a mass m1 on an incline is attached by a massless string to a second mass m2 hanging from a pulley as shown. the incline has a rough surface so there is a frictional force of magnitude ffric on mass m1. mass m1 is observed to be sliding down the incline at constant speed v. how does the magnitude of the tension ft in the string pulling on m1 compare to the magnitude of the force of friction ffric acting on the mass m1? neglect any air resistance

Answer:

0.0334N

Explanation:

Given parameters:

M1  = 5 x 10⁶kg

M2  = 1 x 10⁶kg

Distance  = 100m

Unknown:

Gravitational force  = ?

Solution:

To solve this problem, we use the Newton's law of universal gravitation.

     Fg  = \(\frac{G m1 m2}{r^{2} }\)  

G is the universal gravitation constant

m is the mass

r is the distance

         Fg  = \(\frac{6.67 x 10^{-11} x 5 x 10^{6} x 1 x 10^{6} }{100^{2} }\)   = 0.0334N

The reason why materials become liquids at higher temperatures can be explained in terms of Gibbs free energy.

At higher temperatures, the entropy or disorder of the material increases, which leads to a decrease in Gibbs free energy. In other words, the system becomes more energetically favorable in the liquid state than in the solid state, resulting in a phase transition from solid to liquid. This is due to the fact that in the liquid state, the molecules have more freedom of movement and can occupy a greater number of microstates, which leads to an increase in entropy and a decrease in Gibbs free energy. Therefore, as the temperature increases, the Gibbs free energy of the liquid state becomes lower than that of the solid state, resulting in a phase transition from solid to liquid.

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From the calculation, there is a net force that acts on the car and then the acceleration that is produced by the net force is 0.296 m/s^2.

The term net force refers to the force that is acting on an object that makes it to move. We have to recall that the force of friction is the force the limits the motion of an object. In other words, it is the force of friction that makes a body not to be able to move and this must be overcome by the forward force when it is greater than the friction force.

Now;

Mass of the car = 1352 kg

Forward force = 7820 N

Coefficient of friction = 0.56

Frictional force = μmg

= 0.56 * 1352 kg * 9.8 m/s^2

= 7419.8 N

Net force = Forward force - Frictional force

= 7820 N -  7419.8 N

= 400.2 N

Then;

Net force = ma

m = mass

a = acceleration

a = Net force/m

a = 400.2 N/ 1352 kg

a = 0.296 m/s^2

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Answer:

Approximately \(9.3\; {\rm m\cdot s^{-1}}\).

Explanation:

Apply unit conversion:

\(t = 45\; {\rm ms} = 45 \times 10^{-3}\; {\rm s}\).

At a velocity of \(v\), the momentum \(p\) of an object of mass \(m\) would be \(p = m\, v\).

Initial momentum of this ball:

\(\begin{aligned}p_{0} &= m\, v_{0} \\ &= 0.060\; {\rm kg} \times (-32\; {\rm m\cdot s^{-1}}) \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}\).

When a constant force \(F\) is exerted on an object for a duration of length \(t\), the impulse \(J\) applied to that object would be \(J = F\, t\).

Impulse that the ground applied to this ball:

\(\begin{aligned}J &= F\, t \\ &= 55\; {\rm N} \times (45 \times 10^{-3}\; {\rm s}) \\ &= 2.475\; {\rm N \cdot s}\end{aligned}\).

Note that \(1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}}\). Thus, the impulse applied to this ball would be equivalent to:

\(\begin{aligned}J &= 2.475\; {\rm (kg \cdot m \cdot s^{-2}) \cdot s} \\ &= 2.475\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

After this impulse was applied, the momentum of this ball would become:

\(\begin{aligned}p_{1} &= p_{0} + J \\ &= (-1.92\; {\rm kg \cdot m \cdot s^{-1}}) + 2.475\; {\rm kg \cdot m \cdot s^{-1}} \\ &= 0.555\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

The new velocity of this ball would be:

\(\begin{aligned}v_{1} &= \frac{p_{1}}{m} \\ &= \frac{0.555\; {\rm kg \cdot m \cdot s^{-1}}}{0.060\; {\rm kg}} \\ &\approx 9.3\; {\rm m\cdot s^{-1}}\end{aligned}\).

Answer:

(A)

Explanation:

I took the test

It requires 0.375j of work to stretch the spring an additional 5 cm beyond its natural length.

To stretch the spring 10 cm beyond its natural length requires 15j of work. To stretch it an additional 5 cm requires additional work.

We can use the formula for work done on a spring:

Work = 0.5kx²

Where k is the spring constant and x is the distance the spring is stretched or compressed from its natural length.

Since we know that 15j of work is required to stretch the spring 10 cm, we can solve for k:

15j = 0.5k(0.1m)²

k = 300 N/m

Now we can use this value of k to find the work required to stretch the spring an additional 5 cm:

Work = 0.5(300 N/m)(0.05m)²

Work = 0.375j

It requires 0.375j of work to stretch the spring an additional 5 cm beyond its natural length.

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Answer:

\(Amount\ of\ wire\ used=\frac{M}{44.5\ g/km}\)

mount of wire used=12.808989 Km

Amount of wire used=12808.989 m

Explanation:

Given Data:

Diameter of wire=d=0.080 mm=0.00008 m

Weight of wire per unit length=44.5 g/km

Spool weighs=M=570 g

Required:

Amount of wire used=L=?

Solution:

Formula is:

\(Amount\ of\ wire\ used=\frac{Spool\ weighs}{Weight\ per\ unit\ length}\)

\(Amount\ of\ wire\ used=\frac{M}{44.5\ g/km}\)

The above expression is mathematical model of finding how much wire is used. just put the Value of M we will get the answer.

\(Amount\ of\ wire\ used=\frac{570\ g}{44.5\ g/km}\)

Amount of wire used=12.808989 Km

Amount of wire used=12808.989 m

Answer:

1250 J

Explanation:

W = Fs

W = 500 * 2.5 = 1250 J

From the knowledge of linear momentum,

a.) momentum is conserved

b.) \(V_{1}\) = -1.075 m/s

c.) Same change of momentum.

We have different type of collision.

The parameters given in the question are:

a.) The reason this is considered as an isolated system of colliding bodies is because there is no loss of energy and momentum.

b.) To calculate the velocity of the cart A, let us use the formula below.

\(M_{1}\)\(U_{1}\) - \(M_{2}\)\(U_{2}\) = \(M_{1}\)\(V_{1}\) - \(M_{2}\)\(V_{2}\) ( since they are opposite to each other)

substitute all the parameters into the equation

0.2 x 1.2 - 0.35 x 2 = 0.2 x \(V_{1}\) - 0.35 x 0.7

0.24 - 0.7 = 0.2\(V_{1}\) - 0.245

-0.46 = 0.2\(V_{1}\) - 0.245

0.2\(V_{1}\) = -0.46 + 0.245

0.2\(V_{1}\) = -0.215

\(V_{1}\) = -0.215/0.2

\(V_{1}\) = - 1.075 m/s

c.) Change in momentum of cart A = - 0.2 x 1.075 - 0.2 x 1.2

= -0.215 - 0.24

= -0.455 Kgm/s

Change in momentum of cart B = -0.245 + 0.7

= 0.455 Kgm/s

Therefore, they both have the same change of momentum but in opposite direction.

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c) Superior and inferior portions.

The body's upper (superior) or lower (inferior) halves are separated by the transverse plane, also known as the axial plane.This plane is where rotational or horizontal movements take place, such as:Rotation: turning the torso or even a limb about its axis of rotation.

Transverse plane: A horizontal slit that divides the specimen's top and bottom.additionally called a cross-sectional plane.The left and right halves of the specimen are divided by a vertical cut made along the specimen's exact center line, or midsagittal plane.

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The required temperature in kelvin scale when the temperature in Fahrenheit is calculated to be 421 K.

The Fahrenheit conversion to celsius is determined through the formula is (°F  - 32)  × 5/9 = °C. Hence, we substitute 77 °F where the equivalent temperature in celsius is 25 °C. The temperature in centigrade is multiplied by 273 to get the kelvin equivalent.

The given temperature in Fahrenheit is 298 °F. It is to be converted into kelvin temperature.

So, (°F  - 32)  × 5/9 = °C

(298 - 32) × 5/9 = 147.78 × 5/9 = 147.78 °C

To convert from °C to K, we need to add 273 to celsius temperature.

147.78 °C + 273 = 421 K

Thus, the required temperature in kelvin scale is calculated to be 421 K.

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Abby volunteers at the planetarium at the museum of natural history. she is putting together a presentation about the solar system in which she will describe the shape of the solar system. she uses the term orbital plane when she discusses the plane in which the planets orbit.

The space that connects the centers of the orbiting objects and the object being orbited is known as an orbital plane and is formed like a flat, disk. Planets in our solar system avoid colliding with one another because their orbital planes are similar.

A rotating body's orbit is located in a geometric plane called the orbital plane. An orbital plane can be identified using just three non-collinear points in space. The locations of the centers of an orbiting celestial body and a large body (the host) at two different times or points in its orbit are typical examples.

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Answer:

Waves come in two kinds, longitudinal and transverse

Explanation:

hope it helps hehe

My day is alright! I just finished school for the day.. and I’m excited for the weekend! How was your day?

A. The estimated maximum kinetic energy of the chamber with a 200 gram rock is approximately 0.00196 Joules. B. the estimated maximum acceleration of the chamber with a 200 gram rock is approximately 1.131 m/s².

C. The representation of the motion for a 200 gram rock as a function of time is x(t) = 0.1 × cos(2π × 0.30 Hz × t). D. It does not seem like a lot of force inside the rover.

To evaluate the design and determine if the device can damage the housing, go through the required steps:

a. The maximum kinetic energy of the chamber can be calculated using the formula:

K_max = (1/2) × m × v²

where K_max is the maximum kinetic energy, m is the mass of the rock, and v is the velocity of the rock.

Given:

Mass of the rock (m) = 200 grams = 0.2 kg

Velocity of the rock (v) = 14 cm/s = 0.14 m/s

Using the formula, we can calculate:

K_max = (1/2) × 0.2 kg × (0.14 m/s)²

K_max ≈ 0.00196 Joules

Therefore, the estimated maximum kinetic energy of the chamber with a 200 gram rock is approximately 0.00196 Joules.

b. The maximum acceleration of the chamber can be determined using the formula:

a_max = ω² × A

where a_max is the maximum acceleration, ω is the angular frequency, and A is the amplitude of the oscillation.

Given:

Angular frequency (ω) = 2π × frequency

Frequency = 0.30 Hz

Using the formula, we have:

ω = 2π × 0.30 Hz

Now, let's assume the amplitude of the oscillation is A = 0.1 meters.

a_max = (2π × 0.30 Hz)² × 0.1 meters

a_max ≈ 1.131 m/s²

Therefore, the estimated maximum acceleration of the chamber with a 200 gram rock is approximately 1.131 m/s².

c. The motion of the rock in simple harmonic motion can be described by the equation:

x(t) = A × cos(ω × t)

where x(t) represents the displacement of the rock at time t, A is the amplitude, ω is the angular frequency.

Using the values from earlier:

Amplitude (A) = 0.1 meters

Angular frequency (ω) = 2π × 0.30 Hz

The representation of the motion for a 200 gram rock as a function of time is:

x(t) = 0.1 × cos(2π × 0.30 Hz × t)

d. Based on the given information, the maximum kinetic energy of the chamber with a 200 gram rock is approximately 0.00196 Joules. This is a relatively small amount of energy.

The maximum acceleration of the chamber with a 200 gram rock is approximately 1.131 m/s². This acceleration is also relatively small.

Considering these values, it does not seem like a lot of force inside the rover. The energy and acceleration involved are relatively low, suggesting that the device should not cause significant damage to the housing. However, it is always essential to ensure that the design and materials used in the housing can withstand the expected forces and vibrations to ensure the rover's durability and functionality.

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Answer:

Explanation:

A concave mirror is a curved mirror that is coated outwards. The outer part of the mirror is always coated. The nature of image formed by an object placed in front of a concave mirror can be real or virtual depending on the distance of the object on the axis from the mirror. The only time the object produces a virtual image is when it is placed between the focus and the pole of the mirror. The virtual image formed is a "MAGNIFIED and upright image"

For a convex mirror, the inner part is always coated and the nature of the image formed by the object doesn't depend on the distance between the image and the mirror. No matter where the object is placed, the image formed will always be virtual, upright and DIMINISHED. This means that magnification is always less than 1.

For a plane mirror, the nature of the image produced by a plane mirror also virtual because it is always formed behind the mirror. The size of the image formed is always THE SAME as that of the object. This means that the magnification is always equal to 1.

a) In summary, the difference between virtual images produced by concave, plane, and convex mirrors is that virtual images produced by concave mirror are MAGNIFIED, virtual images produced by plane mirror are THE SAME SIZE as that of the object and virtual images produced by convex mirrors are always DIMINISHED.

b) Magnification is defined as the ratio of the image distance to the object distance. Mag = v/u

Note that object distances are always positive, hence it is only the image distance that can either be positive or negative which in turn affects the magnification causing it to be positive or negative.

Negative image distance shows that the image is virtual while positive image distance shows that the image is real.

A negative magnification therefore shows that the nature of the image is a virtual image.

According to Wien's Law, the wavelength at which Uranus's thermal emission peaks can be calculated using the formula λ(max) = b/T, where b is Wien's constant (2.898 x 10^-3 m K), and T is Uranus's temperature (approximately 59 K).

Plugging in the values, we get:

λ(max) = (2.898 x 10^-3 m K) / (59 K)
λ(max) = 4.91 x 10^-5 meters

Therefore, Uranus's thermal emission peaks at a wavelength of approximately 4.91 x 10^-5 meters or 49.1 micrometers.

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gas to liquid is the answer

Answer:

C. gas to liquid

Explanation:

ed. 2021

According to the question he range of the particle's motion is therefore 30 - 8 = 22.

Particle is a small unit of matter that behaves according to the laws of quantum mechanics. Particles are the building blocks of the universe, making up all matter, energy, and forces. Particles come in many forms and can have varying properties, such as mass, charge, and spin. In the Standard Model of particle physics, the smallest particles are quarks and leptons, which make up protons, neutrons, and electrons. They interact with each other by exchanging force-carrying particles called bosons.

The particle has a kinetic energy of 4.19 J at the point where the potential energy U forms a curved "hill", with UB = 13 J. This means that the particle's velocity is 0 at this point. Therefore, the particle will turn around at this point.
The particle will turn around at the left side when UA = 8 J and the particle will turn around at the right side when UD = 30 J.
The range of the particle's motion is therefore 30 - 8 = 22.

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Explanation:

If Earth did not rotate or revolve, there would be no day or night, and no seasons. The lack of tilt would result in a constant and uniform distribution of sunlight, leading to a lack of temperature variation and climatic zones.

It's possible that life could still exist in such conditions, but it would likely be limited to areas with constant access to sunlight and warm temperatures. The absence of climatic zones would also lead to a lack of diversity in species, as many would not be able to adapt to the uniform conditions.

It's not possible to say where one would want to live in such conditions, as the lack of variation would make the entire planet similar in terms of climate and habitat.

Eating less red meat so fewer cattle need to be raised would help reduce global warming.

The production of red meat, particularly beef, is a major contributor to greenhouse gas emissions. Cattle produce methane, a potent greenhouse gas, and the production of feed for cattle also requires large amounts of energy, water and land. Additionally, the clearing of forests for grazing land and feed production also contributes to carbon emissions.

Riding a bicycle rather than walking to school would also help reduce global warming because it would decrease the amount of CO2 emissions produced by cars and other vehicles.

Clearing more forests to produce more farmland and using more fertilizers to increase crop production would not help to reduce global warming, as the clearing of forests causes a release of stored carbon into the atmosphere and the use of fertilizers and pesticides also has an environmental impact.

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The Dependent and independent variables are two important variables in an experiment. Test score is the dependent variable while listening to music is the independent variable.

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Answer:

3) Act on different objects

Explanation:

Newton's third law of motion states that for every action there is an equal and opposite reaction.

Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move, etc.

Basically, action-reaction force pairs are characterized by the following statements;

I. The forces are the same type such as magnetic force, contact force or gravitational force.

II. The forces are equal in magnitude but opposite in direction.

III. They act up on two different bodies.

Hence, the two forces that make up 3rd law of motion can act on different objects.

For example, while driving down the road, a bug strikes the windshield of a vehicle (Action) and makes a quite obvious mess in front of the face of the driver of the vehicle (Reaction) i.e the bug hit the vehicle and the vehicle hits the bug.

Therefore, the maximum distance that the landing ramp can be placed from the takeoff ramp so that the cyclist still lands on it is 75.5 m. Hence, option C is correct.

We have to find the maximum distance that the landing ramp can be placed from the takeoff ramp so that the cyclist still lands on it, given that a motorcycle daredevil is attempting to jump from one ramp onto another. The takeoff ramp makes an angle of 18.00 above the horizontal, and the landing ramp is identical. The cyclist leaves the ramp with a speed of 33.5 m/s.

Let's begin with the solution:

Consider the diagram shown below:

Here, AB = Take off ramp, BC = Landing rampθ = 18.0°, Speed of the cyclist, u = 33.5 m/s

It is given that the landing ramp is identical to the takeoff ramp.

So, the angle between the ramp and horizontal is also θ = 18.0°.

The vertical and horizontal components of velocity at point A are given by:

v_y = u sin θ and v_x = u cos θ

The time of flight of the cyclist from A to C is given by:

t = [2v_y] / g Where g is the acceleration due to gravity= 9.81 m/s²

The horizontal distance covered by the cyclist in the time of flight is given by:

x = v_x t …..(1)

The height of the landing ramp (point C) from the ground is given by:

y = BC sin θ …..(2)

The cyclist has to land on the landing ramp (point C).

Therefore, the height of the landing ramp must be equal to the height at which the cyclist leaves the takeoff ramp (point A).

Therefore, from the diagram shown above, we have:

y = AB sin θ …..(3)

From (2) and (3), we have:

AB sin θ = BC sin θ

Or

AB = BC ... (identical ramps)

From equation (1),

we have:

x = v_x

t= u cos θ [2v_y / g]... (4)

Substituting the values of u, θ, v_y and g,

we get:

x = [33.5 m/s] cos 18.0° [2 (33.5 sin 18.0°) / 9.81 m/s²]= 75.5 m (approximately)

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Answer:

As the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

Explanation:

Ohm's law states that the current flowing through a circuit is directly proportional to the applied voltage.

V = IR

where;

I is the current

R is the resistance

V is the applied voltage

Based on this law (Ohm's law), as the voltage increases, the current flowing through the circuit increases while the resistance of the resistor remains constant.

Athletes are asked to immediately squat to a depth of their choosing and then jump as high as they can in the Countermovement Jump (CMJ), a vertical jump test.

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Answer:

There cannot be a force without motion and if there is no motion, then there is no force acting.

Explanation:

A force is a vector that causes an object with mass to accelerate.

Answer:

because force need motion

Explanation:

Answer:

Explanation:

Gravitational force = normal force which are both the same thing as the weight of the object which is found in w = mg. Therefore,

w = 10(9.8) = 98 N.

If the object is being pulled at a constant velocity, then the acceleration of said object is 0. Thus,

F - f = ma and

F - f = 0 so

F = f.  So we just need to solve for f, which is found in the equation

f = μ\(F_n\) so

f = .2(98) and

f = 19.6 = F

The net force is 0 if F = f

To operate from a 160-volt line with 100% efficiency, the ratio of secondary to primary turns of the transformer must be 1:1. If the input voltage is 160 volts, the output voltage will also be 160 volts.

This means that the number of turns in the secondary winding should be the same as the number of turns in the primary winding. This is because the voltage in the secondary winding will be equal to the voltage in the primary winding, assuming no losses in the transformer.

We can use the transformer equation to calculate the ratio of secondary to primary turns of the transformer:

\(V_p / V_s = N_p / N_s\)

where Vp is the primary voltage, Vs is the secondary voltage, Np is the number of primary turns, and Ns is the number of secondary turns.

We are given that the primary voltage is 160 V and that the transformer is 100% efficient, which means that the power output equals the power input.

Therefore, if the input voltage is 160 volts, the output voltage will also be 160 volts.

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Answer: See Explanation

Explanation:

Did the car travel at a constant speed?

This means "Is the speed at each interval the same?"

There are 10 intervals for which to calculate from.

For each one, the speed is the distance traveled divided by the time.

Each interval is 1 meter long (distance).

1st: 1 meter / 2.00 s = 0.5 m/s

2nd: 1 meter / (4.00 - 2.00) s = 0.5 m/s

3rd: 1 meter / (6.2 - 4.0) s = 0.454 m/s

Right here you can see that the speed is different, NO is the answer.

Average Speed = total distance divided by total time

v = d / t     v = (10 m) / (20:00 s) = 0.5 (m/s)

Describe the overall motion: (continue on with step one to see the total motion over the 10 meters)

4th: 0.552

5th: 0.472

6th: 0.5

7th: 0.5

8th: 0.4975

9th: 5.39

10th: 0.55

Overall motion stayed steady from 0-2 meters, slowed for the 3rd meter, sped up for the 4th, slowed down the 5th, stayed steady until slowing down in the 8th meter, then increased speed til the 10th meter.

Races would be practical applications to see where people/cars pace themselves, push themselves, etc.