A lost chicken is trying to cross the street. Its velocity v as a function of time t is given in the graph
below where rightwards is the positive velocity direction.
v (m/s)
5
4+
3
21
1-1
2
3
4
5
-2
-3
-4
-5
What is the chicken's displacement Ax from t = 2 sto 4's?

At room temperature (300°k) there is enough thermal energy to break some bonds and create electron-hole pairs. This is True statement.

As we increase the temperature the atom starts vibrating and due to vibrations there is increase in the energy to the lattice. Since some energy is also transferred to the electrons so they also gets excited.

Hole is nothing but the absence of electrons, or negative charge and it is having positive charge but mass is zero.

when there is increase in the energy to the electrons and this energy is greater than or equal to the energy required to pull the electrons, these electrons can break the bond and leave the atoms. These atoms are now free electrons. when they leave atoms, there is electron deficiency created and hole is generate, so they can make electron hole pair.

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The unit vector notation in the given direction is \(0.58 \hat x + 0.81 \hat y\).

A physical quantity that has both directions and magnitude is referred to as a vector quantity.

A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.

In terms of subtracting a vector, it works the same as adding the vector's opposite.

Given that:

\(\vec A = 22 \hat x + (-14)\hat y,\\\vec B = 2.5\hat x + 13\hat y.\)

( two given vectors are written here.)

Therefore: the subtraction of these two vectors will be:

\(\vec A - \vec B = (= 22 \hat x + (-14)\hat y) - (2.5\hat x + 13\hat y)\\= 19.5\hat x - 27 \hat y\)

Unit vector in that direction of vectors  is =

\(= \frac{19.5\hat x - 27 \hat y}{\sqrt{19.5^2 + (-27)^2} } \\= 0.58 \hat x + 0.81 \hat y\)

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Answer:

b. 120 Newton

Explanation:

b. Solution;

mass = 60 kg

acceleration=2m/s^2

Force= mass * acceleration

=60*2

=120 N

Answer:

protons: 6

electrons: 6

neutrons: 8

Explanation:

atomic number -> number of protons -> 6

mass number -> number of protons + number of neutrons

    so 14-6 = 8. 8 neutrons

this atom is neutral (net charge is 0), so the number of electrons is the same as the number of protons, which is 6

Answer:

rocks are vertical.

Explanation:

I'm so sorry if I'm wrong this is what I think

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes

From the question given above, the following data were obtained:

The current drawn by the frying pan can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

Inputting the given parameters, we have:

1500 = Current × 25

Divide both sides by 25

Current = 1500 / 25

Current = 60 amperes

Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

Researchers use a wide range of technologies today to help gather data, depending on the field of study and the type of data they need to collect. Here are some examples:

   Sensors: Sensors are devices that can detect and measure physical quantities such as temperature, pressure, and motion. Researchers use sensors to collect data on the environment, human behavior, and other phenomena.

   Drones: Drones or unmanned aerial vehicles (UAVs) are aircraft that are remotely controlled or can fly autonomously. Researchers use drones to collect data from hard-to-reach or dangerous areas, such as remote forests, volcanoes, or disaster zones.

   Satellites: Satellites are spacecraft that orbit the Earth and can collect data on a wide range of environmental and climatic factors, such as temperature, rainfall, and ocean currents. Researchers use satellite data to study climate change, natural disasters, and other global phenomena.

   Imaging technologies: Imaging technologies such as magnetic resonance imaging (MRI) and computed tomography (CT) scans are used to collect detailed images of the body's internal structures. Researchers use these images to study the human brain, diagnose diseases, and develop new medical treatments.

   Social media and online platforms: Social media and online platforms provide researchers with access to large amounts of data on human behavior, opinions, and attitudes. Researchers use this data to study social trends, political movements, and public opinion.

   Wearable technology: Wearable technology such as fitness trackers and smartwatches collect data on physical activity, heart rate, and other health metrics. Researchers use this data to study human health and behavior.

These are just a few examples of the many technologies researchers use today to help gather data. The use of advanced technology has revolutionized the way researchers collect and analyze data, allowing them to make new discoveries and gain a deeper understanding of the world around us.

Answer:

In physics, a state of matter represents one of the various forms which matter can assume. There are four apparent states of matter in everyday life: solid, liquid, gas, and plasma.

Answer:

Plasma, the fourth state of matter (beyond the conventional solids, liquids and gases), is an ionized gas consisting of approximately equal numbers of positively and negatively charged particles.

