Answers
Answer:
C. 3 m/s²
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
a = (v − u) / t
a = (25 m/s − 10 m/s) / 5 s
a = 3 m/s²
Related Questions
Explain how an object's velocity is related to its acceleration.
Answers
Answer:
Acceleration = Velocity / Time
Explanation:
If an object is changing it's speed, then it's considered to be accelerating. Velocity change = Acceleration
A 2.56×104-kg rocket blasts off vertically from the earth's surface with a constant acceleration. During the motion considered in the problem, assume that g remains constant. Inside the rocket, a 13.6-N instrument hangs from a wire that can support a maximum tension of 27.5 N .
a)Find the minimum time for this rocket to reach the sound barrier (330m/s)
without breaking the inside wire.
b)Find the maximum vertical thrust of the rocket engines under these conditions.
c)How far is the rocket above the earth's surface when it breaks the sound barrier?
Answers
a. The minimum time for the rocket to reach the sound barrier is 33.67 seconds.
b. The maximum vertical thrust of the rocket engines under these conditions is 250,893.6 N.
c. The rocket is 5548.1 meters above the Earth's surface when it breaks the sound barrier.
To solve this problem, we'll use Newton's second law of motion (F = ma) and consider the forces acting on the rocket and the instrument inside.
Calculating the minimum time for the rocket to reach the sound barrier without breaking the inside wire.
a) Minimum time to reach the sound barrier:
Given:
Mass of the rocket (m) = 2.56 × \(10^4\) kg
Acceleration due to gravity (g) = 9.8 m/\(s^2\)
Maximum tension the wire can support (T_max) = 27.5 N
Weight of the instrument (W) = mass of the instrument × acceleration due to gravity = 13.6 N
The forces acting on the instrument inside the rocket are its weight (W) and the tension in the wire (T). At maximum tension, the net force on the instrument is zero.
T - W = 0
T = W
Therefore, the maximum tension in the wire is equal to the weight of the instrument, which is 13.6 N.
Now, let's determine the acceleration of the rocket. The total force acting on the rocket is the sum of the rocket's weight (mg) and the tension in the wire (T).
F_total = mg + T
F_total = (2.56 × \(10^4\) kg)(9.8 m/\(s^2\)) + 13.6 N
F_total = 250,880 N + 13.6 N
F_total = 250,893.6 N
Since we're assuming the rocket's acceleration is constant.
we can use Newton's second law:
F_total = ma
250,893.6 N = (2.56 × \(10^4\) kg)a
Solving for acceleration:
a = 250,893.6 N / (2.56 × \(10^4\) kg)
a ≈ 9.8 m/\(s^2\)
The acceleration of the rocket is approximately 9.8 m/\(s^2\), which is the same as the acceleration due to gravity.
To find the minimum time to reach the sound barrier, we can use the following equation of motion:
v = u + at
where,
v = final velocity (sound barrier velocity = 330 m/s)
u = initial velocity (which is zero since the rocket starts from rest)
a = acceleration
t = time
330 m/s = 0 + (9.8 m/\(s^2\))t
Solving for t:
t = 330 m/s / 9.8 m/\(s^2\)
t ≈ 33.67 s
Therefore, the minimum time for the rocket to reach the sound barrier without breaking the inside wire is approximately 33.67 seconds.
b) Maximum vertical thrust of the rocket engines:
The maximum vertical thrust of the rocket engines is equal to the total force acting on the rocket, which we calculated earlier:
Maximum vertical thrust = F_total
Maximum vertical thrust ≈ 250,893.6 N
Therefore, the maximum vertical thrust of the rocket engines under these conditions is approximately 250,893.6 N.
c) Distance above the Earth's surface when breaking the sound barrier:
To determine the distance above the Earth's surface when breaking the sound barrier, we can use the following equation of motion:
s = ut + (1/2)at^2
where,
s = distance
u = initial velocity (which is zero)
a = acceleration
t = time it takes to reach the sound barrier (33.67 s).
s = 0 + (1/2)( 9.8 m/\(s^2\))\((33.67 s)^2\)
s = (\(4.9 m/s^2\))(1132.8289 \(s^2\))
s ≈ 5548.1 m
Therefore, the rocket is approximately 5548.1 meters (or 5.55 kilometers) above the Earth's surface when it breaks the sound barrier.
