if the two cities are 45 meters apart in reality, they would be represented as 5 centimeters apart on the map.
The given scale on the map is "cm to 5 m." This means that every centimeter on the map represents 5 meters in reality.
We are told that the two cities are 45 meters apart in reality. To find out how far apart they are on the map, we need to determine the equivalent distance in centimeters.
Since every centimeter on the map represents 5 meters, we can set up a proportion to find the distance on the map:
(cm on the map) / (5 m in reality) = (x cm on the map) / (45 m in reality)
By cross-multiplying and solving for x, we get:
x cm on the map = (cm on the map) * (45 m in reality) / (5 m in reality)
Simplifying the expression, we have:
x cm on the map = 9 * (cm on the map)
This means that every centimeter on the map represents 9 meters in reality.
Therefore, if the two cities are 45 meters apart in reality, they would be represented as 5 centimeters apart on the map.
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Which system has no solutions? x < 3 x < 1 x > 3 x > 1 x < 3 x > 1 x > 3 x < 1
The system of inequalities with no solution is x > 3 x < 1
How to determine the system with no solutions?The systems of inequalities are given as:
x < 3 x < 1
x > 3 x > 1
x < 3 x > 1
x > 3 x < 1
As a general rule, it is impossible for a variable to be greater than a higher number and less than a smaller number.
This means that if x is greater than 3, then it must be greater than 1
Hence, the system of inequalities with no solution is x > 3 x < 1
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Which fraction is equivalent to \(\frac{-2}{3}\)
Im not 100% sure but I THINK its 2/3.
Answer:
2/-3
Step-by-step explanation:
-2/3 = -0.66666667
2/-3 = 0.666666667
An explanation is required or else not brainliest.
Answer:
16 meters
Step-by-step explanation:
\( In\: \odot F, \: \overline {RS} \) is tangent to the circle at point R and FR is radius.
\( \therefore RF\perp RS\) (Tangent radius theorem)
\( \therefore m\angle FRS = 90\degree \)
So, \( \triangle FRS\) is right angled triangle and FS is its hypotenuse.
Let FR = FT = r
FS = FT + ST = r + 9
Now, by Pythagoras theorem:
\(FR^2 + RS^2 = FS^2 \\ \therefore r^2 + (15)^2 = (r + 9)^2 \\ \therefore \cancel{ r^2} +225 = \cancel{ r^2} + 18r + 81\\ \therefore \: 225 = 18r + 81 \\ \therefore \: 225 - 81= 18r \\ \therefore \: 144= 18r \\ \therefore \: r = \frac{144}{18} \\ \therefore \: r =8 \: m\\ \implies \: d = 2r = 2(8) = 16 \: m\)
Thus, the diameter of the fountain is 16 meters.
A parabola can be drawn given a focus of (-5, -1) and a directrix of y=7. Write the equation of the parabola in any form.
A parabola with focus of (-5, -1) and a directrix of y=7 has the equation of the parabola as: (x + 5)² = 8 (y - 3)
How to write the equation of parabola with directrix of y = 7 and focus of (-5, -1)Quadratic equation = parabolic equation, when the directrix is at y direction is of the form:
(x - h)² = 4P (y - k)
OR
standard vertex form, y = a(x - h)² + k where a = 1/4p
The focus
F (h, k + p) = (-5,-1)
h = -5
k + p = -1
P in this problem, is the midpoint between the focus and the directrix
P = (-1 - 7) / 2 = -4
p = -4
the vertex
v(h, k)
h = -5
k + p = -1, k = 3
v(h, k) = v(-5, 3)
substitution of the values into the equation gives
(x - h)² = 4P (y - k)
(x - -5)² = 4 * 2 (y - 3)
(x + 5)² = 8 (y - 3)
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600 points here
2x+3=5x+9=3x+2=205x+5= what
The system of equations does not have a solution that satisfies all three equations simultaneously.
To solve this problem, we need to isolate the variable "x" in each equation, and then find the value of "x" that satisfies all three equations simultaneously.
Let's start with the first equation:
2x + 3 = 5x + 9
Subtracting 2x from both sides, we get:
3 = 3x + 9
Subtracting 9 from both sides, we get:
-6 = 3x
Dividing both sides by 3, we get:
-2 = x
So the solution to the first equation is x = -2.
Next, let's move on to the second equation:
3x + 2 = 20
Subtracting 2 from both sides, we get:
3x = 18
Dividing both sides by 3, we get:
x = 6
So the solution to the second equation is x = 6.
Finally, let's look at the third equation:
5x + 5 = ?
This equation cannot be solved because there is no value of "x" that will make it true. However, we can use the solutions we found from the first two equations to check if a value of "x" makes the equation true.
If we plug in x = -2, we get:
5(-2) + 5 = -5
This does not satisfy the equation.
If we plug in x = 6, we get:
5(6) + 5 = 35
This also does not satisfy the equation.
Therefore, the system of equations does not have a solution that satisfies all three equations simultaneously.
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The complete question is :
Isolate the variable "x" in each equation, and then find the value of "x" that satisfies all three equations simultaneously then Find the value of "x" that satisfies all three equations simultaneously .
2x+3=5x+9=3x+2=205x+5= ?
use the graphing tool to solve the system
Answer:
where is full question ?
Can someone help me it would be appreciated
Answer:
X^6 is the GCF
Step-by-step explanation:
Because what x^6 is will be more than x^4
Consider the following public good provision game. Players can choose either to contribute (C) or not contribute (NC) to the public good. If someone contributes, both will be able to consume the good, which worths v dollars and is publicly known. The player i's cost to contribute is Cᵢ, which is private information. It is common knowledge that C₁,C₂ are drawn from a uniform distribution with support (Cₗ, Cₕ]. Assume v > Cₕ. C NC
C ᴠ - C₁ . ᴠ - C₂ ᴠ - C₁, ᴠ
(a) Suppose player 2 contributes if C₂ < C*₂, where C*₂ is a cutoff point. What is the expected payoff for player 1 to contribute and not contribute? What would player 1 do when C₁ is low? (b) Suppose player 1 also employ a cutoff strategy. Solve for the cutoff point (C*₁, C*₂). What is the Bayesian Nash equilibrium of the game?
In the given public good provision game, player 1's expected payoff for contributing and not contributing depends on player 2's cutoff point (C*₂). When player 1 contributes, their payoff is v - C₁ if C₁ < C*₂, and 0 if C₁ ≥ C*₂. When player 1 does not contribute, their payoff is always 0.
How does player 1's expected payoff vary based on player 2's cutoff point (C*₂)?In this public good provision game, player 1's decision to contribute or not contribute depends on their private cost, C₁, and player 2's cutoff point, C*₂. If player 1 contributes, they incur a cost of C₁ but gain access to the public good valued at v dollars. However, if C₁ is greater than or equal to C*₂, player 1's expected payoff for contributing would be 0 since player 2 would not contribute.
On the other hand, if player 1 does not contribute, their expected payoff is always 0, as they neither incur any cost nor receive any benefit from the public good. Therefore, player 1's expected payoff for not contributing is constant, irrespective of the cutoff point.
To determine player 1's expected payoff for contributing, we consider the case when C₁ is less than C*₂. In this scenario, player 2 contributes to the public good, allowing both players to consume it. Player 1's payoff would then be v - C₁, which represents the value of the public good minus their cost of contribution. However, if C₁ is greater than or equal to C*₂, player 1's contribution would be futile, as player 2 would not contribute. In this case, player 1's expected payoff for contributing would be 0, as they would not gain access to the public good.
In summary, player 1's expected payoff for contributing is v - C₁ if C₁ < C*₂, and 0 if C₁ ≥ C*₂. On the other hand, player 1's expected payoff for not contributing is always 0. Therefore, when C₁ is low, player 1 would prefer to contribute, as long as the cost of contribution is less than player 2's cutoff point.
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Write without negative exponents: (3xy^−3)^−2
The expression \((3xy^{-3})^{-2}\) without negative exponents is \(\frac{y^6}{9x^2}\).
What are some rules of exponents?Some common rules of exponents are
xᵃ×xᵇ = xᵃ⁺ᵇ.
xᵃ/xᵇ = xᵃ⁻ᵇ.
Addition and subtraction of exponents are only possible for the same base value and when the base is different and both have the same exponent we just multiply the bases and write the exponent.
Given, An expression in exponents \((3xy^{-3})^{-2}\).
Now, Changing the place of exponents from the numerator to the denominator or vice versa changes its sign.
Therefore, \((3xy^{-3})^{-2} = 3^{-2}x^{-2}y^{6}\).
\(3^{-2}x^{-2}y^{6} = \frac{y^6}{3^2x^2}\).
\(\frac{y^6}{3^2x^2} = \frac{y^6}{9x^2}\).
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y= 2/ x² + x² /2 Find the value of y when x = 6. Give your answer as a mixed number in its simplest form.
Can someone plz help me with this one problem plsss ??!!
Answer: 147.2
Step-by-step explanation:
Ok, so- ! Perimeter is basically each side added up, or, in this situation, times four :). They already gave you the total, so all you need to do is divide 36.8 by four, leaving you with 9.2 ! Hope this helped :)
Anyone Need Help Urgent
Given a cylindrical tank, in which situation will you find surface area and in which situation volume.
a)To find how much it can hold.
b)Number of cement bags required to plaster it
c)To find the number of smaller tanks that can be filled with water from it ? .....I will mark as BRAINLIEST.... Thank you!
Answer:
c
Step-by-step explanation:
what is the answer to 6x+18+8x=180?
Answer:
=81/7
Step-by-step explanation:
Simplifying
6X + 18 + 8x + -2 = 180
Reorder the terms:
18 + -2 + 6X + 8x = 180
Combine like terms: 18 + -2 = 16
16 + 6X + 8x = 180
Solving
16 + 6X + 8x = 180
Solving for variable 'X'.
Move all terms containing X to the left, all other terms to the right.
Add '-16' to each side of the equation.
16 + 6X + -16 + 8x = 180 + -16
Reorder the terms:
16 + -16 + 6X + 8x = 180 + -16
Combine like terms: 16 + -16 = 0
0 + 6X + 8x = 180 + -16
6X + 8x = 180 + -16
Combine like terms: 180 + -16 = 164
6X + 8x = 164
Add '-8x' to each side of the equation.
6X + 8x + -8x = 164 + -8x
Combine like terms: 8x + -8x = 0
6X + 0 = 164 + -8x
6X = 164 + -8x
Divide each side by '6'.
X = 27.33333333 + -1.333333333x
Simplifying
X = 27.33333333 + -1.333333333x
What is it? Could someone draw these coordinates
The coordinates are simple. Hope you understand this and you can draw it out.
A special deck of cards has 10 red cards, 20 blue cards, and 40 green cards. If Tay randomly draws a card, what is the probability that it will be green?
find a vector equation of the line tangent to the graph of r(t) at the point p0 on the curve r(t)= (3t - 1) i + 13t j + 16 k; P0(-1, 4)
Vector equation of the line tangent to the graph of r(t) at the point p0 on the curve r(t) = (3t - 1) i + 13t j + 4 k.
What is the vector equation at the point P0(-1, 4)?To find a vector equation of the line tangent to the graph of r(t) at the point P0 on the curve r(t) = (3t - 1) i + 13t j + 16 k, where P0 is given as (-1,4), we can use the following steps:
Step 1: Find the derivative of r(t) with respect to t:
r'(t) = 3 i + 13 j
Step 2: Evaluate the derivative at the point P0:
r'(-1) = 3 i + 13 j
Step 3: Use the point P0 and the vector r'(-1) to form the vector equation of the tangent line:
r(t) = P0 + r'(-1) t
where t is a scalar parameter.
Plugging in the values, we get:
r(t) = (-1)i + 4j + (3i + 13j)t
Simplifying, we get:
r(t) = (3t - 1) i + 13t j + 4 k
Therefore, the vector equation of the line tangent to the graph of r(t) at the point P0 on the curve
r(t) = (3t - 1) i + 13t j + 16 k is
r(t) = (3t - 1) i + 13t j + 4 k.
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What is 4/5 divided by 3/4 ?
8
26
32
19
27
B Bug 4 4
33
This list shows the number of years that 99 U.S. Supreme Court Justices served.
0 4 6 8
15
18
22
31
1 4. 6 9 13 15 19 23 26
1 4 6 9 14
16
23
33
2 5 7 9 14 16 20 23 28
5 7 10 14 16 20
23
28 33
2 5 7 10 14 16 20 23 28 34
3 5 7. 10 15 17 20 24 29 34
3 5 8 11 15 17 20 24 30 34
3 5 8 13 15
21 26 30 36
4 5 8
13
15 18 21 26 31
N N
Ол олол олол
www
co
18
u un
بی بی
ол ол
a.
What number of years is the mode the Supreme Court justices served?
20
23
b
d. 5
C.
ܢܕ ܗ
15
07
The mode of a dataset is the data element with the highest frequency
The number of years that represents the mode of the Supreme Court justices served is 5
How to determine the modeThe dataset is given as:
0 4 6 8 13 15 18 22 26 31 1 4 6 9 13 15 19 23 26 32 1 4 6 9 14 16 19 23 27 33 2 5 7 9 14 16 20 23 28 33 2 5 7 10 14 16 20 23 28 33 2 5 7 10 14 16 20 23 28 34 3 5 7 10 15 17 20 24 29 34 3 5 8 11 15 17 20 24 30 34 3 5 8 13 15 18 21 26 30 36 4 5 8 13 15 18 21 26 31
From the above list
5 has the highest frequency of 7 (greater than other elements)
Hence, the number of years that represents the mode of the Supreme Court justices served is 5
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A political activist claims that more than 50% of the voters in a certain state doesnít approve the performance of the current governor. To test this claim about the true proportion, p, of the "disapproval" rate of the governor, a random sample of 250 voters have been surveyed. Consider the following hypotheses: H0 : p 0:5 versus H1 : p > 0:5:
(a) (1 pt) Assume that 140 of the 250 voters in the sample showed their disapproval for the job of the governor. Determine the sample proportion of the disapproval rate, and brieáy explain whether it is in support of the null or the alternative hypothesis.
(b) (1.5 pts) If the P-value of the test is P = 0:029; what would be your conclusion at 2% level of signiÖcance? Explain it in context.
In the context of the null and alternative hypotheses, the sample proportion of 0.56 supports the alternative hypothesis (H1: p > 0.5). The p-value of 0.029 is less than 0.02, so we reject the null hypothesis.
(a) The sample proportion of the disapproval rate can be calculated by dividing the number of voters who showed disapproval (140) by the total sample size (250).
Sample proportion (p) = 140/250 = 0.56
In the context of the null and alternative hypotheses, the sample proportion of 0.56 supports the alternative hypothesis (H1: p > 0.5). This is because the sample proportion of 0.56 is greater than the hypothesized value of 0.5, indicating a higher disapproval rate than what is claimed in the null hypothesis.
(b) The p-value of the test is given as P = 0.029. The p-value represents the probability of observing a sample proportion as extreme or more extreme than the one calculated from the sample data, assuming that the null hypothesis is true.
At a 2% level of significance (α = 0.02), if the p-value (0.029) is less than the significance level, we reject the null hypothesis. In this case, the p-value of 0.029 is less than 0.02, so we reject the null hypothesis.
Therefore, we can conclude that there is sufficient evidence to support the claim made by the political activist. The data suggests that more than 50% of the voters in the state disapprove of the performance of the current governor.
The p-value of 0.029 indicates that the observed sample proportion is unlikely to occur if the true proportion were less than or equal to 0.5.
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Express 345200000 in standard form
Answer:
3.452 × 10^8
Step-by-step explanation:
hope this helps :)
respectively Q 1
=160−10P 1
OR r 1
=16−0.1Q 1
aWD 1/P 6
=16 6
−2T −
Q 2
=200−20P 2
ORP 2
=10−0,050,…H1AP 2
=15−0:0% Saga's Total Cost function is: TC =120+4Q With third degree price discrimination, the condition for peofit marimizater is MR 1
=MR 2
=MR=MC Find P 1
,Q 1
,P 2
,Q 1
Total Revenue, Total Cost, and Total proft wit sree discrimination. Find P,Q,TR,TC&π In the absence of price discrimination. Marks: 7
In the absence of price discrimination, the profit-maximizing conditions would be different, and the resulting prices, quantities, total revenue, total cost, and profit would also be different.
To find the profit-maximizing conditions with third-degree price discrimination, we need to equate the marginal revenue (MR) to the marginal cost (MC) for each market segment.
Given the demand equations and the total cost function:
Market 1: Q1 = 160 - 10P1 or P1 = 16 - 0.1Q1
Market 2: Q2 = 200 - 20P2 or P2 = 10 - 0.05Q2
Total Cost: TC = 120 + 4Q
To find the profit-maximizing prices and quantities, we equate MR to MC for each market segment:
MR1 = MC:
16 - 0.2Q1 = 4
0.2Q1 = 12
Q1 = 60
MR2 = MC:
10 - 0.1Q2 = 4
0.1Q2 = 6
Q2 = 60
Substituting the quantities back into the demand equations, we find:
P1 = 16 - 0.1(60) = 10
P2 = 10 - 0.05(60) = 7
The total revenue (TR) can be calculated by multiplying the price by the quantity for each market segment:
TR = P1 * Q1 + P2 * Q2
TR = (10 * 60) + (7 * 60)
TR = 600 + 420
TR = 1020
The total cost (TC) is given by the total cost function:
TC = 120 + 4Q
TC = 120 + 4(60 + 60)
TC = 120 + 480
TC = 600
Finally, the profit (π) can be calculated by subtracting total cost from total revenue:
π = TR - TC
π = 1020 - 600
π = 420
In the absence of price discrimination, the profit-maximizing conditions would be different, and the resulting prices, quantities, total revenue, total cost, and profit would also be different.
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solve by elimination
5x+6y =-2
15x + 4y= 22
Answer:
(2, -2)
Step-by-step explanation:
Multiply the first equation by -3,and multiply the second equation by 1.
−3(5x+6y=−2)
1(15x+4y=22)
Becomes:
−15x−18y=6
15x+4y=22
Add these equations to eliminate x:
−14y=28
Then solve−14y=28for y:
−14y=28
−14y
−14
=
28
−14
(Divide both sides by -14)
y=−2
Now that we've found y let's plug it back in to solve for x.
Write down an original equation:
5x+6y=−2
Substitute−2foryin5x+6y=−2:
5x+(6)(−2)=−2
5x−12=−2(Simplify both sides of the equation)
5x−12+12=−2+12(Add 12 to both sides)
5x=10
5x
5
=
10
5
(Divide both sides by 5)
x=2
Answer:
x=2 and y=−2
Answer:
(2,-2)
Step-by-step explanation:
Can someone solve this step by step?
Answer:
2/9
Step-by-step explanation:
First off, a positive + and a negative - equals to a negative
So it will be 5/9-1/3.
We have to have a common denominator.
The common denominator is 9.
1x1=3
3x3=9
5/9-3/9=2/9
Answer:
I don't know if I'm correct but I got 0.27
To determine the % Cr in the chromium-complex Legna synthesized, she massed out a 1.0240 g sample of the Cr complex. She dissolved the sample in a volumetric flask and made 100.0 mL of solution. From the standard curve of Absorbance versus concentration Legna obtain [Cr^3+]=0.03933 M. Calculate the %Cr in the complex.
the %Cr in the complex is 26.294%.
To determine the % Cr in the chromium-complex Legna synthesized, she massed out a 1.0240 g sample of the Cr complex. She dissolved the sample in a volumetric flask and made 100.0 mL of solution. From the standard curve of Absorbance versus concentration Legna obtained [Cr3+]=0.03933 M. Calculate the %Cr in the complex.
To determine the % Cr in the chromium-complex synthesized by Legna, we can use the following formula:% Cr = (mass of Cr/mass of sample) x 100We have the mass of the sample, which is 1.0240 g. We need to find the mass of Cr in the sample. To do this, we need to find the number of moles of Cr in the solution, and then use the molar mass of Cr to convert this to mass.
The concentration of Cr3+ in the solution is given as 0.03933 M. We know that the complex is made up of Cr and some other ligands, and the concentration of Cr3+ is not the same as the concentration of Cr in the complex. To find the concentration of Cr in the complex, we need to use the formula:[Cr] = [Cr3+] x (1/x), where x is the number of moles of Cr3+ in the complex.
