A negative point charge q1= -4.00nC is on the x-axis at x=0.60m . A second point charge q2 is on the x-axis at x= -1.20m .
Part a
What must the sign and magnitude of q2 be for the net electric field at the origin to be 50.0 N/C in the +x-direction?
part b
What must the sign and magnitude of q2 be for the net electric field at the origin to be 50.0 N/C in the -x-direction?
Answers
A) the electric field produced by q1 is in the +x-direction since it is negative. b) the sign and magnitude of q2 that would produce a net electric field of 50.0 N/C in the -x-direction are -8.10 nC.
Part a:
To make the net electric field at the origin 50.0 N/C in the +x-direction, q2 must have a positive charge. We can find the magnitude using Coulomb's Law:
E = k * |q| / r^2
Where E is the electric field, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), q is the charge, and r is the distance from the origin.
Since the electric field due to q1 should be equal to 50 N/C at the origin, we have:
50 N/C = k * |-4.00 nC| / (0.60 m)^2
50 N/C = (8.99 x 10^9 N m^2/C^2) * (4.00 x 10^-9 C) / (0.60 m)^2
Solving for q2 gives:
q2 = +3.34 nC
Part b:
To make the net electric field at the origin 50.0 N/C in the -x-direction, q2 must have a negative charge. This time, the total electric field at the origin should be 100 N/C (50 N/C from q1 and 50 N/C from q2) in the +x-direction:
100 N/C = k * |q| / r^2
100 N/C = (8.99 x 10^9 N m^2/C^2) * |-q2| / (1.20 m)^2
Solving for q2 gives:
q2 = -1.67 nC
The formula is:E = kq / r^2whereE is the electric fieldk is Coulomb's constant (9 × 10^9 Nm^2/C^2)q is the charge of the point charger is the distance between the point charge and the location where the electric field is to be calculated
Part a:
To determine the sign and magnitude of q2 that would produce a net electric field of 50.0 N/C in the +x-direction, we need to consider the direction and magnitude of the electric field produced by q1 and q2. We know that the net electric field is in the +x-direction.
Therefore, we can conclude that the electric field produced by q1 is in the -x-direction since it is negative.
To determine the magnitude of q2, we can use the formula:E = kq / r^2The distance between the two charges is 1.8 m (0.60 m + 1.20 m), so we can substitute this value into the formula
:E = (9 × 10^9 Nm^2/C^2) (-4.00 nC) / (1.8 m)^2
Solving for q, we get : q = -8.10 nC
Therefore, the sign and magnitude of q2 that would produce a net electric field of 50.0 N/C in the +x-direction are +8.10 nC.
Part b: To determine the sign and magnitude of q2 that would produce a net electric field of 50.0 N/C in the -x-direction, we need to consider the direction and magnitude of the electric field produced by q1 and q2. We know that the net electric field is in the -x-direction.
Therefore, we can conclude that the electric field produced by q1 is in the +x-direction since it is negative.
To determine the magnitude of q2, we can use the formula:
E = kq / r^2
The distance between the two charges is 1.8 m (0.60 m + 1.20 m), so we can substitute this value into the formula:
E = (9 × 10^9 Nm^2/C^2) (+4.00 nC) / (1.8 m)^2
Solving for q, we get:q = +8.10 nC
Therefore, the sign and magnitude of q2 that would produce a net electric field of 50.0 N/C in the -x-direction are -8.10 nC.
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Related Questions
Acme widgets had an order to process 250 widgets. The first unit required 200 minutes to assemble. Before starting, the company estimated the amount of time it would require to assemble all 250 widgets if they learned at an 85% rate. After assembling all 250 widgets, acme realized they had learned at an 80% rate. How much time less than their estimate did acme take? you should be able to compute the answer within plus or minus 2 hours.
Answers
91.2 hours less was taken to assemble the parts of the widgets by estimation.
Firstly, we will find out the range:
Using the cumulative unit table to determine the range, we get that-
Range = 88.83 - 61.47
Range = 27.36
Secondly, we will calculate the minutes requires to assemble the widgets.
Number of minutes = 27.36 × 200 minutes
Number of minutes = 5472minutes
Now, we have to calculate how much time less than their estimate did acme take:
Time = 5472 / 60
Time = 91.2
Therefore, we get that, 91.2 hours less was taken to assemble the parts of the widgets by estimation.
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if a group of students having an average age of 16 years joined a class, the average age of all the students in the class reduces from 18 years to 17 years. what is the ratio of the number of students who joined the class to the number of students who were initially in the class?
Answers
The ratio of the number of students who joined the class to the number of students who were initially in the class is 2:1.
What is age ratio?Age ratio refers to the comparison of the number of individuals in different age groups in a population. It is often expressed as a ratio or percentage of the number of people in a particular age group to the total population or the number of people in another age group.
Given by the question.
Now, when the group of students with an average age of 16 years joins the class, the average age of all the students becomes 17 years. This means that the total age of all the students in the class would now be 17 times the total number of students.
Let "y" be the number of students who joined the class. Then, the total number of students in the class after they joined would be x + y.
So, we have two equations:
18x = 17(x+y) (because the total age of all the students remains the same before and after the group joins)
16y = (x+y)*1 (because the average age of the new group is 16)
Simplifying the above equations, we get:
x = 17y
x = 34y
Equating both the equations, we get:
17y = 34y
y = 2
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How does the solution to a system of equations compare to the solution of a system of inequalities?.
Answers
A collection of equations with the same variables is known as a system of equations. The only difference is that you're working with inequalities rather than equations in a system of inequalities.
What are inequalities?
An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way. The majority of the time, size comparisons between two numbers on the number line are made.
A system of equations has one solution for each variable, whereas a system of inequalities has a range of possible values for each variable.
Set up the equations as follows:
ax + by = c
dx +ey = f
Let the inequitable system exist:
ax + by <c
dx +ey > f
The same technique, such as graphing, substitution, and elimination, can be used to solve both systems.
But there's a difference because:
A system of equations can only have one solution for each variable, whereas a system of inequalities can have any number of solutions for each variable.
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What equation could represent the situation shown in this model? What is the value of `x`?
Select one:
9x+4=24+x; x=2.5
9x=24+x; x=3
4x=24; x=6
9x=28+x; x=3.5
Assessment question image
Answers
Answer:
what>???????????????????/
Step-by-step explanation:
Answer:
9x+4=24+x; x=2.5
Step-by-step explanation:
A patient is to receive 2.6 grams of medication. The medication is available in capsules of 325 milligrams. How many capsules should be given?
Answers
2,600 mgr /325=8
Answer is 8 capsules
There are 8 capsules should be given to patient.
What is Division method?Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.
We have to given that;
A patient is to receive 2.6 grams of medication.
And, The medication is available in capsules of 325 milligrams.
Here, We know that;
1 gram = 1,000 milligrams
⇒ 2.6 grams = 2.6 × 1000
= 2,600 milligrams
Hence, Number of capsules = 2600/325
= 8
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for the following grouped frequency distribution table, what is the width of each class interval? x f 20-29 2 30-39 5 40-49 4 50-59 1
Answers
The width of each class interval from the given grouped frequency distribution table is 9.
What is a class interval?In a frequency distribution, the numerical width of a class is referred to as the class interval. Data is organised into classes in a grouped frequency distribution. The class interval is determined by the difference between the upper and lower class limits.
The give class intervals are 20-29, 30-39, 40-49 and 50-59.
The size, or width, of a class interval is the difference between the lower and upper class boundaries and is also referred to as the class width, class size, or class length.
So, class width = Upper class - Lower class
29-20=9
39-30=9
Therefore, the width of each class interval is 9.
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please help me ;-; Evaluate the following exponentials at the given values
Given f(x)=5^x-3, find f(5)
Answers
Answer:
Putting x=5 in \(f(x)=\{5^x\}-3\) we get f(5)=3122
Step-by-step explanation:
We need to evaluate \(f(x)=\{5^x\}-3\) when f(5)
Finding f(5) we need to put x=5
\(f(x)=\{5^x\}-3\\x=5\\f(5)=\{5^5\}-3\\f(5)=3125-3\\f(5)=3122\)
So, f(5)=3122
Putting x=5 in \(f(x)=\{5^x\}-3\) we get f(5)=3122
what value of h is needed to complete the square for the equation
Answers
To complete the square for the equation \(x^2 + 8x + 32 = (x - h)^2 + 16\),
we need to choose h = -2.
To complete the square for the given equation
\(x^2 + 8x + 32 = (x - h)^2 + 16\),
we need to express the left-hand side of the equation in the form
\((x - p)^2 + q\), where p and q are constants.
We can start by expanding the right-hand side of the equation:
\((x - h)^2 + 16 = x^2 - 2hx + h^2 + 16\)
Now we can compare the coefficients of \(x^2\), x, and the constant term on both sides of the equation:
\(x^2 + 8x + 32 = (x - p)^2 + q\)
=> \(p^2 = 0\) (since the coefficient of \(x^2\) is 1 on both sides)
=> -2hp = 8 (since the coefficient of x is 8 on the left-hand side)
=> h = -2 (solving for h)
=> q = \(h^2 + 16\) = 20 (since the constant term on the right-hand side is 16)
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The complete question may be:
What value of h is needed to complete the square for the equation \(x^2+8 x+32=(x-h)^2+16\) ?
Hello! High school student in Calculus here. I need help solving the problem attached in the image. If someone could help break down the steps and explain how to solve the problem using BOTH the product rule AND quotient rule methods (because my teacher advised us to learn how to solve both ways), I would greatly appreciate it!
Answers
To find the derivative of the function given we can use the product rule and the quotient rule.
Product rule:
The product rule states that:
\(\frac{d}{dx}(fg)=g\frac{df}{dx}+f\frac{dg}{dx}\)Then, for the function given we have:
\(\begin{gathered} \frac{d}{ds}\lbrack(s^3+4)(4s^2+6)\rbrack=(4s^2+6)\frac{d}{ds}(s^3+4)+(s^3+4)\frac{d}{ds}(4s^2+6) \\ =(4s^2+6)(3s^2)+(s^3+4)(8s) \\ =12s^4+18s^2+8s^4+32s \\ =20s^4+18s^2+32s \end{gathered}\)therefore the derivative is:
\(\frac{dg}{ds}=20s^4+18s^2+32s\)Quotient rule:
To use the quotient rule we need to write the function in the following way:
\(g(s)=\frac{s^3+4}{(4s^2+6)^{-1}}\)Now, the quotient rulre states that:
\(\frac{d}{dx}(\frac{f}{g})=\frac{g\frac{df}{dx}-f\frac{dg}{dx}}{g^2}\)Then, in our case we have:
\(\begin{gathered} \frac{d}{ds}(\frac{s^3+4}{(4s^2+6)^{-1}})=\frac{(4s^2+6)^{-1}\frac{d}{ds}(s^3+4)-(s^3+4)\frac{d}{dx}(4s^2+6)^{-1}}{\lbrack(4s^2+6)^{-1}\rbrack^2} \\ =\frac{(4s^2+6)^{-1}(3s^2)-(s^3+4)\lbrack-(4s^2+6)^{-2}\rbrack^{}(8s)}{\lbrack(4s^2+6)^{-1}\rbrack^2} \\ =\frac{\frac{3s^2}{4s^2+6}+\frac{8s(s^3+4)}{(4s^2+6)^2}}{\lbrack(4s^2+6)^{-1}\rbrack^2} \\ =\frac{\frac{1}{4s^2+6}(3s^2+\frac{8s^4+32s}{4s^2+6})}{\lbrack(4s^2+6)^{-1}\rbrack^2} \\ =\frac{\frac{1}{4s^2+6}(\frac{3s^2(4s^2+6)+8s^4+32s}{4s^2+6})}{\lbrack(4s^2+6)^{-1}\rbrack^2} \\ =\frac{\frac{1}{4s^2+6}(\frac{12s^4+18s^2+8s^4+32s}{4s^2+6})}{\lbrack(4s^2+6)^{-1}\rbrack^2} \\ =\frac{\frac{1}{4s^2+6}(\frac{20s^4+18s^2+32s}{4s^2+6})}{\lbrack(4s^2+6)^{-1}\rbrack^2} \\ =\frac{\frac{20s^4+18s^2+32s}{(4s^2+6)^2}}{\frac{1}{(4s^2+6)^2}} \\ =\frac{(4s^2+6)^2(20s^4+18s^2+32s)}{(4s^2+6)^2} \\ =20s^4+18s^2+32s \end{gathered}\)therefore the derivative is:
\(\frac{dg}{ds}=20s^4+18s^2+32s\)(Notice how we get the same result as before)
PLEASE I REALLY NEED HELP
Answers
Answer:
80 students
Step-by-step explanation:
The line in the middle of the box is the 50% line ( the median, which is 50% above and 50% below)
Since it is at 48, there are 50% above 48 points
3/4 of the students had less than 70 marks
3/4 s = 120
s = 4/3 * 120
The number of students = 160
We need 50 % of the students
50% of 160
.5 * 160 = 80
Given z₁ = 4 cos(cos(π/4)+isin(π/4)) and z₂=2(cos(2π/3)+isin(2π/3)), i, find z₁z₂ ii, find z₁/z₂
Answers
z_1 and z_2 are complex number;
i) z₁z₂ = 8(cos(7π/12) + isin(7π/12))
ii) z₁/z₂ = 2(cos(π/12) + isin(π/12))