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Using the right-hand rule, in which direction will the single wire move, and in which direction will the loop rotate?
Answers
Single Wire moves down, loop rotates left.
About single wireA single-wire system is a method of transmitting power or signals using only a single conductor. This is in contrast to the usual use of a pair of wires to provide a complete circuit, or an electrical cable containing (at least) two conductors for this purpose.
A single-wire transmission line is not the same as a single-wire earth return system. This is beyond the scope of this article. The latter system relies on reverse current flow through earth, using earth as a second conductor between earth terminal electrodes. A single-wire transmission line does not have a second conductor of any kind.
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When external forces acting on an object are balanced, what will happen to the object's
motion?
(7 Points)
The object will speed up.
The object will slow down.
The object will change direction.
The object's motion will remain the same
The object will stop
Answers
Answer:
The objects morion will remain the same
Explanation:
2. What are some of the advantages of the metric system?
Answers
Answer:
Prefixed naming convention. All metric units are clearly related to each other using prefixes. ...
If
y
=
s
i
n
a
x
, then
y
'
is
Answers
Differentiation
DerivativesDerivative NotationDerivative Rule [Basic Power Rule]:
\(\displaystyle\begin{aligned}f(x) & = cx^n \\f'(x) & = c \cdot nx^{n - 1} \\\end{aligned}\)
Derivative Rule [Chain Rule]:
\(\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)\)
Let's define what the problem gives us:
We are given a function \(\displaystyle y = \sin ax\)Step 2: WorkWe know from our trigonometric derivatives that the derivative of \(\displaystyle \sin x\) is equal to \(\displaystyle \cos x\). However, since we have some arbitrary constant \(\displaystyle a\) multiplying \(\displaystyle x\) inside our \(\displaystyle \sin x\) function, we will have to apply the derivative rule of Chain Rule:
\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \boxed{ \cos (ax) (ax)' } \\\end{aligned}\)
To further simply the derivative, we now apply the derivative rule of Basic Power Rule and simplify:
\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \cos (ax) (ax)' \\& = (ax)' \cos ax \\& = 1 \cdot ax^{1-1} \cos ax \\& = ax^0 \cos ax \\& = \boxed{ a \cos ax } \\\end{aligned}\)
Answer∴ the derivative of the function \(\displaystyle y = \sin ax\) is equal to \(\displaystyle \boxed{ y' = a \cos ax }\).
___
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Topic: Calculus
Unit: Differentiation
A body dropped over a fixed rough inclined plane of inclination 45 from height h. If after collision velocity of body becomes horizontal
then co-efficient of restitution if co-efficient of friction is 1/2
Answers
As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.
Identify the body's starting velocity:
We may use the equation of motion to get the body's initial velocity (u)
\(v^2 = u^2 + 2as\)
\(0 = u^2 + 2(-9.8)m/s^2 * h\)
\(u^2 = 19.6h\)
u = √(19.6h)
Determine the coefficient of restitution (e):The body's initial velocity (u) and initial relative velocity (u_rel) are the same.
The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).
\(e = v_{rel }/ u_{rel}\)
e = 0 / u_rel = 0 / u
Now, one can investigate the forces affecting the body: When a body is on an inclined plane.
There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).
The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).
Determine the conditions for the body to stop:
μ * N = m * g * sin(45°)
μ * (m * g * cos(45°)) = m * g * sin(45°)
μ * cos(45°) = sin(45°)
(1/2) * cos(45°) = sin(45°)
Simplifying further, we have:
√2 / 4 = √2 / 2
Thus, the body will come to rest following the collision if the equation is valid.
