1. The charge on the hollow sphere is zero, and the charge on its surface is also zero.
2. The potential difference between the hollow sphere and the internal sphere is zero.
Explanation to the above given short answers are written below,
1. According to Gauss's law, the total electric flux through a closed surface is equal to the total charge enclosed by that surface divided by the permittivity of free space (ε₀).
In electrostatic equilibrium, the electric field inside a conductor is zero.
In this case, the metallic hollow sphere is a conductor, and the charge on the inner sphere induces an equal and opposite charge on the inner surface of the hollow sphere.
Since the electric field inside the hollow sphere is zero, there is no net charge on the hollow sphere itself, and the charge is redistributed on its inner surface.
2. Inside a conductor in electrostatic equilibrium, the electric potential is constant. Therefore, there is no potential difference between any two points inside the hollow sphere or between the hollow sphere and the internal sphere.
This is because the charges distribute themselves in such a way that the electric field inside the conductor is zero. As a result, the potential difference between the hollow sphere and the internal sphere is zero.
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 calculate the resistance of a toaster oven if its power is 800 W when connected to a 110 V outlet
To calculate the resistance of a toaster oven, we need to use Ohm's Law, which states that the current (I) flowing through a conductor is directly proportional to the voltage (V) applied to it and inversely proportional to the resistance (R) of the conductor, or I = V/R. We also know that power (P) is equal to the product of voltage and current, or P = V*I.
In this case, we are given that the toaster oven has a power of 800 W when connected to a 110 V outlet. Using the formula for power, we can find the current flowing through the toaster oven as follows:
P = V*I
800 W = 110 V * I
I = 800 W / 110 V
I = 7.27 A
Now that we know the current, we can use Ohm's Law to calculate the resistance of the toaster oven:
I = V/R
7.27 A = 110 V / R
R = 110 V / 7.27 A
R = 15.12 Ω
Therefore, the resistance of the toaster oven is 15.12 Ω when it is connected to a 110 V outlet and has a power of 800 W.
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1.When I cook an egg in a microwave oven, the device uses electromagnetic energy to increase the kinetic energy of particles of matter in the egg.
2.Many stoves and ovens have exhaust fans overhead to remove the rising warm air from the kitchen. The thermal energy is added to air and it rises.
3.When I cook an egg in a pan, thermal energy is transferred as the egg touches the hot surface of the pan. The thermal energy is transferred as objects touch.
choose which one are Conduction, Convection or Radiation
Answer:
1: Radiation 2: Convection 3: Conduction
Explanation:
A negative charge Q1 = -5. 50 is located at a point x1=-6. 00 abd. Positive chsrge Q2= 6. 50 uc is located at point x2= 4. 00 m find the magnitude and direction of the electric force between rhe charges
The magnitude of the electric force between the charges Q₁ and Q₂ is approximately 1.98 × 10^9 N. The force is attractive, pulling the negative charge Q₁ towards the positive charge Q₂.
To calculate the magnitude and direction of the electric force between the charges Q₁ and Q₂, we can use Coulomb's Law:
F = k * |Q₁ * Q₂| / r²
Where:
F is the magnitude of the electric force
k is the Coulomb's constant (approximately 8.99 × 10^9 N·m²/C²)
Q₁ and Q₂ are the magnitudes of the charges
r is the distance between the charges
In this case:
Charge Q₁ = -5.50 µC (microcoulombs)
Charge Q₂ = 6.50 µC (microcoulombs)
Distance between the charges r = 4.00 m
Substituting the given values into the Coulomb's Law equation:
F = (8.99 × 10^9 N·m²/C²) * |(-5.50 µC) * (6.50 µC)| / (4.00 m)²
F = (8.99 × 10^9 N·m²/C²) * (35.75 µC²) / (16.00 m²)
F ≈ 1.98 × 10^9 N
Therefore, the magnitude of the electric force between the charges = 1.98 × 10^9 Newtons. The direction of the force can be determined based on the charges: since Q₁ is negative and Q₂ is positive, the force will be attractive, pulling Q₁ towards Q₂.
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Shelley shines her red, helium-neon laser, whose wavelength is 633 nm, on a photocell that has a work function of 2.38 eV. a) Will the photocell function with this wavelength of light? b) If so, what is the kinetic energy of the photoelectrons released? If not, what wavelength corresponds to the threshold frequency?
The energy of the photons in the light is greater than the work function of the photocell (2.38 eV), the photocell will function with this wavelength of light, and the kinetic energy of the photoelectrons released from the photocell is 0.98 eV.
To determine if the photocell will function with the given wavelength of light, we need to compare the energy of the photons in the light to the work function of the photocell. The energy of a photon will be given by:
E = hc/λ
where h is Planck's constant, c is the speed of light, and λ is the wavelength.
Substituting the values given, we get:
E = (6.626 x 10\(10^{-34}\) J s) × (3.00 x 10⁸ m/s) / (633 x\(10^{-9}\) m)
E = 3.14 x \(10^{-19}\) J
Converting this energy to electron volts (eV), we get:
E = 3.14 x \(10^{-19}\) J / 1.60 x \(10^{-19}\) J/eV
E = 1.96 eV
Since the energy of the photons in the light is greater than the work function of the photocell (2.38 eV), the photocell will function with this wavelength of light.
The kinetic energy of the photoelectrons released from the photocell is given by:
K.E. = E - W
where E is the energy of the photon and W is the work function of the photocell.
Substituting the values given, we get:
K.E. = (3.14 x \(10^{-19}\) J) / (1.60 x \(10^{-19}\) J/eV) - 2.38 eV
K.E. = 0.98 eV
Therefore, the kinetic energy of the photoelectrons released from the photocell is 0.98 eV.
If the energy of the photons in the light had been less than the work function of the photocell, then the photocell would not have functioned. In that case, the threshold frequency (ν) would be given by:
ν = W/h
where h is Planck's constant and W is the work function of the photocell. Once the threshold frequency is known, we can use the formula E = hν to find the corresponding wavelength.
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what two items on the list below are in balance in what we call energy balance?
In the context of energy balance, two items that are in balance are energy intake and energy expenditure.
Energy intake refers to the calories consumed through food and beverages, while energy expenditure refers to the calories burned by the body through daily activities and metabolic processes. When these two factors are equal, the body maintains a stable energy balance, supporting overall health and well-being.
Energy radiated into space from the Sun's surface is equal to energy released by fusion in the Sun's core.
The balance between the quantity of energy input and the amount of energy production is referred to as the "energy balance." We say there is an energy balance when the amount of energy released equals the amount of energy returned to the system.
The primary energy source in the universe is the Sun, which generates energy through the FUSION OF RADIOACTIVE MATERIALS IN ITS CORE. When the energy released by the Sun is equal to the energy released to outer space, we say that there is energy balance.
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In the context of energy balance, two items that are in balance are energy intake and energy expenditure.
Energy intake refers to the calories consumed through food and beverages, while energy expenditure refers to the calories burned by the body through daily activities and metabolic processes. When these two factors are equal, the body maintains a stable energy balance, supporting overall health and well-being.
Energy radiated into space from the Sun's surface is equal to energy released by fusion in the Sun's core.
The balance between the quantity of energy input and the amount of energy production is referred to as the "energy balance." We say there is an energy balance when the amount of energy released equals the amount of energy returned to the system.
The primary energy source in the universe is the Sun, which generates energy through the FUSION OF RADIOACTIVE MATERIALS IN ITS CORE. When the energy released by the Sun is equal to the energy released to outer space, we say that there is energy balance.
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Franz Mesmer believed that his ability to heal people was based on his manipulation of which force? A. Electricity B. Gravity C. Magnetism D. Inertia.
Answer:
Your answer here is C
Explanation:
Good Luck
Inertia is the tendency of an object to continue in the state of motion or rest unless a force acts on it. The state of inertia of a person can be studied and the force which can change the state can be suggested.
What is force?Force is an external agent acts on a body to change it from the state of rest or motion. There are various kinds of forces such as magnetic force, nuclear force etc.
According to Newton's first law of motion, an object will stay at its state of motion or rest until and unless a force acting upon it. This tendency of an object to stay in on the same state is called inertia and this law is called law of inertia.
Inertia can be interpreted in a person because of the tendency to stay in a state. However the force which can be applied to change this situation can be find out appropriately.
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013
A car of mass 1,000 kg begins stationary on a road at the top of a
mountain, at a height h = 3,000 m. The car then rolls freely down a
winding road, travelling a total distance of 5 km, to reach the height h
= 2,000 m. Assume g = 9.8 ms 2.
1
How much energy did the car lose on descent? Give you answer to 3 significant figures,
with units.
Energy lost =
The energy lost by the car on descent is 980×10⁴ J
We'll begin by calculating the energy of car at various heights.
At height 3000 m:Mass (m) = 1000 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 3000 m
Energy (E) =?E = mgh
E = 1000 × 9.8 × 3000
E = 29400000 JAt height 2000 m:Mass (m) = 1000 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 2000 m
Energy (E) =?
E = mgh
E = 1000 × 9.8 × 2000
E = 19600000 JFinally, we shall determine the the energy lost
Energy at 3000 m = 29400000 J
Energy at 2000 m = 19600000 J
Energy lost =?Energy lost = Energy at 3000 m – Energy at 2000 m
Energy lost = 29400000 – 19600000
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A magnifier allows one to look at a very near object by forming an image of it farther away. The object appears larger. To create a magnifier, one would use a.
In order to create a magnifier in convex lens, you should choose a short focal length that is lesser than 1 meter.
What is a convex lens?A convex lens is also referred to as converging lens and it can be defined as a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image.
In Science, a magnifier refer to an optical instrument that allow us to look at a very near object because its image is generally formed farther away. Thus, the image of the object appears to be much larger.
In this context, you should choose a short focal length that is lesser than 1 meter when you want to create a magnifier in convex lens because the nearer the object is to the lens, the larger would be the image formed.
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The maxim 'actus non facit reum, nisi mens sit rea' illustrated the elements required in order to constitute a crime. Yet the principle to imposed criminal responsibility on strict liability offences connoted a contradicting intent. The most worrying trend posed is that strict ability offences have frequently not been afforded any defence, where a conduct is sufficient to be held liable for the offence committed even he has no guilty mind.
Justify your stand over the application of the offence above by citing your own reasons. Do you agree with the application of such offence or not. Support your reason with relevant law authorities.
I agree with the application of such offenses where criminal responsibility is imposed on strict liability offenses because it is needed to protect public welfare, promote safety, and deter potential harm.
What are strict liability offenses?Strict liability offenses are those in which liability is imposed without requiring proof of intent or guilty mind. These offenses focus on the act itself rather than the mental state of the offender. The rationale behind strict liability offenses is often rooted in the need to protect public welfare, promote safety, and deter potential harm.
An argument in favor of strict liability offenses is that they ensure accountability for certain actions that pose a significant risk to society, even in the absence of intent or mens rea. By placing the burden on individuals to adhere to certain standards or regulations, strict liability offenses can help prevent accidents, protect public health, and maintain order.
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A cylindrical glass that is 10cm high is partially filled with water. You see the glass in two positions. What is the height of the water when the glass is upright
Answer:
5 cm.
Explanation:
If the glass is located upright, the height of water is about 5 cm because the height of glass is 10 cm and it is partially filled with water and we know that partial means 50 percent of something and here 50 percent of glass is 5 cm. If the glass is slightly bend, so we can't find its right height so the proper height of water is attain if it is placed on flat table and present upright.
Use your data to predict what a 400g bag would weigh
The volume of the 400g bag of flour is 666.67 cm^3.
This question asks for the calculation of the volume of a 400g bag of flour with a density of 0.6 g/cm^3. The density of a material is defined as its mass per unit volume, and can be expressed mathematically as:
density = mass/volume.
Rearranging the equation to solve for volume, we get:
volume = mass/density.
Substituting the given values, we get:
Volume = 400 g / 0.6 g/cm^3
Solving for the volume, we get:
Volume = 666.67 cm^3
Volume = 400g / 0.6 g/cm^3, which simplifies to 666.67 cm^3.
Therefore, the volume of the 400g bag of flour is 666.67 cm^3.
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--The complete Question is, If a 400g bag of flour has a density of 0.6 g/cm^3, what is its volume in cm^3? --
Which type of energy is stored in an elastic material stretched by a force
Potential energy is stored in the elastic material when we stretch it by some distance.
The energy stored when a force is used to deform an elastic object is called elastic potential energy. The energy is conserved until the force is released and the object returns to its original shape, doing work in the process. Objects can be compressed, stretched, or twisted when deformed.
Elastic material produces elasticity when stretched or compressed. The more the material is crushed or stretched, the greater this force.
Springs have many applications, including bed springs.
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Friction is a ____________ force
a. Artificial
b. Natural
c. Pessimistic
d. Negative
Answer:
natural is the answer
Friction is a natural force which exist
The word _____ is defined as either of two points when the sun's rays strike the earth at the equator.
