A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 563 K, and reservoir 2 is at a temperature of 354 K. Compute the total change in entropy arising from the conduction of 1760 J of heat through the wire. Please give your answer in units of J/K.

Answer:

gpe gained = 60J

Explanation:

gravitational potential energy  =  mass * gravity * height

gpe =  2 kg * 10 N * 3 m

gpe = 60J

the information provided (34 and 42 seconds) does not give the necessary information to determine the speed at which the BEYBLADE is spinning in miles per hour. To calculate the speed of the BEYBLADE we need to know the distance traveled in each rotation. Also, you mentioned that the beyblade makes 1 rotation in 34 seconds and 42 seconds, which is not correct, it should be 1 rotation per second in 34 seconds, and 1 rotation per 42 seconds.

a. Savannah would debit retained earnings and credit dividends payable for the declaration of a cash dividend, and debit dividends payable and credit cash for the payment, b. To declare and pay a stock dividend, Savannah would debit retained earnings and credit common stock dividend distributable for declaration, then debit common stock dividend distributable and credit common stock for payment, and c. Dividends payable to shareholders like Elena and Josh can be computed by multiplying the number of shares owned by the dividend per share.

Dividends Payable is a liability account used to record the amount of dividends that a company owes to its shareholders but has not yet paid out. It represents the obligation of the company to pay out the declared dividend amount to its shareholders, and the balance is typically cleared out when the dividend payment is made. Companies usually set a record date and payment date to declare and pay dividends respectively.

a. To journalize the declaration and payment of the cash dividend, Savannah would make the following entries:

Declaration:

Debit: Retained Earnings

Credit: Dividends Payable

Payment:

Debit: Dividends Payable

Credit: Cash

b. To journalize the declaration and payment of the stock dividend, Savannah would make the following entries:

Declaration:

Debit: Retained Earnings

Credit: Common Stock Dividend Distributable (70,000 x 5% = 3,500 shares)

Payment:

Debit: Common Stock Dividend Distributable

Credit: Common Stock ($7.25 x 3,500 shares)

c. To compute the dividends payable to Elena and Josh, we would use the following formula:

Dividends Payable = Number of Shares x Dividend per Share

For Elena:

Dividends Payable = 300 shares x $0.10 per share = $30.00

For Josh:

Dividends Payable = 75 shares x $0.10 per share = $7.50

Therefore, To declare and pay a cash dividend, Savannah would debit retained earnings and credit dividends payable for declaration, and debit dividends payable and credit cash for payment. To declare and pay a stock dividend, Savannah would debit retained earnings and credit common stock dividend distributable for declaration, then debit common stock dividend distributable and credit common stock for payment. Dividends payable to shareholders like Elena and Josh can be computed by multiplying the number of shares owned by the dividend per share.

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Answer:

i think it's C thx correct me if wrong

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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7.41 m/s^2

When an object is traveling in a straight line with an increase or decrease in velocity at equal intervals of time, then the object is said to be in uniform acceleration

to find the acceleration we can use the formulas

so

Step 1

a)

let

b) replace in equation (2)

replace in equation (1)

now, replace in the previous equation to find a

so, the answer is

finally, let's convert the acceleration from miles per squared hour into meters per square second

remember that:

so

hence

the acceleration is -7.41 m/s^2

I hope this helps you

Answer:The place to go for the answer to such an easy question is the SI Brochure, the document which defines the SI and all its units.

All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

i think C is the answer

Explanation:

The gravitational force between the Earth and Moon will increase by cutting the distance between the Earth and Moon in half. Hence, option (C) is correct.

The given problem is based on the concept of gravitational force. The force of attraction between the two massive bodies in a space is known as the gravitational force. Let us consider the mass of Earth and moon as M and m such that the gravitational force between each is,

\(F = \dfrac{G \times M \times m}{R^{2}}\)

Here,

G is the universal gravitational constant.

R is the distance between the Earth and Moon.

Clearly, the forces between the Earth and Moon varies directly with the masses of Earth and Moon and inversely with the distance between the Earth and Moon. Since, masses are the constant parameters, hence reducing the distance will increase the gravitational force.

Thus, we can conclude that the gravitational force between the Earth and Moon will increase by cutting the distance between the Earth and Moon in half. Hence, option (C) is correct.

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Answer:

The final displacement would be 2cm to right.

Answer:

10 N.m

Explanation:

Force * Perpendicular distance.

= 20 N * 0.5 m

= 10 N.m

Magnetic field lines emerge from one sunspot and re-enter at the other spot. Also, there are more sunspots during periods of increased magnetic activity. At ...

The temperature of sunspots increases because magnetic field lines emerge from one sunspot and reappear in another. During periods of increased magnetic activity, there are also more sunspots.

The magnetic field of the sun has two poles, similar to a bar magnet. Every 11 years, at the peak of the solar activity cycle, the poles flip.

The magnetic field is carried away from the sun's surface and through the solar system by a solar wind made up of charged particles. The sun is more like a fluid than a solid ball.

Thus, the magnetic field lines emerge from one sunspot and reappear in another. During periods of increased magnetic activity, there are also more sunspots.

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Senen Bacani is an entrepreneur, the CEO of La Fuerta Inc which is one of the largest exporters of bananas in Philippines.

Senen Bacani was the formal sectary of Agriculture to president Corazon Aquino and during that time he visited many Philippines province and realize how poor people struggle to fend for their families and remember how his father who  was a doctor received farm produce from his patient, appreciating him for medical care they received seeing the need of the of the rural people, has compelled him to work for shifts in policy and programs as the secretary and later in 1993 after working for president Aquino administration, he establish a business in agriculture to provide employment and to alleviate poverty in the rural areas Mostly in Mindanao, where he establish business venture that brought about not only employment but peace where there had been years of unemployment, crime and inter-ethnic conflict.

Senen Bacani presently head 9 different companies and presently occupies the position of Chairman for  different Inc., in the Philippines.

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Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

Answer:

the magnitude of the average force on the bumper is 3189.8 N

Explanation:

Given the data in the question;

In terms of force and displacement, work done is;

W =\(F^>\) × \(x^>\)

W = \(Fxcos\theta\)    ------- let this be equation 1

where F is force applied, x is displacement and θ is angle between force and displacement.

Now, since the displacement of the bumper and force acting on it is in the same direction,

hence, θ = 0°

we substitute into equation 1

W = \(Fxcos(\) 0° \()\)

W = \(Fx\) ------- let this be equation 2

Now, using work energy theorem,

total work done on the system is equal to the change in kinetic energy of the system.

\(W_{net\) = ΔKE

= \(\frac{1}{2}\)mv² -  \(\frac{1}{2}\)mu² --------- let this be equation 3

where m is mass of object, v is final velocity, u is initial velocity.

from equation 2 and 3

\(Fx\) = \(\frac{1}{2}\)mv² -  \(\frac{1}{2}\)mu²

we make F, the subject of formula

F = \(\frac{m}{2x}\)( v² - u² )

given that mass of car m = 830 kg, x = 0.255 m, v = 0 m/s, and u = 1.4 m/s

so we substitute

F = \(\frac{830}{(2)(0.255)}\)( (0)² - (1.4)² )

F = 1627.45098 ( 0 - 1.96 )

F = 1627.45098 ( - 1.96 )

F = -3189.8 N

The negative sign indicates that the direction of the force was in opposite compare to the direction of the velocity of the car.

Therefore, the magnitude of the average force on the bumper is 3189.8 N

The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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The amplitudes of the waves are added or subtracted when two waves overlap or superpose.

if the amplitude of the resultant wave is greater, it is called the constructive interference.

if the resultant amplitude is less than the amplitudes of the superposing waves, it is the destructive interference.

Here, the answer is destructive interference.

Answer:

a = 15.1 g

Explanation:

The relation between mass and acceleration is given by :

\(m\propto \dfrac{1}{a}\)

If a₁ = 0.80g, m₁ = 1510 kg, m₂ = 80 kg, we need to find a₂

So,

\(\dfrac{m_1}{m_2}=\dfrac{a_2}{a_1}\\\\a_2=\dfrac{a_1m_1}{m_2}\\\\a_2=\dfrac{0.8g\times 1510}{80}\\\\a_2=15.1g\)

So, the car's acceleration would be 15.1 g.

