Given the following data:
Initial frequency = 0.83 Hz.
Additional mass = 780 grams to kg = 0.78 kg
New frequency = 0.60 Hz
To determine the value of the initial mass, m, we would apply the following formula:
;f=1/2л⟌k/m
Where:
F is the frequency.
m is the mass
k is the spring constant.
For mass (m):
0.83=1/2л⟌k/m ...equation 1.
For additional mass:
0.60=1/2⟌k/m+0.78 ...equation 2.
Next, we would divide eqn. 1 by eqn. 2:
;0.83/0.60=1/2л⟌((k/m)/1)/2л⟌m+0.78
1.3833=⟌k/m/⟌k/m+0.78
Taking the square of both sides, we have:
1.9135=k/m/k/m+0.78
1.9135=k/m×m+0.78/k
1.9135=m+0.78/m
1.9135m-m=0.78
0.9135m=0.78
m=0.78/0.9135
m=0.8538kg
the value of mass is 0.8538.
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What is the speed of a snail that travels 20 inches in 5 minutes?
if the kinetic energy of a particle is tripled, by what factor has its speed increased?
Answer:
KE1 = 1/2 m v1^2
KE2 = 3 KE1 = 3 * 1/2 m v1^2 = 1/2 m v2*2
3 v1^2 = v2*2
v2 = 3^1/2 v1
4 meters to the left 9 meters to the right 5 meters to the left and 3 meters to the right this all took 10 seconds and is the speed.
Suppose you discover a Type Ia supernova in a distant galaxy. At maximum brilliance, the supernova reaches an apparent magnitude of 10. How far away in the galaxy
Type Ia supernova is approximately 72.38 million parsecs away in the distant galaxy.
To determine the distance to a Type Ia supernova in a distant galaxy with an apparent magnitude of 10, we will use the distance modulus formula. The distance modulus formula relates the apparent magnitude (m), absolute magnitude (M), and distance (d) in parsecs. The formula is:
m - M = 5 * log10(d) - 5
For a Type Ia supernova, the absolute magnitude is roughly -19.3. Now, we have the values for m and M, and we can solve for d:
10 - (-19.3) = 5 * log10(d) - 5
Next, isolate log10(d):
29.3 = 5 * log10(d) - 5
34.3 = 5 * log10(d)
Now, divide by 5:
6.86 = log10(d)
To find d, raise 10 to the power of 6.86:
d = 10^6.86
Finally, calculate the distance:
d ≈ 72.38 million parsecs
So, the Type Ia supernova is approximately 72.38 million parsecs away in the distant galaxy.
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A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the acceleration.
Answer:
Acceleration (a) = 40 m/s²
Explanation:
Given:
Initial velocity (u) = 6 m/s
Final velocity (v) = 4.4 m/s
Time taken (t) = 0.04sec
Find:
Acceleration (a) = ?
Computation:
We know that,
⇒ v = u + at
⇒ a = (v - u) / t
⇒ Acceleration (a) = (4.4 - 6) / 0.04
⇒ Acceleration (a) = (-1.6) / 0.04
Acceleration (a) = 40 m/s²
The kinetic energy of a bullet fired from a gun is 40j. If the mass of the bullet is 0.1kg, calculate the initial speed of the bullet
Answer:
KE = 1/2 M V^2
V = (2 KE / M)^1/2 = (2 * 40 / .1)^1/2 = 28.3 m/s
Are stairs a type of inclined plane?
Answer:
Inclined planes are simple machines used to make work easier. Ramps, ladders, and staircases are all inclined planes.
Explanation:
Answer:
imma say yes
Explanation:
20 points !!! An infrared wave traveling at the speed of light has a wavelength of 2x10^-5 m. Calculate the frequency of this wave.
Answer:
f=1.5MHz or f=1500Hz
Explanation:
f=v/λ
3×10⁸/2×10-⁵
f=1500Hz
f=1.5MHz
A 55.0-kg person consumes a small order of french fries
(241.0 Cal)
and
wishes to
"work off"
the
energy by climbing a
11.0 m
stairway.
How many vertical climbs are needed to use all the
energy?
To use all the energy from consuming a small order of french fries, the person would need to climb the 11.0 m stairway approximately 17.0 times.
The energy content of the small order of french fries is given as 241.0 Cal. We can convert this value to joules since the unit of energy in the metric system is the joule (J). 1 calorie (Cal) is equal to 4.184 joules (J). To use all the energy from consuming a small order of french fries, the person would need to climb the 11.0 m stairway approximately 57 times.
Energy content of the small order of french fries:
241.0 Cal × 4.184 J/Cal = 1007.144 J
Work done to climb the stairway:
(55.0 kg) × (11.0 m) × (9.8 m/s²) = 59294 J
Number of climbs needed to use all the energy:
1007.144 J ÷ 59294 J ≈ 17.0
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what is CHA-CHA-CHA.
Answer:
The cha-cha-cha, is a dance of Cuban origin. It is danced to the music of the same name introduced by Cuban composer and violinist Enrique Jorrin in the early 1950s. This rhythm was developed from the danzón-mambo
which of the following nuclei is most stable based on its binding energy
A Manganese (mn - 55)
B Zinc (Zn - 64)
C Iodine (I - 127)
D Sodium (Na - 23) Help needed
SUBMIT
Answer:
managanes ( mn - 62 )zinc ( 1 25 )iodin 156desventajas de la fricción cinética
Answer:
Please translate this into Spanish! Sorry I can't :(
Explanation:
Disadvantages of Friction:
Friction produces unnecessary heat leading to the wastage of energy.
The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects.
Forest fires are caused due to the friction between tree branches.
why is light increasingly redshifted as the light source nears a black hole?
Light is increasingly redshifted as the light source nears a black hole due to the immense gravitational pull exerted by the black hole.
As light travels away from a black hole, it has to work against the black hole's strong gravitational pull.
This causes the light's wavelength to stretch or "redshift" as the gravitational force increases with proximity to the black hole.
The greater the redshift, the more the light has been stretched, indicating a stronger gravitational pull.
Summary: The light from a source near a black hole experiences increased redshift due to the powerful gravitational pull of the black hole, which stretches the light's wavelength.
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The accepted value for the free-fall acceleration on Earth's surface is 9.80665 m/s2
Which of the following measurements is the most accurate?
Answer:
The Answer is A 9.80860 m/s²
Explanation:
Two airplanes are flying in the sky in such a way that the gravitational attractions between them decreases. The planes must be flying.
The planes must be flying because of earths gravity when two airplanes are flying in the sky in such a way that the gravitational attractions between them decreases.
In mechanics, gravity—also known as gravitation—is the constant force of attraction that pulls all matter together. It has no impact on determining the internal characteristics of common matter because it is by far the weakest known force in nature.
All objects on Earth experience weight, or a gravitational pull that is proportional to their mass and is imposed by the planet's mass. The acceleration that gravity gives to objects falling freely serves as a gauge of its strength. The acceleration of gravity at Earth's surface is approximately 9.8 meters per second. As a result, during free fall, an object's speed increases by about 9.8 meters per second. A freely falling body accelerates to about 1.6 m/s2 at the Moon's surface.
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What are the units of each of the these
A)distance b)velocity c)displacement d)acceleration e)speed
Answer:
distance is mesured in meters
velocity is measured in m/s
dispacment is mesured in meters +the direction
acceleration is measured in m/s square
Answer:
The basic unit of distance is the centimeter (cm).
Velocity is defined as the rate of change of distance of the body with respect to time. Its unit in SI is m/s.
The SI unit for displacement is the meter (m).
Unit of acceleration is the meter per second per second (m/s2).
The SI unit of speed is the meter per second (mps)
Explanation:
Logic...
A squirrel jumps into the air with a velocity of 7 m/s at an angle of 20 degrees. What is the maximum height reached by the squirrel?
Answer:
.3m
Explanation:
Apex
0.3 is right i just got it right on the test for A P E X :D
What is a cars acceleration in the direction of motion when velocity changes from 20. M/s to 60. M/s in 10. S
Answer:
Acceleration, \(a=4\ m/s^2\)
Explanation:
Given that,
Initial velocity, u = 20 m/s
Final velocity, v = 60 m/s
Time, t = 10 s
We need to find the acceleration of the car. It is equal to the change in velocity divided by time.
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{60-20}{10}\\\\a=\dfrac{40}{10}\\\\a=4\ m/s^2\)
So, the acceleration of the car is \(4\ m/s^2\).
a child drops a ball from a window. the ball strikes the ground in 3.5 seconds. what is the velocity of the ball the instant before it hits the grod
The velocity of the ball just before it hits the ground can be calculated using the formula v = g * t, where v is the velocity, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time taken to reach the ground.
In this case, the time taken by the ball to strike the ground is given as 3.5 seconds. The acceleration due to gravity remains constant at 9.8 m/\(s^2\)throughout the motion of the ball. By substituting these values into the formula, we can calculate the velocity.
v = g * t
= 9.8 m/\(s^2\) * 3.5 s
= 34.3 m/s
So, the velocity of the ball just before it hits the ground is 34.3 meters per second.
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A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also calculate the temperature of the 6-cm- diameter cylinder
The net radiant energy lost by the 2-cm-diameter cylinder per meter of length is X Joules. The temperature of the 6-cm-diameter cylinder is Y °C.
To calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length, we need to consider the Stefan-Boltzmann law and the emissivities of both cylinders. The formula for net radiant heat transfer is given:
Q_net = ε1 * σ * A1 * (T1^4 - T2^4)
Where:
- Q_net is the net radiant energy lost per meter of length.
- ε1 is the emissivity of the 2-cm-diameter cylinder.
- σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/(m^2·K^4)).
- A1 is the surface area of the 2-cm-diameter cylinder.
- T1 is the temperature of the 2-cm-diameter cylinder.
- T2 is the temperature of the surroundings (27 °C).
To calculate the temperature of the 6-cm-diameter cylinder, we can use the formula for the net radiant energy exchanged between the two cylinders:
Q_net = ε1 * σ * A1 * (T1^4 - T2^4) = ε2 * σ * A2 * (T2^4 - T3^4)
Where:
- ε2 is the emissivity of the 6-cm-diameter cylinder.
- A2 is the surface area of the 6-cm-diameter cylinder.
- T3 is the temperature of the 6-cm-diameter cylinder.
By solving these equations simultaneously, we can find the values of Q_net and T3.
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A long cylinder having a diameter of 2 cm is maintained at 600 °C and has an emissivity of 0.4. Surrounding the cylinder is another long, thin-walled concentric cylinder having a diameter of 6 cm and an emissivity of 0.2 on both the inside and outside surfaces. The assembly is located in a large room having a temperature of 27 °C. Calculate the net radiant energy lost by the 2-cm-diameter cylinder per meter of length. Also, calculate the temperature of the 6-cm-diameter cylinder
how much force is needed to accelerate a 3kg skateboard at 5 m/s2
Answer:
15 N
Explanation:
3 kg x5 m/ s square
15( kg x m/s square)
NEED ANSWER FAST
A person pushes a 11.5KG lawn mower with an applied force of 70.0N along the 45.0-degree-handle. if the lawn mower moves at a constant velocity
Determine the net force on the mower:
Fnet=__N
Determine the horizontal component of applied force on the mower:
Fx=__N (round to 3 digits)
Determine the horizontal frictional force acting on the mower
Ff=__N (Round to 3 digits)
Calculate the applied force the person must exert on the mower for it to accelerate at a rate of 1.00m/s^2
F=__N (round to 3 digits)
Force is a vector quantity hence it can be resolved into a vertical and a horizontal components.
1) The horizontal component of the applied force is given by;
Fnet = F cos θ
Fnet = 70.0N × cos (45.0)
Fnet = 49.5 N
2) The horizontal component of the frictional force is;
F = -Ff + mgsinθ
F = applied force
Ff =mgsinθ - F
Ff = (11 × 10 × sin 45) - 49.5
Ff = 28.3 N
Horizontal component of Ff
28.3 N cos 45 = 19.9 N
3) The applied force is given by;
F = 11 Kg × 1.00m/s^2 = 11.0 N
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what complication is introduced in the excerpt? marco is unable to locate his friends in the busy park. the slide’s very long, uniformly charged cylinder have radius R and linear charge density λ.
a. Find the cylinder's electric field strength outside the cylinder, r≥R. Give your answer as a multiple of λϵ0.
Express your answer in terms of some or all of the variables R,r, and the constant II
b. Find the cylinder's electric field strength inside the cylinder, r≤R. Give your answer as a multiple of λϵ0.
Express your answer in terms of some or all of the variables R,r and the constant II
a. To find the electric field strength outside the cylinder, E = λ/(2πϵ0r), where r≥R. b. To find the electric field strength inside the cylinder, E = λr/(2πϵ0R^2), where r≤R.
the electric field strength inside and outside a charged cylinder can be determined using the formulas E = λr/2πϵ0R^2 and E = λ/2πϵ0r, respectively. The electric field strength outside the cylinder is proportional to the linear charge density and inversely proportional to the distance from the center of the cylinder. On the other hand, the electric field strength inside the cylinder is proportional to both the linear charge density and the distance from the center of the cylinder, the slide’s very long, uniformly charged cylinder have radius R and linear charge density λ. a. Find the cylinder's electric field strength outside the cylinder, r≥R. but inversely proportional to the square of the radius of the cylinder. These formulas can be used to solve problems involving charged cylinders and their electric fields.
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Two asteroids head straight for Earth from the same direction. Their speeds relative to Earth are 0.81c for asteroid 1 and 0.59 for asteroid 2.Find the speed of asteroid 1 relative to asteroid 2.Wouldn't it be v=.22?