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At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm.
Calculate the pressure of the gas when it is heated to 900 K.
Answers
The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.
What is the pressure of the gas when it is heated to 900 Kelvin?Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.
It is expressed as;
P₁/T₁ = P₂/T₂
From the data:
Initial pressure P₁ = 3 atmInitial temperature T₁ = 300 KFinal pressure P₂ = ?Initial temperature T₂ = 900 KWe substitute our values into the expression above and solve for final pressure.
P₁/T₁ = P₂/T₂
P₁T₂ = P₂T₁
P₂ = P₁T₂ / T₁
P₂ = ( 3 atm × 900 K ) / 300 K
P₂ = 9.0 atm
Therefore, the final pressure is 9.0 atm.
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A scale measures the weight of a light object to be 11.000 lbs ± 0.034 lbs. what is the uncertainty if this same scale is use to measure an object that weights 78.000 lbs? Assume that the percent uncertainty of the scale remains constant
1)0.034lbs
2)0.044lbs
3)0.310lbs
4)0.240Ibls
Answers
The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.
What is uncertainty in measurement?This is the error associated in an attempt measure the object accurately.The percent uncertainty in measuring the light weight object is calculated as follows;
\(= \frac{0.034}{11} \times 100\%\\\\= 0.309\%\)
The uncertainty of the heavy object if the scale remains constant is calculated as follows;
\(= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs\)
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In some ways, the Hubble Space Telescope could be considered what type of science fiction device?
O
a freeze-ray gun
a time travel machine
a matter transporter
a replicator
Answers
Answer:
Time Travel Machine
Explanation:
The Hubble Space Telescope can look at galaxies that are many light years away. If it captured an image of a star that was 5 light years away, then that means it took light 5 years to reach the lens of the telescope. So, the image we see is what that star looked like 5 years ago. In other words, it is a glimpse of the past.
An acid:decreases the amount of ions in a water solution.feels slippery to the touch, like soap.will have a higher pH than a base.None of the choices are correct.
Answers
From the given options, let's select the correct Answer choice.
An acid can be said to be any substance containing hydrogen which can be able to donate hydrogen ions to another substance.
An acid does not feel slippery, rather it just feels wet. It is a base that is slippery.
An acid has a lower pH when compared to a base. pH less than 7 indicates acidity while pH greater than 7 indicates a base.
When an acid is added to water, the hydroxide ion concentration will reduce and the pH of yhe solution increases towards 7.
Therefore, an acid decreases the amount of ions in a water solution.
ANSWER:
a). Decreases the amount of ions in a water solution.
If the gravitational force disappeared , Earth would break away from its orbit and continue travelling in a ..............line into space.
Answers
Without the sun’s gravitational force, earth would not continue its elliptical orbit around the sun. All of the planets would travel in a straight line away from the sun if not for its strong gravitational pull.
You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answers
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
for the charge distribution provided, indicate the region (a to e) along the horizontal axis where a point exists at which the net electric field is zero. (figure 2)
Answers
At point C along the horizontal axis, the net electric field is zero.
Electrically charged particles are surrounded by a physical phenomenon termed an electric field that either attracts or repels all other adjacent charged particles. The physical field surrounding a system of charged particles can also be referred to. Electric charges and time-varying electric currents make up electric fields.Both electric and magnetic fields are manifestations of the electromagnetic field, one of the four fundamental interactions (sometimes known as forces) of nature.
1. In the region B along the horizontal axis , a point exists at which the net electric field is zero.
2. Nowhere in any region along the horizontal axis the net electric field is zero.
3. In the region A along the horizontal axis , a point exists at which the net electric field is zero.
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Q2.
An aircraft waits at the start of a runway.
The aircraft accelerates from a speed of 0 m/s to a speed of 80 m/s.
The acceleration of the aircraft is 4 m/s².