Answer:
Equinox.
Explanation:
It is Equinox because Equinox is defined as the time when the sun rays passes through the Earth's equator. This happen twice in the year around 21 March and 23 September. It is the time when the center of the sun is directly above the equator.
This normally occur when the Earth axis is either tilted toward or away from the sun which lead to equal amount of daylight and darkness.
Two nuclei join to form a larger nucleus during which process?
• A. Positron emission
• B. Nuclear fusion
• C. Gamma decay
•
D. Nuclear fission
The process of two nuclei joining to form a larger nucleus is called nuclear fusion.
Nuclear fusion is the process by which atomic nuclei come together to form heavier nuclei, releasing a large amount of energy in the process.
In nuclear fusion, two atomic nuclei are brought close enough together that the strong nuclear force overcomes the electrostatic repulsion between the positively charged nuclei. This allows the nuclei to merge and form a new, heavier nucleus. The process of nuclear fusion is what powers the sun and other stars, where hydrogen nuclei combine to form helium and release a tremendous amount of energy in the process.
In contrast, nuclear fission is the process by which a large nucleus is split into smaller nuclei, releasing energy in the process. Nuclear fission is used in nuclear power plants to generate electricity, where the energy released from splitting heavy atomic nuclei is used to heat water and generate steam that powers turbines.
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A car accelerates from a standstill to 60 km/hr in 10.0 seconds. What is its acceleration?
The acceleration of the car is 1.66 m per sec square.
How to calculate acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating.
Initial velocity=0
Final velocity= 60km/hr
To convert it into m/sec
1 km=1000 m
1 hr=3600 sec
So= (60×1000)÷3600=16.66 m/sec
time=10 sec
We know that acceleration is the rate of change of velocity per unit of time.
acceleration=(final velocity-initial velocity)÷ time taken
= (16.66-0)÷10
= 1.66 m per sec square
So, Acceleration will be, 1.66 m per sec square
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An ohm is best described as a unit of measure for...
A. electrical resistance
B. electrical current
C. electrical potential difference
D. magnetic field strength
For freely falling objects near earth's surface, _____ is constant.
A
acceleration
B
speed
C
velocity
D
momentum
The correct option is A. acceleration.
For freely falling objects near Earth's surface, acceleration is constant. An object that is allowed to fall freely under the influence of Earth's gravity is known as a freely falling object. Gravity is an acceleration that acts on any two masses.
For freely falling objects near Earth's surface, the acceleration is indeed constant. This fundamental concept is a result of gravity's influence on objects in free fall. When an object is in free fall, it means that no forces other than gravity are acting upon it. In this scenario, the acceleration experienced by the object remains constant and is equal to the acceleration due to gravity, which is approximately 9.8 meters per second squared (m/s²) near Earth's surface.
The constancy of acceleration in free fall can be attributed to the consistent force of gravity acting on the object. Gravity pulls objects downward towards the center of the Earth, causing them to accelerate uniformly. Regardless of the object's mass, shape, or composition, the acceleration remains constant. This is known as the equivalence principle, which states that all objects experience the same acceleration due to gravity in the absence of other forces.
As an object falls freely, its velocity increases at a steady rate. Each second, the object's velocity increases by approximately 9.8 m/s. This means that in the first second, the velocity increases by 9.8 m/s, in the second second it increases by an additional 9.8 m/s, and so on. The consistent acceleration enables the object to cover greater distances in successive time intervals.
In conclusion, for freely falling objects near Earth's surface, the acceleration remains constant at approximately 9.8 m/s². This constancy arises from the unchanging force of gravity acting on the objects, leading to a uniform increase in velocity over time.
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If I traveled 30 miles in 1 hour, then 20 miles in 1 hour, and 50 miles in 3
hours, what is my average speed?
Answer:
The answer is 20 miles/hr
Explanation:
Explain how you would apply any five pricing techniques to attract customers
Answer:
Explanation:
1. DECOY PRICING
This occurs when customers make a purchase they must often choose between products with different prices and attributes.
This method of pricing is meant to influence the consumer's purchasing decision and maximise the sales of one particular product. The seller will offer at least three products; two of the products will have a similar or equal price. The two products with the similar prices should be the most expensive ones, and one of the two should be less attractive than the other.
2. LOSS LEADER
This is when a product is sold at a low price (often without profit) in order to stimulate other profitable sales or to attract new customers.
The main is that it will help the business to expand their market share as a whole. It's common practice when first entering a market as it introduces new customers to a service or product in the hope of building a customer base and securing future
3.ODD PRICING
This is a method of psychological pricing a product. Prices ending in 9, 95, 97, 99 are sometimes called “charm prices” and in this type of pricing, the seller fixes a price where the last digits are odd numbers. This is intended to give the buyer no room for manœuvering or for bargaining as the price appears to be less - a product priced at £9.99 will seems much cheaper than one priced at £10.00
4. PRICE DISCRIMINATION
The purpose of price discrimination is to capture the market's consumer surplus and generate the most revenue possible for a product. Identical goods or services are sold at different prices from the same provider to different segments of the market. Industries that commonly use price discrimination include the travel industry, pharmaceuticals and textbook publishers.
5. PRODUCT BUNDLE PRICING
Using this method, sellers will combine several products in the same package. It also serves to move old stock. Blu-ray and videogames are often sold using the bundle approach once they reach the end of their product life cycle. This technique is used at auctions where one attractive item may be included in a lot with a box of less interesting things. Buyers must bid for the entire lot. It’s a good way of moving slow selling products, and in a way is another form of promotional pricing.
I’m on earth.I have an object with a mass of 15 kg. When I put it on a scale, what will the scale read?
The scale will read 147N
Explanation:The mass of the object, m = 15 kg
Since I am on the earth, the acceleration due to gravity on the earth is:
g = 9.8 m/s²
The scale will read the weight of the object, and is calculated below
The weight, W = mg
W = 15(9.8)
W = 147 N
Therefore, the scale will read 147N
Which of the following can actually escape from inside a black hole's event horizon?
a. Protons
b. Very high energy gamma rays
c. Electrons
d. Neutrinos
e. None of the above
Once anything, including protons, electrons, gamma rays, and neutrinos, crosses the event horizon of a black hole, it is impossible for it to escape due to the extreme gravitational pull. so, correct option is e)None of the above
Inside a black hole's event horizon, the gravitational pull is so strong that nothing, not even protons, electrons, or any form of electromagnetic radiation such as gamma rays, can escape it. Neutrinos, which are very low-mass particles, also cannot escape the event horizon.
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Describe specifically why a one-time pad is completely unbreakable. What happens if we try and brute-force
something encrypted with a one-time pad?
Encrypt the message "yellowstone" using the key "wolf" using the vignere cipher.
A one-time pad is a type of encryption that is completely unbreakable if it is done correctly. It works by generating a random key that is at least as long as the message being encrypted. The key is then combined with the message using an XOR operation.
This produces a ciphertext that cannot be decrypted without the key. The key is used only once and then discarded, hence the name "one-time pad". A one-time pad is completely unbreakable because there is no pattern to the key that can be used to decrypt the message. Each character in the key is generated randomly and independently of the other characters. Therefore, the key is completely unpredictable. Even if an attacker knows the key length and has access to the ciphertext, they cannot use any techniques to decrypt it.
This is because there is no pattern to the ciphertext that can be used to determine the key.The only way to decrypt a one-time pad is to have the key. If an attacker tries to brute-force the encryption by trying all possible keys, they will generate every possible message that is the same length as the original message. This means that the ciphertext is completely meaningless without the key. It is therefore important to keep the key secret and ensure that it is only used once. ,Message: yellow stone Key: wolf To encrypt the given message using the vigenere cipher, we follow the steps below:Step 1: Write the message and key in a tabular form as shown below. To keep the process organized, we use the letters of the key to label the columns.
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which of the following processes always results in an increase in the energy of a system? multiple choice the system loses heat and does work on the surroundings. the system gains heat and does work on the surroundings. the system loses heat and has work done on it by the surroundings. the system gains heat and has work done on it by the surroundings. none of these is always true.
The process that always results in an increase in the energy of a system is:
the system gains heat and has work done on it by the surroundings.
What is Work Done?
Work done is the energy transferred to or from an object by means of a force acting on it, causing it to move a certain distance in the direction of the force. The amount of work done is defined as the product of the magnitude of the force and the distance moved by the object in the direction of the force. Work is a scalar quantity, and its unit is joule (J) in the SI system of units. Work can be positive, negative, or zero depending on the direction of the force and the direction of the displacement of the object.
