a modern state-of-the-art biomass power plant with heat recovery feature has the capacity to combust up to 1.4 x 106 kg/day of pellets to generate energy. the pellets have an average lhv of 18.1 mj/kg and hhv of 19.1 mj/kg. with a capacity factor of 57% and conversion efficiency of 38%, how much energy does this plant generate on an annual basis?

Answer:

The answer is

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

\(KE = \frac{1}{2} m {v}^{2} \)

where

m is the mass

v is the velocity

From the question

m = 5 kg

v = 4 m/s

The kinetic energy is

\(KE = \frac{1}{2} \times 5 \times {4}^{2} \\ = \frac{1}{2} \times 5 \times 16 \\ = 5 \times 8\)

We have the final answer as

Hope this helps you

Answer:The first spacecraft which did not merely fly by a jovian (or giant) planet, but actually went into orbit around it for an extended period of time was option a, Galileo. The Galileo spacecraft was launched in 1989 and orbited Jupiter for almost eight years, from 1995 to 2003.

Explanation:

Answer:

1500 because i aded 500+500+500= 1500 km/hr thats how i got my answer

Explanation:

Answer:

1500 kmh

Explanation:

500+500+500 making it 1500

The efficiency of the engine is 1.57%.

Efficiency is a measure of how well a system converts input energy into useful output energy. It is calculated as the ratio of useful output energy to the total input energy.

To find the efficiency of the engine, we need to calculate the work done by the engine and the heat absorbed from the reservoirs during the cycle.

Step 1: Isothermal expansion at 325 K from 16.1 L to 31.5 L

Since this is an isothermal process, the temperature remains constant at 325 K. The work done by the engine during this process is given by:

W1 = nRT ln(V2/V1)

where n is the number of moles of the gas, R is the universal gas constant, and T is the temperature in kelvin.

n = 1 mol

R = 8.314 J/mol/K

T = 325 K

V1 = 16.1 L

V2 = 31.5 L

W1 = (1 mol)(8.314 J/mol/K)(325 K) ln(31.5 L/16.1 L)

W1 = 4527.6 J

The heat absorbed from the reservoir during this process is given by:

Q1 = W1 = 4527.6 J

Step 2: Cooling at constant volume to 163 K

Since this is a constant volume process, no work is done by the engine. The heat absorbed from the reservoir during this process is given by:

Q2 = nCvΔT

where Cv is the heat capacity at constant volume and ΔT is the change in temperature.

n = 1 mol

Cv = 21 J/K

ΔT = 163 K - 325 K = -162 K

Q2 = (1 mol)(21 J/K)(-162 K)

Q2 = -3402 J

Step 3: Isothermal compression to its original volume of 16.1 L

Since this is an isothermal process, the temperature remains constant at 163 K. The work done on the engine during this process is given by:

W3 = -nRT ln(V2/V1)

where V1 = 31.5 L and V2 = 16.1 L.

n = 1 mol

R = 8.314 J/mol/K

T = 163 K

V1 = 31.5 L

V2 = 16.1 L

W3 = -(1 mol)(8.314 J/mol/K)(163 K) ln(16.1 L/31.5 L)

W3 = -4456.5 J

The heat released to the reservoir during this process is given by:

Q3 = -W3 = 4456.5 J

Step 4: Heating at constant volume to its original temperature of 325 K

Since this is a constant volume process, no work is done by the engine. The heat released to the reservoir during this process is given by:

Q4 = nCvΔT

where Cv is the heat capacity at constant volume and ΔT is the change in temperature.

n = 1 mol

Cv = 21 J/K

ΔT = 325 K - 163 K = 162 K

Q4 = (1 mol)(21 J/K)(162 K)

Q4 = 3402 J

The net work done by the engine is given by the sum of the work done during steps 1 and 3:

Wnet = W1 + W3 = 4527.6 J - 4456.5 J = 71.1 J

The net heat absorbed from the reservoirs is given by the sum of the heat absorbed during steps 1 and 2, and the sum of the heat released during steps 3 and 4:

Qnet = Q1 + Q2 + Q3 +Q4 = 4527.6 J - 3402 J + 4456.5 J - 3402 J = 2179.1 J

The efficiency of the engine is given by:

η = Wnet/Q1 = 71.1 J/4527.6 J = 0.0157 or 1.57%

Therefore, the efficiency of the engine is 1.57%.

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The acceleration of the outer edge of the armature is approximately 33,400 m/s^2.

Centripetal acceleration is the acceleration of a body traversing a circular path directed radially toward the centre of the circle. The centripetal acceleration ac has a magnitude equal to the square of the body’s speed v along the curve divided by the distance r from the centre of the circle to the moving body. Centripetal acceleration has units of metre per second squared.

In order to find the acceleration of the outer edge of the armature, we have to use the formula for centripetal acceleration:

ac = (v^2) / r

where, ac = centripetal acceleration

v = velocity of the outer edge of the armature

r = radius of the armature

v = (2857.0 rev/min) x (2π rad/rev) x (1 min/60 s) x (0.02685 m) ≈ 29.85 m/s.

Now we can plug in the values in the above equation:

ac = (29.85 m/s)^2 / 0.02685 m ≈ 33,400 m/s^2.

Therefore, the acceleration of the outer edge of the armature is approximately 33,400 m/s^2.

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The reason the efficiency is always less than 100% is because there is always some sort of friction in the machine.

Answer: because of friction

Answer:

Nuclear Fusion

Explanation:

The process releases energy because the total mass of the resulting single nucleus is less than the mass of the two original nuclei. The leftover mass becomes energy.

Answer:

Explanation:

neautrons and protons

Answer:

elephant

Explanation:

Answer:

elephant

Explanation:

All of the statements listed are real motions of our "spaceship Earth." Here's an explanation for each statement:Earth moves with the Sun on an orbit around the center of the Milky Way galaxy:

This statement refers to the fact that Earth, along with the other planets in our solar system, orbits around the Sun. This motion is known as the Earth's revolution.Earth and our solar system move with the Milky Way galaxy relative to other galaxies in our Local Group: The Milky Way galaxy, including our solar system and Earth, is in motion relative to other galaxies in our vicinity. This motion is a result of the gravitational interactions and dynamics of the Local Group of galaxies.

Earth and the Local Group move along with the Local Supercluster on an orbit around the center of the Universe: The Local Group, which includes the Milky Way and other nearby galaxies, is part of a larger structure known as the Local Supercluster. This Supercluster, including Earth and the Local Group, is moving on an orbit around the center of the Universe due to the gravitational pull of the large-scale structure of the cosmos.

Earth orbits the Sun: This statement refers to the Earth's motion around the Sun. The Earth follows an elliptical orbit around the Sun, resulting in the changing seasons and the cycle of the year. This motion is known as the Earth's orbital revolution.Therefore, all four statements describe real motions of our "spaceship Earth" in relation to other celestial bodies and structures.

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Answer:

The net force is zero because both volleyball players are hitting the ball with same force.

Explanation:

Answer:

the correct answer is reduce friction

Answer:

D

Explanation:

Magnetic domains are always present in ferromagnetic materials due to the way the atoms bond to form the material. However, when a ferromagnetic material is in the unmagnetized condition, the magnetic domains are randomly oriented so that the magnetic field strength in the piece of material is zero.

Answer:

D. magnetic fields of atoms being aligned with each other

Explanation:

Answer: The spring constant of a given spring is \(40 N/m\).

Explanation:

Given,

Force (F) = 20N

The displacement of the spring\(= x = 0.5 m\)

To find: Spring constant (k) = ?

As we know that,

Hook's law states that,

\(F = k\) · \(x\)

Therefore, \(k = \frac{F}{x}\)

\(k = \frac{20}{0.5}\)

\(k = \frac{(20)(10)}{5}\)

\(k = 40 N/m\)

Hence, The spring constant of a given spring is \(40 N/m\).

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The car tyre contains air initially at a pressure of 195 kPa after travelling several km the temperature of the air inside a car tyre rises from 30 to 70°C if the tyre is rigid and does not expand then the new pressure inside the tyre would be 220.74 kPa.

The total applied force per unit of area is known as the pressure.

The pressure depends both on externally applied force as well the area on which it is applied.

The mathematical expression for the pressure

Pressure = Force /Area

the pressure is expressed by the unit pascal or N /m²

By using the Charles law for gases which states that the volume of the gas remains constant then the pressure of the gas is directly proportional to the temperature.

As given in the problem the tyre is rigid and does not expand this means the volume of the tyre remains constant.

The mathematical expression for Charles's law is as follows

P₁/P₂ = T₁/T₂

First, we have to change the temperature from degree Celcius to the kelvin temperature scale

K = 273 + C

where k is the temperature in kelvin and the C is degrees of Celcius

Initially, the temperature was 30° C

T₁ = 273 + 30

T₁ = 303 K

Then after travelling the temperature of the air inside a car tyre rises from 30 to 70°C

T₂= 273+ 70

T₂ =343 K

The car tyre contains air initially at a pressure of 195 KPa

P₁ = 195 kPa

Lets us take the final pressure of the air would be P₂

By substituting the values in the formula

P₁/P₂ = T₁/T₂

195/P₂ = 303/343

P₂ = 220.74 kPa

Thus, the new pressure inside the tyre would be  220.74 kPa.

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The two types of scientists who could be called upon to investigate a nuclear leak and assess the damage to the environment are: Nuclear Physicists and environmental Scientist.

Two types of scientists who could be called upon to investigate a nuclear leak and assess the damage to the environment are:

Nuclear Physicists: Nuclear physicists specialize in the study of atomic and nuclear processes, including radiation and nuclear reactions. They have expertise in understanding the behavior of radioactive materials, their decay processes, and the potential impacts on the environment. Nuclear physicists can help assess the extent of the leak, analyze the nature of the radioactive substances involved, and determine the potential risks and effects on the environment and living organisms.

Environmental Scientists: Environmental scientists study the interactions between humans and the environment, including the effects of various pollutants and contaminants. In the case of a nuclear leak, environmental scientists can play a crucial role in assessing the impact on ecosystems, air quality, water sources, and soil contamination. They can conduct environmental monitoring, collect and analyze samples, and evaluate the potential short-term and long-term consequences of the leak on local flora, fauna, and human populations.

The expertise of these scientists is beneficial in determining the extent of damage caused by a nuclear leak because they can provide valuable insights into the behavior of radioactive materials, their dispersion in the environment, potential pathways of exposure, and the subsequent impacts on ecosystems and human health. By conducting thorough investigations and employing their scientific knowledge, these scientists can help assess the severity of the leak, develop mitigation strategies, and provide recommendations for remediation and protection of the affected environment.

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A star of the apparent magnitude of +1 would appear farther away than a star of the apparent magnitude of +2. Hence, option B is correct.

In astronomy, a star is a brilliant plasma spheroid that is held together through gravity. The Sun is the planet's closest star. The human eye can see a great number of other stars at night, but due to our planet's size, they seem alike stationary points of light.

Numerous of the shining stars were given names, whereas the most notable stars have been grouped into constellations and asterisms. The known stars have been recognized and given standard designations in star inventories that astronomers have put together.

The birth of a star is caused by the gravitational attraction of a gaseous nebula made largely of hydrogen, helium, and traces of transition metals. Its overall mass is the primary factor influencing how it will develop and end up.

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Answer:

A) T1 = 566 k = 293°C

B) T2 = 1132 k = 859°C

Explanation:

A)

The average kinetic energy of the molecules of an ideal gas is givwn by the formula:

K.E = (3/2)KT

where,

K.E = Average Kinetic Energy

K = Boltzman Constant

T = Absolute Temperature

At 10°C:

K.E = K10

T = 10°C + 273 = 283 K

Therefore,

K10 = (3/2)(K)(283)

FOR TWICE VALUE OF K10:

T = T1

Therefore,

2 K10 = (3/2)(K)(T1)

using the value of K10:

2(3/2)(K)(283) = (3/2)(K)(T1)

T1 = 566 k = 293°C

B)

The average kinetic energy of the molecules of an ideal gas is given by the formula:

K.E = (3/2)KT

but K.E is also given by:

K.E = (1/2)(m)(vrms)²

Therefore,

(3/2)KT = (1/2)(m)(vrms)²

vrms = √(3KT/m)

where,

vrms = Root Mean Square Velocity of Molecule

K = Boltzman Constant

T = Absolute Temperature

m = mass

At

T = 10°C + 273 = 283 K

vrms = √[3K(283)/m]

FOR TWICE VALUE OF vrms:

T = T2

Therefore,

2 vrms = √(3KT2/m)

using the value of vrms:

2√[3K(283)/m] = √(3KT2/m)

2√283 = √T2

Squaring on both sides:

(4)(283) = T2

T2 = 1132 k = 859°C

A) The temperature at which the average kinetic energy will have a value of 2K10 is; T1 = 293 °C

B) The temperature at which the molecules have twice the rms speed, 2vrms is; T2 = 859 °C

A) We are given;

Initial temperature; T = 10°C = 283 K

Initial kinetic energy; KE = K10

Final kinetic energy; KE1 = 2K10

Now,formula for average kinetic energy of the molecules of an ideal gas is given as;

KE = (3/2)kT

Where;

k is Boltzmann constant

T is temperature

We are told that in the second case, KE = 2K10. Thus;

2K10 = (3/2)kT1

K10 = ¾kT1 - - - (eq 2)

In the first instance, we have;

K10 = (3/2)kT - - - (eq 1)

Put (3/2)kT for K10 in eq 2 to get;

(3/2)kT = ¾kT1

k will cancel out to get;

(3/2)T = ¾T1

Make T1 the subject to get;

T1 = 2T

Thus;

T1 = 2 × 283

T1 = 566 K

Converting to °C gives;

T1 = 293 °C

B) We want to find the temperature T2 (in degrees Celsius) at which the molecules will have twice the rms speed, 2v_rms.

Formula for kinetic energy is also;

KE = ½mv²

Thus;

½m(v_rms)² = (3/2)kT

v_rms = √(3kT/m) - - - (eq 1)

When rms speed is 2v_rms, we have;

½m(2v_rms)² = (3/2)kT2

v_rms = √(¾kT2/m) - - - (eq 2)

Thus;

√(3kT/m) = √(¾kT2/m)

Square both sides to get;

(3kT/m) = (¾kT2/m)

4T = T2

T2 = 283 × 4

T2 = 1132 K

Converting to °C gives;

T2 = 859 °C

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The torque acting on the rectangular loop of wire is 6.0 ×   \(10^{-3}\) Nm.

To calculate the torque (τ) acting on the rectangular loop of wire, we can use the formula:

τ=B⋅I⋅A⋅sin⁡(θ)τ=B⋅I⋅A⋅sin(θ)

where B is the magnetic field induction, I is the current, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop's plane.

In this case, the side of length 0.08 m is normal to the lines of induction, so θ = 90°. The area of the loop is given by A = length × width = 0.05 m × 0.08 m.

Substituting the values into the formula, we have:

τ=(1.5×10−2 T)×(10.0 A)×(0.05 m×0.08 m)×sin⁡(90°)=6.0×\(10^{-3}\) Nmτ=(1.5×10−2T)×(10.0A)×(0.05m×0.08m)×sin(90°)=6.0×\(10^{-3}\)  Nm

Therefore, the torque acting on the loop is 6.0 × \(10^{-3}\)  Nm.

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Answer: F = 131.7N

Explanation:

You are given the following parameters.

Mass M = 30 kg

Coefficient of static friction μ = 0.5

Ø = 30 degrees

When the person is trying to drag the box with force F, the static frictional force Fs will be acting in the opposite direction.

From the figure attached, resolve all forces into horizontal component and vertical component.

Horizontal component:

Fs - F cosØ = 0

Fs = F cosØ

F cosØ = μN ...... (1)

Vertical component:

N + F SinØ - mg = 0

N = Mg - F SinØ ..... (2)

Substitutes m, g and Ø into the equation 2

N = (30 × 9.8) - F × sin30

N = 294 - 0.5F

Substitute N and coefficient of friction into the equation (1)

F cos30 = 0.5 (294 - 0.5F)

Open the bracket

0.8660F = 147 - 0.25F

Collect the like terms

1.116025F = 147

F = 147/1.116025

F = 131.7 N

Therefore, the minimum force the person needs to have to move the box along the floor is 131.7 N

Sound travels at approximately 343 meters (or 1,125 feet) per second in dry air at room temperature.

To determine how far away lightning is when thunder sounds 10 seconds after the lightning flash, we can use the speed of sound.

Distance = Speed × Time

Distance = 343 m/s × 10 s

Distance = 3,430 meters

Therefore, if thunder sounds 10 seconds after the lightning flash, the lightning is approximately 3,430 meters (or 3.43 kilometers) away.

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Answer:

The percent uncertainty of the volume=\(\frac{15.70}{523.59} \times 100=2.99\%\)

The volume of sphere with absolute uncertainty=\(523.59 \pm 15.7 cm^3\)

Explanation:

Radius of sphere = 5 cm

Radius with uncertainty r'= \(5 \pm 0.05\)

Volume of sphere = \(\frac{4}{3} \pi r^3=\frac{4}{3} \pi (r')^3\)

\(V=\frac{4}{3} \pi (r')^3\\\frac{dV}{dr'}=4\pi (r')^2\)

Where dV is the uncertainty in volume

dr' is the uncertainty in radius

\(dV=4\pi (r')^2 dr'\\dV=4 \pi (5)^2(0.05)\\dV=15.70\\V=\frac{4}{3} \pi (r')^3=\frac{4}{3} \pi (5)^3=523.59\)

The percent uncertainty of the volume=\(\frac{15.70}{523.59} \times 100=2.99\%\)

The volume of sphere with absolute uncertainty=\(523.59 \pm 15.7 cm^3\)

I hope I helped you^_^

Answer:

54 Km per hour..

Explanation:

Multiply the speed value by 3.6

Answer:

1000m=1km

simple :) . . .

STP is defined as the standard temperature and pressure. These are some standard values given in 1982. the approximate value of n according to the ideal gas law will be 0.986.

The ideal gas equation is derived from the Boyle and Charles law states that the product of pressure and volume is directly propotional to the temperature at STP.

It is mathematically given as

\(\rm pv=nRT\)

P is the pressure =100kPa at STP.

R is universal gas constant=8.314 j/kgk

v is the volume=22.4 L=22.4×10³ m³

T is the temperature =273.15 K at STP

\(\rm pv=nRT\\\\\rm n=\frac{RT}{pv} \\\\\ \rm n=\frac{8.314\times273.15}{100\times10^3\times10^{-3}} \\\\\rm n=0.986\)

Hence the approximate value of n according to the ideal gas law will be 0.986.

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Answer:

1

Explanation:

1 mol = 22.4 L

(a) The magnetic force experienced by the wire when it perpendicular is 0.01 N.

(b) The magnetic force experienced by the wire when the angle is  30⁰ is 5 x 10⁻³ N.

(c) The magnetic force experienced by the wire when it parallel is 0 N.

The magnetic force experienced by the wire is calculated by applying the following;

F = BIL x sin(θ)

where;

When the angle of inclination is perpendicular,  

F = 1 x 10⁻² x 10 x 0.1 x sin(90)

F = 0.01 N

When the angle of inclination is 30⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(30)

F = 5 x 10⁻³ N

When the wire is parallel, the angle is 0⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(0)

F = 0 N

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As the elevator moves upward, the cables are under 1,960 N of tension.

The given parameters are,

The mass of the elevator (m) = 200 kg

According to Newton's Second Law of Motion, an object's force is directly inversely proportional to its mass times its acceleration.

The tension in the cables as the elevator travel upwards is calculated by applying the 2nd law of Newton,

T = ma +mg

where a is the acceleration of the elevator and g is the acceleration due to gravity,

At constant velocity, acceleration is zero. (a =0)

T = m(0) +mg

T = mg

T = 200*9.8

T = 1,960 N

Thus, As the elevator moves upward, the cables are under 1,960 N of tension.

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