A milkman bought 40 litres of milk at rs. 26.50 per litre and added 6 litres of water to it. He sold the mixture at rs. 17 per litre. How much did he gain? ​

Answer:

-5x+18/x+2

Step-by-step explanation:

I'm pretty sure it's the answer

A= 20%

B= 33%

What is Relative Frequency?

Relative frequency is simply the number of outcomes in a particular subgroup (f) divided by the total number of outcomes in an experiment (n).

Thus, Relative frequency= f/n

In the above question, we need to find the relative frequencies of 2 subgroups- lifeguards and retail.

For lifeguards, f=3 and n=15

∴ Relative Frequency (A) = \(\frac{3}{15}\)

Since we've to express it in percentage form,

A= \(\frac{3}{15}\) * 100

  = 20%

Similarly for retail-

B= \(\frac{5}{15}\) * 100

 = 33%

Thus, A= 20% and B= 33%

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(a) The plot of y versus t for several values of y₀ between 1/2 and 1 shows oscillations with higher y₀ resulting in larger oscillations.

(b) The critical initial population \(y_c\) below which the population becomes extinct is \(y_c\) = 2.5k.

(c) For different values of k, the corresponding critical initial populations \(y_c\) are found

(d) The relationship between the critical initial population \(y_c\) and the predation rate k can be summarized as \(y_c\) = 2.5k.

(a) Plotting y versus t for several values of y₀ between 1/2 and 1:

To solve the initial value problem dy/dt = r(t) * y - k, y(0) = y₀, we need to integrate the differential equation numerically.

Given:

- r(t) = (1 + sin t) / 5

- k = 1/5

We can observe the following:

For each value of y₀ between 1/2 and 1, the population y will exhibit a fluctuating behavior over time. The sine function in r(t) causes the growth rate to oscillate, leading to oscillations in the population as well. The magnitude of the oscillations depends on the initial population y₀.

Higher values of y₀ will result in larger oscillations, while lower values will lead to smaller oscillations. As time progresses, the population may increase or decrease depending on the interplay between the growth rate and the predation rate.

(b) Estimating the critical initial population \(y_c\) below which the population will become extinct:

To estimate the critical initial population \(y_c\), we need to find the value of y₀ for which the population becomes extinct. This occurs when the population y drops to zero or a very small positive value.

For the given differential equation dy/dt = r(t) * y - k, we can see that when y is very close to zero, the rate of decrease (k) dominates over the growth rate (r(t) * y). Therefore, we can set up the following equation:

0 = r(t) * y - k

Solving this equation for y, we find:

y = k / r(t)

Substituting r(t) = (1 + sin t) / 5, we have:

y = 5k / (1 + sin t)

To find the critical initial population \(y_c\), we need to determine the smallest value of y for all t. Since the minimum value of sin t is -1, the smallest value of y is obtained when sin t = -1, yielding:

\(y_c\) = 5k / (1 - (-1))

   = 5k / 2

   = 2.5k

Therefore, the critical initial population \(y_c\) is 2.5 times the predation rate k.

(c) Choosing other values of k and finding the corresponding \(y_c\) for each one:

Let's consider different values of k and calculate the corresponding critical initial population \(y_c\) using the formula derived in part (b):

For k = 1/10:

\(y_c\) = 2.5 * (1/10) = 1/4 = 0.25

For k = 1/4:

\(y_c\) = 2.5 * (1/4) = 5/8 = 0.625

For k = 1/2:

\(y_c\) = 2.5 * (1/2) = 5/4 = 1.25

For k = 1:

\(y_c\) = 2.5 * 1 = 2.5

For k = 2:

\(y_c\) = 2.5 * 2 = 5

For k = 5:

\(y_c\) = 2.5 * 5 = 12.5

These are the corresponding critical initial populations \(y_c\) for different values of k.

(d) Plotting \(y_c\) versus k:

Using the values of \(y_c\) and k calculated in part (c), we can plot \(y_c\) versus k:

k       |   \(y_c\)

-------------------

1/10   |  0.25

1/4    |  0.625

1/2    |  1.25

1       |  2.5

2      |  5

5      |  12.5

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The result of the expression (x / m^2 - 2x / m)(3x^2y / m) is (3x^3y / m^3) - (6x^3y / m^2)

The given expression is

(x / m^2 - 2x / m)(3x^2y / m)

Here we have to apply distributive property

The distributive property states that multiplying the sum of two or more variable by a number gives the same result as when each variable is multiplied individually by the number and the products are added together.

