A loudspeaker on a pole is radiating 600 W of sound energy in all directions. You are walking directly toward the speaker at 0.70 m/s. Assume you are 20 m away. What is the rate (dB/s) at which the sound intensity level is increasing? Hint: Use the chain rule and the relationship og 10 T=lnx/ln10

The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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The work done in the spring is calculated to be 2.8 J

Hooke's law states that, the extension of a given material is directly proportional to the applied force as long as the elastic limit is not exceeded . First, we must bear in mind that the material must remain within the elastic limit for us to apply the Hooke's law in solving the problem.

Now;

From Hooke's law;

F = Ke

F = force applied

K = force constant

e = extension

F = W = mg =  2.50 - kg * 9.8 m/s^2 = 24.5 N

K = 24.5 N/ 2.76 * 10^-2

K = 888 N/m

e = F/K

F = W =  1.25 - kg * 9.8 m/s^2 = 12.25 N

e = 12.25 N/ 888 N/m = 0.014 m or 1.4 cm

Work done by an external agent = 1/2 Kx^2

= 0.5 * 888 * (8 * 10^-2)^2

= 2.8 J

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The acceleration of Thomas is 0.233 m/s^2.

Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.

Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.

We are to find the acceleration of Thomas.

The formula for acceleration is given as :

acceleration = (final velocity - initial velocity) / time

In the given problem, the initial velocity of Thomas, u = 2 m/s.

The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.

Therefore, the acceleration of Thomas will be given as:

a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2

Thus, the acceleration of Thomas is 0.233 m/s^2.

To summarize, the acceleration of Thomas is 0.233 m/s^2.

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Given,

The length of one of the organ pipes, L₁=1.65 m

The frequency of the beat note, f=1.8 Hz

The speed of sound is given by, v=343 m/s

The beat frequency is given by,

Where f₁ is the frequency of the 1st pipe, f₂ is the frequency of the second pipe, and L₂ is the length of the second pipe.

On rearranging the above equation,

On substituting the known values,

The difference in the length of the organ pipes is,

Therefore the second pipe is longer than the 1st pipe by 0.05 m

The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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Answer:

F = 118 N

Explanation:

Assume Ann and Bob lift at their respective ends of the table

Sum moments about Bob's position to zero.

Let F be Ann's upward force

F[2.25] - 18.5(9.80)[2.25 / 2] - 8.33(9.80)[0.750] = 0

F = 117.86133333...  

Given:

The weight of table will be:

→ \(W_t = m_t g\)

        \(= 18.5\times 9.8\)

        \(= 181.3 \ N\)

Now,

→ \(\sum M_A_{nn} = -81.634\times 0.750-181.3\times 1.125+R_{bob}\times 1.125\)

or,

→ \(R_{bob} = \frac{61.2255+203.9625}{2.25}\)

          \(= \frac{265.188}{2.25}\)

          \(= 117.9 \ N\)

Thus the above answer is right.

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The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

Thus, Waveforms with periodic variations are those that recur consistently at set intervals.

The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.

In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.

Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.  

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The kinetic energy of the bullet will be 24.5 Joules and the average stopping force will be 490 Newtons.

The kinetic energy of an object is the energy present in an object due to the motion of object. Kinetic energy is directly proportional to the mass and velocity of the object. Kinetic energy can be converted into potential energy when an object comes at rest.

KE = 1/2 mv²

KE = 1/2 × 0.01 × 70 (10 g = 10/1000 = 0.01 kg)

KE = 24.5 J

Now, work done in stopping the bullet must be 24.5J

W = F × s

24.5 = F × 5/100

F = 490 N

Therefore, the average stopping force will be 490 N.

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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At point P, the electric potential is 0. This is due to the fact that the positive and as a result, at point P, their electric potentials are cancelled.

Positive and negative electrical charges are referred to as opposite forms of charge. A positively charged object will draw a negatively charged object, in accordance with our core concept of charge interaction.

We can apply the following equation to find the electric potential at point P: V = kQ/r1 - kQ/r2.

where:

k = Coulomb's constant (9 x 10⁹ N m²/C²),Q = magnitude of the charge (3.3 μC = 3.3 x 10⁻⁶ C), r1 = distance from the positive charge to point P (a = 0.35 m), r2 = distance from the negative charge to point P (a = 0.35 m)

Using these values, we can calculate the potential at point P as follows:

V = (9 x 10⁹ N m²/C²) * (3.3 x 10⁻⁶  C) / (0.35 m) - (9 x 10⁹ N m²/C²) * (3.3 x 10⁻⁶ C) / (0.35 m)

V = 0.

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The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Answer:

the medium through which it travels

Explanation:

Answer:

1 point?

Explanation:

Answer:

\(T=22.5sec\)

Explanation:

From the question we are told that:

Mass of astronaut \(m_a=105kg\)

Mass of tool \(m_t=16kg\)

Distance \(d=18m\)

Velocity of separation \(v_s= 0.1m/s\)

Velocity of tool bag \(v_t=4.5m/s\)

Generally the equation for momentum is mathematically given by

 \(P=mv\)

Therefore

Initial Momentum before drop

 \(P_1=0.1(105+16)\)

 \(P_1=12.1\)

Initial Momentum after drop

 \(P_2=-16(4.5)+105V\)

Therefore

Since \(P_1=P_2\)

 \(-72+105V=12.1\)

 \(V=0.8m/s\)

Generally the equation for Time T is mathematically given by

 \(T=\frac{d}{V}\)

 \(T=\frac{18}{0.8}\)

 \(T=22.5sec\)

Answer: P=30W

Explanation:

formula is p=w/t

p = power

w = work

t = elapsed time

input variables, solve then simplify.

The power of a lift that transfers 450 J of energy in 15 seconds is 30 watts.

Power is defined as the rate of doing work, i.e. the amount of work done per unit time.

Mathematically, it can be represented as follows:

Power = Work done / time taken

Therefore, the power of a lift that transfers 450 J of energy in 15 seconds can be calculated as follows:

Power = Work done / time taken= 450 J / 15 s= 30 W

Therefore, the power of the lift is 30 watts.

To explain further, we know that power is measured in watts (W), and it is the rate at which work is done or energy is transferred.

Here, we are given that the lift transfers 450 J of energy in 15 seconds.

We can find the power of the lift by dividing the amount of work done by the time taken to do it. By substituting the given values, we get the power of the lift as 30 W.

In simple terms, this means that the lift can transfer energy at a rate of 30 joules per second. This can also be interpreted as the lift can do 30 joules of work in one second.

Hence, we can conclude that the power of the lift is 30 watts.

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Continents have undergone major shifts around 12 times.

To calculate the number of times continents have gone through major shifts in the 4.6 billion year history of the Earth, we can divide the total time span by the average duration between shifts.

Total time span = 4.6 billion years

Average duration between shifts = 395 million years

To convert the total time span to years, we multiply 4.6 billion by 1 billion (1 billion = 1,000 million).

Total time span in years = 4.6 billion years × 1 billion = 4.6 × 10^9 years

Now we can calculate the number of shifts by dividing the total time span by the average duration between shifts:

Number of shifts = Total time span / Average duration between shifts

               = (4.6 × 10^9 years) / (395 million years)

               ≈ 11.65

Therefore, continents of our planet have gone through major shifts approximately 11.65 times in the 4.6 billion year history of the Earth. Since we cannot have a fraction of a shift, we can round the result to the nearest whole number. Thus, continents have undergone major shifts around 12 times.

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If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.

To calculate the total work done by the force in this scenario, we can use the formula for work:

Work = ∫F(x) dx

where F(x) is the force as a function of position and dx represents an infinitesimal displacement.

In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.

Let's break down the calculation step by step:

Write the integral for work:

Work = ∫F(x) dx

Substitute the given force:

Work = ∫√(1 - x²) dx

Integrate with respect to x:

To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.

Work = ∫√(1 - sin²(θ)) cos(θ) dθ

Simplify the integrand:

Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).

Work = ∫cos²(θ) dθ

Apply the power-reducing formula:

The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.

Work = ∫(1 + cos(2θ))/2 dθ

Integrate the terms separately:

Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ

The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.

Work = (1/2) θ + (1/2) (sin(2θ)/2) + C

Evaluate the integral limits:

To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.

At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.

Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]

Simplifying further:

Work = π/4 + (1/2) - (-π/4 + (1/2))

Work = π/4 + 1/2 + π/4 + 1/2

Work = π/2 + 1

Therefore, the total work done by the force is equal to π/2 + 1.

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There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

The density of a binary alloy can be calculated using the following equation:

ρ = w1ρ1 + w2ρ2

where,

ρ = density of the alloy

w1 and w2 = weight fractions of the two components (in this case, gold and silver)

ρ1 and ρ2 = densities of the pure components.

We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:

\(w_{Au}\) = 0.10

\(w_{Ag}\) = 0.90

We are also given the densities of pure gold and silver as:

ρ_Au = 19.32 g/\(cm^{3}\)

ρ_Ag = 10.49 g/\(cm^{3}\)

Now we can substitute these values into the density equation to find the density of the alloy:

ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag

ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))

ρ = 11.08 g/\(cm^{3}\)

Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.

To do this, we can use Avogadro's number and the atomic weights of gold and silver:

\(N_A\) = 6.022 × \(10^{23}\) atoms/mol

Aum = 196.97 g/mol

Agm = 107.87 g/mol

The number of gold atoms:

\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)

Substituting the values, we get:

\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol

\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)

Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

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The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

From the question we have

force = 450 × 2.5

We have the final answer as

Hope this helps you

Answer: 1125 N

Remember the formula: force = mass x acceleration.

The car has a mass of 450 kilograms.

We have to multiply this number by 2.5.

450 x 2.5 = 1125

Put the N sign at the end for North, and you have an answer.

1125 N

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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Answer:

Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.

Explanation:

Hope this helps!

Answer:

c

Explanation:

because whatever elements are used like gas uses water evaporation so yeah

Answer:

(A) Space between particles!

Explanation:

Solids can hold their shape because their molecules are tightly packed together!

Answer:

D: 35 m/s

Explanation:

The bus is moving at a speed of 20 m/s.

Thus; v_bus = 20 m/s

Tennis ball thrown horizontally towards the front of the bus is given as 15 m/s.. Thus, v_ball = 15 m/s

No, due to the fact that the bus and the ball are moving at the same time, an observer will think the speed is the sum of that of the ball and the bus.

Thus, it will appear to an observer on the sidewalk that the speed is; v_bus + v_ball = 20 + 15 = 35 m/s

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:The formula for kinetic energy is

(1/2) M V^2.

With M in kg and V in m/s, the answer will be in Joules.

K.E = 40joule

Explanation:

Answer:

B and D

Explanation:

The movement of kinetic energy from one media or item to another, or from an energy source to a medium or object, is referred to as heat. The correct statements are B and C.

The movement of kinetic energy from one media or item to another, or from an energy source to a medium or object, is referred to as heat. Energy may be transferred in three ways: radiation, conduction, and convection.

The statement that is correct in terms of heat and temperature are:

B. Heat from your feet raises the temperature of the water.

C. Your feet transfer heat into the surrounding water, reducing the temperature of your feet.

These two statements are correct because two statements out of four are stating about heat transfer is due to temperature difference.

Hence, the correct statements are B and C.

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Find the momentum of a 15 kg object traveling at 7 m/s.

The momentum of an object is found by using the following formula:

\(\displaystyle p=mv\)

In this question, the object is 15 kg and is travelling at 7 m/s. That means the mass is 15 kg and the velocity is 7 m/s.

Since all the needed variables are found, substitute it into the equation:

\(\displaystyle p=mv \rightarrow p=15 \times 7\)

Multiply:

\(\displaystyle p=105\ kg \times m/s\)

__________________________________________________________

What is the momentum? 105 kg · m/s

What is the velocity? 7 m/s

What is the mass? 15 kg

What equation did you use to solve? p = mv

__________________________________________________________

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

Answer:

we measure sound intensity in Decibels.

Answer:

Explanation:

We measure  sound power or sound pressure in decibels.

They  were named in honour of Alexander Graham Bell,( the inventor of both the telephone and the audiometer).