A missile is flying at a speed of 125 m/s. If the missile has a mass of 125 kg, what’s its kinetic energy?

Answer:

hhhsstyi chick to yay to today do y'all

Answer:

 ¹₀n

Explanation:

The given expression is:

          ²⁷₁₃Al      +     ₐᵇT   →   ²⁴₁₁Na    +    ⁴₂He

This expression is typical of nuclear reactions. To balance this expression we must conserved the mass number and the atomic number.

The mass number is the superscripts and the atomic number is the subscript;

 Now;

 conserving mass number:

             27 + b  = 24 + 4

             27 + b  = 28  

                   b  = 28 - 27  = 1

conserving the atomic number;

            13 + a  = 11 + 2

             13 + a  = 13

                    a  = 0

So;

The particle T is a neutron    ¹₀n

For the given reaction, decreasing the volume made to the system at equilibrium will result in a net reaction to the right to form more product. Option A is correct.

It is important to mention that when the reaction has reached a stage at which the rates of forward and backward reactions are equal, it is said to be in equilibrium. In this case, both the forward and backward reactions are taking place simultaneously at an equal rate.

According to the Le Chatelier's principle, if a chemical system in equilibrium is subjected to a change in conditions, the equilibrium will shift in the direction that tends to restore the original conditions.

The pressure of a gas is directly proportional to the volume of the container. As a result, decreasing the volume of the container will raise the pressure of the gas. The system will attempt to alleviate the stress by reacting in such a way that the number of moles of gas is decreased.

The reaction shifts to the side with fewer moles of gas.In this situation, the product CH4(g) is a gas, while both C(s) and H2(g) are solids and gases, respectively. The net reaction will be shifted to the right, resulting in the formation of more CH4(g).

Therefore, the correct answer is option A.

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You must compare the total amount of oxygen atoms on the reactant and product sides of the chemical equations in order to determine whether the oxygen atoms are evenly distributed on both sides.

Because matter cannot be generated or destroyed, there must be an equal amount of atoms of each element on both sides of the equation. Coefficients are the only variables that can be altered while balancing equations. An equation cannot be balanced by changing the subscripts in a chemical formula.

Reactant side:

B2Br has no oxygen atoms

6 HNO3 has 18 oxygen atoms (6 x 3)

Product side:

2 B(NO3)3 has 18 oxygen atoms (2 x 3 x 3)

6 HBr has no oxygen atoms

18 oxygen atoms total are present on the reactant side.

18 oxygen atoms total are on the product side.

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Answer:

A

Explanation:

Answer:

C.) Lactobacillus

Explanation:

Is a prokaryote with a simple rod shaped structure. Similar to other prokaryotic bacterium of its shape it has a cell wall, and capsule.

Answer:

V = 21.2 cm³

Explanation:

Given data:

Diameter of block = 3.0 cm

Volume of block = ?

Solution:

Formula:

V = 2πr³

First of all we will calculate the radius from diameter.

r = d/2

r = 3.0 cm/2

r = 1.5cm

V = 2(22/7) (1.5cm)³

V = 2(3.14) (3.375cm³)

V = 21.2 cm³

The relative atomic mass of an element R with two isotopes 63R and 65R is 63.64.

Relative atomic mass is the ratio of the average mass per atom of the naturally occurring form of an element to 1/12 of the mass of a carbon-12 atom.

The relative atomic mass (RAM) of an element with two isotopes can be calculated by multiplying the mass of each isotope by its respective percentage abundance as follows:

RAM = (63 × 0.68) + (65 × 0.32)

RAM = 42.84 + 20.8

RAM = 63.64

Therefore, 63.64 is the relative atomic mass of the element R.

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Answer:

soapy water is not good for plants irrigation that is what I learn

Answer:

Soapy water is not good for plant irrigation because soapy water contains sulphate in it which is not good for the development of plants.

Explanation:

hope this helps

The chemical reaction between 8.0 mol of O2 and 189 g of C2H4 (ethylene) can be represented as shown below:C2H4 + 3O2 → 2CO2 + 2H2OThe balanced equation for the combustion of C2H4 (ethylene) in oxygen is:C2H4 + 3O2 → 2CO2 + 2H2O.