When heat is added to a system, the internal energy of the system increases, which results in an increase in its energy. Similarly, when work is done on a system, it also results in an increase in its energy. Therefore, when both heat is added to a system and work is done on it by the surroundings, the energy of the system increases. This is because the system gains energy from both heat and work.
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Un bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________
Answer:
a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s
b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m
c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s
d) La altura que alcanza el bloque es de 5 metros.
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción
Explanation:
a) Los parámetros dados del bloque son;
La masa del bloque, m = 3 kg
La altura a la que se coloca el bloque, h = 5 m
La constante de resorte, k = 400 N / m
La aceleración debida a la gravedad, g = 9,8 m / s²
La energía potencial de un cuerpo, P.E. = m · g · h
Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;
P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios
P.E. = 147 julios
La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²
Dónde;
v = La velocidad del bloque cuando llega al resorte
Por lo tanto, para el bloque dado tenemos;
K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²
Por el principio de conservación de la energía, tenemos;
El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.
∴ P.E. = K.E.
147 J = 1/2 × 3 kg × v²
v² = 147 J / (1/2 × 3 kg) = 98 m² / s²
v = √ (98 m² / s²) = 7 · √2 m / s
v = 7 · √2 m / s ≈ 9,9 m / s
b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²
Dónde;
k = La constante del resorte = 400 N / m
x = La distancia a la que se comprime el resorte
Por el principio de conservación de la energía, tenemos;
La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.
∴ E = 1/2 · k · x² = P.E.
De lo que tenemos;
E = 1/2 × 400 N / m × x² = 147 julios
x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²
x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m
La distancia a la que se comprime el resorte = x ≈ 0.86 m
c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;
La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²
∴ 1/2 · k · x² = 1/2 · m · v²
∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s
La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s
d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;
P.E. = K.E.
∴ m · g · h = 1/2 · m · v²
v = 7 · √2 m / s
De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción
a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
a) Conforme a la situación de este problema, la energía cinética traslacional final (\(K\)), en joules, es igual a la energía potencial gravitacional inicial (\(U\)), en joules.
\(U = K\) (1)
Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:
\(m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}\) (1)
Ahora despejamos la velocidad de esa ecuación:
\(v = \sqrt{2\cdot g\cdot h}\)
Donde:
\(m\) - Masa del bloque, en kilogramos.\(g\) - Aceleración gravitacional, en metros por segundo al cuadrado.\(h\) - Altura inicial del bloque, en metros.\(v\) - Velocidad final del bloque, en metros por segundo.Si sabemos que \(g = 9.807\,\frac{m}{s^{2}}\) y \(h = 5\,m\), entonces la velocidad final del bloque es:
\(v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}\)
\(v\approx 9.903\,\frac{m}{s}\)
La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:
\(\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}\) (2)
Where:
\(k\) - Constante de resorte, en newtons por metro.\(x\) - Deformación del resorte, en metros.Ahora despejamos la deformación del resorte:
\(x = \sqrt{\frac{m}{k} }\cdot v\) (3)
Si sabemos con \(k = 400\,\frac{N}{m}\), \(m = 3\,kg\) y \(v \approx 9.903\,\frac{m}{s}\), entonces la deformación del resorte es:
\(x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)\)
\(x \approx 0.858\,m\)
El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
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Which scenario describes an effect of tornadoes on the environment? a section of forest that has been burned a path through a town with uprooted trees a town near the coast with heavy flooding a sandy beach that shows signs of erosion
Answer:
B; a path through a town with uprooted trees
Explanation:
took the quiz and got it right on edge2020!
The effect of tornadoes on the environment is a path through a town with uprooted trees. This, option B is correct.
What are tornadoes?It is the typical weather event that contains strong winds and leaves a path of destruction up to 50 miles long. It is also defined as the violently rotating column of air that touches the ground and is usually attached to a thunderstorm.
It is developed from a severe thunderstorm in warm, moist, and unstable air and extended up to 300 miles. The thunderstorms also generate heavy damage and devastate the environment in seconds and cause more fatalities.
A swirling, funnel-shaped, whirling wind is called a tornado and it is accompanied by hurricanes and storms. Strong tornadoes last for twenty minutes and the winds are between 200 mph to 300mph. The United States and Canada are mostly tornado-affecting countries.
The effect of tornadoes is a path through a town with uprooted trees and hence, the ideal solution is option B.
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Assume each mark on the scale represented 1 g. Estimate how much a sheet of paper would mass. A sheet of paper is 28 cm by 21.7 cm.