The distributive property of subtraction is

A(B-C) = AB - AC

Apply the distributive property

(x / m^2 - 2x / m)(3x^2y / m)

= (x / m^2)(3x^2y / m) - (2x / m)(3x^2y / m)

Multiply the terms

= (3x^3y / m^3) - (6x^3y / m^2)

Hence, the result of the expression (x / m^2 - 2x / m)(3x^2y / m) is (3x^3y / m^3) - (6x^3y / m^2)

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Answer: 0.1"/minute

Step-by-step explanation:

Volume of a sphere is:  V = (4/3)πr³

In one minute, the volume increases by 2032 in^3.  Set the starting volume at a point 1 minute from the target of 342342 in^3:  (342342 - 2032) =  340310 in^3.

We can then determine the change in the radius for the initial (340310 In^3) and end (342342 in^3) points as the sphere reaches its maximum size:

Initial:  The radius for a 340310 in^3 sphere is 43.3".

Finish:  The radius for a 342342 in^3 sphere is 43.4".  {Wow]

It took an increase in radius of 0.1" to add the final 2032 in^3 of volume to the sphere.  That occurred in one minute, so the rate of change of the radius is 0.1"/minute.

Step-by-step explanation:

an isoceles triangle means that both legs are equally long.

the perimeter of a triangle is the sum of all 3 sides (the way to walk around the whole triangle).

the baseline is x long.

both legs are 3x - 2 long.

the perimeter

52 = x + 2×(3x - 2) = x + 6x - 4 = 7x - 4

56 = 7x

x = 8

Answer:

NO.2- SSA is not the method to show the congruency of two triangles.

Answer:

Step-by-step explanation:History(H),Economics(E),Literature(L)

1a).To find History(H) only is

H only =H-HE-HL+HEL

H only =60-30-16+10=24

b).E only=50-30-22+10=8

c). L only=48-22-16+10=20

2).no of candidates who sat for the exam is 24+8+20=52

"In an examination of final year students of a school, 60 offered history, 50 offered economics, and 48 literature." The Vein diagram is attached below.

A Venn diagram is a diagram that utilizes circles to demonstrate the similarities and contrasts between two or more items.

Generally, the equation for History students only is mathematically given as

HisO=His-His Eco-His Lie+HisEcoLie

Therefore

HisO=60-30-16+10

HisO=24

EcoO=50-30-22+10

EcoO=8

LieO=48-22-16+10

LieO=20

In conclusion, candidates that sat for at least one subject

At least HEL= 24+8+20

At least HEL=52

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jrjejrjŕjwjskskskskskskksksksksksksks

43³/₄% can be expressed as a decimal to give 43.75%, which can be pronounced as forty-three point seventy-five percent.

A decimal value is a number that contains a whole and a fractional part.

Mathematically, decimal values are expressed using the decimal sign (.).

43³/₄%, which is a fractional value that can be changed into a decimal value thus:

= 43% + ³/₄%

= 43% + 0.75%

= 43.75%

Thus, 43³/₄%, which is forty-three-three-fourth percent, can be expressed as a decimal to give 43.75%.

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Answer:

E or c

Step-by-step explanation:

The demometer is the maximum amount of the number of jills in the group so if 5 out of 15 in the group is named jill then turn it into a fraction like 5/15

But you could simplify by findin the similar factirs then dividing them by the equivalent amounts

Answer:

6

Answer:

6+18

Step-by-step explanation:

HELP ME SOMEONE PLS ANSWER MY QUESTION FROM MY PROFILE.

The coordinates of points A and B are (-4, 5) and (2, 6) respectively. Point B is close to the origin by 0.1 unit

The positions or coordinates of points A and B are (-4, 5) and (2, 6) respectively

In order to use the Pythagorean Theorem to find the straight-line distance from each point to the origin (Consider the attached image):

Distance for point A

d = √((-4)²+5²)

d = √41 = 6.40 units

Distance for point A

d = √(2²+6²)

d = √40 = 6.32 units

To find which point is close to the origin and by how much:

The distance of B is less, so point B is close to the origin

Difference of distance =   6.40 - 6.32  = 0.08 ≈ 0.1 unit

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To find the probability that the flatcar derails, we need to subtract the probability of it not derailing from 1. Since the flatcar has an 80% chance of getting through without derailing.

Therefore, the answer is b. 20%.

What is the probability that both the boxcar and the flatcar get through without derailing
Since the events of the boxcar and the flatcar derailing are independent, we can multiply their probabilities together.

The boxcar has a 90% chance of getting through without derailing (0.9) and the flatcar has an 80% chance (0.8), so the probability that both get through without derailing is

0.9 * 0.8 = 0.72 or 72%.

Therefore, the answer is d. 72%.

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Answer:

24 inches

Step-by-step explanation:

\(a^{2}\) + \(b^{2}\) = \(c^{2}\)

\(18^{2}\) + \(b^{2}\) = \(30^{2}\)

324 + \(b^{2}\) = 900

\(b^{2}\) = 576

\(\sqrt{b^{2} }\) = \(\sqrt{576}\)

b  = 24

Answer:

24 inches

Step-by-step explanation:

Since the size of the screen is measured from the lower corner to the opposite upper corner.

therefore it forms a right angled triangle.

given hypotenuse is 30inch

the height is 18 inches

using the Pythagorean theorem

\( {hypotense}^{2} = {width}^{2} + {height}^{2} \)

then

\( {30}^{2} = {width}^{2} + {18}^{2} \\ 900 = {width}^{2} +324\)

Subtract 324 from both sides

\(576 = {width}^{2} \\ width = \sqrt{576} = 24 \: \: inches\)

Answer:

1/4

Step-by-step explanation:

\( \frac{3}5 \div x = \frac{12}{5} \\ \\ \frac{3}{5 } \times \frac{1}{x} = \frac{12}{5} \\ \\ \frac{3}{5x} = \frac{12}{5} \\ \\ x = \frac{3 \times 5}{12 \times 5} \\ \\ x = \frac{1}{4} \)

Answer:

it's the first one

Step-by-step explanation:

I got it right on edge

The requried, expression to find the value of the given expression when x =-2 and y = 5 is 3²(-2)⁶/5⁴. Option A is correct.

In order to remove pointless terms, factors, or operations from an expression, arithmetic, and algebraic principles are applied. The objective is to get an expression that is simpler to use, manipulate, or solve. For instance, factoring, merging like terms, or applying the distributive property can all be used to simplify an algebraic statement.

Here,
Given expression,
= (3x³y⁻²)²

To find the solution of the above expression given value of x and y,
= (3(-2)³(3)⁻²)²
= (3²(-2)⁶/3⁴)

Thus, the required expression to find the value of the given expression when x =-2 and y = 5 is 3²(-2)⁶/5⁴. Option A is correct.

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In both cases, the estimates depend on the specific characteristics of the box and the probabilities associated with each draw.

To estimate the chance that the sum of the draws will be more than 1,500, we need to know the distribution of values in the box and their probabilities. Without this information, we cannot provide a specific estimate.

(b) Similarly, to estimate the chance that the ticket [3] will be drawn fewer than 90 times, we need to know the distribution of values in the box and their probabilities. Without this information, we cannot provide a specific estimate.

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The population growth rate (r) for 2009 in the tiny country of fremont is found as 1.4.

All these elements are taken into account when formulating the population growth formula.

r = [(b + i) - (d + e)]/1000

Put the values in the formula.

r =  [(2,000 + 100) - (500 + 200)]/1000

r = 2100 - 700/ 1000

r = 1.4

Thus, the population growth rate (r) for 2009 in the tiny country of fremont is found as 1.4.

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With linear relationship, His rate is 7 hot dogs per minute. The number of hot dogs he eat every 3 minutes is 21 hot dogs. He have eaten hot dogs 13 minutes after you arrive is 95 hot dogs.

A straight-line link between two variables is referred to statistically as a linear relationship (or linear association). Both a graphical representation of a linear relationship, in which the variable and constant are connected by a straight line, and a mathematical representation, in which the dependent variable is determined by multiplying the independent variable by the slope coefficient and a constant.

A polynomial or non-linear (curved) relationship can be contrasted with a linear relationship.

The given parameters are;

Number of hot dogs Uncle Blake has eaten after 4 minutes = 32 hot dogs

Number of hot dogs eaten after 10 minutes = 74 hot dogs

Therefore, we have that the points on a graph of hot dog eaten are;

(4, 32), and (10, 74)

Which gives;

The rate of hot dogs eats = (74-32)/(10-4)

The rate of hot dogs eats = 42/6

His rate is 7 hot dogs/minute

He eat hot dogs in every 3 minutes

n = 7.t

n = 7.3

n = 21

The equation to calculate hot dogs eaten in times after our arrival is

n - 32 = 7·(t - 4)

n = 7·t - 28 + 32

n = 7·t + 4

He have eaten hot dogs 13 minutes after our arrive

n = 7·t + 4

n = 7*13 + 4

n = 91 + 4

n = 95

The number of hot dog he had eaten after 13 minutes at our arrival = 95 hot dogs

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Using the SSA method, the maximum number of triangles that can be generate is 1.