To calculate z₁z₂ and z₁/z₂, we need to perform the complex number operations on z₁ and z₂. Let's break down the calculations step by step:
i) To find z₁z₂, we multiply the magnitudes and add the angles:
z₁z₂ = 4cos(cos(π/4) + isin(π/4)) * 2cos(2π/3) + isin(2π/3))
= 8cos((cos(π/4) + 2π/3) + isin((π/4) + 2π/3))
= 8cos(7π/12) + isin(7π/12)
ii) To find z₁/z₂, we divide the magnitudes and subtract the angles:
z₁/z₂ = (4cos(cos(π/4) + isin(π/4))) / (2cos(2π/3) + isin(2π/3))
= (4cos((cos(π/4) - 2π/3) + isin((π/4) - 2π/3))) / 2
= 2cos(π/12) + isin(π/12)
i) z₁z₂ = 8(cos(7π/12) + isin(7π/12))
ii) z₁/z₂ = 2(cos(π/12) + isin(π/12))
Please note that the given calculations are based on the provided complex numbers and their angles.
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Please help. I keep getting these wrong and I am not sure why!
Answers
Solution
\(f\left(x\right)=-\left(x-4\right)^{2}\)The graph
The vertex of a parabola is the point at the intersection of the parabola and its line of
symmetry
Any other point is a point on the graph, you can choose any desired point on the graph
Is this a function or no?
Answers
Answer:
no
Step-by-step explanation:
Calculate the missing term. 32/24 = 20/___
Answers
Answer:
20/30
Step-by-step explanation:
Simplest form of 32/24= 4/3
Multiply both 4 and 3 by 10= 20/30
Hope this helps!
joe is a wrestler and during his workouts he loses 2 pounds. how much water would he have to drink to replenish this water weight loss?
Answers
Answer:
36 ounces or if over 150 lbs drink more water than 36 ounces
Step-by-step explanation:
For every pound of sweat you lose you need to drink 16 ounces of water!
Lia has a dog and a cat. Together, the pets weigh 24 pounds. The dog weighs 2 times as much as the cat.
Answers
Answer:
The dog weighs 16 pounds, while the cat weighs 8 pounds
Step-by-step explanation:
Let's call the weight of the dog d, and the weight of the cat c.
d+c=24
d=2c
Substitute the second equation into the first:
(2c)+c=24
3c=24
c=8
d=24-8=16
Hope this helps!
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Determine each segment length in the right triangle ABC14 14/3 7 14/2 73 72BD=BC=
Answers
The required line segment lengths are AB = 8√2 units and BD= 8 units
In the given question, ΔABC, ΔABD, and ΔDBC are right-angled triangles.
It is also given that DC=AD = 8 units
AC=DC+AD
=8+8
=16 units
In ΔABC, from Trigonometry,
sin(∠BAC) =AB/AC
sin 45 = AB/16
1/√2 = AB/16
AB=16/√2 = 8√2
Again in ΔABC, from Trigonometry,
sin(∠BCA) =BC/AC
⇒ sin(45°) =BC/16
BC= 8√2
In ΔBCD, from Pythagoras theorem,
BC² = CD² + BD²
8√2² - 8² = BD²
BD²= 64×2 -64
BD=8 units.
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Nick's weight to rick's weight is in the ratio 7:5. if nick loses 4 kg and rick puts on 10 kg, their weights will be the same. how heavy is nick?
Answers
Answer:
Nick is 49 kg
Step-by-step explanation:
Let N be Nick's weight in kg and R be Rick's weight in kg
We have the ratio
\(\frac{N}{R}=\frac{7}{5}\) ==> \(R=\frac{5N}{7}\)
The second statement can be mathematically stated as
N - 4 = R + 10 (If Nick loses 4kg and Rick gains 10kg they are both same wt)
Substitute for R in terms of N
\(N - 4 = \frac{5N}{7}+10N\)
\(N - \frac{5N}{7} = 14\)
Multiplying both sides by 7 will get rid of the denominator
7N -5N = 98 ==> 2N=98 ==> N=49
We can easily verify our answer
If Nick is 49, Rick must be (5/7)49 = 35.