According to the chemical equation above, 1 mol of C2H4 reacts with 3 mol of O2 to produce 2 mol of CO2 and 2 mol of H2O. Hence, the amount of O2 required for the complete combustion of 8.0 mol of C2H4 will be:3 moles of O2 for 1 mole of C2H48.0 moles of C2H4 require:8.0 mol C2H4 x 3 mol O2/mol C2H4 = 24 mol O2Therefore, 8.0 mol of O2 is sufficient for the combustion reaction.

Therefore, the limiting reagent is C2H4 and the excess reactant is O2. Now, we will calculate the amount of C2H4 used. The molar mass of C2H4 is 28.05 g/mol. So, 189 g of C2H4 is:189 g / 28.05 g/mol = 6.74 mol of C2H4Since the 8.0 mol of C2H4 given in the problem is greater than 6.74 mol of C2H4 calculated above, C2H4 is in excess. Thus, all the C2H4 will not be used up in the reaction, and there will be some C2H4 remaining after the combustion reaction has completed. Hence, some C2H4 will remain after the completion of the reaction.

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Answer:

Y=84.2%

Explanation:

Hello there!

In this case, for this stoichiometry problem, we need to consider the given balanced chemical reaction, in order to calculate the theoretical yield of radium fluoride, according to the stoichiometry and the 1:1 mole ratio between them:

\(m_{RaF_2}^{theoretical}=300gRa*\frac{1molRa}{226.03g} *\frac{1molRaF_2}{1molRa}*\frac{264.02gRaF_2}{1molRaF_2} \\\\m_{RaF_2}^{theoretical}=350.4gRaF_2\)

Finally, given the actual yield of the product, we can obtain the percent yield by dividing them:

\(Y=\frac{295g}{350.4g} *100\%\\\\Y=84.2\%\)

Best regards!

Answer/Explanation

am not sure but I think its

Standard temperature = 273K

2.50 LTemperature

Less evaporation means that less of the sun's energy is used to convert water into water vapor, and more of it is used to heat up the surface. In urban areas, there is typically less vegetation and more impervious surfaces (such as concrete and asphalt), which reduces the amount of water that can evaporate.

This means that more of the sun's energy is absorbed by the surface, leading to higher temperatures. Additionally, buildings and other structures in urban areas can trap heat and prevent it from dissipating, further contributing to the urban heat island effect.

In rural areas, vegetation and soil moisture play an important role in regulating temperature through a process called evapotranspiration. Evapotranspiration is the combined process of water evaporation from the soil and plant transpiration. It helps to cool the air by removing heat from the surface through the transfer of water from the surface to the atmosphere.

In contrast, urban areas have a significant amount of impervious surfaces like concrete, asphalt, and buildings, which reduce the amount of vegetation and soil moisture. As a result, urban areas have less evapotranspiration, which means less cooling effect from the evaporation of water. This leads to a higher surface temperature in urban areas.

Furthermore, urban areas have a higher proportion of dark-colored surfaces, such as asphalt and concrete, which absorb more solar radiation than lighter-colored surfaces like vegetation and soil. This is known as the "urban heat island effect," which further contributes to higher temperatures in urban areas.

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1.32 g of oxygen combined with 2.00 g of magnesium to form 3.32 g of magnesium oxide.

What is a balanced equation?

A chemical equation is said to be balanced when each element has an equal number of atoms on both the reactant and product sides of the equation. In other words, the equation depicts a chemical reaction in which the total number of atoms present prior to the reaction is equal to the total number present following the reaction.

The law of conservation of mass is upheld when the equation is balanced, and the reaction that is occurring is correctly depicted.

You must find the difference between the total mass of the reactants and the mass of the product in order to calculate the mass of oxygen that combined with magnesium. The chemical equation for the reaction of magnesium and oxygen is as follows:

O2 + 2Mg = 2MgO

Therefore, the mass of magnesium oxide (MgO) produced by the reaction of 2.00 g of magnesium (Mg) and a small amount of oxygen (O) can be expressed as follows:

x g O + 2.00 g Mg = 3.32 g MgO

where x represents the oxygen's mass. You can calculate x by deducting the mass of magnesium from the product's overall mass:

We get 1.32 g from x = 3.32 g - 2.00 g.

Therefore, 1.32 g of oxygen and 2.00 g of magnesium were combined.