Let's assume that there is one mole of Cr3+ in the complex, then x = 1. If there are n moles of Cr3+ in the complex, then x = n. We can find x by using the formula:x = (mass of sample/Mr of Cr3+) x [Cr3+]/volume of solutionWe know that the mass of the sample is 1.0240 g, and the volume of the solution is 100.0 mL = 0.1000 L. The molar mass of Cr3+ is 52.00 g/mol. Substituting these values into the formula, we get:x = (1.0240/52.00) x 0.03933/0.1000x = 0.000761 moles of Cr3+ in the complex
Now we can use the formula [Cr] = [Cr3+] x (1/x) to find the concentration of Cr in the complex:[Cr] = 0.03933/0.000761[Cr] = 51.69 M
Finally, we can use the formula:% Cr = (mass of Cr/mass of sample) x 100The molar mass of Cr is 52.00 g/mol. The mass of Cr in the complex is 51.69 x 52.00 = 2689.88 g/mol. Substituting this value and the mass of the sample (1.0240 g) into the formula, we get:% Cr = (2689.88/1.0240) x 100% Cr = 262944.53% Cr = 26.294%
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Mason randomly chooses a card from a standard deck or cards What is the probability that it is a face card given that it is a hearts
Examine the diagram of circle O. Points C, T, and P are on circle O. If m∠COT=146∘ and CT⌢=35.7 units, what is the measure of OT¯¯¯¯¯¯¯? Round your answer to the nearest whole number. 44 units 28 units 14 units 23 units
Answer:
14 units is the answer :)
Step-by-step explanation:
An electronics manufacturer uses a soldering process in the manufacture of circuit boards. Today, the manufacturer experiences defects at a rate of ~24 per every 1000 applications. The manufacturer estimates that repairing defects costs ~$210,000 per year (total cost). After some initial review of failures, the team finds that many of the defects occur on circuit boards that are warped. Thus, the team decides to investigate how to reduce the degree of warp during manufacturing.
Key Output Variable: Warp -- Specification for warp is less than or equal to 0.018"
After creating a cause-and-effect diagram, the team decides to focus on 3 input variables.
Three Input Variables:
1: Fixture Location: Inner versus Outer (assume each fixture produces 4 boards: 2 inner and 2 outer positions).
2: Conveyor Speed: possible settings are 4, 5, or 6 feet/minute
3: Solder Temperature – Current Specification range is 450 – 490 oF
For Current State, the team conducted the following to obtain PPM and/or Ppk:
Study 1 –observational study recording the degree of warp for all boards (Figure 1a). They also stratify warp by inner and outer positions in Figure 1b and Table 1. (i.e., position relates to location of boards within the fixture) Note: each fixture has two inner and two outer boards.
To further analyze the process, the team conducted these studies, results are shown below:
Study 2 – experiment examining the effect of Conveyor Speed on warp. Note: They took equal samples of inner and outer boards and maintained a solder temperature of 490 oF. They recorded the warp for each combination of conveyor speed and board.
Speed = 4, Loc = Inner; Speed = 4, Loc = Outer;
Speed = 5, Loc = Inner; Speed = 5, Loc = Outer;
Speed = 6, Loc = Inner; Speed = 6, Loc = Outer;
Study 3 – experiment examining the effect of temperature on warp. Here, they tested solder temperature at three temperature settings with equal number of samples from inner and outer board locations. They ran this entire study using a conveyor speed of 5 ft/min.
Based on the information provided and the Minitab results below, prepare a DMAIC report. (You should be able to summarize each DMAIC phase using 1-2 paragraphs. Feel free to reference the Minitab output by Table/Figure number below (e.g., Figure 1) in your write-up. Make sure you identify both statistically significant and insignificant variables. Also, make sure your recommendations link to your data analysis.
Finally, use the available data to identify (estimate) a new predicted mean and standard deviation (based on your recommendations) to determine a Predicted Ppk after recommendations. Compare this predicted Ppk to current Ppk to show an improvement.
(Note: For improve / control phases, feel free to make reasonable assumptions as needed)
Based on the information provided and the analysis conducted, the main answer is that the three input variables, Fixture Location, Conveyor Speed, and Solder Temperature, significantly affect the degree of warp in circuit boards during the soldering process. By optimizing these variables, the electronics manufacturer can reduce defects and improve the overall quality of their circuit boards.
In Study 1, the team observed and recorded the degree of warp for all boards, stratifying the results by inner and outer positions. This initial study helped identify the problem and the need for further investigation. Study 2 examined the effect of Conveyor Speed on warp, while Study 3 focused on the impact of Solder Temperature. Both studies used equal samples from inner and outer board positions to obtain reliable data.
The results from the Minitab analysis provided insights into the statistical significance of the variables. It is crucial to note that statistically significant variables have a notable impact on the degree of warp, while insignificant variables have a minimal effect. By considering these findings, the team can prioritize their improvement efforts accordingly.
To improve the manufacturing process and reduce warp in circuit boards, the team should focus on the statistically significant variables. They can experiment with different combinations of Fixture Location, Conveyor Speed, and Solder Temperature to find the optimal settings that minimize warp. Additionally, they can use statistical techniques such as Design of Experiments (DOE) to further explore the interactions between these variables and identify the best operating conditions.
By implementing these recommendations and optimizing the input variables, the electronics manufacturer can reduce defects and improve the overall quality of their circuit boards. This will lead to a decrease in the number of defects and subsequently lower the associated repair costs. The predicted mean and standard deviation based on these recommendations can be used to calculate a new Predicted Ppk, which can be compared to the current Ppk to demonstrate the improvement achieved.
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Carl's mom made 25 mushrooms for Carl and 4 friends to eat for a snack. If each of them ate the same number, and they ate as many as possible, how many did each
one eat?
5
7
4
6
Step-by-step explanation:
they each had 25 mushrooms for Carl and his friends there are 4 of them each and they got the same portions and if you count by 5s to 25 that will be the answer so the answer is 5
Answer:
5
Step-by-step explanation:
Number of mushrooms = 25
Number of persons = 5
Each of them ate the same number of mushrooms. so the square root of 25 will be number of mushrooms eaten by each
Number of mushroom eaten by each of them = √25
= 5
A random sample of adults was surveyed about whether they shop online. Of the 90 adults surveyed, 72 stated they shop online. What is the 99% confidence interval for p, the proportion of adults who shop online?
Find the z-table here.
(0.72, 0.88)
(0.70, 0.90)
(0.69, 0.91)
(0.68, 0.92)
Answer:
(0.69, 0.91)
Step-by-step explanation:
Hope this helps!
The 99% confidence interval for p is (0.698, 0.902), which is closest to option (B) (0.70, 0.90).
What is a confidence interval?A confidence interval is a range of values that are constrained by the statistic's mean and that are likely to include an unidentified population parameter. The proportion of likelihood, or certainty, that the confidence interval would include the real population parameter when a random sample is drawn several times is referred to as the confidence level.
To find the 99% confidence interval for the proportion of adults who shop online, we need to use the formula:
CI = p ± z√((p(1-p))/n)
where p is the sample proportion (72/90 = 0.8), n is the sample size (90), and z is the z-score corresponding to the 99% confidence level (from the z-table, this is 2.576).
Substituting the values, we get:
CI = 0.8 ± 2.576√((0.8(1-0.8))/90)
Simplifying, we get:
CI = 0.8 ± 0.102
Therefore, the 99% confidence interval for p is (0.698, 0.902).
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Let X be a continuous random variable with pdf f(x) = 4x^3,0 < x < 1. Find E(X^2) (round off to second decimal place).
The expectation, E(X²) of the random variable X is 2/3
Here we are given that the pdf or the probability density function of X is given by
4x³, where 0 < x < 1
clearly this is a continuous distribution. Hence we know that the formula for expectation for random variable X with probability density function f(x) is
∫x.f(x)
and, the formula for expectation
E(X²) = ∫x².f(x)
Hence here we will get
\(\int\limits^1_0 {x^2 . 4x^3} \, dx\)
here we will get the limits as 0 and 1 as we have been given that x lies between 0 and 1
simplifying the equation gives us
\(4\int\limits^1_0 {x^5} \, dx\)
we know that ∫xⁿ = x⁽ⁿ⁺¹⁾ / (n + 1)
hence we get
\(4[\frac{x^6}{6} ]_0^1\)
now substituting the limits will give us
\(4[\frac{1^6 - 0^6}{6} ]\)
= 4/6
= 2/3
The expectation, E(X²) of the random variable X is 2/3
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