Therefore, the isolators would be more effective at speeds closer to 200 cycles per minute (200 rpm), and their effectiveness would decrease as the machine speed deviates from this value.
The natural frequency of the machine-spring system is 200 cycles per minute, and the machine generates a vertical force p(t) = posinot.
When the machine runs at different speeds, it experiences various amplitudes of steady-state vertical displacement, such as 0.2 in at 20 rpm, 1.042 in at 180 rpm, and 0.0248 in at 600 rpm.
To calculate the amplitude of vertical motion when the steel springs are replaced with rubber isolators that provide the same stiffness but introduce 25% damping, you need to consider the damping ratio and the ratio of forcing frequency to natural frequency.
Without the exact values for the stiffness and damping coefficient of the system, it is not possible to provide the amplitude of vertical motion with the rubber isolators. However, we can comment on the effectiveness of the isolators at various machine speeds.
In general, rubber isolators will be more effective in reducing vibrations at frequencies closer to the natural frequency of the system due to the added damping. At speeds far from the natural frequency, the isolators may not have a significant impact on the amplitude of vertical motion.
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compute the downward acceleration of a falling wheel of the same shape and size as the one in the laboratory, but made of a different material which is three times as heavy.
The downward acceleration of the falling wheel made of a different material that is three times as heavy as the one in the laboratory is approximately 9.8 m/s².
The downward acceleration of a falling object near the surface of the Earth is typically denoted by the letter "g" and is approximately 9.8 m/s², assuming no air resistance. This value represents the acceleration due to gravity.
The mass of an object affects the force of gravity acting on it but does not affect the acceleration due to gravity. The acceleration due to gravity is constant for all objects near the Earth's surface, regardless of their mass. This is known as the equivalence principle, which states that the gravitational mass and inertial mass of an object are equivalent.
When the wheel made of a different material is three times as heavy as the one in the laboratory, its mass will be three times greater. However, the acceleration due to gravity acting on both wheels will remain the same, approximately 9.8 m/s².
The downward acceleration of the falling wheel made of the different material, which is three times as heavy, will still be approximately 9.8 m/s². The material of the wheel does not affect the acceleration due to gravity, which remains constant near the surface of the Earth.
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A cheetah can maintain a constant speed of 30 m/s. At this rate, how far will it travel in 3 seconds? (Express you answer in m.)
Answer:
90m
Explanation:
it travels at 30 m/s so 30*3 is 90
A point source emits electromagnetic radiation uniformly in all directions If the power output of the source is 960 W what are the amplitudes of the electric and magnetic fields in the wave at a distance of 15.0 m from the source? (The surface area of a sphere that has radius Ris 4nR? e0 = 8.854x10 C? /(N-m') . #to 4tx10 T-mA .) Ans. electric field amplitude_LbQNlc_ 2 magnetic field amplitude _5_3.3XLO
The electric and magnetic field amplitudes of an electromagnetic wave can be calculated using the power output of the source and the distance from the source. We can use the formula:
P = (1/2)ε₀cE₀²A,
where P is the power output, ε₀ is the permittivity of free space (8.854x10⁻¹² C²/(N·m²)), c is the speed of light (3x10⁸ m/s), E₀ is the electric field amplitude, and A is the surface area of a sphere with radius R.
First, let's calculate the surface area of the sphere at a distance of 15.0 m:
A = 4πR² = 4π(15.0 m)² ≈ 2827.43 m².
Now, rearranging the formula, we can solve for E₀:
E₀² = (2P) / (ε₀cA) = (2 * 960 W) / (8.854x10⁻¹² C²/(N·m²) * 3x10⁸ m/s * 2827.43 m²).
Calculating this expression gives us E₀² ≈ 8.76x10⁻⁶ N²/C².
Taking the square root, we find:
E₀ ≈ 9.36x10⁻⁴ N/C.
Finally, we can use the relationship between the electric and magnetic field amplitudes in an electromagnetic wave:
B₀ = E₀ / c,
where B₀ is the magnetic field amplitude.
Substituting the values, we get:
B₀ ≈ (9.36x10⁻⁴ N/C) / (3x10⁸ m/s) ≈ 3.12x10⁻¹² T.
Therefore, the electric field amplitude at a distance of 15.0 m from the source is approximately 9.36x10⁻⁴ N/C, and the magnetic field amplitude is approximately 3.12x10⁻¹² T.
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. A cyclist traveling southeast along a road at 15 km/h feels a wind blowing from the southwest at 25 km/h. To a stationary observer, what are the speed and direction of the wind
The speed and direction of the wind with respect to the observer is 10 km/h southwest.
Relative velocity of the wind
The velocity of the wind appears to be greater for the cyclist than a stationary observer with zero velocity.
\(V_o + V_c = V_w\)
where;
Vo is the velocity of the wind with respect to a stationary observerVc is the velocity of the cyclist with respect to the observerVw is velocity of the windVo = 25 - 15
Vo = 10 km/h southwest
Thus, the speed and direction of the wind with respect to the observer is 10 km/h southwest.
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the velocity of a bobsled is v= 10 ft/s. when t = 2 s, the position is s= 25 ft. what is its position at f= 10 s?
The position of the bobsled at t = 10 s is 125 f with the data that is presented to us, including velocity.
To find the position of the bobsled at t = 10 s, we need to use the equation that relates velocity, position, and time for constant acceleration:
s =\(s0 + v0t + 1/2at^2\)
where s0 is : initial position, v0 : initial velocity, a : constant acceleration, and t is :time.
Given that the velocity of the bobsled is v = 10 ft/s at t = 2 s and its position is s = 25 ft, we can use this information to determine the initial position s0 and the constant acceleration a.
From the velocity equation, we can write:
v = v0 + at
Substituting v0 = 10 ft/s, t = 2 s, and v = 10 ft/s, we get:
10 = 10 + 2a
Solving for a, we get:
a = 0 \(ft/s^2\)
This means that the bobsled is moving with constant velocity, so its position after 10 seconds will simply be:
s = s0 + v0t
= 25 + 10(10-2)
= 125 ft
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which of these comprises the least radiation in the everyday environment?
Among the given options, visible light comprises the least radiation in the everyday environment. Visible light is part of the electromagnetic spectrum and falls within a specific wavelength range that is detectable by the human eye.
The electromagnetic spectrum consists of various types of radiation, including radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of radiation has different wavelengths and energy levels. It is a form of electromagnetic radiation that we encounter daily through natural sunlight, artificial lighting, and reflections from various objects.
In terms of energy and potential harm to living organisms, visible light has lower energy compared to higher-energy forms of radiation like X-rays and gamma rays. While excessive exposure to ultraviolet radiation (UV) can be harmful, visible light falls within a relatively safe range of the electromagnetic spectrum. It allows us to see our surroundings and plays a vital role in our daily activities.
It is important to note that even though visible light comprises the least radiation in the everyday environment, it is still a form of electromagnetic radiation and can have specific effects on materials and biological systems under certain conditions.
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Question 3 of 10
An artist uses a ratio that compares the length and width of an average
human face. Which type of model is this?
A. It is mathematical.
B. It is computer-generated.
C. It is physical.
D. It is conceptual.
SUBMIT
Answer:
Mathematical
Explanation:
Because you are comparing the length and width
Find the potential on the axis of a uniformly charged solid cylinder, a distance z from the center. The length of the cylinder is L, its radius is R, and the charge density is p. Use your result to calculate the electric field at this point. (Assume that z > Lj2.)
A uniformly charged solid cylinder's axis has a potential that is equal to kpAL arcsinh(z/R) at a distance of z from the center. The electric field at this location is -kpAL/R / (R² + z²), where the length of the cylinder is L, its radius is R, and the charge density is p.
To find the potential on the axis of the cylinder, we can use the formula for the potential due to a charged ring:
dV = kdq/r
here,
dV is potential contribution from a small element of charge dq on the ring,
We can break up the cylinder into small rings of charge and integrate to find the total potential:
= V
= ∫dV
= k∫dq/r
To simplify the calculation, we can use the fact that the charge density is uniform, so:-
dq = pAdz,
here,
A is area of the ring
dz is thickness of the ring.
The area of the ring is:-
A = 2πRL
and the distance from the ring to the point on the axis is:-
r = √(R² + z²).
Reserving these values:-
V = k∫pAdz/√(R² + z²)
= kpAL.∫dz/√(R² + z²)
= kpAL arcsinh(z/R)
here,
L is length of the cylinder and
arcsinh is inverse hyperbolic sine function.
E = -dV/dz
dV/dz = k pAL/R /√(R² + z²)
Hence, the electric field at a point on the axis a distance z from the center of the cylinder is:
= E
= -dV/dz
= -kpAL/R / √(R² + z²)
Note that the field points in the opposite direction to the axis, so it is negative.
Therefore, the potential on the axis of a uniformly charged solid cylinder, a distance z from the center, is:
V = kpAL arcsinh(z/R)
Electric field on this particular mark:-
E = -kpAL/R / √(R² + z²)
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Please help
Need help with question 1) and 2) please ASAP ??? 15 points ?
matter is any thing that has mass and occupies space
Answer:
yes omg u are so handsome
a telescopic gauge is used with what other measurement tool
A telescopic gauge is typically used in conjunction with an outside micrometer to measure the internal diameter of a bore or hole.
The telescopic gauge consists of a set of spring-loaded plungers that expand when inserted into the hole, while the outside micrometer is used to measure the diameter of the plungers when they are fully expanded.
To measure with this setup, the telescopic gauge is first inserted into the hole, and then the outside micrometer is used to measure the diameter of the expanded plungers. The measurement recorded on the micrometer scale corresponds to the internal diameter of the hole.
This combination of a telescopic gauge and an outside micrometer provides a practical and accurate method for measuring internal dimensions of bores or holes in various industries such as machining, engineering, and manufacturing.
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Scientists have detected an asteroid that is 700,000,000 km from Earth. About how many astronomical units is that? 0. 5 AU 1 AU 3. 5 AU 4. 5 AU.
Answer:
it is 4.67921098559 astronomical units
Explanation:
An asteroid that is 700,000,000 km is equivalent to 4.67 AU.
Option D is the correct answer.
How do you convert KM into AU?Given that an asteroid that is 700,000,000 km from Earth.
We know that 1 AU is equal to 149597870.691 KM. The expression can be given below.
\(1 \;\rm AU = 149597870.691\;\rm KM\)
\(1 \;\rm KM = \dfrac {1}{149597870.691} \;\rm AU\)
\(700,000,000 \;\rm KM = \dfrac {1}{149597870.691} \times 700,000,000 \;\rm AU\)
\(700,000,000 \;\rm KM = 4.67 \;\rm AU\)
Hence we can conclude that 700,000,000 km is equivalent to 4.67 AU. Option D is the correct answer.
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Using the fft function in MATLAB, plot the magnitude spectrum versus frequency for the signal g(t)=exp(−10t)u(t) for 0≤t≤1 with Δt=0.01. Determine the number of points in the signal. Use 450 zeros for precede and trail and determine the period T. B. Separately, plot the continuous magnitude transform given by: G(f)= 10+j2πf
1
[1−e −(10+j2πf)
] Utilize the same separation in frequencies. C. Using the fft function in MATLAB, plot the magnitude spectrum versus frequency for the signal: g(t)=sinc(πt). Assume Δt=0.01, and use 450 zeros for precede and trail and determine the period T.
The magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) and the continuous magnitude transform, and to determine the number of points in the signal and the period, the provided MATLAB code can be used.
A. To plot the magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) for 0 ≤ t ≤ 1 with Δt = 0.01 and determine the number of points in the signal:
```matlab
% Define parameters
delta_t = 0.01; % Sampling interval
t = 0:delta_t:1; % Time vector
g = exp(-10*t).*(t >= 0); % Signal definition
% Pad with zeros
N_zeros = 450;
g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];
% Compute the Fourier Transform
G = fft(g_padded);
% Compute the magnitude spectrum
G_mag = abs(G);
% Determine the number of points in the signal
num_points = length(g_padded);
% Determine the period
T = num_points * delta_t;
% Determine the frequency vector
Fs = 1/delta_t; % Sampling frequency
f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);
% Plot the magnitude spectrum versus frequency
plot(f, G_mag);
xlabel('Frequency');
ylabel('Magnitude Spectrum');
title('Magnitude Spectrum versus Frequency');
```
B. To plot the continuous magnitude transform given by G(f) = (10 + j2πf) / (1 - e^(-(10 + j2πf))) and utilize the same frequency separation:
```matlab
% Define frequency range
f = -Fs/2 : Fs/num_points : Fs/2 - Fs/num_points;
% Evaluate the expression for G(f)
G_continuous = (10 + 1j * 2 * pi * f) ./ (1 - exp(-(10 + 1j * 2 * pi * f)));
% Plot the continuous magnitude transform
plot(f, abs(G_continuous));
xlabel('Frequency');
ylabel('Magnitude');
title('Continuous Magnitude Transform');
```
C. To plot the magnitude spectrum versus frequency for the signal g(t) = sinc(πt) assuming Δt = 0.01 and determine the period T:
```matlab
% Define parameters
delta_t = 0.01; % Sampling interval
t = -1:delta_t:1; % Time vector
g = sinc(pi*t); % Signal definition
% Pad with zeros
N_zeros = 450;
g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];
% Compute the Fourier Transform
G = fft(g_padded);
% Compute the magnitude spectrum
G_mag = abs(G);
% Determine the number of points in the signal
num_points = length(g_padded);
% Determine the period
T = num_points * delta_t;
% Determine the frequency vector
Fs = 1/delta_t; % Sampling frequency
f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);
% Plot the magnitude spectrum versus frequency
plot(f, G_mag);
xlabel('Frequency');
ylabel('Magnitude Spectrum');
title('Magnitude Spectrum versus Frequency');
```
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a truck with 0.335 m radius tires travels at 45.0 m/s. at how many radians per second are the tires rotating?
The tires of the truck are rotating at approximately 21.4 Radians per second.
To determine the radian per second at which the tires of the truck are rotating, we first need to calculate the angular velocity of the tires. We know that the linear velocity of the truck is 45.0 m/s, and since the tires are in contact with the ground, their linear velocity must be the same. Therefore, the circumference of the tire can be calculated as 2πr, where r is the radius of the tire (0.335 m in this case).
Circumference of tire = 2πr = 2π(0.335) = 2.104 m
Now, we can calculate the angular velocity using the formula:
Angular velocity = Linear velocity / Circumference of tire
Angular velocity = 45.0 / 2.104
Angular velocity ≈ 21.4 radians per second
Therefore, the tires of the truck are rotating at approximately 21.4 radians per second.
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Which is a negative effect of deforestation on the environment? A. habitat restoration B. desertification C. soil production D. urbanization
Answer:Deforestation refers to the decrease in forest areas across the world that are lost for other uses such as agricultural croplands, urbanization, or mining activities. Greatly accelerated by human activities since 1960, deforestation has been negatively affecting natural ecosystems, biodiversity, and the climate. The UN’s Food and Agriculture Organization estimates the annual rate of deforestation to be around 1.3 million km2 per decade.
Explanation:
The negative effect of deforestation on the environment is desertification. The correct option is B.
What is desertification?Desertification is the process by which fertile land becomes desert, typically as a result of drought, deforestation, and inappropriate agriculture or land use practices. It occurs when land that was once able to support vegetation and life becomes increasingly dry, barren, and unable to sustain crops, livestock, or human populations. This can be due to natural causes such as prolonged droughts, but it is often exacerbated by human activities such as deforestation, overgrazing, and soil degradation. Desertification can have devastating effects on the environment, leading to soil erosion, loss of biodiversity, and reduced productivity of the land. It can also cause social and economic problems, such as displacement of people, food shortages, and conflicts over resources.
Here in the question,
Deforestation is the clearing of trees and other vegetation from an area, leading to the loss of habitat and biodiversity, and disruption of water cycles. It can also cause soil erosion, which can result in the depletion of soil nutrients, reduced productivity, and eventually lead to desertification. Additionally, deforestation contributes to climate change by releasing carbon dioxide into the atmosphere, which can cause global warming and other environmental problems. Habitat restoration, soil production, and urbanization are not negative effects of deforestation but can be impacted by it.
Therefore, The correct answer is B i. e Desertification.
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A charge of - 4.0 µC is located at the origin and a charge of - 5.0 µC is located along the y-axis at y = 2.0 m. At what point along the y-axis is the electric field zero?
I got y = 0.94427191 and y = -16.944272. Not sure if right tho.
I did \({k q_1 \over y^2} &= {k q_2 \over (2-y)^2}\), put the known in and solved it.
Does a light bulb at a temperature of 2500K produce as white a light as the sun at 6000K
Answer:
No. ... UV light causes sunburn, whereas visible light does not.
Explanation:
The light energy produced from a light bulb is far low compared to the light energy produced by the sun. The heat energy also greatly differ in both.
What light energy ?Light energy is a form of energy produced by stars and man made devices. One form of energy can be transformed into other form without destroying the energy.
The source of light and heat energy in stars is nuclear fusion. Fusing of two light nuclei forming a heavy nuclei accompanies the release of tremendous amount of energy.
In a light bulb, the electrical energy is converted to light energy and some energy is lost in the form of heat energy. The light the white light produced by a bulb cannot be as intense as the white lite from sun.
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Two tiny spheres of mass 5. 30 mg carry charges of equal magnitude, 62. 0 nc , but opposite sign. They are tied to the same ceiling hook by light strings of length 0. 530 m. When a horizontal uniform electric field e that is directed to the left is turned on, the spheres hang at rest with the angle θ between the strings equal to 58. 0∘
Answer:in this situation we have during the two tiny spheres of masks, 5.8 mg carry Charges of equal magnitude 30 77 Nano column but opposite in sign They are tied to the same ceiling hook by light in spring of 2.53 m. It is known that when they original uniform electric village applied that is directed to the left. The angle between the springs is 58°. Then we have to find the value of E. So given that the mass M is 5.8 mg, that is 5.8 into 10 to the power -3 g. And This is five and we have the charge that is Q. Is 77 and a column. So this is 77 into 10 to the power -9 columns. The length of the string is 0.53 m. And the angle between the spring.
How is fishpond raising affected by global climate change?
Answer:
It creates bad air so that’s like air pollution I guess
Explanation:
A plane is going at a speed of 300 km/h at 63 W of N. The wind hits the plane at a direction of 65 km/h at 52 S of E. What is the final direction of plane and the speed at which it is moving?
Q2. Fill in the blanks:
North Pole of a magnet will.....
.. North pole of another magnet.
South Pole of a magnet will.
North pole of a another magnet.
Needle of a compass lines up with the......
of a magnet.
You can find the shape of a magnetic field using........
...... and also a plotting.
Answer:
repel , attract,l am sure with these two blanks only
Answer:
Magnetic fields
A magnet creates a magnetic field around it. You cannot see a magnetic field, but you can observe its effects. A force is exerted on a magnetic material brought into a magnetic field. The force is a non-contact force because the magnet and the material do not have to touch each other.
A 7.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball. How fast does the ball need to be moving in order to send the man off at a speed of 3.00 m/s?
Answer:
35.14 m/s
Explanation:
The Law of Conservation of Momentum states that the momentum before and after a collision is the same.
m₁ v₁ + m₂ v₂ = m₁ v₁ + m₂ v₂Let's set the ball to have the subscript of 1 and the man to have the subscript of 2.
The initial and final mass of the ball is the same, so m₁ = 7.00 kg on both sides of the equation.
The initial velocity of the ball, v₁ on the left side of the equation, is the unknown variable we are trying to find.
The initial and final mass of the man is the same, so m₂ = 75.0 kg on both sides of the equation.
The man starts at rest, meaning that his initial velocity is v₂ = 0 m/s on the left side of the equation.
The final velocity of both the ball and the man is 3.00 m/s, so we can set v₁ and v₂ on the right side of the equation to equal 3.00 m/s.
Left side of the equation:
m₁ = 7.00 kg v₁ = ?m₂ = 75.0 kgv₂ = 0 m/sRight side of the equation:
m₁ = 7.00 kg v₁ = 3.00 m/sm₂ = 75.0 kgv₂ = 3.00 m/sSubstitute these values into the Law of Conversation of Momentum formula.
(7.00) v₁ + (75.0)(0) = (7.00)(3.00) + (75.0)(3.00)Multiply and simplify.
7.00 v₁ = 21 + 225 7 v₁ = 246Divide both sides of the equation by 7.
v₁ = 35.14 m/sThe ball needs to be moving at a speed of 35.14 m/s in order to send the man off at a speed of 3.00 m/s.
The ant's aunt's aunt travels from the 15.00 cm mark to the 85.00 cm mark back to the 30.00 cm mark and then finally to the 30.00 cm mark. What is the ant's displacement?
Answer:
15 cm
Explanation:
Displacement is the shortest distance between the point of origin of a body in motion to the final stopping positing.
For this ant's aunt's aunt that travels from the 15.00 cm mark to the 85.00 cm mark back to the 30.00 cm mark and then finally to the 30.00 cm mark, the displacement from the starting position is..
displacement = stopping point - starting point
d = 30 cm - 15 cm = 15 cm
A bus is traveling at a velocity of 25 m/s straight south what affect on acceleration have of 4 m/s2 north have on the bus
Answer:
The effect of the acceleration on the bus is that the acceleration slows down the bus by 4 m/s, for each second the bus is in motion
Explanation:
The given parameters are;
The velocity of the bus, u = 25 m/s
The direction in which the bus is moving = South
The acceleration acting on the = 4 m/s²
The direction of the acceleration = North
We have;
The acceleration = Rate of change of velocity with time
The acceleration, a = dv/dt
∴ dv = a × dt
The velocity in the direction of the acceleration, v is therefore;
∫dv = v = ∫a × dt = a × t
v = a×t
The direction of the change in velocity due to the acceleration is opposite to the direction of the velocity of the bus, therefore, the effect of the acceleration on the velocity of the bus is given by the following equation for the resultant velocity, s, as follows;
s = u - a × t = 25 - 4×t
s = 25 - 4×t
Therefore, the acceleration slows down the bus by 4 m/s, every second.
Answer:
Explanation:
Gtt
what is Newton's gravitational constant ? write down its value and si unit.
__________ receptors detect presence of acids in substances, whereas __________ receptors detect sodium in substances. a. sour . . . salt b. sweet . . . bitter c. bitter . . . salt d. sweet . . . sour please select the best answer from the choices provided a b c d
The correct option is A.
Sour receptors help in the detection of the presence of acids in substances, whereas salt receptors help in the detection of sodium in substances.
A sour type of taste is considered as a quality of primary task that makes an innate rejection type of response in humans as well as in many other animals. Generally, Acidic stimuli are certain unique sources of a sour taste as whenever a rejection response might serve a discouragement of ingestion of foods which is spoiled by microorganisms that produce acids. The mechanisms by which an acid excites receptor cells of taste (TRCs) are actually complicated by the variability of wide species and are within species that are apparently different kinds of mechanisms for the case of strong and weak acids in substances.
The presence of epithelial sodium channels mediates the mechanism of salt taste. Usually, these receptors are open, and whenever foods are ingested with a high concentration of salt, sodium starts to flow into the cell which causes depolarization. This change occuring in the membrane potential then opens to voltage-gated sodium as well as calcium channels. The calcium influx is in an increased state that causes releasing of serotonin which is filled by vesicles. The serotonin aids in the acting of afferent taste as by axon which causes depolarization and action potentials.
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what is the wavelength of such a wave? the speed of sound in air is 340 m/s.
Answer:
wavelength is λ=fv=440340=0. 77m.
When you cook a steak, what kind of energy do you increase in the steak?
O A. Sound energy
OB. Thermal energy
O C. Nuclear energy
O D. Elastic energy
Answer:
B im pretty sure.
Explanation:
Question #2 What happens to some metals when the kinetic energy of their particles is decreased? A. they melt? B. they conduct? C. they expand it? D. they contract ? I NEED HELP FAST PLS
Some metals when the kinetic energy of their particles is decreased.
Hence, the correct option is D.
When the kinetic energy of the particles in a metal is decreased, it means that the particles are moving slower and have less energy. This can have a number of effects on the metal, depending on the specific properties of the metal.
A) Melting occurs when a solid substance is heated to a temperature where it becomes a liquid. A decrease in kinetic energy of particles is unlikely to cause melting of a metal.
B) Metals are good conductors of electricity due to the mobility of their electrons. A decrease in kinetic energy may not affect the metal's ability to conduct electricity, unless it affects the number of free electrons in the metal.
C) Most metals expand when they are heated and contract when they are cooled. However, a decrease in kinetic energy of particles in a metal may not cause it to expand.
D) Most metals contract when they are cooled.
Therefore, a decrease in kinetic energy of particles in a metal could lead to contraction of the metal.
Hence, the correct option is D.
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