Calculate the distance, x, travelled by the aircraft while it is accelerating.
Use the equation
X=
v²-u²
2a (Hint: v is final speed; u is initial speed))
Answers
The distance x traveled by the aircraft is 800 m.
What is distance?
Distance can be defined as the length between two points.
To calculate the distance x travelled by rge aircraft, we use the formula below.
Formula:
X = (v²-u²)/2a........... Equation 1\Where:
v = Final velocityu = Initial velocityX = Total distance traveled by the aircrafta = Acceleration of the aircraft.From the question,
v = 80 m/su = 0 m/sa = 4 m/s²Substitute these values into equation 1
X = (80²-0²)/(2×4)X = 800 mHence, the distance x traveled by the aircraft is 800 m.
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Description of a recent example of human trafficking that has displayed in your community
Answers
ASSIGNMENT what is the length of wire whose resistivity 3x10^-6ohm with the r=0.2mm with a given Value of 15.552 Resistance.
Answers
The length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.
Given data: r = 0.2 mm = 0.2 x 10^-3m Resistivity = 3 x 10^-6 ohm R = 15.552 ohm
Formula Used: Resistivity (ρ) = (RA)/L
Where, R is resistance, A is the area of cross-section, L is the length of the wire.
Resistance (R) = ρ (L/A)
Multiplying A on both sides, we get
Resistance (R) x A = ρ L ... equation (1)
Area of the cross-section of a wire of radius (r) is given by, A = πr^2
where, π is a constant whose value is 3.14
Substituting the given values, we get
A = πr^2= π (0.2 x 10^-3m)^2= 1.2566 x 10^-7 m^2
Substituting the values of R, A and ρ in equation (1), we get
Length of wire (L) = (Resistance x Area) / Resistivity= (15.552 ohm x 1.2566 x 10^-7 m^2) / (3 x 10^-6 ohm)= 6.5268 m
Therefore, the length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.
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Select the correct answer.
F₁ = 70 N
F₂ = 15 N
8
F₁
W = 80 N
Use this free body diagram to help you find the magnitude of the force F₁ needed to keep this block in static equilibrium.
Answers
Explanation:
F1 will have to have 65 N vertical up force to balance the net 65 N down on the body AND it will have to have 70 N horizontal to the right to balance the 70 N force that is acting to the left
Magnitude = sqrt ( 65^2 + 70^2) = 95.5 N
POSSIBLE POINTS: 100
What is the frequency of a wave that has a period of 0.32 seconds? Show all work and use correct units of measure
Answers
Answer: \(f=3.125 Hz\)
Explanation:
frequency = 1 / period
\(f=\frac{1}{T}\)
\(f=\frac{1}{0.32}=3.125Hz\)
Therefore, the frequency of the wave is 3.125 Hz.
what is borh's postulates for the hydrogen atom
Answers
Answer:
An atom has a number of stable orbits in which an electron can reside without the emission of radiant energy. ... Each orbit corresponds, to a certain energy level.
Explanation:
Hope it is helpful....
A spaceship hovering over the surface of Uranus drops an object from a height of 19 m. How much longer does it take to reach the surface than if dropped from the same height on Earth? Neglect air resistance in both cases. [The acceleration due to gravity on Uranus is 88.9% of that on Earth, gUranus = (0.889)g.] answer in : s
Answers
h= height = 19 m
g.e = gravity on earth = 9.8 m/s^2
g.u = gravity on Uranus = 9.8 x (88.9/100) = 8.71 m/s^2
Apply :
h = vot + 1/2 gt^2
h= 1/2 g t^2
t = √(2h/g)
Earth:
t= √(2(19)/9.8) = 1.97 s
Uranus
t= √(2(19)/8.71) = 2.09 s
Tu - Te = 2.09 - 1.97 = 0.12 s
Answer : 0.12 s
how can you prove that acceleration is a derived unit
Answers
a = (dx / dt)²
Explanation: Unit of distance is m (metres) and unit of time is s (seconds) speed v is first derivative of distance x versus time:
v = dx / dt, unit is m/s. Acceleration is second derivative of
speed versus time a = (dx / dt)² = (dv/dt) , unit is m/s²
Answer:
Explanation:
Acceleration is derived unit because it has two fundamental units involved i.e. meter and second square.
A bar of soap when weighed in air has a weight of 5,2N . When completely immersed in water , however it has a weight of 3,7N . What is the volume of the bar of soap
Answers
Answer:
A bar of soap when weighed in air has a weight of 5,2N . When completely immersed in water , however it has a weight of 3,7N . What is the volume of the bar of soap
A block of mass kg is initially sliding up the incline and is increasing in speed with acceleration m/s2. the applied force is horizontal, as shown. the coefficients of friction between the block and the incline are and . the angle of the incline is 25.0 degrees. (a) what is the force ? [140,160] n (b) what is the normal force between the block and incline? [125,140] n (c) what is the force of friction on the block? [35,50] n
Answers
(a) The force is 12 N. (b) The normal force between the block and incline is 46.2 N. (c) The force of friction on the block is 12 N.
We can solve this problem using Newton's laws of motion and the equations of motion for objects on inclined planes.
(a) To find the force applied to the block, we can use the equation:
\(F_a_p_p_l_i_e_d = m * a\)
here,\(F_a_p_p_l_i_e_d\) is applied force,
m is mass of the block, and
a is acceleration of the block.
Reserving values:-
\(F_a_p_p_l_i_e_d = (5.2 kg) * (2.3 m/s^2) = 12 N\)
Therefore, the force applied on block is 12 N.
(b) To find the normal force between the block and the incline, we can use the component of the force of gravity that is perpendicular to the incline:-
\(F_n_o_r_m = m * g * cos\theta\)
here,
m is mass of the block,
g is acceleration due to gravity, and
theta is angle of the incline.
Reserving values:-
\(F_n_o_r_m = (5.2 kg) * (9.81 m/s^2) * cos25.0 = 46.2 N\)
Therefore, the normal force between the block and the incline is about 46.2 N.
(c) To find the force of friction on the block, we need to compare the applied force to the maximum frictional force that the surface can provide, which is given by:
\(F_f_r_i_c_t_i_o_n_,_m_a_x = mu * F_n_o_r_m\)
here, mu is coefficient of friction and
\(F_n_o_r_m\) is normal force.
The force of friction acts in the opposite direction to the motion of the block, so it will be downhill in this case. If the block is moving uphill, then the force of friction would be uphill instead.
Reserving values:-
\(F_f_r_i_c_t_i_o_n_,_m_a_x = (0.26) * (46.2 N) = 12.0 N\)
Since the applied force of 12 N is equal to the maximum frictional force, the block will slide with a constant velocity. Therefore, the force of friction on the block is 12 N.
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Question for everybody... Do you like billie eilish or do u hate her and give a explanation why you hate or like her?
Answers
Answer:
I like Billie Eilish
Explanation:
My friend introduced me to yer music and really liked stuff like the 30th and Happier than ever. Me and my friend bond over her music and my friend has her own records that we listen too. Billie sticks up for herself and hasnt had to many big controversal moments and she bring modernism to the music indrustry. We have seen many sides of her and she supports others and seems to be a good be a good human being.
Answer:
Yes I like Billie sm
Explanation:
I've heard her music in so many places for years, and she is on my playlist. She is very amazing! I love Happier than Ever, lovely, and Ocean Eyes, they are my fav!
16. The density difference between warm, moist air and cold air causes the moist
air to rise. This is key to forming
A. lightning.
B. clouds.
C. stars.
D. snow.
Answers
Warm, moist air rises because of the difference in densities between warm, moist air and cold air, which is essential for the formation of clouds.
The moisture in the air condenses into minute water droplets or ice crystals when warm, wet air rises and cools. Clouds are made up of these suspended ice crystals and water droplets.