In the given question,

In SSA case for an obtuse angle, we have to find the maximum number of triangles that can be generate with the given information.

As we know that,

There cannot be a second obtuse angle if the specified first angle is already obtuse since the triangle's angle total would be greater than 180°. As a result, there is only one way to construct the triangle, making SSA a valid congruence theorem when the supplied angle is acute.

So the maximum number of triangles that can be generate is 1.

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Based on the given dividend of $4.91, a discount rate of 8.6%, and an expected perpetual growth rate of 3.6%, we would expect the stock's price to be $98.20 today.

To determine the stock's price today, we can use the dividend discount model (DDM), also known as the Gordon growth model. The DDM calculates the present value of all future dividends, taking into account the required rate of return and the expected growth rate.

Let's plug in the values given in your question:

Dividend (D) = $4.91

Discount Rate (r) = 8.6% or 0.086

Perpetual Growth Rate (g) = 3.6% or 0.036

Now we can substitute these values into the formula to calculate the stock's price today:

Stock Price =4.91 - 0.086 = 0.036

Stock Price= 0.086−0.036 = 4.91

Simplifying the denominator:

Stock Price = 4.91/0.05

Stock Price=98.20

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Answer: x=120

Step-by-step explanation:

If it is a regular polygon then the sum of internal angles is 180 degrees. Each angle should be 60. Since a straight line is 180, 180 - 60 would equal x!

Answer: 120

Step-by-step explanation: A triangle has a sum of 180°. A regular polygon has equal angles, so you divide 180 by 3, getting 60. Next x is supplementary to the adjacent angle, so you must do 180-60, yielding 120° as x.

Answer:

\(\frac{3}{2}\)

Step-by-step explanation:

let n be the number , then

\(\frac{1}{3}\) n = \(\frac{1}{2}\) ( multiply both sides by 3 )

n = 3 × \(\frac{1}{2}\) = \(\frac{3}{2}\)

As per the given length and width, the percentage of increase in perimeter is 1.07%

The perimeter of the rectangle is calculated by using the formula

P = 2(l + w)

where l refers the length and w refers the width of the rectangle.

Here we have the rectangle ABCD.

The length of AB is 20 cm and the width of CD is 30cm.

Then the perimeter of ABCD is calculated by using the formula,

=> P1 = 2(20 + 30)

=> P1 = 2(50) = 100

Now, the length of the rectangle is increased by 10%, then

=> l = 20 + [20 x 10/100] = 22

Then the width of the rectangle is increased by 5% is calculated as,

=> w = 30 + [30 x 5/100] = 31.5

Then the perimeter is calculated as,

=> P2 = 2(22 + 31.5) = 107

Then the increasing percentage is calculated as,

=> P2/P1 x 100

=> 107/100

=> 1.07%.

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If 100 students participate in the fundraiser, each student needs to raise $137.50.If 25 students participate in the fundraiser, each student needs to raise amount $550.

Amount = (Total Amount Needed) ÷ (Number of Students)

For 60 students:

Amount = $275 ÷ 60 = $4.58

For 75 students:

Amount = $275 ÷ 75 = $3.67

For 40 students:

Amount = $275 ÷ 40 = $6.88

To solve this problem, we need to use a simple equation: Amount = (Total Amount Needed) ÷ (Number of Students). We can then plug in the given information to calculate the amount each student needs to raise. For example, if 50 students participate in the fundraiser, we can calculate that each student needs to raise $275 ÷ 50 = $5.50. We can then use this equation to calculate the amount that each student needs to raise if there are different numbers of students participating in the fundraiser. For example, if there are 100 students participating in the fundraiser, each student needs to raise $275 ÷ 100 = $2.75. Similarly, if there are 25 students participating in the fundraiser, each student needs to raise $275 ÷ 25 = $11.00.

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Answer:

1/3

Step-by-step explanation:

2/6=1/3

Hello!

30 - 25 = 5

so + 5kg

+ 5kg = + 5kg/25kg = + 5/25 = + 0.2 = + 20/100 = + 20%

Answer:

4:3

8:6

32:24

Step-by-step explanation:

Well, you can change the values of both numbers and keeping the same ratio by dividing or multiplying both numbers (in this case 16 and 12) by the same number. So, first we can divide both numbers by 4 to get the ratio.... 4:3 and we could divide both numbers by 2 to get the ratio..... 8:6 and we can multiply both numbers by 2 to get the ratio....32:24

Hope this Helps!!! :)

Let me know in the comments if I should change anything or if the answer was perfect!