A molecule of methane absorbs much more infrared energy than a
molecule of carbon dioxide.
True/False

A substance composed of atoms of more than one element that are held together by chemical bonds is called a compound. Therefore the correct option is option A.

A compound is a pure material that is created by chemically combining two or more distinct components in a specific order. Chemical bonds, which can be ionic or covalent, hold the atoms of a substance together.

The characteristics of compounds are distinct from the characteristics of the constituent parts.

For instance, sodium is a soft metal and chlorine is a greenish-yellow gas; nevertheless, when these two elements combine to produce sodium chloride (table salt), they create a white crystalline solid that is far more stable than the constituent parts of each element alone. Therefore the correct option is option A.

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If the student measures the density of the aluminum as 2. 87 g/mL and the actual value is the 2.69 g/mL,  the student's % error is 6.6 %.

The measures density of the aluminum  = 2.87 g/mL

The actual density of the aluminum = 2.69 g/mL

The expression of the percent error is as follows :

% error = (|actual value - measured value | / actual value ) × 100 %

% error = (|2.87 - 2.69 | / 2.69 ) × 100 %

% error = 0.066 × 100 %

% error  = 6.6 %

Thus, the percent error is 6.6 %.

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This seems to be a Hess' Law problem. Hess' Law states that "states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes." (Libretext)

Compare the step reaction to the final reaction to see the similarity and differences. We may have to flip an equation or multiply it by a constant to obtain the number of moles of the species in the final equation. Just remember, whatever we do to the equation, we have to do to the ΔH as well.

3C  +  4H₂  →  C₃H₈      ΔH= +104 kJ  [1]

      C + O₂ → CO₂        ΔH= -394 kJ  [2]

  2H₂ + O₂ → 2H₂O      ΔH= -572 kJ  [3]

C₃H₈  + 5O₂  → 3CO₂ + 4H₂O  ΔH = ?

_____________________________________________

Compare the Equation

Equation [1]

In [1] the C₃H₈is on the product side. But the final equation has the C₃H₈ on the reactant side. Thus we have to flip the equation. This flips the sign of ΔH.

                C₃H₈   →   3C  +  4H₂     ΔH= - 104 kJ  [1]

Equation [2]

The CO₂ in the final equation is on the product side but is 3 moles. Thus we have to multiply [2] by three. The ΔH is also multiplied by 3.

               3C + 3O₂ → 3CO₂        ΔH= 3 (-394 kJ)    [2]

Equation [3]

The H₂O in the final equation has a coefficient of 4. Thus we have to multiply [3] by 2.

              4H₂ + 2O₂ → 4H₂O      ΔH= 2(-572 kJ)  [3]

Combine the Equations

Combine the newly sorted versions of the equation and simplify to see if it matches the final equation. We also add the ΔH.

⇒  C₃H₈ +  3C + 3O₂ + 4H₂ + 2O₂   →   3C  +  4H₂  + 3CO₂ + 4H₂O

              ΔH= - 104 kJ + 3 (-394 kJ) + 2(-572 kJ)

⇒   C₃H₈ +  + 5 O₂   →  3CO₂ + 4H₂O

              ΔH= - 104 kJ + 3 (-394 kJ) + 2(-572 kJ) = −2430 kJ

Answer:

When an electric current is passed through acidified water, it decomposes to give hydrogen and oxygen gas. The hydrogen gas is obtained at the cathode and the oxygen gas is obtained at the anode

The substance XZ is classified as a compound  when X and Z are chemically bonded, resulting in a new substance with distinct properties.

The correct answer is option C.

The classification of a substance with the formula XZ is fundamental in chemistry and depends on the nature of X and Z and how they chemically combine. Option C, classifying it as a compound, is correct.

A compound is formed when two or more elements chemically bond, resulting in a new substance with unique properties. Compounds have a fixed chemical composition, and the arrangement of X and Z atoms is specific, defining their characteristics like melting and boiling points and reactivity.

Options A and D, suggesting homogeneous or heterogeneous mixtures, are not applicable when chemical bonding occurs. Option B, indicating an element, would only apply if XZ represented a single type of atom or molecule, which is not the case.

Therefore, from the given options the correct one is C.

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Answer:B

Explanation:There you go

Answer:

B

Explanation:

Answer:

65°C

Explanation:

Formula for calorimetry is:

Q = C . m . ΔT

Where Q is heat, C is specific heat, m is mass and ΔT is the difference between final T° and initial.

We have all data to replace.