Answer:
607.6g
Explanation:
Assume each mark on the scale represented 1 g. That is 1 cm = 1g
To estimate how much a sheet of paper would mass a sheet of paper is 28 cm by 21.7 cm, first calculate the area.
Area = 28 × 21.7 = 607.6 cm^2
Mass = 607.6 × 1g = 607.6 g
Therefore, the estimation will be 607.6g
A truck with 20 -in.-diameter wheels is traveling at 60mi/h. Find the angular speed of the wheels in rad/min: rad/min How many revolutions per minute do the wheels make? rpm Question Help: D Video □ Message instructor Rae and Inga are riding the Prince Charming Carousel at Disney World. Rae is on a horse 18 feet from the center. Inga is on a horse 23 feet from the center. Prince Charming has the carousel spinning at 55 revolutions per minute. What is Rae's linear speed (in feet per second) ft/sec What is Inga's linear speed (in feet per second) ft/sec Question Help: □ Video □ Message instructor A vinyl record is spinning at 70 revolutions per minute. A ladybug is sitting on the record 20 centimeters from the center. What is the angular velocity of the ladybug in rad/sec: rad/sec What is the linear speed of the ladybug in cm/sec ? cm/sec
A truck with 20 -in.-diameter wheels is traveling at 60mi/h. The angular speed of the wheels is approximately 637.18 rad/min. Rae and Inga are on horses 18 feet 23 feet from the center. Rae's linear speed is 34.557 ft/sec while Inga's linear speed is 83.992 ft/sec.
a) To find the angular speed of the wheels in rad/min, we need to convert the linear speed from miles per hour to inches per minute and then calculate the angular speed.
Linear speed of the truck = 60 mi/h = 60 * 5280 * 12 inches / 60 minutes
Now, we can calculate the angular speed:
Angular speed (in rad/min) = Linear speed (in inches/min) / Circumference (in inches) * 2π
Let's plug in the values and calculate the angular speed:
Circumference = π * 20 inches ≈ 62.83 inches
Linear speed = 60 * 5280 * 12 / 60 ≈ 6,336 inches/min
Angular speed = 6,336 inches/min / 62.83 inches * 2π ≈ 637.18 rad/min
Therefore, the angular speed of the wheels is approximately 637.18 rad/min.
To find the number of revolutions per minute the wheels make, we can convert the angular speed to revolutions per minute:
Revolutions per minute = Angular speed (in rad/min) / 2π
Revolutions per minute ≈ 637.18 rad/min / (2π) ≈ 101.43 rpm
Therefore, the wheels make approximately 101.43 revolutions per minute.
b)The linear speed of an object moving in a circle can be calculated using the formula:
Linear speed = (2π * radius) * (rotational speed)
Let's calculate Rae's linear speed first:
Rae's radius = 18 feet
Rotational speed = 55 revolutions per minute
Rae's linear speed = (2π * 18 feet) * (55 revolutions/minute)
Rae's linear speed = (2π * 18 feet) * (55 * 2π radians / 60 seconds)
Simplifying:
Rae's linear speed = (36π² * 18 feet) / 60 seconds
Now, let's calculate Inga's linear speed:
Inga's radius = 23 feet
Rotational speed = 55 revolutions per minute
Inga's linear speed = (2π * 23 feet) * (55 revolutions/minute)
Converting revolutions per minute to radians per second:
1 revolution = 2π radians
1 minute = 60 seconds
Inga's linear speed = (2π * 23 feet) * (55 * 2π radians / 60 seconds)
Simplifying:
Inga's linear speed = (46π² * 23 feet) / 60 seconds
Calculating the numerical values:
Rae's linear speed ≈ 34.557 ft/sec
Inga's linear speed ≈ 83.992 ft/sec
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Putting your thumb over the end of a hose causes the water to flow out more quickly what law is it
"Please include all relevant working out as detailed as possible
and all relevant diagram to find the answer. Much appreciated! I
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Find total response of the system (transient+steady state). Do not solve for coefficients. Determine the frequency of applied force at which resonance will occur? M = 20 kg F, = 90 N Given: -6 rad/s M
Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.
The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:
ωn = √(K / M),
where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.
Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.
ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.
Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
The correct question is given as,
M= 20kg
Fo = 90 N
ω = 6 rad/s
K = 400 N/m
C = 125 Ns/m
Determine the frequency of applied force at which resonance will occur?
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