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The oxidation state of elements in reactants and products is +4,0,+2,0 respectively and Ti is reduced and Mg is oxidized respectively.

The reaction is TiCl4+2Mg---2MgCl2+Ti

Assume the oxidation state be x

Then, x-1x4=0

x=+4

The oxidation state is as follows;

x-1x2=0

x=+2

The oxidation state is as follows;

x-1x2=0

x=+2

The oxidation state is +4,0, and +2,0 respectively

The oxidation state of Ti decreases from +4 to 0 so it is reduced. The oxidation state of Mg increases from 0 to +4  so it is oxidized.

So Ti is reduced and Mg is oxidized

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Answer: increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.

Explanation:

edge

Answer:

Your answer is A.

Explanation:

Answer:

The answer is A.

Explanation:

Answer:  A. \(0.00301J/g^0C\)

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

\(Q=m\times c\times \Delta T\)

Q = Heat absorbed  = 4.56 J

m = mass of substance = 123 g

c = specific heat capacity = ?

Change in temperature ,\(\Delta T=T_f-T_i=12.32^0C\)

Putting in the values, we get:

\(4.56J=123g\times c\times 12.32^0C\)

\(c=0.00301J/g^0C\)

The specific heat of a 123 g substance that requires 4.56 J of heat in  order to increase its temperature by 12.32 °C is \(0.00301J/g^0C\)

The molecular formula is C₂H₄O₂ when molecular weight is 180 g having empirical formula of CH₂O.

The compound's empirical formula is CH₂O, which contains two hydrogen atoms and one oxygen atom for every carbon atom.

CH₂O has a mass of 30 (=12+2*1+16).The molecule has a molecular weight of about 180.As a result, the supplied molecule has the molecular formula C₆H₁₂O₆.

What is the chemical structure of the equation for water, CH₂O?

A substance that is organic and has a molar mass pf 60 grams / mole as well as an empirical formula of CH₂O also has a molecular formula or C₂H₄O₂.

How much CH₂O is in a mole?

A mol of CH₂O has a molar mass of 30.026 g.

The periodic chart must first be used to estimate its atomic mass of the each element in the compound.

Therefore, the molecular formula is C₂H₄O₂ with the empirical formula of CH₂O.

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The compound that would form a precipitate in water is  BaSO4.

option d.

BaSO4 (barium sulfate) would form a precipitate in water because it is classified as an insoluble compound according to most solubility charts. When a compound is considered insoluble, it means that it has a very low solubility in water, resulting in the formation of solid particles or precipitate when dissolved in water.

In the case of BaSO4, it does not readily dissociate into ions in water and remains as solid particles, causing it to precipitate.

On the other hand, a. KCI (potassium chloride), b. NaOH (sodium hydroxide), and c. (NH4)2S (ammonium sulfide) are soluble compounds in water. They dissociate into ions and form homogenous solutions when dissolved in water, without forming a precipitate.

It's worth noting that solubility can vary depending on factors such as temperature and concentration, so it's always important to consult a solubility chart or reference for accurate and up-to-date information on specific compounds.option d.

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Answer:

yes, I am pretty sure it can

In chemoheterotrophs, cellular metabolism is primarily fueled by chemical energy in the form of organic compounds obtained from external sources.

These organisms rely on the intake of complex organic molecules, such as carbohydrates, proteins, and lipids, from their environment as sources of energy. Once these organic compounds are ingested, they undergo various metabolic processes to break them down into smaller molecules. The energy stored in the chemical bonds of these molecules is then extracted through a series of enzymatic reactions in a process called cellular respiration. During cellular respiration, the organic molecules are oxidized, releasing electrons that are passed through a series of electron carriers in the electron transport chain. This process generates adenosine triphosphate (ATP), the primary energy currency of cells. ATP provides the necessary energy for cellular activities, such as biosynthesis, active transport, and movement.

The breakdown of organic compounds and the subsequent production of ATP occur through different metabolic pathways, including glycolysis, the citric acid cycle, and oxidative phosphorylation. Overall, chemoheterotrophs obtain energy for cellular metabolism by oxidizing organic compounds, generating ATP through cellular respiration. This allows them to meet their energy needs for growth, maintenance, and reproduction.

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Valence electrons in non-metal occupy directional p-orbitals.

Metal valence electrons spread out into spherical s-orbitals.

Valence electrons can be defined as the number of electrons that are present in the outermost shell of an atom. Also, valence electrons are typically used to determine whether an atom or group of elements found in a periodic table can bond with others.

This ultimately implies that, valence electrons is a property is typically used to determine the chemical properties of chemical elements.

A sublevel can be defined as an energy level that is associated with the electrons found outside the atomic nucleus.

In Chemistry, there are four (4) types of sublevel and these include the following:

I. s-orbital (sublevel): it has one (1) orbital i.e 1s.

II. p-orbital (sublevel): it has three (3) orbitals.

III. d-orbital (sublevel): it has five (5) orbitals.

IV. f-orbital (sublevel): it has seven (7) orbitals.

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157.6 g of Tris-HCl to make 100 ml of the binding buffer with a concentration of 100 mM.

To make 100 ml of the binding buffer with 100 mM Tris-HCl and 150 mM NaCl, we first need to calculate the amount of each reagent required. The molecular weight of Tris-HCl is 157.6 g/mol, and the molecular weight of NaCl is 58.44 g/mol.

To calculate the mass of Tris-HCl required, we can use the formula:

mass = (concentration x volume x molecular weight) / 1000

where concentration is in mM, volume is in ml, and the molecular weight is in g/mol.

Substituting the given values, we get:

mass of Tris-HCl = (100 mM x 100 ml x 157.6 g/mol) / 1000 = 157.6 g

Therefore, we need 157.6 g of Tris-HCl to make 100 ml of the binding buffer with a concentration of 100 mM.

To calculate the mass of NaCl required, we can use the same formula:

mass = (concentration x volume x molecular weight) / 1000

Substituting the given values, we get:

mass of NaCl = (150 mM x 100 ml x 58.44 g/mol) / 1000 = 87.66 g

Therefore, we need 87.66 g of NaCl to make 100 ml of the binding buffer with a concentration of 150 mM.

To make the buffer, we can follow the following steps:

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Answer:

A

freezing is a physical change when it turns to solid. If this helped plz give brainliest: )

The value of ΔH for the reaction CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g) is -1272 kJ.

To calculate the enthalpy change (ΔH) for the given reaction, we can use Hess's law, which states that the overall enthalpy change of a reaction is equal to the sum of the enthalpy changes of the individual reactions involved.

Given the enthalpy changes:

1. 2 C(s) + O₂(g) → 2 CO(g)... ∆H = -222 kJ

2. C(s) + O₂(g) → CO₂(g)... ∆H = -394 kJ

3. 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

We need to manipulate these reactions to obtain the desired reaction:

1. Reverse reaction 2: CO₂(g) → C(s) + O₂(g)... ∆H = +394 kJ

2. Multiply reaction 2 by 2 to balance carbon atoms: 2 CO₂(g) → 2 C(s) + 2 O₂(g)... ∆H = -788 kJ

3. Leave reaction 3 unchanged: 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

By adding reactions 2 and 3, we obtain the desired reaction:

CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g)... ∆H = -788 kJ + (-484 kJ) = -1272 kJ

Therefore, the value of ΔH for the given reaction is -1272 kJ.

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The correct answer is 0.15.

We are aware that there is 0.05 mol of an unidentified hydrocarbon we will refer to as "X" and that its burning produces 6.6 g of carbon dioxide and 3.6 g of water.

These quantities might be converted to moles by applying the following formula:

amount= mass/ relative atomic mass

Thus, the following equation may be written for H2O: moles = 3.6 / 18 = 0.2 and for CO2: moles = 6.6 / 44 = 0.15.

0.05X + x'O2 = 0.15CO2 + 0.2H2O

This may be made simpler by dividing through by 0.05 (this step is likely to be the most helpful to you), resulting in:

1 x + x O2 = 3 co2 + 4 H2O

The hydrocarbon must have been the source of all the carbon in the carbon dioxide and all the hydrogen in the water.

Accordingly, 4 x 2 = 8 moles of H and 3 x 1 = 3 moles of C.

There are 3/1 = 3 Cs and 8/1 = 8 Hs in one X molecule.

This clearly identifies C3H8 or propane as the hydrocarbon X (dividing by 1 seems unnecessary, but it illustrates the process to use if there were more than one mol of X in the first equation).

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