A mixture of two gases with a total pressure of 2.00 atm contains 0.70 atm of Gas A. What is the partial pressure of Gas B in atm?

The maximum mass of hydrogen sulfide that can form is 17.01 g.

What is Limiting Reagent?

A limiting reagent, also known as a limiting reactant, is the substance that is completely used up in a chemical reaction and limits the amount of product that can be formed. It is the reactant that is present in the smallest stoichiometric amount and, as a result, determines the theoretical yield of the reaction. The other reactants may be present in excess and may not be completely used up.

To determine which reactant is the limiting reagent, we need to calculate the amount of product that each reactant would produce and see which one produces less.

The balanced chemical equation for the reaction between aluminum sulfide and water is:

First, we need to calculate the amount of moles of each reactant:

moles of Al2S3 = mass ÷ molar mass = 25.00 g ÷ 150.16 g/mol = 0.1664 mol

moles of H2O = mass ÷ molar mass = 50.00 g ÷ 18.02 g/mol = 2.776 mol

Next, we need to determine the limiting reagent. From the balanced equation, we can see that one mole of Al2S3 reacts with 6 moles of H2O. Therefore, the amount of H2O required to react with 0.1664 mol of Al2S3 is:

0.1664 mol Al2S3 × 6 mol H2O/mol Al2S3 = 0.9984 mol H2O

Since we have 2.776 mol of H2O available, we have more than enough water to react with the 0.1664 mol of Al2S3. This means that aluminum sulfide is the limiting reagent.

To calculate the maximum mass of hydrogen sulfide that can form, we need to use the amount of moles of Al2S3 as the basis of our calculation. From the balanced equation, we know that 1 mole of Al2S3 produces 3 moles of H2S. Therefore:

moles of H2S = moles of Al2S3 × 3 mol H2S/mol Al2S3 = 0.1664 mol × 3 mol H2S/mol Al2S3 = 0.4992 mol H2S

Finally, we can calculate the mass of hydrogen sulfide produced using its molar mass:

mass of H2S = moles of H2S × molar mass = 0.4992 mol × 34.08 g/mol = 17.01 g

Therefore, the maximum mass of hydrogen sulfide that can form is 17.01 g.

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Answer:

The atomic mass of second isotope is 112.926 amu.

Explanation:

Given data:

Average atomic mass of indium = 114.818 amu

Atomic mass of one isotope = 114.903 amu

Percentage abundance of 1st isotope = 95.70%

Mass of other isotope = ?

Solution:

First of all we will calculate the percentage abundance second isotope.

100 -  95.70% = 4.3%

percentage abundance of second isotope = 4.3%

Now we will calculate the mass if second isotope.

Average atomic mass of indium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

114.818 = (114.903×95.70)+(x×4.3) /100

114.818 =   10996.2171 + (x4.3) / 100

114.818×100 = 10996.2171 + (x4.3)

11481.8 -  10996.2171  = (x4.3)

485.583 = x

x = 485.583 /4.3

x = 112.926

The atomic mass of second isotope is 112.926.

The electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

The expression 'electronic configuration' makes reference to the spacial arrangement of electrons in distinct energy orbitals of an atom/molecule.

The orbitals are designed with numbers and letters, whereas the amount of electrons in each orbital is expressed as superscripts (e.g., 1s² 2s² 2p² in the C atom that form glucose).

In conclusion, electronic configuration of organic compounds depends on the orbitals of their atoms and molecules.

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The weaker acid involved in the given reaction is HC₂O₄⁻. Option B is correct.

The position of equilibrium in an acid-base reaction can provide information about the relative strength of the acids and bases involved. In the given reaction, if the equilibrium lies to the left, it indicates that the forward reaction is not favored and the reverse reaction is favored.

This means that the products NH₃(aq) and H₂C₂O₄(aq) have a tendency to react and form the reactants HC₂O₄⁻(aq) and NH₄⁺(aq).

Therefore, the acid dissociation constant of HC₂O₄⁻(aq) is K_a1 = 5.9 × 10⁻². The acid dissociation constant of H₂C₂O₄(aq) is K_a2

= 5.9 × 10⁻⁵.

Since the equilibrium lies to the left, it means that the concentration of HC₂O₄⁻(aq) is higher than that of H₂C₂O₄(aq) at equilibrium. This suggests that HC₂O₄⁻(aq) is the weaker acid, as it does not dissociate as much as H₂C₂O₄(aq) does.

Hence, Option B is correct.

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Answer:

1.674 x 10^-23 grams

Explanation:

Hydrogen-1 is called Protium

wikipedia

atomic mass of Protium is 1.00794 amu

sciencedirectcom

atomic mass of 10 Protiums is 10.0794 amu

10.0794 amu in grams is

1.6737236x10^-23 grams

The concentration of reactant A must change by approximately 0.752 M to achieve a non-standard Gibbs free energy of -1.69 kJ.

We will use the non-standard Gibbs free energy equation to solve this problem:

ΔG = ΔG° + RT ln(Q)

where ΔG is the non-standard Gibbs free energy, ΔG° is the standard Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

We will use this equation twice, once for the initial state and once for the final state.

Initial state:

Since the reaction is initially at standard conditions, the concentrations of A and B are both 1 M, and Q = [B]/[A] = 1.

-5.17 = -5.17 + (0.008314)(287) ln(1)

-5.17 = -5.17

The equation is satisfied for the initial state. Now, we want to find the change in concentration of A such that the non-standard Gibbs free energy is -1.69 kJ.

Final state:

ΔG = -1.69 kJ/mol

ΔG° = -5.17 kJ/mol

R = 0.008314 kJ/mol K

T = 287 K

Let x be the change in the concentration of A. Then, the concentration of A in the final state is (1 - x) M, and the concentration of B is (1 + x) M. The reaction quotient for the final state, Q', is given by:

Q' = [B]/[A] = (1 + x)/(1 - x)

Now we can plug everything into the non-standard Gibbs free energy equation for the final state:

-1.69 = -5.17 + (0.008314)(287) ln((1 + x)/(1 - x))

Now we need to solve for x:

4.48 = (0.008314)(287) ln((1 + x)/(1 - x))

4.48 / (0.008314 * 287) = ln((1 + x)/(1 - x))

1.9563 = ln((1 + x)/(1 - x))

Now we find the inverse of the natural logarithm (exponential function):

e^(1.9563) = (1 + x)/(1 - x)

7.073 = (1 + x)/(1 - x)

Now we can solve for x:

7.073(1 - x) = 1 + x

7.073 - 7.073x = 1 + x

8.073x = 6.073

x ≈ 0.752

Thus, the concentration of reactant A must change by approximately 0.752 M to achieve a non-standard Gibbs free energy of -1.69 kJ.

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The equation most likely used to calculate the acceleration from a velocity vs. time graph is a = Δv/t. Therefore, option C is correct.

Acceleration of a body can be defined as the change of the body's velocity per unit of time. The acceleration can be described as a vector quantity exhibiting magnitude as well as direction.

Acceleration can be demonstrated as the 2nd derivative of position w.r.t. time and the 1st derivative of velocity of an object per unit of time.

In the velocity vs. time graph, the velocity is plotted along the y-axis and the time is plotted along the x-axis. the slope of the graph is equal to acceleration.

Acceleration, a = (v₂ - v₁)/(t₂ - t₁) = Δv/t

Therefore, a = Δv/t

Therefore, the equation a = delta-v over t can be used to determine the acceleration from a velocity vs. time graph.

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Answer:

the first one(atoms only give off certain frequencies)

Explanation:

Taking into account the Charles's law, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C. ​

Charles's law shows the relationship between the volume and temperature of a gas sample at constant pressure.

This law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

\(\frac{V}{T}= k\)

Considering an initial state 1 and an initial state 2:

\(\frac{V1}{T1}= \frac{V2}{T2}\)

In  this case, you know:

Replacing in Charles's Law:

\(\frac{0.0141 m^{3} }{284.5 K}=\frac{V2}{368 K}\)

Solving:

\(\frac{0.0141 m^{3} }{284.5 K}x368 K=V2\)

0.0182 m³= V2

Finally, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C. ​

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What will be the temperature?

Let's see

Let

According to Amonton's or Gay Lussacs law

\(\\ \rm\Rrightarrow P\propto T\)

So if pressure is quadrupled then temperature will be also quadrupled.

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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Answer:

Atoms of the same element can have different numbers of neutrons.

Explanation:

This statement is true because atoms of the same element have the same number of protons, which determines the element's atomic number. However, they can have different numbers of neutrons, which gives rise to different isotopes of that element. These isotopes have the same number of protons, but different numbers of neutrons, leading to different atomic weights. So, while the number of protons is fixed for a particular element, the number of neutrons can vary.

Magnesium-24, with an atomic mass of 24 u, is the most prevalent isotope of magnesium.

Isotopes are atoms that have the same number of protons but differing numbers of neutrons. They have nearly identical chemical characteristics but differ in mass and hence in physical qualities. A chemical element in which the atoms have the same number of protons (part of an atom's nucleus) but a distinct number of neutrons (part of the nucleus of an atom). Carbon isotopes include carbon 12, carbon 13, and carbon 14.

Here,

The average atomic mass of an element is a weighted average of the masses of its isotopes, with the weights being the abundances of the isotopes. So, to determine the most abundant isotope of magnesium, we need to compare the abundances of its three isotopes and find the one with the highest abundance. Since the average atomic mass of magnesium is 24.305 u, we can use this value and the atomic masses of the three isotopes of magnesium to estimate their abundances. However, this requires more information and calculations that are beyond the scope of this answer.

In general, the most abundant isotope of magnesium is magnesium-24, which has an atomic mass of 24 u.

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The Brønsted-Lowry reaction can be written as; \(HPO_{4} ^{2-} + HNO_{2} ----- > H_{2} PO_{4} ^- + NO_{2}^-\). A proton was transferred in the reaction.

We know that there are various definitions of acids and bases. One of the definitions of an acid is that an acid is a substance that is able to donate a proton. In this case we look upon an acid as a proton donor in a reaction. The base is a substance that is able to able to accept to proton hence we would classify the base as a proton acceptor in a given reaction.

We now have to look at the reaction as we have seen it here. In this case, we are looking at the reaction between the substance and we are looking at the one that looses a proton and the one that gained a proton so as to be able to obtain the products of the reaction.

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Centrifugation, a technique that separates particles based on their density, is used to separate a mixture of solid components of blood.

A important biological fluid called blood circulates throughout the body, carrying nutrients and oxygen to the tissues and eliminating waste. It is made up of platelets, plasma, and red and white blood cells.

The centrifuge, a device that spins the blood sample at high speeds to separate the solid from the liquid components of the sample, is used to collect a blood sample.

White blood cells and platelets form a thin layer above red blood cells, while red blood cells, which are denser than other blood components, settle at the bottom of the tube. At the top of the tube is the plasma, which is the liquid portion of blood.

The layers of the sample can be delicately scraped off using a pipette after centrifugation, allowing the liquid and solid components of blood to be separated. Certain blood components, such as red blood cells or platelets, are isolated with this approach in lab settings for further examination or therapy.

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The order of increasing ionic property is;

WO3 < ZrS2 < MnS2< ZnS < MnS

Ionic compounds are compounds that contain an ion pair. Typically, ionic compounds are formed between metals and nonmetals.

The degree of ionic character depends on the type of metal involved and the magnitude of charge it carries.

Typically, first row transition metals form ionic compounds. The degree of ionic character depends on the row in which the metal is found and the magnitude of charge it carries.

Hence, the order of ionic character of the compounds from most ionic to least Ionic is; WO3 < ZrS2 < MnS2< ZnS < MnS.

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Explanation:

The intermolecular forces present in the bonding of CH₃F are dipole-dipole interactions and London dispersion forces.

1.) No, CH₃F does not exhibit hydrogen bonding. Hydrogen bonding occurs when a hydrogen atom is bonded to a highly electronegative atom such as fluorine, oxygen, or nitrogen. In CH₃F, the hydrogen atom is bonded to carbon, which is not highly electronegative.

2.) Yes, CH₃F exhibits dipole-dipole interactions. Dipole-dipole interactions occur between molecules that have permanent dipoles due to the electronegativity difference between the atoms. In CH₃F, the fluorine atom is more electronegative than the carbon and hydrogen atoms, resulting in a polar molecule with a permanent dipole moment.

3.) Yes, CH₃F exhibits London dispersion forces. London's dispersion forces, also known as Van der Waals forces, are present in all molecules and arise from temporary fluctuations in electron distribution. Although CH₃F has dipole-dipole interactions, it also experiences London dispersion forces due to the temporary shifts in electron density.

Hence, the bonding in CH₃F was explained above.

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The percent yield of \(Fe_2O_3\)  if 57.8g was collected is 75.1%.

To calculate the percent yield, we need to compare the actual yield (the amount of\(Fe_2O_3\) collected) to the theoretical yield (the amount of \(Fe_2O_3\)that would be obtained if the reaction went to completion).

First, we need to determine the molar mass of \(Fe_2O_3\) and \(Fe_2S_3\):

Molar mass of \(Fe_2O_3\):

2(55.85 g/mol) + 3(16.00 g/mol) = 159.69 g/mol

Molar mass of\(Fe_2S_3\):

2(55.85 g/mol) + 3(32.07 g/mol) = 207.67 g/mol

Next, we can calculate the theoretical yield of\(Fe_2O_3\) using stoichiometry:

2 moles of \(Fe_2S_3\) produce 2 moles of \(Fe_2O_3\)(according to the balanced equation).

So, the molar ratio of \(Fe_2O_3\)to Fe2S3 is 2:2.

The molar mass ratio of \(Fe_2O_3\) to Fe2S3 is:

159.69 g/mol : 207.67 g/mol

To calculate the theoretical yield, we can use the following equation:

Theoretical yield of\(Fe_2O_3\) = (mass of \(Fe_2S_3\)) * (molar mass of \(Fe_2O_3\) / molar mass of \(Fe_2S_3\))

Theoretical yield of \(Fe_2O_3\) = (100.0 g) * (159.69 g/mol / 207.67 g/mol)

Theoretical yield of \(Fe_2O_3\) = 76.46 g

Now we can calculate the percent yield using the formula:

Percent yield = (actual yield / theoretical yield) * 100

Percent yield = (57.8 g / 76.46 g) * 100

Percent yield = 75.1%

Therefore, the percent yield of \(Fe_2O_3\) is 75.1%.

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Answer:

D. Na+

Explanation:

Na+ is the only ion here that is not related to pH. Adding OH- increases pH, and adding H3O+ or H+ (the two are interchangeable) decreases pH.

Daria had some beach sand with her. The sand has a 72 gramme mass. She calculated the volume using the graduated cylinder below. The graduated cylinder contains 15 mL of sand.

The volume of the sand is calculated using the graduated cylinder below. The sand's bulk is specified as 72 grammes.

We can use the water displacement method to calculate the volume of the sand. Following is a description of how to estimate the amount of sand using the water displacement method:

The graduated cylinder of water should first be measured for volume.

The graduated cylinder's water volume should then be measured after adding the sand to it. The volume of water increases by the same amount.

Let's use the provided problem to implement this approach.

In the beginning, there is 10 mL of water in the graduated cylinder. The graduated cylinder contains 25 mL of water once the sand has been added.

The amount of sand is therefore equal to the difference between the two volumes, which is: Sand volume equals final water volume minus initial water volume (25 - 10 = 15 mL).

As a result, there are 15 mL of sand in the graduated cylinder.

Answer : 15

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Barium chloride turned from sparkly white into dull white during the heating process.

An inorganic substance with the formula BaCl2 is barium chloride. It is among the most popular barium salts that dissolve in water. Like the majority of some of the other water-soluble barium salts, is also white, extremely hazardous, and gives flames a yellow-green tint.

Among the most common barium salts is barium chloride. Bacl2 is hygroscopic and soluble in water. Deep hypokalemia, generalized muscle weakness, and eventually paralysis of the limbs and breathing muscles can occur within 1 to 4 hours of consumption.

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Answer:

C.) No. of electrons

Explanation:

A.) is incorrect. The atomic number represents the number of protons in an element. Nitrogen (N) and sodium (Na) always have a differing amount of protons.

B.) is incorrect. The mass number represents the number of protons and neutrons in an element. The number of neutrons and protons are specific to each element (disregarding isotopes). When elements ionize, these amounts are not altered.

C.) is correct. When an element becomes an ion, the number of electrons change. When nitrogen gains 3 electrons and sodium loses 1 electron, they end up having the same number of electrons (10).

D.) is incorrect. When elements ionize, the number of neutrons does not change. The only way two different elements could have the same number of neutrons is if at least one of the elements is an isotope. Isotopes are two or more atoms of the same element that differ in their amounts of neutrons.

Three major factors contribute to water pollution: industrial, municipal, and oil spills.

Water contamination occurs when chemicals contaminate water sources and render the water unfit for swimming, drinking, cleaning, or other uses. In addition to chemicals, waste, bacteria, and parasites, pollutants also include. Water becomes contaminated by all types of pollutants eventually.

Water contamination occurs when chemicals contaminate water sources and render the water unfit for swimming, drinking, cleaning, or other uses. In addition to chemicals, waste, bacteria, and parasites, pollutants also include. Water becomes contaminated by all types of pollutants eventually.

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Answer:

c

no need to thank me okay

Answer:

it is b (they are soluble)

Explanation:

got it right on edg and on quizlet

Answer:

B. They are soluble

Explanation:

Answer:

There are several ways of expressing the concentration of a solution.

Explanation:

Concentration is the proportion of a substance in a mixture. There are several ways of expressing them, each with their own usefulness. What's incredibly useful is with a little math and conversion factors, these can all be interconverted.

Note: to find the percent of some of these, such as for mass percent or volume percent, multiply the result by 100.

Additionally, with some practice you can answer a question such as, "The label on a 0.750-L bottle of Italian chianti says "11.5% alcohol by volume." How many liters of alcohol does the wine contain?". etc...

I really hope this helps! Take care.

The temperature changes for the water and the metal can be calculated by subtracting their initial temperatures from the final temperature.

AT (water) = √°C - °℃

AT (metal) = √°C - °℃

The above equations give the temperature changes for the water and the metal, respectively. The specific values of the temperatures and the final temperature are not provided, so the actual temperature changes cannot be determined without knowing these values.

In general, the temperature change of a substance is given by the difference between the final and initial temperatures. When a warmer object comes into contact with a cooler one, heat energy is transferred from the warmer object to the cooler one until they reach thermal equilibrium, where their temperatures become equal.

The magnitude of the temperature change depends on factors such as the specific heat capacity of the substances involved and the amount of heat exchanged between them.

To accurately calculate the temperature changes, the specific heat capacities of water and the metal would be needed. Additionally, the masses or quantities of the substances would be necessary to determine the amount of heat exchanged. Without these specific values, it is not possible to provide a precise numerical answer.

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