Have a wonderful day! :-)

Answer:

A. the speed of the object

Explanation:

The color wouldn't make any difference to the potential energy and knowing the mass the way the object is shaped or the height of it would make no difference

Answer:

D) The tray would need to be raised higher before the items start to slide.

Explanation:

The tray would need to be raised higher due to the gritty sandpaper causing it to have more grip or fraction between the two surfaces. In the first experiment it would have a smooth surface to slide across but in the second experiment it would have a rougher surface to slide across.

Example: It would be like taking two different kinds of shoes like tennis shoes and football cleets. Then seeing which one has more traction when going up a hill.

Hope this helps!!

The article "Sunrise, Sunset...or Not?" by ReadWorks has a more formal tone compared to "The Ever-Changing Sky" by Megan McGibney.

In "Sunrise, Sunset...or Not?" the author uses scientific and technical terms such as "counterclockwise," "Arctic Circle," and "phenomenon," and provides a detailed explanation of the scientific reasoning behind the rising and setting of the sun.

In contrast, "The Ever-Changing Sky" by Megan McGibney has a more casual tone, using more colloquial language such as "clear day," "bright and shiny," and "People have always looked up at the sky with wonder." The author also uses phrases like "guess how long" and "right!" which implies that the author is addressing a less formal audience and is being conversational.

In all, "Sunrise, Sunset...or Not?" has a more formal tone because of its use of technical language, explanation of scientific concepts, and a generally informative and explanatory writing style.

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Sunrise, Sunset...or Not?

by ReadWorks

The sun is a wonderful thing for Earth. It is a star that heats the planet and makes life on

Earth possible. In addition, its light shines onto the planet. It is Earth's ultimate source of

energy.

Summer days may be longer than winter days, but for most people, the sun seems to do the

same thing each day: it appears to come up in the east for the day, and it appears to go down

in the west for the night. The sun looks like it rises in the east and sets in the west because of

how the earth spins in space. It spins toward the east, or counterclockwise. This means that

when most people look at the sky in the morning, the sun will first appear in the east.

The earth takes 24 hours to complete one turn. For most places on Earth, there is a daytime

and nighttime every 24 hours. But in some places for many days at a time, the sun might stay

up in the sky, or it might not even come up above the horizon.

In some parts of the world, the sun can be up in the sky for months. During part of the spring

and summer in Earth's Northern Hemisphere, the Northern Hemisphere is tilted towards the

sun so much that the sun in northern Alaska, which is located in the Arctic Circle, never goes

below the horizon. The Arctic Circle is an area at the top of the earth. In Barrow, Alaska, the

sun doesn't set for almost three months! This phenomenon is called the midnight sun, when

the sun has not set at midnight. Try sleeping through that!

During parts of the fall and winter in Earth's Northern Hemisphere, the Northern Hemisphere

is tilted in such a way that the sun doesn't come over the horizon in northern Alaska for a little

over two months. Therefore, nights last more than 24 hours. This phenomenon is called the

polar night. Although the sun never rises above the horizon during parts of the fall and winter

in the Arctic Circle, enough light often shines so that people who live there don't need

The Ever-Changing Sky

The Ever-Changing Sky

by Megan McGibney

Look up at the sky on a clear day. You will see the sun. It is bright and shiny, warming much of

what its light touches. Look up at the sky again at night. You may see the stars. They are also

bright and shiny, glimmering in the dark sky. You may also see the moon. It looks bright and

shiny, reflecting light from the sun. People have always looked up at the sky with wonder.

Some have even studied the sun, moon, and stars. These people, called astronomers, have

learned that those objects in the sky do not stay in the same place all the time.

The Ever-Changing Sky

extra quarter of a day.

Let's take a closer look at the moon. The earth does not revolve around the moon. Instead,

the moon revolves around the earth. It takes the moon about four weeks to complete a

revolution around the earth. The portion of the moon we, here on Earth, see changes over

this period of about four weeks as the moon's position around the earth changes. The

moonlight we see at night is the moon's reflection of sunlight onto Earth. The different ways

the moon appears to us are known as the moon's phases. The moon's phases depend on the

moon's position in relation to the earth and the sun.

The four-week period starts and ends with the new moon. The new moon cannot be seen

because the side of the moon lit by the sun is facing away from the earth.

Use the articles "The Ever-Changing Sky" and "Sunrise, Sunset...or Not?" to answer

questions 6.

6. Which article has a more formal tone? Support your answer with details from both texts.

Answers will vary.

Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

Answer:

She Had a Criminal Record. In 1872, Anthony registered to vote at a barbershop in Rochester, New York, and cast a ballot in the presidential election.

Explanation:

Answer:

a: true.

Explanation:

We can define an equipotential surface as a surface where the potential at any point of the surface is constant.

For example, for a punctual charge, the equipotential surfaces are spheres centered at the punctual charge.

Or in the case of an infinite plane of charge, the equipotential surfaces will be planes parallel to our plane of charge.

Now we want to see if the electric field is always perpendicular to these equipotential surfaces.

You can see that in the two previous examples this is true, but let's see for a general case.

Now suppose that you have a given field, and you have a test charge in one equipotential surface.

So, now we can move the charge along the equipotential surface because the potential in the surface is constant, then the potential energy of the charge does not change. And because there is no potential change, then there is no work done by the electric field as the charge moves along the equipotential surface.

But the particle is moving and the electric field is acting on the particle, so the only way that the work can be zero is if the force (the one generated by the electric field, which is parallel to the electric field) and the direction of motion are perpendiculars.

Then we can conclude that the electric field will be always perpendicular to the equipotential surfaces.

The correct option is a.

Answer:

2Kg

first you find the total mass of both the person und skateboard

f = m*a

30 = m* 0.5

m= 30/ 0.5

m= 60 kg

then you subtract the mass of the person from the total mass

m1 - m2

60 - 58

= 2 kg

Taking into account the Newton's second law, the mass of the skateboard is 2 kg.

Newton's Second Law establishes the relationship between the forces acting on an object and the acceleration it experiences. This law says that the acceleration that an object experiences when subjected to a net force (force applied to the body) is proportional to that force.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

In this case, you know:

Replacing:

30 N= m× 0.5 m/s²

Solving:

m= 30 N÷0.5 m/s²

m= 60 kg

The mass of the sistem is the sum of the mass of the skateboard and the mass of the mass of your body:

Mass= mass of the skateboard + mass of your body

In this case:

60 kg= mass of the skateboard + 58 kg

Solving:

mass of the skateboard= 60 kg - 58 kg

mass of the skateboard= 2 kg

Finally, the mass of the skateboard is 2 kg.

Learn more about the Newton's second law:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 50 × 0.85

We have the final answer as

Hope this helps you

Static friction cancels out the force of the push, so it also has a magnitude of 25 N.

The resultant displacement of the Polly protractor is 25 km.

The displacement of an object is the change in the position of the object.

The displacement of the Polly protractor is calculated as follows;

d² = 15² + 20²

d = √(15² + 20²)

d = 25 km

Thus, the resultant displacement of the Polly protractor is 25 km.

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The complete question is below:

Find the resultant displacement of the Polly protractor.

Answer:

The correct option

(C) 50W

-

Hope it help's u :))!

Answer:

I don't understand the question that up added

Explanation:

what do you mean by ti and tk

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

Answer:

B. False

Explanation:

Health-related components of fitness are not just important for people who do not play competitive sports.

Answer:

C. The robot fires the ball backward with a speed of 2 m/s.

Explanation:

The robot fires the ball backward with a speed of 2 m/s.

To find the correct statement among all the options, we need to know about the relative velocity.

Velocity is a relative physical quantity that depends on the chosen frame of reference.

Thus, we can conclude that the robot fires the ball backward with a speed of 2 m/s.

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Answer:

12\(s^{-1}\)

Explanation:

Period= how long for each revolution

Since we have 10 revolutions in 120 seconds.

120/10=12s

Psychology is a science because it makes use of scientific method such as observation, asking question, making prediction, etc to study the mind and behavior.

Psychology is the scientific study of mind and behavior.

The different types of Psychology include;

So we can conclude that Psychology is science because it uses scientific method to study the mind and behavior.

Scientific method entails the process of observing, asking questions, and seeking answers through tests and experiments is not unique to any one field of science.

The characteristics of scientific method include;

Psychology applies such scientific method to arrive to a conclusion, hence we can conclude that Psychology is a science.

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Answer:

9.8m/s

Explanation:

Answer: The speed 1934

The effort distance​ will be 160 cm.Applying the moment at the center as follows will provide the effort distance:

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of forces in levers and pulleys.

Given data;

Effort,\(\rm F_e=00 N\)

Load,\(\rm P= 400 \ N\)

Distance from the fulcrum,\(\rm d=40 \ cm\)

The effort distance​ is found by applying the moment at the center as;

\(\rm F_e \times d= P \times d' \\\\ 200 \ N \times d'=800 \ N \times 40 \ cm \\\\ d'=160 \ cm\)

Hence, the effort distance​ will be 160 cm

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The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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