N-4 = 49-4 = 45
R+10 = 35 + 10 = 45
And we see they are both the same value
Help me please. These are my last two problems
Answers
Answer:
9. 2ab =30
10.Ans;
\([ \frac{6}{b} ] ^{c} = 4\)
Step-by-step explanation:
9. Ans;
\(2ab = 2(5)(3) = (10)(3) = 30 \)
__o_o__
10. Ans;
\([ \frac{6}{b} ] ^{c} = [ \frac{6}{3} ] ^{2} \\ \\ = [ 2 ] ^{2} = 4\)
I hope I helped you^_^
Noah spent $190 on books. Math books cost $26 and English books cost $28. If he bought a total of 7 books, then how many of each kind did he buy?
Answers
Answer:
he bought three math books and four english books
Step-by-step explanation:
26x3=78 (three books)
28x4=112 (four books)
112+78=190
d=n+4m solve for m plz help
Answers
Answer:
\(m=\frac{d-n}{4}\)
Step-by-step explanation:
\(d=n+4m\\d-n=n+4m-n\\d-n=4m\\\frac{d-n}{4}=\frac{4m}{4}\\\frac{d-n}{4}=m\)
set s is defined as the following: abb ∈ s if s_l, s_r ∈ s, then b⋆s l ⋆a⋆s r ⋆b ∈ s show that for any string in s, the number of bs in the string is twice the number of as in the string.
Answers
To prove that for any string in set s, the number of 'b's in the string is twice the number of 'a's in the string, we will use mathematical induction.
Base case:
Let's consider the simplest string in s, which is 'abb'. The number of 'b's is 2, and the number of 'a's is 1. It satisfies the condition, as 2 is twice the number of 1.
Inductive step:
Assume that for any string in s of length k, the number of 'b's is twice the number of 'a's.
Now, consider a string 's' of length k+1 in set s. By the definition of set s, 's' can be represented as 'b⋆s_l⋆a⋆s_r⋆b', where 's_l' and 's_r' are strings in s.
The number of 'b's in 's' is the sum of the number of 'b's in 's_l' and 's_r' plus 2. Similarly, the number of 'a's in 's' is the sum of the number of 'a's in 's_l' and 's_r' plus 1.
According to the inductive assumption, the number of 'b's in 's_l' and 's_r' is twice the number of 'a's. Thus, the number of 'b's in 's' is twice the number of 'a's.
By mathematical induction, we have proved that for any string in set s, the number of 'b's is twice the number of 'a's.
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WWhat is the equation for the line of reflection? On a coordinate plane, triangle A B C has points (6, 3.7), (5.4, 2), (1, 3). Triangle A prime B prime C prime has points (3.7, 6), (2, 5.4), (3, 1). x = 3 y = 3 y = x x = 6
Answers
Answer:
\(y = x\)
Step-by-step explanation:
Given
\(A =(6,3.7)\)
\(B = (5.4,2)\)
\(C = (1,3)\)
\(A' = (3.7, 6)\)
\(B' = (2, 5.4)\)
\(C' = (3, 1)\)
Required
The equation for the line of reflection
Taking points A and A' as a point of reference:
\(A =(6,3.7)\) and \(A' = (3.7, 6)\)
First, calculate the midpoint (M)
\(M = (\frac{x_2+x_1}{2},\frac{y_2+y_1}{2})\)
\(M = (\frac{3.7+6}{2},\frac{6+3.7}{2})\)
\(M = (\frac{9.7}{2},\frac{9.7}{2})\)
\(M = (4.85, 4.85)\)
Calculate the slope (m)
\(m = \frac{y_2 - y_1}{x_2 - x_1}\)
\(m = \frac{6 - 3.7}{3.7 - 6}\)
\(m = \frac{2.3}{-2.3}\)
\(m = -1\)
The midpoint of a reflection is always perpendicular to the points being reflected.
