A manufacturer of plumbing fixtures has developed a new type of washerless faucet. let rho-p(a randomly selected faucet of this type will develop a leak within 2 years under normal use). the manufacturer has decided to proceed with production unless it can be determined that p is too large; the borderline acceptable value of p is specified as 0.10. the manufacturer decides to subject n of these faucets to accelerated testing (approximating 2 years of normal use). with x = the number among the n faucets that leak before the test concludes, production will commence unless the observed x is too large. it is decided that if p = 0.10, the probability of not proceeding should be at most 0.10, whereas if rho = 0.30 the probability of proceeding should be at most 0.10. (assume the rejection region takes the form reject h if x2 c for some c. round your answers to three decimal places.)
1. what are the error probabilities for n10? p-value- can n- 10 be used?
a. it is not possible to use n = 10 because there is no value of x which results in a p-value
b. it is not possible to use n10 because it results in b(0.3)> 0.1
c. it is not possible to use n 10 because it results in b(0.3)<0.1 0.1.
d. it is possible to use n = 10 because both the p-value and β(0.3) are less than 0.1
e. it is possible to use 10 because both the p-value and b(0.3) are greater than 0.1
what are the error probabilities for n-20? p-value = β(0-3) = can n 20 be used?
a. it is not possible to use n = 20 because there is no value of x which results in a p-value
b. it is not possible to use n 20 because it results in b(0.3)0.1
c. it is not possible to use n 20 because it results in b(0.3) < 0.1
d. it is possible to use n 20 because both the p-value and b(0.3) are less than 0.1
e. it is possible to use n 20 because both the p-value and b(0.3) are greater than 0.1
2. what are the error probabilities for n-25? p-value . p(0.3) can n 25 be used?
a. it is not possible to use n-25 because there is no value of x which results in a p-value
b. it is not possible to use n 25 because it results in b(o.3) > 0.1
c. it is not possible to use n 25 because it results in b(0.3) < 0.1
d. it is possible to use n 25 because both the p-value and b(0.3) are less than 0.1
e. it is possible to use n 25 because both the p-value and b(0.3) are greater than 0.1 0.1.

The equation of the parabola is gotten as;

 y = -4x² + 24x - 32

We are given the coordinates of a parabola to be;

(3, 4) ; (4,0) ; (2,0)

The general form of equation of a parabola is given by;

y = ax² + bx + c

Let's plug in the x and y coordinates as given to us from the question.

(3²)a + 3b + c = 4

9a + 3b + c = 4  ----(eq 1)

(4²)a + 4b + c = 0

16a + 4b + c = 0  ----(eq 2)

(2²)a + 2b + c = 0

4a + 2b + c = 0  ----(eq 3)

       y = -4x² + 24x - 32

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Answer:

Hi please resend the question so i can help u!

Step-by-step explanation:

The constant percent rate of change of f(x) with respect to x is (d) 25% decay

The function is given as

f(x) = 46(0.75)^x

The above function is an exponential function

The growth/decay factor is

b = 0.75

The constant rate is then calculated as

Rate = 1 - b

This is because b is less than 1 (i.e. an exponential decay)

So, we have

Rate = 1 - 0.75

Evaluate

Rate = 25%

Hence, the constant percent rate of change of f(x) with respect to x is (d) 25% decay

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Answer: D

Hope this helps :)

Answer:

B

Step-by-step explanation:

sum of any number with zero gives the same number

Answer:

Yes, and its B

Step-by-step explanation:

if you flip and turn the one to the right, it matches up to the one on the left

hope that helps :)

Answer:

B

Step-by-step explanation:

Answer:

The actual distance between Phoenix and Fountain Hills is 7.3 miles

Step-by-step explanation:

We note that the scale factor gives the ratio of the map reading to the actual distance reading

The scale factor of the map is 1 inch = 2.5 miles

The distance between Phoenix and Fountain Hills = 2.92 inches on the map

Let the actual distance between Phoenix and Fountain Hills = D, we have;

D/(2.92 inches) = 2.5 miles/inch

Therefore;

D = 2.92 inches ×  2.5 miles/inch = 7.3 miles

D = 7.3 miles

The actual distance between Phoenix and Fountain Hills = D = 7.3 miles.

Answer:

We have a problem here, Houston.

Step-by-step explanation:

Is "(x+5)2=36" supposed to be (x+5)^2=36 ?

If so,

x = ± 11

-----------------------

If it is indeed (x+5)2=36

then:

2x + 10 = 36

2x = 26

x = 13

None of the answer options fir either of these two interpretations of the equation provided.  Please check the equation.

Answer:

-11 and 1

Step-by-step explanation:

did the test

Example that demonstrates the contrapositive of the limit comparison test. Let's consider a pair of series an and bn with positive terms, where lim(n→∞)(an/bn) = 0, bn diverges, but an converges.

Let's define the series an and bn as follows:
- an = 1/\(n^2\)
- bn = 1/n

Now, let's examine the limit:
lim(n→∞)(an/bn) = lim(n→∞)((1/\(n^2\)) / (1/n))

To simplify the limit expression, we multiply both numerator and denominator by \(n^2\):
lim(n→∞)(\(n^2\)(1/\(n^2\)) / \(n^2\)(1/n)) = lim(n→∞)(n/\(n^2\)) = lim(n→∞)(1/n)

As n approaches infinity, the limit becomes:
lim(n→∞)(1/n) = 0

Now, let's check the convergence of the series an and bn:
- an = Σ(1/\(n^2\)) is a convergent p-series with p = 2 > 1.
- bn = Σ(1/n) is a divergent p-series with p = 1.

Thus, we have provided an example of a pair of series an and bn with positive terms, where lim(n→∞)(an/bn) = 0, bn diverges, but an converges. This demonstrates the contrapositive of the limit comparison test, as requested.

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Answer:

5 months

Step-by-step explanation:

9/3=3

15/3=5

The answer is 2 1/4 cupcakes

Answer:

2 1/4 cupcakes

Step-by-step explanation:

Step 1: State what is know

There are 3 people Jake, Brother 1, and Brother 2.  They all ate 3/4 of a cup cake each

Step 2: Solve

Multiple 3 by 3/4

3 x 3/4 = \(C_{Total}\)

2.25 = \(C_{Total}\\\)

0.25=1/4

2 1/4 cupcakes

Step 3: Therefore Statement

Therefore the 3 brothers ate 2 1/4 cupcakes

Answer:

slope = -1/2

Step-by-step explanation:

m=mx+b so y=-1/2x+1  x is ur slope

Answer:

B > A

Step-by-step explanation:

B and A are both in between 0 and 1 on a number line.

On a number line, the further right you go, the higher numerical values get, and the further left - vice versa.

Anyhow, B is further to the right, as well as closer to 1 than A is, so we can assume that B is the greater number.

Have a nice day, fam. Spread The Love.

Answer:

$6.80

Step-by-step explanation:

1.79 x 3.8 = 6.802

So $6.80

Answer:

157

Step-by-step explanation:

Answer:

multiply them.

Step-by-step explanation:

The correctanswer is-the percentage of the pieces that will meet the length specs is 98.78%.

The given data may be a random variable that takes after the normal distribution with mean μ=64 and standard deviation σ=0.1

The required value is to discover the rate of the pieces that will meet the length specs which is between 63.76 and 64.24 inches.

To find the required percentage, standardize the given limits as follows: Lower Limit: (63.76 - μ) / σ= (63.76 - 64) / 0.1 = -2.4

Upper Limit: (64.24 - μ) / σ= (64.24 - 64) / 0.1 = 2.4

Using the Standard Normal Distribution Table, the probability that the value will fall between -2.4 and 2.4 is found to be 0.9878.

The required percentage is then found by multiplying the probability by 100, which is: Percentage = 0.9878 x 100% = 98.78%

Therefore, the percentage of the pieces that will meet the length specs is 98.78%.

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A vertical asymptote exists of the form x = k where y→∞ or y→ -∞.

A slant asymptote exists of the form y = mx + b where m ≠ 0.

Vertical lines go up and down and are in the form of x = a, where a stands for the common x-coordinate of all locations, whereas horizontal lines go left to right and take the shape of y = b, where b stands for the y-intercept.

A vertical line that directs the function's graph but is not actually a part of it is called a vertical asymptote. Because it appears at an x-value outside of the function's domain, the graph can never cross it. There may be multiple vertical asymptotes for a given function. All common factors are cancelled in the denominator, D(x).

A horizontal asymptote exists of the form y = k where x→∞ or x→ -∞ if the value of the one/both of the limits lim ₓ→∞ f(x) and lim ₓ→ -∞ f(x).

A vertical asymptote exists of the form x = k where y→∞ or y→ -∞.

A slant asymptote exists of the form y = mx + b where m ≠ 0.

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The question illustrates equivalent ratios, because both quadrilaterals are similar.

The length of GH is 35.1 units

From the question (see attachment), the corresponding sides are:

So, we have:

\(\mathbf{CD : DE = GH : HI}\)

The side lengths are:

\(\mathbf{HI = 51}\)

\(\mathbf{CD = 11}\)

\(\mathbf{DE = 16}\)

So, we have:

\(\mathbf{11 : 16 = GH : 51}\)

Express as fractions

\(\mathbf{\frac{11 }{ 16} = \frac{GH }{ 51}}\)

Make GH the subject

\(\mathbf{GH =51 \times \frac{11 }{ 16}}\)

\(\mathbf{GH =35.1}\)

Hence, the length of GH is 35.1 units

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Answer:

>

Step-by-step explanation:

.4 is bigger than .06. I hope thid helps:D

Answer: C. 7

Step-by-step explanation:

The simple 2D finite difference scheme you described is a common approach for discretizing and solving problems involving partial differential equations or approximating derivatives on a discrete grid.

In a simple 2D finite difference scheme, each point in a matrix is updated by taking a weighted average of its four neighboring points. This scheme is commonly used to approximate the derivatives of a function or solve partial differential equations on a discrete grid.

Let's consider a matrix with indices i and j, where a[i,j] represents the value at point (i,j). The update equation for each point in the matrix can be expressed as:

a[i,j] = w * (a[i-1,j] + a[i+1,j] + a[i,j-1] + a[i,j+1])

In this equation, a[i-1,j], a[i+1,j], a[i,j-1], and a[i,j+1] represent the neighboring points of a[i,j] in the horizontal and vertical directions. The weight factor w determines the contribution of each neighbor in the average. The specific values of the weights will depend on the specific finite difference scheme being used and the problem being solved.

The purpose of this update equation is to propagate information through the grid, allowing for the gradual convergence of values toward a solution. By iteratively applying this update equation to all points in the matrix, the values can be updated and refined over multiple iterations until a desired level of accuracy or convergence is achieved.

It's worth noting that the choice of weights and the specific details of the finite difference scheme can vary depending on the problem being solved and the desired accuracy or stability properties. Different schemes, such as central differences or forward/backward differences, may be used to approximate derivatives or solve different types of equations.

Overall, the simple 2D finite difference scheme you described is a common approach for discretizing and solving problems involving partial differential equations or approximating derivatives on a discrete grid.

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Answer:

cos(theta/2) = sqrt((1+x)/2)

Step-by-step explanation:

From the double angle formula

cos^2(t)-sin^2(t) = cos(2t)  ...................(1)

cos^2(x)+sin^2(x) = cos(t-t) =1...............(2)

Add (1) and (2)

2cos^2(t) = 1+cos(2t)

cos^2(t) = (1+cos(2t))/2

cos(t) = sqrt((1+cos(2t))/2)

substitute t = theta/2

cos(theta/2) = sqrt((1+cos(theta))/2)

substitute cos(theta) = x

cos(theta/2) = sqrt((1+x)/2)

The smallest number of eggs that could have been in the box is 1134

The problem is to find the smallest number of eggs that could have been in the box, given the remainder when taking them out by different numbers. Here are the moves toward tackling it:

Allow n to be the quantity of eggs in the container. Then we have the accompanying arrangement of congruences:

n ≡ 1 (mod 2)

n ≡ 1 (mod 3)

n ≡ 1 (mod 4)

n ≡ 1 (mod 5)

n ≡ 1 (mod 6)

n ≡ 0 (mod 7)

For this problem, we have k = 6 k = 6, a i = {1,1,1,1,1,0} a_i = {1,1,1,1,1,0}, M i = {1260,840,630,504,420,720} M_i = {1260,840,630,504,420,720}, and y i = {−1,−2,−3,-4,-5,-6} y_i = {-1,-2,-3,-4,-5,-6}.

Plugging these values into the formula and simplifying modulo 5040, we get:

n = (−1260 + −1680 + −1890 + −2016 + −2100 + 0) mod 5040

n = (−8946) mod 5040

n = (−3906) mod 5040

n = 1134 mod 5040

Therefore, the smallest number of eggs that could have been in the box is 1134

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Answer:

D

Step-by-step explanation:

become beg an so he just come i will come yesterday

The total distance that needs to be covered from the art gallery to the theater through the described station will be 10 miles so option (C) will be correct.

There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.

The same sign is used in an equation to indicate that two expressions are equivalent in a formula.

To put it another way, the equation needs to be subject to some constraints.

Distance from the art gallery to the magic shop

7 - 5 = 2 miles.

Distance from magic shop to dry cleaners

7 - 4 = 3 miles.

Distance from dry cleaners to theater

7 - 2 = 5 miles

Total distance covered

2 + 3 + 5 = 10 miles.

Hence the total distance covered will be 10 miles.

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The derivative of the function \($f(t) = \cos^2(e^{\cos^2(t)})$\) is \($\frac{d}{dt} f(t) = -2\cos(e^{\cos^2(t)}) \sin(e^{\cos^2(t)}) \cdot 2\cos(t) \sin(t) e^{\cos^2(t)}$\).

The derivative of the function \($f(t) = \cos^2(e^{\cos^2(t)})$\) can be found using the chain rule and the derivative properties of trigonometric and exponential functions.

To find the derivative of the given function, we apply the chain rule. Let's break down the function into its constituent parts and find their derivatives separately.

The outer function is \($g(t) = \cos^2(u)$\), where \($u = e^{\cos^2(t)}$\).

The derivative of g(t) can be found using the chain rule and the derivative of the cosine function:

\($\frac{d}{dt} g(t) = -2\cos(u) \sin(u) \cdot \frac{du}{dt}$\)

Now, we need to find the derivative of u with respect to t.

Let \($v = \cos^2(t)$\)

Then, \($u = e^v$\), and the derivative of u with respect to t is

\($\frac{du}{dt} = \frac{dv}{dt} \cdot e^v$\)

To find \($\frac{dv}{dt}$\), we differentiate \($v = \cos^2(t)$\) using the chain rule and the derivative of the cosine function:

\($\frac{dv}{dt} = -2\cos(t) \sin(t)$\)

Putting it all together, we have

\($\frac{d}{dt} f(t) = \frac{d}{dt} g(t) \cdot \frac{du}{dt} = -2\cos(u) \sin(u) \cdot -2\cos(t) \sin(t) e^{\cos^2(t)}$\)

Simplifying further, we get

\($\frac{d}{dt} f(t) = -2\cos(e^{\cos^2(t)}) \sin(e^{\cos^2(t)}) \cdot 2\cos(t) \sin(t) e^{\cos^2(t)}$\)

Therefore, the derivative of the function \($f(t) = \cos^2(e^{\cos^2(t)})$\) is \($\frac{d}{dt} f(t) = -2\cos(e^{\cos^2(t)}) \sin(e^{\cos^2(t)}) \cdot 2\cos(t) \sin(t) e^{\cos^2(t)}$\).

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Answer: 11

Step-by-step explanation:

Answer:

443.666

Step-by-step explanation:

because i used a caulculator boiiiiiiii

Answer:

B

Step-by-step explanation:

To evaluate g(7) substitute x = 7 into g(x) , that is

g(7) = \(\frac{7}{8}\) × 7 - \(\frac{1}{2}\)

      = \(\frac{49}{8}\) - \(\frac{4}{8}\)

      = \(\frac{45}{8}\) → B

Answer:

A) 283.4mm^2

Step-by-step explanation:

Ok area of a circle

A=πr2

Radius is half of diameter

19/2=9.5

so

A=(3.14)9.5^2

A=283.385

round this nearest tenth

283.4mm^2

Answer:

area of semi circle=1/2 ×π(19/2)²=1/2 ×3.14×19²/4=1133.54/8=141.6925=151.7mm²

Answer:

801.66

Step-by-step explanation:

calculator

Answer:

801.6632653061

Step-by-step explanation:

.......

Answer: 8/9

Step-by-step explanation: We can use the Keep, Change, Solve method of multiplication to evaluate this question.

Since 4/1 is our first fraction, it remains the same.

    2. Change

Now we have to reciprocate 9/2 so it becomes 2/9.

    3. Solve

Now that we have our new fractions, we can multiply:

4/1 × 2/9 = 8/9