It is defined as the stress that results in the elongation of the material

Answer:

Explanation:

The formula for calculating the period of a wave is expressed as

Period = 1/frequency

From the information given,

frequency = 459.2 Hz

Thus,

Period = 1/459.2

Period = 0.0022 seconds

If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.

Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.

Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.

While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.

Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.

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The evidence that Wegener did NOT use to support his idea of continental drift is "the thickness of layers of ice in the Antarctic.

option C

Wegener's primary evidence for continental drift included the fit of the coastlines of different continents, the distribution of fossils across different continents, and the alignment of rock strata on different continents.

So the thickness of layers of ice in the Antarctic, was not used by Wegener to support his idea of continental drift. While this evidence is important for supporting the theory of glaciation, it is not relevant to the theory of continental drift.

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The speed of the car is 6 m/s. The acceleration vector at point B has a direction of (-1, -1) and a magnitude of approximately 16.97 m/s².

We can start by finding the speed of the toy car. Since it is moving with constant speed around the circle, its speed is the same at points A and B. To find the speed, we can use the fact that the velocity vector has a magnitude equal to the speed:

|v| = √((6 m/s)²) = 6 m/s

So the speed of the car is 6 m/s.

Next, we can find the direction of the velocity vector at point B. We know that the car is moving around a circle centered at the origin, and that point B is on the circle. Therefore, the velocity vector at point B is tangent to the circle and perpendicular to the line connecting the origin to point B.

The line connecting the origin to point B is given by:

y = (0 - 3)/(0 - (-3)) * (x - (-3)) + 0

y = -x + 3

The velocity vector at point B is therefore perpendicular to this line, which means it has a direction given by the vector (1, -1).

Finally, we can find the acceleration vector at point B. Since the car is moving with constant speed around a circle, it is undergoing uniform circular motion, which means it is accelerating towards the center of the circle. The magnitude of the acceleration is given by:

a = v² / r

where v is the speed and r is the radius of the circle. We don't know the radius of the circle, but we can find it using the fact that point B lies on the circle. The distance from the origin to point B is:

d = √((-3 - 0)² + (0 - 3)²) = 3√(2) m

Therefore, the radius of the circle is:

r = d / 2 = (3√(2)) / 2 m

Substituting in the values for v and r, we get:

a = (6 m/s)² / ((3√(2)) / 2 m) ≈ 16.97 m/s²

To find the direction of the acceleration vector, we can use the fact that it is pointing towards the center of the circle. The center of the circle is at the origin, so the acceleration vector at point B is given by the vector (-3, 0) minus the vector (0, 3), which is:

(-3, 0) - (0, 3) = (-3, -3)

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Hello..!

We initially apply the data to the problem.

Data:

Then, we apply the formula that is.

Formula:

Finally we develop the problem.

Developing:

Therefore the correct option is 25.3 kilometers per hour.

Answer:

Formula

Resolve

Hope this helped

Answer:

a

Explanation:

The final velocity of a truck is 74.0 ft/s, if it accelerates at a range of 3.00 ft/\(s^2\) from an initial velocity of 5.00 ft/s, then it will take the truck 23.67 seconds to attain its final velocity of 74.0 ft/s.

v = u + at

Here, v =the final velocity, u =the initial velocity, a =the acceleration, and t =the time taken.

Substituting the given values, one can get,

74.0 ft/s = 5.00 ft/s + 3.00 ft/\(s^2\) × t

Solving for t, one gets,

t = (74.0 ft/s - 5.00 ft/s) / (3.00 ft/\(s^2\)) = 23.67 s (that is  23.67 seconds is needed to attain final velocity of 74.0 ft/s)

Hence, a truck needs 23.67 seconds time to attain its final velocity of 74.0 ft/s and this is the final velocity.

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Answer:

Explanation:

m1*v1 = m2 v2

1200kgm/s=600kg*v1=(7+600)*v2

6000=607*v

v2=9.8m/s