So, the slope of \(M = (4.85, 4.85)\) is:
\(m_2 = -\frac{1}{m}\)
\(m_2 = -\frac{1}{-1}\)
\(m_2 = 1\)
The equation is then calculated as:
\(y = m_2(x - x_1) + y_1\)
Where:
\((x_1,y_1) = (4.85,4.85)\)
\(y = 1(x - 4.85) + 4.85\)
\(y = x - 4.85 + 4.85\)
\(y = x\)
Hence, the equation of line of reflection is:
\(y = x\)
Answer:
c
Step-by-step explanation:
Victoria needs $299 to purchase a music player. She earns $4.50 per hour from her neighbor
for babysitting. She has already saved $75. Which inequality bestrepresents the minimum
number of hours she will have to babysit to earn enough money to purchase the music
player?
Answers
Answer:
4.50(x)+75=299
Fill in the blanks:
___ triangle ABC by directed line segment B to B’. Next ___ the translated image of ABC across line B’A’. Because rigid transformations were used to map triangle ABC to A’B’C’, corresponding angles and sides are ___.
Answers
The triangle ABC is translated upward and left and then rotate about AB to make A'B'C'.
What is the transformation of a graph?Transformation is rearranging a graph by a given rule it could be either increment of coordinate or decrement or reflection.
Reflection is a mirror image of a graph about any axis.
If we reflect any graph about y = x then the coordinate will interchange it that (x,y) → (y,x).
As per the given triangles,
If we translated the triangle ABC upward and then left then side AB will coincide with side A'B'.
In order to match C with C' we need to rotate the triangle ABC about AB so it will completely coincide.
Hence "The triangle ABC is translated upward and left and then rotate about AB to make A'B'C'".
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These figures are similar. The perimeter and area of one are given. The perimeter of the other is also given. Find its area and round to the nearest tenth.
Perimeter= 20m
Area=19.6m^2
Perimeter=34m
What is the Area=
Answers
The area of the larger figure that is similar to the smaller one is: 28.2 m².
How to Find the Area of Similar Figures?Where A and B represent the areas of two similar figures, and a and b are their corresponding side lengths, respectively, the formula that relates their areas and side lengths is:
Area of figure A / Area of figure B = a²/b².
Given that the two figures are similar as shown in the image above, find each of their respective side lengths if we are given the following:
Perimeter of smaller figure = 20 m
Area of smaller figure = 19.6 m²
Perimeter of larger figure = 34m
Area of larger figure = x
Therefore:
20/34 = a/b
Simplify:
10/17 = a/b.
Find the area (x) of the larger figure using the formula given above:
10²/12² = 19.6/x
100/144 = 19.6/x
100x = 2,822.4
x = 2,822.4/100
x ≈ 28.2 m²
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GUYS AND GIRLS PLEASE HELP
Answers
Answer:
i do not know the answer sorry
a gorcery store sells a smal case of 6 bottles of water $4 and large case of q8 bottles for $10. Is the price per bottle pf water proportional?
Answers
6 bottles for $4 each bottle cost $1.50
the sum of the 4 digit numbers ABCD and DCBB is a multiple of 10.
the digits A,B,C and D are consecutive integers
the number ABCD is a multiple of 3.
so it asks you to find the difference between the numbers ABCD and DCBB
Answers
The difference between the numbers ABCD and DCBB is 10000
How to determine the differenceFrom the information given, we have that:
ABCD and DCBB is a multiple of 10.The digits A,B,C and D are consecutive integersThe number ABCD is a multiple of 3We can say that:
B + D = 10
A = 3
B = 4
C = 5
D = 6
Now,
ABCD = 3456
DCBB = 6544
Difference between the numbers ABCD and DCBB = 3456 + 6544 = 10, 000
Thus, the difference between the numbers ABCD and DCBB is 10000
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a basket of fruits contains 5 apples and 3 pears. sharon took two fruits at random. what is the probability that both fruits are apples?
Answers
The probability that both fruits are apples is 5/14.
We have,
There are 8 fruits in the basket, and 5 of them are apples.
When Sharon takes the first fruit, she has a 5/8 chance of getting an apple.
When Sharon takes the second fruit, there are only 4 fruits left in the basket, and 4 of them are apples.
So the probability of getting another apple is 4/7.
To find the probability of both events happening (i.e. getting two apples in a row), we multiply the probabilities:
P(getting two apples) = (5/8) x (4/7) = 20/56 = 5/14
Therefore,
The probability that both fruits are apples is 5/14.
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