A molecule of H2SO4 contains how many atoms?

Answer:

The time taken for the sound wave to make the round trip is 0.16 s.

Explanation:

Given;

distance traveled by the sound wave, d = 120 m

bulk modulus of sea water, B = 2.3 x 10⁹ N/m²

density of sea water, ρ = 1022 kg

The speed of the wave is given by;

\(v = \sqrt{\frac{B}{\rho} } \\\\v = \sqrt{\frac{2.3*10^9}{1022} }\\\\v = 1500.16 \ m/s\)

Speed is given by;

\(Speed = \frac{Distance}{Time}\)

total distance of the round trip = 2 x 120m = 240 m

Time taken for the sound wave to make the round trip is given by;

\(Time = \frac{Distance}{Speed} \\\\Time = \frac{240}{1500.16} \\\\Time = 0.16 \ second\)

Therefore, the time taken for the sound wave to make the round trip is 0.16 s.

Answer:

Yes you  worked

Explanation:

You may have not seen a good outcome but you did put effort in.

When a force is applied on the car and it doesn't move then it simply means

work wasn't done.

The formula for work is given below:

Work = Force ₓ Displacement

For work to have been done , the applied force must cause the object to

change its position(displacement).

In situations where the force applied doesn't cause a change in position then work can't be calculated. This means no work was done on the car despite the applied force causing him to be tired.

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Answer:

True

Explanation:

because their is friction(e.g take a ruler rub it in your hair then put it on top of a piece of paper on the table then u will see the process)among the two objects.

Answer:

HI!!!

Explanation:

Answer:

what is your questions

(a) The work necessary to bring a 101 kg object to a height of 992 km above the surface of the Earth is 986 MJ. (b) The extra work needed to launch the object into circular orbit at a height of 992 km above the surface of the Earth is 458 MJ.

To bring an object to a height of 992 km above the surface of the Earth, we need to do work against the force of gravity. The work done is given by the formula;

W = mgh

where W is work done, m is mass of the object, g is acceleration due to gravity, and h is the height above the surface of the Earth.

Using the given values, we have;

m = 101 kg

g = 9.81 m/s²

h = 992 km = 992,000 m

W = (101 kg)(9.81 m/s²)(992,000 m) = 9.86 × 10¹¹ J

Converting J to MJ, we get;

W = 986 MJ

Therefore, the work necessary to bring a 101 kg object to a height of 992 km above the surface of the Earth is 986 MJ.

To launch the object into circular orbit at this height, we need to do additional work to overcome the gravitational potential energy and give it the necessary kinetic energy to maintain circular orbit. The extra work done is given by the formula;

W = (1/2)mv² - GMm/r

where W is work done, m is mass of the object, v is velocity of the object in circular orbit, G is gravitational constant, M is the mass of the Earth, and r is the distance between the object and the center of the Earth.

We can find the velocity of the object using the formula:

v = √(GM/r)

where √ is the square root symbol. Substituting the given values, we have;

v = √[(6.67 × 10⁻¹¹ N·m²/kg²)(5.97 × 10²⁴ kg)/(6,371 km + 992 km)] = 7,657 m/s

Substituting the values into the formula for work, we have;

W = (1/2)(101 kg)(7,657 m/s)² - (6.67 × 10⁻¹¹ N·m²/kg²)(5.97 × 10²⁴ kg)(101 kg)/(6,371 km + 992 km)

W = 4.58 × 10¹¹ J

Converting J to the required units, we get;

W = 458 MJ

Therefore, the extra work needed to launch the object into circular orbit at a height of 992 km above the surface of the Earth is 458 MJ.

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--The given question is incomplete, the complete question is

"(a) Calculate the work (in MJ) necessary to bring a 101 kg object to a height of 992 km above the surface of the Earth.__ MJ (b) Calculate the extra work (in MJ) needed to launch the object into circular orbit at this height of 992 km above the surface of the Earth .__MJ."--

Answer:

A pair of scales

Explanation:

The electromagnetic spectrum measures the property of waves known as frequency. Frequency is the number of waves that pass a fixed point per second.

The electromagnetic spectrum encompasses all the different types of electromagnetic radiation, which are characterized by their frequency and wavelength. It includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

The frequency of electromagnetic waves is directly proportional to their energy, which means that high-frequency waves have more energy than low-frequency waves. This relationship is important because it allows us to use different types of electromagnetic radiation for different purposes.

For example, radio waves are used for broadcasting radio and television signals, while microwaves are used for communication and cooking food. Infrared radiation is used in remote controls and for heating, while visible light is used for vision and plant growth. Ultraviolet radiation is used for sterilization and tanning, while X-rays are used for medical imaging.

Finally, gamma rays are used for cancer treatment and sterilization. The electromagnetic spectrum is an important tool for scientists and engineers who work with electromagnetic radiation. By understanding the properties of different types of electromagnetic radiation, they can develop new technologies and solve problems in a wide range of fields.

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Answer:

3.4 or 3 11/23

Explanation:

just dive so you can see it as if it were Evelyn distributed

a) Mutual inductance = 0.108 H; Coupling coefficient = 0.482. b) - 4.95 V.


a) Mutual inductance, M between coil A and coil B can be given as:

M = k√(L_AL_B) here, k is the coupling coefficient, L_A and L_B are the inductances of the coil A and coil B respectively. Since 54% of flux produced by coil A links coil B,

So, K = 0.54

L_A = N_A Φ/I_AL_A

= 8120 × 0.02/6

= 27.07 mH

L_B = N_B Φ/I_BL_B

= 11842 × 0.078/6

= 154.63 mH

M = k√(LALB) = 0.482 × √(27.07 × 0.15463) = 0.108 H

b) The emf induced in coil B can be given as:-

ε = M (dI_B/dt)/L_B

ε = 0.108 × (-6/0.015) / 0.15463 = -4.95 V

Thus, the emf induced in coil B when the current is reversed in 0.015 seconds is -4.95 V.

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Given:

The height from the ground is h = 350 m

The gravitational potential energy is GPE = 120,200 J

To find the mass of the hiker.

Explanation:

The mass of the hiker can be calculated by the formula

Here, g =9.8 m/s^2 is the acceleration due to gravity.

On substituting the values, the mass of the hiker will be

Thus, the mass of the hiker is 35.044 kg

To increase the amount of power you get from your solar panel, while working with LiPo batteries that come in multiples of 3.7V, you can consider the following steps:

1. Increase the solar panel's size or efficiency: By using a larger solar panel or a panel with higher efficiency, you can capture more sunlight and generate more power, which can be stored in the LiPo batteries.

2. Optimize the angle and orientation of the solar panel: Adjust the solar panel's angle and orientation to face the sun directly, maximizing the exposure to sunlight and increasing the power generated.

3. Use a voltage converter or a charge controller: A voltage converter can help regulate the voltage from the solar panel to match the battery's voltage requirements, ensuring maximum power transfer. Additionally, a charge controller can be used to manage the charging process and protect the battery from overcharging.

4. Connect multiple solar panels in parallel or series: If you need more power than a single solar panel can provide, you can connect multiple panels in parallel to increase the current or in series to increase the voltage, depending on your battery requirements.

By implementing these steps, you can increase the amount of power you get from your solar panel while working with LiPo batteries that have limited voltage options.

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Given data:

* The initial velocity of the train is 30 m/s.

* The time taken by the train is 44 s.

* The final velocity of the train is zero.

Solution:

(a). By the kinematics equation,

The acceleration of the train in terms of the change in velocity is,

where v is the final velocity, u is the initial velocity, and t is the time taken by the train to stop,

Substituting the known values,

Here, the negative sign indicates the decrease in the velocity with time,

Thus, the accerlation of the train is -0.682 meter per second squared.

(b). By the kinematics equation, the distance tarveled by the train is,

where S is the distance traveled by the train,

Substituting the known values,

Thus, the stopping distance is 661.76 m.

The statement "the ball falls faster during the fourth second than it did during the first second" is false.

The ball falls at a constant acceleration due to gravity, which is approximately 9.8 m/s² near the surface of the Earth. Therefore, the speed of the ball increases at a constant rate as it falls. The equation d = 1/2 * g * t² can be used to calculate the distance the ball falls in a given amount of time, where d is the distance, g is the acceleration due to gravity, and t is the time. The statement "the ball falls a greater distance during the fourth second than it did during the first second" would be true.

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Answer:

chemical energy to sound energy Explanation: BATTERY CONSISTS OF CHEMICAL ENERGY.WHEN OUR RADIO IS OPERATED BY INSERTING BATTERY INTO IT,CHEMICAL ENERGY IN BATTERY IS CONVERTED INTO SOUND ENERGY AND THUS WE HEAR SOUND FROM THE RADIO.

Explanation:

Answer:

YES the first option

Explanation:

two atom are held together

Answer:

In a covalent bond, two atoms are held together by the attraction between each atom and the shared electrons. The number of covalent bonds that an atom can form depends on the number of valence electrons in the atom.