Answer:No, the calculation you provided is incorrect. To find the relative speed of asteroid 1 with respect to asteroid 2, we need to use the relativistic velocity addition formula:
v = (v1 - v2) / (1 - v1*v2/c^2)
where v1 is the velocity of asteroid 1 relative to Earth, v2 is the velocity of asteroid 2 relative to Earth, and c is the speed of light.
Substituting the given values, we get:
v = (0.81c - 0.59c) / (1 - 0.81c * 0.59c / c^2)
v = 0.22c / (1 - 0.48)
v = 0.42c
Therefore, the speed of asteroid 1 relative to asteroid 2 is 0.42 times the speed of light (c).
Explanation:
PLEASE HELP! **
Two cars are initially separated by 150m but they will both move in the same direction. Car A has a constant velocity of 10m/s while car B (which starts behind car A) has a constant velocity of 12m/s. How long will it take for Car B to catch up to car A?
show your work.
1. Calculate voltage ab such that voltage across 2 Ohm resistor is 20 V. I, 6.0 a + V b 2012 I 10 I 20 2. A 42 resistor in series with a 7.96 mH inductor is connected across a 110 V 60 Hz source. Determine (a) the impedance, (b) input current, (c) the voltage across the resistor and the inductor, (d) draw phasor diagram showing the current and voltage.
The information provided is incomplete to calculate the voltage "ab" and answer the questions regarding the series circuit. Further details or equations are required to provide a precise response.
For the second part of the question, let's analyze the series circuit consisting of a 42 Ohm resistor and a 7.96 mH inductor connected to a 110V, 60 Hz source:
(a) The impedance of the circuit (Z) can be calculated using the formula Z = √(R^2 + (ωL)^2), where R is the resistance and ω is the angular frequency (2πf) of the source. Plugging in the values, Z = √((42^2) + ((2π * 60 * 7.96 * 10^(-3))^2)).
(b) The input current (I) can be determined using Ohm's Law: I = V/Z, where V is the source voltage and Z is the impedance.
(c) The voltage across the resistor (VR) can be calculated using Ohm's Law: VR = I * R. The voltage across the inductor (VL) can be determined by subtracting VR from the source voltage: VL = V - VR.
(d) The phasor diagram shows the relationship between the current and voltage in a circuit. It represents the magnitude and phase of the current and voltage. Drawing the phasor diagram would require knowledge of the phase relationship between the current and voltage in the circuit, which is not provided in the question.
Please provide additional information or equations to accurately answer the question.
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Dos resistencias de 30 y 20 Ω se conectan en seria a un generador que tiene una diferencia de potencial de 20 V entre sus bornes. a. Determina la resistencia equivalente de la asociación b. Dibuja el circuito y coloca un amperímetro que indique el valor de la intensidad de la corriente y unos voltímetros que muestren la diferencia de potencial entre los extremos de las resistencias ¿Qué valores muestran estos aparatos?
Answer:
V = 12V, V = 8V
Explanation:
a) In this series circuit the equivalent resistance is
Req - R1 + R2
Req = 30 + 20
Eeq = 50 Ω
b) see attached
c) the circuit current is
i = V / Req
i = 20/50
i = 0.4 A
voltages are>
V = 0.4 30
V = 12V
V = 0.4 20
V = 8V
Please help ASAP, studying for finals.
A racecar rounds a curve on the track at a constant speed of 180 mph. Is the car accelerating?
1)No, its mass is constant.
2)Yes, its mass is constant.
3) No, its speed is constant.
4)Yes, its speed is constant.
Answer:
3)No, it's speed is constant.
Aircraft carriers use catapults to launch jets from their deck. One such catapult accelerates a 18,900 kg aircraft from rest to 61 m/s in 3.3 s. What is the magnitude of the force (in N) required to do this?
Given that the mass of catapult, m = 18900 kg
The initial velocity is
\(v_o=\text{ 0 m/s}\)As the body is at rest initially.
The final speed is
\(v_f=\text{ 61 m/s}\)The time taken is t = 3.3 s
We have to find the force.
According to Newton's second law, the formula to calculate force is
\(\begin{gathered} F=\text{mass}\times acceleration \\ =m\times\frac{(v_f-v_o)}{t} \end{gathered}\)Substituting the values, the force will be
\(\begin{gathered} F=18900\times\frac{61-0}{3.3} \\ =349363.63\text{ N} \end{gathered}\)Thus, the force is 349363.63 N
Explain with reason that when sunlight is focused on a piece of paper with the help of a convex len the paper will burn.
Answer:
Convex lenses concentrates the light energy to one spot on the paper so that the heat energy accumulates on that one small spot of paper. ... As the heat increases, combustion will occur when the spot becomes too hot and the paper will burn.
Explanation:
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