First of all, we convert kJ to J → 4.94 kJ . 1000 J / 1 kJ = 4940 Joules

We made this conversion because the unit of C, is in J

As heat is lost, we have to think in a negative value. Let's replace:

- 4940 J = 4.18 J/ g °C . 35 g . ( Final T° - 98.8°C)

- 4940 J / (4.18 J/ g °C . 35 g) =  Final T° - 98.8°C

Final T° = - 4940 J / (4.18 J/ g °C . 35 g) + 98.8°C

Final T° = 65.03 °C

Notice, that this answer has sense because as T° decreased, heat has been lost.

Answer:

velocity

Explanation:

"Speed is a measure of the distance an object travels per unit of time."

Type 1A antiarrhythmics are a class of medications used to treat certain types of cardiac arrhythmias, including atrial fibrillation and ventricular tachycardia. Examples of Type 1A antiarrhythmic drugs include quinidine, procainamide, and disopyramide.

These drugs work by blocking the flow of sodium ions through the cell membrane of cardiac muscle cells, which slows down the rate of depolarization and makes it more difficult for an abnormal electrical impulse to be generated. This slows down the heart rate and helps restore normal rhythm.

Type 1A antiarrhythmics are known as "moderate" sodium channel blockers, as they block sodium channels to a moderate degree and have intermediate effects on cardiac conduction. They have a relatively broad range of effects on cardiac action potential and can affect both atrial and ventricular muscle cells.

However, Type 1A antiarrhythmics can have significant side effects, including the risk of inducing arrhythmias, especially if the dose is too high. They can also cause gastrointestinal symptoms, headaches, and hypotension.

Due to these potential risks, Type 1A antiarrhythmics are typically only used in patients with specific arrhythmias and under careful medical supervision.

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Answer:

The answer should be primary pollutants from a stationary source.

Explanation:

Primary pollutants are emitted directly from a source and do not change in the atmosphere, and from a stationary source because manufacturing factories have a fixed location.

Hope this helped :D

After one half life, 50% of the atoms will change to a stable isotope.

After one half life, 50% of the atoms will remain radioactive.

After three half lives, 87.5% of the atoms will change to stable isotope.

After three half lives, 12.5% of the atoms will remain radioactive.

When the initial value of any compound is 100%, after one - half it will reduce to 50%, after the second half -life, it will reduce to 25%, after third half it will reduce to 12.5%.

Half- life may be described as the time required for the radioactivity of a specified isotope to drop to half its initial value.

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Answer:

A. hibernation

Answer:

Hibernation.

Explanation:

Soil erosion is basically the soil being deteriorated by the gradual impact of water or wind to it, being a very mechanical situation, where water or wind will hit the soil, detaching some particles and making the soil weaker. The main cause will be hits from water or wind. Deforestation will have a huge impact on erosion, since the soil where trees are taken down is more likely to receive impacts from wind or water, if the trees were left in their place, they would be used as a "shield" for the soil

The balanced equation becomes: 2Ca + 2H2O -> 2Ca(OH)2 + 2Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3
Now, the equation is balanced with equal numbers of atoms on both sides.

The given equation is: Ca + H2O -> Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3

To balance the equation, we need to ensure that the number of atoms on both sides of the equation is equal.

First, let's balance the calcium (Ca) atoms. There is one Ca atom on the left side and two Ca atoms on the right side. To balance this, we need to put a coefficient of 2 in front of Ca on the left side.

The balanced equation becomes: 2Ca + H2O -> Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3

Next, let's balance the hydrogen (H) atoms. There are two H atoms in H2O and two H atoms in H2SO4 on the left side. On the right side, there are four H atoms in Ca(OH)2 and three H atoms in HNO3. To balance this, we need to put a coefficient of 2 in front of H2O on the left side.

The balanced equation becomes: 2Ca + 2H2O -> Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3

Now, let's balance the oxygen (O) atoms. There are four O atoms in Ca(OH)2 on the right side. To balance this, we need to put a coefficient of 2 in front of Ca(OH)2 on the right side.

The balanced equation becomes: 2Ca + 2H2O -> 2Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3

Finally, let's balance the aluminum (Al) atoms. There is one Al atom on the right side. To balance this, we need to put a coefficient of 2 in front of Al(NO3)3.

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Answer:

[HClO₄] = 0.35 M

Explanation:

Neutralization reaction is:

HClO₄ + LiOH  →  LiClO₄  +  H₂O

In this case, we have a titration between a weak acid and a strong base.

In chemistry it is also called an acid base equilibrium.

HClO₄  +  H₂O  ⇄  ClO₄⁻   +  H₃O⁺       Ka

The weak acid is firstly neutralized by the strong base, in order to have a buffer solution before the equivalence point.

When we reach the equivalence point, mmoles of acid = mmoles of base and there is a formula to determine it so:

M acid . Volume of acid = M base . Volume of base

M acid . 100 mL = 0.75 M . 46.9 mL

M acid = (0.75 M . 46.9 mL) / 100 mL → 0.35 M

Answer:

12) In the ball and stick model, an orange ball representing the phosphorus atom and three green balls representing chlorine atoms are connected by means of sticks that are coloured halfway green and orange respectively to represent the shared electrons between phosphorus and chlorine with the chlorine atoms forming the base of a triangular pyramid while the phosphorus atom forms the top of the pyramid.

13) The scientist will have 6 grams of product as before but will have two grams of unreacted copper atoms because the mass ratio of copper to sulfur in this reaction is 2:1

Explanation:

12) Phosphorus trichloride has a trigonal pyramidal structure and is composed of three atoms of chlorine and one atom of phosphorus.

In the ball and stick model, an orange ball representing the phosphorus atom and three green balls representing chlorine atoms are connected by means of sticks that are coloured halfway green and orange respectively to represent the shared electrons between phosphorus and chlorine with the chlorine atoms forming the base of a triangular pyramid while the phosphorus atom forms the top of the pyramid.

13) The reaction between copper and sulfur to form copper sulfide is shown in the equation below:

Cu + S ---> CuS

1 mole of copper reacts with 1 mole of sulfur to produce 1 mole of copper sulfide

molar mass of copper = 64 g/mol; molar mass of sulfur = 32 g/mol, molar mass of copper sulfide = 96 g/mol

mass ratio of copper to sulfur = 63 g/ 34 g = 2

This means that 2 grams of copper will react with 1 g of sulfur to produce 3 grams of product. similarly, 4 g of copper will react with 2 g of sulfur to produce 6 grams of product.

Therefore 6 g of of copper will react with 3 g of sulfur. However, since the amount of sulfur available for reaction is 2 g only, 2 g of copper will be left unreacted after 4 g has reacted completely with 2 g of sulfur to produce 6 g of copper sulfide.

The equilibrium concentration of I2 will be (n0 - x) / 2.35, and the equilibrium concentration of I will be 2x / 2.35.

To determine the concentrations of the gases at equilibrium for the dissociation of I2 into I atoms, we'll use the given initial moles of I2 and the equilibrium constant (Kc) at 1000 K.

The balanced equation for the reaction is:

I2(g) ⇌ 2I(g)

Let's denote the initial moles of I2 as n0 (given as 0.0459 mol) and the change in moles as x. The equilibrium moles of I2 will be (n0 - x), and the equilibrium moles of I will be (2x).

To calculate the concentrations, we divide the moles by the volume (2.35 L).

The expression for Kc is:

Kc = ([I]^2) / [I2]

Substituting the equilibrium concentrations into the equation, we get:

Kc = ((2x / 2.35)^2) / ((n0 - x) / 2.35)

Given Kc as 3.80×10^(-5), we can solve for x.

3.80×10^(-5) = (4x^2) / (2.35n0 - 2.35x)

Cross-multiplying, we have:

3.80×10^(-5) * (2.35n0 - 2.35x) = 4x^2

Expanding the equation further:

0.0893n0 - 0.0893x = 4x^2

Rearranging the equation:

4x^2 + 0.0893x - 0.0893n0 = 0

Now, we can solve this quadratic equation using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Here, a = 4, b = 0.0893, and c = -0.0893n0.

Substituting these values into the quadratic formula, we find the values of x. There will be two possible values, but we choose the one that is physically meaningful for the given scenario.

Once we determine the value of x, we can calculate the equilibrium concentrations.

By substituting the value of x back into the expressions for the equilibrium concentrations, we can obtain the specific numerical values.

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work done on the ship if it moves 2000m is 15×\(10^{6}\)J

When an external pulling force is applied to an object, the object moves from one place to another or we can simply say that it changes its position. The amount of work required to move the object from its initial position to the final position is directly proportional to the force applied to the object.

Work done depends on two main components that is force and displacement of an object. The displacement of an object must happen along the line of action of the force in order for the force to do work on the object.

Work has units of energy because it is defined as an amount of (transferred) energy, so work usually has units of J (joules).

To calculate work the formula that we use is;

W = F × d, where W = work done, F = Force  and d = distance

W = 7500N × 2000m

W =  15×\(10^{6}\)J

Therefore 15×\(10^{6}\)J of work is done on the ship.

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Answer:

A substance may undergo phase change from a solid to a gas or from a gas to a solid if the temperature it is exposed to is changed very quickly. If the temperature around a solid is raised very quickly, it can sublimate, or phase change from a solid to a gas without existing as a liquid.

Explanation:

The graph shows the behavior of carbon dioxide gas at different temperatures.

The y-axis represents the pressure (P) multiplied by the volume (V) and divided by the absolute temperature (T) of the gas, which is known as the reduced pressure (PV/RT). The x-axis shows the reduced volume of the gas.

The graph displays three curves that represent the behavior of carbon dioxide at different temperatures. The highest curve represents the gas at the highest temperature, while the lowest curve represents the gas at the lowest temperature.

The curve in the middle represents the gas at an intermediate temperature.

To answer the question, you need to rank the curves in order of decreasing temperature. This means you need to place the highest temperature curve first, followed by the intermediate temperature curve, and finally, the lowest temperature curve.

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The balanced chemical equation for the reaction of ascorbic acid (H2C6H6O6) with NaOH is:

H2C6H6O6 + 2 NaOH → Na2C6H6O6 + 2 H2O

From the equation, we can see that 1 mole of ascorbic acid reacts with 2 moles of NaOH.

The number of moles of NaOH used in the titration is:

n(NaOH) = C(NaOH) x V(NaOH)

n(NaOH) = 0.100 mol/L x 0.0220 L

n(NaOH) = 0.00220 mol

Since 2 moles of NaOH react with 1 mole of ascorbic acid, the number of moles of ascorbic acid in the mixture is:

n(H2C6H6O6) = 0.00220 mol / 2 = 0.00110 mol

The mass of ascorbic acid in the mixture is:

m(H2C6H6O6) = n(H2C6H6O6) x M(H2C6H6O6)

m(H2C6H6O6) = 0.00110 mol x 176.13 g/mol

m(H2C6H6O6) = 0.193 g

The percentage of ascorbic acid in the mixture is:

% H2C6H6O6 = (m(H2C6H6O6) / m(mixture)) x 100%

% H2C6H6O6 = (0.193 g / 0.500 g) x 100%

% H2C6H6O6 = 38.6%

Therefore, the mixture contains 38.6% ascorbic acid.

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Answer:

C

Explanation:

I took this class it's C they are balanced

The electronegativity of an atom determines how strongly it attracts electrons in a bond. When atoms with different electronegativities are bonded together, the shared electrons are not equally shared, leading to the formation of a bond dipole.

The direction of the bond dipole is from the less electronegative atom towards the more electronegative atom.

In this series, the electronegativity of the central atom increases from B to C to N, while the electronegativity of the bonded hydrogen atom remains relatively constant. Therefore, the bond dipoles are expected to increase in magnitude from a) BâH > CâH > NâH, since the difference in electronegativity between the central atom and the hydrogen atom becomes larger as we move from N to C to B. The direction of the bond dipoles is from the hydrogen atom towards the central atom.

Therefore, the correct answer is a) BâH > CâH > NâH.

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The structure of n‑methyl‑2‑pyrrolidone when it is heated with aqueous acid. product is given below

A polar solvent without an acidic proton is known as a polar aprotic solvent. These solvents don't include hydroxyl or amine groups. These solvents can act as proton acceptors, but unlike protic solvents, they do not act as proton donors in hydrogen bonding.

After being exposed to a strong aqueous acidic media and being heated, N-methyl-2-pyrrolidone opens up, forming a molecule with a carboxylic group at one end and a protonated nitrogen atom with a methyl group connected to it at the other.

Alcohol, water, hydrogen fluoride, formic acid, acetic acid, ammonia, methanol, ethanol, and other well-known substances are a few examples of polar protic solvents. Polar aprotic solvents, on the other hand, lack acidic protons and do not function as donors during hydrogen bonding.

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Answer:

Using the coarse adjustment knob of the microscope in high power may lead to the breaking of the slide if adjusted and raised the slide too much which can damage the sample as well as the high power lens.

In this case, I would recommend using the fine adjustment knob and moving away from the end of the viewing area of the microscope so there would no collision take place. The fine adjustment will help to get a clear image.

you decide to test your pillbugs' preference for an acidic environment versus a nonacidic environment. on one side of the chamber you place filter paper moistened with water. Dry filter paper is appropriate to place on the other side to test this variable.

Armadillidiidae (Pillbugs) is a family of woodlice, a terrestrial crustacean group in the order Isopoda. Unlike members of some other woodlice families, members of this family can roll into a ball, an ability they share with the outwardly similar but unrelated pill millipedes and other animals. This ability gives woodlice in this family their common names of pill bugs or roly polies.Other common names include slaters, potato bugs, and doodle bugs. Most species are native to the Mediterranean Basin, while a few species have wider European distributions. The best-known species, Armadillidium vulgare, was introduced to New England in the early 19th century and has become widespread throughout North America.

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