The resistor required to discharge the capacitor to 20.0% of its initial charge in 2.80 ms is approximately 9.77 kΩ.

To determine the value of the resistor required to discharge a 2.00 μF capacitor to 20.0% of its initial charge in 2.80 ms, we can use the equation:

V = V₀ * \(e^{-t/RC}\)

where V is the final voltage (20.0% of the initial voltage), V₀ is the initial voltage, t is the time (2.80 ms), R is the resistance of the resistor, and C is the capacitance of the capacitor (2.00 μF).

We can rearrange the equation to solve for R:
R = -t / (C * ln(V/V₀))

Plugging in the given values, we get:
R = -2.80 ms / (2.00 μF * ln(0.20))
R = 9.77 kΩ

Therefore, the resistor required to discharge the capacitor to 20.0% of its initial charge in 2.80 ms is approximately 9.77 kΩ.

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Answer: encountering Native Americans and Exploring land west of the Colonies

Explanation:

America was buit from people form europe who were white man who wanted power over other people

Answer:C

Explanation:

The frequency of the G allele in the population is 0.4, the correct option is B. 0.4.

The frequency of beetles with glabrous elytra in a population of ground beetles is 0.36. The frequency of the G allele is to be calculated, assuming that the population is in Hardy-Weinberg equilibrium.

What is Hardy-Weinberg equilibrium? The Hardy-Weinberg equilibrium is a model that describes the genetic makeup of a non-evolving population.

This model postulates that the genetic variation in a population remains constant from generation to generation in the absence of disturbing influences such as mutation, migration, or natural selection.

According to the Hardy-Weinberg equilibrium, the frequency of alleles and genotypes remains constant if certain conditions are met.

The Hardy-Weinberg equilibrium is represented by the following equation:p2 + 2pq + q2 = 1 Where:p2 = frequency of homozygous individuals (GG)2pq = frequency of heterozygous individuals (Gg)q2 = frequency of homozygous recessive individuals (gg)p + q = 1Now let's move on to the calculation of the frequency of the G allele.

The frequency of individuals with the gg genotype can be obtained from the following equation:q2 = 0.36q2 = 0.36^(1/2)q = 0.6

The sum of the frequency of all genotypes must be equal to 1, which can be used to calculate the frequency of the G allele:p + q = 1p = 1 - qp = 1 - 0.6p = 0.4The frequency of the G allele in the population is 0.4.Therefore, the correct option is B. 0.4.

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Answer:

11.3

Explanation:

The first nanosatellite from Bhutan to be launched into space was named BHUTAN-1. The satellite was created as part of the Birds-2 program at the Kyushu Institute of Technology. The Birds program aids nations in launching their initial satellite. On June 29, 2018, BHUTAN-1 was put into orbit by the SpaceX CRS-15 mission. On August 10, 2018, it was released from the International Space Station's (ISS) Kib module. The Earth was captured by the satellite's cameras.

The BHUTAN-1 (Bhutan), UiTMSAT-1 (Malaysia), and Maya-1 satellites were created as part of the Birds-2 program (Philippines). Graduate students from Bhutan who were attending Kyutech to complete their master's degrees created BHUTAN-1 (Kyushu Institute of Technology).

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Answer:

The gravity helps the planets stay together near the Sun, without it Earth would be floating away with the planet eventually becoming frozen up, thus the role gravity have in the motion of planets around the sun is by keeping them together.

Explanation:

Hope this helps!

Light travels faster in air than glass

Answer:

\(\boxed{Air}\)

Explanation:

Light travels faster in the air than in glass because glass has a higher refractive index than air.

glass is solid and more packed than air, so the light will have more space and less resistance in the air to travel than in glass.

\(-TheAnimegirl-\)

F =

t = 0.17 s

Impulse (J) = 20,000 N

J = F x t

F = J / t = 20,000 Ns / 0.17 s = 117,647.0588 N

Answer:

A touch screen on a phone is an example of a device that uses a capacitor.

When you bring your finger close to the screen your finger acts as one of the plates.

A sensing circuit works out the position of your finger. The camera on a phone is an example of a device that uses a CCD.

Light hits a grid of devices that produce charge.

Each of the squares is a capacitor.

If a powerful motorcycle can reach 13.57m/s² (58 mi/h) from rest in under 1.90 seconds, its average acceleration is 4.20 m/s2, and it will travel 24.51 m.

The rate at which velocity varies is termed acceleration. Acceleration usually signifies a shift in speed, but not usually. An item that follows a circular course while maintaining a constant speed is still moving forward as the direction of its motion is fluctuating.

given,

initial speed,u = 0 m/s

final speed,v = 25.8 m/s

time, t= 1.90 s

a) acceleration,

a =  v-u/t

a = 25.8-0/1.90

a = 13.57 m/s²

(b) distance to travel in that time

using equation of motion

v² = u² + 2 as

  25.8² = 0² + 2 x 13.57 x s

      13.57 s = 332.7

         s = 24.51 m

the motorcycle will travel 24.51 m

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Answer:

m per second is the answaegnzxn

Answer:

2.205 pounds

Explanation:

5.5 kg is 2.205 lbs. hope this helps!

Answer:

Explanation:

Assuming you want to find the resultant vector of the two given vectors:

We can use the graphical method or the component method to find the resultant vector. Here, I will demonstrate the component method:

Step 1: Convert the given vectors into their component form (i.e., horizontal and vertical components).

Vector 1: 120 N bearing 70°

Horizontal component = 120 cos(70°) ≈ 38.23 N

Vertical component = 120 sin(70°) ≈ 113.41 N

Vector 2: 160 N bearing 40°

Horizontal component = 160 cos(40°) ≈ 122.15 N

Vertical component = 160 sin(40°) ≈ 103.08 N

Step 2: Add the horizontal components and vertical components separately to get the components of the resultant vector.

Horizontal component of resultant vector = 38.23 N + 122.15 N ≈ 160.38 N

Vertical component of resultant vector = 113.41 N + 103.08 N ≈ 216.49 N

Step 3: Use the Pythagorean theorem to find the magnitude of the resultant vector.

Magnitude of resultant vector = √(160.38 N)^2 + (216.49 N)^2 ≈ 268.15 N

Step 4: Find the direction of the resultant vector.

Direction of resultant vector = tan^-1(216.49 N / 160.38 N) ≈ 53.12°

Therefore, the resultant vector of the two given vectors is approximately 268.15 N at a bearing of 53.12°.

Answer:

Wilhelm Wundt

Explanation:

Wilhelm Wundt was the first person referred to as a psychologist.

Wilhelm Maximilian Wundt (1832–1920) had a significant impact on the growth of psychology as a science, particularly in the United States.

With a sarcastic and sardonic demeanor, Wundt fiercely controlled his chosen arenas—the lecture hall and the pages of books—despite being reserved and shy in public.

His range was enormous, and he produced so much. His writings, which amount to around 53,000 pages, include essays on poisons, hypnotism, spiritualism, and politics; textbooks and handbooks on "medical physics" and human physiology; and encyclopedic works on linguistics, logic, and other subjects.

Therefore, Wilhelm Wundt was the first person referred to as a psychologist.

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As an astronaut meal planner, here is a menu for a day's worth of meals in space includes Breakfast, Lunch and Dinner.

Breakfast:

Scrambled Eggs with Vegetables

Special Packaging: Individual vacuum-sealed pouches

Preparation: The scrambled eggs with vegetables will be precooked and dehydrated. Astronauts will rehydrate the meal with hot water, stir, and allow it to sit for a few minutes before consuming. This ensures the eggs and vegetables rehydrate properly in the zero-gravity environment.

Lunch:

Teriyaki Chicken Stir-Fry with Rice

Special Packaging: Sealed pouches for each component (chicken, vegetables, rice, and sauce)

Preparation: The chicken, vegetables, and rice will be precooked and dehydrated separately. The teriyaki sauce will be in a separate pouch. Astronauts will rehydrate each component individually with hot water, then mix them together in a resealable pouch. After a few minutes, the meal will be ready to eat.

Dinner:

Grilled Salmon with Quinoa and Roasted Vegetables

Special Packaging: Vacuum-sealed pouches for each component

Preparation: The salmon will be cooked and then freeze-dried for preservation. The quinoa and roasted vegetables will be precooked and dehydrated separately. Astronauts will rehydrate the quinoa and vegetables with hot water, then warm up the salmon using a food warmer. The components will be combined on a tray and secured with fasteners to prevent them from floating away.

Modifications for space include using dehydration and freeze-drying techniques to remove water content from the food while preserving nutrients. Vacuum-sealed and sealed pouches are used to prevent spoilage and maintain freshness. Rehydration with hot water is necessary to restore the food's texture and taste.

Additionally, it's important to consider portion control and individual packaging to prevent cross-contamination and maintain food safety. The use of condiments and seasonings may be limited to avoid loose particles floating in the spacecraft.

By designing meals that are easy to prepare, consume, and clean up, astronauts can enjoy nutritious and satisfying meals while adapting to the unique challenges of the zero-gravity and non-refrigerated environment in space.

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