol

C) 199 g/mol

D) 309 g/mol

Answer A: 6.02 mol

Explanation: 6.022 x 10^22 atoms of aluminium is equal to 6.02 moles of aluminium, since 1 mol of a substance is equal to 6.022 x 10^23 atoms of that substance.

Answer C: 18.066 x 10^24

Explanation: There are 6.022 x 10^23 atoms in 1 mol of a substance, so 3 moles of bromine would contain 18.066 x 10^24 atoms of bromine (3 x 6.022 x 10^23).

Answer A: 6.022 x 10^23 molecules

Explanation: 1 mol of a substance is equal to 6.022 x 10^23 molecules of that substance, so 15 moles would contain 6.022 x 10^23 molecules of carbon dioxide (15 x 6.022 x 10^23).

Answer B: 0.65 mol

Explanation: The molar mass of KCI is 74.55 g/mol, so 23 g of KCI

What is the molecules?

Molecules are the smallest building blocks of matter. Chemical bonds hold the atoms that make them up together. Molecules come in all shapes and sizes, ranging from the simplest molecules such as water, which is composed of two hydrogen atoms and one oxygen atom, to complex molecules such as proteins, which contain hundreds of atoms. Molecules can also interact with each other, forming larger compounds, such as crystals. Molecules can be found in all kinds of materials, including solids, liquids, and gases. They are responsible for many of the physical and chemical properties of materials, such as the color, smell, and taste of a substance. Molecules also play a critical role in the body's functions, helping to regulate hormones, carry oxygen, and provide energy through the breakdown of food.

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Answer:

THE HEAT REQUIRED TO RAISE 29.2 G OF NICKEL BY 51.3 °C IS 663.60 J

Explanation:

Mass of nickel = 29.2 g

Temperature change = 69.6 °C -  18.3°C = 51.3 °C

Specific heat of nickel = 0.443 J/g °C

Heat = unknown

The heat of reaction of nickel is the amount of heat needed to raide a unit mass of nickel by 1 °C

Mathematically.

heat = mass * specific heat * change in temperature

Heat = m C ΔT

Heat = 29.2 * 0.443 * 51.3

Heat = 663.596 J

The heat needed to raise 29.2 g of nickel by 51.3 °C is approximately 663.60 J

Molar mass of H2O = 18 g/mole

Molar mass of O2 = 32 g/mole

Molar mass of glucose = 180 g/mole

What is molar mass?

The molar mass is the substance; it helps to determine the mass of the sample substance to the atom of the sample or substance. The molar mass depends on the molecular formula and the isotopes of the atom. Molar mass is used for the inducement of electric charge. Molar mass is the measurement of the volume of the mass. The molar mass is expressed in the unit of dalton.

A mole is the atom's elementary particle, an ion. The mole of the substance is always related to the Avogadro number. The mole is always associated with the weight or mass of the element or substance. The standard unit of a mole is mol. The mole is a significant factor of the reactant and products to form an equation. A mole calculates the atom, ion, and substance weighs.

6CO2 + 6H2O ----> C6H12O6 + 6O2

Atomic mass C = 12 g/mole

atomic mass of O = 16 g/mole

atomic mass of H = 1 g/mole

Thus, molar mass of CO2 = 44 g/mole

Molar mass of H2O = 18 g/mole

Molar mass of O2 = 32 g/mole

Molar mass of glucose = 180 g/mole

Thus, moles of glucose in 0.075 g of it = mass/molar mass  = 0.075/180 = 0.00042

number of molecules of aspirin = moles*Avagadro's Number = 0.00042*6.022*1023 = 2.509*1020

239Pu + 4He2+ ------> 240Cm + 3n10

Therefore, Green plants take in water (h2o) and carbon dioxide (co2) and produce glucose (c6h12o6) and oxygen gas (o2), the moles are listed above.

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Answer:

isotopes, there elements with a diffrent type atomic weight then the original, usally due to a higher amout of neutrons than the original. Some Isotopes are just as useable as the normal versions, but in some cases, such as Uranium, they can be even more radioactive than the original form

Answer:

The coefficient that must be placed against NaCl to balance this equation is 2.

Explanation:

You have the unbalanced equation:

BaCl₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + NaCl(aq)

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts .

Left side:  1 barium Ba, 2 chlorine Cl, 2 sodium Na, 1 carbon C and 3 oxygen O.

Right side:  1 barium Ba, 1 chlorine Cl, 1 sodium Na, 1 carbon C and 3 oxygen O.

In this case, carbon, barium and oxygen have the same amount on both sides, so it only remains to balance the chlorine and the sodium.  

The coefficients in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter subscripts.

By multiplying the mentioned coefficient by the subscript, you get the quantity of each element present in the reaction.

To balance the chlorine and the sodium, you can modified the coefficients in front of the molecule NaCl  as it's shown in the following:

BaCl₂(aq) + Na₂CO₃(aq) → BaCO₃(s) + 2 NaCl(aq)

Then:

Left side:  1 barium Ba, 2 chlorine Cl, 2 sodium Na, 1 carbon C and 3 oxygen O.

Right side:  1 barium Ba, 2 chlorine Cl, 2 sodium Na, 1 carbon C and 3 oxygen O.

Finally, you have the same amount of each element on both sides.

The coefficient that must be placed against NaCl to balance this equation is 2.

Answer:

2

Explanation:

Answer:

cause they like it that way

Explanation:

btw cant tell if this is legit or not

The balanced molecular equation for the reaction of magnesium nitrate, Mg(NO₃)₂ and sodium phosphate, Na₃PO₄ is:

3Mg(NO₃)₂(aq) + 2Na₃PO₄(aq) → 6NaNO₃(aq) + Mg₃(PO₄)₂(s)

The balanced molecular equation for the reaction of magnesium nitrate, Mg(NO₃)₂ and sodium phosphate, Na₃PO₄ can be written as illustrated below:

Mg(NO₃)₂(aq) + Na₃PO₄(aq) → NaNO₃(aq) + Mg₃(PO₄)₂(s)

There is 1 atom of Mg on the left side and 3 atoms on the right. It can be balanced by writing 3 before Mg(NO₃)₂ as shown below:

3Mg(NO₃)₂(aq) + Na₃PO₄(aq) → NaNO₃(aq) + Mg₃(PO₄)₂(s)

There is 1 atom of P on the left side and 2 atoms on the right. It can be balanced by writing 2 before Na₃PO₄ as shown below:

3Mg(NO₃)₂(aq)  + 2Na₃PO₄(aq) → NaNO₃(aq) + Mg₃(PO₄)₂(s)

There are a total of 6 atom of Na on the left side and 1 atom on the right. It can be balanced by writing 6 before NaNO₃ as shown below:

3Mg(NO₃)₂(aq) + 2Na₃PO₄(aq) → 6NaNO₃(aq) + Mg₃(PO₄)₂(s)

Now, the equation is balanced.

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Answer:

what is the question is it

Answer:

D is the answers for the question

Explanation:

please mark me as brainlest and follow me

Explanation:

hope it's helpful for you

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