By reflecting sunlight back into space and storing heat, clouds play a significant part in the Earth's climate system, influencing temperature and weather patterns.
Although lightning is frequently connected to clouds, moist air does not directly cause lightning to occur. Electric charge builds up in the atmosphere, typically during thunderstorms, which leads to lightning.
Snow is created by the freezing of water vapor in the atmosphere, just as stars are created by the gravitational collapse of gas and dust clouds in space.
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A box full of charged plastic balls sits on a table. The electric force exerted on a ball near one upper corner of the box has components 1.2 x 10^-3 N directed north, 5.7 x 10^-4 N directed east and 2.2 x 10^-4 N directed vertically upward. The charge on this ball is 110 nC.
If this ball were replaced with one that has a charge of -50nC , what would be the force components exerted one the replacement ball?
F north=?
F east=?
F up=?
Answers
We have that the values for F north, F east, F up are
\(F_N=1.09090909*10^{-5}\)\(F_E=5.18181818*10^{-6}\)\(F_E=2*10^{-6}\)
From the Question we are told that
electric force \(F_1 = 1.2 x 10^{-3} N(N)\)
electric force , \(F_2=5.7 x 10^{-4} N(E)\)
electric force , \(F_3=2.2 x 10^{-4} N (U)\)
charge on this ball one \(q_1= 110 nC.\)
charge on this ball two \(q_2= -50 nC.\)
Generally the equation for the F north is mathematically given as
\(F_N=\frac{F_1}{q_1}\\\\F_N=\frac{ 1.2 * 10^{-3} )}{110}\)
\(F_N=1.09090909*10^{-5}\)
For F East
\(F_E=\frac{F_2}{q_1}\\\\F_E=\frac{5.7 x 10^-4 }{110}\)
\(F_E=5.18181818*10^{-6}\)
For F UP
\(F_U=\frac{F_3}{q_1}\\\\F_U=\frac{2.2 x 10^-4 }{110}\)
\(F_E=2*10^{-6}\)
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5. Hilda is trying to move a 40 kg couch across a level floor and pushes with a horizontal force of
150 N, but the couch does not move. What is the minimum coefficient of static friction with the
floor? Assume the acceleration due to gravity is g = 9.8 m/s2
Answers
The minimum coefficient of static friction with the floor is 0.3846.
To find the minimum coefficient of static friction with the floor, we need to consider the forces acting on the couch. In this case, the force of gravity is pulling the couch downward with a magnitude of mg, where m is the mass of the couch (40 kg) and g is the acceleration due to gravity (9.8 m/s²).
Since the couch does not move, the force of static friction between the couch and the floor must be equal in magnitude but opposite in direction to the horizontal pushing force of 150 N.
Therefore, we have the equation F_friction = F_push, where F_friction is the force of static friction.
The force of static friction can be calculated using the formula F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.
Since the couch is on a level floor and is not accelerating vertically, the normal force N is equal in magnitude but opposite in direction to the force of gravity, which is mg.
Substituting the values into the equation, we have μs * mg = 150 N.
Solving for μs, we get μs = 150 N / (mg).
Substituting the given values, we have μ_s = 150 N / (40 kg * 9.8 m/s²).
Simplifying, we find that μs = 0.3846.
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A thermos bottle works well because:
a. its glass walls are thin
b. silvering reduces convection
c. vacuum reduces heat radiation
d. silver coating is a poor heat conductor
e. none of the above
Answers
Answer:
A thermos bottle works well because:
A) Its glass walls are thin
Answer:
A thermos bottle works well because:
C
Vacuum reduces heat radiation
A mixture has particles that cannot be seen but do reflect light. It should be classified as a
Answers
Answer:
A mixture has particles that cannot be seen but do reflect light. It should be classified as a colloid. A colloid is a mixture in which one substance is suspended throughout another substance.
Explanation: