The percent by mass of each compound in the mixture is 24.04% NaBr and 75.96% Na₂SO₄.
Percentage by mass, mass %, is a measure of concentration that indicates the mass of solute per mass of solution. In other words, the mass percent of a component in the solution is defined as the ratio of the mass of the component to the mass of the solution, expressed as a percentage.
mass % = (mass of solute / mass of solution) x 100
In the case of a mixture of NaBr and Na₂SO₄ that contains 29.96% Na by mass, assume 100 g of the mixture.
Let x = mass of NaBr
100 - x = mass of Na₂SO₄
29.96 g = mass of Na in NaBr + mass of Na in Na₂SO₄
29.96 g = (mass of NaBr)(mass % Na in NaBr/100) + (mass of Na₂SO₄)(mass % Na in Na₂SO₄/100)
29.96 g = (x)(22.989769/102.893769) + (100 - x)(2 · 22.989769/142.040538)
29.96 g = 0.2234320817x + (100 - x)(0.3237071518)
29.96 g = 0.2234320817x + 32.37071518 - 0.3237071518x
0.3237071518x - 0.2234320817x = 32.37071518 - 29.96
x = 24.04102213
100 - x = 100 - 24.04102213 = 75.95897787
mass % NaBr = (mass of NaBr / mass of mixture) x 100
mass % NaBr = (24.04102213 / 100) x 100
mass % NaBr = 24.04102213
mass % Na₂SO₄ = (mass of Na₂SO₄ / mass of mixture) x 100
mass % Na₂SO₄ = (75.95897787 / 100) x 100
mass % Na₂SO₄ = 75.95897787
Hence, the mass % of each compound is 24.04% NaBr and 75.96% Na₂SO₄.
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please help me
16 1 point What is the decay rate of a sample of Oxygen-21 if the sample has 8.31x1017 atoms and a decay constant of 0.203/s? 4.09x1018Bq 1.69x10¹7Bq 0.203Bq 2.44x10-1⁹Bq Previous
decay rate of approximately 1.69x10^17 Bq (becquerels),
The decay rate of a radioactive sample is determined by the number of radioactive atoms present and the decay constant, which represents the probability of decay per unit of time.
To calculate the decay rate, we multiply the number of atoms in the sample by the decay constant. In this case, the sample has 8.31x10^17 atoms and a decay constant of 0.203/s. Multiplying these values gives a decay rate of approximately 1.69x10^17 Bq (becquerels), which represents the number of decays per second in the sample.
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why is it important for a measurement system to have an international standard ?
Answer:
Mark me brainliest
Explanation:
Standards help avoid confusion and ambiguity when taking measurements. For example, a meter will always be the same length, no matter who is taking the measurement or where it is being taken.
In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine the percentage yield if 9.77 g of carbon dioxide was obtained in the lab.
Answer:
89.3 %
Explanation:
M(CH4) = 12+ 4*1 = 16 g/mol
M(O2) = 2*16 = 32 g/mol
M(CO2) = 12 + 2*16 = 44 g/mol
8.50 g * 1 mol/16 g = 0.5313 mol CH4
15.9 g * 1 mol/32 g = 0.4969 mol O2
9.77 g * 1 mol/44 g = 0.2220 mol CO2
1) CH4 + 2O2 -----> CO2 + 2H2O
from reaction 1 mol 2 mol
given 0.5313 mol (0.4969 mol)
1 mol CH4 --- 2 mol O2
0.5313 mol CH4 --- x mol O2
x= 2*0.5313 = 1.0626 mol O2
We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.
2) CH4 + 2O2 -----> CO2 + 2H2O
from reaction 2 mol 1 mol
given 0.4969 mol x mol
x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield
3)
Practical yield CO2 = 0.2220 mol
Theoretical yield CO2 = 0.2485 mol
% yield = (0.2220/0.2485)*100% = 89.3 %
Which is the best way to determine if an object is made of pure silver
Answer:
The Nitric Acid Test
Explanation:
The Nitric Acid Test is used to check if silver is pure or plated. To do so, file a small part of the item in a discreet area where it cannot be seen. Apply a few drops of nitric acid. If the area turns into creamy white, the silver is pure or sterling. If green, it is probably fake or silver-plated.
A rectangular yard measuring 35 ft by 49 ft is bordered and surrounded) by a fence. Inside, a walk that is 4 ft wide goes all the way along the fence. Find the
area of this walk. Be sure to include the correct unit in your answer.
(ANSWER)
AREA OF WALK = 444 SQUARE FEE
(EXPLANATION)
FIRST, CALCULATE THE AREA OF THE RECTANGULAR YARD.
♥ A = L × W where A equals area, L equals length, and W equals width.
ACCORDING TO YOUR STATED PROBLEM:
♥ A = 1519 square feet. <––– Area of Rectangular yard.
♥ NOW, ACCORDING TO YOUR STATED PROBLEM THERE IS A WALK THAT IS 3 FEET WIDE GOING ALL THE WAY ALONG THE FENCE (INSIDE).
♥ THEREFORE, YOU HAVE SIX FEET TO SUBTRACT FROM EACH OF THE VALUES ABOVE (31) AND (49).
WHY?
THREE FEET ON EACH SIDE, CORRECT?
A = L × W
A = 25 × 43
A = 1075 square feet <––––Area of new rectangle formed by allowing for three foot walk.
♥ NOW, SUBTRACT THE AREA OF THE NEW RECTANGLE FORMED FROM THE AREA OF THE ORIGINAL AREA. DOING SO, WILL GIVE YOU THE AREA OF THE WALK, CORRECT?
♥ ORIGINAL AREA = 1519 square feet
♥ NEW AREA = 1075 square feet
_____________________________________
What is the most common solvent that is used in a solution?
Answer:
It's water.
Explanation:
Water is also called as universal solvent, because it's literally almost the only one we use.
Sorry if I spelled something wrong. I'm Dominican so yeah . I hope this helps you :)
How many grams of ammonia would comprise a 2.00 mole sample of ammonia
We know that the molar mass of ammonia is 17.03 grams per mole. This means that 1 mole of ammonia will have a mass of 17.03 grams.
The mole concept is a convenient method of expressing the amount of a substance. Any measurement can be broken down into two parts – the numerical magnitude and the units that the magnitude is expressed in. We are given that we have a 2.00 mole sample of ammonia. This means that we have 2 times the amount of ammonia that we would have in a 1.00 mole sample.
To find the mass of our sample, we need to multiply the number of moles by the molar mass. This gives us :-
2.00 moles * 17.03 grams/mole = 34.06 grams
Therefore, our sample of ammonia has a mass of 34.06 grams.
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Charlotte is driving at 60.2 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for
3.91 s. How far has Charlotte traveled in feet during this time?
Charlotte, driving at 60.2 mi/h, would travel approximately 344 feet during the 3.91 seconds that she looked at her phone.
Explanation:To find out how far Charlotte traveled, we can first convert her speed to feet per second since we're given the time she looked at her phone in seconds. We know that 1 mile is approximately 5280 feet, so Charlotte's speed in feet per second is 60.2 miles per hour multiplied by 5280 feet over 3600 seconds (the number of seconds in an hour). This comes out to be approximately 88 feet per second.
Therefore, in the 3.91 seconds that Charlotte looked at her phone, she would've traveled 88 feet per second times 3.91 seconds, which equals roughly 344 feet.
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What do the planets Earth and Mars have in common?
A Presence of an atmosphere and a gas surface composition
B Presence of an atmosphere and a rock surface composition
C Presence of moons and rings
D Presence of rings but no moons
Answer:
the answer is D
Explanation:
because I had a test that had this question and I got it correct
HELLO IS ANYONE GOOD AT SCIENCE IF SO PLEASE ANSWER THIS IS DUE TONIGHT
1) Find the moles of each element in 1.25 mol of Na2CO3.
2) Convert 2.50 mol of Na2CO3 to mass in g.
3) Convert 5.50 g of Na2CO3 to mol.
4) Covert 5.50 g of Na2CO3 to number of particles.
In one mole of sodium carbonate, there are 2 moles of sodium , 6 moles of oxygen and 1 mole of C. Hence, in 1.25 moles of the compound, 2.5 moles of Na, 7.5 moles of O and 1.25 moles of C.
What is molar mass ?The molar mass of a compound is the mass of one mole of the compound. One mole of any compound contains 6.02 × 10²³ atoms. This number is called Avogadro number.
2. Convert 2.50 mol of Na2CO3 to mass in g.
Molar mass of sodium carbonate = 106 g/mol
then, mass of 2.50 mol = 265 g.
3. Convert 5.50 g of Na2CO3 to mol.
Number of moles in 5.50 g of sodium carbonate = 5.50 g/ 106 = 0.051 moles.
4.Covert 5.50 g of Na2CO3 to number of particles
Now, one mole of sodium carbonate contains Avogadro number of atoms or molecules . Then number of particles in 5.50 g that is 0.051 moles is:
0.051 × 6.022 × 10²³ = 3.072 × 10²² particles.
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What will be the [OH-], [H3O], pH and pOH of a 0. 025 M weak acid olution? (pKA= 4. 615)
The [OH-] of the 0.025 M weak acid solution will be equal to the pKA of the acid, 4.615.
What is weak acid solution?
A weak acid solution is a solution that contains an acid that is not completely ionized in water. Weak acids, such as acetic acid, have pH values between 4.5 and 6.0. These acids are not strong enough to completely break apart in water, leaving some of the molecules still intact. Because of this, weak acids form molecules that can react with other molecules, such as bases, in solution.
This is because the equilibrium of the acid dissociation reaction is reached with the same concentration of acid and its conjugate base in solution. The [H3O] will be equal to 0.025 M, as the acid is in dissociation equilibrium with its conjugate base. The pH of the solution can be calculated by taking the negative log of the [H3O], which will be 1.59. The pOH can be calculated by taking the negative log of the [OH-], which will be 4.615.
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Ge
Express your answer in complete form in the order of orbital as a string without blank space between orbitals.
The complete string representing the order of orbital filling without blank spaces is: \(1s^22s^22p^63s^23p^64s^23d^1{0}4p^65s^24d^105p^66s^24f^145d^{10}6p^67s^25f^146d^{10}7p^6\)
To express the order of orbital filling as a string without blank spaces, we follow the Aufbau principle, which states that electrons fill orbitals starting from the lowest energy level and move upward. The order of orbital filling is as follows:\(1s^22s^22p^63s^23p^64s^23d^1{0}4p^65s^24d^105p^66s^24f^145d^{10}6p^67s^25f^146d^{10}7p^6\)
Let's break it down step by step:
1s^2: The 1s orbital can hold up to 2 electrons.
2s^2: The 2s orbital can also hold up to 2 electrons.
2p^6: The 2p orbitals can hold up to 6 electrons.
3s^2: The 3s orbital can hold up to 2 electrons.
3p^6: The 3p orbitals can hold up to 6 electrons.
4s^2: The 4s orbital can hold up to 2 electrons.
3d^10: The 3d orbitals can hold up to 10 electrons.
4p^6: The 4p orbitals can hold up to 6 electrons.
5s^2: The 5s orbital can hold up to 2 electrons.
4d^10: The 4d orbitals can hold up to 10 electrons.
5p^6: The 5p orbitals can hold up to 6 electrons.
6s^2: The 6s orbital can hold up to 2 electrons.4f^14:
The 4f orbitals can hold up to 14 electrons.
5d^10: The 5d orbitals can hold up to 10 electrons.
6p^6: The 6p orbitals can hold up to 6 electrons.
7s^2: The 7s orbital can hold up to 2 electrons.
5f^14: The 5f orbitals can hold up to 14 electrons.
6d^10: The 6d orbitals can hold up to 10 electrons.
7p^6: The 7p orbitals can hold up to 6 electrons.
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energy in a system can be transformed from one state to another. which statement is true for all energy transformationsA. Total energy in a system either increased or decreases B. Total energy in a system remains constant C. There must be an input of chemical energy for a transformation to occur D. Electrical energy is always converted to mechanical energy
According to the laws of thermodynamics, energy will remain constant in a system, therefore energy will not be created or destroed but it will be transformed, remaining constant. Letter B
How many electrons are in bromine's (atomic number 35) next to outer shell (n = 3)?
a. 2
b. 4
c. 8
d. 18
The answer is c. 8 electrons are in bromine's next to outer shell (n = 3). Therefore, the answer is c. 8 electrons are in bromine's next to outer shell (n = 3).
Bromine has an atomic number of 35, which means it has 35 protons in its nucleus and 35 electrons in its electron cloud. To determine the number of electrons in bromine's next to outer shell (n = 3), we need to look at the electron configuration of bromine. The electron configuration of bromine is: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5
The electrons in the outermost shell (n = 4) are the valence electrons, which are involved in chemical reactions. However, we are interested in the electrons in the next to outer shell (n = 3), which are also important in determining chemical properties. To determine the number of electrons in the next to outer shell, we need to subtract the number of electrons in the outermost shell (n = 4) from the total number of electrons in the atom.
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Molarity of Kool Aid solutions can be calculated by comparing the concentrations of Kool Aid powder and sugar added to a given volume of water. The molar mass of Kool Aid will be the same as that of sugar for our purpose. The molecular formula for sugar is C12H22O11- Your objective for this lab will be to calculate the molarity of Kool Aid desired based on package directions. You will then be provided two concentrated Kool Aid solutions. You will use dilution calculations to determine the amount of water and concentrated solution you will need in order to prepare 65 mL of the desired molarity.
Calculate the molarity of Kool Aid desired based on the following information from the package directions.
1 package Kool Aid powder = 4. 25 grams 1 cup sugar = 192. 00 grams
2. 00 quarts of water (1. 06 quarts = 1 liter)
The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.
To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:
Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)
= 144.12 + 22.22 + 176.00
= 342.34 g/mol
Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:
Number of moles of Kool Aid powder = Mass / Molar mass
= 4.25 g / 342.34 g/mol
≈ 0.0124 mol
Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:
Number of moles of sugar = Mass / Molar mass
= 192.00 g / 342.34 g/mol
≈ 0.5612 mol
Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:
Volume of water = 2.00 quarts * (1.06 liters / 1 quart)
= 2.12 liters
To find the molarity, we use the formula:
Molarity (M) = Number of moles / Volume (in liters)
Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L
≈ 0.286 M
To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.
Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:
(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:
(C M)(V mL) = (0.286 M)(65 mL)
V mL = (0.286 M)(65 mL) / C M
So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.
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Which of the following has the greatest number of nonbonding pairs of electrons? C H He F
The element with the greatest number of nonbonding pairs of electrons is He, as it has a full valence shell and does not need to form any bonds to fulfill the octet rule.
It seems you are asking about nonbonding pairs of electrons among the elements C (Carbon), H (Hydrogen), He (Helium), and F (Fluorine). Nonbonding pairs, also known as lone pairs, are valence electrons not involved in bonding.
In this case, Fluorine (F) has the greatest number of nonbonding pairs of electrons. Fluorine has 7 valence electrons, and when it forms a bond, it typically forms a single bond, using one electron for bonding. This leaves 6 electrons (3 pairs) as nonbonding pairs. In comparison, Carbon and Hydrogen typically form bonds with all of their valence electrons, and Helium has only 2 electrons in its outer shell which are not involved in bonding but do not form pairs.
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Given 45.73 moles of BCl3, how many grams are present?
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 0.98grams are present in 45.73 moles of BCl\(_3\).
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number. The stoichiometry represents the number of moles.
Mathematically,
number of moles of BCl\(_3\) =given mass of BCl\(_3\) ÷ molar mass of BCl\(_3\)
Molar mass of 1 mole of BCl\(_3\) = 46.264 g/mol
number of moles of BCl\(_3\) = 45.73 moles
Substituting all the given values in the above equation, we get
45.73 moles =mass of BCl\(_3\)÷46.264 g/mol
mass of BCl\(_3\) =0.98grams
Therefore, 0.98grams are present in 45.73 moles of BCl\(_3\).
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i'll mark you the brainlest just hurry up and answer the question.
Estimate the bounce height of the ball in this photo. Measure from the floor to the bottom of the ball. 107 ball bounce Question 2 options: 38 in 38 cm 40 mm 50 km
Answer:
The correct answer would be B.
Hope this helps :D
6. Note the pattern of changes in rainfall as elevation increases on the mountains of Kohala and Mauna Kea. What discrepancy can you identify?
The spatial, temporal, and seasonal distribution of rainfall is referred to as a rainfall pattern. More rain falls in the tropics than in deserts.
What are the patterns of rainfall?Rain does not fall in colder places, such as the poles, since it is converted to snow before it reaches the ground. Mountain barriers have a substantial impact on air mass modification. and the distribution of precipitation is influenced by topography. Rising air on Hawaii's Big Island causes the leeward side of the mountains to be dry while the windward side is covered with rain.
The Orographic Effect is what we refer to as. The modification of air masses is significantly influenced by mountain barriers, and the distribution of precipitation is influenced by topography. Rising air on Hawaii's Big Island causes the leeward side of the mountains to be dry while the windward side is covered with rain.
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the teacher prepares 2.50 liters (l) of a salt solution for a class experiment. how many quarts (qt) are in 2.50 l? (1 l =1.06 qt)
The amount of quarts in 2.50 L is 2.65 qt
How many quarts are in 2.50 l?Since the teacher prepares 2.50 liters of salt solution for a class experiment, we require how many quarts there are in 2.50 liters.
Since we know that 1 L = 1.06 qt, converting liters to quarts, we have
2.50 L = 2.50 × 1 L
= 2.50 × 1.06 qt
= 2.65 qt
So, the amount of quarts in 2.50 L is 2.65 qt
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Describe the periods in Mendeleev’s table.
Answer:
In Mendeleev's table, each period contains eight elements, and then the pattern repeats in the next row
Explanation:
this should be it
In a titration, acetic acid is used as the analyte and sodium hydroxide is the titrant. At the equivalence point, will the ph be higher than, lower than, or equal to 7?.
In a titration, acetic acid is used as the analyte and sodium hydroxide is used as the titrant. At the equivalence point, ph be higher than 7.
The equivalence point of the titration is that point at which enough titrant has been added to react with all of the substance being titrated. A strong acid with a weak base gives a slightly acidic salt. Likewise, a strong base with weak acid gives slightly basic salt.
When acetic acid react with NaOH then a salt sodium acetate and water is formed. Acetic acid, CH3COOH react with sodium hydroxide, to produce sodium acetate, CH3COONa and water
CH3COO- + H2O ---> CH3COOH + OH-
This reaction of the acetate ion makes the ph greater than 7.
At the equivalence point, moles of acetic acid is equal to the moles of sodium hydroxide. The solution will turn pink as more of sodium hydroxide is added.
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the rate constant for a reaction increases from 10.0 to 100 when the temperature is increased from 300k to 400k what is the activcation energy
A reaction's rate constant rises from 10.0 to 100. when the temperature rises from 300°C to 400°C 45.6 kJ/mol is the activation energy.
The activation energy for the reaction can be calculated using the Arrhenius equation, which relates the rate constant to the activation energy and the temperature. The Arrhenius equation is: k = A * e^(-Ea/RT). Where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature. By rearranging the equation to solve for Ea, we get: Ea = -RT * ln(k/A)We know that k1 = 10.0 s^-1 at T1 = 300 K, and k2 = 100. s^-1 at T2 = 400 K. We can use these values to calculate the activation energy: Ea = -(8.314 J/mol*K) * (400 K - 300 K) * ln(100/10)=Ea ≈ 45.6 kJ/mol.
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You find an unidentified gem stone while digging in your backyard. It’s mass is 5.28 g and its volume is 2 cm3. What did you find?
Answer:
a big rock
Explanation:
What is the density of gold if 97.3 cm^3 has a mass of 1880 grams?
Answer:
Explanation:
the equation is d=m/v
convert cm to m
97.3*100=9730m^3
d=1880g/9730cm^3
d=0.19g/m^3
what are the factors affecting gravity?
Gravity, as a fundamental force of nature, is influenced by several factors. The following are some of the key factors affecting gravity:
Mass: The most significant factor affecting gravity is the mass of the objects involved. According to Newton's law of universal gravitation, the gravitational force between two objects is directly proportional to the product of their masses. Greater mass leads to a stronger gravitational force.Distance: The distance between two objects also plays a crucial role in the strength of gravity. According to the inverse square law, the gravitational force decreases as the distance between objects increases. As objects move farther apart, the gravitational attraction between them weakens.Gravitational Constant: The gravitational constant, denoted by G, is a fundamental constant in physics that determines the strength of the gravitational force. It is a universal constant and does not change, affecting the overall magnitude of gravity.Shape and Distribution of Mass: The distribution of mass within an object can influence the gravitational field it generates. Objects with a more compact and concentrated mass distribution will have a stronger gravitational pull compared to those with a more spread-out mass distribution.External Influences: Gravity can be influenced by external factors such as nearby celestial bodies or the presence of other forces. For example, the gravitational interaction between the Earth and the Moon affects tides on Earth's surface.How did you use the tools in the sim that helped you decide if the atom had a positive, negative, or 0 charge?
Answer:
The atomic number on the Periodic Table will tell you how many protons are in the nucleus of each atom.
Explanation:
number of electrons and protons should be equal in a neutral atom. Because each electron has a -1 charge, and each proton a +1 charge, the number of each must be the same for the net charge to equal zero.
How many grams of KBr is required to prepare 100 mL of
2.0 M KBr solution?
Answer:
23.8g
Explanation :
Convert 2.0M into mol using mol= concentration x volume
2.0M x 0.1L (convert 100mL to L since the units for M is mol/L)
= 0.2 mol
We can now find grams by using the molar mass of KBr
=119.023 g/mol (Found online) webqc.org
but can be be calculated by using the molecular weight of K and Br found on the periodic table
We can now calculate the grams by using grams=mol x molar mass
119.023g/mol x 0.2mol
= 23.8046 g
=23.8g (rounded to 1decimal place)
what does the Law of Conservation say?
Answer:
The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.
Explanation:
yw <3
Answer:
energy cannot be created or destroyed. it is instead transferred from one form to another
Explanation: