A man walking at 0.5 m/s increases his pace to 0.8 m/s in 3 seconds. What is his acceleration?

Answer:

Average speed equals distance / time

380 / 40 = 9.5 m/s.

Explanation:

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Answer:

a). Single replacement.

Explanation:

Because one element replaces another element in a compound

Answer:

zzyibgsdwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwe

Explanation:

The compressive force that would be enough to produce a fracture is 4000 N.

We know that the femur is one of the most important bones that we have in the human body. In this case, we have been told that In the human femur, bone tissue is strongest in resisting compressive force, approximately half as strong in resisting tensile force, and only about one- fifth as strong in resisting shear force.

Then we know that;

Tensile force = 8000

The compressive force would be half of this magnitude as such;

Compressive force = 4000 N

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The equal and the opposite force is the person's force of gravity pulls up on the elevator. Option A

We know that the elevator is the kind of device that can be used when we are going up or down a high rise building. We have to note that the elevator that we talking about will also work based on the law of Newton.

We have to note that for every force there is an equal and an opposite force and the same is true when you are using the elevator to move up or down as we can see here.

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The true statements regarding VDGS Systems are you must power on and check the system before arrival and a qualified agent must man the Emergency stop.

VDGS stands for Visual Docking Guidance System. It is a technology used in airports to assist pilots in parking their aircraft at the gate by providing visual cues and guidance through the use of lights and/or displays.

The following statements regarding VDGS Systems are true:

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The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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Answer:

Electric dipole

Explanation:

the dipole axis makes an angle with the electric field. depending on direction (clockwise/aniclockwise) you get the torque

Hope this helps

The momemtum is not conserved in scenario d.

Momentum of an object is the product of its mass and velocity.

To determine in which of the conditions in which momentum is not conserved, we need to know the law of conservation of momentum.

The law of conservation of momentum states that as long as no external force acts on a system, the total momentum of the system of two colliding objects is conserved.

If we consider scenarios a, b and c, we see that no external force acts on the system of two objects in the three instances so, the total momentum is conserved.

In scenario d, an external force acts on the system, so total momentum is not conserved since according to the law of conservation of momentum, total momentum is only conserved when there is no external force acting on a system.

So, the momemtum is not conserved in scenario d.

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Answer:

Explanation:

Wind is caused by the uneven heating of the atmosphere by the sun, variations in the earth's surface, and rotation of the earth. ... Wind turbines convert the energy in wind to electricity by rotating propeller-like blades around a rotor. The rotor turns the drive shaft, which turns an electric generator

Answer:

B.

Explanation:

Answer:

So the force acting on the train during the time of constant acceleration is -35,217.75 N and the stopping distance is 985.76 m.

Explanation:

The force acting on the train during the time of constant acceleration can be calculated using the equation:

force = mass x acceleration

To calculate the acceleration, we can use the equation:

acceleration = (final velocity - initial velocity) / time

where the final velocity is 0 m/s (the train comes to rest), the initial velocity is 220 km/h (converted to m/s) and the time is 16s.

initial velocity = 220 x 1000/3600 = 61.11 m/s

acceleration = (0 - 61.11) / 16 = -3.819 m/s^2

force = mass x acceleration = 9.25 x 105 kg x -3.819 m/s^2 = -35,217.75 N

The negative sign indicates that the force is acting in the opposite direction of the velocity, which is in the opposite direction of the train's motion, which is braking.

To calculate the stopping distance, we can use the equation:

distance = (initial velocity x time) + (1/2 x acceleration x time^2)

stopping distance = (61.11 m/s x 16s) + (1/2 x -3.819 m/s^2 x 16s^2) = 985.76 m

So the force acting on the train during the time of constant acceleration is -35,217.75 N and the stopping distance is 985.76 m.

Answer:

no

Explanation:

i did it and got it right.

The mass of the wheel is 0.38 kg. It is related to weight, which is the force exerted on an object due to gravity and is proportional to the object's mass.

What is Mass?

Mass is a measure of the amount of matter in an object. It is a scalar quantity and is usually measured in kilograms (kg) in the SI system of units. Mass is a fundamental property of an object and does not change with its location or motion.

Let's start by finding the tension in the wire using the motion of the object. We can use the kinematic equation:

y = (1/2)at^2

where y is the distance the object moves, a is the acceleration, and t is the time. Substituting the given values:

2.95 m = (1/2)a(1.85 s)^2

Solving for the acceleration:

a = 2.47 m/s^2

Now, we can find the tension in the wire using the rotational dynamics of the wheel. The torque due to the tension is equal to the moment of inertia times the angular acceleration:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration. Since the wheel is rotating without friction, the torque due to the tension is the only torque acting on the wheel, so:

Tension * radius = (1/2)mr^2 * α

where m is the mass of the wheel and r is its radius. We can rearrange this equation to solve for the tension:

Tension = (1/2)ma

Substituting the values we found:

Tension = (1/2)(4.3 kg)(2.47 m/s^2) = 5.31 N

Now we can use the torque equation again to solve for the moment of inertia of the wheel:

Tension * radius = (1/2)mr^2 * α

Substituting the values we found and solving for the moment of inertia:

I = 2(Tension * radius) / α = 0.033 kg·m²

Finally, we can use the moment of inertia to find the mass of the wheel using the formula:

I = (1/2)mr^2

Substituting the values we found:

0.033 kg·m² = (1/2)m(0.288 m)^2

Solving for the mass:

m = 2I / r^2 = 0.38 kg

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Answer:

B

Explanation:

Where it shows on the map is B

Answer:

pls first attach the fig.

The graph in the figure shows the position of a particle as it travels along the x-axis. The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s. Therefore, option B is correct.

The term average speed is defined as the total distance traveled by the object in a particular time interval.

In the kinematics studies the movement of bodies, give the relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is known as uniform motion.

       v = Δ x / Δt

Where v is the velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.

Therefore,

v =  2.0 - ( - 2.0 ) / 4.0 - 1.0

v = 1.33 m / s          

Thus, The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s, option B is correct.

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Your question is incomplete, most probably your question was

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s?

Please help!! The graph in the figure shows the position - 1, Graph is attache below in image.

The accurate statements are:Her average velocity was 100 kilometers per hour south.At one point, her instantaneous velocity was 125 kilometers per hour south.

The accurate statements about Maryanne's drive are:

Her average velocity was 100 kilometers per hour south. Average velocity is calculated by dividing the total displacement by the total time taken. In this case, since she drove directly south for a distance of 100 km in 1 hour, her average velocity is indeed 100 km/h south.

At one point, her instantaneous velocity was 125 kilometers per hour south. Instantaneous velocity refers to the velocity at a specific moment in time. Although her average velocity was 100 km/h south, there could have been moments during her drive where her speed reached 125 km/h south, indicating her instantaneous velocity.

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Answer:

\(1.6 \,\,\,10^{-4}\)

Explanation:

Recall that scientific notation involves expressing the number in powers of ten, and using a multiplicative factor whose value is larger than or equal to 1 (one) and strictly smaller than 10 in the form:

\(a\,\,\,10^n\\with\,\,\,1\leq a<10\)

and with n an integer value.

in our case, notice that 0.00016 = 16 / 100000 = 1.6 / 10000

and that denominator can be expressed as: 10^4, and can also be brought to the numerator as a negative power of ten:

1.6 / 10000 = 1.6 / 10^4 = 1.6 * 10^(-4)

\(\frac{16}{100000} =\frac{1.6}{10000}=\frac{1.6}{10^4}=1.6\,\,\,10^{-4}\)

a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while  b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.

a. Isothermal compression:

For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Since the process is isothermal, we can write:

\(P_1V_1 = P_2V_2\)

where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.

We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:

\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)

To find the final temperature, we can use the ideal gas law again:

PV = nRT

Rearranging, we get:

T = PV/(nR)

Substituting the values we know, we get:

T = (\(1.5*10^5\)Pa)(V1)/(nR)

Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:

T2 = T1 = 293 K

b. Adiabatic compression:

For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:

PV^γ = constant

where γ = Cp/Cv is the ratio of specific heats.

Since the process is adiabatic and reversible, we can write:

\(P_1V_1\)^γ = \(P_2V_2\)^γ

We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:

\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)

To find the final temperature, we can use the adiabatic equation again:

\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K

Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.

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The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N

The following data were obtained from the question:

The centripetal force can be obtained as illustrated below:

F = mv²/r

= (50 × 7²) / 5

= (50 × 49) / 5

= 2450 / 5

= 490 N

Thus, we can concluded that the centripetal force is 490 N

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Answer:

Inertia

Explanation:

Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.

ANSWER:

a) Fraindrop

(b) Fearth

STEP-BY-STEP EXPLANATION:

(a)

We calculate the force, multiplying the value of the mass by gravity, just like this:

(b)

by newton's 3rd law they are are equal and opposite so:

Answer:

A. 1.17

B.

the angular momentum is conserved because there is n o external force doing torque on the pivot

Linear momentum is not conserved because this is not an example of elastic collision where the final and initial kinetic energies are the same

Explanation:

A.

1.17 rad/s

B.

the angular momentum is conserved because there is n o external force doing torque on the pivot

Linear momentum is not conserved because this is not an example of elastic collision where the final and initial kinetic energies are the same

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

For a given spring the extension is directly proportional to the force applied For example if the force is doubled, the extension doubles When an elastic object is stretched beyond its limit of proportionality the object does not return to its original length when the force is removed

Explanation: